Explain how pH increases with antacids.​

Answer:

Explanation:

do it right now leking good......, my feet my back due tomorrow

Proteins, nucleic acids, and carbohydrates are grouped by common structural features found within their groups. Lipids can be grouped based on their poor solubility in polar solvents, high solubility in nonpolar solvents, high reactivity towards oxidation, and high solubility in aqueous solutions of neutral pH.

Lipids are a class of macromolecules that are not defined by a particular structural feature. Proteins, nucleic acids, and carbohydrates are grouped according to common structural features found within their groups. However, lipids can be grouped based on several properties, including: Their poor solubility in polar solvents Lipids are hydrophobic and will not dissolve in water. They are instead soluble in nonpolar solvents such as ether, benzene, and chloroform.

Their high solubility in nonpolar solvents: Lipids are hydrophobic and will dissolve in nonpolar solvents such as ether, benzene, and chloroform.Their high reactivity towards oxidation: Lipids are easily oxidized due to the presence of unsaturated fatty acids in their structure.

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Double bonds can form when a molecule or ion has fewer than 8 valence electrons around the central atom.

A molecule is a group of atoms held together by chemical bonds. Molecules can vary greatly in size and complexity, ranging from single atoms to large molecules made up of thousands of atoms. Molecules are the smallest units of matter that can take part in a chemical reaction and are essential for life. Molecules can be made up of elements from the periodic table, such as oxygen, hydrogen, and carbon, or can be composed of metals, such as gold and silver.

This is because a double bond has two electron pairs shared between them, so in order to form one, there must be enough electrons available to form the bond. Additionally, double bonds are formed in order to ensure that the central atom has an octet of valence electrons around it, which is a more stable arrangement.

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Answer:

In order to calculate the work that the spike did, you have to respect the following equation:

WORK = FORCE X DISPLACEMENT X COS (0)

Explanation:

Work is measured in joules, and is the amount of energy a body needs to make a certain force over a certain distance.

In the case of this bird we would be calculating with the equation written up in the previous item the work that said animal would do to grind a seed.

Taking into account the definition of calorimetry, the heat change that would take place as 25.7 g of liquid Ethyl alcohol are cooled from 55.2 °C to 30 °C is -1554.336 J.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Replacing in the expression to calculate heat exchanges:

Q= 2.40 \(\frac{J}{gC}\)× 25.7 g× (30 °C - 55.2 °C)

Solving:

Q= -1554.336 J

Finally, the heat change that would take place as 25.7 g of liquid Ethyl alcohol are cooled from 55.2 °C to 30 °C is -1554.336 J.

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To determine how much of solution A would be needed to generate the electrical energy used daily in the home

we need to calculate the ratio of the energy released by fusion of hydrogen to the electrical energy used daily.

Energy ratio = Energy released by fusion of hydrogen / Electrical energy used daily

Energy ratio = (8.4 x 10^12) / (3 x 10^8)

To simplify the calculation, we can convert the values to scientific notation with the same exponent:

Energy ratio = (8.4 / 3) x (10^12 / 10^8)

Energy ratio = 2.8 x 10^4

This means that for every unit of electrical energy used daily in the home, we would need 2.8 x 10^4 units of solution A to generate that energy.

Therefore, to generate the electrical energy used daily in the home, we would need 2.8 x 10^4 liters of solution A.

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The standard free-energy change at 25 ∘C for the given reaction, Mg(s)+Fe₂+(aq)→Mg₂+(aq)+Fe(s) can be calculated using the equation:ΔG∘ = ΣnΔGf∘ (products) − ΣnΔGf∘ (reactants)where ΔGf∘ is the standard free energy of formation of the compound, n is the stoichiometric coefficient of each compound in the reaction.

