Find a vector of magnitude 5 which is parallel to 2icap -jcap

please solve step by step​

Answer:

Researchers use a wide range of technologies today to help gather data, depending on the field of study and the type of data they need to collect. Here are some examples:

   Sensors: Sensors are devices that can detect and measure physical quantities such as temperature, pressure, and motion. Researchers use sensors to collect data on the environment, human behavior, and other phenomena.

   Drones: Drones or unmanned aerial vehicles (UAVs) are aircraft that are remotely controlled or can fly autonomously. Researchers use drones to collect data from hard-to-reach or dangerous areas, such as remote forests, volcanoes, or disaster zones.

   Satellites: Satellites are spacecraft that orbit the Earth and can collect data on a wide range of environmental and climatic factors, such as temperature, rainfall, and ocean currents. Researchers use satellite data to study climate change, natural disasters, and other global phenomena.

   Imaging technologies: Imaging technologies such as magnetic resonance imaging (MRI) and computed tomography (CT) scans are used to collect detailed images of the body's internal structures. Researchers use these images to study the human brain, diagnose diseases, and develop new medical treatments.

   Social media and online platforms: Social media and online platforms provide researchers with access to large amounts of data on human behavior, opinions, and attitudes. Researchers use this data to study social trends, political movements, and public opinion.

   Wearable technology: Wearable technology such as fitness trackers and smartwatches collect data on physical activity, heart rate, and other health metrics. Researchers use this data to study human health and behavior.

These are just a few examples of the many technologies researchers use today to help gather data. The use of advanced technology has revolutionized the way researchers collect and analyze data, allowing them to make new discoveries and gain a deeper understanding of the world around us.

Answer:

\(v=\sqrt{26}~m/s\)

Explanation:

Parametric Equation of the Velocity

Given the position of the particle at any time t as

\(r(t) = (x(t),y(t))\)

The instantaneous velocity is the first derivative of the position:

\(v(t)=(v_x(t),v_y(t))=(x'(t),y'(t))\)

The speed can be calculated as the magnitude of the velocity:

\(v=\sqrt{v_x^2+v_y^2}\)

We are given the coordinates of the position of a particle as:

\(x=5t-3t^2\)

\(y=5t\)

The coordinates of the velocity are:

\(v_x(t)=(5t-3t^2)'=5-6t\)

\(v_y(t)=(5t)'=5\)

Evaluating at t=1 s:

\(v_x(1)=5-6(1)=-1\)

\(v_y(1)=5\)

The velocity is:

\(v=\sqrt{(-1)^2+5^2}\)

\(v=\sqrt{1+25}\)

\(\mathbf{v=\sqrt{26}~m/s}\)

Answer:

Approximately \((-0.33)\; {\rm m\cdot s^{-2}}\) (\((-1/3)\; {\rm m\cdot s^{-2}}\)) on average.

Explanation:

Acceleration is the rate of change in velocity.

For the ball in this question:

Subtract the initial velocity \(u\) from the final velocity \(v\) to find the change in velocity:

\(\begin{aligned}(\text{change in velocity}) &= (\text{final velocity}) - (\text{initial velocity}) \end{aligned}\).

\(\begin{aligned}\Delta v &= v - u \\ &= 0\; {\rm m\cdot s^{-1}} - 12\; {\rm m\cdot s^{-1}} \\ &= (-12)\; {\rm m\cdot s^{-1}} \end{aligned}\).

(Note that the change in velocity is negative because the final velocity \(v = 0\; {\rm m \cdot s^{-1}}\) is more negative than the initial velocity \(u = 12\; {\rm m\cdot s^{-1}}\).)

To find the average acceleration \(a\) (average rate of change in velocity,) divide the change in velocity \(\Delta v\) by the time \(\Delta t\) required to achieve such change:

\(\begin{aligned}(\text{average acceleration}) &= \frac{(\text{velocity change})}{(\text{time required for change})}\end{aligned}\).

\(\begin{aligned} a &= \frac{\Delta v}{\Delta t} \\ &= \frac{(-12)\; {\rm m\cdot s^{-1}}}{36\; {\rm m\cdot s^{-1}}} \\ &\approx (-0.33) \; {\rm m\cdot s^{-2}}\end{aligned}\).

(Average acceleration is negative since velocity is becoming less positive.)

Answer:

afgiknvdeyiknvxwtuinvdruincdyukn

The moment of inertia is 0.00625 kg·m^2 for both the initial and final speeds

To calculate the moment of inertia when the speed of the wheel increases, we need to know the distribution of mass in the body. Assuming the body is a thin ring with the mass concentrated on the rim, we can use the formula for the moment of inertia of a thin ring:

I = m * \(r^2\)

where I is the moment of inertia, m is the mass, and r is the radius.

Given:

Mass of the body (m) = 100 g = 0.1 kg

Diameter of the circular path = 500 mm

Radius (r) = Diameter / 2 = 500 mm / 2 = 250 mm = 0.25 m

Calculate the initial moment of inertia:

Initial speed = 450 rpm

Initial angular velocity (ω1) = 450 rpm * 2π / 60 = 47.12 rad/s

Using the formula for moment of inertia:

I1 = m * r^2

I1 = 0.1 kg * (0.25 m)^2

I1 = 0.00625 kg·m^2

Calculate the final moment of inertia:

Final speed = 750 rpm

Final angular velocity (ω2) = 750 rpm * 2π / 60 = 78.54 rad/s

Using the formula for moment of inertia:

I2 = \(m * r^2\)

I2 = \(0.1 kg * (0.25 m)^2\)

I2 = \(0.00625 kgm^2\)

Therefore, the moment of inertia remains the same as the mass and radius do not change. The moment of inertia is 0.00625 kg·m^2 for both the initial and final speeds.

Know more about moment of inertia    here

https://brainly.com/question/14460640

#SPJ8

The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

For more such questions on time elapsed, click on:

https://brainly.com/question/31287589

#SPJ8

Answer:

3150

Explanation:

if if you were two times 45 times 70 it would give you that answer

Answer:

option 5

Explanation:

because all u do is have to add them up

On average, the Sun is located around 93,000,000 miles (150 million kilometers) from Earth. It is so far away that it takes roughly 8 minutes for the Sun's light, which is moving at a speed of 186,000 miles per second (300,000 kilometers per second), to reach us.

The Sun is only 8.3 light minutes away from Earth, or 1.5781e-5 light years, since light travels from the photosphere of the Sun to the Earth in only 8.3 minutes.

The distance light travels in a year is measured in light-years. Light travels 5.88 trillion miles and 186,000 miles per second through interstellar space.

To know more about light travels visit:-

https://brainly.com/question/1831789

#SPJ4

ANSWER:

STEP-BY-STEP EXPLANATION:

Given:

Mass (m) = 8.1 kg

T1 = 64 °F

T2 = 743 °F

Specific heat (C) = 385 J/kg*°C

Answer:

Newton

Explanation:

Newton's are the standard unit of force.

The moment of inertia (I) will changes and net torque (Tnet) will also change, while the angular acceleration (a) remains constant.

The formula for net torque acting on an object is given as;

T(net) = Ia

where;

The  moment of inertia of an object is given as;

I ∝ MR²

where;

So mass, M changes, the moment of inertia (I) changes and net torque will also change, while the angular acceleration remains constant.

Learn more about moment of inertia here: https://brainly.com/question/3406242

#SPJ1

Plate Boundaries on Earth assignment involves identifying and illustrating different types of plate movements at the Earth's contact points.

Here are the steps to be followed:

Step 1: Understanding the Assignment Requirements

Read through the assignment instructions carefully to ensure a clear understanding of the tasks and expectations.

Step 2: Research

Start by conducting research on plate boundaries, their types, movements, and associated geological processes. Use reliable and valid resources such as scientific journals, textbooks, and reputable websites. Take notes on the different plate movements, their characteristics, and examples of each.

Step 3: Worksheet Setup

Create a table or chart with six rows corresponding to the six categories specified in the assignment instructions: Plate Boundary (Movement), Diagram, Lithosphere (Created or Destroyed), Geologic Process, Real World Example, and References.

Step 4: Fill in Row 1 - Plate Boundary (Movement)

In the first row, list the three types of plate boundaries: convergent, divergent, and transform. Next to each type, write the correct description in parentheses: sliding, separating, or colliding.

Step 5: Fill in Row 2 - Diagram

In the second row, draw a diagram or illustration for each type of plate movement. Use arrows to indicate the direction of movement and whether the plates are colliding, separating, or sliding past each other.

Step 6: Fill in Row 3 - Lithosphere (Created or Destroyed)

In the third row, identify whether the Earth's crust is created or destroyed at each type of plate boundary. Note the corresponding effects of plate movement on the lithosphere.

Step 7: Fill in Row 4 - Geologic Process

In the fourth row, provide at least one example of a geologic process or event that occurs as a result of plate movement at each type of boundary. This could include processes like subduction, seafloor spreading, or earthquakes.

Step 8: Fill in Row 5 - Real World Example

In the fifth row, give at least one real-world example of a location where each type of plate movement is demonstrated along a plate boundary. Include the name of the location and its corresponding plate boundary type.

Step 9: Fill in Row 6 - References

In the final row, provide the references for your research in APA format. Include the sources you used to gather information on plate boundaries, plate movements, and related geological processes.

