find probability a particle scatters at a given angle for d sigma d omega

In many series circuits, a single value may represent the value for other components in a circuit because all components in a series circuit share the same current.

This means that the same current flows through each component, and therefore, the voltage drop across each component is proportional to its resistance. As a result, if the resistance of one component is known, it can be used to calculate the values of other components in the circuit.

This simplifies the circuit analysis process and allows for more efficient circuit design.

However, it is important to note that this only applies to series circuits and not parallel circuits, where each component has a different current flowing through it.

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To determine the amount of energy stored in the bow at full extension (0.5 m), or E-bow,

1. First, collect data points of force and extension (distance) for the bowstring. Ensure you have more than 3 or 4 data points for a better estimate.

2. Plot the force vs. extension data points on a graph.

3. Calculate the area under the curve of the force vs. extension graph up to the full extension (0.5 m).

The area under the curve represents the work done on the bowstring and is equal to the energy stored in the bent bow (E-bow).

4. You can find the area under the curve using various methods, such as numerical integration, trapezoidal rule, or Simpson's rule, depending on the data points' distribution and the required accuracy.

Once you've calculated the area under the curve, that value will represent the amount of energy stored in the bow at full extension (0.5 m), which is E-bow.

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The speed of the satellite orbiting the new planet is less than the speed of the satellite orbiting Earth.

(a) The speed of the satellite orbiting the new planet is less than the speed of the satellite orbiting Earth. This is because the speed of the satellite is determined by the gravitational force between the satellite and the planet it is orbiting.

Since the new planet is significantly more massive than Earth, the gravitational force acting on the satellite is much greater. This means that the satellite needs to travel at a slower speed in order to maintain a circular orbit at the same distance d from the surface of the planet.

Therefore, the speed of the satellite orbiting the new planet is less than the speed of the satellite orbiting Earth.

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According to the question, the heat required to melt 5.5 gram of ice at 0°C is 1,839 J.

Heat is the transfer of energy from one object to another due to a difference in temperature. Heat is the total energy of the motion of particles in an object, including the kinetic energy of the particles and the energy associated with their relative positions. Heat energy is transferred by conduction, convection, and radiation. Conduction is the transfer of heat energy through direct physical contact between particles, while convection is the transfer of heat energy through the movement of a fluid, such as air or water. Radiation is the transfer of heat energy through electromagnetic waves.

The heat required to melt 1 gram of ice at 0°C is 334 J. Therefore, the heat required to melt 5.5 grams of ice at 0°C is 1,839 J.

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Answer:

The equal and opposite force is equal to the sum of any frictional force to the product of the mass of the wagon and the acceleration of the wagon

Explanation:

Newton's third law states that for every action, or force, there is an equal and opposite reaction

The equal and opposite force = The mass of the Wagon, m × The acceleration of the wagon, a + Any frictional force present, \(F_f\)

Whereby the force with which the horse pulls the wagon = F, mathematically, we have;

The equal and opposite force = -F = m × a + \(F_f\).

Answer:

Ground pushes up on the horse’s hooves

Explanation:

khan academy

Answer:

As the voltage increases, the current flowing through the circuit increases while the resistance of the resistor remains constant.

Explanation:

Ohm's law states that the current flowing through a circuit is directly proportional to the applied voltage.

V = IR

where;

I is the current

R is the resistance

V is the applied voltage

Based on this law (Ohm's law), as the voltage increases, the current flowing through the circuit increases while the resistance of the resistor remains constant.

Answer:

the nearest point.

A satellite in an elliptical orbit around the Earth travels fastest when it is closest to the Earth, at the point called perigee.

In an elliptical orbit, the distance between the satellite and the Earth varies throughout its orbital path. At perigee, the satellite is at its closest distance to the Earth, and due to the conservation of angular momentum, it experiences the highest orbital velocity. As the satellite moves away from perigee and reaches the farthest point called apogee, its velocity decreases.Therefore, the satellite travels fastest at perigee, where it is closest to the Earth.

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Answer:

The projectile's horizontal speed is constant throughout the entire trajectory because gravity only acts downwards in the vertical direction.

Explanation:

I did this in Physics a while ago but I believe my answer is correct.

Hope this helps! (:

An element of atomic number 88 decays radioactively to an element of atomic number 82. The emissions that achieve this result is one alpha particle. The correct option is D. The emission that achieves this result is one alpha particle. The correct option is C.

To determine the emissions that achieve the radioactive decay from an element with atomic number 88 to an element with atomic number 82, we need to consider the changes in atomic number and mass number during the decay process.

In a radioactive decay, the atomic number decreases by the emission of a particle, and the mass number decreases by a specific amount as well.

Atomic number of initial element = 88

Atomic number of final element = 82

From this information, we can conclude that the decay process involves the emission of an alpha particle.

