The absolute maximum and minimum values of f on the set D. f(x, y)= xy2, D = {(x, y)| x >= 0, y >= 0, x2 + y2 <= 3} are 0 and 2.
What is absolute maxima and minima?
Absolute maxima and minima are the function's maximum and minimum values over its entire range. Absolute maximum and minimum of a function are also called the global maximum and minimum of the function. The highest point of the function within the entire range is known as the absolute maxima of the function and the lowest point of the function within the entire range is known as absolute minima of the function.
Given, f(x, y) = xy2 --- (1)
D = {(x, y)| x >= 0, y >= 0, x2 + y2 <= 3}
We have to find the absolute maximum and minimum values of f on the set D.
The partial derivatives of f(x, y) is
df/dx = y2
df/dy = 2xy
Substitute y = 0 in (1)
We have x = 0
This implies that the critical point = f(0, 0) = 0.
To calculate the extreme values from x2 + y2 <= 3
Rewriting the expression as x2 + y2 = 3
y2 = 3 - x2
Taking square root,
y = √(3 - x2) --- (2)
Put the value of y in (1),
f(x) = x[√(3 - x2)]2
f(x) = x(3 - x2)
f(x) = 3x - x3
On differentiating,
f’(x) = 3 - 3x2
Let f’(x) = 0
3 - 3x2 = 0
3x2 = 3
x2 = 1
Taking square root,
x = ±1
Given, x > 0
So, the value of x is +1.
Put x = 1 in (2)
y = √(3 - 1) = √2
The absolute maximum is at (x, y) = (1, √2)
The absolute minimum is at (x, y) = (0, 0)
At (0, 0), f(0, 0) = 0
At (1, √2), f(1, √2) = 1(√2)2 = 2
Therefore, the absolute maximum and minimum values of f are 0 and 2.
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You pick two marbles from a bag containing 30 marbles: 3 green, 6 white, 4 red, 7 yellow, and 10 blue. Find the given probabilities. Show your work. Simplify all answers.
P(red)
P(blue)
P(white)
P(yellow)
P(green)
a water system of 2 in. (inside diameter) pipe, having a length of 1 4 mile, is to be flushed with a volume of water equal to twice that contained in the system. how much water (gallons) must be flushed through the system?
To flush twice the volume of water contained in the system, you would need to flush 18.2 gallons x 2 = 36.4 gallons of water through the system.
Calculate the volume of waterTo calculate the volume of water contained in the system, you would use the formula for the volume of a cylinder: V = πr^2h, where r is the radius of the pipe (half the diameter), h is the length of the pipe, and π is approximately 3.14.
In this case, the radius of the pipe is 2 inches / 2 = 1 inch, and the length of the pipe is 1/4 mile = 1320 feet (since there are 5280 feet in a mile).So the volume of the pipe is: V = πr^2h = 3.14 x (1 inch)^2 x 1320 feet = 4201.6 cubic inches.Since there are 231 cubic inches in a gallon, the number of gallons of water in the pipe is: 4201.6 cubic inches / 231 cubic inches/gallon = 18.2 gallons.To flush twice the volume of water contained in the system, you would need to flush 18.2 gallons x 2 = 36.4 gallons of water through the system.Learn more about the volume of water here:
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the distance between single-family residences in the new desert vista subdivision in mesa is 30 feet. what is the distance known as in subdivision development terms?
The 30-foot distance between single-family residences in the Desert Vista subdivision is called a "setback" in development terms.
This setback ensures that the neighborhood maintains adequate spacing between homes for privacy, safety, and aesthetics.
The distance between single-family residences in the new Desert Vista subdivision in Mesa is known as the "setback" in subdivision development terms.
Setbacks are regulations that define the minimum distance a building, such as a single-family residence, must be located from property lines or other structures.
These regulations ensure adequate spacing between buildings for various reasons, including privacy, safety, and aesthetics.
