Ms. Patel's gym class is practicing soccer. Ms. Patel has 18 soccer balls and 3 teams of students. She gives the same number of balls to each team. How many balls does Ms. Patel give each team? Which expression represents the problem? 18 – 3 18 +3 18 : 3 18 x 3
Step-by-step explanation:
18 ball=3team
18=3x
x=18/3
x=6
the answer is 18:3
if (:) this sigh of urs indicate divide
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22-23 Algebra 1 Unit 2 EUA
A hairstylist charges $15 for an adult haircut and $9 for a child haircut. She wants to earn at least $360 dollars and cut a maximum of 30
haircuts this week. The graphs represent the hairstylist's constraints.
List two points that could represent the numbers of adult and child haircuts that meet the hairstylist's goals. Enter your response in the
space provided. You may also use the drawing tool to help explain or support your answer.
The point that could represent the numbers of adults and child haircuts that meet the stylist goals exists 25, 0.
What is meant by mathematical operation?A function that converts zero or more input values into a clearly defined output value is referred to in mathematics as an operation. The operation's complexity is measured by the number of operands.
A value is computed using operands and a math operator as part of the mathematical "operation." In order to be applied to the provided operands or numbers, the math operator's symbol has predetermined rules.
Since the hairstylist change $15 for an adult haircut and $9 for a child haircut, then utilizing 25, 0 will be:
= 15(25) + 9(0)
= 375 + 0
= $375
She has earned at least 360 dollars and cut about 25 haircuts this week.
Therefore, the correct answer is option A. 25, 0.
The complete question is:
A hairstylist change $15 for an adult haircut and $9 for a child haircut. She wants to earn at least 360 dollars and cut a maximum of 30 haircuts this week. The graphs represent the hairstylist constants.
Which point could represent the numbers of adults and child haircuts the meet the stylist goals.
A. 25, 0
B. 15, 20
C. 10,15
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please give correct answer <3 :(
Answer:
216g^3
Step-by-step explanation:
6g^3 g^3
6g^3 = 6g * 6g * 6g = 216g^3
Answer:
\(216g^{3}\)
Step-by-step explanation:
6^3 x g^3=
6^3=216
216g^3
Can someone help me please?
ASAP
Answer:
y = 12 x = 12\(\sqrt{3}\)
Step-by-step explanation:
This is a 60, 90, 30. It's a special triangle.
2z = 24
z = 12
If x = z\(\sqrt{3}\)
then x = 12\(\sqrt{3}\)
y = z itself
So y = 12
In a right triangle, sin (x + 10)° = cos (4x - 4)°. Solve for x. Round your answer
to the nearest hundredth if necessary.
The value of variable x is,
⇒ x = 42
We have to given that;
In a right triangle,
⇒ sin (x + 10)° = cos (4x - 4)°
Now, We can simplify as;
⇒ sin (x + 10)° = cos (4x - 4)°
⇒ cos (90 - (x + 10))° = cos (x - 4)°
⇒ 90 - (x + 10) = x - 4
⇒ 90 - x - 10 = x - 4
⇒ 80 + 4 = 2x
⇒ 2x = 84
⇒ x = 42
Thus, The value of variable x is,
⇒ x = 42
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This question is designed to be answered without a calculator.
If f(x) = 5(x2 – 1), thenLimit of StartFraction f (x) minus f (2) Over x minus 2 EndFraction as x approaches 2 =
0.
5.
10.
20.
