find molarity of 0.38 l of solution made with 0.12 moles of ca(no3)2

Answer:

\(v_{solute}=25mL\)

Explanation:

Hello there!

In this case, according to the by-volume concentration of this solution, it is possible for us to use its mathematical definition as shown below:

\(\%v=\frac{v_{solute}}{v_{solution}}*100\%\)

Thus, given the percent and the volume of the solution, we can solve for the volume of ethanol (solute) as shown below:

\(v_{solute}=\frac{\%v*v_{solution}}{100\% }\\\\v_{solute}=\frac{5.00\%*500mL}{100\%}\\\\ v_{solute}=25mL\)

Best regards!

Answer:

Explanation:

B is the ans

pls mark BRAINLIEST

The expression relating the concentration of a gas in \(\mu g/m^-^3 (X)\) with the concentration expressed in ppm (Y) is \(Y = (X/MW) * 10^6 / V\)

To derive an expression relating the concentration of a gas in \(\mu g/m^3 (X)\) with the concentration expressed in ppm (Y), we can use the ideal gas law. The ideal gas law states that \(PV = nRT\), where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Rearranging the equation, we have \(n = PV/RT\)

To convert the concentration from \(\mu g/m^-^3 (X)\) to moles (n), we divide X by the molecular weight (MW) of the gas. Thus, \(n = X/MW\)

Combining the two equations, we have \(X/MW = PV/RT\)

Since the concentration expressed in ppm (Y) is the same as the number of moles per million parts of air, we can write \(Y = n * 10^6 / V\)

Substituting \(n = X/MW\), we get \(Y = (X/MW) * 10^6 / V\)

Therefore, the expression relating the concentration of a gas in \(\mu g/m^3 (X)\) with the concentration expressed in ppm (Y) is:

\(Y = (X/MW) * 10^6 / V\)

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Complete question is:

Using the ideal Gas Law, derive an expression relating the concentration of a gas \(\mu_g^-^3 (X)\) with the concentration expressed in ppm (Y). (10 pts) Hint:- Ideal gas law \(PV= nRt -R = 0.0821 atm mol^-^1\)  −MW=X= molecular weight

Answer:

I can i have done this before

Explanation:

hope this helps

may i get braineist

btw im in 5th grade too  i have the same worksheets i can help if your behind. i got an 100% on this

There are approximately 38.4 moles of water in the cylindrical glass.

To determine the number of moles of water in the cylindrical glass, we first need to calculate the volume of water in the glass. We can use the formula for the volume of a cylinder:

V = πr^2h
Where V is the volume, π is a constant (3.14), r is the radius, and h is the height.
Plugging in the given values, we get:
V = π(4.67 cm)^2(10.1 cm) = 3.14 * 4.67 cm * 4.67 cm * 10.1 cm
V = 691.6474 cm^3

Next, we can use the density of water to find the mass of the water in the glass. Density is defined as mass per unit volume, so we can rearrange the formula to solve for mass:
density = mass/volume
m = density x volume

Plugging in the density of water (1.00 g/cm^3) and the volume we just calculated, we get:

m = 1.00 g/cm^3 x 691.6474 cm^3
m = 691.6474 g

Finally, we can use the molar mass of water to convert the mass of water to moles of water. The molar mass of water is 18.015 g/mol.

moles of water = mass of water / molar mass of water
moles of water = 691.6474 g / 18.015 g/mol
moles of water = 38.39 mol ≈ 38.4 mol

Therefore, there are approximately 38.4 moles of water in the cylindrical glass.

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Answer: All cells are made from the same major classes of organic molecules: nucleic acids, proteins, carbohydrates, and lipids.

Explanation: please mark as brainliest

Na+ will become smaller when compared to the Na atom since the cations of a specific element have smaller radii than the neutral atom.

So because 3s1 electron has indeed been removed to create a closed circle with n = 2, the Na+ ion is considerably smaller than that of the neutral Na atom.

Since the outer electrons, which are located the farthest from of the nucleus, are lost, cations were smaller than that of the comparable neutral atoms.The diameter of the ion is further lowered as more electrons are removed from the cation.