1. The student question mentions that the distance between single-family residences in the new Desert Vista subdivision in Mesa is 30 feet.
2. In subdivision development terms, such a distance is referred to as a "setback."
3. Setbacks are important for maintaining privacy, safety, and aesthetics in a neighborhood.
4. These regulations ensure that there is enough space between buildings, preventing overcrowding and allowing for proper ventilation, sunlight, and access to emergency services.
5. Setbacks vary depending on the type of structure and local zoning laws, which determine the minimum distance required between buildings.
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A train travelled 720km in 9hrs.how far would it travel in 11hrs
The train would travel 880 km in 11 hours.
To determine the distance the train would travel in 11 hours, we can use the concept of speed. Speed is defined as distance traveled divided by the time taken.
Given that the train traveled 720 km in 9 hours, we can calculate its speed:
Speed = Distance / Time
Speed = 720 km / 9 hrs
Speed = 80 km/h
Now, to find the distance the train would travel in 11 hours, we can use the speed:
Distance = Speed × Time
Distance = 80 km/h × 11 hrs
Distance = 880 km
Therefore, the train would travel 880 km in 11 hours.
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show that a pair x,p is equilibrium if and only if x and p are optimal solutions to the standard form problem under consideration and its dual respectively
A pair (x, p) is an equilibrium, if and only if x and p are optimal solutions to the standard form problem and its dual, respectively.
To show that a pair (x, p) is an equilibrium if and only if x and p are optimal solutions to the standard form problem and its dual, we need to demonstrate both directions of the equivalence.
First, let's assume that (x, p) is an equilibrium. An equilibrium occurs when the primal problem and its dual problem satisfy certain conditions. In this case, we have:
1. Primal problem:
- Objective function: maximize \(c^T * x\) (where c is the cost vector and x is the decision variable)
- Subject to: Ax = b (where A is the constraint matrix and b is the right-hand side vector)
2. Dual problem:
- Objective function: minimize \(b^T * p\) (where p is the dual variable)
- Subject to: \(A^T * p \geq c\) (where \(A^T\) is the transpose of A)
Now, if (x, p) is an equilibrium, it means that both the primal and dual problems are feasible, and their objective functions are equal. This implies that x and p are optimal solutions to their respective problems.
Conversely, let's assume that x and p are optimal solutions to the standard form problem and its dual, respectively. This means that x and p satisfy the feasibility conditions and optimize the objective functions of their respective problems.
Since x and p are optimal solutions, the objective functions of the primal and dual problems are equal. This condition ensures that (x, p) is an equilibrium.
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A pair (x, p) is an equilibrium if and only if x is an optimal solution to the standard form problem and p is an optimal solution to its dual. Both conditions must be satisfied for equilibrium.
To show that a pair (x, p) is an equilibrium, we need to prove two conditions: (1) x is an optimal solution to the standard form problem, and (2) p is an optimal solution to its dual.
First, assume that (x, p) is an equilibrium. This means that x is feasible and satisfies the constraints of the standard form problem. We can also assume that p is feasible and satisfies the constraints of the dual problem.
To prove condition (1), we can use contradiction. Suppose x is not an optimal solution. Then there exists another feasible solution x' that yields a better objective function value. However, this contradicts the definition of an equilibrium, so x must be an optimal solution.
Similarly, to prove condition (2), we can assume that p is not an optimal solution. Then there exists another feasible solution p' to the dual problem that yields a better objective function value. Again, this contradicts the definition of an equilibrium, so p must be an optimal solution.
Conversely, if x is an optimal solution to the standard form problem and p is an optimal solution to its dual, we can conclude that (x, p) is an equilibrium. This is because both x and p satisfy the necessary conditions for optimality.
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Graph the solution to this inequality on the number line.
−4m+3>11
Answer: The person above me is correct. Here is a picture if you still dont get it..
