find an expression for the magnitude of the electric field that enables the block to remain at rest.

Answers

Answer 1

To keep the block at rest, an electric field with a magnitude equal to the gravitational force divided by the block's charge is required.

What is magnitude?

A physical quantity's magnitude can be used to gauge its size or strength, such as in the case of a vector. The term "magnitude" in the context of an electric field refers to the field's amplitude.

The "equilibrium electric field" is the electric field needed to hold an object still. A force will be applied to a charged object in an electric field, either in the direction of or away from the source of the field. The net force must be zero in order to maintain the item at rest, which necessitates counteracting the electric field's force with another force.

E = k * q / d2, where k is the Coulomb constant, q is the charge on the object, and d is the separation between the item and the field source, can be used to calculate the size of the electric field necessary for equilibrium. According to this equation, the electric field is inversely proportional to the square of the distance between the item and the field source and directly proportional to the charge on the object.

As a result, if an object is charged and placed in an electric field, the size of the field needed to keep the object at rest will depend on the object's charge and the distance between it and the field source.

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Answer 2

An expression for the magnitude of the electric field that enables the block to remain at rest is:

\(\mathrm{ E = \dfrac{m \times g\times sin(\theta) }{q} }\)

What is magnitude?

A physical quantity's magnitude can be used tο gauge its size or strength, such as in the case of a vector

The "equilibrium electric field" is the electric field needed to hold an object still. A force will be applied to a charged object in an electric field, either in the directiοn of or away from the source of the field. The net force must be zero in order to maintain the item at rest, which necessitates cοunteracting the electric field's fοrce with another force.

According to this equation, the electric field is inversely proportional to the square οf the distance between the item and the field source and directly proportional to the charge on the οbject.

As with a typical inclined plane problem, we need tο find the compοnent of the gravitational fοrce parallel to the incline.

That is

\(\mathrm{ m \times g\times sin(\theta) }\)

For the blοck to remain stationary, we set this equal to the coulοmb force

\(\mathrm{ qE = m \times g\times sin(\theta) }\)

since E is parallel to the incline,

sοlving for E, we find the answer tο part a:

\(\mathrm{ E = \dfrac{m \times g\times sin(\theta) }{q} }\)

Thus, an expression fοr the magnitude οf the electric field that enables the block tο remain at rest is:

\(\mathrm{ E = \dfrac{m \times g\times sin(\theta) }{q} }\)

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Related Questions

Helen is para sailing. She sits in a seat harness which is attached by a tow rope toba speedboat. The rope makes an angle of 59.9* with the horziontal and has a tension of 364N. Determine the horziontal and vertical component of the tension force

Answers

To find the horizontal and vertical components of the tension force in para sailing, we can use the basic trigonometric ratios of sine, cosine and tangent.

How to use trigonometric ratios ?First, given the rope's angle (59.9 degrees) and the tension force (364 N), we can apply the following formula to determine the tension force's horizontal component (Fx): Fx = Tension force x cos(angle) = 364 N x cos (59.9).Next, we can use the angle of the rope and the tension force to find the vertical component (Fy) of the tension force using the formula: Fy = Tension force x sin(angle) = 364 N x sin(59.9)You must convert the angle to radians because these calculations, as you should be aware, employ radians rather than degrees.As a result, the tension force's horizontal component has the following formula: Fx = 364N x cos(59.9) = 225.98N roughly.Additionally, the vertical component of the tension force is roughly 318.6N, or Fy = 364N x sin(59.9)According to these calculations, the tension force has two components: a horizontal component that is 225.98 N and a vertical component that is 318 N.

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can anyone write for me all the equation of linear motion​

Answers

All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.

Equations of Motion

In terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.

s = ut + (1/2)at^2v = u + atv_avg = (u + v) / 2s = v_avg * ts = (u + v) / 2 * tv^2 = u^2 + 2as

In conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.

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Model a hydrogen atom as a three-dimensional potential well with Uo = 0 in the region 0 < x a. 283 eV
b. 339 eV
c. 113 eV
d. 226 eV

Answers

This question is incomplete, the complete question is;

Model a hydrogen atom as a three-dimensional potential well with U₀ = 0 in the region 0 < x < L, 0 < y < L and 0 < z < L, and infinite otherwise, with L = 1.0 × 10⁻¹⁰ m.