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Answer:

answer in the picture hi shirllleeyyyyy

In this question, we have:

31.1 grams of O2

84.3 grams of F2

94.9 L of total volume

55.77°C of temperature which is equal to 328.92 K

Now, to find the pressure of this container, we can find the number of moles of each gas, and add both values together making it one value of moles and then we will use the Ideal gas law to find the pressure, so let's start with O2

The molar mass of O2 is 32g/mol and we have 31.1 grams

32g = 1 mol

31.1g = x moles

x = 0.972 moles of O2

Now for F2, the molar mass is 38g/mol, and we have 84.3 grams

38g = 1 mol

84.3g = x moles

x = 2.22 moles of F2

Now we add these values, 0.972 + 2.22 = 3.192 moles

And now we can use the ideal gas law formula:

PV = nRT

Remember that R is the gas constant, 0.082

P * 94.9 L = 3.192 * 0.082 * 328.92

94.9P = 86.1

P = 0.91 atm

Answer:

I think D

Explanation:

it has both H and G in the planes.

Answer:

Plants wilt when the turgor turns to zero. From diminished water in cells. The rate of water being lost is greater then the water being absorbed.

Something like this. NOT EXACTLY THIS this is just an example.

I didn't know anything about this topic but I looked it up. For the other words I would look up the other words and see what they have to do with plants withering.

Strong nucleophile, good leaving group, polar aprotic solvent, methyl or primary halide. The correct answer is option: b.

In an SN2 reaction, a nucleophile attacks the carbon atom to which the leaving group is attached, while the leaving group departs from the molecule. The reaction proceeds in a single step, with the nucleophile and leaving group involved in the transition state. A strong nucleophile is required to attack the carbon atom, and a good leaving group is necessary to depart from the molecule. Methyl or primary halides are preferred substrates because they are less hindered, making the attack by the nucleophile easier. Option b is correct.

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C. slight opposite charges

Explanation: opposites attract

Water molecules able to weakly bond to one another with hydrogen bonds because of hydrogen and oxygen poles having slight opposite charges. Option C is correct.

Water molecules are polar, meaning they have regions with different electrical charges. Oxygen is more electronegative than hydrogen, so it pulls the shared electrons in the covalent bonds towards itself, creating a partial negative charge (δ⁻) near the oxygen atom and a partial positive charge (δ⁺) near the hydrogen atoms.

This charge separation gives rise to a weak electrostatic attraction between the δ⁺ hydrogen of one water molecule and the δ⁻ oxygen of another, forming a hydrogen bond. This bond is not as strong as covalent bonds but contributes to the cohesive and adhesive properties of water, allowing it to form a network of interconnected molecules and exhibit characteristics like high surface tension, capillary action, and high heat capacity.

Hence, C. is the correct option.

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Answer: I would make a conclusion or an inference on the information that is given.

Explanation: As readers, we may need to find out what caused a disaster to occur or why a character feels a certain way; identifying the cause and the effect help us to do that. It is important to recognize these relationships because they can help readers draw conclusions and make inferences.

The moles would be 12 moles, 4 moles and 11.34 moles

When hydrogen gas (H2) reacts with oxygen gas (O2) to produce water (H2O), the balanced chemical equation is:

2H2 + O2 -> 2H2O

So,

For every 6 moles of H2, 12 moles of H2O will be produced

For every 2 moles of H2, 4 moles of H2O will be produced

For every 5.67 moles of H2, 11.34 moles of H2O will be produced.

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Answer:

B . The release of solar energy from the reactants increase the energy level of the products giving gulcose a higher potential energy compared to the carbon dioxide.

Answer:  No! I just did this question and I got it wrong... the correct answer is "The input of solar energy converts the reactants into products, giving glucose a higher potential energy compared to the carbon dioxide."

Explanation:

Solar energy is an input, not a release in photosynthesis. Glucose has a higher energy than carbon dioxide. This is why glucose can be used by the cell for energy.

Answer:

they have two valence electrons

Explanation:

They readily give up their two valence electrons to achieve a full outer energy level, which is the most stable arrangement of electrons

Answer:

carbon dioxide

it is made up of carbon and oxygen.

burning of wood logs and paper. food digestion. egg being boiled. utilisation of chemical batteries. metal electroplating cake baking milk turning bad. Multiple metabolic processes take place inside cells.

A few examples of chemical changes include the production of carbon dioxide by baking soda and vinegar, iron rusting, and wood burning. Among the numerous chemical reactions that the body performs are the metabolization of meals and the creation of amylase from the blending of sugar and saliva.

Chemical transformations are also referred to as chemical reactions. Our lives are significantly impacted by chemical changes. Each new compound is created as a result of chemical reactions. As an illustration, a series of chemical changes result in food digestion in human bodies, fruit ripening, grape fermentation, etc..

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Explanation:The scientific inquiry process is the process in which scientists or researchers find an explanation for any natural world phenomena with logic and evidence collected by the systemic method or work. The scientific inquiry process begins with a question or thinking (observation) for any natural phenomena like why freshwater has low albedo where ice has a high albedo percentage.

Answer:

The cycle of prototyping, testing, and refining that's at the core of iterative design offers numerous benefits: Testing gives you a valuable collection of user feedback that you can use to improve your site and to understand what's working for you. It helps you catch problems before they spiral out of control.

Iteration assists you in detecting problems before they go out of control.

Iteration is a design technique that revolves around a cyclical process of developing, testing, evaluating, and refining a product or process. Changes and adjustments are made based on the outcomes of testing the most current version of a concept.

Iteration, or the cycle of prototyping, testing, and refining that is at the heart of iterative design, has multiple advantages. Testing provides you with a valuable collection of user input that you can use to develop your site and understand what works for you.

Hence, Iteration assists you in detecting problems before they go out of control.

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Given the equilibrium constant (K) of 1.600 at 570.00 K for the reaction A(g) + B(g) = C(g) + D(g), the extent of reaction (e) at equilibrium can be calculated. The extent of reaction is found to be 2.310 mol. The equilibrium mole fractions are YA = 0.487, YB = 0.513, YC = 0.113, and YD = 0.113.

At equilibrium, the reaction quotient Q is equal to the equilibrium constant K. The equilibrium constant is defined as K = (YC * YD) / (YA * YB), where Y represents the molar fraction of each gas species.

Given the initial moles of A and B as 4.200 and 4.700, respectively, and no C or D initially, we can calculate the initial molar fractions:

YA = 4.200 / (4.200 + 4.700) = 0.487

YB = 4.700 / (4.200 + 4.700) = 0.513

Since the equilibrium constant K is given as 1.600, we can rearrange the equation to solve for the extent of reaction (e):

e = YA_initial - (YA_initial / (K * YB))

Substituting the known values, we get:

e = 4.200 - (4.200 / (1.600 * 0.513)) ≈ 2.310 mol

To determine the equilibrium mole fractions, we can use the equation:

YC = YA * YB / (YD * K)

Since YA = YB, we can simplify it further:

YC = YA^2 / (YD * K)

Substituting the known values, we find:

YC = 0.487^2 / (0.113 * 1.600) ≈ 0.113

Similarly, YD = YC.

Thus, the equilibrium mole fractions are:

YA = 0.487

YB = 0.513

YC = 0.113

YD = 0.113

These values represent the composition of the gas mixture at equilibrium, with A and B having higher mole fractions than C and D.

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Answer:

Al₂O₃

Explanation:

When writing the correct compound, you need to take the charges of both ions into account.

Aluminum (Al) has an ionic charge of +3.

Oxygen (O) has an ionic charge of -2.

The ionic compound should have an overall charge of 0 (neutral). Evidently, the charges of the ions don't balance out if you were to form a compound with just one aluminum and one oxygen (making an overall charge of +3 - 2 = +1).

To fix this, make the charge of each ion the subscript of the other element.

This makes the compound:

Al₂O₃

Now, the aluminum is contributing +6 (2 x +3 = +6) and oxygen is contributing -6 (3 x -2 = -6). This balanced the compound and results in an ionic compound with no overall charge.

The concentrations of the reaction's reactants and products must be equal at equilibrium. Following is a description of how CO and H2O react to generate CO2 and H2: CO + H2O <=> CO2 + H2 We can determine the equilibrium CO and H2O concentrations using the available data.

The starting concentrations of CO and H2O are 0.800 M and 0.800 M, respectively, due to the total moles of CO and H2O being 2.00 moles and the total volume being 2.50 L. The equilibrium expression may be used to compute the equilibrium concentrations of CO and H2O: K = [CO2][H2]/[CO][H2O] K = (0.00775)(0.00775)/[CO] may be used to derive the equilibrium constant given that [CO2] and [H2] are both equal to 0.00775 M.

[H2O] K = (0.00775)(0.00775)/[0.0455], when the equilibrium concentrations of CO and H2O are plugged in.[0.0455]. ][0.0455] K = 0.0020 From this, we can calculate the equilibrium concentrations of CO and H2O: [CO] = 0.0455 M [H2O] = 0.0455 M .

The standard free energy change (G°), which can be calculated using the formula G° = -RTlnK, may be used to estimate the sign of G for this reaction. Since K > 1, we may anticipate a spontaneous response, meaning that G will be negative.

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The characteristics of the graphs we can find the answer on how to draw the graph

The graphical representation is one of the best methods to visualize the relationships between a series of experimental data and to be able to find their functional relationships.

A graphic representation has several parts

The scales are found with the relationship between the variation of the data between the amount of paper or graph range, let's look for the scales for each axis.

x-axis

The variation of the data  Δx = Final value - initial value

Paper range, generally it is  x = 20cm (sheet size)

They indicate that the graph must start at zero, so the minimum value must be changed,

             initial value = 0

              Δx = 760 -0 = 760

             x scale  = 760/20

             x scale  = 38 mb / cm of paper

y-axis

Data range   Δy= 0.9 -0

Paper range  y= 20 cm (sheet size)

            y-scale  = 0.9 / 20

            y scale  = 0.045 mL / cm paper

One of the characteristics of the scale is that it must be comfortable for graphing, which is why it approximates the following units

Selected scales  

         x scale  = 40 mb / cm paper

         y scale = 0.05 mL / cm paper

The second part consists of marking values ​​equally spaced and facilitating readable in the two axes, see attached for a graph made in a computer program

Plot each experimental point as best as possible, there are always some approximations by the selected scales

Draw a curve that passes through most of the experimental points and those that remain outside are balanced above and below the curve, in this case the program draws a line between each point, but it is preferable to draw a smooth curve.

In conclusion with the characteristics of the graphs we can find the answer on how to draw the graph

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The enthalpy change of the reaction of decane would be -6582.3 kJ/mol of decane.

The enthalpy change of a reaction can be calculated using the following equation:

ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)

We are given the standard molar enthalpy of formation of n-decane, C10H22, which is -249.4 kJ/mol.

Using the balanced chemical equation, we can identify the stoichiometric coefficients of the reactants and products:

C10H22(I) + 12.5O2(g) --> 10CO2(g) + 11H2O(g)

Reactants:

n(C10H22) = 1

n(O2) = 12.5

Products:

n(CO2) = 10

n(H2O) = 11

Now we can calculate the enthalpy change of the reaction:

ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)

ΔH = [10(-393.5 kJ/mol) + 11(-241.8 kJ/mol)] - [1(-249.4 kJ/mol) + 12.5(0 kJ/mol)]

ΔH = -6582.3 kJ/mol

The enthalpy change of the reaction is -6582.3 kJ/mol of decane.

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Given what we know, we can confirm that when an excited electron spontaneously emits a photon, the energy released is electromagnetic energy.

Therefore, we can confirm that when an excited electron spontaneously emits a photon, the energy released is electromagnetic energy due to the properties of the photon being emitted.

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When an excited electron spontaneously emits a photon, the energy transformation from potential to kinetic energy takes place.

If an atom is in an excited state means full of energy, it goes from higher energy level to lower energy level. The electron releasing energy in the form of a photon, which is emitted in a random direction.

When the electron returns to a low energy state, it releases the potential energy in the form of kinetic energy so we can conclude that the energy transformation from potential to kinetic energy takes place.

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