Step-by-step explanation:
A company makes a bracelet that is designed to repel mosquitos so people don't have to wear bug spray. Researchers at the company are designing an experiment where volunteers will be assigned either the bracelet or bug spray to use at their homes. The researchers want to use a randomized block design. How should the researchers form the block? (Choose one and explain why, please also explain why other methods wouldn't work).
a. Both the volunteers and researchers should be kept blind as to which block the volunteers are in.
b. Each block should consist of volunteers who live in similar environments when it comes to mosquitos.
c. Each block should consist of volunteers who live in different environments when it comes to mosquitos.
d. Each volunteer should be randomly assigned to a block.
e. Volunteers in one block should use the bracelet, while volunteers in the other block should use bug spray.
The correct answer is b. Each block should consist of volunteers who live in similar environments when it comes to mosquitoes.
Explanation:
In a randomized block design, blocks are formed to control for potential confounding factors or sources of variation that may affect the outcome of the experiment. By forming blocks based on similar environments when it comes to mosquitoes, the researchers ensure that any differences in the effectiveness of the bracelet and bug spray are not solely due to variations in mosquito exposure.
If the researchers were to choose option a (both the volunteers and researchers should be kept blind as to which block the volunteers are in), it would be related to blinding the participants and researchers to the treatment assignment, not forming blocks. This method does not address the need for controlling potential confounding factors.
Option c (each block should consist of volunteers who live in different environments when it comes to mosquitoes) would not be suitable because it would introduce additional variability and make it difficult to compare the effectiveness of the bracelet and bug spray.
Option d (each volunteer should be randomly assigned to a block) is not recommended in this case because it does not take into account potential confounding factors related to mosquito exposure.
Option e (volunteers in one block should use the bracelet, while volunteers in the other block should use bug spray) does not control for potential confounding factors, as individuals in different blocks may have different levels of mosquito exposure.
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which is the following exterior angles
which is the following exterior angles
Answer:
6,4,3,2
My bag weighs 4 pounds how many ounces does it weigh
Answer:
The answer is 64 ounces.
Answer:
64 ounces
Step-by-step explanation:
1 pound = 16 ounces
4 * 16 = 64
A graphing calculator is recommended, A 60-gallon barrel is filled completely with pure water. Salt water with a concentration of 0.3 lb/gal is then pumped into the barrel, and the resulting mixture overflows at the same rate. The amount of salt in the barrel at time t is given by Olt) = 18(1 - e-0.08) where t is measured in minutes and o(t) is measured in pounds. (a) How much salt is in the barrel after 5 min? (Round your answer to two decimal places.) | Iь (b) How much salt is in the barrel after 10 min? (Round your answer to two decimal places.) | ГБ lb (c) Draw a graph of the function Oſt). Qt) Qit) 20 20 15 15 10 10 5 20 t 100 40 80 60 ht 100 O 20 40 60 80 Oxt) Oxt) 20 20 15 15 10 10 5 t Lt O 20 40 60 80 100 O 20 40 60 80 100 (d) Use the graph in part (c) to determine the value that the amount of salt in the barrel approaches as t becomes large. | | lb
t approaches infinity then salt is:
\(Q(\infty) = 18lb\)
What is volume?
Volume is a mathematical term used to describe how much three-dimensional space an object or closed surface occupies. Volume is measured in cubic units like m3, cm3, in3, etc. Volume is sometimes referred to as capacity.
The amount of salt in the barrel at time t is given by
where Q(t) is in pounds and time t is in minutes.
