expand (x-2)^7 using binomial theorem
Answers
Answer:
x^7-14x^6+84x^5-280x^4+560x^3-672x^2+448x^2-128
Step-by-step explanation:
ends are x^7 and 120^7, and use the therom in the middle
Related Questions
Find the value of x. Write your answer in simplest form.
Answers
Answer:
\(x = \frac{9}{ \sqrt{2} } = \frac{9 \sqrt{2} }{2} \)
Type the correct answer in each box.
Day Amount
1
$26
2
$23
3
$31
4
$26
5
534
The table shows the amount Bill spent on 5 days last week.
The mean of the amount he spent is $
The mean absolute deviation is $
Reset
Next
Answers
The mean absolute deviation is $106.6.
Given the table shows the amount Bill spent on 5 days last week.
DayAmount12622313126534To find the mean of the amount he spent: The formula for calculating the mean of a given set of values is mean=∑x/n where x represents the values, n represents the number of values, and ∑x represents the sum of the values.
Mean=total sum of values/total number of values Mean=(26+23+31+26+534)/5Mean=640/5Mean=128So,
the mean of the amount he spent is $128.To find the mean absolute deviation: The mean absolute deviation (MAD) is the average distance between each data value and the mean. MAD shows how much the data set deviates from the mean. The formula for calculating the MAD is MAD=∑|xi−m|/n where xi represents the values, m represents the mean, and n represents the number of values. So, the calculation for each day is:
Day Amount Absolute deviation from mean1 26 |128-26|=102 23 |128-23|=105 31 |128-31|=974 26 |128-26|=102 534 |128-534|=406
The sum of all absolute deviations is:
10+10+97+10+406=533The mean absolute deviation (MAD) is: MAD=533/5=106.6So.
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In a programming team of 16 persons, 1/4 are women and 3/4 are men. To obtain a team with 40 percent women, how many women should be hired
Answers
Answer:
4 more woman. total women in the team = 8 women
Step-by-step explanation:
1/4 * 16 = 4 women and 16 - 4 = 12 men
8/20 * 100 = 40%
Answer:
Step-by-step explanation:
4
WS SAMPLE
Find the area of each sector. Round your answers to the nearest tenth.
13)
60° 10 in
Answers
Area of sector would be,
⇒ Area of sector = 102.6 feet squared
We have to given that,
Radius of circle = 14 ft
Angle θ = 60°
Now, We know that,
Area of sector = [θ/360]πr²
Where, r is radius of circle.
Hence, We can substitute all the values, we get;
Area of sector = [θ/360]πr²
Area of sector = [60/360](22/7)(14)²
Area of sector = [1/6][22/7][196]
Area of sector = 102.6 feet squared
Thus, Area of sector would be,
⇒ Area of sector = 102.6 feet squared
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The points (-2, 11) and (6, 3) lie on the same line.
What is the x-intercept of the line?
Answers
m=-7/8
----------------
y=mx+b
3=-7/8*6+b
3=-42/6+b
3=-7+b
b=10
-----------------
y=-7/8x+10
0-10=-7/8x
x=11.43
(11.43,0)
Answer:
Step-by-step explanation:
Kara categorized her spending for this month into four categories: Rent, Food, Fun, and Other. The amountsshe spent in each category are pictured here.Food$356Rent$444OtherFun$267$533What percent of her total spending did she spend on Rent? Answer to the nearest whole percent.%
Answers
hello
the question presented here deals with percentages
the percentage of a variable is the ratio of the value of that function to the total variable multiplied by 100
total categories = food + rent + other +fun
sum the value of everything
\(\begin{gathered} \text{total }=\text{ food }+\text{ rent }+\text{ fun }+\text{ other} \\ \text{total }=\text{ 356 }+\text{ 444 }+\text{ 533 }+\text{ 267} \\ \text{total }=\text{ \$1600} \end{gathered}\)she spends a total of $1600 for that month
the percentage of her total spending spent on rent = (rent / total spending) * 100
\(\text{percentage of rent }=\text{ }\frac{rent}{total\text{ spending}}\text{ }\times\text{ 100}\)\(\begin{gathered} \text{percentage of rent }=\text{ }\frac{444}{1600}\text{ }\times\text{ 100} \\ \text{percentage of rent }=\text{ 27.75\%} \end{gathered}\)the percentage of her monthly spending spent on rent is 27.75%
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Erica earned a total of $67,250 last year from her two jobs. The amount she earned from her job at the store was $1,250 more than three times the amount she earned from her job at the college. How much did she earn (in dollars) from her job at the college?
