Experiment 3: Relationship between wavelength and frequency Results: Tension Frequency Time to Wavelength Speed Frequency travel the cm Length/ x length of time wavelength the stringLow 1 5.26 1.2 Low 2 5.39 0.5 Low 3 5.43 0.3 Moderate 1 2.24 1.2 Moderate 2 2.20 1.9 Moderate 3 2.15 1.1 High 1 1.35 6.2 High 2 1.42 2.4 High 3 1.39 2 String length 6.8cm Conclusion: 1. If the tension remains constant and the frequency increases, what happens to the wavelength? 2. Is there any pattern in the last two columns of the table (speed and Frequency X wavelength)? 3. What is the relationship between frequency, wavelength and speed of a wave?
Answers
The relationship between wavelength and frequency can be observed in Experiment 3. The results show that as the frequency increases, the wavelength decreases, and vice versa. This is because the two are inversely proportional to each other, meaning that if one increases, the other decreases.
This relationship can be observed in the first two columns of the table, where the frequency and wavelength are listed.
1. If the tension remains constant and the frequency increases, the wavelength will decrease. This is because the two are inversely proportional to each other, meaning that if one increases, the other decreases.
2. There is a pattern in the last two columns of the table (speed and Frequency X wavelength). The speed of the wave is equal to the product of the frequency and the wavelength. This relationship can be observed in the last two columns of the table, where the speed and Frequency X wavelength are listed.
3. The relationship between frequency, wavelength, and speed of a wave is that the speed of the wave is equal to the product of the frequency and the wavelength. This relationship can be observed in the last two columns of the table, where the speed and Frequency X wavelength are listed.
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Related Questions
why does knowing the velocity of a cloud in the disk of the milky way help astronomers figure out how far away it is?
Answers
Knowing the velocity of a cloud in the disk of the Milky Way is important for astronomers because it allows them to use the Doppler effect to determine how far away the cloud.
The Doppler effect is the change in frequency of waves (such as light waves) as the source of the waves moves closer or further away from an observer. By measuring the Doppler shift of the light emitted by the cloud, astronomers can calculate its velocity relative to Earth. Then, using the known rotation curve of the Milky Way, they can determine how far away the cloud is from the center of the galaxy. So, by knowing the velocity of a cloud, astronomers can calculate its distance and better understand the structure and dynamics of the Milky Way.
Knowing the velocity of a cloud in the disk of the Milky Way helps astronomers figure out how far away it is because it allows them to apply the principles of galactic rotation and the Doppler effect.
Step 1: Measure the cloud's radial velocity, which is its motion towards or away from us, using the Doppler effect. This effect causes the observed wavelength of light from the cloud to shift due to its motion.
Step 2: Understand that the Milky Way rotates differentially, meaning objects closer to the center rotate faster than those farther out. Astronomers can use a rotation curve to determine the expected velocity for a given distance from the galactic center.
Step 3: Compare the measured radial velocity with the expected velocity from the rotation curve. The difference between these velocities allows astronomers to calculate the angle between our line of sight and the cloud's actual path of motion.
Step 4: Apply trigonometry to determine the distance between us and the cloud using the angle and the known distances to other reference points within the Milky Way.
In summary, knowing the velocity of a cloud in the disk of the Milky Way helps astronomers figure out how far away it is by allowing them to use the Doppler effect, galactic rotation principles, and trigonometry to calculate its distance.
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The wavelength of UV light absorbed strongly by DNA is 263 nm. What is the energy in Joules of a quantum of this light?
Answers
Explanation:
E = hc / wavelength
Given that:
h = 6.626 × 10-34 Js
c = 2.998 x 10^8 m/s
wavelength = 263 x 10^-9 m
Which body in our solar system is larger than earth.
Answers
Answer:
The Neptune
Explanation: Hope it helps you :))))
Have a good day
Write a description of how you know a chemical reaction is occurring
Answers
Answer:
A change of color, formation of bubbles, color change, formation of gas, change of temperature.
Explanation:
Answer:
Chemical reactions involve the chemical interaction of two or more chemical substances, result in a new substance being formed, and are usually irreversible. The signs of chemical reactions include gas formation, energy release in the form of light or flame, heat absorption, precipitate formation, and color change.
Explanation:
Sample Response
Could Mars be a suitable alternative to Earth as a second home for humans? Explain your answer.