Step 10: Review and Proofread

Review the completed assignment, ensuring that all information is accurate and properly cited. Proofread for any grammatical or spelling errors.

Note: The specific format and layout of the worksheet may vary based on your preference or instructor's instructions. Make sure to follow any specific formatting guidelines provided by your instructor.

Know more about  plate boundaries    here:

https://brainly.com/question/30407141

#SPJ8

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

For more such questions on equilibrium, click on:

https://brainly.com/question/517289

#SPJ8

Answer:

To solve this problem, you'll need to break the initial velocity of the seed into its horizontal and vertical components, then use the equations of motion to find the time of flight and horizontal distance.

The initial velocity (v) of the seed is 2.65 m/s. The angle it's launched at (θ) is 30.0 degrees below the horizontal. The height (h) it's launched from is 0.460 m.

First, calculate the horizontal (v_x) and vertical (v_y) components of the velocity. Because the seed is launched downward, the vertical component will be negative:

v_x = v * cos(θ) = 2.65 m/s * cos(30.0) = 2.29 m/s

v_y = v * sin(θ) = -2.65 m/s * sin(30.0) = -1.325 m/s

Next, use the equation of motion to find the time it takes for the seed to hit the ground:

h = v_y * t + 0.5 * g * t^2

Where g is the acceleration due to gravity, which is approximately 9.8 m/s². Solving the equation for t gives:

t = (-v_y - sqrt((v_y)^2 - 4 * 0.5 * g * (-h))) / (2 * 0.5 * g)

Plugging in the values:

t = (1.325 + sqrt((-1.325)^2 - 4 * 0.5 * 9.8 * (-0.460))) / (2 * 0.5 * 9.8)

t = 0.182 seconds

Finally, use the horizontal velocity and time of flight to find the horizontal distance the seed covers:

x = v_x * t = 2.29 m/s * 0.182 s = 0.417 m

So, the seed lands after approximately 0.182 seconds and travels approximately 0.417 meters horizontally.

The number of revolutions is 102.655 it makes during this motion, assuming no slipping.

V= u+ at

24.8= 0 + a× 10.1

a= (24.8/10.1) m/s²

s= ut +1/2at² = at²/2

= 24.8/10.1×2 × 10.1²

=125.24m

Circumference of tire = πd. =. 3.14 × 0.389= 1.22

Total revolution= 125.24/ 1.22 = 102.655

What is acceleration?

The measurement of a change in velocity called acceleration. Acceleration typically indicates a change in speed, albeit not necessarily. An object moving in a circular path at a constant speed is still moving forward because the direction of motion is shifting. Acceleration is the rate at which an object's velocity varies in relation to time in physics. Newton's Second Law states that an object accelerates as a result of the total of all the forces acting on it. The SI system uses the meter per second squared (m s2) as the measure of acceleration.

Know more about acceleration- brainly.com/question/25876659

#SPJ1

Answer:

..In a distance-time graph, the slope or gradient of the line is equal to the speed of the object. The steeper the line (and the greater the gradient) the faster the object is moving. Calculate the speed of the object represented by the green line in the graph, from 0 to 3 s.

d) steeper

D)Today

If I were an astronaut, the first job I would do on the International Space Station (ISS) would be to familiarize myself with the station and its systems.

I would need to learn how to operate the various equipment and how to maintain the station in good working order. I would also need to learn the procedures for conducting experiments and for performing spacewalks.

Once I had a good understanding of the station and its systems, I would begin working on my assigned tasks. These tasks could include conducting experiments, performing maintenance, or teaching other astronauts new skills. I would also take the opportunity to conduct research on my own and to learn more about the space environment.

Find out more on ISS here: https://brainly.com/question/19594570

#SPJ1

If a 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Then the total work done by the force is equal to π/2 + 1.

To calculate the total work done by the force in this scenario, we can use the formula for work:

Work = ∫F(x) dx

where F(x) is the force as a function of position and dx represents an infinitesimal displacement.

In this case, the force is given by F(x) = √(1 - x²), and we need to find the total work done as the object moves from xo = -1 to xf = 1.

Let's break down the calculation step by step:

Write the integral for work:

Work = ∫F(x) dx

Substitute the given force:

Work = ∫√(1 - x²) dx

Integrate with respect to x:

To integrate the square root of (1 - x²), we use the trigonometric substitution. Let's substitute x = sin(θ) and dx = cos(θ) dθ.

Work = ∫√(1 - sin²(θ)) cos(θ) dθ

Simplify the integrand:

Using the trigonometric identity sin²(θ) + cos²(θ) = 1, we can rewrite the integrand as cos²(θ).

Work = ∫cos²(θ) dθ

Apply the power-reducing formula:

The power-reducing formula states that cos²(θ) = (1 + cos(2θ)) / 2. We can use this formula to simplify the integrand further.

