Answer:
Tom walked until he was 100 metres from his home. Then, he realised that he had dropped his homework, so he turned around and went 60 metres to pick it up again. He again turned back and started to walk faster to get to the bus stop on time. He got to the bus stop 100 seconds after leaving his home and waited for the bus.
Explanation:
PLSSS HELP ITS URGENT ILL RATE YOU BRAINLIEST:) A truck whose bed is 4 m long, 2.2 m wide, and 1.0 m high is delivering sand for a sand-sculpture competition. About how many trips must the truck make to deliver 23 m^3 of sand?
Answer:
one truck load is 2.5*1.5*1 = 3.75m^3
7/3.75 = 1.86 loads,
so 2 trips must be made.
Explanation:
assuming no external forces, when a tennis ball and the earth collide, if the coefficient of restitution is equal to one then we can conclude the following:
If a tennis ball and the earth collide with a coefficient of restitution of one, it means that the collision is perfectly elastic.
In other words, all of the kinetic energy that the tennis ball had before the collision is transferred back to the ball after the collision.
This would result in the tennis ball bouncing back up to its original height, which is the same height from which it was dropped.
The ball would continue to bounce up and down indefinitely, assuming there are no external forces acting on it.
In reality, it is impossible for a collision between a tennis ball and the earth to be perfectly elastic, as there are always external forces at play, such as air resistance and friction.
However, assuming no external forces, a coefficient of restitution of one would result in a perfectly elastic collision and the ball would bounce back up to its original height indefinitely.
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Why can't our current theories describe the conditions that existed in the universe during the Planck era
Current theories can't describe the conditions that existed in the universe during the Planck era because of energy fluctuation.
Who was Planck?He is referred to as the father of quantum mechanics and postulated that the energy of light is proportional to the frequency with the constant being referred to as planck's constant.
Current theories can't describe the conditions that existed in the universe during the Planck era because of energy fluctuation which led to the gravitational field to randomly warp space and time.
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why is it more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity?
It is more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity because of static friction.
Static friction refers to the resistance encountered when attempting to initiate the movement of two objects that are in contact with each other but not currently in motion relative to each other. When an object is at rest, the force of static friction acts in the opposite direction to any force applied to it.
In this case, the force applied to the carton is the force needed to start moving it from rest. The force of static friction is greater than the force applied to the carton, making it difficult to start moving the carton from rest.
Once the carton is moving with constant velocity, the force of static friction is no longer acting on it. The only force acting on the carton is the force that is applied to keep it moving at a constant velocity. This force is equal to the force of kinetic friction which is less than the force of static friction.
To summarize, the initial effort required to overcome the static friction between a heavy carton and its resting position is greater compared to the continuous force needed to maintain its constant velocity. The force of static friction is greater than the force applied to the carton, making it difficult to start moving the carton from rest.
Once the carton is moving with constant velocity, the force of static friction is no longer acting on it, and the only force acting on the carton is the force that is applied to keep it moving at a constant velocity.
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Please help me as soon as possible.
Answer:
true
Explanation:
calculate the height of the mercury in the tube above the surface in the trough. (Take air pressure = 1.0*1.0^5 pa & density of mercury = 136000 kg/m^3)
Answer:
Explanation:
To calculate the height of the mercury in the tube above the surface in the trough, we can use the following formula:
h = (P - P<sub>0</sub>) / ρg
where h is the height of the mercury column, P is the pressure at the bottom of the tube, P<sub>0</sub> is the atmospheric pressure, ρ is the density of the mercury, and g is the acceleration due to gravity.
Since the pressure at the bottom of the tube is due to the weight of the mercury column above it, we can also express P as P = ρgh, where h is the height of the mercury column in the tube.
Substituting this expression for P into the formula above, we get:
h = (ρgh - P<sub>0</sub>) / ρg
Simplifying this expression, we get:
h = h - P<sub>0</sub> / g
Solving for h, we get:
h = P<sub>0</sub> / ρg
Substituting the given values, we get:
h = (1.0 x 10<sup>5</sup> Pa) / (136000 kg/m<sup>3</sup> x 9.81 m/s<sup>2</sup>)
h = 0.073 m
Therefore, the height of the mercury in the tube above the surface in the trough is approximately 0.073 meters.
compare the physical properties of air and gold .
Answer:
Gold is metallic, with a yellow color when in a mass, but when finely divided it may be black, ruby, or purple. It is the most malleable and ductile metal; 1 ounce (28 g) of gold can be beaten out to 300 square feet. It is a soft metal and is usually alloyed to give it more strength.
Formula --
Molecular Weight (lb/m o l) 28.96
Critical Temp. (°F) N/A
Critical Pressure (p s i a) N/A
Boiling Point (°F) -317.8
Melting Point (°F) N/A
Psat 70°F (p s i a) (note 1)
Explanation:
how to make a brainliest questions Or how to Get them?
Answer:
Select the crown at the bottom of an answer where the speech bubble icon is.
A boat of mass 250 kg is coasting, with its engine in neutral, through the water at speed 3.00 m/s when it starts to rain. The rain is falling vertically, and it accumulates in the boat at the rate of 10.0 kg/hr.
What is the speed of the boat after time 2.00 hr has passed? Assume that the water resistance is negligible.
Express your answer in meters per second.
The rate of acceleration due to the increase in the mass of the boat is 0.04 m/s2.
The mass of the boat is 250 kg and it is coasting through the water at speed 3.00 m/s with its engine in neutral. The rain is falling vertically and accumulating in the boat at the rate of 10.0 kg/hr.
To calculate the rate of acceleration due to the increase in the mass of the boat, we will use the equation F = ma. F is the force, m is the mass, and a is the acceleration. We know the force (10.0 kg/hr) and the mass (250 kg) so we can calculate the acceleration:
a = F/m
= 10.0 kg/hr / 250 kg
= 0.04 m/s2
This is the rate of acceleration due to the increase in mass of the boat. The boat's speed will therefore increase by 0.04 m/s each second. If the initial speed of the boat is 3.00 m/s, the speed after one second will be 3.04 m/s, and so on. The boat's speed will continue to increase as the mass of the boat increases due to the rain.
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Apakah yang berlaku kepada kekuatan medan magnet jika satu lagi sel kering 1.5 v ditambahkan
Answer:
The magnetic field is doubled.
Explanation:
What happens to the strength of the magnetic field if one more 1.5 v dry cell is added?
The magnetic field due to a current carrying conductor is directly proportional to the current flowing in the wire.
If we connect one more battery of 1.5 V so the voltage is doubled and according to the Ohm's law, as the resistance of wire is constant, so the current in the wire is also doubled.
When the current doubles, the magnetic field produced by the wire is also doubled.
A force of 73.8 newtons is applied to travel bag at an angle 39.0° with the horizontal. What are the horizontal and vertical components of the force? A. Fx = 57.4 newtons and Fy = 46.4 newtons B. Fx = 46.4 newtons and Fy = 57.4 newtons C. Fx = 57.4 newtons and Fy = 57.4 newtons D. Fx = 46.4 newtons and Fy = 46.4 newtons
The horizontal component of the force is 57.4 N and the vertical component of the force is 46.4 N (option A)
How do I determine the horizontal component of force?The horizontal component of the force can be obtained as follow:
Force applied (F) = 73.8 NewtonsAngle of projection (θ) = 39 °Horizontal component of force (Fx) =?Horizontal component of force (Fx) = F × Cosθ
Fx = 73.8 × Cos 39
Fx = 57.4 N
Thus, the horizontal component of force is 57.4 N
How do I determine the vertical component of force?The vertical component of the force can be obtained as follow:
Force applied (F) = 73.8 NewtonsAngle of projection (θ) = 39 °Vertical component of force (Fy) =?Vertical component of velocity (Fy) = u × Sine θ
Fy = 73.8 × Sine 39
Fy = 46.4 N
Thus, the vertical component of force is 46.4 N
Therefore, the correct answer to the question is Fx = 57.4 N and Fy = 46.4 N (option A)
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Why do you think the lunar cycle is longer than the time it takes the moon to orbit Earth?
Answer:
because the moon returns to the same place on the sky once every siderial period, but the sun is also moving on the sky.
Explanation:
Hope that helps!
Answer:
Because the moon returns to the same place on the sky once every siderial period (27.3 days), but the sun is also moving on the sky.Cycle of lunar phases takes 29.5 days. This is called the SYNODIC PERIOD
Explanation:
Read the following prompt and type your response in the space provided. Please help asap this is for my science unit test. ty loves <3
4.09 Unit Test: Geologic History - Part 2
Imagine you are a paleontologist and you found a coprolite in a rock layer at the edge of a sea cliff in Africa. Later you found the same type of coprolite in a rock layer at the bottom of a low valley in South America. What could you conclude?
Answer:
That 1st, they went through the same period. 2nd South America was lower once than Africa?
Explanation:
This is one of those things I'm not 100% sure about
Find the direction of the sum ofthese two vectors:BW TOT60.0 °85.0 mA
We are given two vectors and we are asked to determine the direction of their sum. To do that we will rewrite them on coordinates form. For vector A, since it is a horizontal vector it only has an x-coordinate equivalent to its magnitude, like this:
\(A=(85,0)\)For vector B we will use the following formula:
\(B=(\lvert B\rvert\cos \theta,\lvert B\rvert\sin \theta)\)Replacing the values:
\(B=(101\cos 60,101\sin 60)\)Solving the operations
\(undefined\)a person stands on a scale in an elevator. as the elevator starts, the scale has a constant reading of 598 n. as the elevator later stops, the scale reading is 384 n. assume the magnitude of the acceleration is the same during starting and stopping. (a) determine the weight of the person. n (b) determine the person's mass. kg (c) determine the magnitude of acceleration of the elevator.
The magnitude of the acceleration of the elevator is approximately 3.51 \(m/s^2\).
(a) The scale reading when the elevator is at rest gives the normal force acting on the person, which is equal in magnitude to the person's weight. Thus, the weight of the person is 598 N when the elevator is at rest.
(b) The weight of an object is given by the product of its mass and the acceleration due to gravity.
weight = mass x acceleration due to gravity
598 N = mass x 9.81 \(m/s^2\)
mass = 60.9 kg
Therefore, the person's mass is approximately 60.9 kg.
(c) We can use Newton's second law (F = ma) to find the acceleration of the elevator. The net force acting on the person is given by:
net force = final force - initial force
net force = 384 N - 598 N
net force = -214 N
net force = mass x acceleration
-214 N = 60.9 kg x acceleration
acceleration = -3.51 \(m/s^2\)
Therefore, the magnitude of the acceleration of the elevator is approximately 3.51 \(m/s^2\).
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Distance =S=u′t+1/2a′t2 12=0.t+1/2a′t2 12=1/2∗0.3∗t2 t2=80,t=8.944 s 8.944 s passes before the front bumper are lined up. S= constant=1/2 (a1−a2)t2 t=a1−a22 S
that means t[infinity](a1−a2) 1 time inversely proportional to acceleration approach. as a2→a1, relative acceleration decreases, that time to approach increases. Relative acceleration of the car a′= (SUV car acceleration - truck bumper acceleration) =(2.1−1.8) m/s2=0.3 m/s2 initial velocity of both vehicles =Vi m/s Distance in between their front bumper S=12 m Relative velocity u′=SUV initial velocity - truck initial velocity =Vi−Vi =0
The problem statement provides the following information: The distance between the front bumpers of the SUV and the truck is 12 meters. The acceleration of the SUV is a1 = 2.1 m/s^2.
The acceleration of the truck is a2 = 1.8 m/s^2.
The initial velocity of both vehicles is Vi.
The relative velocity between the vehicles is 0 m/s.
Using the kinematic equation for distance (S), we can calculate the time it takes for the front bumpers to line up: S = u't + 1/2 a't^2; where u' is the relative velocity (0 m/s), and a' is the relative acceleration between the vehicles (a1 - a2 = 2.1 - 1.8 = 0.3 m/s^2).