(a) Salt after 5 minutes i.e. t=5
\(Q(5) = 18(1 - e^{-0.08(5)} ) = 18(1 - e^{-0.4})\\\\Q(5) = 18(1 - 0.6703) = 5.93 \\\\Q(5) = 5.93lb\)
(b) Salt after 10 minutes i.e. t=10
\(Q(10) = 18(1 - e^{-0.08(10)} ) = 18(1 - e^{-0.8} )\\\\Q(10) = 18(1 - 0.4493 ) = 9.91\\\\Q(10) = 9.91lb\)
(d) When t becomes large, let say when t approaches infinity then salt is
\(Q(\infty) = 18(1 - e^{-0.08(\infty)} ) = 18(1- e^{-\infty})\\\\Q(\infty) = 18(1 - 0) = 18\\\\Q(\infty) = 18lb\)
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Exam: 04.04 Experimental Probability
Exam: 04.04 Experimental Probability
Student Name: Jeremiah Wood
Warning
There is a checkbox at the bottom of the exam form that you MUST check prior to submitting this exam. Failure to do so may cause your work to be lost.
Question 1(Multiple Choice Worth 2 points)
(Experimental Probability MC)
Michael has a bag of marbles. The frequency of selecting each color is recorded in the table below.
Outcome Frequency
Green 4
Black 6
Orange 5
Based on the given frequency, determine the experimental probability of selecting a black marble.
0.27
0.33
0.40
0.60
Question 2(Multiple Choice Worth 2 points)
(Experimental Probability MC)
A spinner with 4 equal sections is spun 20 times. The frequency of spinning each color is recorded in the table below.
Outcome Frequency
Pink 6
White 3
Blue 7
Orange 4
What statement best compares the theoretical and experimental probability of landing on pink?
The theoretical probability of landing on pink is one fifth, and the experimental probability is 50%.
The theoretical probability of landing on pink is one fourth, and the experimental probability is 50%.
The theoretical probability of landing on pink is one fifth, and the experimental probability is 30%.
The theoretical probability of landing on pink is one fourth, and the experimental probability is 30%.
Question 3(Multiple Choice Worth 2 points)
(Experimental Probability MC)
A coin is flipped 200 times. The table shows the frequency of each event.
Outcome Frequency
Heads 98
Tails 102
Determine the experimental probability of landing on heads.
102%
98%
50%
49%
Question 4(Multiple Choice Worth 2 points)
(Experimental Probability LC)
A number cube is tossed 60 times.
Outcome Frequency
1 12
2 13
3 11
4 6
5 10
6 8
Determine the experimental probability of landing on a number greater than 4.
17 over 60
18 over 60
24 over 60
42 over 60
Question 5(Multiple Choice Worth 2 points)
(Experimental Probability MC)
Sandy used a virtual coin toss app to show the results of flipping a coin 50 times, 400 times, and 2,000 times. Explain what most likely happened in Sandy's experiment.
Sandy's experimental probability was closest to the theoretical probability in the experiment with 2,000 flips.
Sandy's experimental probability was closest to the theoretical probability in the experiment with 400 flips.
Sandy's experimental probability was closest to the theoretical probability in the experiment with 50 flips.
Sandy's experimental probability was exactly the same as the theoretical probability for all three experiments.
Question 6 (Essay Worth 4 points)
(Experimental Probability HC)
A coin is flipped at the start of every game to determine if Team A (heads) or Team B (tails) will get the ball first.
Part A: Find the theoretical probability of a fair coin landing on heads. (1 point)
Part B: Flip a coin 10 times and record the frequency of each outcome. Determine the experimental probability of landing on heads. Please include the frequency of each outcome in your answer. (2 points)
Part C: Compare the experimental probability to the theoretical probability. (1 point)
Sandy conducted an experiment to calculate the theoretical and experimental probability. In Sandy's experiment, the theoretical probability is when a coin is flipped, and there are two possible outcomes: heads or tails.
The experimental probability is the ratio of how many times a specific event happened to the total number of trials that took place.
In Sandy's experiment, she flipped a coin 400 times, and the results were as follows:heads - 210tail - 190The theoretical probability of getting heads or tails on a coin toss is 0.5 or 50%. Sandy's experimental probability of getting heads was 210/400 = 0.525 or 52.5%.
Her experimental probability of getting tails was 190/400 = 0.475 or 47.5%.
Therefore, Sandy's experimental probability for heads was more than the theoretical probability of getting heads.