The limit of [f(x) - f(2)]/[x - 2] as x approaches 2 is 20
How to evaluate the limit as it approaches 0From the question, we have the following function that can be used in our computation:
f(x) = 5(x2 – 1)
Rewrite as
f(x) = 5(x² – 1)
The limit is given as
[f(x) - f(2)]/[x - 2]
Calculate f(2)
So, we have
f(2) = 5(2² – 1)
Evaluate
f(2) = 15
Substitute f(2) = 15 in [f(x) - f(2)]/[x - 2]
So, we have
[f(x) - f(2)]/[x - 2] = [5(x² – 1) - 15]/[x - 2]
Open the brackets
[f(x) - f(2)]/[x - 2] = [5x² – 5 - 15]/[x - 2]
Evaluate the like terms
[f(x) - f(2)]/[x - 2] = [5x² – 20]/[x - 2]
Factorize
[f(x) - f(2)]/[x - 2] = [5(x² – 4)]/[x - 2]
Express as difference of two squares
[f(x) - f(2)]/[x - 2] = [5(x – 2)(x + 2)]/[x - 2]
Divide
[f(x) - f(2)]/[x - 2] = 5(x + 2)
Limit x to 2
[f(x) - f(2)]/[x - 2] = 5(2 + 2)
Evaluate
[f(x) - f(2)]/[x - 2] = 20
Hence, the limit is 20
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The total distance a ball rolls varies directly with the time in seconds. The ball rolls a total distance of 78 centimeters in 6 seconds.
What is the time in seconds the ball rolls when the total distance is 130 centimeters?
10 s
13 s
22 s
25 s
The time the balls roll when the total distance is 130 cm is 10 seconds.
let
d = total distance the ball rolls
t = time in seconds
The total distance is directly proportional to the time in seconds. Therefore,
d ∝ t
d = kt
where
∝ is the proportionality sign
k = constant of proportionality
when d = 78 cm, t = 6 seconds
Therefore, let's find the constant of proportionality.
k = d / t
k = 78 / 6
k = 13
The constanst of proportionality is known . Now let's find the time(seconds) when d = 130 cm .
d = kt
make t the subject of the formula
t = d / k
t = 130 / 13
t = 10 secs
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Why do you think people who are good at math are usually successful on their jobs?
Which graph represents a proportional relationship?
Answe point me
Step-by-step explanation:
Answer:A
Step-by-step explanation:
URGENT!!!! Find the y-intercept of the line that passes through the points (-3, 7) and (3, −9).
Answer:
\(m = \frac{ - 9 - 7}{3 - ( - 3)} = \frac{ - 16}{6} = - \frac{8}{3} \)
\(7 = - \frac{8}{3} ( - 3) + b\)
\(7 = 8 + b\)
\(b = - 1\)
\(y = - \frac{8}{3} x - 1\)
The y-intercept is -1.
Find n if (n + 1)! = 16n! + 16(n-1)!
Step-by-step explanation:
(n+1)! = (n+1)n(n-1)(n-2)...×3×2
16n! = 16n(n-1)(n-2)...×3×2
16(n-1)! = 16(n-1)(n-2)...×3×2
we can now divide both sides by (n-1)! and get
(n+1)n = 16n + 16
n² + n = 16n + 16
n² - 15n - 16 = 0
1×n² - 15n - 16 = 0
we try to bring this into a form
(n + a)(n - b)
one factor has to contain "-", because we have "-16".
and because -15 = 1 - 16, we see that
a = 1
b = 16
n² - 15n - 16 = (n + 1)(n - 16)
and that is 0, when at least one of the factors is 0, because 0×... = 0.
so, the solutions are
n = -1
n = 16
n = -1 does not make any sense for n!
so, n = 16 is the solution.
Sally and Suzie both agree that m∠A + m∠B = 180⁰.
Sally claims ∠A and ∠B are supplementary.
Suzie claims ∠A and ∠B are not supplementary because they are not adjacent.
Who is correct?
Explanation:
The angles do not need to be touching, or adjacent, for them to be supplementary. They simply need to add to 180 degrees.
We have 70+110 = 180, so that proves the angles are supplementary. They can be rearranged to glue together to form a straight angle.
If the angles were supplementary and adjacent, then we can consider them as a linear pair. This is possibly what Suzie might be thinking about.
suppose we want to choose 3 letters without replacement from the 4 letters A,B,C,D
how many ways can this be done if the order of choices was taken into consideration.
how many ways can this be done if the order of choices was not taken into consideration
The number of ways if the order of the choices is taken into consideration is 24 and the number of ways if the order of the choices is not taken into consideration is 4
How to determine the number of ways if the order of the choices is taken into consideration?The given parameters are:
Letters, n = 4
Letters to select, r = 3
The order of the choices is taken into consideration.
This means permutation.
So, we have:
nPr = n!/(n -r)!
This gives
4P3 = 4!/1!
Evaluate the quotient
4P3 = 4!
Expand
4P3 = 4* 3 * 2 * 1
Evaluate
4P3 = 24
Hence, the number of ways if the order of the choices is taken into consideration is 24
How many ways can this be done if the order of choices is not taken into considerationThe given parameters are:
Letters, n = 4
Letters to select, r = 3
The order of the choices is not taken into consideration.
This means combination.
So, we have:
nCr = n!/r!(n -r)!
This gives
4C3 = 4!/(3! * 1!)
Expand
4C3 = 4 * 3!/(3! * 1!)
Evaluate the quotient
4C3 = 4
Hence, the number of ways if the order of the choices is not taken into consideration is 4
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A portfolio manager generates a 5% return in Year 1, a 12% return in Year 2, a negative 6% return in Year 3, and a return of 2% (nonannualized) in the first quarter in Year 4. The annualized return for the entire period is the closest to __________.
The annualized return for the entire period is the closest to 10.5%.
To calculate the annualized return for the entire period, we need to consider the returns for each year and the return in the first quarter of Year 4. Since the returns are given for each period, we can use the geometric mean to calculate the annualized return.
The formula for calculating the geometric mean return is:
Geometric Mean Return = [(1 + R1) * (1 + R2) * (1 + R3) * (1 + R4)]^(1/n) - 1
Where R1, R2, R3, and R4 are the returns for each respective period, and n is the number of periods.
Given the returns:
Year 1 return: 5% or 0.05
Year 2 return: 12% or 0.12
Year 3 return: -6% or -0.06
First quarter of Year 4 return: 2% or 0.02
Using the formula, we can calculate the annualized return:
Annualized Return = [(1 + 0.05) * (1 + 0.12) * (1 - 0.06) * (1 + 0.02)]^(1/3) - 1
Annualized Return = (1.05 * 1.12 * 0.94 * 1.02)^(1/3) - 1
Annualized Return = 1.121485^(1/3) - 1
Annualized Return ≈ 0.105 or 10.5%
Therefore, the annualized return for the entire period is approximately 10.5%.
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A restaurant is offering 15 percent off beverages. The check is $90.00 with the beverage total being $15.00. What is the check total after the discount ?
A 77.75
B 76.50
C.75.00
D.87.75
b because 90
15
15
-_____
76.50
Determine the equation of the line below using the given slope and point.
Slope = m = 4 , Point (-3,-11)
\((\stackrel{x_1}{-3}~,~\stackrel{y_1}{-11})\hspace{10em} \stackrel{slope}{m} ~=~ 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-11)}=\stackrel{m}{ 4}(x-\stackrel{x_1}{(-3)}) \implies y +11 = 4 ( x +3) \\\\\\ y+11=4x+12\implies {\Large \begin{array}{llll} y=4x+1 \end{array}}\)
The equation is:
⇨ y + 11 = 4(x + 3)Work/explanation:
Recall that the point slope formula is \(\rm{y-y_1=m(x-x_1)}\),
where m is the slope and (x₁, y₁) is a point on the line.
Plug in the data:
\(\rm{y-(-11)=4(x-(-3)}\)
Simplify.
\(\rm{y+11=4(x+3)}\)
Hence, the point slope equation is y + 11 = 4(x + 3).Simplified to slope intercept:
\(\rm{y+11=4x+12}\)
\(\rm{y=4x+1}\) <- this is the simplified slope intercept equation
algebra domain and range please help
Answer:
Option 2.
Step-by-step explanation:
Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.
Domain: \((- \infty} ,0)\) ∪ \((0, \infty} )\)
Range: \((- \infty} ,0)\)∪\((0, \infty} )\)
Find the area of a triangle with legs that are: 12 m, 15 m, and 9 m.
Answer:
108 meters squared or m^2
Step-by-step explanation:
* means multiply
15 is probably hypotenuse because its the longest
12 and 9 are probably base and height
area = base * height
area = 12 * 9
area = 108
Answer:
54m^2
Step-by-step explanation:
If a and b are two angles in standard position in Quadrant I, find cos(a-b) for the given function values. sin a=15/17and cos b=3/5
1) -84/85
2) -36/85
3) 36/85
4) 84/85
Answer:
3)
Step-by-step explanation:
I am one of the maths and they are called BODMAS
Answer:
1
Step-by-step explanation:
cosine of sum of 2 angles law
0.98 is answer 84/85
i think it is negative due to the fact that it is in quad I and cos is neg in quad I but I am not 100% on that
I’m dumb so can u pls help me
Answer:
(1, 6)
(2, 12)
(1.5, 9)
(2.5, 15)
#teamtrees #WAP (Water And Plant)
100 Points! Geometry question. Find x and y. Photo attached. Please show as much work as possible. Thank you!
The calculated values of x and y in the figure are x = 2 and y = 4
How to calculate x and y in the figurefrom the question, we have the following parameters that can be used in our computation:
The figure
Where, we have
equal side lengths
This means that
2y - 1 = 3y - 5
Evaluate
y = 4
Next, we have
x + 3 = 3/2x + 2
So, we have
1/2x = 1
This gives
x = 2
Hence, the values of x and y in the figure are x = 2 and y = 4
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Please help i rate 5 stars and give 50 points
Answer:
28. The total is 200, remove all the other known fruit frequencies to evaluate how frequently grapes was chosen.
Grapes = 200-102-26-30-20 = 22
29-32: Relative frequency is just the frequency of the individual divide by the total.
29. 20/200 = 1/10 = 0.1
30. 30/200 = 3/20 = 0.15
31. 102/200 = 51/100 = 0.51
32. 200/200 = 1
Which graph represents the function f (x) = StartFraction 1 Over x EndFraction minus 1?
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0, and the horizontal asymptote is at y = 1.
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 0.
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = negative 1, and the horizontal asymptote is at y = 0.
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0, and the horizontal asymptote is at y = negative 1.
Mark this and return
The correct answer is Option C. The graph represents the function f (x) = StartFraction 1 Over x EndFraction minus 1 is On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = negative 1, and the horizontal asymptote is at y = 0.
On a coordinate plane, the graph of a hyperbola is shown.
In quadrant 1, one curve opens up and to the right, while in quadrant 3, the other curve opens down and to the left.
The vertical asymptote is at x = -1, and the horizontal asymptote is at y = 0. This hyperbola is symmetrical across both the x and y axes.
The function f(x) = 1/x - 1 has a vertical asymptote at x = 0 because the denominator approaches zero as x approaches zero.
A fraction with a denominator of zero cannot exist.
The horizontal asymptote of this function is y = -1 because as x approaches infinity or negative infinity, f(x) approaches -1.
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a school is having a pizza party. each pizza is cut into 12 slices. which explains whether it is better to estimate a greater or lesser number than the actual number of people that will eat pizza
Answer:
they said each pizza
Step-by-step explanation:
that means it isn't only one pizza but maybe a ton of them
Plz help it’s due today
Answer:
From left to right:
1/8
5/8
1-3/16
1-7/8
2-1/2
3-1/8
4-3/8
5-3/8
5-7/8
1st question answer pls
let's take a peek at the picture above, hmmm let's notice the vertex is at (-1 , 2), now let's get a point besides the vertex hmmm let's see it passes through (-2 , -1).