Which of the following is NOT one of the lowest three energy levels of an electron in this model?

a. 283 eV

b. 339 eV

c. 113   eV  

d. 226 eV        

Answer:

the lowest three energy are; 113 eV, 225 eV, and 339 eV.

Hence Option a) 283 eV is not among the three lowest energy

Explanation:

Given the data in the question;

Three dimension cube or particle in a cubic box

the energy value is given by;

\(E_{nx,ny,nz\) = \(( n_x^2 + n_y^2 + n_z^2 )\) × π²h"² / 2ml²

where h" = h/2π and h is Planck's constant ( 6.626 × 10⁻³⁴ m² kg / s )

m is mass of electron ( 9.1 × 10⁻³¹ kg )

l is length of side of box ( 1.0 × 10⁻¹⁰ m )

for ground level ( \(n_x = n_y = n_z = 1\) )

so

\(( n_x^2 + n_y^2 + n_z^2 )\) ×  π²h"² / 2ml²

since h" = h/2π

\(( n_x^2 + n_y^2 + n_z^2 )\) × π²h² / (2π)²2ml²

so we substitute

\(E_{111\) = ( 1² + 1² + 1² ) × [ π²( 6.626 × 10⁻³⁴ )² ] / [ (2π)² × 2 × 9.1 × 10⁻³¹ kg × ( 1.0 × 10⁻¹⁰)² ]

\(E_{111\) = 3 × [ (4.333188779 × 10⁻⁶⁶) / ( 7.185072 × 10⁻⁴⁹ ) ]    

\(E_{111\) = 3 × [ 6.03082165 × 10⁻¹⁸ ]

Now, we know that electric charge = 1.602 x 10⁻¹⁹

so

\(E_{111\) = 3 × [ (6.03082165 × 10⁻¹⁸) / (1.602 x 10⁻¹⁹) ]

\(E_{111\) = 3 × [ 37.645578 ]

\(E_{111\) = 112.9 ≈ 113 eV

\(E_{211\) = \(( n_x^2 + n_y^2 + n_z^2 )\)  × π²h² / (2π)²2ml²

we substitute

\(E_{211\) = ( 1² + 1² + 2² ) × [ 37.645578 ]

\(E_{211\) = 6 × [ 37.645578 ]

\(E_{211\) = 225.87 ≈ 226 eV

\(E_{221\) = \(( n_x^2 + n_y^2 + n_z^2 )\)  × π²h² / (2π)²2ml²

we substitute

\(E_{221\) = ( 2² + 2² + 1² ) × [ 37.645578 ]

\(E_{211\) = 9 × [ 37.645578 ]

\(E_{211\) = 338.8 ≈ 339 eV

Therefore, the lowest three energy are; 113 eV, 225 eV, and 339 eV.

Hence Option a) 283 eV is not among the three lowest energy

the_______ of an elemnet is the total number of protons an neutrons in the _______of the atom

Answers

The mass number of an element is the total number of protons and neutrons in the nucleus of the atom.

What is mass number?

Mass number is the total number of protons and neutrons in an atomic nucleus with symbol: A.

An atom is the smallest possible amount of matter which still retains its identity as a chemical element, now known to consist of a nucleus surrounded by electrons.

The atom of an element is made up of the following subatomic particles;

ProtonElectronNeutron

The sum of the proton and neutron in the atom's nucleus is the atom's mass number.

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The work-energy theorem states that the change in the kinetic energy of an object is equal to what?

Answers

The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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Assume you are driving a car at a constant speed of 78.0 km/h. Suddenly you see a deer standing on the highway and you must put on the brakes. Your reaction time (time elapsed between the moment you see the deer and your foot hitting the brakes) is 0.130 sec. The brakes provide an acceleration with a magnitude of 4.6 m/s2, and a direction opposite the initial velocity.
A) Find the distance (in m) the car travels (at 78.0 km/h) during your reaction time.
B) Calculate the total distance (in m) traveled by the car before stopping.

Answers

(a) The distance  the car travels during your reaction time is 2.83 m.

(b) The total distance traveled by the car before stopping is 97.8 m

What is the distance travelled?

To find the distance traveled during the reaction time, we need to find the velocity after the reaction time and then use it to find the distance traveled.