Answers
Answer:
yes
Explanation:
After the Earth, Mars is the most habitable planet in our solar system due to several reasons: Its soil contains water to extract. It isn't too cold or too hot. ... Gravity on Mars is 38% that of our Earth's, which is believed by many to be sufficient for the human body to adapt to.
in an automobile crash, a vehicle that was stopped at a red light is rear-ended by another vehicle. The vehicles have the same mass. If the tire marks show that the two vehicles moved after the collision at 4 m/s, what was the speed of the vehicle before the collision
Answers
The initial speed of the vehicle before the collision is 8 m/s.
Let the mass of the vehicle = mLet the initial speed of the vehicle stopped = uThe initial speed of the vehicle parked at the red light = 0Principle of conservation of linear momentumThe initial speed of the vehicle before the collision is calculated by applying principle of conservation of linear momentum as follows;
\(m_1 u_1 + m_2 u_2 = v(m_1 + m_2)\\\\mu + m(0) = 4(m+ m)\\\\mu = 4(2m)\\\\mu = 8m\\\\u = 8 \ m/s\)
Thus, the initial speed of the vehicle before the collision is 8 m/s.
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A person inhales and exhales 1.5 L of 38 °C air, evaporating of 0.04 g water from the lungs and breathing passages with each breath. The latent heat of vaporization of water is 2430 × 10³ J/kg. Use 1 L = 10-³m³. Density of air = 1.29 kg/m³, and the specific heat of air is 721 J/(kg°℃) (a) How much heat transfer occurs due to evaporation in each breath? Heat transfered in each breath = (b) What is the rate of heat transfer in watts if the person is breathing at a moderate rate of 18.0 breaths per minute? Rate of heat transfer= W (c) If the inhaled air had a temperature of 20 °C, what is the rate of heat transfer for warming the air? Think & Prepare 1. To raise the temperature of air from 20°C to 38°C, how much heat is required? 2. How will you calculate the mass of air from its volume and density? 3. Use the breathing rate to calcuate the rate of heat transfer in W. Rate of heat transfer= W (d) Discuss the total rate of heat transfer as it relates to typical metabolic rates. Will this breathing be a major form of heat transfer for this person? Total heat tranfer during to two processes W
Answers
In each breath, 0.04 g of water evaporates, resulting in a heat transfer of 97.2 J due to evaporation. At a breathing rate of 18 breaths per minute, the rate of heat transfer is 29.13 W. Additionally, warming the inhaled air from 20°C to 38°C contributes a heat transfer of 22.128 J. The total rate of heat transfer per breath is 119.328 J. However, compared to overall metabolic heat production, breathing is a minor form of heat transfer for this person.
(a) To calculate the heat transferred due to evaporation in each breath, we need to find the amount of heat required to evaporate the water.
The formula for heat transfer due to evaporation is Q = m × Lv, where Q is the heat transfer, m is the mass of water evaporated, and Lv is the latent heat of vaporization of water.
Here, m = 0.04 g and Lv = 2430 × 10³ J/kg. Converting the mass to kilograms, we get m = 0.04 × 10⁻³ kg. Substituting the values, we find Q = (0.04 × 10⁻³ kg) × (2430 × 10³ J/kg) = 97.2 J.
(b) The rate of heat transfer in watts can be calculated by dividing the total heat transfer by the time taken.
Given that the breathing rate is 18.0 breaths per minute, the time for each breath is 1 minute / 18 breaths = 1/18 minutes = (1/18) × 60 seconds.
Thus, the rate of heat transfer is 97.2 J / [(1/18) × 60 s] = 97.2 J / 3.33 s = 29.13 W.
(c) To calculate the rate of heat transfer for warming the air, we need to determine the amount of heat required to raise the temperature of air from 20°C to 38°C.
The formula for heat transfer due to temperature change is Q = m × c × ΔT, where m is the mass of air, c is the specific heat of air, and ΔT is the change in temperature.
We can calculate the mass of air using the density of air and the volume of air inhaled and exhaled in each breath. The volume of air is given as 1.5 L, which is equal to 1.5 × 10⁻³ m³.
The density of air is 1.29 kg/m³. Thus, the mass of air is (1.5 × 10⁻³ m³) × (1.29 kg/m³) = 1.935 × 10⁻³ kg. Substituting the values, we find Q = (1.935 × 10⁻³ kg) × (721 J/(kg°℃)) × (38°C - 20°C) = 22.128 J.
