explain how the tension force gets transmitted along from one end of a string to the other. does the amount of force gets transmitted depends on how elastic or stretchable the string is

Answer:B is the right answer because you the object dose not stay still unlike the other answers

Explanation:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 10 × 16

We have the final answer as

Hope this helps you

Answer:

m

Explanation:

Metres, m, is the SI unit of length

Hope this helped you-have a good day bro cya)

A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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Answer:

t = 4.08 s

R = 40.8 m

Explanation:

The question is asking us to solve for the time of flight and the range of the rock.

Let's start by finding the total time it takes for the rock to land on the ground. We can use this constant acceleration kinematic equation to solve for the displacement in the y-direction:

We have these known variables:

And we are trying to solve for t (time). Therefore, we can plug these values into the equation and solve for t.

The time it takes for the rock to reach the ground is 4.08 seconds.

Now we can use this time in order to solve for the displacement in the x-direction. We will be using the same equation, but this time it will be in terms of the x-direction.

List out known variables:

We are trying to solve for:

By using the same equation, we can plug these known values into it and solve for Δx.

The rock lands 40.8 m from the base of the cliff.

Answer:

yoga postures and breathing techniques in Hatha yoga purify the physical body.

Explanation:

The mass of the salt obtained is 33.06 g, rounded to two significant figures.

To find the mass of the salt, we need to subtract the mass of the empty beaker from the total mass of the beaker and the salt.
Total mass of beaker + salt = 108.06 g
Mass of empty beaker = 75.0 g
Mass of salt = Total mass - Mass of empty beaker
Mass of salt = 108.06 g - 75.0 g
Mass of salt = 33.06 g
Therefore, the mass of the salt is 33.06 g, rounded to two significant figures.
When conducting experiments, measuring the mass of substances is crucial in obtaining accurate results. A beaker is a commonly used container to hold liquids and solids during experiments. The mass of the beaker needs to be known before adding any substance to it. In this case, the mass of the empty beaker is 75.0 g. To find the mass of the salt, we need to add it to the beaker and then subtract the mass of the empty beaker from the total mass. The mass of the salt obtained is 33.06 g, rounded to two significant figures.

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The mass of the salt, calculated by subtracting the mass of the empty beaker from the total mass of the beaker with salt, is 33.06 g.

To determine the mass of the salt, you have to subtract the mass of the empty beaker from the total mass of the beaker with the salt. This is done through subtraction as follows:

Total mass of beaker with salt = 108.06 g

Mass of the empty beaker = 75.0 g

So, Mass of salt = 108.06 g - 75.0 g = 33.06 g

Therefore, the mass of the salt, using the correct number of significant figures, is 33.06 g.

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The magnitude of the angular acceleration (assuming no slipping) is 0.104 rad/s².

We need to use the kinematic equation for rotational motion:

v² = u² + 2αs

where:

v is the final linear velocity,

u is the initial linear velocity,

α is the angular acceleration,

s is the linear displacement.

Given:

Diameter of the wheel = 68 cm = 0.68 m

Initial linear velocity u = 8.4 m/s

Final linear velocity v = 0 m/s (rest)

Linear displacement s = 115 m

First, we need to convert the linear displacement into angular displacement (θ).

Since the wheel rolls without slipping, the linear displacement s is equal to the angular displacement θ multiplied by the radius of the wheel (r).

r = diameter / 2 = 0.68 m / 2 = 0.34 m

θ = s / r = 115 m / 0.34 m = 338.24 radians

Next, we can substitute the given values into the kinematic equation:

0² = (8.4 m/s)² + 2α(338.24 radians)

Simplifying the equation:

0 = 70.56 m²/s² + 676.48α

Rearranging the equation:

α = -70.56 m²/s² / 676.48

   ≈ -0.104 rad/s²

Taking the magnitude of the angular acceleration, we get approximately 0.104 rad/s².

Therefore, the magnitude of the angular acceleration (assuming no slipping) is 0.104 rad/s².

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Answer:

Its called pollen. Pollen is a powdery substance consisting of pollen grains which are male microgametophytes of seed plants, which produce male gametes (sperm cells).

Hope this helps, have a great day/night and stay safe!

To determine the number of bright spots seen on a screen behind a grating when a 490 nm laser is shone through it, we need to consider the concept of diffraction and the properties of the grating.

A grating consists of a series of equally spaced slits or lines, which act as sources of secondary wavelets when illuminated by a laser beam. These secondary wavelets interfere with each other, resulting in the formation of bright and dark spots on a screen.

The number of bright spots, also known as diffraction orders, can be calculated using the formula:

m * λ = d * sin(θ)

Where:

m is the order of the bright spot,

λ is the wavelength of the laser light (490 nm = 490 × 10^(-9) m),

d is the spacing between the lines on the grating, and

θ is the angle at which the bright spot is observed.

To determine the number of bright spots, we need to know the specifics of the grating, such as the number of lines or slits and their spacing. With this information, we can use the formula mentioned above to calculate the angles and corresponding orders of the bright spots. The total number of bright spots will depend on the particular design of the grating and its parameters.

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Answer:

Energy in the campfire originates from the potential chemical energy of the wood, before it is burnt to warm and give light around the campfire.

Explanation:

For a camp fire, the energy input is in the form of the potential chemical energy, stored up in the firewood used to fuel the flame.

The energy output is in the form of heat energy that the campfire radiates all around, light energy given off from the flame, and a little bit of sound energy, heard in the cracking of the firewood as they burn in the flame.

chemical energy ⇒ heat energy + light energy + sound energy

Given:

a.

b.

To find:

a. mg into km

b. cm into nm

Explanation:

a.

Hence,

b.

Hence,

The capacitance of a parallel plate capacitor is proportional to the area of the plates. Hence option C is correct.

A capacitor is a device that stores electrical energy in an electric field by collecting electric charges on two isolated surfaces. It is a passive electronic component with two terminals.

Capacitance is the effect of a capacitor. While any two electrical conductors in close proximity in a circuit have some capacitance, a capacitor is a component designed to provide capacitance to a circuit. The capacitor was initially referred to as a condenser, a word that is still used in a few compound names, such as the condenser microphone.

Capacitance of the capacitor is directly proprtional to the area of the plates and inversly proprtional to the distance between them.

C = ∈A/d

Hence option C is correct.

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Explanation:

1. f = r/2 = 34.0/2 = 17.0 cm

2. 1/s'= -1/f - 1/s

= -1/17 - 1/50

= (-50-17) /850

= (-67) /850

s' = 850/(-67) = - 12.69 cm

3. M = |s'/s| = |-12.69/50| = 0.25

h' = 0.25×20 = 4 cm

Answer:

18 km

Explanation:

Since cost = 0 €, the value of sinθ will be 1.  Recall that the Pythagorean identity for sine and cosine states that sin²θ + cos²θ = 1. So, sin²θ = 1 - cos²θ. Given cost=0 €,cosθ=0. Substituting cosθ = 0, we get;sin²θ = 1 - cos²θ.  sin²θ = 1 - 0² = 1Therefore,sinθ = √1 = 1  

This means that sin28 = 1  Since sin20 lies in the first quadrant (0° to 90°), it will have a positive value. To determine sin20, we can use a calculator or reference a trigonometric table. To the nearest tenth of a degree, sin20 is 0.3 and it lies in the first quadrant.

An identity that expresses the Pythagorean theorem in terms of trigonometric functions is known as the Pythagorean trigonometric identity, or simply the Pythagorean identity. It is one of the fundamental relations between the sine and cosine functions, along with the sum-of-angles formulas. The angle can be any real value, and the equation is s i n 2 + c o s 2 = 1. Given both the sine value and the quadrant in which the angle is located, we can use the Pythagorean identity to determine the angle of cosine.

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Answer:

Jupiter

Explanation:

Jupiter is the largest planet in our solar system and is about 11 times larger than earth.

To determine the direction of the magnetic force in this situation, we can use the right-hand rule for the cross product of vectors.

When using the right-hand rule, you can follow these steps:

1. Extend your right hand and align your fingers in the direction of the current (from right to left in this case).

2. Curl your fingers towards the direction of the magnetic field (upwards in this case).

3. Your thumb will point in the direction of the magnetic force.

In this scenario, if the current is traveling from right to left along the wire and the magnetic field is pointing straight up, the magnetic force will be directed out of the screen or towards you.

So, the magnetic force in this situation is directed towards you.

Answer:

Approximately \(2.69\; {\rm A}\).

Explanation:

Ensure that all values are measured in standard units. Charge should be measured in coulombs, while time should be measured in seconds:

\(\begin{aligned}t &= 3.0\; {\rm hr} \times \frac{3600\; {\rm s}}{1\; {\rm hr}} = 10800\; {\rm s}\end{aligned}\).

Electric current \(I\) is the rate of flow of electric charge.

In order to find the electric current, divide electric charge \(q\) by the time \(t\) required to transfer these charge. If charge \(q\!\) is measured in coulombs and time \(t\!\) is measured in seconds, the unit of current \(I\)would be amperes:

\(\begin{aligned}I & = \frac{q}{t} \\ &= \frac{29000\; {\rm C}}{10800\; {\rm s}} \approx 2.69\; {\rm A}\end{aligned}\).

The commonality between an engine using gasoline to power a car and boiling an egg is that they both involve a transformation of energy from one form to another.

Gasoline is a liquid fuel that is primarily used to power internal combustion engines, such as those found in cars, trucks, and motorcycles. It is a mixture of various hydrocarbons, typically derived from crude oil through the refining process. The composition of gasoline can vary depending on the source and refining process, but it typically contains hydrocarbons with between 4 and 12 carbon atoms per molecule. The most common hydrocarbons found in gasoline are isooctane and heptane, which are used to determine the octane rating of gasoline.

Gasoline is a highly flammable substance that must be handled and transported with care. It is typically stored in underground tanks at gas stations and delivered to vehicles through pumps. In addition to its use as a fuel, gasoline is also used as a solvent and a raw material to produce other chemicals.

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Answer: Wave a the first answer is right

Brainliest.

Explanation:

If a 0.2-ml blood sample with a paco2 of 40 mm hg diffuses across a membrane into the e2 electrode containing 0.3 ml of solution, the final paco2 in the blood sample will be less than 16 mm Hg.

PaCO2(initial)×Vinitial=PaCO2(final)×Vfinal

(40 mm Hg)(0.2 mL)=PaCO2(final)×(0.5 mL)

PaCO2(final)=16 mm Hg

In this example, CO2 diffuses from blood into a reaction solution, where some of the CO2 is removed as it is converted to HCO3−.

See the image given below:

In this case, the force required to lift the object is equal to its weight, which is the product of its mass and the acceleration due to gravity is approximately 3,585.6 joules.

The work done on an object is given by the equation:

work = force × distance.

In this case, the force required to lift the object is equal to its weight, which can be calculated using the formula:

weight = mass × acceleration due to gravity.

The mass of the object is given as 68 kg, and the acceleration due to gravity is approximately 9.8 m/s².

Therefore, the weight of the object is

(68 kg) × (9.8 m/s²)

= 666.4 newtons.

Now, we can calculate the work done by multiplying the force (weight) by the distance lifted. The distance lifted is given as 5.3 m.

Therefore, the work done is

(666.4 N) × (5.3 m)

= 3,585.6 joules.

Hence, approximately 3,585.6 joules of work needs to be done to lift the 68 kg object by 5.3 m.

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Friction affects the work done by machines by reducing the mechanical advantage of that machine.

MA = \(F_{o}\) / \(F_{i}\)

MA = Mechanical advantage

\(F_{o}\) = Output force

\(F_{i}\) = Input force

Mechanical advantage is the ratio of output force to input force in a system.

According to law of conservation of energy, input energy is equal to output energy. It is true in the machines also but some of the output energy is not necessarily asked of the machine. That energy which is not useful is heat produced due to friction.

Therefore, friction affects the work done by machines by reducing the mechanical advantage of that machine.

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Time = (distance) / (speed)

Time = (26 meters) / (8 meters/hour)

Time = 3.25 hours or 3 hours 15 minutes

Refraction results from differences in light's speed. The correct answer is C) speed.

Refraction is the term for the bending of light as it passes through transparent materials (it also occurs with sound, water, and other waves). We are able to create lenses, magnifying glasses, prisms, and rainbows because to this bending caused by refraction.

Refraction occurs when light passes through different mediums and changes its speed. This change in speed causes the light to bend, creating the effect of refraction.

This is why objects appear to be in different positions when viewed through water or a lens. The frequency and incident angles of the light do not affect refraction, only the speed of the light does.

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A radio frequency identification application would most likely interface with an Operational Data Store.

The Operations Data Store (ODS) is a central database that provides the latest data snapshots from multiple transaction systems for operational reporting.

It allows organizations to combine data in its original format from various sources into a single destination to provide business reporting.

ODS contains integrated updates from operational sources and supports business intelligence (BI) tools to facilitate tactical decision making.

For example, an administrator can configure ODS to pull weekly batches of data from a billing application that is rarely updated, importing individual transaction records as they occur in the sales database(thanks to these database triggers), then combine the two into new relational tables.

As a result, querying and reporting on operational data in ODS comes with the assurance that these integrated tables contain the latest and most relevant snapshots of the business.

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Answer: I think a

Explanation:

Answer:

A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.

Explanation:

Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

The period is the time that elapses between the emission of two consecutive waves. In other words, it is the time it takes for a complete wave to pass a reference point. The period (T) is simply the inverse of the frequency (f):

\(T=\frac{1}{f}\)

In this case, f=5*10¹⁰ Hz. So, replacing in the definition of period T:

\(T=\frac{1}{5*10^{10} Hz }\)

Solving:

T= 2*10⁻¹¹ seconds

A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.

A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.

The fequency is defined as the number of cycles achieved by the any wave it is expressed in hertz.

Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

The period is the time that elapses between the emission of two consecutive waves. In other words, it is the time it takes for a complete wave to pass a reference point. The period (T) is simply the inverse of the frequency (f):

\(T=\dfrac{1}{f}\)

In this case, f=5*10¹⁰ Hz. So, replacing in the definition of period T:

\(T=\dfrac{1}{5\times 10^{10}}=2\times 10^{-11}\ Sec\)

A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.

Thus a microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.

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An airplane is flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. The  pressure at the point on the wing is  \(P = 6.96 * 10^4 N/m^2\).

To calculate the pressure at a point on the wing, we can use Bernoulli's equation, which relates the pressure, velocity, and density of a fluid in steady, incompressible flow.

The equation is as follows:

P + 1/2 * ρ * \(V^2\) = constant

where P is the pressure, ρ is the density of the fluid, and V is the velocity of the fluid.

Given:

\(P_1 = 7.01 * 10^4 N/m^2\) (pressure at standard altitude)

ρ = \(0.909 kg/m^3\) (density of the fluid)

\(V_1 = 42 m/s\) (velocity of the airplane)

\(V_2 = 88 m/s\) (velocity at the point on the wing)

To find the pressure at the point on the wing, we can use Bernoulli's equation for the standard altitude and the point on the wing, and then solve for P:

\(P_1 + 1/2\) * ρ * \(V_1^2\) = \(P + 1/2\)  * ρ * \(V_2^2\)

Substituting the given values:

\(7.01 * 10^4 + 1/2 * 0.909 * 42^2 = P + 1/2 * 0.909 * 88^2\)

Simplifying the equation:

\(7.01 × 10^4 + 1/2 * 0.909 * 1764 = P + 1/2 * 0.909 * 7744\)

7.01 × 10^4 + 804.906 = P + 3526.242

\(P + 4329.148 = 7.01 *10^4\)

\(P = 7.01 * 10^4 - 4329.148\)

\(P = 6.96 * 10^4 N/m^2\)

Therefore, the pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\)

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