78 km/h = 78,000 m/h ÷ 3600 s/h = 21.67 m/s

After the reaction time, the velocity is equal to the initial velocity plus the acceleration during the reaction time:

v = v₀ + at

v = 21.67 m/s - (4.6 m/s²)(0.130 s)

v = 21.67 m/s - 0.599 m/s

Finally, the distance traveled during the reaction time is given by:

d = v₀t  + ¹/₂at²

d  = 21.67  x 0.130 s    +    ¹/₂(-4.6) x (0.130)²

d = 2.83 m

B) To find the total distance traveled before stopping, we need to find the time it takes for the velocity to reach 0.

The velocity after the reaction time is equal to 21.67 m/s - 0.599 m/s = 21.07 m/s.

Using the equation v = v₀ + at, we can find the time it takes to come to a stop:

t = -v₀ / a

t = -21.07 / -4.6

t = 4.58 s

The total distance traveled can be found using the equation:

d =  v₀t  + ¹/₂at²

d  = 21.67 x 4.58  + ¹/₂(-4.6) x 4.58

d = 97.8 m

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(Figure 1) is the potential-energy diagram for a 500 g particle that is released from rest at A . What is the particle's speed at B ?

(Figure 1) is the potential-energy diagram for a 500 g particle that is released from rest at A . What

Answers

Answer:

Explanation:

according to the graph at B the potential energy of the particle is 2J

therefore we can use the kinetic energy equation to calculate the particle's velocity or speed.

\(E_{k} =1/2mv^{2}\)

2J= 1/2*1/2kg*v^2

8=v^2

v= 2√2 ms-1

map.
Which best describes the motion of the object
between 1 and 4 seconds?
کے م
The object has decreasing acceleration and
increasing velocity.
The object has positive acceleration and eventually
stops.
The object has decreasing acceleration and
decreasing velocity.
The object has negative acceleration and eventually
stops.

Answers

Answer:

The object has decreasing acceleration and decreasing velocity.

Why in drinking hot water, a thin-bottomed glass is taken?​

Answers

Answer:

beacause it's contracts

Explanation:

when using a large bottomed glass the hot water cools that's why is good to use thin bottomed glass

If the eggs are being thrown with the samevelocity, and the eggs have the same mass,then what else is the same between the twoeggs?

Answers

Both the eggs have the same value of velocity and the same value of mass.

As the momentum of the body in terms of mass and velocity is,

\(p=mv\)

The mass and velocity of both the eggs are the same, thus, the value of momentum for both the eggs is also the same.

The initial kinetic energy of the body is,

\(K=\frac{1}{2}mv^2\)

Thus, the kinetic energy of both the eggs also remains same.

Hence,

How long would it take a machine to do 5.000
joules of work if the power rating of the machine
is 100 watts?
A. 5,000 sec
B.
50 sec
C.
10 sec
D. 0.2 sec




Answer : B

Answers

Answer:

a

Explanation:

How long would it take a machine to do 5.000

joules of work if the power rating of the machine

is 100 watts?

The given machine will take 50 s to complete the work. the power is the rate of performing work.

What is power?

It can be defined as the rate of performing work. It can also be written as the amount of work divided by the time it takes to complete the work.

\(p = \dfrac wt\)

So

\(t = \dfrac w p\)

Where,

\(p\) - power = 100 watt  = 100 J/s

\(t\) - time = ?

\(w\)- work = 5000 J

Put the values in the formula,

\(t = \dfrac{ 5000 \rm \ J} {100 \rm \ J/s}\\\\t = 50 \rm \ s\)

Therefore, the given machine will take 50 s to complete the work.

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A boy on a bicycle approaches a brick wall as he sounds his horn at a frequency of 400 Hz. The sound he hears reflected back from the wall is at a frequency of 408 Hz. At what is the speed is the boy riding his bicycle toward the wall? Assume the speed of sound in air is 340 m/s.

Answers

hope you find this helpful

A boy on a bicycle approaches a brick wall as he sounds his horn at a frequency of 400 Hz. The sound

An object moves 60.0 m [E 75.0° N] and then 50.0 m [E 45.0° S].
a. Determine the object’s total displacement using graphing scaled diagram.
b. Determine the object’s total displacement using component method
Determine the object’s total displacement using sine and cosine law.

