express the following sum with the correct number of significant figures 1.90m+134.5cm+3.62×10^5 meuo m

The specific heat capacity of a piece of wood if 1500.0 g of the wood absorbs 67,500 joules of heat, and it’s temperature changes from 32C to 57C is 1.8 J/gºC.

The given data to find specific heat capacity is,

Mass (M) = 1500 g

Heat (Q) absorbed = 67500 J

Initial temperature (T₁) = 32 °C

Final temperature (T₂) = 57 °C

Specific heat capacity (C) =?

The specific heat capacity is described as the quantity of warmth (J) absorbed per unit mass (kg) of the material while its temperature will increase 1 okay (or 1 °C), and its gadgets are J/(kg ok) or J/(kg °C).

At first, we shall determine the change in temperature of the wood. This can be obtained as follow:

Initial temperature (T₁) = 32 °C

Final temperature (T₂) = 57 °C

Change in temperature (ΔT) =.?

ΔT = T₂ – T₁

ΔT = 57 – 32

ΔT = 25 °C

Finally, we shall determine the heat capacity of the wood. This can be obtained as follow:

Mass (M) = 1500 g

Heat (Q) absorbed = 67500 J

Change in temperature (ΔT) = 25 °C

Specific heat capacity (C) =?

Q = MCΔT

67500 = 1500 × C × 25

67500 = 37500 × C

Divide both side by 37500

C = 67500 / 37500

C = 1.8 J/gºC

Thus, the heat capacity of the wood is 1.8 J/gºC.

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The direction cosines of a→ - b→ are:

l_x = 1 / √46

l_y = 3 / √46

l_z = -6 / √46

The direction cosines of a vector can be found by dividing the components of the vector by its magnitude.

Here's how you can find the direction cosines of the vector a→ - b→:

Step 1: Subtract the vectors a→ and b→ to get a new vector, let's call it c→:

c→ = a→ - b→

In this case, a→ = 4i^ + 7j^ - 5k^ and b→ = 3i^ + 4j^ + k^, so we can subtract them component-wise:

c_x = 4 - 3 = 1

c_y = 7 - 4 = 3

c_z = -5 - 1 = -6

So, c→ = 1i^ + 3j^ - 6k^.

Step 2: Find the magnitude of vector c→ using the formula:

|c→| = √(c_x^2 + c_y^2 + c_z^2)

Substituting the values we found earlier:

|c→| = √(1^2 + 3^2 + (-6)^2)

|c→| = √(1 + 9 + 36)

|c→| = √46

Step 3: Divide the components of vector c→ by its magnitude to find the direction cosines:

l_x = c_x / |c→|

l_y = c_y / |c→|

l_z = c_z / |c→|

Substituting the values we found earlier:

l_x = 1 / √46

l_y = 3 / √46

l_z = -6 / √46

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the direction cosines of the vector a→ - b→ are (0.155, 0.466, -0.932).

we first calculate the vector a→ - b→:

a→ - b→ = (4i^ + 7j^ - 5k^) - (3i^ + 4j^ + k^)

= (4-3)i^ + (7-4)j^ + (-5-1)k^

= i^ + 3j^ - 6k^

Next, we find the magnitude of the vector a→ - b→:

|a→ - b→| = √(1^2 + 3^2 + (-6)^2) = √46

We then find  the direction cosines of the vector a→ - b→:

cos α = (1/√46) = 0.155

cos β = (3/√46) = 0.466

cos γ = (-6/√46) = -0.932

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The meteoroid that is most likely to reach the Earth's surface is the one with the highest mass-to-surface area ratio which is number 2. This is because as a meteoroid enters the Earth's atmosphere, it encounters a great deal of resistance, which generates heat due to friction.

Meteoroids are small rocky or metallic objects that are present in the solar system. They range in size from tiny particles to large boulders, and they can originate from comets, asteroids, or other celestial bodies. When a meteoroid enters the Earth's atmosphere, it becomes a meteor or a shooting star, and if it survives the descent and reaches the Earth's surface, it is then called a meteorite.

The meteoroid that is most likely to reach the Earth's surface is the one with the highest mass-to-surface area ratio. This is because as a meteoroid enters the Earth's atmosphere, it encounters a great deal of resistance, which generates heat due to friction. This heat is transferred to the meteoroid through conduction, and it can cause the meteoroid to vaporize or break apart. However, a larger meteoroid has more mass to dissipate this heat over, so it is less likely to be completely destroyed.

Additionally, a larger meteoroid has a smaller surface area to mass ratio, which means that there is less surface area to be heated and potentially destroyed by the heat generated during entry into the Earth's atmosphere. Therefore, a larger meteoroid with a higher mass-to-surface area ratio is more likely to survive and reach the Earth's surface.

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Meteoroid 2, with an initial mass of 3.24 kg, is most likely to reach the Earth's surface.

This is because the surface temperature of the meteoroid in space before entering the atmosphere is relatively high at 92°C, which means it has a greater amount of heat energy than the other meteoroids. When meteoroids enter the Earth's atmosphere, they encounter resistance from the air, which causes them to slow down and heat up due to friction.

The surface temperature of Meteoroid 2 at 150 km above the Earth's surface is 1727°C, which is higher than the other meteoroids. This suggests that Meteoroid 2 has a greater ability to resist the heat transfer from the high temperatures it reaches during entry into the Earth's atmosphere.

According to the table, the initial mass of Meteoroid 2 is the largest, and it also has the highest surface temperature in space. These factors contribute to the meteoroid's ability to resist heat transfer and increase the likelihood of it reaching the Earth's surface.

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Explanation:

speak a English I don't know you language

i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

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Answer:

The most common oxidation numbers for a given element

Explanation:

The voltage sensitivity of  a galvanometer is given by :

\(\dfrac{NBA}{RK}\)

Where

N=Number of turns

A=Area of coil

B=Magnetic field produced in coil

K=Torsion constant of galvanometer

R=Resistance of galvanometer

The current sensitivity of  a galvanometer is given by :

\(\dfrac{NBA}{K}\)

Hence, this is the required solution.

Answer:

B. . by consuming plants or other animals

The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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The velocity of the bucket after falling a distance of 12 ft is 7.54 m/s.

To determine the velocity of the bucket after it has fallen a distance of 12 ft, we need to use the equation of motion for an object falling under the influence of gravity:

v = √(2gh)

where v is the velocity of the object, g is the acceleration due to gravity (9.8 m/s²), h is the height the object has fallen, and h is the distance the object has fallen.

In this case, h = 12 ft = 3.66 m, so the velocity of the bucket after falling a distance of 12 ft is:

v = √(2 × 9.8 m/s² × 3.66 m) = 7.54 m/s

Note that this is the velocity of the bucket relative to the ground, and does not take into account any effects of the windlass or the spokes.

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Answer

1) AlH3= trigonal planar

2) CH2F2= tetrahedral

3) PH3= trigonal pyramidal

4) O3= bent

Explanation:

I took the test

Answer:

hdhshsisjsbrtheisebvrtctvsjusyevevrvrg eggs haushehegehs

Answer: a

Explanation:

Answer:

F₁ = 4 F₀

Explanation:

The force applied on the string by the ball attached to it, while in circular motion will be equal to the centripetal force. Therefore, at time t₀, the force on ball F₀ is given as:

F₀ = mv₀²/r   --------------- equation (1)

where,

F₀ = Force on string at t₀

m = mass of ball

v₀ = speed of ball at t₀

r = radius of circular path

Now, at time t₁:

v₁ = 2v₀

F₁ = mv₁²/r

F₁ = m(2v₀)²/r

F₁ = 4 mv₀²/r

using equation (1):

F₁ = 4 F₀

When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.

The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.

Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:

Mass of air = Mass of filled container - Mass of empty container

= 0.428 kg - 0.419 kg

= 0.009 kg

Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:

Volume of air = Volume of perplex box * Number of times air inside

= 1000 cm³ * 7.2

= 7200 cm³

Convert the volume of air to cubic meters (m³) by dividing by 1000000:

Volume of air = 7200 cm³ / 1000000

= 0.0072 m³

Calculate the density of air using the formula:

Density = Mass / Volume

Density = 0.009 kg / 0.0072 m³

≈ 1.25 kg/m³

Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.

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The wavelength of the light if a monochromatic light from a distant source is incident on a slit 0.750 mm wide. On a screen 2.00m away, the distance from the central maximum of the diffraction pattern to the first minimum is measured to be 1.35mm is 506.25 nm

When a wave is bent by an obstruction whose dimensions are close to the wavelength, diffraction is noticed. We can disregard the effects of extremes because the Fraunhofer diffraction is the simplest scenario and the impediment is a long, narrow slit.

This is a simple situation where the Fraunhofer single slit diffraction equation can be applied:

y = mλ D

        α

where,

y = displacement from the centerline for minimum intensity = 1.35 mm

m =  order number = 1

λ  =  light wave length

α =  witdh of the slit = 0.750 mm

D = distance between the screen and the slit = 2m

so  

λ = yα

     mD

λ = (1.35 x 10⁻³)( 0.750 x 10⁻³) = 5.0625 x 10⁻⁷m = 506.25 nm

                     1x2

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Explanation:

arn core concepts.

See Answer

1) For a P wave with velocity of 8 km/s (typical upper mantle speed) in a Poisson solid,compute the wavelength for waves with periods of:

a) 15 sec

b) 1 sec

c) 0.1 sec (100 Hz)

2) Repeat question 2 for an S wave in the same medium (Hint: you have to determine the S wave speed).

The average speed of the round trip is 1.25 m/s.

The average speed of the round trip journey is obtained by taking the average of the forward and return speed of the journey.

Average speed = 1.0 + 1.5/2 = 1.25 m/s

In conclusion, the average speed of the round trip is the average of the initial and final speeds.

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From the darkest part of the object's shadow, you would be able to see a small amount of the light source. There would be a small amount of light that is visible, but it would be faint. On the other hand, from the lightest part of the shadow, you would be able to see much more of the light source. The light source would be far brighter and more visible, and you would be able to identify the source of the light.

Answer:

10 g at 10°C

Explanation:

Answer:

10 g at 10°C

Explanation:

Heat energy is directly proportional to the mass and the temperature of a substance. When comparing two samples of the same substance, the one with higher mass contains more heat energy. Similarly, a substance with higher temperature contains more heat energy compared to the same substance with a lower temperature.

In this case, the smallest amount of heat energy would be in the sample of 10g at 10°C. This is because it has the lowest mass and temperature compared to the other three options.



ALLEN

I am not able to understand..

What are you saying?

Answer:

Explanation:

A microscope is made up of a convex lens and the nature of the image formed by the object viewed from it is a virtual image. Since the image is virtual, the image distance will be negative and the focal length will be positive (for convex lenses).

Using the lens formula to first calculate the image distance from the lens;

1/f = 1/u + 1/v

f is the focal length = 0.150 cm,

u is the object distance = 0.155 cm

v is the image distance.

Since the image distance is negative,

1/f = 1/u - 1/v

1/0.150 = 1/0.155 - 1/v

1/v = 1/0.155 - 1/0.15

1/v = 6.542 - 6.667

1/v = -0.125

v = 1/-0.125

v = -8 cm

Magnification = image distance/object distance

Mag = 8/0.155

Mag = 51.6

Magnification produces is 51.6

Answer:

mass and distance

Explanation:

mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

ANSWER:

a. Water vapor

STEP-BY-STEP EXPLANATION:

The density of water vapor is less than the density of a water liquid, in the case of ice, we can see how ice floats on liquid water, which indicates that it has a lower density.

The water obtains its highest density at 4°C, being equal to 1000 kg/m³, in that state it is still liquid water, at room temperature, it is a little lower but it is still a higher density than water vapor, boiling water and ice.

Water vapor would have a lower density than all of them since it is a gas, so the correct answer is a. Water vapor

The unit vector along r(t) will be 3t–4t^2+2

A vector is a quantity with direction and magnitude that is especially useful for locating one location in space in relation to another. A quantity or phenomena with independent qualities for both size and direction is called a vector. The word can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields weight are a few examples of vectors in nature.

Given the the position of particle as a function of particle of time is given by: r(t)=3tî–4t^2j+2k. Where î & j are unit vector along the x-axis and y-axis respectively.

We have to find the unit vector along r(t)

To find the unit vector along r(t) we have to put the value of (i,j,k) = (1,1,1) in r(t)

So,

r(t) = 3tî–4t^2j+2k

r(t) = 3t(1)–4t^2(1)+2(1)

r(t) = 3t–4t^2+2

Therefore the unit vector along r(t) will be 3t–4t^2+2

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Answer: The lowest outside temperature for which the sleeping bag provides adequate protection is approximately 89.61°C below the hiker's skin temperature of 34°C.

Explanation:

To find the lowest outside temperature for which the sleeping bag provides adequate protection, we need to determine the rate of heat loss through conduction and compare it to the heat loss the hiker can safely tolerate.

The rate of heat loss through conduction can be calculated using the formula:

Q = (k * A * ΔT) / d

Where:

Q is the rate of heat transfer (in Watts)

k is the coefficient of thermal conductivity (0.019 Wm¹¹°C-¹ in this case)

A is the surface area (1.3 m² in this case)

ΔT is the temperature difference (in this case, the difference between the skin temperature and the outside temperature)

d is the thickness of the sleeping bag (30 mm, which needs to be converted to meters by dividing by 1000)

Let's plug in the values:

Q = (0.019 * 1.3 * ΔT) / (30 / 1000)

The hiker can safely lose 85 W of heat, so we can set up the equation:

85 = (0.019 * 1.3 * ΔT) / (30 / 1000)

To solve for ΔT, we can rearrange the equation:

ΔT = (85 * (30 / 1000)) / (0.019 * 1.3)

ΔT ≈ 89.61°C