The values of ΔGf∘ for the given reaction are:

Mg₂+ (aq):−467.2 kJ/mol Fe(s): 0 kJ/mol Fe₂+(aq): −237.2 kJ/mol Mg(s): 0 kJ/molΔG∘ =

ΣnΔGf∘ (products) − ΣnΔGf∘ (reactants)ΔG∘ =

[ΔGf∘ (Mg₂+ (aq)) + ΔGf∘ (Fe(s))] - [ΔGf∘ (Mg(s)) + ΔGf∘ (Fe₂+(aq))]ΔG∘ =

[−467.2 kJ/mol + 0 kJ/mol] - [0 kJ/mol + (−237.2 kJ/mol)]ΔG∘ =

−230.0 kJ/mol At 25 ∘C, the standard free-energy change for the given reaction is −230.0 kJ/mol. The units of ΔG∘ are kilojoules per mole (kJ/mol). Hence, the answer is -230.0 kJ/mol.

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Answer:

2.67 moles of cesium carbonate (Cs2CO3).

Explanation:

We'll begin by writing the equation for the reaction. This is illustrated below:

Cs + Fe2(CO3)3 —> Cs2CO3 + Fe

The above equation can be balance as follow:

There are 2 atoms of Fe on the left side and 1 atom on the right side. It can be balance by putting 2 in front of Fe as shown below:

Cs + Fe2(CO3)3 —> Cs2CO3 + 2Fe

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by 3 in front of Cs2CO3 as shown below:

Cs + Fe2(CO3)3 —> 3Cs2CO3 + 2Fe

There are 6 atoms of Cs on the right side and 1 atom on the left. It can be balance by putting 6 in front of Cs as shown below:

6Cs + Fe2(CO3)3 —> 3Cs2CO3 + 2Fe

Thus, the equation is balanced.

From the balanced equation above,

6 moles of Cs reacted with 1 mole of Fe2(CO3)3 to produce 3 moles of Cs2CO3.

Finally, we shall determine the moles of cesium carbonate (Cs2CO3) produced by the reaction of 5.34 moles of cesium (Cs). This can be obtained as follow:

From the balanced equation above,

6 moles of Cs reacted to produce 3 moles of Cs2CO3.

Therefore,

5.34 moles of Cs will react to produce = (5.34 × 3)/6 = 2.67 moles of Cs2CO3.

Thus, 2.67 moles of cesium carbonate (Cs2CO3) were produced from the reaction.

Answer:

Explanation:

Because electrons are delocalized around positively charged nuclei, metallic bonding explains many properties of metals. Electrical conductivity: Most metals are excellent electrical conductors because the electrons in the electron sea are free to move and carry charge.

The chemical equation for the ionic compound formed by ammonium particle (NH4+) and phosphate particle (PO43-) is (NH4)3PO4.

At the point when an ammonium particle (NH4+) reacts with a phosphate particle (PO43-), an ionic compound is shaped by the exchange of electrons from the ammonium particle to the phosphate particle, bringing about the development of positive and negative particles.

The positive particle, ammonium (NH4+), and the negative particle, phosphate (PO43-), are then kept intact by ionic bonds to shape an ionic compound.

The addendums in the formula demonstrate the proportion of the particles in the compound and address the substance equation of the ionic compound.

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Answer:

0.56L

Explanation:

This question requires the Ideal Gas Law:  \(PV=nRT\) where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the Ideal Gas constant, and T is the Temperature of the gas.

Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units:\(R=0.0821\frac{L\cdot atm}{mol\cdot K}\)

Since the conditions are stated to be STP, we must remember that STP is Standard Temperature Pressure, which means \(T=273.15K\) and \(P=1atm\)

Lastly, we must calculate the number of moles of \(O_2(g)\) there are.  Given 0.80g of \(O_2(g)\), we will need to convert with the molar mass of \(O_2(g)\).  Noting that there are 2 oxygen atoms, we find the atomic mass of O from the periodic table (16g/mol) and multiply by 2:  \(32g\text{ }O_2=1mol\text{ }O_2\)

Thus, \(\frac{0.80g \text{ }O_2}{1} \frac{1mol\text{ }O_2}{32g\text{ }O_2}=0.25mol\text{ }O_2=n\)

Isolating V in the Ideal Gas Law:

\(PV=nRT\)

\(V=\frac{nRT}{P}\)

...substituting the known values, and simplifying...

\(V=\frac{(0.025 mol \text{ }O_2)(0.0821\frac{L\cdot atm}{mol \cdot K} )(273.15K)}{(1atm)}\)

\(V=0.56L \text{ } O_2\)

So, 0.80g of \(O_2(g)\) would occupy 0.56L at STP.

Answer:

0.56 L

Explanation:

Answer:

toward the hydrogen atom

Explanation:

Answer:

toward the chlorine atom.

Explanation:

took the quiz and got it correct :)

The diagram became horizontal at X because hydrogen gas is produced at a steady rate​.

option D.

When a reaction involves one or more intermediates, the concentration of one of the intermediates remains constant at some stage of the reaction. Thus, the system has reached a steady-state.

Considering the diagram illustrated by the rate curve that was obtained when Mg reacted with excess dilute HCl, we can observe that at point X the reaction rate becomes constant, this implies that hydrogen gas is produced at a steady rate​ because the volume of HCL becomes constant at that point.

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The pressure of neon gas, connected to the manometer, is 729.1 torr.

To determine the pressure of the neon gas in the flask, we need to consider the relationship between the pressure difference in the manometer and the difference in the height of the mercury levels in the two arms.

In this case, we have an open-ended mercury manometer, where one arm is connected to the flask of neon gas and the other arm is exposed to the atmosphere. The height difference between the two mercury levels is given as 9.3 cm.

The pressure in the open arm (exposed to the atmosphere) is equal to the atmospheric pressure, which is given as 729 torr. The pressure in the arm connected to the neon gas is what we need to find.

When the two arms of the manometer are at the same height, the pressure in the flask is equal to the atmospheric pressure. However, when one arm is higher than the other, there is a pressure difference.

The pressure difference in a manometer is given by the equation:

ΔP = ρgh

Where ΔP is the pressure difference, ρ is the density of the fluid (in this case, mercury), g is the acceleration due to gravity, and h is the height difference between the two arms.

To find the pressure of the neon gas, we need to rearrange the equation:

ΔP = P_neon - P_atmosphere

P_neon = ΔP + P_atmosphere

Now we can substitute the values into the equation. The density of mercury is approximately 13.6 g/cm³, and the acceleration due to gravity is approximately 9.8 m/s².

Converting the height difference from centimeters to meters:

h = 9.3 cm = 0.093 m

Substituting the values into the equation:

ΔP = (13.6 g/cm³) * (0.093 m) * (9.8 m/s²)

Calculating ΔP:

ΔP = 13.6 g/cm³ * 0.093 m * 9.8 m/s² = 12.395 Pa

Now, we can convert the pressure difference from Pascals to torr:

1 torr = 133.322 Pa

ΔP = 12.395 Pa * (1 torr / 133.322 Pa) = 0.0930 torr

Finally, we can calculate the pressure of the neon gas:

P_neon = ΔP + P_atmosphere = 0.0930 torr + 729 torr = 729.0930 torr

Rounding to the appropriate number of significant figures, the pressure of the neon gas in the flask is 729.1 torr.

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Answer:

A. Potassium (K)

Explanation:

The trend of atomic radius goes:

As group number increases, radius decreases

As period number increases, radius increases

Answer:

francium

Explanation:

Atomic radii vary in a predictable way across the periodic table. As can be seen in the figures below, the atomic radius increases from top to bottom in a group, and decreases from left to right across a period. Thus, helium is the smallest element, and francium is the largest.

Before performing the titration of the unknown acid, if the partner accidentally dilutes the sample by adding water, it would affect the following aspects of the titration curve:

1. The volume of base necessary to reach the equivalence point will remain unaffected.

2. It would not have any effect on the pH at the half-equivalence point.

3. It would decrease the pH at the equivalence point.

Titration is a process in which a solution of known concentration (the titrant) is added to a solution of unknown concentration (the analyte) until the reaction between them is complete. When this reaction is complete, it is known as the equivalence point, and it is indicated by the titration curve.

The accidental dilution of the unknown acid by adding water to it before titration would affect only the pH at the equivalence point. Here's how:

Effect on volume of base used: The volume of base required to reach the equivalence point remain unaffected or unchanged as volume of base depends upon number of moles of acid. Here, dilution doesn't affects the number of moles, it is affecting the concentration of solution. That's why it doesn't matter that how much diluted a sample is, the thing matters is the number of moles of acid which are not changing.

Effect on pH at the half-equivalence point: It would not have any effect on the pH at the half-equivalence point. The pH at the half-equivalence point depends only on the dissociation constant (Ka) of the acid. It is also not affected by concentration of acid.

Effect on pH at the equivalence point: As the sample is diluted by adding water, the concentration of the acid decreases, and the amount of H+ ions released by it also decreases. Therefore, it would require fewer hydroxide ions (OH-) to neutralize the acid, which means that the pH of the equivalence point would decrease.

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Answer: D

Explanation:

took test

Answer:

D

Explanation:

got it right  

The enthalpy change for the reaction a→ca→c is -5341kJ/mol.  

Hess's law states that the enthalpy change for a reaction at constant pressure is the sum of the enthalpies of formation of the products minus the enthalpies of formation of the reactants. The enthalpy of formation of a substance is the amount of heat required to produce one mole of that substance from its elements in their standard states at constant pressure and temperature.

For part a, we need to find the enthalpy change for the reaction a→bδh= 19kja→bδh= 19kj. To do this, we can use the enthalpies of formation of the products and reactants from their standard states. The standard enthalpy of formation of water is 4 kJ/mol, and the standard enthalpies of formation of oxygen and sulfur are 0 kJ/mol and -47 kJ/mol, respectively. The standard enthalpy of formation of sulfur dioxide is -296 kJ/mol.

Using the equation for Hess's law, we can write:

ΔH = ΣΔHf - ΣΔHr

ΔH = (19kJ/mol - 0 kJ/mol) - (b - a)δh - (53kJ/mol - (b - a)δh)

Simplifying this equation, we get:

ΔH = 19kJ/mol - 0 kJ/mol - (b - a)δh - (53kJ/mol - (b - a)δh)

ΔH = 19kJ/mol - 0 kJ/mol - (b - a)δh - (53kJ/mol - (b - a)δh)

ΔH = 19kJ/mol - 0 kJ/mol - (b - a)δh - (53kJ/mol - (b - a)δh)

ΔH = 19kJ/mol - (b - a)δh - (53kJ/mol - (b - a)δh)

Substituting the values for δh, we get:

ΔH = 19kJ/mol - (b - a)29kJ/mol - (53kJ/mol - (b - a)29kJ/mol)

ΔH = 19kJ/mol - 5343kJ/mol

ΔH = -5341kJ/mol

Therefore, the enthalpy change for the reaction a→ca→c is -5341kJ/mol.  

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Answer:

The second one

Explanation:

It the graph is correct, it has the most nuetrons

The enthalpy change upon converting 2.5 g of water at -35.0 °C to steam at 140.0 °C is approximately 9035.78 J.

To calculate the enthalpy change upon converting water from -35.0 °C to steam at 140.0 °C, we need to consider the different stages of the process and calculate the enthalpy changes for each stage. The stages are as follows:

Heating the ice from -35.0 °C to 0 °C (ice to liquid water)

Melting the ice at 0 °C (phase transition)

Heating the liquid water from 0 °C to 100 °C

Converting the liquid water at 100 °C to steam at 100 °C (phase transition)

Heating the steam from 100 °C to 140 °C

Let's calculate the enthalpy changes for each stage:

Heating the ice:

The specific heat capacity of ice is given as 2.03 J/g·K. The mass of ice is 2.5 g, and the temperature change is 0 °C - (-35.0 °C) = 35.0 °C.

Enthalpy change = mass × specific heat capacity × temperature change

Enthalpy change = 2.5 g × 2.03 J/g·K × 35.0 °C = 178.38 J

Melting the ice:

The enthalpy of fusion for water is given as 6.01 kJ/mol. To convert it to J/g, we can use the molar mass of water, which is approximately 18 g/mol.

Enthalpy change = mass × enthalpy of fusion / molar mass

Enthalpy change = 2.5 g × (6.01 kJ/mol / 18 g/mol) = 0.8361 kJ = 836.1 J

Heating the liquid water:

The specific heat capacity of liquid water is given as 4.18 J/g·K. The mass of water is still 2.5 g, and the temperature change is 100 °C - 0 °C = 100 °C.

Enthalpy change = mass × specific heat capacity × temperature change

Enthalpy change = 2.5 g × 4.18 J/g·K × 100 °C = 1045 J

Converting the liquid water to steam:

The enthalpy of vaporization for water is given as 40.67 kJ/mol. Again, we need to convert it to J/g using the molar mass of water.

Enthalpy change = mass × enthalpy of vaporization / molar mass

Enthalpy change = 2.5 g × (40.67 kJ/mol / 18 g/mol) = 5.6483 kJ = 5648.3 J

Heating the steam:

The specific heat capacity of steam is given as 1.84 J/g·K. The mass of steam can be calculated using the equation: mass = mass of water + mass of ice.

mass = 2.5 g + 2.5 g = 5 g

The temperature change is 140 °C - 100 °C = 40 °C.

Enthalpy change = mass × specific heat capacity × temperature change

Enthalpy change = 5 g × 1.84 J/g·K × 40 °C = 368 J

Finally, to get the total enthalpy change, we sum up the enthalpy changes from all the stages:

Total enthalpy change = 178.38 J + 836.1 J + 1045 J + 5648.3 J + 368 J = 9035.78 J

Therefore, the enthalpy change upon converting 2.5 g of water at -35.0 °C to steam at 140.0 °C is approximately 9035.78 J.

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Answer:

what is this language i dont know about it

can you please send me in English

Answer:

a molecule of an element is called atomicity

Water and oil, Honey and tea, lemon juice in tea chocolate and milk, Examples of mixtures are coffee and cream, cream and sugar, flour and butter, and cereal and milk.

One or more distinct components of differing compositions make up a combination. The two categories of combinations are homogenous and heterogeneous mixtures. While homogeneous mixtures seem uniform throughout, forms of an element have measurable traits components.

A mixture is a substance comprised of two or more dissimilar chemical compounds that are not chemically linked in chemistry .Physical combination of two or more substances results in solutions, suspensions, or colloids, which retain the individual identities of the constituent constituents.

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The graph of P against 1/V, using 1 cm to represent 0.01 atm on the vertical axis and 1cm to represent 0.02 unit on the horizontal axis is found in the attachment.

The gas law that is in agreement with the results is Boyle's law.

Boyle's law describes the relationship between the pressure and volume of a gas at a constant temperature.

Boyle's law states that the pressure of a given amount of gas is inversely proportional to its volume.

The mathematical expression of Boyle's law is:

P1V1 = P2V2

where;

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Complete question:

b) the following result (in the table attached) were obtained at room temperature in an experiment to verify one of the gas laws using a glass syringe​

(i) Plot a graph of P against 1/v, using 1 cm to represent 0.01 atm on the vertical axis and 1cm to represent 0.02 unit on the horizontal axis.

(ii) Which of the gas laws is in agreement with the results?

Answer:

The products will occupy a volume of 56.448 L when measured at STP

Explanation:

The first thing to check here is the mole ratio of the reactant in question to the product.

From the chemical equation, we can see that 1 mole of CS2 gave a total mole of 3 moles of the products(1 mole of carbon iv oxide and 2 moles of sulphur iv oxide)

Now if 1 mole of reactant can give 3 moles of the products,

then 0.84 mole of reactant will give 3 * 0.84 moles of the product = 2.52 moles of the products

We are told to calculate the total volume.

At STP , 1 mole of a gaseous substance will occupy a volume of 22.4L or 22.4 dm^3 (liters and dm^3 are same)

This means that 2.52 moles will occupy a volume of 22.4 * 2.52 = 56.448L

Answer:

true

Explanation:

i checked on moogle

Answer:

c

Explanation:

Answer:

Proportion : The Equality of two ratios

Equation:  Values of two mathematical expressions are equal.

Formula: Mathematical relationship or rule expressed in symbols.

Explanation: