Factors behind a non-nuclear state’s decision on whether or not to pursue nuclear weapons include:
Answers
The Factors include the following:
Capabilities and Security.
What are nuclear weapons?Nuclear weapons are a type of weapon that uses nuclear reactions to create destructive explosion.
When a nuclear weapon explodes, it gives off four types of energy: a blast wave, intense light, heat, and radiation.
The factors that may cause a country to obtain or not to obtain nuclear weapons are discussed below:
Capabilities: This has to do with the financial and economic status of the country involved as nuclear weapon materials are very costly to purchase.Security: Nuclear weapons are considered the best security guarantee against any external aggression.Learn more about nuclear reactions here:
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Related Questions
A car, initially traveling at 5 meters per second north, accelerates to 25 meters per second north in 4.0 seconds. Determine the magnitude and direction of the car's acceleration.
Answers
Answer:
a = 5 [m/s²]
Explanation:
To solve this equation we must use the following equation of kinematics.
\(v_{f} =v_{o} +a*t\)
where:
Vf = final velocity = 25 [m/s]
Vo = initial velocity = 5 [m/s]
a = acceleration [m/s²]
t = time = 4 [s]
Note: The positive sign for the acceleration in the above equation means that the car is increasing its velocity.
25 = 5 +a*(4)
25 - 5 = 4*a
20 = 4*a
a = 5 [m/s²]
Helpp pls, with explanation
Answers
Answer:
B .
Explanation:
Elastic potential energy stored in a spring is given by;
E=1/2*k*{Δl}² where
k= spring constant
Δl = change is length of spring
if k is different the energy stored in the system is different. This is true also in the case where Δl is different.
For a parallel system, springs help each other to carry the weight. The stiffness doubles up to mean ;
k parallel =2k
and
Δl parallel = 1/2 Δl
so;
E in one spring = 1/2*k*{Δl}²----------{a}
Using {a} this in the parallel system;
E parallel = 1/2 * 2k * {1/2Δl}²
= 1/2 * 2* k* 1/4 *{Δl}²
= 1/2 E in one spring
Answer : Ep / 2
Two solenoids have the same cross-sectional area and length, but the first one has twice as many turns per unit length as the second. The ratio of the self-inductance of the second solenoid to that of the first is.
Answers
Answer:
2:1
Explanation:
What separates musical theater from other dance styles?
Answers
Answer: Musical theater is like acting in a musical.
Explanation: Other dance styles don't involve singing.
a sonar system can use sound waves wih a frequency of 120kHz or 200kHz. A. what is the wavelength of each of these waves when they are sent through sea water?
B. What are their wavelengths in freshwater?
C. The ship operating these sonar systems is in sea water with a depth of 3km.
How long will it take an echo to return to the ship after a ‘ping’
Answers
(A) The wavelength of each of these waves when they are sent through sea water is 0.0126 m and 0.0076 m respectively.
(B) The wavelength of each of these waves when they are sent through freshwater is 0.012 m and 0.0074 m respectively.
(C) The time taken for the echo to return to the ship is 3.97 seconds.
What is the wavelength of the sound wave in sea water?
The wavelength of the sound wave in sea water depends on the speed of sound in seawater and frequency of the wave.
The speed of sound in seawater, v = 1,510 m/s
λ = v/f
when the frequency, f = 120 kHz
λ = 1510 / 120,000
λ = 0.0126 m
when the frequency, f = 200 kHz
λ = 1510 / 200,000
λ = 0.0076 m
The speed of sound in freshwater, v = 1481 m/s
when the frequency, f = 120 kHz
λ = 1481 / 120,000
λ = 0.012 m
when the frequency, f = 200 kHz
λ = 1481 / 200,000
λ = 0.0074 m
The time taken for the echo to return is calculated as follows
v = 2d/t
t = 2d/v
t = (2 x 3,000 m) / (1510 m/s)
t = 3.97 s
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Need help quick!!!!
When trying make an object accelerate, what kind of Net force is required?
A. Balanced Force
B. Unbalanced Force
C. Force of Friction
D. Normal Force
Answers
A sphere with radius 10 cm is filled with a uniform charge distribution. The magnitude of the electric field at a point 5 cm from the center of the sphere is 3014 N/coul. Use this fact to calculate the charge density rho inside the sphere.
Answers
Answer:15 cm
Explanation: u had 10cm. them u had another 5cm
Write a C++ program to combine two resistor values, R1 and R2. If the resistors are in series, the will add. That is Rseries =R1+R2. If the resistors are in parallel, they will add inversely. That is, Rparallel =1.0/(1.0/R1+1.0/R2). In your program, ask your user to specify the two resistor values, and ask if they are in series or in parallel. Write a single function that combines the resistances in the appropriate manner if the resistances are in series or parallel. Your function argument list should have three values, the two resistances (which are both type double) and a string indicating "series" or "parallel". The function should return a double that is the net series or parallel resistance, and your program should output this value. Test your code by combining a 100ohm and 50ohm resistance in series and then again in parallel.
Answers
C++ program to combine two resistor values is as follows:```#include
#include
using namespace std;
double resistance_combine(double R1, double R2, string combine_type){
double res_value;
if(combine_type == "series"){
res_value = R1 + R2;
}
else if(combine_type == "parallel"){
res_value = 1.0 / (1.0 / R1 + 1.0 / R2);
}
else{
cout << "Error: combine type can only be 'series' or 'parallel'" << endl;
}
return res_value;
}
int main(){
double R1, R2;
string combine_type;
cout << "Enter the value of R1: ";
cin >> R1;
cout << "Enter the value of R2: ";
cin >> R2;
cout << "Enter the combine type (series/parallel): ";
cin >> combine_type;
double res_value = resistance_combine(R1, R2, combine_type);
cout << "Net resistance value: " << res_value << " ohms" << endl;
return 0;
}`
``In this C++ program, we have created a function named `resistance_combine` that takes three arguments: two resistances (`R1` and `R2`) and a string indicating whether the resistances are in series or parallel. The function checks the `combine_type` argument to determine whether the resistances are in series or parallel.
If the resistances are in series, the function adds them up and returns the result. If the resistances are in parallel, the function adds them inversely and returns the result.
The `main` function asks the user to enter the two resistor values (`R1` and `R2`) and the combine type (`series` or `parallel`). It then calls the `resistance_combine` function with these values and displays the result. The user can test the program by combining a 100ohm and 50ohm resistance in series and then again in parallel.
The `resistance_combine` function is a generic function that can be used to combine any two resistors in series or parallel. It can be easily modified to include more resistors. This program is useful for calculating the total resistance in a circuit when resistors are connected in series or parallel.
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A 26 kg bin is stationary on the driveway. The coefficient of static friction is 0.25. You pull on the bin with a force of 52 N [E] and your friend pulls with a force of 110 N [W]. Will the bin move? Explain your reasoning.
Answers
The bin will not move because the frictional force is greater than the net force acting on the bin.
What is the net force acting on the bin?The net force acting on the bin is obtained by subtracting the force acting on the Easterly direction from that acting in the Westerly direction.
Net force = 110 N - 52 N
Net force = 58 N
The frictional force acting on the bin is determined as well using the given formula:
Frictional force = coefficient of static friction * normal reaction
Norma reaction = 26 * 9.81
Normal reaction = 255.06 N
coefficient of static friction = 0.25
Frictional force = 0.25 * 255.06
Frictional force = 63.8 N
Since the frictional force is greater than the net force acting on the bin, the bin will not move.
In conclusion, the frictional force is the force that opposes relative between two objects at their surface of contact.
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Two cars bump going the same direction and stick together. Car A has a mass of 1000kg car B has a mass of 2000kg. What the speed of the cars after the collision?
Answers
Answer:
I belive that the 2000 kg will be going faster then the 1000kg
Explanation:
Because it is 2x as heavy as the other car which means it most likely would hit the car and keep going because it can hit it so hard that the car dosent hit effected
1. Find the density of the N nucleus. 2. The binding energy per nucleon E, of the lithium isotope Li is 5.6 MeV/nucleon. Find its atomic mass of this isotope. 3. Find the energy needed to remove a proton from the nucleus of the potassium isotopek
Answers
The density of the N nucleus can be calculated by dividing its mass by its volume, the binding energy per nucleon E of the lithium isotope Li is \(5.6 MeV/nucleon\), the energy needed to remove a proton from the nucleus of the potassium isotope K is \(289.77 MeV\)
The mass number of N is 14 and its atomic number is 7. The number of neutrons in the N nucleus is given by \(14 - 7 = 7\) neutrons.
The mass of one neutron is about 1.008665 atomic mass units (amu) or \(1.67493 \times 10^{-27} kg\).
The mass of the N nucleus = \(7(1.008665) + 7.016004 = 14.04273 $ amu\). Thus, the density of the N nucleus can be calculated by dividing its mass by its volume.
The binding energy per nucleon E of the lithium isotope Li is 5.6 MeV/nucleon. To find its atomic mass of this isotope, the mass defect of the nucleus is calculated using the formula:
Mass defect = (Zmp + Nmn) - M
where
Z = number of protons, N = number of neutrons, mp = mass of a proton, mn = mass of a neutron, M = mass of the nucleus.The mass of a proton is approximately \(1.00728 amu\), while the mass of a neutron is approximately \(1.00866 amu\).
Mass defect = \((3 \times 1.00728 + 4 \times 1.00866) - 7.01600\)Mass defect = \(0.126 $ amu\)Atomic mass of \(Li-7 = 7.01600 - 0.126\)Atomic mass of \(Li-7 = 6.89 amu\)The energy needed to remove a proton from the nucleus of the potassium isotope K can be calculated using the formula:
Binding energy = \(E \times A\)
where E is the binding energy per nucleon, A is the mass number. Binding energy of K isotope = 7.43 MeV/nucleon (given)
Mass number of K isotope = \(39\)Binding energy = \(7.43 \times 39\)Binding energy = \(289.77 MeV\)Thus, the energy needed to remove a proton from the nucleus of the potassium isotope K is \(289.77 MeV\).
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Find the work done by F over the curve in the direction of increasing t. F = 3xyi + 4yj - 3yzk r(t) = ti+t?j + tk
Answers
The work done by the applied force in the direction of increasing t is determined as 3xyt + 4yt - 3yzt.
What is the work done by the force?The work done by the force is calculated by applying the following formulas.
W = Fd
where;
F is the applied forced is the displacement of the objectThe force is given as;
F = 3xyi + 4yj - 3yzk
d = r(t) = ti + tj + tk
The work done by the object is the dot product of the force and the displacement;
F · r(t) = [3xy + 4y - 3yz] · [t + t + t]
F · r(t) = 3xyt + 4yt - 3yzt
Thus, the work done by the applied force in the direction of increasing t is determined as 3xyt + 4yt - 3yzt.
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please help will give brainlest
Which of the following situations best demonstrates the effects of friction?
a
a loaded slingshot
b
a parachutist descending to the ground
c
two trucks colliding
d
an apple falling from a tree
Answers
Answer:
Two trucks colliding C.
A ______ is like a ramp that can work while it is in _____.
Answers
A wedge is like a ramp that can work while in motion.
What is ramp?
As a tool for raising or lowering a load, an inclined plane, also referred to as a ramp, is a flat supporting surface that is tilted at an angle from the vertical direction with one end higher than the other. One of the six traditional simple machines that Renaissance scientists defined is the inclined plane.
Heavy loads are transported over vertical obstacles using inclined planes. Examples include a ramp used to load cargo into a truck, a pedestrian ascending a ramp, or an automobile or train ascending a grade.
Less force is needed to lift an object up an inclined plane than to lift it straight up, but the distance travelled is greater. Hence, a wedge is like a ramp that can work while in motion.
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What is the equation that shows the inverse relationship between wavelength and frequency?
Answers
Answer:
V = f * λ velocity equals frequency * wavelength
If f is increased then λ must decrease for the velocity to remain constant.
Convection does NOT occur in
which states of matter?
A. gas
B. solid
C. liquid
Answers
Answer: SOLID
Some giant ocean waves have a wavelength of 25 m and a frequency of
0.26 Hz. What is the wavespeed of such a wave? *
Answers
Answer:
Explanation:
The frequency equation for waves is
\(f=\frac{v}{\lambda}\) where f is the frequency, v is the velocity, and lambda is the wavelength. Filling in:
\(.26=\frac{v}{25}\) so
v = .26(25) and
v = 6.5 meters/second
a group on the periodic table is best described as as
Answers
Answer:
vertical columns
Explanation:
you should search up answers before putting them here. It will save time
A car speeds up from rest to 40 m/s in 5 s. Find the car speed at 2 s and overall
distance traveled.
Answers
Answer:
I would have to say that i feel that after 2 seconds it would be 8 m/s and the overall distance would be 200 m but don't quote me on it
Explanation:
8. Numerical problems (a) Hani drags a load of 60 kg along a distance of 12m. What amount of work does he do ? Also mention the type of work. salur
Answers
Applying Newton's law
\(\\ \sf\longmapsto F=mg\)
\(\\ \sf\longmapsto F=60(10)\)
\(\\ \sf\longmapsto F=600N\)
Now
\(\\ \sf\longmapsto W=Fd \)
\(\\ \sf\longmapsto W=600(12)\)
\(\\ \sf\longmapsto W=7200J\)
Positive work doneScientists study how the continents move. Why might scientists use a model
to show this movement?