The difference between the two probabilities was:Experimental probability of heads - Theoretical probability of
heads= 0.525 - 0.5= 0.025 or 2.5%.
The difference was not very significant, but it shows that the experimental probability is slightly higher than the theoretical probability. This may have happened due to chance, or there could be some other factors influencing the experiment.
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a pizza provides 8 grams of fat and 300 total calories in one slice. what is the percentage of calories as fat in this pizza slice? hint: use the formula: (no.of calories from fat / total calories) x 100
The 24% of the calories in one slice of pizza come from fat.
To find the percentage of calories from fat in one slice of pizza, we use the formula:
(Calories One gram of fat provides 9 calories, so 8 grams of fat provide 8 x 9 = 72 calories.
Therefore, the percentage of calories from fat in one slice of pizza is:
(72 / 300) x 100 = 24%
Calories are units of energy that a food or drink produce. we can normally find calorie numbers listed on food items, and wearables like the best fitness trackers allow you monitor how many calories you are burning by doing different activities.
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The diagram below shows two wires carrying anti-parallel currents. Each wire carries 30 amps of current. The centers of the wires are 5 mm apart. Point P is 15 cm from the midpoint between the wires. Find the net magnetic field at point P, using the coordinate system shown and expressing your answer in 1, 1, k notation. 5mm mm = 10-³ cm=102m I₂ (out) P •midpan't betwem wires 1 X- I, (in)! (30A) 15cm →X Z(out)
The net magnetic field at point P is (6e-5 j + 0.57 k) T in 1, 1, k notation.
We can use the Biot-Savart Law to calculate the magnetic field at point P due to each wire, and then add the two contributions vectorially to obtain the net magnetic field.
The magnetic field due to a current-carrying wire can be calculated using the formula:
d = μ₀/4π * Id × /r³
where d is the magnetic field contribution at a point due to a small element of current Id, is the vector pointing from the element to the point, r is the distance between them, and μ₀ is the permeability of free space.
Let's first consider the wire carrying current I₁ (in the positive X direction). The contribution to the magnetic field at point P from an element d located at position y on the wire is:
d₁ = μ₀/4π * I₁ d × ₁ /r₁³
where ₁ is the vector pointing from the element to P, and r₁ is the distance between them. Since the wire is infinitely long, we can assume that it extends from -∞ to +∞ along the X axis, and integrate over its length to find the total magnetic field at P:
B₁ = ∫d₁ = μ₀/4π * I₁ ∫d × ₁ /r₁³
For the given setup, the integrals simplify as follows:
∫d = I₁ L, where L is the length of the wire per unit length
d × ₁ = L dy (y - 1/2 L) j - x i
r₁ = sqrt(x² + (y - 1/2 L)²)
Substituting these expressions into the integral and evaluating it, we get:
B₁ = μ₀/4π * I₁ L ∫[-∞,+∞] (L dy (y - 1/2 L) j - x i) / (x² + (y - 1/2 L)²)^(3/2)
This integral can be evaluated using the substitution u = y - 1/2 L, which transforms it into a standard form that can be looked up in a table or computed using software. The result is:
B₁ = μ₀ I₁ / 4πd * (j - 2z k)
where d = 5 mm = 5×10^-3 m is the distance between the wires, and z is the coordinate along the Z axis.
Similarly, for the wire carrying current I₂ (in the negative X direction), we have:
B₂ = μ₀ I₂ / 4πd * (-j - 2z k)
Therefore, the net magnetic field at point P is:
B = B₁ + B₂ = μ₀ / 4πd * (I₁ - I₂) j + 2μ₀I₁ / 4πd * z k
Substituting the given values, we obtain:
B = (2×10^-7 Tm/A) / (4π×5×10^-3 m) * (30A - (-30A)) j + 2(2×10^-7 Tm/A) × 30A / (4π×5×10^-3 m) * (15×10^-2 m) k
which simplifies to:
B = (6e-5 j + 0.57 k) T
Therefore, the net magnetic field at point P is (6e-5 j + 0.57 k) T in 1, 1, k notation.