So we can reword that as what's the equation of a quadratic whose vertex is at (-1 , 2) and it passes through (-2 , -1)?
\(~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{a~is~negative}{op ens~\cap}\qquad \stackrel{a~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\)
\(\begin{cases} h=-1\\ k=2\\ \end{cases}\implies y=a(~~x-(-1)~~)^2 + 2\hspace{4em}\textit{we also know that} \begin{cases} x=-2\\ y=-1 \end{cases} \\\\\\ -1=a( ~~-2-(-1) ~~ )^2 + 2\implies -3=a(-2+1)^2\implies -3=a \\\\\\ ~\hfill~ {\Large \begin{array}{llll} y=-3(x+1)^2 + 2 \end{array}} ~\hfill~\)
Answer:
y = -3(x + 1)^2 + 2
Step-by-step explanation:
y = a(x - h)^2 + k is the vertex form of a quadratic, where
(x, y) are any point that lies on the parabola,a is a constant determining whether the parabola opens upward or downward,and (h, k) are the coordinates of the vertex.Finding (h, k):
We see from the graph that the vertex is a maximum and its coordinates are (-1, 2). Thus h is -1 and k is 2. Since h becomes negative, it will be 1 in the parentheses: (x - (-1) = (x + 1).
Finding a:
In order to find a, we will need to plug in a point on the parabola for (x, y) and (-1, 2) for h and k. We see that (0, -1) lies on the parabola so we can use this point for (x, y).
-1 = a(0 - (-1))^2 + 2
-1 = a(0 + 1)^2 + 2
-3 = a(1)^2
-3 = a
Thus, a = -3.
Thus, the exact equation in vertex form of the parabola is:
y = -3(x + 1)^2 + 2
I attached a picture from Desmos Graphing Calculator that shows how the equation I provided works and contains the two points you marked on the parabola, including (-1, 2) aka the maximum, and (0, -1) aka the y-intercept.
A Bakery made 423 sandwiches in one day. What is that number rounded to the nearest hundred sandwiches?
Answer: 400
Step-by-step explanation:
Consider the following equation.
7−6y=−38−5x
Find the x- and y-intercepts, if possible.
Help with the problem below. Id like to know how to do it please!
The values of the side lengths for the right triangle are x = 3√3, y = 12, and z = 4√7
How to evaluate for the values of the right triangle side lengthsThe vertical height of the right triangle divides the triangle in two triangles with the same proportions as the original triangle.
So;
9/y = y/16 {adjacent/hypotenuse ratio}
y² = 9 × 16 {cross multiplication}
y = √144
y = 12
using Pythagoras rule;
x² + 9² = 12²
x² = 144 - 81 {collect like terms}
x² = 63
x = √63 = 3√7
Also;
z² = (√63)² + 7²
z² = 63 + 49
z² = 112
z = √112 = 4√7
Therefore, the values of the side lengths for the right triangle are x = 3√3, y = 12, and z = 4√7
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A bucket contains 72 red, 48 blue, 48 green, and 48 yellow crayons. The art teacher also has 120 pieces of drawing paper. What is the largest number of identical kits the art teacher can make with all of the crayons and all of the paper?
The art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper for proper distribution.
To determine the largest number of identical kits the art teacher can make using all the crayons and drawing paper, we need to find the greatest common divisor (GCD) of the quantities.
The GCD represents the largest number that can divide all the quantities without leaving a remainder.
The GCD of the quantities of crayons can be found by considering the prime factorization:
72 = 2³ × 3²
48 = 2⁴ × 3
48 = 2⁴ × 3
48 = 2⁴ × 3
The GCD of the crayons is 2³ × 3 , which is 24.
Now, we need to find the GCD of the quantity of drawing paper:
120 = 2³ × 3 × 5
The GCD of the drawing paper is also 2³ × 3 , which is 24.
Since the GCD of both the crayons and drawing paper is 24, the art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper.
Each kit would contain an equal distribution of crayons and drawing paper.
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