O A. It is too slow to observe directly.
O B. It is too fast to observe directly.
O C. It is too dangerous to observe directly.
O D. It is too complex to observe directly.
Answers
Answer: A
Explanation: continents move very slowly, about one inch per year
Answer:
A
Explanation:
it takes thousands of years to see the continents progress in it's movement. by the time we see progress of how they are moving you'd have been dead for 50000 years XD
if you expend a 10 j of work to push a 1-C charge against an electric field what is its change in velocity
Answers
The charge could have a final velocity of either 4.47 m/s or -4.47 m/s, depending on the direction of the electric field and the direction of the force exerted on the charge.
ΔK = (1/2)mv²f - (1/2)mv²i
Substituting these values into the equation, we get:
(1/2)mv²f - (1/2)mv²i = W
(1/2)(1 kg)(v²f - 0) = 10 J
Simplifying the equation, we get:
v²f = 20 m²/s²
Taking the square root of both sides, we get:
vf = ±4.47 m/s
Velocity is a vector quantity that describes the rate at which an object changes its position in a particular direction. It is defined as the rate of change of displacement with respect to time. Velocity is expressed in units of meters per second (m/s) or any other unit of distance divided by time. The direction of the velocity vector is the same as the direction of motion of the object.
The difference between velocity and speed is that velocity takes into account the direction of motion, whereas speed only refers to the magnitude of the motion. An object can have different velocities at different times. If the velocity of an object changes, then it is said to be accelerating. The acceleration of an object is the rate of change of velocity with respect to time.
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How do you find the equation of the best fit line?
Answers
To find the equation of the best-fit line, you must first gather a set of data points that represent the relationship between two variables. Next, you will use a statistical method known as linear regression to find the line that best fits the data points.
There are two common methods for finding the equation of the best-fit line: the least squares method and the method of gradient descent.
The least squares method involves finding the line that minimizes the sum of the squared differences between the observed data points and the line. This method can be solved algebraically using matrices and linear algebra.
The gradient descent method involves iteratively adjusting the line parameters until the sum of the squared differences between the observed data points and the line is minimized. This method is typically used in machine learning and requires programming and optimization algorithms.
Once you have found the equation of the best-fit line, you can use it to make predictions about future data. For example, if you have data on the relationship between the height and weight of individuals, you can use the equation of the best-fit line to estimate the weight of an individual based on their height.
The equation of the best-fit line is a mathematical representation of the relationship between two variables in a dataset. It is used to make predictions about future data based on past observations.
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If a box of max 59kg is place in a height 25m, what is the potantial energy (take= g as 10k)
Answers
Placing a box weighing up to 59 kg at a height of 25 m results in potential energy of 14,750 Joules, assuming the acceleration due to gravity is 10 m/s².
The potential energy of an object is given by the equation PE = mgh, where m represents the mass of the object, g is the acceleration due to gravity, and h is the height of the object from a reference point. In this case, the box has a maximum weight of 59 kg.
To calculate the potential energy, we can substitute the given values into the equation. With a mass of 59 kg, a height of 25 m, and g as 10 m/s², we have PE = (59 kg) * (10 m/s²) * (25 m).
Multiplying these values together, we find that the potential energy of the box is 14,750 Joules. The unit of potential energy is Joules, which represents the amount of energy an object possesses due to its position relative to a reference point.
Therefore, when a box with a maximum weight of 59 kg is placed at a height of 25 m, it has a potential energy of 14,750 Joules, assuming the acceleration due to gravity is 10 m/s².
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HEELLLLLPPPPPPPPPPPP MEEEEEEEEEE!!!!!!!!!!!!
Which statement best describes the thermosphere?
The thermosphere sits directly below the troposphere.
Lighter gases such as nitrogen and oxygen rise to the top of the thermosphere.
Heavier gases such as hydrogen and helium stay at the bottom of the thermosphere.
The atmosphere is so thin that gas molecules rarely contact each other.
Answers
Answer:
I think the second one
Explanation:
its the only one that makes since tell me if I'm wrong
Answer:
the answer is "The atmosphere is so thin that gas molecules rarely contact each other."
Explanation: just took the semester test
Two physics students, Albion and Gotham, are observing a grapefruit as it rolls naturally up, and then back down, a ramp. Their instructor asks them to find the grapefruit's acceleration at the very top of the ramp, just before it starts to roll back down. Albion says, "The velocity is zero at the top. That means the acceleration also has to be zero." Gotham replies, "I disagree. At the top of the ramp the velocity is changing, which means the acceleration can't be zero." Which student do you agree with? Explain the reason for your choice. Further, consider the perspective of the student who you think is incorrect, and explain why they might be confused. The depth and clarity of your response matter just as much as its correctness!
Answers
In the given case, Gotham is correct that the acceleration can't be zero at the top of the ramp.
When a grapefruit rolls up, and then back down a ramp, it goes through multiple stages of motion. At the very top of the ramp, the grapefruit comes to rest for a moment and switches its direction of motion. This point is called the maximum point. Now, to understand the acceleration of the grapefruit at the top of the ramp, let's define the variables:
v: Velocity of the grapefruit as it rolls up and back down the ramp
a: Acceleration of the grapefruit as it rolls up and back down the ramp
t: Time taken by the grapefruit to go up and back down the ramp
The grapefruit reaches the maximum point at time t. At this point, its velocity is zero, and it starts to reverse direction. From Albion's argument, it's possible to infer that he's thinking of a situation where the grapefruit is moving in one direction. In that case, if it comes to rest at the top, then the acceleration has to be zero. However, in the given situation, the grapefruit is not just moving in one direction but is going up and then back down. At the top of the ramp, the grapefruit has to switch direction, and this is where its velocity is zero. However, its acceleration is not zero, as it's in the process of changing direction. The grapefruit's velocity is changing at the top of the ramp, and hence the acceleration can't be zero.
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Important factors that contribute to smog formation in the Los Angeles basin include which of the following?
I. Ample summer sunshine
II. Sea-level elevation
II. High concentration of automobiles
I only
III only
I and III only
II and III only
I, II, and III
Answers
The combined influence of these factors (I, II, and III) contributes to the persistent smog problem in the Los Angeles basin.
What is one important factor that contributes to smog formation in the Los Angeles basin?The factors that contribute to smog formation in the Los Angeles basin include I, II, and III. I, ample summer sunshine, plays a crucial role in the chemical reactions that form smog.
The intense sunlight triggers the photochemical reactions between nitrogen oxides (NOx) and volatile organic compounds (VOCs) emitted by various sources.
II, sea-level elevation, is significant because it traps pollutants within the basin, limiting their dispersion and contributing to smog buildup. III, the high concentration of automobiles, releases significant amounts of NOx and VOCs, acting as primary contributors to smog formation.
The combined influence of these factors (I, II, and III) contributes to the persistent smog problem in the Los Angeles basin.
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A ball is thrown from a hot air balloon that is at rest 245 m above the ground. How long will it take for the ball to reach the ground? How fast will the ball be traveling when it reaches the ground?
Answers
Answer:
7.07 s
69.3 m/s
Explanation:
Taking the negative direction to be down and the positive direction to be up:
We have 3 variables in the y-direction and can solve for time.
v₀ = 0 m/sa = -9/8 m/s² Δy = -245 m t = ?Use this kinematics equation to solve for time.
Δx = v₀t + 1/2at² -245 = 1/2(-9.8)t² -245 = -4.9t² t² = 50t = 7.07106781187It will take the ball 7.07 s to reach the ground.
We can solve for final velocity using the same variables in the y-direction:
v₀ = 0 m/sa = -9/8 m/s² Δy = -245 m v = ?Use this kinematics equation to solve for final velocity.
v² = v₀² + 2aΔxv² = 2(-9.8)(-245) v² = 4802v = 69.2964645563The ball will be traveling at a speed of 69.3 m/s at the instant before it reaches the ground.
Problem 3. 28 a circular ring in the xy plane (radius r, centered at the origin) carries a uniform line charge λ. Find the first three terms (n = 0, 1, 2) in the multipole expansion for v (r, θ )
Answers
Find the first three terms (n = 0, 1, 2) in the multipole expansion for the potential due to a uniform line charge λ on a circular ring in the xy-plane with radius r and centered at the origin.
To find the multipole expansion for the potential, we can use the formula:
v(r,θ) = 1/(4πε0) ∑n=0 ∞ \((1/r^(n+1))\)∫(Pn(cosφ')) ρ(r',φ') \(r'^n dr' dφ'\)
where Pn is the nth Legendre polynomial, ρ is the charge density, r' and φ' are the polar coordinates of the charge element, and the integral is taken over the entire charge distribution.
For a circular ring with radius r and uniform line charge λ, the charge density is:
ρ(r',φ') = λ/(2πr')
and we can simplify the integral by using the substitution u = cos(φ' - θ):
v(r,θ) = λ/(4πε0) ∫(0 to 2π) [∑n=0 ∞ \((r'/r)^(n+1)\) Pn(u)] du
The Legendre polynomials can be expressed as:
Pn(u) = \((1/2^n) (d^n/dx^n) (x^2 - 1)^n/2\) |x=u
So we can evaluate the sum inside the integral for the first few terms:
n=0: (r'/r) P0(u) = (r'/r)
n=1: \((r'/r)^2 P1(u)\) = (3/2) (r'/r) u
n=2:\((r'/r)^3 P2(u)\) = (5/2) \((3u^2 - 1) (r'/r)^3 / 2\)
Plugging these into the integral and evaluating, we get:
v(r,θ) = λ/(4πε0) [2(r/r') - \((3/2)(r/r')^2\) cos(θ - φ') + \((5/4)(r/r')^\)3 \((3cos^2(θ - φ') - 1)]\)
Expanding the cosine terms using the identity cos(θ - φ') = cosθ cosφ' + sinθ sinφ', we can write:
\(v(r,θ) = λ/(4πε0) [2(r/r')\) - \((3/2)(r/r')^2\)cosθ ∫(0 to 2π) cosφ' dφ' - \((3/2)(r/r')^2\)sinθ ∫(0 to 2π) sinφ' dφ' +\((15/4)(r/r')^3 cos^2θ\) ∫(0 to 2π) \(cos^2φ' dφ' - (15/4)(r/r')^3\) sinθ cosθ ∫(0 to 2π) cosφ' sinφ' dφ' -\((5/4)(r/r')^3 ∫(0 to 2π) dφ']\)
Evaluating the integrals, we get:
∫(0 to 2π) cosφ' dφ' = ∫(0 to 2π) sinφ' dφ' = 0
∫(0 to 2π)\(cos^2φ' dφ' = π\)
∫(0 to 2π) cosφ' sinφ' dφ' = 0
∫(0 to 2π) dφ' = 2π
So the final expression for the potential becomes:
\(v(r,θ) = λ/(2ε0) [r/r' - (3/4)(r/r')^2 cosθ + (15/8)(r/r')^3 cos^\)
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two equally charged particles are held 3.2x10-3 m apart and then released from rest. the initial acceleration of the first particle is observed to be 7.0 m/s2 and that of the second to be 9.0m/s2 . if the mass of the first particle is 6.3 x 10-7 kg, what are (a) the mass of the second particle and (b) the magnitude
Answers
The mass and magnitude of the second particle are calculated below.
The initial velocity of an object is its velocity prior to the effect of acceleration, which causes the change. The velocity will be the final velocity after accelerating the object for some time. When a particle moves at a constant speed, it can be accelerated. When a point object moves in a horizontal circular path at a constant speed, the direction of its velocity vector changes over time. It means that in a uniform circular motion, the object's velocity vector changes over time.
Distance between the charges, r = 3.2 × \(10^{-3}\)m
initial acceleration of first particle, \(a_{1}\) = 7m / \(s^{2}\)
Initial acceleration of second particle, \(a_{2}\) = 9.0m / \(s^{2}\)
Mass of first particle, \(m_{1}\) = 6.3 × \(10^{-7}\)kg
Mas of second particle, m₂ = ?
a) Since, \(F_{1}=F_{2}\)
∴ \(m_{1}a_{1} = m_{2}a_{2}\)
mass of second particle-\(m_{2}\) =\(\frac{m_{1}\times a_{1}}{a_{2}}\)
= \(\frac{6.3\times10^{-7}\times7.0}{9.0}\)
=4.9 × \(10^{-7}\)Kg
b)As, \(F_{1} = F_{2}\)
= \(\frac{q_{1}q_{2}}{4\pi E_{0}r^{2}}\) = \(m_{1}a_{1}\)
= 6.3 × \(10^{-7} \times\) 7.0
= 44.1 × \(10^{-7}\)
∴ q = 7.1 × \(10^{-11}\)C.
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