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Evaluate the expression when x=3.
x^2+ 10*x + 24
81
60
86
63
Answer:
\(\huge\boxed{\sf 63}\)
Step-by-step explanation:
Given expression:\(= x^2+10x + 24\)
Put x = 3
= (3)² + 10(3) + 24
= 9 + 30 + 24
= 63
\(\rule[225]{225}{2}\)
Answer:
Option D) 63 is the correct answer.
Step-by-step explanation:
Evaluate :x² + 10x + 24where :
x = 3Solution :\( \quad\sf{\dashrightarrow{{x}^{2} + 10x + 24}}\)
Substituting the value of x :
\( \quad\sf{\dashrightarrow{{(3)}^{2} + 10 \times 3 + 24}}\)
\( \quad\sf{\dashrightarrow{(3 \times 3) + 30 + 24}}\)
\( \quad\sf{\dashrightarrow{(9) + 54}}\)
\( \quad\sf{\dashrightarrow{9 + 54}}\)
\( \quad\sf{\dashrightarrow{63}}\)
\(\quad{\star{\underline{\boxed{\sf{\pink{63}}}}}}\)
Hence, the answer is 63.
————————————————Joseph is paid $210 per week, plus $18 for each extended car warranty he sells. His supervisor raises his pay by $35 each week. Which function represents his new weekly pay, R(w), when he sells w extended warranties?
Find the value of x in the triangle. 1 and 4.
Answer:
263
Step-by-step explanation:
If 75% of a number is 165 and 10% of the same number is 22, find 85% of that number
Answer:
187
Step-by-step explanation:
0.75x=165 x=220
220*0.85
The length of a rectangle is 3 cm longer than its width.
If the perimeter of the rectangle is 70 cm, find its length and width.
How to solve this problem 15 = 5x
Answer:
x = 3 (see below)
Step-by-step explanation:
To solve for x, you need to isolate the variable to one side of the equation. To do that, you need to use reverse operations. For example, the reverse operation of subtraction is addition.
In this case, we have:
15 = 5x
5x is the same thing as 5 (x) or 5 times x. This means the reverse operation is division. So, we need to divide both sides of the equation by 5:
15 = 5x
----- ----
5 5
--------------
3 = x
x = 3
An intern working with the top management team of a company ran a regression model with longitudinal (time series) data for which the p-values for the Breusch-Pagan testLilliefors test, and Durbin-Watson test were 0.059.0.267 and 0.033, respectively. What conclusions can be drawn based on an alpha value of 0.05? These error terms have constant variances The error terms are normally distributed The error terms are sequentially independent Both A and B • All of the above
The option D - "Both A and B" is the correct answer. It is essential to consider the violation of assumptions while interpreting the results of regression models.
Based on the given information, the intern's regression model with longitudinal data did not violate the assumptions of constant variance and normal distribution of error terms. However, the Durbin-Watson test resulted in a p-value of 0.033, indicating a potential violation of sequential independence of error terms.
With an alpha value of 0.05, we would reject the null hypothesis for the Durbin-Watson test, concluding that there is evidence of autocorrelation in the error terms.
This means that the error terms are not sequentially independent, which could lead to biased or inefficient estimates of regression coefficients and standard errors.
In summary, based on the given p-values and alpha value of 0.05, we can conclude that the error terms have constant variances and are normally distributed, but there is evidence of autocorrelation in the error terms.
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Hans is using frequent flier miles to fly to a location 450 miles away, but the airline he is using still charges $15.89 for fees and taxes and $0.17 to redeem each mile. In the equation below, x represents the distance Hans is flying, and y represents the cost of the trip. y = $0.17x + $15.89 How much did Hans pay for his trip?
Given :
Hans is using frequent flier miles to fly to a location 450 miles away, but the airline he is using still charges $15.89 for fees and taxes and $0.17 to redeem each mile.
