Answer:
The simple way to put it, sound energy comes from vibrations moving through something. ... Sound energy is the result when a force, either sound or pressure, makes an object or substance vibrate. That energy moves through the substance in waves. Those sound waves are called kinetic mechanical energy.
Hope this helps (≖ᴗ≖✿)
Ability to make things move is called
Answer:
Force
Explanation:
You can't "make" things move but you can apply enough force on to an object for it to move, pls brainliest!
The anomalous expansion characteristics of liquid water are crucial to many biological systems. Rather than an approximately constant value for the coefficient of volume expansion, the value for water changes drastically, as illustrated in the figure.
Below what temperature T
does water shrink when heated?
If the temperature of water at 30 ∘C
is raised by 1 ∘C
, the water will expand. At approximately what initial temperature T
will water expand by twice as much when raised by 1 ∘C
?
(A) The water will shrink when is heated above 4°C. (B).water at an initial temperature of 33.3°C will be expand by twice as much when it is raised by 1°C compared to water at 30°C.
The anomalous expansion of water refers to the fact that its volume increases upon cooling from 4°C to 0°C, and then contracts upon further cooling to 0°C, and continues to contract upon further cooling. Similarly, when water is heated, its volume first contracts until it reaches 4°C, and then expands upon further heating.
To determine at what temperature water shrinks when heated, we need to find the point at which the coefficient of volume expansion, β, becomes negative. The coefficient of volume expansion is defined as the fractional change in volume per degree Celsius change in temperature, i.e.,
β = (1/V) (dV/dT)
where V is the volume of the water and dV/dT is the rate of change of volume with respect to temperature.
At temperatures below 4°C, the coefficient of volume expansion is positive, indicating that water expands upon heating. However, at temperatures above 4°C, the coefficient of volume expansion becomes negative, indicating that water contracts upon heating.
Therefore, water will shrink when heated above 4°C.
To determine the initial temperature at which water will expand by twice as much when raised by 1°C, we can use the formula for the coefficient of volume expansion:
β = (1/V) (dV/dT)
We want to find the initial temperature T such that
(dV/dT)T = 2 (dV/dT)30
where (dV/dT)T is the rate of change of volume with respect to temperature at temperature T, and (dV/dT)30 is the rate of change of volume with respect to temperature at 30°C.
Using the coefficient of volume expansion for water, we have
β = 3α
where α is the coefficient of linear expansion, which is approximately constant for small temperature changes. Therefore, we can write
(dV/dT) = V × 3α
Substituting this into the equation above and simplifying, we get
T = 30 + 10/3 = 33.3°C
Therefore, water at an initial temperature of 33.3°C will expand by twice as much when raised by 1°C compared to water at 30°C.
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five point charges placed on a straight line, at intervals d= 2 cm. We give Q3=Q5 = 8C and Q4 = 4 . For what values of q1 and q2 is the resultant electric force exerted on each of the other three charges zero?
The values of q1 and q2 in which the resultant electric force exerted on each of the other three charges zero is - 4C.
What is the value of q1 and q2?
The value of charges q1 and q2 is calculated by applying the formula for electric force as shown below.
F = (kqₙqₓ) / (d²)
where;
K is Coulomb's constantq is the magnitude of the chargesd is the distance between the chargesIf the force exerted on each of the other three charges is zero, then
F₁₃ + F₃₄ = 0
F₂₃ + F₃₄ = 0
F₁₃ = (k x q₁ x 8) / (d²)
F₂₃ = (k x q₂ x 8 ) / (d²)
F₃₄ = (k x 8 x 4 ) / (d²)
F₁₃ = - F₃₄
(k x q₁ x 8) / (d²) = - (k x 8 x 4 ) / (d²)
8q₁ = - 32
q₁ = -32 / 8
q₁ = - 4 C
F₂₃ = - F₃₄
(k x q₂ x 8 ) / (d²) = - (k x 8 x 4 ) / (d²)
q₂ = - 4 C
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The figure shows a cube resting on top of a table . If the table rotates and moves the cube in a counterclockwise circle at a constant speed , describe the direction of the acceleration experienced by the cube .
Answer:
Forwarded
Explanation:
What is hydrometer? Describe its use and any one type of hydrometer.
Answer:
An instrument for measuring the density of liquids.
Explanation:
A hydrometer is an instrument used to determine specific gravity. It operates based on the Archimedes principle that a solid body displaces its own weight within a liquid in which it floats. Hydrometers can be divided into two general classes: liquids heavier than water and liquids lighter than water.
Thermohydrometers is one type of hydrometer.
An object moves from position x = -1.88 m to x = -4.27 m. What is it's displacement?
Answer: Displacement = -2.39 m
Explanation: The displacement of an object is the difference between its final position and its initial position. In this case, the object moved from x = -1.88 m to x = -4.27 m, so its displacement is:
Displacement = Final position - Initial position
Displacement = (-4.27 m) - (-1.88 m)
Displacement = -4.27 m + 1.88 m
Displacement = -2.39 m
Therefore, the displacement of the object is -2.39 m.
Please mark me brainliest if you understand now! Thank you
Determine the work done by the constant force. The locomotive of a freight train pulls its cars with a constant force of 15 tons a distance of one-quarter mile.
Answer:
5.92×10⁷ J
Explanation:
We'll begin by converting 15 tons to Newton. This can be obtained as follow:
1 ton = 9806.65 N
Therefore,
15 ton = 15 ton × 9806.65 N / 1 ton
15 ton = 147099.75 N
Next, we shall convert one-quarter (¼) or 0.25 mile to metre. This can be obtained as follow:
100 mi = 160934 m
0.25 mi = 0.25 mi × 160934 / 100 mi
0.25 mi = 402.335 m
Finally, we shall determine the Workdone. This can be obtained as follow:
Force (F) = 147099.75 N
Distance (d) = 402.335 m
Workdone (Wd) =?
Wd = F × d
Wd = 147099.75 × 402.335
Wd = 5.92×10⁷ J
Thus, the Workdone is 5.92×10⁷ J
b. Density and relative density.
Explanation:
density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.
The relative density of a substance is defined as the ratio of the density of that substance to the density of water at 4oC. It is also defined as the ratio of the mass of substance to the mass of equal volume of water at 4oC. i.e., R.D. = Mass of the substance / mass of an equal volume of water at 4oC
the distance between two successive maxima of a certain transverse wave is 1.2m height crests or maxima pass a given point along the direction of travek every 12a calcultae the wave speed
The wave speed is 01 m/s, which can be calculated by using the formula:
wave speed distance between two successive maxima/time interval between two successive maxima
In this case, the distance between two successive maxima is given as 1.2m and the time
interval between two successive maxima is given as 12s.
So, the wave speed can be calculated as:
wave speed = 1.2m/12s = 0.1 m/s
It is worth mentioning that the wave speed is a scalar quantity, which means it has only magnitude and no direction. The given information is about the transverse wave which is a type of wave in which the oscillation is perpendicular to the direction of energy transfer
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Why are theories constructed
A) During the experiment
B) after data is collected from an experiment
C) before the experiment
D) after there is numerous data collected
Answer:
The correct answer is d.
Theories are constructed after there is numerous data collected during the experiment.
Explanation:
hope it helps
Pushing a chair is a law of______?
A. Law of friction
B. Law of interaction
C. Law of acceleration
D. Law of universal gravitation
please help..
Answer:
A.Law of friction
Explanation:
because friction is the move chair floor
True or false-Normal reaction is the force
that opposes the force of gravity and acts in
the direction of the force of gravity.
O True
O False
false
normal force always acts perpendicular to the contact force
When an archer draws back their bowstring before they fire, what type of energy is stored in the bowstring?
A. Thermal energy
B. Elastic potential energy
C. Nuclear energy
D. Kinetic mechanical energy
Answer: B
Explanation: the energy stored in the bowstring is a result of the elastic nature of the string (k) how far the bow has been stretched (x).
elastic potential energy is the energy stored in any elastic material when stretched.
ayuden ha resolver este ejercicio porfa
Answer:
un café y a seguir pensando porque no se la respuesta xd
A graduated cylinder contains 20.0ml of water. After a rock is placed in the cylinder, the level rises as shown below. what is the volume of the rock
The volume of the rock, given the data is 14 mL (Option A)
Data obtained from the questionFrom the question given above, the following data were obtained:
Volume of water = 20 mLVolume of water + rock = 34 mLVolume of rock =?How to determine the volume of the rockThe volume of the rock can be obtained by calculating the displacement of the water when the rock was added. this can be obtained as follow:
Displacement of water = (Volume of water + rock) - (volume of water)
Displacement of water = 34 - 20
Displacement of water = 14 mL
Thus, the volume of the rock is 14 mL
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Complete question:
See attached photo
4. What is stellar parallax?
Answer:
I don't k own what it is dad fjf f fjff
Answer:
Explanation:
Stellar parallax is the apparent shift of position of any nearby star against the background of distant objects
HALP I NEED THE ANSWER!!!! Move on to electric force. Blow up the two balloons and knot them. Then tie a thread onto each balloon. Suspend the two balloons using tape so that they’re about six inches apart, and check that they don’t move or interact. Rub both balloons with wool or fur. If wool or fur is not available, rub the balloons on your hair. Do they attract or repel (push away) each other?