(d) The total rate of heat transfer for each breath is the sum of the heat transfer due to evaporation and the heat transfer for warming the air.
Thus, the total rate of heat transfer per breath is 97.2 J + 22.128 J = 119.328 J.
Considering the breathing rate of 18 breaths per minute, the total rate of heat transfer would be 119.328 J/breath × 18 breaths/minute = 2147.904 J/minute.
This form of heat transfer through evaporation and warming of inhaled air is relatively small compared to the overall metabolic heat production in the human body.
Metabolic rates are typically in the range of hundreds to thousands of watts, while the heat transfer rate in this case is only 2147.904 J/minute, equivalent to approximately 35.798 W.
Therefore, breathing alone is not a major form of heat transfer for this person compared to other metabolic processes.
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What happens if you move a bar magnet back and forth along the axis of the
coiled wire shown below?
Answers
c. A current is induced in the coiled wire, which lights the light bulb.
What is electromagnetic induction?If we kept the bar magnet stationary and moved the coil back and forth within the magnetic field an electric current would be induced in the coil.
Then by either moving the wire or changing the magnetic field we can induce a voltage and current within the coil and this process is known as Electromagnetic Induction and is the basic principle of operation of transformers, motors and generators.
When the magnet shown below is moved “towards” the coil, the pointer or needle of the Galvanometer, which is basically a very sensitive center zeroed moving-coil ammeter, will deflect away from its center position in one direction only.
When the magnet stops moving and is held stationary with regards to the coil the needle of the galvanometer returns back to zero as there is no physical movement of the magnetic field.
Therefore ,
If you move a bar magnet back and forth along the axis of the coiled wire shown below then a current is induced in the coiled wire, which lights the light bulb.
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How is energy related to the change of state represent ed by the model
Answers
Answer:
Atoms gain energy as a solid changes to a liquid. If atoms energy during a change of state, they are pulled together by attractive forces and become more organized.
Explanation:
A B-52 bomber jet flies at a horizontal velocity of 286.2 m/s and at an altitude of 7500 m above the ground. How far away horizontally should a payload be dropped to land on a target?
Answers
Answer:
11196.14 m
Explanation:
From the question given above, the following data were obtained:
Horizontal velocity (u) = 286.2 m/s
Height (h) = 7500 m
Horizontal distance (s) =?
Next, we shall determine the time taken for the payload to get to the target. This can be obtained as follow:
Height (h) = 7500 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
7500 = ½ × 9.8 × t²
7500 = 4.9 × t²
Divide both side by 4.9
t² = 7500 / 4.9
Take the square root of both side
t = √(7500 / 4.9)
t = 39.12 s
Finally, we shall determine the horizontal distance as follow:
Horizontal velocity (u) = 286.2 m/s
Time (t) = 39.12 s
Horizontal distance (s) =.?
s = ut
s = 286.2 × 39.12
s = 11196.14 m
Thus the payload will travel 11196.14 m horizontally in order to hit the target
Iron-cutting scissors have short edges, whereas cloth-cutting scissors have long edges. Why
Answers
Answer:
It depends on the amount of pressure needed to cut the material.
Iron is a tougher material to cut though, so the blades must be shorter to create more pressure to break through the iron.
Cloth on the other hand is easier to cut through so the blades can be longer in order to cut more in each snip.
Explanation:
During the Battle of Bunker Hill, it is commonly thought that the commanders gave the order "Don't shoot until you see the whites of their eyes!" to make sure the British troops were close enough that a hit was a certainty.s = 2.5 cmD = 4.9 mm1. If take your commander's instructions literally and don't fire until the whites of the enemy's eyes are just resolvable by your pupil, how far away (in meters) are they when you open fire? Assume your target has an eye which is 2.5 cm across, the diameter of your pupil is 4.9 mm, and you are observing at a wavelength of 555 nm.
Answers
The distance to open fire, based on the given parameters, is approximately 267 meters.
What is distance?
Distance is a scalar quantity that refers to the extent of space between two points or objects. It is a measurement of how far apart two locations or objects are from each other.
To calculate the distance at which the enemy's eyes are just resolvable by your pupil, we can use the concept of angular resolution. The formula for angular resolution is:
θ = 1.22 * (λ / D)
In this case, the diameter of the target's eye (s) is given as 2.5 cm, which is equivalent to 0.025 m. The diameter of the pupil (D) is given as 4.9 mm, which is equivalent to 0.0049 m. The wavelength of light (λ) is given as 555 nm, which is equivalent to 555 × 10⁻⁹ m.
Substituting these values into the formula, we can solve for the angular resolution (θ). Once we have the angular resolution, we can use basic trigonometry to calculate the distance (d) at which the target is located:
d = (s / 2) / tan(θ)
By plugging in the values, we find that the distance at which the target is when you open fire is approximately 267 meters.
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A high-voltage transmission line is made of bare wire; it is not insulated. Assume that the wire is 100 km long, has a resistance of 7.0 ohm, and carries 200 A. A bird is perched on the wire with its feet 2.0 cm apart. What is the potential difference between its feet?
Answers
Voltage drop across 2 cm of wire= 2 * 14 V = 28 V. The potential difference between the feet of the bird is 28 V..
A high-voltage transmission line is a wire that carries power across long distances. It is not insulated. This is due to the high voltage used to transmit electricity, which requires a minimum clearance from the ground and other structures. A bird perched on the wire with its feet 2.0 cm apart.
The potential difference between its feet is to be calculated.Below is the working:Resistance of the wire=7.0 ohmLength of the wire =100 km= 100000 mCurrent flowing through the wire = 200 APotential difference between the feet of the bird = Voltage drop across 2 cm of wireVoltage drop across 1 meter of wire = Voltage drop across 100 cm of wire=I*R= 200 * 7 = 1400 VVotage drop across 1 cm of wire= 1400/100 = 14.
Therefore, voltage drop across 2 cm of wire= 2 * 14 V = 28 V. The potential difference between the feet of the bird is 28 V.Answer: The potential difference between the feet of the bird is 28 V.
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Like all planets, the planet Venus orbits the Sun in periodic motion and simultaneously spins about its axis. Just as on Earth, the time to make one complete orbit (i.e., the period of orbit) is what defines a year. And the time to make one complete revolution about its axis (i.e., the period of rotation) is what defines a day. The period of orbit for the Earth is 365.25 days and the period of rotation is 24 hours (1.00 day). But when these same values for Venus are expressed relative to Earth, it is found that Venus has a period of orbit of 225 days and a period of rotation of 243 days. So for Venus inhabitants, a day would last longer than a year! Determine the frequency of orbit and the frequency of rotation (in Hertz) on Venus. Ans: A marine weather station detects waves which are 9.28 meters long and 1.65 meters high and travel a distance of 50.0 meters in 21.8 seconds. Determine the speed and the frequency of these waves. Ans:
Answers
Answer:
a) F = 5.14 10⁻⁸ Hz, f = 4.76 10-8 Hz, b) v = 2.29 m / s, f = 42.5 Hz
Explanation:
a)This problem has two parts.
For the calculations relative to the planet Venus, we use that the period and the frequency are related
f = 1 / T
frequency of the orbit around the Sun
Let's reduce the period to the SI system
T = 225 days (24h / 1days) (3600 s / 1h) = 1.94 10⁷ s
F = 1 / 1.94 10⁷
F = 5.14 10⁻⁸ Hz
rotation frequency
T = 243 d = 2.1 107 s
f = 1 / T
f = 1 / 2.1 107
f = 4.76 10-8 Hz
b) give the data of some marine waves
the speed of the wave can be found with kinematics
v = x / t
v = 50.0 / 21.8
v = 2.29 m / s
If the wavelength is L = 9.28m
this distance is the distance between two consecutive ridges or valleys
λ / 2 = L
λ = 2L
λ = 2 9.28
λ = 18.56 m
the speed of the wave is
v = λ f
f = v /λ
f = 2.29 / 18.56
f = 42.5 Hz
What do we call a simple machine that is a flat surface set at an upward angle sloping at any point less than a 90 degree angle?
Answers
A simple machine that is a flat surface set at an upward angle sloping at any point less than a 90 degree angle is called an inclined plane.
A sloping surface makes up an inclined plane, which is utilized to lift heavy objects. The mechanical advantage of the plane is that less force is needed to drive an item up the slope than is necessary to lift its weight (discounting friction).
As a tool for lifting or lowering a load, an inclined plane, sometimes referred to as a ramp, is a flat supporting surface that is slanted at an angle from the upward direction with one end higher than the other.
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Jill runs for 20 seconds at 10 m/s, how far did she travel?
Answers
Answer:
200 (m) for 20 seconds
10 times 20 is 200
Answer:
200
Explanation:
Jill is running at 10 meters per second
20 * 10 = 200
slader A jet is circling an airport control tower at a distance of 15.9 km. An observer in the tower watches the jet cross in front of the moon. As seen from the tower, the moon subtends an angle of 8.74x10-3 radians. Find the distance traveled (in meters) by the jet as the observer watches the nose of the jet cross from one side of the moon to the other.
Answers
Answer:
y = 138.96 m
Explanation:
The angle subtended by the moon is the mean of the angle of the arc between the two most extreme points of the moon, we can see that the angle is very small, so we can approximate this arc to a straight line and then use the trigonometric relationships
sin θ = y / L
where L = 15.9 10³ m and θ = 8.74 10⁻³ rad
y = L sin θ
y = 15.9 10³ sin (8.74 10⁻³)
y = 15.9 10³ 0.0087399
y = 138.96 m
which situation will produce the greatest change of momentum for a 1.0 kilogram cart?
1) applying a net force of 5 N for 2 s
2) applying a net force of 10 N for .5 s
3) accelerating it from rest to 3 m/s
4) accelerating it from 2 m/s to 4 m/s
Answers
To determine which situation will produce the greatest change of momentum for a 1.0-kilogram cart, we need to compare the magnitudes of the impulse in each situation. Impulse is defined as the change in momentum of an object and is equal to the force applied multiplied by the time interval over which the force acts.
Impulse = Force * Time, the impulse for each situation:
1) Impulse = (Force) * (Time) = (5 N) * (2 s) = 10 N·s
2) Impulse = (Force) * (Time) = (10 N) * (0.5 s) = 5 N·s
3) In this situation, we need to calculate the initial momentum (p_initial) and final momentum (p_final) to find the change in momentum.
Initial momentum (p_initial) = mass * initial velocity = 1.0 kg * 0 m/s = 0 kg·m/s
Final momentum (p_final) = mass * final velocity = 1.0 kg * 3 m/s = 3 kg·m/s
Change in momentum = Final momentum - Initial momentum = 3 kg·m/s - 0 kg·m/s = 3 kg·m/s
4) In this situation, we again calculate the initial momentum (p_initial) and final momentum (p_final) to find the change in momentum.
Initial momentum (p_initial) = mass * initial velocity = 1.0 kg * 2 m/s = 2 kg·m/s
Final momentum (p_final) = mass * final velocity = 1.0 kg * 4 m/s = 4 kg·m/s
Change in momentum = Final momentum - Initial momentum = 4 kg·m/s - 2 kg·m/s = 2 kg·m/s.
The situation that will produce the greatest change in momentum for the 1.0-kilogram cart is situation 1, where a net force of 5 N is applied for 2 seconds, resulting in an impulse of 10 N·s.
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Three light bulbs are connected in a series, as shown in the diagram.
After the circuit is completed, the middle light bulb breaks. What will happen to the remaining light bulbs?
a
Only the light bulb closest to the positive end of the battery will stay lit.
b
Only the light bulb closest to the positive end of the battery will go out.
c
Both of the remaining light bulbs will go out.
d
Both of the remaining light bulbs will stay lit.
Answers
After the circuit is completed, the middle light bulb breaks, both of the remaining light bulbs will go out. Option c is correct.
In a series circuit, components (in this case, light bulbs) are connected end-to-end, so that the current has to flow through each component in turn. The voltage of the battery is divided among the components, so that the sum of the voltage drops across each component equals the total voltage of the battery.
In a series circuit, the current passes through each component in turn. When one component fails or is removed, the current can no longer flow, and the circuit is broken. In this case, when the middle light bulb breaks, it will create an open circuit, preventing the current from reaching the other two light bulbs. Therefore, both of the remaining light bulbs will go out. Option c is correct.
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A box with a mass of 5kg is sitting in a storeroom. The manager asks their employee to push the box across the hall which is 3 meters long. How much work does the employee have to input to move the box the required distance?
Answers
The amount of work that the employee input to move the box over the required distance is 15J.
What is work?Work is the measure of energy expended in moving an object; most commonly, force times distance.
It is said that no work is done if the object does not move. The work done on an object can be calculated by multiplying the force applied by the distance moved as follows:
Work done = Force × distance
According to this question, a box with a mass of 5kg is sitting in a storeroom. The manager asks their employee to push the box across the hall which is 3 meters long. The work done on the box is calculated thus;
Work done = 5N × 3m = 15J
Therefore, 15J is the work done on the box.
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Which is the equivalent of 2000 mm?
a. 200 m b. 2 m c. 0.002 m d. 0.02 m
Answers
2000 mm is equivalent to 2 m. This can be derived from the fact that 1 m = 1000 mm. Thus, 2000 mm would be equal to 2 m since it is twice the length of 1000 mm. This conversion is important in various fields such as construction, engineering, and science where precision is necessary.
It is crucial to be able to convert between different units of measurement in order to make accurate calculations and measurements.The millimeter is a unit of length that is often used to measure small distances such as the thickness of a sheet of paper or the size of a small component. It is part of the metric system, which is a system of units used across the world that is based on multiples of 10.
This system makes it easy to convert between different units since it is based on a consistent set of rules.For example, to convert 2000 mm to meters, we can simply divide by 1000 since there are 1000 millimeters in a meter. This gives us 2 meters, which is the equivalent length in meters of 2000 millimeters.
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6. Do you think that aliens exist?
Answers
what is happening inside a star while it expands into a subgiant? question 7 options: it is fusing helium into carbon in a shell outside the core. it is fusing hydrogen into helium in a shell outside the core. it is fusing hydrogen into helium in the core. it is not fusing any element; it is contracting and heating up. it is fusing helium into carbon in the core.
Answers
The that is happening inside a star while it expands into a subgiant is that it is fusing hydrogen into helium in a shell outside the core.
What happens when star expands into a subgiant ?The expansion of the outer layers of the star into the subgiant size can be seen as one that is balance and bring aboput the increase of energy generated by the hydrogen shell fusion wehich do make the star to nearly maintain its surface temperature.
It shopuld be noted that it causes the spectral class of the star to change very little and this can be felt from the lower end of this range of star mass.
In conclusion, the Fusion as described can be seen as one that do occurs when two atoms slam together so the formation of the heavier atom, can be acheied as seen in the way the hydrogen fuss into helium in a shell outside
Therefore, the second option is correct.
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Three balls with different masses are shown below.
(picture of beach ball) - 85g
(picture of football) 425g
(picture of baseball) - 149g
If the same amount of kicking force is applied to each ball, which will travel the farthest?
F - They will all travel the same distance because the applied force is the same
G - the baseball because it's the smallest
H - The football because it has the highest mass and was designed for kicking
J - the beach ball because it has the lowest mass
(btw it's a football, not soccer ball)
Answers
Answer:
$10 a g
Explanation:
Answer:
As The mass of the beach ball is having lowest magnitude when compared with the other balls given so when apply the same magnitude of force to all the balls then the beach ball due to its lighternessand also its inertia of rest would not resist the force so much so when you apply the force to this ball it would starts to roll and covers the maximum diatance whwn compared with the other ball only in the condition when same magnitude of force applied.Thats this ball would do more work than the other ball.The mass also influences the velocity carried by the body and also the kinetic energy possessed by the body. More the force applied more the distance it would cover
Hope it helps
Two identical conducting spheres are placed with their centers 0.80 m apart. One is given a charge of +6 × 10−9 C, and the other is given
a charge of −11 × 10−9 C.
Find the electric force exerted on one sphere by the other.
Please help asap
Answers
The electric force exerted on one sphere by the other is equal to 9.27 × 10⁻⁷ N.
What is coulomb's law?According to Coulomb’s law, the force of attraction between two charged bodies is the product of their charges and is inversely proportional to the square of the distance by which they are separated. This force acts along the line joining the two-point charges.
The magnitude of the electric force is given by:
\(F = k\frac{q_1q_2}{r^2}\)
where k is constant proportionality and has a value of 8.99 × 10⁹ N.m²/C².
Given the charge on one sphere, q₁ = + 6 ×10⁻⁹ C
The charge on the other sphere, q₂ = -11 × 10⁻⁹C
The distance between these two charges, r = 0.80 m
The magnitude of electric force between the spheres will be:
\(F = 8.99 \times 10 ^9(\frac{6\times 10^{-9}\times 11\times 10^{-9}}{(0.80)^2} )\)
F = 927.09 × 10⁻⁹ N
F = 9.27 × 10⁻⁷ N
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Calculate the net force on particle q₁.
Now use Coulomb's Law and electric constant to
calculate the force between 91 and 93.