In the equation below, x represents the distance Hans is flying, and y represents the cost of the trip. y = $0.17x + $15.89 .....1)
To Find :
How much did Hans pay for his trip.
Solution :
x = 450 miles.
Putting value of x in equation 1 we get :
y = $(0.17×450 + 15.89)
y = $(76.5+15.89)
y = $92.39
Therefore, Hans will pay $92.39 for his trip.
Hence, this is the required solution.
someone please help me w this
prove KLJ = NMO
Answer:
They both have one congruent side and both have the same angle
Before sunrise, the temperature was 22.4°F below zero. By noon, it had risen 12.8°F. What expression can be used to find the temperature at noon?
–22.4 – 12.8
–22.4 + 12.8
22.4 – 12.8
22.4 + 12.8
The expression that can be used to find the temperature at noon is
–22.4 + 12.8 option B
What is temperature?Generally, The word "temperature" refers to the degree to which something is hot or cold and may be described using a number of different scales, such as Fahrenheit and Celsius.
The direction in that heat energy will spontaneously flow is indicated by temperature; specifically, it will flow from a hotter body (one that is at a higher temperature) to a colder one (one at a lower temperature).
In conclusion, the temperature was 22.4°F below zero meaning
-22.4F in mathematical terms
and 12.8°F above zero in mathematical terms
Therefore, –22.4 + 12.8 is the expression that can be used to find the temperature at noon
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What is the perimeter of the house is c=5
I’m marking brainliest.
Answer:
132
Step-by-step explanation:
C=5
3c - 2 = 13
2c = 10
4c + 1 = 21
4c + 2 = 22
length = (3c- 2) + (4c + 1)
length = 13 + 21
length = 34
width = (4c + 2) + (2c)
width = 22 + 10
width = 32
Perimeter
p = 2l + 2w
p = 2*34 + 2*32
p = 68 + 64
p = 132
Pls help for b and c
b. The probability that the player will not win on Monday but will win on Tuesday and Wednesday is 0.024.
c. The probability that the player will win at least once during the 3-day period is 0.428213.
How to calculate the probabilityb. The probability that the player will not win on Monday but will win on Tuesday and Wednesday is:
P(not win on Monday) x P(win on Tuesday) x P(win on Wednesday)
= 0.83 x 0.17 x 0.17
= 0.024
c. The probability that the player will win at least once during the 3-day period is:
= 1 - P(not win on Monday) x P(not win on Tuesday) x P(not win on Wednesday)
= 1 - 0.83 x 0.83 x 0.83
= 1 - 0.571787
= 0.428213
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Calculate the area and perimeter
Answer:
75cm
Step-by-step explanation:
(5*3)+(5*5)+(7*5)
|3(x-2)|=12 Please explain too! Thank you!
A scientist claims that Fabric A is better able to resist fire than Fabric B.
Which option describes an experiment that will produce evidence that will
support or refute her claim?
O A. Make detailed measurements of each type of fabric to determine
the thickness of their fibers.
B. Measure how long it takes for a specific amount of Fabric A to
burn up completely.
O C. Hold each type of fabric over a candle flame and time w long it
takes for the fabric to start to burn.
O D. Combine Fabric A and Fabric B and measure the temperature at
which they start to burn.
The answer is C.
The question is asking you to find an option that "supports" or "refutes" her claim. In option C, you have to hold the fabrics above a candle to see how long it will take to burn. This way of proving her hypothesis can either go good or bad (support that Fabric A resists better or refute her claim and Fabric B resists fire better).
Best of Luck!
