A flywheel having constant angular acceleration requires 4.00 ss to rotate through 164 radrad . Its angular velocity at the end of this time is 106 rad/srad/s . Find the angular velocity at the beginning of the 4.00 ss interval; the angular acceleration of the flywheel. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Rotation of a bicycle wheel.
Answer:
\(\omega '=-13.5rad/s\)
Explanation:
From the question we are told that:
Time \(t=4sec\)
Angular displacement \(\theta= 161 rad\)
Final Angular velocity \(\omega = 100 rad / s\)
Let
Angular acceleration \(\alpha\)
Generally the equation for Initial Angular velocity \(\omega '\) is mathematically given by
\(-\omega '^2=2 \alpha \theta -\omega^2\)
\(\omega '^2= \alpha 328 +11236\)
Also,Initial Angular velocity \(\omega '\) is mathematically given by
\(\omega '=\omega - \alpha t\)
Therefore substitution
\(-\omega '^2=2 \alpha \theta -\omega^2\)
\(\omega '=\omega - \alpha t\)
\((\omega - \alpha t)^2=2 \alpha \theta -\omega\)
\(-16\alpha^2+848\alpha+11236= \alpha 328 -11236\)
\(16\alpha^2-520\alpha=0\)
\(\alpha=29.875rads/s^2\)
Substitution in the 2nd equation for Initial Angular velocity \(\omega '\)
\(\omega '=106-(29.875rads/s^2*4)\)
\(\omega '=-13.5rad/s\)
a bus with a maximum speed of 20m/s takes 21sec to travel 270m from stop to stop. Its acceleration is twice as great as its deceleration. Find: A, the acceleration B, the distance traveled at maximum speed
Answer:
We can use the kinematic equations to solve this problem.
Let a be the acceleration and d be the distance traveled at maximum speed.
First, we can use the equation:
d = vt + (1/2)at^2
where v is the maximum speed, t is the time traveled at maximum speed, and a is the acceleration.
We know that the bus takes 21 seconds to travel 270 meters, so the time traveled at maximum speed is:
21 - 2a = t
We also know that the acceleration is twice as great as the deceleration, so we can write:
a = 2d
Then, we can substitute these expressions into the first equation:
d = (20)(21 - 2a) + (1/2)(2d)(21 - 2a)^2
Simplifying and solving for d, we get:
d = 210 - 5.25a + 0.25a^2
To find the acceleration, we can use the fact that the maximum speed is reached at the midpoint of the trip, so the distance traveled at maximum speed is half the total distance:
d = 1/2(270)
Solving for d, we get:
d = 135
Substituting this value into the equation for d, we get:
135 = 210 - 5.25a + 0.25a^2
Simplifying and solving for a, we get:
a = 8 m/s^2
Finally, we can use the equation:
d = vt
to find the distance traveled at maximum speed:
d = (20)(21 - 2a)
Substituting the value of a, we get:
d ≈ 188.4 m
Therefore, the acceleration of the bus is 8 m/s^2 and the distance traveled at maximum speed is approximately 188.4 meters.
How to travel in the speed of light?
Answer:
Explanation:
1. eectromagnetic Fields. Most of the processes that accelerate particles to relativistic speeds work with electromagnetic fields to the same force that keeps magnets on your fridge!
Magnetic Explosions
Wave-Particle Interaction's
A velocity time graph shows how____ changes over time
Answer: A velocity-time graph shows how velocity changes over time
Explanation:
Answer:velocity
Explanation:
The delivery track is at rest on a horizontal road .It has four wheels and the distance between it's front and rear axle is 2.3 m .Workers have loaded the truck in such a way that it;s center of gravity(cg) is only slightly (0.63) forward of the rear axle.The total mass of the truck and its contents is 8010 kg.Finf the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck.
Answer:
The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is 62271.86 N
Explanation:
To find the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck, we need to consider the static equilibrium condition of the truck.
The weight of the truck and its contents acts downwards through its center of gravity (cg) and the normal force exerted by the ground acts upwards. The normal force is distributed between the front and rear axles of the truck according to the position of the cg.
Let F_R be the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck.
Then, from the static equilibrium condition:
Sum of vertical forces = 0
F_R + (8010 kg)(9.81 m/s^2) - F_F = 0
where F_F is the magnitude of the total vertical force exerted by the ground on the front wheels of the truck.
The distance between the cg and the rear axle is given as 0.63(2.3 m) = 1.449 m.
The distance between the cg and the front axle is therefore (2.3 m - 1.449 m) = 0.851 m.
We can assume that the weight is evenly distributed between the four wheels of the truck. Therefore, the weight supported by each wheel is:
(8010 kg)(9.81 m/s^2)/4 = 19653.45 N
Using moments about the rear axle, we get:
F_F(0.851 m) - F_R(1.449 m) = 0
Solving these two equations simultaneously, we get:
F_R = 62271.86 N
Therefore, the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is 62271.86 N.
The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is approximately 62,203 N.
What is static equilibrium?Static equilibrium refers to the state of an object at rest when the net force acting on it is zero. In other words, when an object is in static equilibrium, it is not accelerating in any direction and all forces acting on it are balanced.
The principle of static equilibrium states that the sum of all forces acting on an object in static equilibrium is zero, and the sum of all torques (rotational forces) acting on the object is also zero. This principle can be applied to solve problems involving the forces and torques acting on objects at rest.
Static equilibrium is important in many areas of physics and engineering, including structural analysis, civil engineering, and mechanical engineering. Understanding static equilibrium is essential for designing structures and machines that can support loads without collapsing or breaking, and for analyzing the stability of systems in various applications.
Here in the Question,
To find the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck, we need to analyze the forces acting on the truck and apply the principle of static equilibrium, which states that the sum of all forces acting on an object in static equilibrium is zero.
The forces acting on the truck are the weight of the truck and its contents and the reaction forces from the ground acting on each of the four wheels. The weight of the truck and its contents can be represented as a single force acting vertically downwards at the center of gravity (cg) of the truck.
Since the truck is at rest on a horizontal road, the reaction forces from the ground acting on the wheels must balance the weight of the truck and its contents in both the horizontal and vertical directions. The horizontal components of the reaction forces cancel each other out, since the truck is at rest and not moving in the horizontal direction.
To find the vertical forces, we can first find the weight of the truck and its contents:
w = m*g
where w is weight, m is mass, and g is the acceleration due to gravity (9.81 m/s^2).
Substituting the given values, we get:
w = 8010 kg * 9.81 m/s^2 = 78,419.1 N
Next, we can find the position of the center of gravity (cg) relative to the front and rear axles of the truck:
d = L * (m1 - m2) / m
where d is the distance from the cg to the rear axle, L is the distance between the front and rear axles (2.3 m), m1 is the mass of the truck and contents behind the cg, m2 is the mass of the truck and contents in front of the cg, and m is the total mass of the truck and contents.
Substituting the given values, we get:
d = 2.3 m * (8010 kg * 0.63 - 8010 kg * 0.37) / 8010 kg = 0.743 m
Now, we can find the magnitudes of the vertical forces acting on the rear and front wheels of the truck using the principle of static equilibrium. Since the truck is not moving vertically, the sum of the vertical forces acting on it must be zero. Therefore:
Frear + Ffront = w
where Frear is the vertical force exerted by the ground on the rear wheels, Ffront is the vertical force exerted by the ground on the front wheels, and w is the weight of the truck and its contents.
The rear wheels support the weight of the truck and its contents, as well as a portion of the weight shifted forward of the rear axle due to the position of the cg. The front wheels support only a portion of the weight shifted backward of the front axle. To find the magnitudes of the vertical forces, we can use the following equations:
Frear = (m1/m)*w
Ffront = (m2/m)*w
where m1 is the mass of the truck and contents behind the cg, m2 is the mass of the truck and contents in front of the cg, and m is the total mass of the truck and contents.