F₂ = k191931
r2
ke 8.99 x 10⁹
r = 0.55 m
F₁ = -14.4 N
+13.0 μC
+91
0.25 m
+7.70 με
+92
F₂ = + [?] N
0.30 m
-5.90 μC
93
Enter
Answers
The force between q₁ and q₂ is -1.17 x 10⁻³ N, net force on q₁ is -14.40117 N, force between q₂ and q₃ is 1.09 x 10⁻³ N.
How to determine net force?The given information suggests that there are two particles, q₁ and q₂. The force on q₁ due to q₂ is given by Coulomb's law:
F₂ = k(q₁q₂/r²)
Where, k = Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q₁ and q₂ = charges of particles in Coulombs, and r = distance between the particles in meters.
The net force on q₁ is the vector sum of the forces on q₁ due to all other charges.
Given data:
Charge on q₁, q₁ = +13.0 μC = +13.0 x 10⁻⁶ C
Charge on q₂, q₂ = -5.90 μC = -5.90 x 10⁻⁶ C
Distance between q₁ and q₂, r = 0.30 m
Distance between q₁ and q₃, d = 0.55 m
Charge on q₃, q₃ = +7.70 μC = +7.70 x 10⁻⁶ C
Force between q₁ and q₃, F₁ = -14.4 N
Now, calculate the force between q₁ and q₂ as follows:
F₂ = k(q₁q₂/r²)
F₂ = (8.99 x 10⁹ Nm²/C²) [(+13.0 x 10⁻⁶ C) x (-5.90 x 10⁻⁶ C) / (0.30 m)²]
F₂ = -1.17 x 10⁻³ N
(The negative sign indicates that the force is attractive)
Therefore, the force between q₁ and q₂ is -1.17 x 10⁻³ N.
The net force on q₁ is given by the vector sum of the forces on q₁ due to q₂ and q₃:
Net force on q₁ = F₁ + F₂
Net force on q₁ = (-14.4 N) + (-1.17 x 10⁻³ N)
Net force on q₁ = -14.40117 N
Therefore, the net force on q₁ is -14.40117 N.
Finally, calculate the force between q₂ and q₃, which can be found using Coulomb's law as:
F₃ = k(q₂q₃/d²)
F₃ = (8.99 x 10⁹ Nm²/C²) [(-5.90 x 10⁻⁶ C) x (+7.70 x 10⁻⁶ C) / (0.55 m)²]
F₃ = 1.09 x 10⁻³ N
(The positive sign indicates that the force is repulsive)
Therefore, the force between q₂ and q₃ is 1.09 x 10⁻³ N.
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Books in a library were counted one by one. There were a total of 57000 books in the library. How many significant digits are there in the result? Will the result change if the books are measured in the paacket of 10?
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The total number of significant digits in the given number is five. If the books are measured in packets of 10, the number of significant digits reduces to two.
The given data is: Total number of books in the library = 57,000. We are to determine how many significant digits are there in the result? For this, let us define what are significant digits: Digits that are used to communicate meaning or accuracy of measurements are known as significant digits. In other words, the digits that carry meaning contributing to its measurement uncertainty are called significant digits. It is used to determine the accuracy of the results. In this question, the total number of books in the library is given as 57,000. As there are five non-zero digits in the given number, there are five significant digits in the result. Will the result change if the books are measured in the packet of 10? If the number of books is measured in the packet of 10, then there will be a change in the number of significant digits. When we express 57,000 in the packet of 10, we get: 57,000 = 5.7 × 10^4. Now, there are only two significant digits in the result (5 and 7), and hence the result changes.
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1. Suppose you know that the veight of standard poodles is Normally distributed with a standard deviation of 5 pounds. Bob tells you that the average weight of standard poodles is 55 pounds. You take an SRS of 8 poodles and find their average weight to be 52 pounds. (a) Run a two-sided significance test, with a significance level of 5% to see if Bob is correct or not. (b) You have reason to believe that Bob is wrong, and that the average is actually smaller than they ciaim. Run the appropriate onesided significance test with a significance level of 5%. (c) Somebody else believes that Bob is wrong, and that the average is actually larger than the first person claimed. Run the appropriate one-sided significance test with a significance level of 5%. (d) Compare your three answers above.
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the results of the three tests are as follows:
(a) Two-sided test: Fail to reject the null hypothesis. No evidence to suggest a difference in average weight.
(b) One-sided test (smaller): Reject the null hypothesis. Evidence suggests the average weight is smaller.