Answers

Answer:

An object moves in a straight line along a horizontal surface. so it determined so video with me this movement

Explanation:

the distance from A to B is the displacement i.e

addistion of the x components to addition of y components

summation Y: sin75 * 60 - sin 45 *50 = 15.529

summation X: cos75 *60 + sin 45 *50 =50.884

then

\( \sqrt{x { \: }^{2} + y^{2} } = 76.375\)

along 16° 58' north of easf

An object moves 60.0 m [E 75.0 N] and then 50.0 m [E 45.0 S]. a. Determine the objects total displacement

A car rounds a flat curve of radius R with a speed of . The coefficient of friction between the tires and the road is . For the car not to slide on the road, which of the following statements must be true? (A) The car's speed u cannot be greater than ㎍R (B) The car's speed cannot be less than μgR. (C) The radius R of the car's path cannot be greater than vo lug (D) The radius R of the car's path cannot be less (E) The centripetal acceleration must be less than g.

Answers

The vehicle's speed is  \(\mu g r\)

When the car is in drive, all the forces are in

\(F_N cos\theta =mg + \mu_s\ F_N sin\theta\)

It is a situation in which opposing forces or actions are in equilibrium and can be either static

like when forces act on a body and the resultant is zero or dynamic as in a reversible chemical reaction when the rates of reaction in both directions are equal

The state of equilibrium is one in which the forward and backward rates of response are equal.

equilibrium and harmony the vertical axis equation should be

\(F_N cos\theta +\mu_s F_N cos\theta =\frac{mv^2}{R}\)

and along the horizontal axis,

\(F_N\) = normal force= mg

solving equations 1 and 2 as a pair

\(v^2= \frac{(\mu_s \ cos\theta + sin\theta)Rg}{cos\theta - \mu_s sin \theta}\)

in order to bank \(\theta = 0\)

= \(\mu_s Rg\)

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The switch in the circuit of the figure has been in position "a" for a long time, so the capacitor is fully charged. The switch is changed to position "b" at t = 0. What is the current in the circuit immediately after the switch is closed? What is the current in the circuit 25 µs later?​

The switch in the circuit of the figure has been in position "a" for a long time, so the capacitor is

Answers

The current in the circuit 25 µs later, given that the switch is changed to position "b" is 0.36 A

How do i determine the current in the circuit?

From the question given above, the following data were obtained:

Voltage (V) = 9.0 VCapacitance (C) = 1.0 µF = 1×10⁻⁶ FResistance (R) = 10 Ω Time (t) = 25 µs = 25×10⁻⁶ sCurrent in circuit (I) =?

The current in the circuit can be obtain as illustrated below:

Q = It

But,

Q = CV

Thus,

It = CV

I × 25×10⁻⁶ = 1×10⁻⁶ × 9

I × 25×10⁻⁶ = 9×10⁻⁶

Divide both sides by 25×10⁻⁶

I = 9×10⁻⁶ / 25×10⁻⁶

I = 0.36 A

Thus, from the above calculation, we can conclude that the current in the circuit is 0.36 A

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What is a pendulum?

A.)A pendulum is a grandfather clock.

B.)A pendulum is a mass suspended on the bottom of a string.

C.)A pendulum is several weights tied together and arranged in a circle.

D.) A pendulum is the time it takes for a bob to swing back and forth one time.

Answers

B) A pendulum is a mass suspended on the bottom of a string.

A pendulum is a simple mechanical device that consists of a mass (known as the bob) suspended from a fixed point by a string, wire, or rod. When the bob is pulled to one side and released, it swings back and forth under the influence of gravity, forming a regular pattern of motion. The time it takes for the pendulum to complete one full swing (i.e., from one extreme position to the other and back again) is known as its period. The period of a pendulum is affected by the length of the string and the strength of gravity. The longer the string, the longer the period, and the stronger the gravity, the shorter the period.Pendulums have a wide range of practical applications, such as timekeeping, as seen in grandfather clocks. They are also used in scientific experiments to measure time intervals and gravitational acceleration.

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A fish pond appears to be 1m deep but when vewed vertically above the refractive Index of the Water on the pond is 1.5. calculate the real depth formed​

Answers

Answer:

real depth / apparent depth = R.I.

