Explain the concept of relative velocity

Answer: f = -12 cm

Explanation: Combined lenses is an array of  simple lenses with a common axis. The combination is useful for correction of optical aberrations which cannot be corrected by simple lenses.

When two lenses are in contact and are thin, focal lengths are related as:

\(\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}\)

If there is a distance between the lenses, the focal length will be:

\(\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}} -\frac{d}{f_{1}f_{2}}\)

Since the lenses in the question above are thin and in contact, the focal length of one of them will be:

\(\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}\)

\(\frac{1}{f_{2}} =\frac{1}{f_{1}} -\frac{1}{F}\)

\(\frac{1}{f_{2}} =\frac{1}{8} -\frac{1}{24}\)

\(\frac{1}{f_{2}} =\frac{-2}{24}\)

\(f_{2}=\) -12

The focal length of the other lens is -12 cm, with the negative sign meaning it's a converging lens.

Answer:

0.00033333333

Explanation:

Answer:

c.

Equal to 200 N..........

Yes it can, an object can be moving a certain direction while the ACCELERATION is in the opposite direction.

Lets say your riding a bike... if your squeezing your handle bar breaks, the acceleration of the bike would be pushing in the opposite direction of the direction the bike is moving.

Hope this helped!

Answer:

carbon isnt 12

Explanation:

Answer:

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

Explanation:

Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that:

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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The heat released in the whole process in which a sample of water is cooled and frozen is 4.64 * 10⁸ J.

The problem is to be divided into two steps. This process releases a certain quantity of heat,

Step 1) Solidification of the water at 0°C into ice.

Q = m* Lf

where,

m is the mass of the water

Lf stands for the latent heat of ice fusion

Substituting numbers, we find

Q₁ = (1271 kg)* (334 kJ/kg) = 424514 kJ = 4.2* 10⁸ J

step 2) The water became ice, now we need to cool it down to -36°C . This process releases a certain quantity of heat, which is

Q₂ = m* Cs* ΔT

where,

m is the mass of ice

Cs is the specific heat of ice

ΔT is the variation of temperature

By placing the numbers in the formula, we have,

Q₂ = (1271 kg)* (2050 J/kg K) (-17-0) = 44294350 J = - 0.44 * 10⁸ J

The negative sign means the heat is released by the system.

Thus, the overall process produces heat that is

Q = Q₁ + Q₂ = 4.2* 10⁸ J + 0.44 * 10⁸ J = 4.64 * 10⁸ J

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The maximum force of static friction that the car's wheels can experience with the flat concrete road is  μ×5000 N.

The force of friction that the wheels experience when the car is moving is less than maximum force of static friction.

The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.

As the normal force = 5000 N.

The maximum force of static friction = μ×5000 N.

The force of friction that the wheels experience when the car is moving is less than maximum force of static friction.

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The effort distance of a lever should be increased to lift a heavier load because it provides a mechanical advantage, allowing for easier lifting of the load.

The effort distance of a lever should be increased to lift a heavier load because it allows for a mechanical advantage that compensates for the increased weight.

In a lever system, the effort distance is the distance between the point of application of the input force (effort) and the fulcrum, while the load distance is the distance between the point of application of the output force (load) and the fulcrum. The mechanical advantage of a lever is determined by the ratio of the load distance to the effort distance.

By increasing the effort distance, the mechanical advantage of the lever system is increased. This means that for the same input force (effort), a greater output force (load) can be achieved. When dealing with a heavier load, a higher mechanical advantage is required to overcome the increased resistance.

By increasing the effort distance, the lever system can effectively multiply the applied force, making it easier to lift the heavier load. This allows for the redistribution of force and facilitates the efficient use of human effort in various applications, such as in construction, engineering, and even everyday tools like scissors and pliers.

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The correct answer isThe astronaut's b) mass remains the same.

The mass of an object remains constant regardless of its position or distance from the center of the Earth. Mass is a measure of the amount of matter in an object and is an intrinsic property. It does not change with the position or location of the object.

On the other hand, the weight of an object can vary depending on its distance from the center of the Earth. Weight is the force experienced by an object due to gravity and is dependent on the mass of the object and the gravitational acceleration at its location.

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As an astronaunt travels from the surface of the earth to a postion that is four times

as far away from the center of the earth, the astronaut's

a) mass decreases

b)

mass remains the same

c) weight increases

d) weight remains the same

The ranking of the voltages, V₁, V₂, V₃, and V₄ in the order of decreasing voltage value is; V₂ > V₃ > V₁ > V₄

A voltage is the difference in potential or pressure that pushes or causes the flow of electric current in a circuit or conducting loop.

The current flowing through the circuit can be found using the following formula;

\(I=\dfrac{V}{R}\)

The formula for conductivity is presented as follows;

\(\sigma =\dfrac{l}{R\times A}\)

Where;

σ = The conductivity of the material

l = The length

R = The resistance to electricity

A = The cross-sectional area of the conductor

Therefore;

\(R=\dfrac{V}{I}\)

\(R=\dfrac{l}{A\times \sigma}\)

\(\dfrac{V}{I} =\dfrac{l}{A\times \sigma}\)

\(V=\dfrac{l \times I}{A\times \sigma}\)

Based on the dimensions of the cylinders, obtained from a similar question, we get;

\(V_1=\dfrac{3\cdot L \times I}{\pi \cdot D^2\times \sigma} = 3\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}\)

\(V_2= \dfrac{2\cdot L \times I}{\pi \cdot \dfrac{D^2}{4} \times \sigma} = \dfrac{8\cdot L \times I}{\pi \cdot D^2\times \sigma} = 8\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}\)

\(V_3=\dfrac{L \times I}{\pi \cdot \dfrac{D^2}{4} \times \sigma} =\dfrac{4\cdot L \times I}{\pi \cdot D^2\times \sigma}= 4\times \dfrac{L \times I}{\pi \cdot D^2\times \sigma}\)

\(V_4=\dfrac{L \times I}{\pi \cdot D^2\times \sigma} = 1\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}\)

Therefore;

V₁ = 3·V₄

V₂ = 8·V₄

V₃ = 4·V₄

The rank of the voltages in the order of decreasing value is therefore;

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The correct drills that can be used to practice digging in volleyball are b. shuffle steps and c. knock out drill.

b. Shuffle steps: Shuffle steps are an essential footwork drill for improving defensive movements, including digging.

In this drill, players shuffle laterally in a low defensive stance, simulating the movements required to dig a ball. It helps players develop quick and efficient footwork, enabling them to react and move quickly to reach the ball for a dig.

c. Knock out drill: The knock out drill focuses on improving a player's reaction time and defensive skills. In this drill, players form a line and take turns receiving rapid hits or "knocks" from a coach or teammate.

The objective is to successfully dig each hit and keep the ball in play.

This drill helps players develop their reflexes, positioning, and technique when digging in various directions and angles.

a. Double decker and 1. toss catch drill are not specific drills for practicing digging in volleyball. Double decker is a term used to describe a defensive formation, while the toss catch drill is more focused on developing ball control and setting skills rather than digging.

By incorporating shuffle steps and the knock out drill into practice sessions, players can enhance their digging abilities, improve their defensive movements, and develop the necessary skills to successfully retrieve hard-driven balls in a game situation.

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Answer:

m = 2.4

Explanation:

Given that,

Input force, \(F_i=5\ N\)

Output force, \(F_o=12\ N\)

We need to find the mechanical advantage of the ramp. The ratio of output force to the input force is equal to mechanical advantage. So,

\(m=\dfrac{12}{5}\\\\m=2.4\)

So, the mechanical advantage of his ramp is 2.4.

Answer:

This answer was wrong

Explanation:

I took the test and I missed this question.  So it is not answer B: pass a literacy test.  

It will need an A. pass a vision and hearing test

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Total weight in tons

\(\\ \sf\longmapsto 2.3\times 10^6\times 2.4\)

\(\\ \sf\longmapsto 5.52\times 10^6\)

\(\\ \sf\longmapsto 5520000ton\)

\(\\ \sf\longmapsto 5520000\times 1000\)

\(\\ \sf\longmapsto 5520000000kg\)

\(\\ \sf\longmapsto 5.52\times 10^9Kg\)

The wavelength of the light is 1.92 * 10^-6 m which corresponds to the infrared region as shown in the image attached.

We know that the hydrogen atom has electrons that occupy energy levels that are in conformity with the Bohr model. According to the Bohr model, electrons can move from a higher to a lower energy level.

We now have;

1/λ = RH (1/\(n_{2} ^2\) - 1/\(n_{1}^2\))

λ = wavelength

RH = Rydberg constant

The initial and the final levels are also shown therefore;

1/λ = 1.097 * 10^7 ( 1/3^2 - 1/4^2)

1/λ= 1.097 * 10^7 (0.11 - 0.0625)

λ=1.92 * 10^-6 m

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Short circuits occur when a high-volume electrical current is passed through a low-resistance path that isn't meant to carry electricity. Short circuits occur when a live wire makes contact with a conductive object that it should not have.

The most dangerous aspect of a short circuit is that it will cause a sudden and dramatic change in electrical resistance. Electrical systems can cause a large amount of resistance and will be constantly sending electricity to different areas when appliances are plugged in or outlets are being used. This has the possibility to cause bodily harm and appliance damage to those who are using electrical appliances at the time a short circuit happens, and can also cause structural damage to your home through fires and burns

Wires with faulty or unstable connections will create a situation in which the electrical current can take a detour down an unintended path if it is the one of least resistance. This can be unpredictable, and the route that the current travels could be through flammable materials or a human being.

Short circuits are liable to cause fires, electrical burns, and electrocution. Stray electrical currents can also cause considerable damage to appliances and a home’s electrical system.

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Answer:

Explanation:

a) The position of the particle at t=2sec

X=12t² -2t³ = 12*2² -2*2³=48-16=32m

b)velocity of particle = dx/dt=24t-6t²

velocity of particle at t=3sec is 24*3-6*3² =72-54=18 m/s

Acceleration = dv/dt = 24-12t

acceleration at t=3sec is 24-12(3)= -12 m/s²

The potential difference across the each bulb and the current entering each bulb.

Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.

The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.

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Using the formula for the Doppler effect:

f' = (v + vr) / (v + vs) * f

Given:

Source frequency (horn): f = 625 Hz

Speed of sound: v = 343 m/s (approximate value at room temperature)

The velocity of the receiver, vr, is zero because the person waiting at the crosswalk is stationary.

The velocity of the source, vs, is the speed of the car, which is given as 9.0 m/s.

Thus:

f' = (v + vr) / (v + vs) * f

= (343 m/s + 0) / (343 m/s + 9.0 m/s) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

Therefore, the person waiting at the crosswalk hears a frequency of approximately 609 Hz.

(2)Using the same Doppler effect formula:

f' = (v - vr) / (v - vs) * f

In this case, the velocity of the receiver, vr, is still zero because the person remains stationary.

The velocity of the source, vs, is now negative, indicating that the car is moving away from the person.

Thus:

f' = (v - vr) / (v - vs) * f

= (343 m/s + 0) / (343 m/s - (-9.0 m/s)) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

In other words, as the car moves away from the person, they would still hear a frequency of approximately 609 Hz.

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Answer: It’s fastest in gases. Letter C !

Explanation:

Answer:

its c

Explanation:

Answer:

3rd sentence

Explanation:

Answer:

90.3N

Explanation:

⊥mg = (0.170 m)(1.20 kg) 9.81 m/s

τ ball = r⊥Wball = (0.340 m)(1.42 N) = − 0.483 N ⋅m

F − 2.001− 0.483 N ⋅m = 0

F = 2.484 N ⋅m

0.0275 m = 90.3 N

The net torque acting on the forearm and hand is 90.3N

Torque is a measure of the pressure that can motivate an object to rotate about an axis. simply as pressure is what causes an object to accelerate in linear kinematics, torque is what reasons an item to collect angular acceleration. Torque is a vector amount.

⇒mg = (0.170 m)(1.20 kg) 9.81 m/s

⇒torque = r⊥weight of the ball

⇒ (0.340 m)(1.42 N) = − 0.483 N ⋅m

⇒F = − 2.001− 0.483 N ⋅m = 0

⇒F = 2.484 N ⋅m

⇒0.0275 m = 90.3 N

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Answer:

7 degree

Explanation:

given data

width = 4.1 inches

length = 35.4 inches

solution

we consider as per fig

O is mid point of BC

so  OB  = 2.05 inches

and

AB = \(\sqrt{OB^2 + OA^2}\)

AB = \(\sqrt{2.05^2 + 35.4^2}\)

AB = 35.078 inches

so

\(sin \frac{\alpha }{2} = \frac{OB}{AB}\)

\(sin \frac{\alpha }{2} = \frac{2.05}{35.078}\)

\(\alpha = 7 degree\)