Substituting the given values for S and a', we get: 12 = 0*t + 1/2 * 0.3 * t^2
Simplifying the equation, we get: 0.15t^2 = 12; t^2 = 80; t = 8.944 seconds (rounded to three decimal places)
Therefore, it takes 8.944 seconds for the front bumpers of the SUV and truck to line up.
Using the formula for time (t) in terms of distance (S) and relative acceleration (a'), we can see that time is inversely proportional to acceleration: t = (a1 - a2)/(2*S)
This means that as the relative acceleration (a') approaches zero (when a2 approaches a1), the time to approach also increases.
Since the relative acceleration between the vehicles is 0.3 m/s^2, we can conclude that the time to approach is relatively short. However, if the truck's acceleration approaches that of the SUV, the time to approach would increase.
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URGENT‼
Physics Angled Projectile
Answer:
5. 0.5 m/s
6. 2.06 m/s
7. 0.22 m
Explanation:
From the question given above, the following data were obtained:
Horizontal range (Rₓ) = 0.21 m
Time of flight (T) = 0.421 s
Time (t) to reach the top = 0.2105 s
5. Determination of the horizontal velocity of the ball.
Horizontal range (Rₓ) = 0.21 m
Time of flight (T) = 0.421 s
Horizontal velocity (vₓ) =?
Rₓ = vₓ × T
0.21 = vₓ × 0.421
Divide both side by 0.421
vₓ = 0.21 / 0.421
vₓ = 0.5 m/s
Thus, the horizontal velocity is 0.5 m/s.
6. Determination of the initial vertical velocity of the ball.
Time (t) to reach the top = 0.2105 s
Final vertical velocity (vբᵧ) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Initial vertical velocity (vᵢᵧ) =?
vբᵧ = vᵢᵧ – gt (ball is going against gravity
0 = vᵢᵧ – (9.8 × 0.2105)
0 = vᵢᵧ – 2.06
Collect like terms
0 + 2.06 = vᵢᵧ
vᵢᵧ = 2.06 m/s
Thus, the initial vertical velocity of the ball is 2.06 m/s.
7. Determination of the maximum height reached by the ball.
Time (t) to reach the top = 0.2105 s
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =?
h = ½gt²
h = ½ × 9.8 × 0.2105²
h = 4.9 × 0.2105²
h = 0.22 m
Thus, the maximum height reached by the ball is 0.22 m
A young diver is practicing his skills before an important team competition. Use the diagram below in order to analyze the energies of the diver and complete the statements below.
Where m = mass (kg), g = 9.8 m/s2, v = velocity (m/s), h = height (m), KE = kinetic energy (J), and GPE = gravitational potential energy (J).
Use the equations above to answer the following questions.
A diver with a mass of 90 kg is at a height of 10 m, and he has not jumped off of the board yet (v = 0 m/s). When the diver reaches a height of 5 m (Point C), his gravitational potential energy is
A. 1350 J
B. 8820 J
C. 4410 J
D. 0 J
and his velocity is
E. 4.5 m/s
F. 0 m/s
G. 3.2 m/s
H. 9.9 m/s
Please help will mark brainliest
Answers:
The gravitational potential energy of the diver when he reaches point C is 4410 J.
The velocity of the diver is 9.9 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
\(\\ \sf\longmapsto PE=mgh\)
\(\\ \sf\longmapsto PE=90(5)(9.8)\)
\(\\ \sf\longmapsto PE=4410J\)
Now
It's converted to kinetic energy while reaching ground.
\(\\ \sf\longmapsto K.E=4410\)
\(\\ \sf\longmapsto \dfrac{1}{2}mv^2=4410\)
\(\\ \sf\longmapsto 90v^2=8820\)
\(\\ \sf\longmapsto v^2=98\)
\(\\ \sf\longmapsto v=9.9m/s\)
You are stationary and you observe a frisbee being thrown out of a car. The car is going 20 m/s to the right. The frisbee is thrown at a speed of 10 m/s (relative to the car) to the right. How fast do you see the frisbee fly by, and in which direction
Answer:
V = Vcar + Vfrisbee = 20 m/s + 10 m/s = 30 m/s
V has the same sign for the car and the frisbee and the "Galilean Transformation" has the same sign for both velocities.
you would see the frisbee fly by at a speed of 30 m/s to the right, in the same direction as the car.
What is relative speed?Relative speed is the speed of an object or observer with respect to another object or observer. It is the speed at which one object appears to be moving relative to another object.
Relative speed is calculated by subtracting the velocity of one object from the velocity of another object. If the two objects are moving in the same direction, we subtract the smaller velocity from the larger velocity. If they are moving in opposite directions, we add the velocities together.
Here in the Question,
As the frisbee is being thrown out of the car, we can assume that it is also moving to the right at the same speed as the car, which is 20 m/s. Therefore, the frisbee has a velocity of 20 m/s to the right relative to the ground before it is thrown.
When the frisbee is thrown at a speed of 10 m/s (relative to the car) to the right, its velocity relative to the ground can be found by adding the velocity of the car to the velocity of the frisbee relative to the car. Using the principle of vector addition, we get:
velocity of frisbee relative to ground = velocity of car + velocity of frisbee relative to car
velocity of frisbee relative to ground = 20 m/s to the right + 10 m/s to the right
velocity of frisbee relative to ground = 30 m/s to the right
Therefore, The frisbee would pass by you to the right, moving at a speed of 30 m/s, in the same direction as the car.
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\(what \: is \: amplitude \: {?} \)
Answer:
The amplitude is a measure of its change in a single period (such as time or spatial period)
what is amplitude?
Answer:A periodic variable's amplitude is a measure of its change across a single period, such as time or space. Amplitude is defined in a variety of ways, but they're all based on the size of the disparities between the variable's extreme values. The amplitude of a periodic function is sometimes referred to as the phase in older writings texts.
-------------------------hope it helps...have a great day!!How can I rewrite the equation a - b = d using addition?
Explanation:
A=b+d that is the way to rewrite the equation
At the advertising agency, decision-making power flows downward. The partners make the rules and pass them on to the junior partners, who then pass them down to the ad executives, who then pass them on to the administrative assistants. This reflects which characteristic of bureaucracy
The given scenario exemplifies the characteristic of hierarchy in a bureaucratic organization where decision-making power flows downwards.
The given scenario reflects the characteristic of hierarchy in bureaucracy.
In a bureaucratic structure, decisions and authority flow in a hierarchical manner from the top level to the lower levels. The partners in the advertising agency represent the top level of authority and decision-making, followed by junior partners, ad executives, and administrative assistants. This reflects the typical hierarchy in a bureaucratic organization where the top-level managers make the rules and policies that are implemented by the lower-level employees.
Therefore, the given scenario exemplifies the characteristic of hierarchy in a bureaucratic organization where decision-making power flows downwards.
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Need Help With Physical Ed
which of the following is not a barrier to physical activity it is fear of injury I think.
The relation "having the same color" is reflexive. True False
The relation of having the same color is reflexive. Therefore, the statement is true.
A reflexive relation is one in which every element maps its own component. Every component of the set reflects itself in its own image.
A reflexive relation on a set I is also represented as L = {(a, a): a ∈ I}, where I L ⊆ R and R is a relation defined on the set I.
According to the question,
if we have the same color, y
then,
(y, y) belongs to R
Therefore, color y and color y have the same color.
Hence, the relation between color y and R is reflexive. The statement is true.
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In a controlled experiment,
a) control group is compared to an experimental group.
B) there are only 2 variables.
c) a variable is not needed
D) all factors should be the same.
In a controlled experiment, control group is compared to an experimental group.
The correct option is A.
What is a controlled experiment meaning?In experiments, independent variables are changed to see how they effect dependent variables. In a controlled experiment, every factor besides the independent variable is kept under control or constant to ensure that it has no impact on the dependent variable.