Answers
Step-by-step explanation:
x = earnings from the store
y = earnings from the college
x + y = 67,250
x = 3y + 1,250
now we use the identity of the second equation in the first equation :
(3y + 1,250) + y = 67,250
4y = 66,000
y = $16,500
x = 3y + 1,250 = 3×16,500 + 1,250 = 49,500 + 1,250 =
= $50,750
i will give Brainiest if you are right
Answers
Answer:
d) $7.82
Step-by-step explanation:
just multiply the 2 numbers
¿De qué número 64 es el 80%?
Answers
The monthly sale (in thousands of units) for the tth month after the introduction of a product in the market is given by S = 135t/(t2 + 50). In which earliest month would the sale (S) have been 9?
Answers
Answer: 3rd month
Step-by-step explanation:
S = 135t/(t2 + 50)
9=135t/(2t + 50)
9(2t+50)=135t
18t+450=135t
450=117t
t=3.85 ==> t=3rd month
PICTURES PROVIDED! PLEASE HELP!
I. Fill in the table below. You may want to go back and read the beginning for ideas. (And yes, if you like the way it smells when it bakes, that’s an advantage.) Put down any point you can think of.
J. Decision Time! Tell whether or not you have decided to buy the bread machine. Give several reasons for your decision.
Answers
The value of x is 24/7, by setting up and solving a proportion based on the fact that the two triangles in the figure are similar.
To find the value of x, we need to use the fact that the two triangles in the figure are similar. This means that the corresponding angles are equal, and the corresponding sides are in proportion.
We can see that the angle marked y is the same in both triangles. Therefore, we can set up the following proportion:
x / 8 = 12 / (12 + 16)
Simplifying the right-hand side, we get:
x / 8 = 12 / 28
Multiplying both sides by 8, we get:
x = 8 × (12 / 28)
Simplifying the right-hand side, we get:
x = 96 / 28
Dividing both the numerator and denominator by their greatest common factor, which is 4, we get:
x = 24 / 7
Therefore, the value of x is 24/7.
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What is -9 as a fraction?
Answers
Answer:
\(-\frac{9}{1}\)
Step-by-step explanation:
Its just the same way as making positive 9
a fraction, but just add the negative sign.
Hope this helps :))
What is 3 3/5 X 2 1/4
Answers
Answer:
Step-by-step explanation:
answer is below
A man is 4 times as old as his son. In 5 years time he will be 3 times as old as his son. What is the present age of the son in years.
Answers
Answer: 40 years old.
Step-by-step explanation:
Let man's age = a
Let son's age = b
Since a man is 4 times as old as his son, therefore
a= 4b
In 5 years, he will only be 3 times as old as his son, therefore
a+5=3(b+5)
Apply substitution method :
4b+5=3b+15
b=10
a=40
If u help u get brainleist and 15 points
Answers
Answer:
324 if its for volume
Step-by-step explanation:
L x W x H = 6 x 6 x 9
Can you help me solve this question
Answers
Answer:
t = 32
Step-by-step explanation:
The given equation is :
\(24=\dfrac{3}{4}t\) ....(1)
Where
t is the number of guests attending the catered event.
The reciprocal of \(\dfrac{3}{4}\) is \(\dfrac{4}{3}\).
Multiplying both sides by the reciprocal of \(\dfrac{3}{4}\).
\(24\times \dfrac{4}{3}=\dfrac{3}{4}\times \dfrac{4}{3}t\\\\t=8\times 4\\\\t=32\)
Hence, 32 guests will attend the catered.
$893.996 rounded to the nearest cent
Answers
Answer:
$893.666 rounded to the nearest cent is $894.00
please help me on this
Answers
Answer:
monkey is monkey so monkey and monkey conbided = baby little happy monkey
Step-by-step explanation:
A dairy needs 258 gallons of milk containing 7% butterfat how many gallons each of milk containing 8% butterfat and milk containing 2% butterfat must be used to obtain the desired 258 gallons
Answers
Let's assume x gallons of milk containing 8% butterfat and y gallons of milk containing 2% butterfat are used.
The total amount of milk is x + y gallons, and we want it to be equal to 258 gallons.
To determine the amount of butterfat in the mixture, we can multiply the volume of each type of milk by its respective butterfat percentage and sum them up.
For milk containing 8% butterfat, the amount of butterfat is 0.08x (8% is equivalent to 0.08 as a decimal).
For milk containing 2% butterfat, the amount of butterfat is 0.02y (2% is equivalent to 0.02 as a decimal).
Since we want the final mixture to contain 7% butterfat, we can set up the following equation:
0.08x + 0.02y = 0.07(258)
Simplifying the equation, we have:
0.08x + 0.02y = 18.06
To solve for x and y, we need another equation. Since the total amount of milk is x + y = 258, we can rearrange it to y = 258 - x.
Substituting this value into the equation above, we get:
0.08x + 0.02(258 - x) = 18.06
Solving this equation will give us the values of x and y, which represent the gallons of milk containing 8% butterfat and 2% butterfat, respectively, needed to obtain the desired 258 gallons.
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consider the following scores: 13, 18, 9, 27, 15, 15, 28, 5, 16, 21, 23, 29, 15, 15 what z-score would be earned by a person who had scored 25 points?
Answers
A person who scored 25 points in this dataset would have a z-score of 0.99.
The mean can be calculated by adding up all of the scores and dividing by the number of scores:
(13 + 18 + 9 + 27 + 15 + 15 + 28 + 5 + 16 + 21 + 23 + 29 + 15 + 15) / 14 = 18
The standard deviation can be calculated using the formula:
sqrt(sum((x - mean)^2) / (n - 1))
where x is each score in the dataset, mean is the mean of the dataset, and n is the number of scores.
Using this formula, we get:
sqrt (((13-18) ^2 + (18-18) ^2 + (9-18) ^2 + (27-18) ^2 + (15-18) ^2 + (15-18) ^2 + (28-18) ^2 + (5-18) ^2 + (16-18) ^2 + (21-18) ^2 + (23-18) ^2 + (29-18) ^2 + (15-18) ^2 + (15-18) ^2) / (14 - 1))
= 7.05
Now we can calculate the z-score of a scores of 25 using the formula:
z = (x - mean) / standard deviation
where x is the score, we are interested in, mean is the mean of the dataset, and standard deviation is the standard deviation of the dataset.
Plugging in the values, we get:
z = (25 - 18) / 7.05 = 0.99 (rounded to two decimal places)
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Find the composition of transformations that map
ABCD to EHGF.
Reflect over the [? ]-axis, then translate
(x+[ ], y+[ ]).
Note: Enter x or y for axis.
G H
D
Enter
![Find the composition of transformations that mapABCD to EHGF.Reflect over the [? ]-axis, then translate(x+[](https://i5t5.c14.e2-1.dev/h-images-qa/contents/attachments/sPBFXh11USxvmM28ApasSaAu9A8Q0OOk.png)
Answers
Clearly, the reflection is over the \(y\)-axis.
This maps \(A(-5,2)\) to \((5,2)\). However, the corresponding vertex of \(EFGH\) has coordinates \((4,3)\). So, there was a translation 1 unit left and 1 unit up.
Reflect over the \(y\)-axis, then translate \((x+(-1), y+1)\)what a subcategory of a polygon
Answers
Three or more line segments that only intersect at their ends form closed, two-dimensional shapes known as polygons.
What is a polygon?A polygon is a closed, two-dimensional shape with straight sides that is flat or plane. It has straight sides. Polygons are a different category that belongs to the category of two-dimensional figures because two-dimensional (2D) figures are flat because they lack volume.