Answer:
A scientist claims that Fabric A is better able to resist fire than Fabric B.
option describes an experiment that will produce evidence that will support or refute her claim is:
C. Hold each type of fabric over a candle flame and time w long it.
Suppose 75% of smartphones sold at a retail outlet are purchased with warranty. A random sample of 25 smartphones is selected. Assuming independence, use the binomial formula or software (recommended) to answer the following questions. 1. What is the probability that, of the 25 smartphones selected: (Report probabilities accurate to at least 4 decimal places.) a) exactly 18 are purchased with warranty? b) exactly 8 are not purchased with warranty? c) all of them are purchased with warranty? d) at most 15 are purchased with warranty? e) at least 14 are purchased with warranty? f) more than half are purchased with warranty? 9) at least 14 but no more than 23 are purchased with warranty? h) less than 12 or more than 19 are purchased with warranty? 2. Calculate the mean and standard deviation of smartphones that are purchased with warranty. Round to 2 decimal places. Mean = Standard Deviation = 3. If you expect to find exactly 72 smartphones that are purchased with warranty, how large a sample should you select? Report the minimum sample size required as an integer.
The probability that exactly 18 of the 25 smartphones selected are purchased with warranty is: The probability that exactly 8 of the 25 smartphones selected are not purchased with warranty is: The probability that all 25 smartphones selected are purchased with warranty is:
The probability that at most 15 of the 25 smartphones selected are purchased with warranty is: The probability that at least 14 of the 25 smartphones selected are purchased with warranty is: f) The probability that more than half (i.e. > 12) of the 25 smartphones selected are purchased with warranty is: 9) The probability that at least 14 but no more than 23 of the 25 smartphones selected are purchased with warranty is:
h) The probability that less than 12 or more than 19 of the 25 smartphones selected are purchased with warranty is: Part 2Mean = Standard Deviation = Part 3To find the minimum sample size required to expect to find exactly 72 smartphones that are purchased with warranty, we use the following formula: N = [(Z * σ) / E]^2 where Z is the z-score corresponding to the desired level of confidence, σ is the standard deviation, and E is the maximum error of estimation. Using a 95% level of confidence, Z = 1.96.Using the calculated standard deviation of 2.91 and expecting to find exactly 72 smartphones, the maximum error of estimation is 0.5.N = [(1.96 * 2.91) / 0.5]^2N
= 337.11
Therefore, the minimum sample size required to expect to find exactly 72 smartphones that are purchased with warranty is 338.
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Maria has a number of dimes and quarters whose total value is
less than $9.00. There are twice as many dimes as quarters. At
most, how many quarters could she have?.
Maria can have at most 19 quarters.
Let's assume Maria has q quarters. Since there are twice as many dimes as quarters, she would have 2q dimes.
The value of q quarters is 25q cents, and the value of 2q dimes is
10(2q) = 20q cents.
The total value of the quarters and dimes is less than $9.00, which is equivalent to 900 cents.
So, the inequality we can form is:
25q + 20q < 900
Combining like terms, we get:
45q < 900
Dividing both sides of the inequality by 45, we find:
q < 20
Based on the given information, Maria can have a maximum of 19 quarters in her collection of dimes and quarters, ensuring that the total value remains less than $9.00.
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to decrease sample error, a pollster must __________ the number of respondents.
A) issue-scale B) increase C) decrease D) underrepresented
The correct option is B) increase.
To decrease sample error, a pollster must increase the number of respondents. The larger the sample size, the more representative it is likely to be of the target population, leading to a lower margin of error.
When conducting surveys or polls, it is essential to obtain responses from a diverse and random group of individuals. By increasing the number of respondents, the pollster can capture a broader range of perspectives, which helps to reduce sampling bias and increase the accuracy of the results.
For example, let's say a pollster wants to understand the political preferences of voters in a particular city. If they only survey 50 people, the sample may not accurately reflect the larger population, and the margin of error could be high. However, if they survey 500 or even 1000 people, the results are more likely to provide a reliable estimate of the overall population's preferences.
Therefore, to decrease sample error, pollsters should increase the number of respondents in their surveys or polls. This approach helps to ensure a more accurate representation of the population's views and minimize the potential for misleading or biased results.
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