Work = ∫(1 + cos(2θ))/2 dθ

Integrate the terms separately:

Work = (1/2) ∫dθ + (1/2) ∫cos(2θ) dθ

The first integral, ∫dθ, is simply θ, and the second integral, ∫cos(2θ) dθ, can be calculated as sin(2θ)/2.

Work = (1/2) θ + (1/2) (sin(2θ)/2) + C

Evaluate the integral limits:

To find the total work done, we need to evaluate the integral at the upper and lower limits of integration.

At xf = 1, the angle θ is π/2, and at xo = -1, the angle θ is -π/2.

Work = (1/2) (π/2) + (1/2) (sin(2(π/2))/2) - [(1/2) (-π/2) + (1/2) (sin(2(-π/2))/2)]

Simplifying further:

Work = π/4 + (1/2) - (-π/4 + (1/2))

Work = π/4 + 1/2 + π/4 + 1/2

Work = π/2 + 1

Therefore, the total work done by the force is equal to π/2 + 1.

To learn more about Workdone click:

brainly.com/question/28172139

#SPJ1

Answer:

the answer to this question is Accelerated motion

Answer:

Larger in magnitude

Explanation:

As the vectors get closer reducing the 90 degree angle, based on the "parallelogram rule" for vector addition, the magnitude of the resultant vector gets larger than when they are forming a 90 degree angle.

Answer:

☝

Explanation:

Jamil cycles to the shop and back home in 360 seconds. Jamil takes 150 seconds to reach the shop and stays there for 90 seconds and come back to home.

Speed is the rate at which an object or a body moves.

Formula of Speed:

Speed = Distance/Time

In the given graph, Jamil cycles to the shop, time taken by Jamil to reach the shop can be calculated by the first part of the graph.

Time taken = (150-0)sec

Time = 150 sec

The distance travelled by Jamil is denoted on the Y-axis:

Distance travelled to get to the shop = 450m

Speed at which Jamil cycles to the shop can be calculated by:

Speed = Distance/Time

Speed = 450m/150sec

Speed = 3m/sec

The time period for which Jamil stays at the shop can be inferred from the graph as the distance travelled will be zero at that time.

Time for which distance is constant = Horizontal part of the graph

Time = 240sec-150sec

Time = 90sec

The speed at which Jamil cycles back to his home can be calculated by the last part of the graph when he goes back to his home from shop.

Time taken = (360-240)sec

Time taken = 120 sec

Distance Travelled = 450m

Speed = Distance travelled/ Time taken

Speed = 450m/120sec

Speed = 3.75m/sec

Therefore, the speed of Jamil while going to the shop is 3m/sec while the speed of Jamil returning back to home is 3.75m/sec.

Learn more about Speed here:

https://brainly.com/question/6280317

#SPJ1

Answer:

We may have people making habitats on asteroids ... I know that humans will colonize the solar system and one day go beyond. Richard Gott has estimated that the human race could survive for another 7.8 million years, but it is not likely to ever colonize other planets.

To be sure there are many daunting challenges facing prospective space colonists such as protection from exposure to deadly radiation levels, the impact on the human body while living and working in cramped, low-gravity environments for extended periods of time and the psychological toll of isolation and confinement.

According to me we can't colonize other planets which is against humanity

Answer:

The question lacks a photo to fully answer correctly

If the fossil has its neck bent backwards towards its back, that is the common way to which dinosaurs died.

If the fossil is scattered a bit from its other linking fossil pieces, than it is most likely that the dinosaur was a meal to a predator.

Fossils that are in array but are divided clearly at a section suggests that land moved. Possibly earthquake or Pangea took place.

Answer:

Peripatus, which lived around 570 MYA, is in the top layer of rock. The trilobites that lived later, between 498 MYA and 445 MYA, appear in the bottom layer. Based on superposition, younger layers of rock are expected to be on top. The rock layers have been overturned, placing the younger layer on the bottom.

Explanation:

actually answer plauto

Answer:

V = 5.55 volts

Explanation:

Given that,

Current, I = 3.7 A

Resistance, R = 1.5 ohms

We need to find the voltage of the circuit. Let V is the voltage. We can find it using Ohm's law as follows :

V = IR

Substituting all the values, we get :

\(V=3.7\times 1.5\\\\=5.55\ V\)

So, the voltage of the circuit is 5.55 V,

The temperature gradient in the flow of direction is 294525 W.

A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.

Q= T/( L/ KA)

Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)

   = 294525 W

Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.

Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.

Therefore, The temperature gradient in the flow of direction is 294525 W.

To learn more about Temperature gradient, refer to the link:

https://brainly.com/question/13020257

#SPJ9

Answer:

it shows the gorwth

Explanation: