Explica con tus palabras que significa que un cuerpo enga aceleracion de 5m/S

Explanation:

(i) The horizontal component of the tension in the right wire points right, and the horizontal component of the tension in the left wire points left.  Since these components are equal and opposite, the resultant horizontal force is 0.

∑Fₓ = 15 N cos 20° − 15 N cos 20°

∑Fₓ = 0 N

(ii) ∑Fᵧ = 15 N sin 20° + 15 N sin 20°

∑Fᵧ = 10.26 N

i) The resultant horizontal component of the tension forces is 0N

ii) The resultant vertical component of the tension forces is 10.26N

iii) The sum of force along the horizontal is zero because the force has the same magnitude and moving in the opposite direction.

i) From the given figure, the horizontal component of the force is given as;

\(F_x = + 15 cos 20^0 + (-15cos20^0)\\F_x = + 15 cos 20^0 -15cos20^0\\F_x =0\)

The sum of force along the horizontal is zero because the force has the same magnitude and moving in the opposite direction.

ii) The vertical component of the force is expressed as

\(F_y = + 15 sin 20^0 + 15sin20^0)\\F_y = 2(15sin20^0)\\F_y=2(5.13)\\F_y=10.26N\)

Hence the resultant vertical component of the tension forces is 10.26N

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Answer:750

Explanation:

Answer:

The doctors could see if her cells are getting the molecules they need from food and air

Explanation:

The doctors could see if her cells are getting the molecules they need from food and air. Doing so allows the doctors a general overview of how well her body's biological systems are performing since the basic necessities of the human system are food and oxygen. Therefore if the body is receiving both food and oxygen properly and distributing it properly and efficiently as well without any problems then the most likely outcome is that she is healthy enough to perform her tasks in the submarine under more pressure.

Answer:

The doctors could see if her cells are getting the molecules they need from food and air

Explanation:

for each of them you need to type how they make you feel when you like need to make decision

Explanation:

Answer:

We know that potential energy of a body;

= mass(m)× gravitational acceleration(g) × height(h)

Lets find out the mass of the body

P.E. = mgh

=> 6500J = mass × 9.8m/s^2 × 12m

=>6500J = mass × ( 9.8 × 12 ) × ( m/s^2 × m)

=> 6500 Nm = m × 117.6 × m^2 / s^2

=> 6500/117.6 Ns^2/m = mass [°.° Ns^2/m = kg]

=> 55.272 Kg = mass

Therefore the mass of the body = 55.272 kg ~ 60 kg (Ans)

Hope it helps you

Sabiendo la tasa de energía electromagnética que el sol radi, la distancia a la cual la intensidad disminuye a 1000 W/m² es de 6.96×10¹⁰ m metros o 69.6 millones de kilómetros.

La intensidad de la energía electromagnética emitida por el Sol disminuye a medida que se aleja del Sol. Esta disminución está dada por la ley del cuadrado inverso, que establece que la intensidad es inversamente proporcional al cuadrado de la distancia desde la fuente.

La intensidad de la energía electromagnética se puede calcular mediante la siguiente fórmula:
I = P / 4πr²

Donde I es la intensidad, P es la potencia del Sol, y r es la distancia desde el Sol.

Si queremos encontrar la distancia a la cual la intensidad disminuye a 1000 W/m², podemos despejar r de la fórmula y sustituir los valores conocidos:
1000 = 3.85×10²⁶ / 4πr²
r² = 3.85×10²⁶ / (1000 × 4π)
r = √(3.85×10²⁶ / (1000 × 4π))
r = 6.96×10¹⁰ m

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Answer:

(You find the epicenter of an area earthquake by using triangulation)

But alright moving towards the graph, in the top row will be 'a' for the seismic station, for the P-wave arrival time (for the top row) it'll be 09:20:42 AM, for the s-wave arrival time (of the top row still) will be 09:21:09 AM, for the S-P interval (in sec) will be 27, and for the Distance to epicenter (km) will be 283 :)

now moving onto the second row, the seismic station is now 'b' , the p-wave arrival time is 09:21:27 AM, the s-wave arrival time will be 09:22:27 AM, the S-P interval (in seconds) is 60, the distance to epicenter is 632,

now moving onto the third row, the seismic station is 'c', the p-wave arrival time is 09:21:49 AM, the s-wave arrival time is 09:23:05 AM, the S-P interval is 76, and the distance to epicenter is 806

that's all for the graph :)

okay so now, for the second part to your question "according to the data table, which type of wave reached station A first, the P waves or the S waves? would you expect this fact to hold data from other seismic" okay so looking at what I've already said earlier about the tables it should be pretty easy to figure out but I'm sure you just want an answer so you can finish your schoolwork so i wont go on to long about it lol, the answer would be the p-waves got there first, and yes it can hold this for data on other seismic station, it also asked you to explain your answer so here's that: in 'b' station and 'c' station the p-wave always reached the stations before the s-wave.

Explanation:

I dont know if you do online school or go to virtual school house, but i do  and my teacher there posted a video in the place where we turn in our work showing us the different tables, anyways i hope this helped :) !!

