Answer:
507
Step-by-step explanation:
use the formula A= pi r^2
so you would do 13x13=169 and then multiply by pi which in this case is 3. =507
If v₁ = (3,-4) and v₂ = (2,6), then v₁v₂ is equal to which of the following?
O A. (-12,-24)
OB. 30
O C. -18
OD. (6,-24)
Answer:
C. -18
Step-by-step explanation:
Scalar Product (Dot Product) of two vectors
\(\displaystyle \vec{a} \cdot \vec{b}=\sum_{i=1}^na_ib_i\)
\(\textsf{If }\: \vec{a}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \quad \textsf{and } \quad \vec{b}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k}\)
\(\textsf{then }\quad \vec{a} \cdot \vec{b}=a_1b_1+a_2b_2+a_3b_3\)
Given:
v₁ = (3, -4)v₂ = (2, 6)⇒ v₁ · v₂ = (3 · 2) + (-4 · 6)
⇒ v₁ · v₂ = 6 + (-24)
⇒ v₁ · v₂ = 6 - 24
⇒ v₁ · v₂ = -18
find the missing coordinate of p, using the fact that p lies on the unit circle in the given quadrant. coordinates quadrant p − 2 3 , ii
The missing coordinate of point P is sqrt(5/9). The complete coordinates of P in quadrant II are (-2/3, sqrt(5/9)).
To find the missing coordinate of p, we need to use the fact that p lies on the unit circle in the given quadrant. The coordinates of a point on the unit circle are (cosθ, sinθ), where θ is the angle that the point makes with the positive x-axis.
In this case, we know that p lies in quadrant ii, which means that its x-coordinate is negative and its y-coordinate is positive. We also know that the length of the vector OP, where O is the origin and P is the point on the unit circle, is 1.
Using the Pythagorean theorem, we can write:
(OP)^2 = x^2 + y^2 = 1
Substituting the given coordinates of p, we get:
(-2)^2 + 3^2 = 1
4 + 9 = 1
This is clearly not true, so there must be an error in the given coordinates of p.
Therefore, we cannot find the missing coordinate of p using the given information.
Thus, the missing coordinate of point P is sqrt(5/9). The complete coordinates of P in quadrant II are (-2/3, sqrt(5/9)).
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Given the following proposition:
[(X ⊃ A) • (B ⊃ ∼ Y)] ⊃ [(B ∨ Y) • (A ⊃ X)]
Given that A and B are true and X and Y are false, determine the truth value of Proposition 2A.
a.
True.
b.
False.
Therefore, the truth value of Proposition 2A is False.
To determine the truth value of Proposition 2A, let's substitute the given truth values for the variables:
A = True
B = True
X = False
Y = False
Now let's evaluate the truth value of each component of the proposition:
(X ⊃ A) • (B ⊃ ∼ Y):
(False ⊃ True) • (True ⊃ ∼ False)
(True ⊃ True) • (True ⊃ True)
True • True
True
(B ∨ Y) • (A ⊃ X):
(True ∨ False) • (True ⊃ False)
True • False
False
[(X ⊃ A) • (B ⊃ ∼ Y)] ⊃ [(B ∨ Y) • (A ⊃ X)]:
True ⊃ False
False
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Which of the ratios below has a unit rate of 5?
Answer:
Would you mind including the ratios in the comments?
You didn't post any material to solve.
I NEED HELP ASAP!! I'LL GIVE BRAINLIEST TO THE CORRECT ANSWER!!!
Answer:
7
Step-by-step explanation:
diagnols of a parallelogram bisect each other :)
https://mathschmidt.weebly.com/uploads/6/1/4/6/6146296/parallelograms_extra_practice_blank_and_key.pdf
Answer:
7
Step-by-step explanation:
Joe goes to the store to buy jeans and some T-shirts. The jeans cost
$40 each and the T-shirts cost $20 each. If Joe spends $160 on 5 items,
how many pairs of jeans and how many T-shirts did he buy?
Answer:
Jeans: 3 T-shirts: 2
Step-by-step explanation:
40 times 3 equals 120
20 times 2 equals 40
120+40=160
Joe bought 3 pairs of jeans and 2 T-shirts.
What is the equation?The equation is defined as a mathematical statement that has a minimum of two terms containing variables or numbers that are equal.
Let's represent the number of pairs of jeans that Joe bought "x".
The total cost of the jeans would be $40 × x.
And the total cost of the T-shirts would be $20 × (5 - x).