Real depth = 1.5 x 1 = 1.5 m

Mr. Dunn drives 64.8km from work at a speed of 48km/h. Mrs. Dunn drives 81.2km from work
at a speed of 58km/h. They both leave work at the same time. Show complete working to secure
full credits. [4]
i. Who arrives home first?
ii. How many minutes later is it before the second person gets home?
iii. A Coyote is chasing its meal (the Road Runner). Unfortunately, the Coyote has difficulty
adjusting to the Road Runner’s speed but we have a good idea of what it is.
plz help me i will mark you as brainliest

Answers

Answer:

i) Mr. Dunn arrives to home first.

ii) 3 min

Explanation:

i. To find who arrives first to home you calculate the time, by using the following formula:

\(t=\frac{x}{v}\)

x: distance

v: velocity

Mr. Dunn:

\(t=\frac{64.8km}{48km/h}=1.35h\)

Mrs. Dunn:

\(t=\frac{81.2km}{58km/h}=1.4h\)

Hence, Mr. Dunn arrives to home first.

ii. To calculate the difference in minutes, you convert hours to minutes:

\(1.35h*\frac{60min}{1h}=81min\\\\1.40h*\frac{60min}{1h}=84min\\\\\Delta\ t=(84-81)min=3min\)

the difference between the times is 3min

(i) Mr. Dunn takes less time so he arrives at home first.

(ii) The second person arrives 3 min late.

Time taken to arrive home:

(i) We have to calculate the time taken to reach home by Mr. Dunn and Mrs. Dunn.

t = x/v

where x is the distance

and v is the velocity

Time taken by Mr. Dunn:

distance x = 64.8 km

speed v  = 48 km/h

t = 64.8 / 48

t = 1.35 h

Time taken by Mrs. Dunn:

distance x = 81.2 km

speed v  = 58 km/h

t' = 81.2 / 58

t' = 1.4 h

Hence, Mr. Dunn arrives at home first.

(ii) To calculate the difference in minutes, you convert hours to minutes:

The time taken by Mr. Dunn in minutes is:

t = 1.35×60 = 81 minutes

The time taken by Mrs. Dunn in minutes is:

t' = 1.4×60 = 84 minutes

the difference between the times is 3min

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If the ball rebounds with only half the velocity it comes in with, what is the magnitude of the impulse in kg m/s?

Answers

the magnitude of the impulse in kg m/s is equal to 3/2 times the product of the mass of the ball and its initial velocity.

Lab Report
Light
It’s time to complete your Lab Report. Save the lab to your computer with the correct unit number, lab name, and your name at the end of the file name (e.g., U4_ Lab_Light_Alice_Jones.doc).
Introduction
1. What was the purpose of the experiment?
Type your answer here:
2. What were the independent, dependent, and control variables in your investigation? Describe the variables for each part of the experiment.
Type your answer here:
Experimental Methods
1. What tools did you use to collect your data?
Type your answer here:
2. Describe the procedure that you followed to collect your data.
Type your answer here:
Data and Observations
1. Record your observations in the data tables.
Type your answer here:
Table 1. Angles of Incidence and Angles of Reflection for a Beam of Light Reflected off a Mirror
Angle of incidence (°) Angle of reflection (°)






Table 2. Angles of Incidence and Angles of Refraction for a Beam of Light Refracted through a Glass Lens
Angle of incidence (°) Angle of refraction (°)





Conclusions
1. Draw a diagram (develop a model) that shows what happens to light when it reflects off a mirror. Look for patterns in your data to help you develop your model. Hint: Is the angle of reflection always greater than, less than, or equal to the angle of incidence? Include labels.
Type your answer here:
2. Use your model to predict the angle of reflection of a beam of light reflected off a mirror if the angle of incidence of the beam of light is 40 degrees.
Type your answer here:
3. Draw a diagram (develop a model) that shows what happens to light when it is refracted through a glass lens. Look for patterns in your data to help you develop your model. Hint: Is the angle of refraction always greater than, less than, or equal to the angle of incidence? Include labels.
Type your answer here:

Answers

Answer:

Explanation:

the answer is b

what is the physics behind why electric parallel plates move from positive to negative

Answers

The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.

Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.

What are electric parallel plates?

When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.

The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.

In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.

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Can a charged particle have a net negative charge of 6.4 x 10-19
C? Take the elementary charge (the charge of a single electron) to
be -1.6 x 10 19 C.
No, because the particle has a positive charge.
Yes, because the particle has excess charges.
0/1 pts
No, because the particle has deficiency of charges
(missing electrons)
Yes, because the particle has an integer number of excess
electrons.

Answers

By dividing an object's charge by its basic charge, one can calculate the quantity of extra electrons (or protons, in the case of positive charges), in a system.

What material that has an excess of electrons?When there are lots of free electrons in a material, it is said to have high electron mobility, but when there are few or no free electrons, it is said to have low electron mobility. Here are some typical illustrations of conductors and insulators: Conductors.It indicates that metals contain extra electrons in their outermost shell that are free to move about. These extra electrons act as charge carriers and are physically transferred when a current is running.To convert, multiply the net charge, Q, by the factor 1.6 x 10 x 19 to obtain the charge's value in basic charge units. This is also equivalent to how many extra electrons are present on the thing.

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Hey, I need help can someone help me out, please?

Hey, I need help can someone help me out, please?

Answers

Explanation:

6) newton

7) f =ma = 15*15 = 225N

8) a= 100/20 = 5ms^-2

Answer:

6 newton

7) f =ma = 15*15 = 225N

8) a= 100/20 = 5ms^-2

Explanation:

this is right pls mark as brainliest

Assume you push a 20 kg child in a little red wagon with a force of 100 N. However, the dirt and rocks below the wheels
create a frictional force of 25 N. What is the acceleration on the wagon and child?
A. 1.25 m/s2
B.3.75 m/s2
C. 5 m/s2
D. 0.2 m/s2

Answers

Answer:

a

Explanation:

CONSISTENCY AND CONVERSION F1A 1) Starting with the definition 1 inch = 2.54cm, find the Mur OF (W) Kilometers in 1.00 mile and (b)feet in 1. 00 km [Hint: 1km: 0.621 mile and Im = 3·281 ft)​

Answers

A conversion factor is a ratio that can be used to convert a quantity expressed in one unit of measurement to another unit of measurement.

What is conversion factor?

For example, the conversion factor between meters and feet is given by:

1 meter = 3.281 feet

This means that to convert a quantity expressed in meters to feet, multiply by 3.281. To convert a quantity expressed in feet to meters divide by 3.281.

To convert 1.00 mile to kilometres, the conversion factor is used 1 km = 0.621 miles.

To convert 1.00 km to feet, the conversion factor of 1 km = 3.281 ft

Calculation of the above statement:

This question asks to use the given definition (1 inch = 2.54 cm) to convert the units of measurement of miles and feet to kilometers.

(a) To convert 1.00 mile to kilometres, the conversion factor is used 1 km = 0.621 miles. So, to convert 1.00 mile to kilometers,  multiply 1.00 by 0.621:

So, 1.00 mile is equivalent to 0.621 kilometers.

(b) To convert 1.00 km to feet, use the conversion factor of 1 km = 3.281 ft. So, to convert 1.00 km to feet, multiply 1.00 by 3.281:

So, 1.00 km is equivalent to 3.281 feet.

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During the earthquake, what we need to do to be safe,write steps.
(i) When you are in the classroom.
(ii) When you are out of danger

Answers

During an earthquake, it is important to take appropriate steps to ensure safety

Steps you can follow in two different scenarios

(i) When you are in the classroom

Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.

Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.

Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.

(ii) When you are out of danger:

Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.

Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.

Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.

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How far would you push a car if you did 28,000J of work, exerting a force of 825N?

Answers

We push a car to the distance of 33.939m if we do 28000J work , exerting a force of 825N.

What is work done and force ?work done: The amount of energy transferred to a body .Force : force is an influence that can change the velocity of an object .

How to calculate distance moved from work done and force ?we know ; work done =Force ×distance moved in the direction of force Mathematically, W=F.Swhere W= work done

F = applied force

S = distance moved

So S=W/F

=28000J/825N

=33.939meter

Thus, we can conclude that the distance moved by the car is 33.939m.

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Vincent carrying his luggage with a mass of 10.5kg . If he does 100J of work to what height will raise it?

Answers

The height of the luggage with work done of 100J with a mass of 10.5 kg is 0.97m.

Work done equals the product of force and displacement. The energy that gets transferred by the force to move a object is called work done. Work done is equal to the potential energy of the object.

Work done = potential energy

                   = m×g×h

m is the mass of the luggage = 10.5 kg

g is the acc. due to gravity = 9.8 m/s

W is the work done = 100J

h (height) = W / (m×g)

               = 100 / ( 10.5×9.8)

              = 0.97 m

Thus, the luggage rises above the ground with a height of 0.97 m.

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Which two elements have similar properties and 8 electrons in their outmost shells?

Answers

Answer:

neon and argon

Explanation:

because they are inert gas

3. A change in _____ indicates the acceleration of an object.

Answers

Velocity which indicates the acceleration of a object/thing
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