How are controlled experiments conducted?To reduce potential confounding factors in controlled experiments, researchers randomly assign participants to either the experimental group or the control group. The experimental group is the group that receives the variable, or treatment, that the researchers are testing, whereas the control group does not.
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A ray of light is incident on a square slab of transparent
plastic in air. It strikes the centre of one side at an angle of
61
Find the minimum refractive index of the plastic if the light is
to be to
To achieve total internal reflection, the minimum refractive index of the plastic must be at least 0.869 when a ray of light is incident at an angle of 61 degrees on the center of one side of the plastic slab in air.
The minimum refractive index of the plastic can be found , we need to consider the conditions for total internal reflection.
Total internal reflection occurs when the angle of incidence is greater than the critical angle, which is the angle at which the refracted ray is at a 90-degree angle to the normal.
In this scenario, the ray of light is incident on the plastic at an angle of 61 degrees. We can use Snell's law to relate the angle of incidence to the angle of refraction:
n1 * sin(angle of incidence) = n2 * sin(angle of refraction)
Here, n1 is the refractive index of air (approximately 1), and n2 is the refractive index of the plastic.
Since we want the light to be totally internally reflected, the angle of refraction will be 90 degrees. Thus, we have:
1 * sin(61 degrees) = n2 * sin(90 degrees)
Rearranging the equation, we get:
n2 = sin(61 degrees) / sin(90 degrees)
Calculating this expression, we find that n2 is approximately 0.869.
Therefore, the minimum refractive index of the plastic should be at least 0.869 to ensure total internal reflection in this scenario.
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Complete question:
A ray of light is incident on a square slab of transparent plastic in air. It strikes the center of one side at an angle of 61 degrees. Find the minimum refractive index of the plastic if the light is to be totally internally reflected.
Problem 2: Solve the logarithmic equation. \[ \log _{2}(5 x-2)-2=1 \]
Given the logarithmic equation \[ \log _{2}(5 x-2)-2=1 \], we need to solve for x. We can begin by first adding 2 to both sides of the equation, which gives\[ \log _{2}(5 x-2) = 3 \]
Next, we will convert the logarithmic equation to exponential form using the definition of logarithms.
Recall that \[\log_a b = c \iff a^c = b\]
Therefore, we get \[2^3 = 5x - 2\]
Evaluating the left hand side, we get \[2^3 = 8\]
So the equation now becomes \[8 = 5x - 2\]
Adding 2 to both sides of the equation gives\[10 = 5x\]
Dividing both sides by 5, we get\[x = 2\]
Therefore, the solution to the logarithmic equation \[ \log _{2}(5 x-2)-2=1 \] is \[x = 2\].
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you are measuring the n-th harmonic of a string, you found that when n=4, the harmonic frequency is 1,362hz. what is the string's fundamental frequency?
This means that the string is vibrating at a fundamental frequency of 340.5 Hz when it is in its first harmonic state.
The fundamental frequency of a string is the lowest frequency at which it vibrates, and is sometimes referred to as the first harmonic. The higher harmonics are integer multiples of the fundamental frequency, so if you know the frequency of one of the higher harmonics, you can find the fundamental frequency.
In this case, you have measured the fourth harmonic, with a frequency of 1,362 Hz. Therefore, the fundamental frequency can be found by dividing the harmonic frequency by the harmonic number:
fundamental frequency = harmonic frequency / harmonic number
fundamental frequency = 1,362 Hz / 4 = 340.5 Hz
The higher harmonics are multiples of the fundamental frequency, so the fourth harmonic will have a frequency of 4 times the fundamental frequency.
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What are organs made of?
O Organs are made of colections of tissues,
O Organs are made of cells, but not tissues.
O Organs are made of collections of other
O Organs are made of muscle and bone.
DONE
Answer:
Organs are made of collections of tissues, which are groups of cells.
Explanation:
which car traveled at an average speed of about 20 km/hr?
Answer:
car b
Explanation:
b is 2/3 of the way to 30 km an hour so that means its 20