The emission of an alpha particle corresponds to the emission of a helium nucleus, which consists of two protons and two neutrons. This emission reduces the atomic number by 2 and the mass number by 4.

Therefore, the emission that achieves this result is C, one alpha particle.

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Answer:

its lost 91

Explanation:

Answer:

one billion to ten billion joules.

Explanation:

To keep a 100-watt light bulb going for one second, one hundred joules of energy will be used.

Answer:

In 3 lightning bolts, there is approximately 1 billion to ten billion joules.

Explanation:

According to Heisenberg's Uncertainty Principle, it is impossible to determine the position and momentum of a particle with absolute certainty at the same time. The Uncertainty Principle is defined as Δx * Δp ≥ h/4π, where Δx is the uncertainty in position, Δp is the uncertainty in momentum, and h is Planck's constant.
For the given problem, the uncertainty in position of a proton with mass 1.673 x 10-27 kg and kinetic energy 1.2 keV can be calculated as follows:

We know that the momentum p of a particle is given by p = mv, where m is the mass of the particle and v is its velocity.
The kinetic energy of the proton can be converted to momentum using the equation E = p²/2m, where E is the kinetic energy.
1.2 keV = (p²/2m)    (1 eV = 1.6 x 10^-19 J)
p²/2m = 1.92 x 10^-16 J
The momentum p of the proton can be calculated by taking the square root of both sides:
p = √(2mE) = √(2 x 1.673 x 10^-27 x 1.6 x 10^-16) = 7.84 x 10^-22 kg m/s

Using Heisenberg's Uncertainty Principle, we can calculate the uncertainty in position as follows:
Δx * Δp ≥ h/4π
Δx ≥ h/4πΔp
Substituting the values of h, Δp, and solving for Δx:
Δx ≥ (6.626 x 10^-34)/(4π x 7.84 x 10^-22)
Δx ≥ 2.69 x 10^-12 m

Therefore, the uncertainty in position of the proton is 2.69 x 10^-12 m.

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To find the magnitude and sign of the charge of the third particle (qC) such that each particle is in equilibrium under the action of electric forces, we can use the principle of electrostatic equilibrium.

In electrostatic equilibrium, the net force on a charged particle is zero. Therefore, the sum of the forces acting on the third particle (qC) due to the other two charges (qA and qB) must be zero.

The electric force between two charges is given by Coulomb's law:

F = k * |q1 * q2| / r^2

where F is the force, k is the electrostatic constant (k = 8.99 × 10^9 N·m^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.

Let's analyze the forces acting on the third particle (qC) individually:

1. Force due to qA:

The force exerted by qA on qC is attractive since the charges have opposite signs. The distance between qA and qC is x, which is the position of qC on the x-axis. The force due to qA can be calculated using Coulomb's law:

F_A = k * |qA * qC| / x

2. Force due to qB:

The force exerted by qB on qC is repulsive since both charges have the same sign. The distance between qB and qC is 15.0 cm - x. The force due to qB can be calculated using Coulomb's law:

F_B = k * |qB * qC| / (15.0 cm - x)^2

To achieve equilibrium, the sum of these forces should be zero:

F_A + F_B = 0

Substituting the values of qA, qB, and the expressions for the forces:

(k * |qA * qC| / x^2) + (k * |qB * qC| / (15.0 cm - x)^2) = 0

Simplifying the equation and substituting the given values of qA and qB:

(8.99 × 10^9 N·m^2/C^2 * |-12.0 σC * qC| / x^2) + (8.99 × 10^9 N·m^2/C^2 * |45.0 σC * qC| / (15.0 cm - x)^2) = 0

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When a beta particle is emitted from the nucleus, the atomic number increases by 1, while the mass number remains unchanged.

Beta decay occurs when a neutron in the nucleus converts into a proton, releasing a beta particle (an electron) and an antineutrino. Since a neutron is converted into a proton, the number of protons (atomic number) increases by 1. However, the mass number, which represents the sum of protons and neutrons, remains the same because the mass of an electron (beta particle) is negligible compared to that of a proton or neutron. Therefore, the overall mass of the nucleus is unaffected by the emission of a beta particle, while the atomic number increases by 1 due to the newly formed proton.

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Answer:

तिकडी एकच

Explanation:

आप सल क्ल वल दन रव दंचंबी एक गम ok plz

Answer:

\(\huge\boxed{\sf S = 18.75 \ meters}\)

Explanation:

Given Data:

Initial Velocity = Vi = 0 m/s (rest)

Final Velocity for 6 seconds = Vf = 25 m/s

Time (1) = T1 = 6 seconds

Time (2) = T2 = 3 seconds

Required:

Distance for 3 seconds = S = ?

Solution:

For 6 seconds, the acceleration will be:

\(\displaystyle a = \frac{Vf-Vi}{t} \\\\a = \frac{25 - 0}{6} \\\\a = 25 / 6\\\\\boxed{a = 4.167 \ m/s^2}\)

Since, acceleration is constant, it will be the same at 3 seconds as well.

Using second equation of motion to find Distance (S) with time being 3 seconds:

\(\displaystyle S= Vit+\frac{1}{2} at^2\\\\S = (0)(3)+ \frac{1}{2} (4.167)(3)^2\\\\S = \frac{1}{2} (4.167)(9)\\\\S = \frac{37.5}{2} \\\\\boxed{S = 18.75 \ meters}\\\\\rule[225]{225}{2}\)

Hope this helped!

Answer:

These deep-ocean currents are driven by differences in the water's density, which is controlled by temperature (thermo) and salinity (haline). This process is known as thermohaline circulation.

Explanation:

Answer: the stopping distance for an initial speed of 15 m/s with a constant deceleration of 3.9 m/s² is approximately 57.7 meters.

Explanation:

To calculate the stopping distance, we need to use the following equation of motion:

v² = u² + 2as

where:

v is the final velocity (in this case, it is 0 because the car stops)

u is the initial velocity (15 m/s)

a is the deceleration (-3.9 m/s²)

s is the stopping distance (what we want to find)

Substituting the given values in the equation, we get:

0² = 15² + 2(-3.9)s

Simplifying and solving for s, we get:

s = (15²) / (2 × 3.9) ≈ 57.7 meters

The magnitude of the velocity of the 6.0 kg mass after the collision is approximately 1.7 m/s.

We can solve this problem using conservation of momentum and conservation of kinetic energy. Conservation of momentum states that the total momentum of a system is conserved if there are no external forces acting on it. In this case, the system is the two masses.

Let p1 and p2 be the initial momenta of the 3.0 kg and 6.0 kg masses, respectively, and p1' and p2' be their final momenta after the collision. Since the 6.0 kg mass is initially at rest, we have:

p1 = m1v1 = (3.0 kg)(10 m/s) = 30 kg·m/s

p2 = m2v2 = (6.0 kg)(0 m/s) = 0 kg·m/s

After the collision, the 3.0 kg mass moves at an angle of 35° with a speed of 8.0 m/s. We can break its velocity into x- and y-components:

vx = v1' cos(35°) = 8.0 m/s cos(35°) ≈ 6.6 m/s

vy = v1' sin(35°) = 8.0 m/s sin(35°) ≈ 4.6 m/s

The total momentum of the system after the collision is:

p1' + p2' = m1v1' + m2v2'

We can use conservation of momentum to say that p1 + p2 = p1' + p2', so:

p1' + p2' = 30 kg·m/s

Substituting in the known values, we have:

(3.0 kg)(6.6 m/s) + (6.0 kg)v2' = 30 kg·m/s

Solving for v2', we get:

v2' = (30 kg·m/s - 19.8 kg·m/s) / 6.0 kg ≈ 1.7 m/s

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Answer:

The bright blue and black colors represent the following:

Constructive and destructive interference are represented by the blue and black colors, respectively. When two water waves collide constructively, the resultant wave is bright blue, while when they collide destructively, the resultant wave is black in color.

Explanation:

   When two propagating waves with the same frequency (say, \(\nu\)) and wavelength (say,\(\lambda\)) but slightly different amplitudes (say, A 1 and A 2) traveling in the same direction interfere or are superimposed on each other (that is incident at the same point or object), a third resultant wave with a different amplitude (increased or decreased) but same wavelength and frequency is generated.  

The direction difference between the two waves determines whether they intervene constructively (increasing the amplitude of the resultant wave) or destructively (increasing the amplitude of the resultant wave) (decreased amplitude of the resultant wave). To put it another way, when the difference in direction between the two waves is of the form -

      \(\Delta x = n\lambda , n=0,1,2,.....\) is the order of interference.

The two waves are then assumed to be in phase, and the interference is constructive, resulting in the resultant wave having a larger amplitude (which is the sum of the two amplitudes \(A_1 +A_2\)  also known as a maxima). When the difference in direction between the two waves is in the form -

  \(\Delta x = (2n-1)\frac{\lambda}{2} , n=0,1,2,.....\) is the order of interference.

The two intervening waves are then said to be out of phase, and the interference is disruptive, resulting in the resultant wave having a lower amplitude (which is the difference between the two amplitudes \(A_1+A_2\), also known as a minima).

Hence , the graphical representation of constructive (blue )and destructive (black) is attached.

Answer:

Friction can be increased the longer two objects are rubbed together, since the longer they are rubbed is the more heat produced.