Substituting the given values and using the value of d found earlier, we get:
Frear = (8010 kg * 0.63 / 8010 kg)*78,419.1 N = 62,202.7 N
Ffront = (8010 kg * 0.37 / 8010 kg)*78,419.1 N = 36,216.4 N
The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is:
Frear = 62,202.7 N ≈ 62,203 N
Therefore, the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is approximately 62,203 N.
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How much heat is absorbed by 60 g of copper (c=385 J/kg K) when it is heated
from 20°C to 80°C?
Answer:
Q = 1386 J
Explanation:
Mass, m = 60 g = 0.06 kg
Specific heat of copper, c=385 J/kg K
It is heated from 20°C to 80°C.
We need to find the heat absorbed. It can be given by the formula as follows :
\(Q=mc\Delta T\\\\Q=0.06\times 385 \times (80-20)\\\\Q=1386\ J\)
So, 1386 J of heat is absorbed.
9. Which of these tissues hold bones together at movable joints? O ligaments O cartilage O tendons O disks
Answer:
The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.
Explanation:
The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.
Answer:
The answer is ligaments!
Explanation:
Hope this helps!! :)
Translate the following sentence into an equation. "The distance traveled is the speed multiplied by the time." a) d = v * t a) d = v * t b) Δx = v * Δt c) v = d/t d) d=Δx*t
The correct answer is A) d = v * t
Explanation:
When writing an equation the goal is to represent the equality between different mathematical expressions or elements. Due to this, in an equation the symbol = is always used. Additionally, to translate a sentence into an equation, the variables should be represented using numbers or letters.
For example, in the sentence "The distance traveled is the speed multiplied by the time" there are three variables mentioned: distance, speed, and time. Also, these can be represented through the letters d (distance), v (speed or velocity), and t (time). Besides this, the sentence explains speed should be multiplied by time, which means it should be written as v × t or v * t and this is equivalent (=) to distance or t. According to this, the final equation would be d = v * t.
A planet of mass m = 4.25 x 1024 kg orbits a star of mass M = 6.75 x 1029 kg in a circular path. The radius of the orbits R = 8.85 x 107 km. What is the orbital period Tplanet of the planet in Earth days?
285.3 days
Explanation:
The centripetal force \(F_c\) experienced by the planet is the same as the gravitational force \(F_G\) so we can write
\(F_c = F_G\)
or
\(m\dfrac{v^2}{R} = G\dfrac{mM}{R^2}\)
where M is the mass of the star and R is the orbital radius around the star. We know that
\(v = \dfrac{C}{T} = \dfrac{2\pi R}{T}\)
where C is the orbital circumference and T is orbital period. We can then write
\(\dfrac{4\pi^2R}{T^2} = G\dfrac{M}{R^2}\)
Isolating \(T^2\), we get
\(T^2 = \dfrac{4\pi^2R^3}{GM}\)
Taking the square root of the expression above, we get
\(T = 2\pi \sqrt{\dfrac{R^3}{GM}}\)
which turns out to be \(T = 2.47×10^7\:\text{s}\). We can convert this into earth days as
\(T = 2.47×10^7\:\text{s}×\dfrac{1\:\text{hr}}{3600\:\text{s}}×\dfrac{1\:\text{day}}{24\:\text{hr}}\)
\(\:\:\:\:\:= 285.3\:\text{days}\)
what is the movement of energy by waves
Answer; thermal energy
Explanation:
'Wave' is a common term for a number of different ways in which energy is transferred: In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels.
needing help with this please
Answer:
So A we cant sadly do because we cant draw. B is going to be kinetic. Thats because static friction means it stays in one place, for kinetic it means moving. So it will be 0.05 as the coefficient of the friction. Sadly, I cannot calculate C. You will have to use trigonemetry but I cannot fit that big an explanation.
Answer to A: the free body diagram would be the ski things inclined with gravity, friction, and air resistance. I except you know which directions
Answer to B: Kinetic friction is the answer.
Answer to C: Find on own, I cannot write super big explanations - use trigonometry.
William Gilbert used a terella in an attempt to explain _____.
why like poles of a magnet repel
why unlike poles of a magnet attract
why compasses point toward the north and south poles of the earth
the properties of lodestone
Answer:
why compasses point towards the north and south poles of the earth.
Explanation:
hope it helps!!
Describe how excavations are done.
Answer:
It includes earthwork, trenching, wall shafts, tunneling and underground
Explanation:
Calculate the displacement and then velocity for an object 12.77s after it is dropped.
Answer:
799 m
125 m/s
Explanation:
Take down to be positive. Given:
v₀ = 0 m/s
a = 9.8 m/s²
t = 12.77 s
Find: Δy and v
Δy = v₀ t + ½ at²
Δy = (0 m/s) (12.77 s) + ½ (9.8 m/s²) (12.77 s)²
Δy ≈ 799 m
v = at + v₀
v = (9.8 m/s²) (12.77 s) + 0 m/s
v ≈ 125 m/s
can anyone write for me all the equation of linear motion
All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.
Equations of MotionIn terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.
s = ut + (1/2)at^2v = u + atv_avg = (u + v) / 2s = v_avg * ts = (u + v) / 2 * tv^2 = u^2 + 2asIn conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.
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If the length of the standing wave below is 2 meters, what is the wavelength of the standing
wave? *
Answer:
fffffgggggggggggggghhh
The mass of a car is 625kg. Calculate the weight of the gravitational field strength is 10 N/kg.
Ans: 62.5
Explanation: \(F{net}\) = m x a
1N = 1kg x 1m/ \(s{2}\)
the greatest amount o. lolololoms?
Answer:
If you are asking for the answer with the highest molar mass, then the answer is B.
B. Fe₂O₃
Một khối khí hidro bị nén đến thể tích bằng 1/2 lúc đầu khi nhiệt độ không đổi. Nếu vận tốc trung bình của phân tử hidro lúc đầu là V thì vận tốc trung bình sau khi nén là bao nhiêu ?
answer: what language is this???
A spring stretches 6.0 cm when a 0.25 kg block is hung from it.
If a 0.80 kg block replaces the 0.25 kg block, how far does the spring stretch?
When a 0.80 Kg block is used in place of a 0.25 Kg block, the length of the string is increased by 19.6 cm.
How does spring stretch become calculated?The formula used by the Hooke's Law Calculator is Fs = -kx, where F is the spring's restoring force, k is the spring constant, and x is the displacement, or the length by which the spring is being stretched
We'll start by determining the spring's string constant. Specifics below:
Extension (e) = 6.0 cm
Mass (m) = 0.25 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) = mg = 0.25 × 9.8 = 2.45 N
Spring constant (K) =?
F = Ke
2.45 = K × 6
Divide both sides by 6
K = 2.45 / 6
K = 0.40 N/cm
The extension will be calculated after the 0.25 kg block is replaced with the 0.80 kg block. As demonstrated below:
Mass (m) = 0.80 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) = mg = 0.80 × 9.8 = 7.84 N
Spring constant (K) = 0.40 N/cm
Extension (e) = ?
F = Ke
7.84 = 0.40 × e
Divide both sides by 0.40
e = 7.84 / 0.40
e = 19.6 cm
We may thus deduce from the preceding computation that the spring will lengthen by 19.6 cm.
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A motorcycle moving at a constant velcoity suddenly accelerates at a rate of 4.0 m/s/s to a speed of 35 m/s in 5.0 s. What was the initial speed of the motorcycle?
Answer:
15 m/s
Explanation:
v = u+ at
35 = u + 20
35-20 = u
u= 15 m/s
in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting
It is not recommended to fire a gun straight up into the air.
When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.
Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.
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Vector A has a magnitude of 5 meters and points west vector B has a magnitude of 5 meters pointing east what is the direction and magnitude
The direction and magnitude of the net vector is:
Direction: None Magnitude: 0 meters.How to find the resultant and magnitude of the resultant vectorWhen vector A with magnitude of 5 meters pointing west and
vector B with magnitude of 5 meters pointing east are added,
they will result in a net vector with a magnitude of the difference between the magnitudes of the vectors and a direction equal to the direction of the vector with the largest magnitude.
Since both vectors have the same magnitude (5 meters), the net vector will have a magnitude of 0 meters.
This means that the vectors completely cancel each other out and there is no net vector remaining.
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In the film, describe at least one scientific miscalculation that Homer and his friends made and what the result of that miscalculation was for their science experiment.
Relate the following key terms from chapter 8 and 9 to the scientific method Homer and his friends engaged in to successfully launch a rocket.
-Force
-Work
-Acceleration
-Velocity
Explain the relationship between Newton's Third law of action-reaction forces and Homers rocket experiment.
To cause a change in position, a force is required. No net force equals no velocity change. Speed and direction are both specified by velocity.
What exactly is meant by velocity?The velocity of a person or object determines its direction of motion. A scalar is velocity's most basic representation. Velocity is essentially a vector quantity. The relocation change rate is the issue.
How can you calculate velocity?The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t). Velocity is the pace and direction of an object's movement, whereas speed is indeed the time rate that an object is travelling along a path.
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Momentum conservation often assumes that the mass of an object remains
constant throughout a process or event. However, a change in momentum can
also occur when mass changes. Consider an automobile with a full tank of
gasoline traveling at a velocity of 88.0 km/h to the east. The mass of the car when
the fuel tank is full is 1292 kg. Suppose that the car travels along a highway that
extends eastward for 600 km. By the time the car has traveled this distance, its
mass is 1255 kg. What is the car's velocity at the end of the journey?
The law of conservation of momentum states that in an isolated system, the total momentum of two or more bodies acting on each other remains constant unless an external force acts on them. Therefore, it cannot create or destroy momentum.
What is the speed of the car at the end of the trip?Velocity is the percentage of time an object moves along a path, and Velocity is the speed and direction of an object's movement.If the car is moving at a constant speed, the car is also moving at a constant speed. The confusion between the two rates, which are actually measured in the same units, is:Velocity is a vector quantity, but velocity is a scalar quantity.This is just Newton's first law. An object at rest will remain stationary and an object in motion will continue to move in the same direction at a constant speed unless an unbalanced force acts on it. The car tends to keep moving at a constant speed and direction because the two forces are canceling (i.e. balanced).To know more about speed visit:
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The electron dot diagram shows the arrangement of dots without identifying the element.
? with 2 dots above and 1 dot each right, below, left.
Which element’s symbol could replace the question mark in the diagram?
boron (B)
neon (Ne)
rubidium (Rb)
arsenic (As)
Answer:
Arsenic (As)
Explanation:
Arsenic is the only answer choice that has five valence electrons like the electron dot structure shows.
Answer:
Arsenic (As)
Explanation:
What force pulls all objects with mass toward
one another?
In a reading assignment, the main headings and key concepts are useful for which of
the following?
0000
defining vocabulary words
finding the general location of information in reading assignments
giving exact answers to exam questions
none of the above
The main headings and key concepts are useful for finding the general location of information in reading assignments. They provide a quick overview of the content and organization of the text, which can help readers to locate specific information more easily. However, they may not always be sufficient for defining vocabulary words or giving exact answers to exam questions, as these tasks often require more detailed and specific information from the text.
2. The muscles on the right side of your body are controlled by what part of your brain? the right cortex the right hemisphere the left cortex the left hemisphere
Answer:
Motor cortex
Both hemispheres have a motor cortex, with each side controlling muscles on the opposite side of the body (i.e, the left hemisphere controls muscles on the right side of the body).
Explanation:
Which of the following are species of wild goats? (Select all that apply.)
Himalayan markhor
Caucasian moschus
Siberian ibex
Ethiopian marmot
please choose as many as you can
Answer:
Siberian ibex and Himalayan markhor
Siberian Ibex and Himalaya markor are example of species of wild goats.
What is species of wild goat?The wild goat or common ibex refers wild goat species that lives in mountainous areas, forests, shrublands around Turkey and the Caucasus in the west to Turkmenistan, Afghanistan and Pakistan in the east.
They can be found in mountainous area around Africa, Asia, North America.
There are 36 Subfamily of wild goats and they have surefoot which help them to live in mountainous areas.
Therefore, Siberian Ibex and Himalaya markor are example of species of wild goats.
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