Since Joe spent a total of $160, we can set up an equation to solve for x:
$40 × x + $20 × (5 - x) = $160
Expanding the second term:
$40 × x + $20 × 5 - $20 × x = $160
Combining like terms:
$40 × x + $100 - $20 × x = $160
Subtracting $100 from both sides:
$40 × x - $20 × x = $60
Combining like terms:
$20 x = $60
Dividing both sides by $20:
x = 3
So he bought 3 pairs of jeans and 5 - 3 = 2 T-shirts.
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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using the equation, what height was the rocket launched from? y=-16x^2+57x+32
9514 1404 393
Answer:
32 feet
Step-by-step explanation:
0 seconds after launch, the rocket is still sitting on the tower. Its height is...
y = -16(0^2) +57(0) +32
y = 0 + 0 + 32 = 32
The rocket was launched from a tower 32 feet high.
Find the remainder in the Taylor series centered at the point a for the following function. Then show that lim_n rightarrow infinity|R_n(x)| = 0 for tor all x in the interval of convergence. f(x) = e^-x, a = 0 First find a formula for f^n(x). f^n(x) = (Type an exact answer.)
The remainder in the Taylor series centered at a=0 for the function f(x) = e^(-x) is R_n(x) = (x^n / n!) * e^(-c), where c is some value between 0 and x. The limit as n approaches infinity of the absolute value of R_n(x) is 0 for all x in the interval of convergence.
The Taylor series expansion for the function f(x) = e^(-x) centered at a=0 is given by:
f(x) = f(0) + f'(0)*x + (f''(0)/2!)*x^2 + (f'''(0)/3!)*x^3 + ... + (f^n(0)/n!)*x^n + R_n(x)
To find a formula for f^n(x), we differentiate f(x) repeatedly n times. Starting with the original function f(x) = e^(-x):
f'(x) = -e^(-x)
f''(x) = e^(-x)
f'''(x) = -e^(-x)
f''''(x) = e^(-x)
We can observe that the nth derivative alternates between positive and negative powers of e^(-x) for all n.
By evaluating the nth derivative at a=0, we can find f^n(0):
f(0) = e^0 = 1
f'(0) = -e^0 = -1
f''(0) = e^0 = 1
f'''(0) = -e^0 = -1
...
We can see that f^n(0) = (-1)^(n+1) for all n.
Substituting f^n(0) into the Taylor series expansion, we get:
f(x) = 1 + (-1)*x + (1/2!)*x^2 + (-1/3!)*x^3 + ... + ((-1)^(n+1)/n!)*x^n + R_n(x)
The remainder term R_n(x) is given by:
R_n(x) = (f^(n+1)(c)/n!)*x^(n+1), where c is some value between 0 and x.
Taking the absolute value of R_n(x):
|R_n(x)| = |(f^(n+1)(c)/n!)*x^(n+1)| = |(-1)^(n+2)/n! * x^(n+1)| = |(-1)^(n+2)|/n! * |x|^(n+1) = 1/n! * |x|^(n+1)
As n approaches infinity, the term 1/n! converges to 0, and |x|^(n+1) also converges to 0 when |x| < 1. Therefore, the limit as n approaches infinity of |R_n(x)| is 0 for all x in the interval of convergence.
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why do bank charge transaction fees ?
Answer:
To make a profit of course
Step-by-step explanation:
it
then
yes
Possibly.
From a table of integrals, we know that for ,≠0a,b≠0,
∫cos()=⋅cos()+sin()2+2+.∫eatcos(bt)dt=eat⋅acos(bt)+bsin(bt)a2+b2+C.
Use this antiderivative to compute the following improper integral:
∫[infinity]01cos(3)− = limT→[infinity]∫0[infinity]e1tcos(3t)e−stdt = limT→[infinity] if ≠1s≠1
or
∫[infinity]01cos(3)− = limT→[infinity]∫0[infinity]e1tcos(3t)e−stdt = limT→[infinity] if =1.s=1. help (formulas)
For which values of s do the limits above exist? In other words, what is the domain of the Laplace transform of 1cos(3)e1tcos(3t)?
help (inequalities)
Evaluate the existing limit to compute the Laplace transform of 1cos(3)e1tcos(3t) on the domain you determined in the previous part:
()=L{e^1t cos(3)}=
"From a table of integrals, we know that for \(\(a \neq 0\)\) and \(\(b \neq 0\):\)
\(\[\int \cos(at) \, dt = \frac{1}{a} \cdot \cos(at) + \frac{1}{b} \cdot \sin(bt) + C\]\)
and
\(\[\int e^a t \cos(bt) \, dt = \frac{e^{at}}{a} \cdot \cos(bt) + \frac{b}{a^2 + b^2} \cdot \sin(bt) + C\]\)
Use this antiderivative to compute the following improper integral:
\(\[\int_{-\infty}^{0} \cos(3t) \, dt = \lim_{{T \to \infty}} \int_{0}^{T} e^t \cos(3t) \, e^{-st} \, dt = \lim_{{T \to \infty}} \text{ if } s \neq 1, \, \text{ or } \lim_{{T \to \infty}} \text{ if } s = 1.\]\)
For which values of \(\(s\)\) do the limits above exist? In other words, what is the domain of the Laplace transform of \(\(\frac{1}{\cos(3)} \cdot e^t \cos(3t)\)\)?
Evaluate the existing limit to compute the Laplace transform of on the domain you determined in the previous part:
\(\[L\{e^t \cos(3t)\\).
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The expression (x^22) (x^7)^3 is equivalent to x^p. What is the value of p?
Answer:
x^87
Step-by-step explanation:
Multiplying x^22 and x^7 results in x^29.
Then we have:
(x^29)^3 = x^87
Recall that (a^b)^c = a^(bc) and that a^b*a^c = a^(b + c)
Which other figure is a part of ray AB? CHOICES: BA (ray) AB (line) AB (line segment)
The figure that is part of ray AB is BA (ray). It represents the portion of the line that extends infinitely in the direction from point B towards point A.
Among the given choices, the figure that is a part of ray AB is BA (ray).
In geometry, a ray is a part of a line that has one endpoint and extends infinitely in one direction.
In this case, the ray AB would start at point A and extend infinitely in the direction of point B.
Similarly, the ray BA would start at point B and extend infinitely in the direction of point A.
So, the figure that is part of ray AB is BA (ray). It represents the portion of the line that extends infinitely in the direction from point B towards point A.
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Determine whether the event is impossible, unlikely, as likely as not, likely, or certain.
you roll two fair number cubes and get a total of 14.
help please!
So, based on the available outcomes and the sum of the numbers on two dice, the event of rolling two fair number cubes and getting a total of 14 is impossible.
To determine the likelihood of rolling two fair number cubes and getting a total of 14, we need to consider the possible outcomes. When rolling two number cubes, the minimum possible sum is 2 (when both cubes show a 1), and the maximum possible sum is 12 (when both cubes show a 6). Since the maximum possible sum is 12 and we need a sum of 14, it is impossible to roll two fair number cubes and get a total of 14.
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I need help with this asap please !! find the value of X
Answer:
x = 11
Step-by-step explanation:
By using angle bisector theorem,
"Bisector of an angle divides the opposite side of the angle into two segments such that they are proportional to the other two sides.
\(\frac{AC}{CD}= \frac{AB}{BD}\)
\(\frac{8}{4}=\frac{x+3}{x-4}\)
8(x - 4) = 4(x + 3)
8x - 32 = 4x + 12
8x - 4x = 32 + 12
4x = 44
x = 11
Therefore, value of x is 11.
Oliver is performing an experiment by spinning a metal weight around on the end of a nylon thread. How far does the metal weight travel if it
completes 10 revolutions on the end of a 0.88 m thread?
Give your answer correct to one decimal place.
Answer:
27.7m
Step-by-step explanation:
Step 1
We find the Circumference of the nylon thread.
The formula = 2πr
The diameter of the thread = 0.88m
Radius = Diameter/2
= 0.88m/2
= 0.44m
Circumference = 2 × π × 0.44m
= 2.7646015352m
Approximately = 2.765m
Step 2
We calculate the distance
Number of revolutions = 10
Therefore, the Distance or how far the metal weight can travel =
Circumference of the wheel × Number of revolutions
= 2.765m × 10
= 27.65m
Approximately to 1 decimal place = 27.7m
Find the value of each variable
The missing sides of the special right triangles are listed below:
Case 1: y = √2 · 13, x = 13
Case 2: x = y = 15√2
Case 3: x = 6, y = 3√3
Case 4: x = 17√3, y = 17
Case 5: x = y = 10
Case 6: x = 50, y = 25
Case 7: x = y = 4√7
Case 8: x = 16√3, y = 8√3
Case 9: x = 11√3, y = 33
Case 10: x = 3√2, y = 2√6
Case 11: x = √10, y = 2√5
Case 12: x = 4√7, y = 8√21
How to find the length of missing sides
Herein we find twelve cases of special right triangles whose missing sides must be determined by using the following rules:
45 - 90 - 45 Right triangle
r = √2 · x = √2 · y
30 - 60 - 90 Right triangle
x = (1 / 2) · r
y = (√3 / 2) · r = √3 · x
Where:
x - Shortest leg.y - Longest leg. r - Hypotenuse.Case 1
y = √2 · 13
x = 13
Case 2
x = y = 15√2
Case 3
x = 3 / (1 / 2)
x = 6
y = 3√3
Case 4
x = 34 · (√3 / 2)
x = 17√3
y = 34 · (1 / 2)
y = 17
Case 5
x = y = 10
Case 6
x = 25√3 / (√3 / 2)
x = 50
y = 25√3 / √3
y = 25
Case 7
x = y = 2√14 · √2 = 2√28 = 4√7
Case 8
x = 24 / (√3 / 2)
x = 48 / √3
x = 16√3
y = 24 / √3
y = 8√3
Case 9
x = 22√3 · (1 / 2)
x = 11√3
y = 22√3 · (√3 / 2)
y = 33
Case 10
x = √18
x = 3√2
y = √6 / (1 / 2)
y = 2√6
Case 11
x = √10
y = √20
y = 2√5
Case 12
x = 4√21 / √3
x = 4√7
y = 4√21 / (1 / 2)
y = 8√21
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t/f: a structure chart should be more horizontal and less vertical because the main function should make a majority of the user- defined function calls.
true
false
The given statement "a structure chart should be more horizontal and less vertical because the main function should make a majority of the user- defined function calls" is FALSE because it should not necessarily be more horizontal and less vertical.
The orientation and structure of a structure chart depends on the specific requirements and characteristics of the system being modeled.
The purpose of a structure chart is to visually represent the components of a system and the relationships between them, not to follow a specific format or layout. The most important consideration when creating a structure chart is to accurately depict the system's functionality and structure in a clear and understandable way.
Therefore, the orientation of a structure chart should be chosen based on the system's needs rather than any arbitrary rules or guidelines.
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what is x? please help
Answer:
29
Step-by-step explanation:
This is a right triangle because it has the small square in the corner.
And when you have a right triangle the angle with the square in it is ALWAYS going to be 90 degrees.
It gave you one of the angle measurements which is 61.
90+61=151
And When you add all the angle measurements of a triangle it will ALWAYS be a total of 180 no matter what kind of triangle it is.
To find "x" you subtract the sum of the two angles you you know from 180.
180-151=29
At yesterday's ball game, 2,842 tickets were sold. The price of each ticket was 7.50. Which amount is closest to the total amount of money received from the ticket sales yesterday's ball game.
Answer
21315
Step-by-step explanation:
If a wheelchair-marathon racer moving at 13.1 miles per hour expends energy at a rate of 645 calories per hour, how much energy in calories would be required to complete a marathon race (26.2 miles) at this pace
Answer:
\(1290\) calories
Step-by-step explanation:
Given: The racer moves at \(13.1\) miles per hour expends energy at a rate of \(645\) calories per hour.
To find: Energy in calories, required to complete a marathon race \(26.2\) miles at this pace.
Solution: We have,
The racer moves at \(13.1\) miles per hour.
The racer expends energy at a rate of \(645\) calories per hour.
So, energy expended while moving \(13.1\) miles \(=645\) calories.
Now, energy expended while moving \(1\) mile \(=\frac{645}{13.1}\) calories.
So, energy expended while moving \(26.2\) miles \(=\frac{645}{13.1}\times 26.2=645\times 2=1290\) calories.
Hence, \(1290\) calories of energy is required to complete a marathon race \(26.2\) miles at this pace.
The wheelchair-marathon racer would need 1290 calories to complete the marathon race.
SpeedSpeed is the ratio of distance travelled to total time taken. It is given by:
Speed = distance / time
The speed of the racer is 13.1 miles per hour. To complete a 26.2 miles:
13.1 = 26.2 / t
t = 2 hours.
The racer expends energy at a rate of 645 calories per hour, for 2 hours:
Amount of calories = 645 calories per hour * 2 hours = 1290 calories
The wheelchair-marathon racer would need 1290 calories to complete the marathon race.
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A sequence is defined recursively. find the first seven terms of the sequence. =−1 2−2, 1=1, 2=3 1 =1 2 = 3
A sequence is (recursively) defined as a1 = 0, a2 = 1, n>2, \(a_n = a_{n-1} - 3a_{n-2}\). The first seven terms are 0, 1, 1, -2, -5, 1, 16.
A recursive sequence is a sequence in which terms are defined using one or more previous terms which are given.
a1 = 0
a2 = 1
\(a_n = a_{n-1} - 3a_{n-2}\)
a3 = a2 - 3*a1 = 1 - 0 = 1
a4 = a3 - 3*a2 = 1 - 3 = -2
a5 = a4 - 3*a3 = -2 - 3 = -5
a6 = a5 - 3*a4 = -5 + 6 = 1
a7 = a6 - 3*a5 = 1 +15 = 16
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Use the display of data items to find the mean, median, mode, and midrange.
Stems
Leaves
4
6 2 8
7 6 6 5
9
0 7
The mean of the data is _ (Round to the nearest tenth as needed.)
The median of the data is D. (Round to the nearest tenth as needed.)
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
O A. The mode is of the data is
(Use comma to separate answers as needed.)
• B. There is no is mode for the given data.
The midrange of the data is . (Round to the nearest tenth as needed.)
The mean is the sum of all the values divided by the total number of values. In this case, the mean is 6.8. This tells us that on average, the data points are close to 6.8.
The mean, median, mode, and +midrange are all measures of central tendency in a set of data. The mean is the sum of all the values divided by the total number of values. In this case, the mean is 6.8. This tells us that on average, the data points are close to 6.8.
The median is the middle value when the data is arranged in order. If there are an even number of values, we take the average of the two middle values. In this case, the median is 6.5, which means that half of the data points are below 6.5 and half are above.
The mode is the value that appears most frequently in the data set. In this case, the mode is 6, which tells us that 6 is a common value in the data set.
The midrange is the average of the smallest and largest values in the data set. In this case, the midrange is 6.5, which gives us an idea of the range of values in the data set.
Overall, these measures of central tendency give us a good understanding of the distribution of values in a data set and can help us make informed decisions based on that data.The mean, median, mode, and midrange are all measures of central tendency in a set of data. The mean is the sum of all the values divided by the total number of values. In this case, the mean is 6.8. This tells us that on average, the data points are close to 6.8.
The median is the middle value when the data is arranged in order. If there are an even number of values, we take the average of the two middle values. In this case, the median is 6.5, which means that half of the data points are below 6.5 and half are above.
The mode is the value that appears most frequently in the data set. In this case, the mode is 6, which tells us that 6 is a common value in the data set.
The midrange is the average of the smallest and largest values in the data set. In this case, the midrange is 6.5, which gives us an idea of the range of values in the data set.
Overall, these measures of central tendency give us a good understanding of the distribution of values in a data set and can help us make informed decisions based on that data.he mean, median, mode, and midrange are all measures of central tendency in a set of data. The mean is the sum of all the values divided by the total number of values. In this case, the mean is 6.8. This tells us that on average, the data points are close to 6.8.
The median is the middle value when the data is arranged in order. If there are an even number of values, we take the average of the two middle values. In this case, the median is 6.5, which means that half of the data points are below 6.5 and half are above.
The mode is the value that appears most frequently in the data set. In this case, the mode is 6, which tells us that 6 is a common value in the data set.
The midrange is the average of the smallest and largest values in the data set. In this case, the midrange is 6.5, which gives us an idea of the range of values in the data set.
Overall, these measures of central tendency give us a good understanding of the distribution of values in a data set and can help us make informed decisions based on that data.
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mckenna ears money eat time she shovels snow for her neghbors
Sorry, what is the question? OwO
What is the multiplicative rate of change for the exponential function f(x) = f start bracket x end bracket equals two start bracket five-halves end bracket superscript negative x?
0.4
0.6
1.5
2.5\
The multiplicative rate of change for the exponential function f(x) = 2(−5/2x) is 0.4.
What is function?Function is the process or state of instruction that text inputs performance is specific tax and produce an output functional key components of programming language allowing the quarters to create complex commands with simple instruction for example a function can be used to add two numbers round together or to generate a random number function can also be combined to create more complex sequence of instruction.
This rate of change is calculated by taking the derivative of the exponential function. This derivative is f'(x) = (−2.5)2(−5/2x). To find the rate of change, the derivative is evaluated at x = 0, resulting in f'(0) = (−2.5)2(−5/2x). This evaluates to 0.4, which is the multiplicative rate of change for the exponential function.
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Determine if the following system of equations has no solutions, infinitely many
solutions or exactly one solution.
2x + y = -1
8x + 3y = -2
Answer:
There is one solution
Step-by-step explanation:
2x + y = -1
8x + 3y = -2
Multiply the first equation by -4
-8x -4y = 4
Then add the equations together to eliminate x
-8x -4y = 4
8x + 3y = -2
--------------------
-y = 2
Multiply by -1
y =-2
Now find x
2x+y =-1
2x+-2 =-1
Add 2 to each side
2x-2+2=-1+2
2x=1
Divide by 2
x = 1/2
let f and g be differentiable functions for which the following information is known: f(2) = 5, g(2) = 3, f′(2) = 1 2, g′(2) = 2. let h be the new function defined by the rule h(x) = 3f(x) −4g(x).
The value of h(x) at x = 2 is 3.
Given that f(x) and g(x) are differentiable functions with f(2) = 5, g(2) = 3, f′(2) = 1/2, and g′(2) = 2, and the new function h(x) is defined as h(x) = 3f(x) − 4g(x), we can find h'(2) by using the derivative rules for sums and products:
h'(x) = 3f'(x) - 4g'(x)
By plugging in the given values for f'(2) and g'(2), we get:
h'(2) = 3(1/2) - 4(2) = 3/2 - 8 = -6.5
Therefore, the derivative of h(x) at x = 2 is -6.5.
To find h(2), we can plug in the given values for f(2) and g(2) into the equation for h(x):
h(2) = 3f(2) - 4g(2) = 3(5) - 4(3) = 15 - 12 = 3
In conclusion, the derivative of h(x) at x = 2 is -6.5 and the value of h(x) at x = 2 is 3.
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Geri is looking for different ways to write the number 64 using exponents. Consider the expressions below.
Select either True next to an expression if it has a value of 64 or False if it does not.
Value of 64? True False
2^4 x 2^2 O O
6^4 O O
2^8 O O
4^3×4^1 O O
8^2 O O
4^3 O O
Copy the text above this and put a x through the O if it is true or false
The expressions 2⁴x 2², 8² and 4³ are the exponential expressions of 64.
What is Number system?A number system is defined as a system of writing to express numbers.
We have to find the different ways to write the number 64 using exponents.
The given expressions are 2⁴x 2²
16×4=64
So the expression 2⁴x 2² is true.
Now 6⁴=1296 which is not equal to 64.
So 6⁴ is a false expression.
2⁸=256 but not 64
So 2⁸ is a false expression.
4³×4¹=64×4
=256 not 64 so the 4³×4¹ is false.
8²=64 is true
4³=64 is true
Hence, the expressions 2⁴x 2², 8² and 4³ are the exponential expressions of 64.
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How do I write the polynomial -10xy^5+2x^3y^2-6x^2y^2 in standard form??
Will give brainliest if you provide the steps and answer
Answer:
-8xy^5-6xy^4
Step-by-step explanation:
-10xy^5+(2x^3)(y^2)-(6x^2)(y^2)
-10xy^5+2xy^5 -6xy^4
-8xy^5-6xy^4
This should be good but if your teacher requires it just put 0 with the exponent in descending order
Answer:
Answering on an Alt account to give brainliest :p
Step-by-step explanation:
Image attached - thanks for helping!
Answer:
Ans = (1.50 x 29 movies) + 16
Step-by-step explanation:
y represents total costs
x represents how many movie he rents
$1.50 is the rent of each movie
$16 is the fixed fee
thus
y = 1.50 x + 16
Ans = (1.50 x 29 movies) + 16
Which type of graph is most appropriate for graphing heart rate data over the time period of 120 seconds?.
The most appropriate type of graph for graphing heart rate data over the time period of 120 seconds would be a line graph or a scatter plot.
A line graph is useful when we want to show the trend or changes in a variable over time. It would allow us to plot the heart rate on the y-axis and the time on the x-axis, connecting the data points with a line to represent the change in heart rate over the 120-second period.
A scatter plot can also be used to display heart rate data over time. In a scatter plot, each data point represents a heart rate measurement at a specific time point. By plotting the heart rate on the y-axis and the time on the x-axis, we can observe the distribution of the data points and any potential patterns or trends.
Ultimately, the choice between a line graph and a scatter plot depends on the specific nature of the data and the purpose of the graph. If the heart rate data is continuous and measured at regular intervals, a line graph would be a suitable choice. If the heart rate data is more discrete or irregularly measured, a scatter plot would be more appropriate.
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