Polygons are flat 2D shapes that have straight lines and all lines are closed, meaning that they don't have any disconnected lines. Polygons are a subcategory of 2D figures because they carry all traits of 2D figures but also have special ones of their own. Examples of polygons are squares, rectangles, and triangles. Examples of nonpolygons but still are 2D figures are circles, ovals, and any other flat shape.
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Complete question
How can polygons be considered a subcategory of two-dimensional figures?
which of the following is a function
Answers
Answer: the second one
Answer:
B
Step-by-step explanation:
because it's the only one that passes the vertical line test.
Say that the input for an Huffman coding contains 256 letters. Each appearing the the same number of times. (a) If we choose to code all letters by codes of the same length, what is the number of bits required
Answers
Complete Question
Say that the input for an Huffman coding contains 256 letters. Each appearing the the same number of times.
(a) If we choose to code all letters by codes of the same length, what is the number of bits required?
(b) Is the Huffman code better than the code of the first item?
Answer:
a
\(N = 8 bits\)
b
Huffman coding.Hence for this question Huffman's code is equivalent to the code of the first item
Step-by-step explanation:
From the question we are told that
The input for an Huffman coding contains n = 256 letters
Generally in the case where it has been decided to code all letters by code of the same length , the of bits required is mathematically represented as
\(N = log _2 {256}\)
=> \(N = 8 bits\)
Generally from the question we are told that each letter appears the same number of time ,in Huffman coding this letter will be on the same level of leaf nodes for the sake of the reason stated above,and what this mean is that the number of bits required for the code of the first item is equal to the number of bit required for Huffman coding.Hence for this question Huffman's code is equivalent to the code of the first item
Translate the sentence into an equation.Eight more than the quotient of a number and 3 is equal to 4.Use the variable w for the unknown number.
Answers
We are to translate into an equation
Eight more than the quotient of a number and 3 is equal to 4.
Let the number be w
Hence, quotient of w and 3 is
\(\frac{w}{3}\)Therefore, eight more than the quotient of a number and 3 is equal to 4
Is given as
\(\frac{w}{3}+8=4\)Solving for w
we have
\(\begin{gathered} \frac{w}{3}=4-8 \\ \frac{w}{3}=-4 \\ w=-12 \end{gathered}\)Therefpore, the equation is
\(\frac{w}{3}+8=4\)Combine Like terms.
5a + 5b -2a + b
Answers
Answer:
3(a+2b)
Step-by-step explanation:
5a+5b−2a+b
Multiply and combine like terms.
3a+6b
Factor out 3.
3(a+2b)
3.75 +9.25-(-4.75*0.5-0.2*2-3)
Answers
Answer:
-7.225 according to a calculator.
Estimate the sum of 12.15,16.85 and1.74 by rounding each number to nearest tenth
Answers
The Sum of the given numbers is 30.80.
What do we mean by the sum of numbers?When we add two or more numbers, the result or answer is known as the SUM. Addends are the numbers that are added. In the preceding example, 6 and 4 are addends, and their sum is 10. In other words, the sum of 8 and 5 equals 13, or 8 plus 5 equals 13.SUM:
12.15 + 16.85 + 1.7429 + 1.7430.74Rounding off to nearest tenth = 7 + 1 = 30.80
Therefore, the Sum of the given numbers is 30.80.
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Please help me !!!!!
Answers
Answer:
11.5
Step-by-step explanation:
Put the numbers in order from smallest to largest
2,2,6,9,9,11,11,12,32,43,46,54,54,59
The median is the middle number
There are 14 numbers so the middle is between 7 and 8
2,2,6,9,9,11,11, 12,32,43,46,54,54,59
Take the average of the 7th and 8th numbers
(11+12)/2 = 11.5
The median is 11.5
Answer: 11.5
Step-by-step explanation:
The median is the middle number in a sorted list of numbers. So, to find the median, we need to place the numbers in value order and find the middle number.
Ordering the data from least to greatest, we get:
2 2 6 9 9 11 11 12 32 43 46 54 54 59
As you can see, we do not have just one middle number but we have a pair of middle numbers, so the median is the average of these two numbers:
Median= 11+12/2=11.5