Excepted packaging refers to fiberboard boxes, sturdy wooden boxes, or steel crates that are designed to transport:

When the variables are expressed in terms of fundamental dimensions, we get:

In physics, derived units are units that are formed by combining fundamental units such as length, mass, time, temperature, and electric charge. For example, velocity is a derived unit that combines length and time, expressed as meters per second (m/s).

The questions 24 to 29 are asking to express the given quantities in terms of fundamental dimensions. The unit of absorbed radiation dose is the joule per kilogram (J/kg).

The unit of electrical field is volts per meter (V/m). The unit of acoustic impedance is pascals per second per meter (Pa s/m). The unit of magnetic permeability is henries per meter (H/m). The unit of ideal gas constant is atmospheres times liters per mole times kelvin (atm L/(mol K)).

Find out more on fundamental dimensions at https://brainly.com/question/13109090

#SPJ1

Answer:

52m/s

12 kpa

0.1 kg/m

Explanation:

make me brainless tyyy

Answer:

the output of the IF amplifier consist of 675 kHz

Explanation:

Given the data in the question;

AM signal carrier frequency \(_{RF\)  = 460 kHz

Local oscillator frequency\(_{lo\) = 1135 kHz

Now, The output of the IF amplifier consists of difference of local oscillator frequency & AM carrier signal frequency;

FREQUECY\(_{IF\) = FREQUECY\(_{lo\) - FREQUECY\(_{RF\)

so we substitute in our given values

FREQUECY\(_{IF\) = 1135 kHz - 460 kHz

FREQUECY\(_{IF\) = 675 kHz

Therefore, the output of the IF amplifier consist of 675 kHz

Answer:

ANSI A sized paper is commonly referred to as Letter and ANSI B as Ledger or Tabloid.

Explanation:

Answer:

it's not included

Explanation:

plz exact ur explain

Answer:

si amor

Explanation:

Hoiykñjdnlklbutrk

Explanation:

sory sorry sorry sorrysorrysorry

Answer:

true

Explanation:

i took the test and got it right

The threshold when no explicit rule is in effect is six feet, which is the standard rule for the construction industry.

To learn more about OSHA refer

https://brainly.com/question/13591663

#SPJ4

Answer:

If you are driving below 40 mph, you should leave at least one second for every 10 feet of vehicle length.

A bend is defined as a change in the shape of the part between the damaged and undamaged area that is smooth and continuous.

What is a kink?

A kink can be defined as a sharp bend with a small radius over a short distance.

So when any part is kinked it must be replaced without any doubt. A part is kinked if it just doesn't work on the repair.

What is a bend?

Unlike a kink, a bend can be restored. That is after a bend also  a part can be bought back to its original position.

When the part is straightened, it is returned to proper shape and state without any areas of permanent deformation.

To know more about bend visit:

https://brainly.com/question/27937041

#SPJ9

Answer:

The answer could be correct

Explanation:

According to your explanation this would really help out the Analyze the example of this band saw wheel and axle. The diameter of the wheel is 14 inches. The diameter of the axle that drives the wheel is 3/4 inch. The actual force needed to cut through a one-inch-thick softwood board is 1.75 pounds. Consider the efficiency of this band saw to be 22%.

Questions: Calculate ideal mechanical advantage when the effort force is applied to the axle.

Questions: considering the efficiency calculate the actual mechanical advantage of the wheel and axle.

Questions: If you used the same wheel and axle in a different way and applied effort force to the wheel to drive the axle, what is the ideal mechanical advantage of the wheel and axle?

The article on ACM Code of Ethics and Professional Conduct is given as follows.

The ACM Code of Ethics and Professional Conduct provides a framework for ethical behavior in computing professions. As an undergraduate computing student, adherence to the Code is crucial as it not only guides behavior but also establishes a professional identity. One of the Code's principles, "Avoid harm to others" (1.1), highlights the importance of ensuring that computing activities do not cause harm to others. In practice, this means ensuring the security and privacy of user data and avoiding the creation of software that could be used to cause harm. As an undergraduate computing student, this principle should guide decisions related to class projects and personal projects.

Another principle of the ACM Code that is relevant to undergraduate computing students is "Honor confidentiality" (1.2). This principle stresses the importance of respecting the confidentiality of user data, personal information, and other sensitive information. As computing becomes increasingly integrated into everyday life, the potential for misuse of personal data has increased. Adhering to this principle means that undergraduate computing students must prioritize the privacy of user data in their projects and research. Additionally, they must be mindful of their own personal data and ensure that they do not misuse sensitive information.

A third principle of the ACM Code that is relevant to undergraduate computing students is "Be honest and trustworthy" (1.3). This principle emphasizes the importance of honesty in computing activities. In practice, this means avoiding plagiarism, ensuring that credit is given to other sources, and accurately representing one's own work. Honesty and trustworthiness are fundamental components of professional behavior and must be upheld by all computing professionals. As an undergraduate computing student, it is important to prioritize honesty in academic work and personal projects.

In conclusion, the ACM Code of Ethics and Professional Conduct provides a set of guidelines for ethical behavior in computing professions. As an undergraduate computing student, adherence to the Code is important as it establishes a professional identity and promotes ethical behavior. The principles of "Avoid harm to others," "Honor confidentiality," and "Be honest and trustworthy" are particularly relevant to undergraduate computing students and should guide behavior in class projects and personal projects. By upholding these principles, undergraduate computing students can contribute to a more ethical computing profession.

Learn more about ACM Code of Ethics and Professional Conduct at:

https://brainly.com/question/13960327?

#SPJ1

Solution :

Given :

External diameter of the hemispherical shell, D = 500 mm

Thickness, t = 20 mm

Internal diameter, d = D - 2t

                                 = 500 - 2(20)

                                 = 460 mm

So, internal radius, r = 230 mm

                                 = 0.23 m

Density of molten metal, ρ = \($7.2 \ g/cm^3$\)

                                                  = \($7200 \ kg/m^3$\)

The height of pouring cavity above parting surface is h = 300 mm

                                                                                                  = 0.3 m

So, the metallostatic thrust on the upper mold at the end of casting is :

\($F=\rho g A h$\)

Area, A \($=2 \pi r^2$\)

            \($=2 \pi (0.23)^2$\)

            \($=0.3324 \ m^2$\)

\($F=\rho g A h$\)

   \($=7200 \times 9.81 \times 0.3324 \times 0.3$\)

     = 7043.42 N

The average daily flow of water in 10 years would be 21,249 m³/day.

To estimate the average daily flow of water in 10 years,

we have to use the current population and water consumption as a baseline.

We have to find the daily water consumption for the current population,

⇒ 6,083,270 m³ / 365 days = 16,676 m³/day

Now we have to calculate the expected water consumption for the future population,

= 16,676 m³/day x (73,728 / 58,000) = 21,249 m³/day

Therefore,

We can estimate that the average daily flow of water in 10 years would be 21,249 m³/day.

To know more about average visit:-

brainly.com/question/24057012

#SPJ4

Answer:

The right solution is "2625 kN".

Explanation:

According to the question,

The average pressure will be:

= \(density\times g\times \frac{h}{2}\)

By putting values, we get

= \(1000\times 9.8\times \frac{12.2}{2}\)

= \(1000\times 9.8\times 6.1\)

= \(59780\)

hence,

The average force will be:

= \(Pressure\times Area\)

= \(59780\times 3.6\times 12.2\)

= \(2625537 \ N\)

Or,

= \(2625 \ kN\)

20

Explanation:

Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A​

Answer:people tend to do this when they are in a different environment they lose something or just have something going on in their life

Explanation:

Answer:

None of the above cause thats what i put

According to Collins and Quillian's semantic network model, it would take the longest to verify the statement "A turtle is related to a fish" out of the given options.

Explanation: Collins and Quillian's semantic network model is based on the concept of hierarchical organization of knowledge. According to this model, verifying a statement takes longer when it involves traversing more levels in the semantic network. In the given options, the statement "A turtle is related to a fish" requires traversing multiple levels in the network to establish the relationship between turtles and fish. The model suggests that verifying this statement would take longer compared to the other statements.

On the other hand, the statement "A turtle is an amphibian" would take less time to verify because it involves a direct link between turtles and amphibians. Similarly, the statement "A turtle is an animal" would also be relatively easier to verify as it involves a single level traversal in the semantic network. Finally, the statement "Turtles are turtles" is a self-referential statement and would be the easiest to verify since it only requires confirming the identity of turtles.

To learn more about Quillian's semantic network refer:

https://brainly.com/question/29317050

#SPJ11

Answer:

Object-Oriented Software Engineering Using UML, Patterns, and Java, 3e, shows readers how to use both the principles of software engineering and the practices of various object-oriented tools, processes, and products.

Answer:

2)

a)  to the right of the dipole    E_total = kq [1 / (r + a)² - 1 / r²]

b)To the left of the dipole      E_total = - k q [1 / r² - 1 / (r + a)²]

c) at a point between the dipole, that is -a <x <a  

      E_total = kq [1 / x² + 1 / (2a-x)²]

d) on the vertical line at the midpoint of the dipole (x = 0)

E_toal = 2 kq 1 / (a ​​+ y)² cos θ

Explanation:

2) they ask us for the electric field in different positions between the dipole and a point of interest. Using the principle of superposition.

This principle states that we can analyze the field created by each charge separately and add its value and this will be the field at that point

Let's analyze each point separately.

The test charge is a positive charge and in the reference frame it is at the midpoint between the two charges.

a) to the right of the dipole

The electric charge creates an outgoing field, to the right, but as it is further away the field is of less intensity

           E₊ = k q / (r + a)²

where 2a is the distance between the charges of the dipole and the field is to the right

the negative charge creates an incoming field of magnitude

           E₋ = -k q / r²

The field is to the left

therefore the total field is the sum of these two fields

           E_total = E₊ + E₋

           E_total = kq [1 / (r + a)² - 1 / r²]

we can see that the field to the right of the dipole is incoming and of magnitude more similar to the field of the negative charge as the distance increases.

b) To the left of the dipole

The result is similar to the previous one by the opposite sign, since the closest charge is the positive one

E₊ is to the left and E₋ is to the right

          E_total = - k q [1 / r² - 1 / (r + a)²]

We see that this field is also directed to the left

c) at a point between the dipole, that is -a <x <a

In this case the E₊ field points to the right and the E₋ field points to the right

                      E₊ = k q 1 / x²

                      E₋ = k q 1 / (2a-x)²

                      E_total = kq [1 / x² + 1 / (2a-x)²]

in this case the field points to the right

d) on the vertical line at the midpoint of the dipole (x = 0)

    In this case the E₊ field points in the direction of the positive charge and the test charge

    in E₋ field the ni is between the test charge and the negative charge,

the resultant of a horizontal field in zirconium on the x axis (where the negative charge is)

                      E₊ = kq 1 / (a ​​+ y) 2

                      E₋ = kp 1 / (a ​​+ y) 2

                      E_total = E₊ₓ + E_{-x}

                      E_toal = 2 kq 1 / (a ​​+ y)² cos θ

e) same as the previous part, but on the negative side

                        E_toal = 2 kq 1 / (a ​​+ y)² cos θ

When analyzing the previous answer there is no point where the field is zero

The different configurations are outlined in the attached

3) We are asked to repeat part 2 changing the negative charge for a positive one, so in this case the two charges are positive

a) to the right

in this case the two field goes to the right

           E_total = kq [1 / (r + a)² + 1 / r²]

b) to the left

            E_total = - kq [1 / (r + a)² + 1 / r²]

c) between the two charges

E₊ goes to the right

E₋ goes to the left

            E_total = kq [1 / x² - 1 / (2a-x)²]

d) between vertical line at x = 0

E₊ salient between test charge and positive charge

           E_total = 2 kq 1 / (a ​​+ y)² sin θ

In this configuration at the point between the two charges the field is zero

To determine the magnitude of the counterweight W for which the maximum absolute value of the bending moment in the beam is as small as possible, we need to draw the bending-moment diagram. The diagram will show the variation of the bending moment along the length of the beam.

Assuming that the beam is simply supported, the bending moment diagram will be a parabolic curve. The maximum absolute value of the bending moment occurs at the mid-span of the beam. To make this value as small as possible, we need to add a counterweight at this point.

Let W be the magnitude of the counterweight. By adding the counterweight, we are essentially creating a new force couple that acts in the opposite direction of the original load. The magnitude of this force couple is equal to the weight of the counterweight multiplied by the distance between the counterweight and the load.

To find the distance between the counterweight and the load, we need to use the principle of moments. The moment due to the counterweight is equal to the weight of the counterweight multiplied by the distance between the counterweight and the mid-span of the beam. The moment due to the load is equal to the load multiplied by half the span of the beam.

Setting the two moments equal and solving for the distance between the counterweight and the mid-span of the beam, we get:

W × x = P × L/2

where P is the load on the beam, L is the span of the beam, and x is the distance between the counterweight and the mid-span of the beam.

Substituting x into the equation for the moment due to the counterweight, we get:

M = W × (L/2 - x)

The bending moment at the mid-span of the beam due to the load is given by:

M = P × L/4

To make the maximum absolute value of the bending moment as small as possible, we need to equate the absolute values of the largest and negative bending moments obtained. That is:

|W × (L/2 - x)| = |P × L/4|

Solving for W, we get:

W = (P × L/4) / (L/2 - x)

Now we can find the corresponding maximum normal stress due to bending. The maximum normal stress occurs at the top and bottom fibers of the beam at the mid-span. The maximum normal stress due to bending is given by:

σ = (M × c) / I

where c is the distance from the neutral axis to the top or bottom fiber, and I is the moment of inertia of the beam.

For a rectangular cross-section beam, the moment of inertia is given by:

I = (b × h^3) / 12

where b is the width of the beam, and h is the height of the beam.

Substituting the values for M, c, and I, we get:

σ = (P × L/4) × (h/2) / ((b × h^3) / 12)

Simplifying, we get:

σ = (3 × P × L) / (2 × b × h^2)

So, the magnitude of the counterweight W for which the maximum absolute value of the bending moment in the beam is as small as possible is given by:

W = (P × L/4) / (L/2 - x)

And the corresponding maximum normal stress due to bending is given by:

σ = (3 × P × L) / (2 × b × h^2)

learn more about https://brainly.in/question/31621889

#SPJ11

Answer:

Use GitHub or stackoverflow for this answer

Explanation:

It helps with programming a lot

Excitons play a crucial role in silicon solar cells and are involved in several processes that contribute to the generation of electricity. Here are some key roles of excitons in silicon solar cells:

1. Absorption of Photons: When photons from sunlight strike the silicon material of a solar cell, they can be absorbed by silicon atoms, promoting an electron from the valence band to the conduction band. This process creates an exciton—a bound electron-hole pair.

2. Exciton Diffusion: After absorption, excitons can diffuse through the silicon material, moving towards the region of the solar cell where charge separation occurs. This diffusion process allows excitons to reach the vicinity of the p-n junction, where the separation of charges takes place.

3. Exciton Dissociation: At the p-n junction of a silicon solar cell, excitons can undergo dissociation. The electric field created by the junction separates the electron and hole of the exciton, allowing them to move freely in opposite directions as charge carriers.

4. Electron and Hole Transport: Once the exciton is dissociated, the free electron and hole can move independently within the solar cell. They are transported through the silicon material to the respective electrodes, creating an electric current that can be harnessed for external use.

5. Recombination: Excitons can also undergo recombination, where the electron and hole recombine, releasing energy in the form of light or heat. Recombination is undesirable in solar cells as it reduces the overall efficiency of the device.

To enhance the efficiency of silicon solar cells, various strategies are employed to minimize exciton recombination and improve exciton dissociation and charge carrier transport. These include the use of anti-reflection coatings, surface passivation techniques, and optimization of the device structure.

Overall, excitons play a vital role in the absorption and conversion of sunlight into electrical energy in silicon solar cells. Understanding and controlling exciton dynamics are essential for improving the performance of solar cells and advancing the field of photovoltaics.

Learn more about silicon solar cells here:

https://brainly.com/question/32456926

#SPJ11

Answer:

  4800 watts

Explanation:

Power is the product of voltage and current:

  P = VI = (240 V)(20 A) = 4800 W

The wattage is 4800 watts.

The design brief that identified the problem of mine headgear is:

The structural structure above an underground mine shaft that facilitates the hoisting of machinery, persons, or supplies is known as a headframe (also called as a gallows frame, winding tower, hoist frame, pit frame, shafthead frame, headgear, headstock, or poppethead).

Mine headgear supports wheel systems that suspend winding cables that convey employees and ore up and down deep level shafts. These weird humanoid constructions have become the mining industry's defining emblem.

A miner's helmet consists of four major components:

Part 1: The hoist or winch is in a winding house. This component of the system is responsible for winding and unwinding the steel cable.

A motor and a control system are connected to the hoist.

When a steel cable unwinds from the winch, the mine cage and skips are lowered into the mine.

When the steel cable is wound up again, the mine cage and skips are elevated.

The sheave wheel is a pulley wheel that stands above the mining shaft in Part 2. The hoist rope travels over the sheave wheel and down the mine shaft.

The sheave wheel minimizes the mine cable's sliding friction.

Part 3: The head frame is the framework that holds the sheave wheel in place. When lifting the heavy mine cage, it must be robust enough to maintain the sheave wheel in place.

The head frame's left "legs" slope towards the hoist. This is due to the cable's strain dragging the entire frame in that direction. The sloping legs keep the head frame from tipping or collapsing.

Part 4: The cage and the jumps. Miners and equipment are transported up and down the mine in the cage. Skips are attached beside or beneath the cage.

Skips are used to transport ore and waste materials from mines.

A design brief, also called as a creative brief, is a program management document that identifies the scope, scale, and key aspects of your impending design project.

Learn more about design brief:

https://brainly.com/question/21422013

#SPJ1

Answer:

1) This is because too much fuel is needed to get a payload from the surface to orbital altitude an accelerated to orbital speed.

2) This is because space travel present extreme environment that affect machines operations and survival.

Explanation:

Hope it helps

sen yapsana mk halla halla yaw

Answer: Photo lines

Explanation: made more sense

Answer:

Employees may request a separate closing conference without the employer present.

Explanation:

it’s basically the answer lol