Answer:

110 km/h

Explanation:

"Headwind" means, that the velocity of the wind is opposite to the velocity of the airplane. Thus, in order to find the resultant speed, one should subtruct those velocities

If you pull yourself to the center of the merry-go-round,  the rotation of the merry go round will decrease.

This is the radial acceleration experienced by a person moving in a circular path as the merry-go-round rotates about its mean position.

a = v²/r

where;

From the formula given above, as the radius of the merry go round increases, the centripetal acceleration of the merry go round decreases.

v = ωr

where;

Thus, when the radius of the circular path decreases, the speed of the merry go round will decrease as well.

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Answer:

7500

Explanation:

multiply the mass / volume value by 1000

This statement is incorrect. The frequency range mentioned for infrared radiation and radio wave radiation is not accurate. Infrared radiation generally has frequencies ranging from 3.0×10^11 Hz (300 GHz) to 3.0×10^14 Hz (300 THz).

Infrared radiation is associated with thermal energy and is commonly used in applications such as heat sensing, communication, and remote control systems. Radio waves, on the other hand, have frequencies ranging from 3.0×10^5 Hz (300 kHz) to 3.0×10^7 Hz (30 MHz) for traditional radio broadcasting. However, radio waves can extend to much higher frequencies in other applications, such as Wi-Fi and satellite communication. It's important to note that the frequency ranges of different types of electromagnetic radiation can overlap, and they can be used for various purposes depending on the specific application.

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The answer is no. Hope this helps

Explanation:

Efficiency is a way of describing the amount of useful ​output​ a process or machine can generate as a percentage of the ​input​ required to make it go. In other words, it compares how much energy is used to do work versus how much is lost or wasted to the environment. The more efficient the machine, the less energy wasted.

For example, if a heat engine is able to turn 75 percent of the fuel it receives into motion, while 25 percent is lost as heat in the process, it would be 75 percent efficient. Out of the original 100 percent of the fuel, 75 percent was output as useful work.  

the equation:

energy efficiency =useful output energy/total input energy

Answer:

the answer is D

Explanation:

got it right on time for learning

Answer:

D is correct

Explanation:

Answer:

See below

Explanation:

CALCULATED volume from their measurements:

5.08 X 5.09 X 5.10 = 131. 9   cm^3

( I think you my have the "The actual volume of the block was 15.3 cm3" incorrectly posted)

(131.9 - 15.3) / 15.3     x 100 % =  762 %  error !!!!!

The part of the scapula that articulates with the clavicle is called the acromion process. The acromion process is a bony projection located at the lateral end of the scapula, and it forms a joint called the acromioclavicular joint (AC joint) with the medial end of the clavicle. This joint allows for movement and stability between the scapula and the clavicle, contributing to the overall mobility of the shoulder.

In addition to the acromion process, there is another part of the scapula that articulates with the clavicle. It is called the lateral end of the clavicle. The lateral end of the clavicle forms a joint called the sternoclavicular joint with the medial end of the clavicle. This joint connects the clavicle to the sternum and allows for movement and stability of the shoulder girdle.

To summarize, the scapula articulates with the clavicle at two different joints: the acromioclavicular joint (AC joint) formed by the acromion process of the scapula and the medial end of the clavicle, and the sternoclavicular joint formed by the lateral end of the clavicle and the sternum. These joints play a crucial role in shoulder movement and stability.

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Answer:

0.0001158443168226212 Celcius (significant digits? who cares.....) or about 0.00021 Fahrenheit

Explanation:

500g=0.5kg

PE=mgh

PE=(0.5)*(9.81)*(1.5)

PE=7.36J

3% of 7.36 is 0.22J is converted to heat

From there, it's tricky.

I just used a joules to celcius converter to get 0.0001158443168226212 degrees celcius or 0.00021 degrees fahrenheit rise in temp.

Answer:

1.56 m

Explanation:

First, we need to find the current in the wire, so we will use the following equation:

Where V is the voltage, R is the resistance and I is the current. Replacing the values and solving for I, we get:

So, the current is 0.17 A.

Now, the magnetic field generated by a wire with current I at a distance r is equal to:

Where μ is 4π x 10^(-7). So, replacing the values and solving for r, we get:

Therefore, the distance is 1.56 m

Answer: what is it in

Explanation:

The fastest time trial for the first quarter checkpoint is 2.02 s.

The slowest time trial for the first quarter checkpoint is 2.7 s.

The range of the times measured for the checkpoint is 0.68 s.

The given parameters;

The fastest time trial for the first quarter checkpoint is the least measured time value.

fastest time trial = least time measured

fastest time trial =  2.02 s

The slowest time trial for the first quarter checkpoint is the highest measured time value.

slowest time trial = 2.7 s

The range of the times measured for the checkpoint is difference between the fastest time and slowest time.

Range = fastest time - slowest time

Range = 2.7 - 2.02

Range = 0.68 s

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Answer:

2.02, 2.15, 0.13

Explanation:

A 2-column table with 5 rows. The first column has entries empty, time of trial number 1 (seconds), time of trial number 2 (seconds), time of trial number 3 (seconds), average time (seconds). The second column labeled one quarter checkpoint has entries 2.15, 2.05, 2.02, 2.07.

Use the table to answer the questions.

What is the fastest time trial for the first quarter checkpoint?

2.02

seconds

What is the slowest time trial for the first quarter checkpoint?

2.15 seconds

What is the range of times measured for this checkpoint?

0.13 seconds

Answer:

Given: V = 220V, Pmin = 360W, Pmax = 840W

For minimum heating case:

We know that

Pmin = VI

360 = 220 X I

I = 1.63 amp

R = V/I

R = 220/1.63

R = 134.96ohms

For maximum heating case:

We know that

Pmax = VI

840 = 220 X I

I = 3.81 amp

R = V/I

R = 220/3.81

R = 57.74 ohms

Water is not wet itself or it does not make things wet. The water makes bond with the other materials through adhesive forces.

Wetness is a description of the experience of water, it is a quality of the liquid water. Liquid water is not itself wet, however it cannot even make things actually wet. Wetness is the ability of a liquid to adhere to the surface of a solid material, so when we say that something is wet, we mean that the liquid material is sticking to the surface of a material.

An adhesion is present between two things and something that the water molecules cannot do to itself. Water has to be wetted by something else or it makes no sense at all. Water can be wetted easily by oil or another foreign liquid, however it cannot wet itself.

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Answer:

2NH3 --> N2 + 3H2 decomposition

Answer:

The maximum potential difference or current can be increased by:

1. increasing the rate of rotation.

2. increasing the strength of the magnetic field.

3. increasing the number of turns on the coil.

Answer:

It depends. Remember that power is voltage x current. So, do you have enough voltage? You can buy modules that increase and decrease voltage. That is one possibility. Please check all safety guidelines of the generator before doing this. modifying the voltage to a generator without making sure it can take more voltage can be counterproductive

The angle in radians between two vectors can be found using the dot product formula:

\(θ = cos^-1 ((a • b) / (||a|| ||b||))\)

Where:
- θ is the angle between the vectors in radians
- a and b are the two vectors
- a • b is the dot product of the vectors
- ||a|| and ||b|| are the magnitudes of the vectors

To find the angle between the vectors, first calculate the dot product of the vectors by multiplying the corresponding components of the vectors and adding the results. Then, find the magnitudes of the vectors by taking the square root of the sum of the squares of the components. Finally, plug the dot product and magnitudes into the formula and use the inverse cosine function to find the angle in radians.

For example, if the vectors are a = (1, 2, 3) and b = (4, 5, 6), the angle between them would be:

\(θ = cos^-1 (((1)(4) + (2)(5) + (3)(6)) / (sqrt((1)^2 + (2)^2 + (3)^2) * sqrt((4)^2 + (5)^2 + (6)^2)))\)

\(θ = cos^-1 ((4 + 10 + 18) / (sqrt(14) * sqrt(77)))θ = cos^-1 (32 / (sqrt(14) * sqrt(77)))θ = 0.225 radians\)
So the angle between the vectors is 0.225 radians.

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The force on the current-carrying loop is 0 N, and the torque experienced by the loop is 0.009 Nm.

To find the force and torque on the square-shaped 6A current-carrying loop, we first need to understand that the force on a current loop in a magnetic field is given by F = qvB, where q is the charge, v is the velocity, and B is the magnetic field strength. In this case, the force will be 0 N, because the magnetic field is parallel to the loop and the angle between them is 0°.

To calculate the torque τ, we use the formula τ = μBsinθ, where μ is the magnetic moment, B is the magnetic field strength, and θ is the angle between them. The magnetic moment μ is calculated as μ = IA, where I is the current and A is the area of the loop. Plugging in the values, we have μ = 6A × 0.0025m^2 = 0.015 Am^2. Since the magnetic field is tilted at 37°, we have θ = 37°.

Now, τ = (0.015 Am^2)(2 × 10^-2 T)sin(37°) ≈ 0.009 Nm. Thus, the torque experienced by the loop is 0.009 Nm.

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Answer:

It is a song called Come out and Play. It is released on 1994 in a Album called Smash. It comes under Punk-Rock.

I hope i answered your Question.

Answer:

Explanation:

Adding to the other answer, this song is about violence in streets and schools among young people involved in gangs; how they have little hope for their future. Band member Dexter got idea to make the song while he was in college.

Answer:

1/2 watt hr    

Explanation:

watts = V I   =   6 * 5 = 30 watts   for 1/60 hr

30 watts * 1/60 hr = 1/2  watt hr

Given data:

* The mass of the first bowling ball is 10.1 kg.

* The mass of the second bowling ball is 8.4 kg.

* The distance between the bowling balls is 1.25 m.

Solution:

The gravitational force between the bowling balls is,

where G is the graviatational constant, m_1 is the mass of first bowling ball, m_2 is the mass of second bowling ball, and r is the distance between the bowling balls,

Thus, the gravitational force acting between the bowling balls is,