Explanation:

Answer:

walking, car moving

Explanation:

basically anything with two surfaces pressing together ig

Answer:

Given Mas (m) =63kg

velocity (v) =4.3m/s

momentum (p) =?

p=mv

63kgx4.3m/s

270.9kg.m/s

the momentum =270.9kg.m /s

If a ball of mass 0.63 kilograms is moving at 4.3 meters/seconds, then the momentum of the ball would be 2.709-kilogram meters/second.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle.

Momentum = mass of the object × velocity of the object

As given in the problem we have to calculate the momentum of the ball if it has a mass of 0.63 kilograms and moving with a speed of  4.3 meters/seconds,

The momentum of the ball = 0.63× 4.3

                                             =2.709 kilogram meters/second

Thus, the momentum of the ball comes out to be 2.709-kilogram meters/second.

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 4.6 × 9.2

We have the final answer as

Hope this helps you

The magnitude of the electric field at point P which has coordinates (1, 0, 2) m is E = √((-6)² + 0² + 12²) V/m= √180 V/m= 6√5 V/m.

Over a certain region of space, the electric potential is (3x² - 4y² - 12z) V. Find the expressions for the x, y, and z components of the electric field over this region. For a uniform electric field in a given region, the electric potential over that region is related to the electric field through the relation

E = -∇V,

Here ∇ is the nabla operator in Cartesian coordinates.

So, for the given electric potential (3x² - 4y² - 12z) V, the electric field components are given by:

Ex = -dV/dx = -6x V/m

Ey = -dV/dy = 8y V/m

Ez = -dV/dz = 12 V/m

Therefore, the expressions for the x, y, and z components of the electric field over this region are Ex = -6x V/m, Ey = 8y V/m, and Ez = 12 V/m, respectively. The magnitude of the field at point P (1, 0, 2) m can be calculated using the expression for the magnitude of the electric field given by

E = √(Ex² + Ey² + Ez²).

Substituting the given coordinates of point P, we get

Ex = -6(1) V/m = -6 V/m

Ey = 8(0) V/m = 0 V

Ez = 12 V/m

Thus, the magnitude of the electric field at point P is 6√5 V/m.

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Answer:

When gamma rays pass through the human body, they ionize the tissue.  gamma ray ionization can affect healthy cells. When high levels of gamma rays bombard a body, a resulting dangerous ionization of tissue can cause skin cancer.

Explanation:

Jupiter is a gas giant with no solid surface so it needs airships floating houses or spacecraft to live on.

Jupiter is the fifth planet from the Sun and the largest planet in the solar system. It is a gas giant with a mass more than two and a half times that of all the other planets in the Solar System combined, but slightly less than one-thousandth the mass of the Sun.

Jupiter's magnetic field traps charged particles from the Sun and Mars's volcanic moon Io. These particles create intense radiation belts. The radiation belt around Io's orbit is powerful enough to kill an unprotected human within minutes. It's easy to see with your eyes if you know when and where to look.

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The units of Planck's constant are Joule seconds (J*s).

Planck's constant is a fundamental physical constant that plays a crucial role in quantum mechanics. It relates the energy of a photon to its frequency through the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency. The unit of energy is Joules (J), and the unit of frequency is Hertz (Hz), so the unit of Planck's constant is J*s.

The significance of Planck's constant lies in its ability to bridge the gap between classical physics and quantum mechanics. It helps explain phenomena such as wave-particle duality, where particles can behave as waves and vice versa. Additionally, it is used in calculations related to atomic and subatomic particles, including the energy levels of electrons in atoms and the behavior of photons in lasers.

Overall, the units of Planck's constant demonstrate its importance as a fundamental constant in the field of quantum mechanics and its role in bridging the gap between classical physics and the mysterious realm of the subatomic world.

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The displacement of the coin when viewed vertically from above is approximately 3.08 cm.

When a coin falls into a tank containing two immiscible liquids, the displacement of the coin when viewed vertically from above can be calculated by considering the principles of refraction at the interface between the liquids.In this case, the refractive index of liquid A is given as 1.3, and the refractive index of liquid B is given as 1.4. Let's assume that the coin is submerged in liquid A, and we want to find the displacement when viewed from above the surface.To calculate the displacement, we need to determine the apparent shift in the position of the coin due to the change in refractive index. The apparent shift is given by the formula:

Apparent Shift = Actual Shift x (Refractive Index B - Refractive Index A) / Refractive Index A

Here, the actual shift is the distance the coin has moved vertically downward. Since the coin is submerged in liquid A, its actual shift is 40 cm.Plugging in the values, we get:

Apparent Shift = 40 cm x (1.4 - 1.3) / 1.3 = 40 cm x 0.1 / 1.3 ≈ 3.08 cm

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