(c) One-sided test (larger): Fail to reject the null hypothesis. No evidence to suggest the average weight is larger.
These results indicate that there is some evidence to support the claim that the average weight of standard poodles is smaller than 55 pounds,
To perform the significance tests, we can use the t-distribution since the population standard deviation is unknown and the sample size is small (n < 30).
(a) Two-sided significance test:
Null hypothesis (H0): The average weight of standard poodles is 55 pounds.
Alternative hypothesis (Ha): The average weight of standard poodles is not 55 pounds.
Using a significance level of 5% (α = 0.05) and an SRS of 8 poodles with a sample mean of 52 pounds, we can calculate the t-value and compare it to the critical t-value.
The t-value is calculated as (sample mean - population mean) / (sample standard deviation / √n):
t = (52 - 55) / (5 / √8) ≈ -1.897
Degrees of freedom (df) = n - 1 = 8 - 1 = 7
Looking up the critical t-value for a two-sided test with α = 0.05 and df = 7, we find that t_critical ≈ ±2.365.
Since -1.897 falls within the range -2.365 to 2.365, we fail to reject the null hypothesis. There is not enough evidence to conclude that the average weight of standard poodles is different from 55 pounds.
(b) One-sided significance test (smaller):
Null hypothesis (H0): The average weight of standard poodles is 55 pounds.
Alternative hypothesis (Ha): The average weight of standard poodles is less than 55 pounds
Using a significance level of 5% (α = 0.05) and the same sample data, we calculate the t-value and compare it to the critical t-value for a one-sided test.
t = (52 - 55) / (5 / √8) ≈ -1.897
Looking up the critical t-value for a one-sided test with α = 0.05 and df = 7, we find that t_critical ≈ -1.895.
Since -1.897 is slightly less than -1.895, we reject the null hypothesis. There is evidence to suggest that the average weight of standard poodles is smaller than 55 pounds.
(c) One-sided significance test (larger):
Null hypothesis (H0): The average weight of standard poodles is 55 pounds.
Alternative hypothesis (Ha): The average weight of standard poodles is greater than 55 pounds.
Using a significance level of 5% (α = 0.05) and the same sample data, we calculate the t-value and compare it to the critical t-value for a one-sided test.
t = (52 - 55) / (5 / √8) ≈ -1.897
Looking up the critical t-value for a one-sided test with α = 0.05 and df = 7, we find that t_critical ≈ 1.895.
Since -1.897 is less than -1.895, we fail to reject the null hypothesis. There is not enough evidence to conclude that the average weight of standard poodles is greater than 55 pounds.
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Spring tides occurs at two of the time shown which two? how do u know ?
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Spring tides are extremely wide ranges of tidal highs and lows that occur during full moon or new moon phases when the gravitational forces of the Sun and Moon are at their strongest.
Neap tides are characterized by lower high tides and higher low tides, while spring tides feature higher high tides and lower low tides. Because of this, a spring tide has a significantly wider range than a low tide (the difference in water level between high and low tide).Spring tides are the tides that occur right after a new or full moon when the difference between high and low water is the biggest. The earth, moon, and sun are in a straight line at this time, causing the gravitational pull to be at its strongest. There are more high tides than usual and fewer low tides than usual.To know more about spring tides
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Two different rivers have drops that are the same height. In river A, this section of the river is a waterfall. In river B, this section has a hydroelectric dam. In what way does the energy differ between the drops in the two rivers?
The potential energy of the water would be less at the top of the drop in river A than in river B.
The kinetic energy of the water would be less at the bottom of the drop in river A than in river B.
The potential energy of the water would be greater at the top of the drop in river A than in river B.
The kinetic energy of the water would be greater at the bottom of the drop in river A than in river B.
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Answer:
The kinetic energy of the same amount of water would be greater at the bottom of the drop of river A (waterfall) than in river B (hydroelectric dam.)
Explanation:
In a uniform gravitational field, the gravitational potential energy of an object is proportional to height relative to the ground. It is given that the top of the two drops are of the same height. As a result, the same amount of water at the top of the drops would have the same amount of gravitational potential energy.
When water moves from the top of the drop to the bottom, gravitational potential energy is converted into kinetic energy.
In the waterfall of river A, the change in potential energy is nearly entirely converted into kinetic energy. However, in river B, some of that potential energy is converted into the mechanical energy of the hydroelectric generators. Since energy is conserved, the same amount water at the bottom of the river B drop would have less kinetic energy.