Answer:
Attract
Explanation:
The balloons attract each other due to electrons.
Hope this helps :)
Samir is waiting for a slow reaction to finish. What is the best way to make the reaction go faster?
Question 12 options:
Put it in the fridge where it is cold
Cover it with a blanket so it's dark
Warm it up on the stove
There is nothing you can do to change the speed of the reaction
In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.
Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct
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A 30cm long tendon was found to stretch 9.0mm by a force of 11.2N.The tendon was approximately round with an average diameter of 8.9 mm.Calculate Young's modulus of this tendon.
Answer:
Young's Modulus = 6 x 10⁶ Pa = 6 MPa
Explanation:
First we need to find the stress on tendon:
Stress = Force/Area
Stress = 11.2 N/πr²
Stress = (11.2 N)/π(4.45 x 10⁻³ m)²
Stress = 180 x 10³ Pa
Now, we calculate the strain:
Strain = Change in length/Original Length
Strain = (9 x 10⁻³ m)/(0.3 m)
Strain = 0.03
Now, we calculate the Young's Modulus:
Young's Modulus = Stress/Strain
Young's Modulus = (180 x 10³ Pa)/0.03
Young's Modulus = 6 x 10⁶ Pa = 6 MPa
A deer with a mass of 156 kg is running head on toward you with a speed of 10 m/s. Find the momentum of the deer
Hi there!
\(\large\boxed{1560 kgm/s}\)
Recall that:
P = m · v, where:
P = momentum
m = mass (kg)
v = velocity (m/s)
Thus:
P = 156 · 10
P = 1560 kgm/s
Given the two vectors A =i+ j and B = j + k, find the following.
(a) A + B and |A + B|
(b) 3A - 2B
(c) A • B
(d) AxB and |AxB|
a) The value of the vector A + B is i + 2j + k and |A + B| is √6 units.
Given:
A = i + j
B = j + k
A + B = i + j + j + k
= i + 2j + k
|A + B| is the magnitude of the vectors A and B
|A + B| = √(1² + 2² + 1²)
= √(1 + 4 +1)
= √6
b) The vector 3A - 2B has the value of 3i + j -2k
Given:
A = i + j
3A = 3i + 3j
B = j + k
2B = 2j + 2k
3A - 2B = 3i + 3j - 2j - 2k
= 3i + j -2k
c) The scalar product of the vector that is A • B is equal to 3 units
The scalar product is calculated as follows:
A • B = i + j • j + k
= 1 + 1 * 1 + 1
= 1 + 1 + 1
= 3 units
d) The vector product or A x B is i - j + k and the magnitude of the same is √3 units.
i j k
A 1 1 0
B 0 1 1
The vector product is calculated as follows:
A x B = (1 * 1 - 1 * 0) i + (0 * 0 - 1 * 0) j + (1 * 1 - 0 * 1) k
= (1 - 0) i + (0 - 1) j + (1 - 0) k
= i - j + k
| A x B | = √(1² + (-1)² + 1²
= √1 + 1 + 1
= √3 units
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When a rural road becomes a city road what type of road condition are you dealing with?
Answer:
Potholes, large cracks, and a generally bumpy (and not smooth) road.
Explanation:
Rural roads tend to be poorly kept as they are not usually paid for by the city's tax money.
Poor road characteristics can include;
Potholes, fallen trees, uncovered water drains, and shoulder drop off (the shoulder – right side of the road past the solid white line – drops more than two inches from the road's surface).
SOURCE:
https://www.edgarsnyder.com/car-accident/cause-of-accident/bad-roads/hazardous-roads-types.html
how long does it take for light to travel 2.5m in water?
3.) A boat is moving south at 15.0, a passenger is walking north along the boat deck at 4.0 and throws a
rock north at 3.0, what is the velocity of the rock when viewed from the boat and the shore? (2)
A device that has the capacity to receive and store electrical energy is a(n)
.
Answer:
Yes, capacitor is the correct answer
Explanation:
When you apply a horizontal force of 51 N to a block, the block moves across the floor at a constant speed. (a) When you apply a force of 40 N to the block initially at rest, what is the magnitude of the horizontal component of the force that the floor exerts on the block? (b) When you apply a force of 59 N, what is the magnitude of the horizontal component of the force that the floor exerts on the block?
(a) When you apply a force of 40 N, the magnitude of the horizontal component of the force that the floor exerts on the block is 51 N.
(b) When you apply a force of 59 N, the magnitude of the horizontal component of the force that the floor exerts on the block is 51 N.
Net force on the blockThe horizontal component of the force that the floor exerts on the block is determined by applying Newton's second law of motion;
\(F = ma\)
When the block moves at a constant speed\(\Sigma F = 0\\\\F - F_f = 0\\\\F = F_f\)
\(F_f = F\\\\F_f = 51 \ N\)
where;
\(F_f\) is the frictional force exerted on the block by the floorSince the surface (floor) is constant, the frictional force (horizontal component of the force that the floor exerts on the block ) will be the same on the cases.
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Based on the definition of limiting frictional force;
the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 40 N when a force of 40 N is applied to the block, the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 51 N, the limiting frictional force, when a force of 59 N is applied to the block.What is force?Force is any push or pull effect which tends to cause a change in the motion or shape of an object.
Based on Newton's third law, every force produces an equal and opposite reaction.
Therefore, the force that the floor exerts on the block is oppositely direction to the force exerted by the horizontal force acting on the block.
Since a horizontal force of 51 N applied to the block is required to keep the block moving across the floor at a constant speed, this is the limiting frictional force.
a) when a force of 40 N is applied to the block, the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 40 N
b) when a force of 59 N is applied to the block, the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 51 N, the limiting frictional force.
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A car is moving at 5 m/s. 2 seconds later, it is traveling at 17 m/s. How far did the car go?
Equation 1: Vf = Vo+at
Equation 2: Vf2=V0+2ad
Equation 3: Xf=X0+vot+12at2
Equation 4: Xf=X0+(vf+vo2)t
Answer:
gh
Explanation:
A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.625 kg mass attached to the other end. The pulley, which is a disk of radius 9.00 cm , has friction in its axle.What is the magnitude of the frictional torque that must be exerted by the axle if the system is to be in static equilibrium? (Answer should be in N m)
Answer:
The frictional torque is \(\tau = 0.2505 \ N \cdot m\)
Explanation:
From the question we are told that
The mass attached to one end the string is \(m_1 = 0.341 \ kg\)
The mass attached to the other end of the string is \(m_2 = 0.625 \ kg\)
The radius of the disk is \(r = 9.00 \ cm = 0.09 \ m\)
At equilibrium the tension on the string due to the first mass is mathematically represented as
\(T_1 = m_1 * g\)
substituting values
\(T_1 = 0.341 * 9.8\)
\(T_1 = 3.342 \ N\)
At equilibrium the tension on the string due to the mass is mathematically represented as
\(T_2 = m_2 * g\)
\(T_2 = 0.625 * 9.8\)
\(T_2 = 6.125 \ N\)
The frictional torque that must be exerted is mathematically represented as
\(\tau = (T_2 * r ) - (T_1 * r )\)
substituting values
\(\tau = ( 6.125 * 0.09 ) - (3.342 * 0.09 )\)
\(\tau = 0.2505 \ N \cdot m\)
Answer:here to earn points
Explanation:
A guy wire 1000 feet long is attached to the top of a tower. When pulled taut it makes a 42˚ angle with the ground. How tall is the tower? How far away from the base of the tower does the wire hit the ground?
Answer:
669.1 ft and 743.1 ft
Explanation:
Given data
Lenght of wire= = 1000ft
Angle = 42˚
Applying SOH CAH TOA
1. How tall is the tower?
SOH
sine ∅= opp/hyp
sin 42= opp/1000
0.6691= Opp/1000
0.6691*1000= Opp
Opp=669.1 ft
Applying SOH CAH TOA
2.How far away from the base of the tower does the wire hit the ground?
CAH
cos ∅= adj/hyp
cos 42= adj/1000
0.7431*1000=adj
adj=743.1 ft
What must your speed be in order to travel 400 km in 3 hrs?
Answer:
\(\boxed {\tt s=133 \frac{1}{3} \ or \ 133.333333 \ km/hr}\)
Explanation:
We want to find speed, so we can use the following formula.
\(s=\frac{d}{t}\)
where \(d\) is the distance traveled and \(t\) is the time.
We traveled 400 kilometers in 3 hours. Therefore,
\(d= 400 \ km \\t= 3 \ hrs\)
Substitute the values into the formula.
\(s=\frac{400 \ km }{3 \ hrs}\)
Divide
\(s= 133.33333 \ km/hr\)
\(s= 133 \frac{1}{3} \ km/hr\)
The speed is 133 1/3 or 133.33333 kilometers per hour.