Find the distance between the points (4, 6) and (2, -6). Round to the nearest tenth.
a.3.7
b. 12.2
c.14d.
d.148

Answer:

perpendicular is 5/4 (fraction)

parallel is -4/5 (fraction)

Step-by-step explanation:

Answer:

Can you be more specific if you can I will answer in the comments :)

Step-by-step explanation:

Answer:

x = 1

y = -1

Step-by-step explanation:

A*B= (4y-8 3x-3)

1-) (4×2)+(3×y)= 3y+8

2-) (4×x)+(3×(-1))= 4x-3

AB=C

(3y+8 4x-3)=(5 1)

So

3y+8=5 ; y= -3/3 = -1

4x-3=1 ; x=4/4 =1

The area of the smaller sector is 76.9 degrees.

The area of the smaller sector can be found as follows:

Therefore,

area of a sector = ∅/ 360 × πr²

where

Therefore,

∅ = 77 degrees

r = 10.7 inches

area of the sector = 77 / 360 × 3.14 × 10.7²

area of the sector = 77 / 360 × 3.14 × 114.49

area of the sector = 27681.3922 / 360

area of the sector = 76.8927561111

area of the sector = 76.9 degrees

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Answer:

No solution.

Step-by-step explanation:

The two lines are parallel and will never meet. Therefore, they have no solution.

Answer:

Answer is B because 24 divided by 3 is 8

Step-by-step explanation:

Nillllll

Step-by-step explanation:

Parallel lines cut by a transversal coloring activity is an activity that helps students understand the pattern of angles when parallel lines are cut by a transversal. The activity involves coloring the angles formed by the parallel lines and the transversal in different colors. This helps students identify the different types of angles formed and their relationships with each other.

The two consecutive even numbers are 4 and 6.

A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.

Integers are numbers that have a denominator of 1. Integers are of two types one is a negative integer and another is a positive integer.

Let the two consecutive even integers be n and (n + 2).

Given, Three times the larger of two consecutive even integers is ten more than the smaller which can be numerically expressed as,

3(n + 2) = n + 10.

3n + 6 = n + 10.

3n - 2n = 10 - 6.

n = 4 and hence (n + 2) = 6.

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The first partial derivatives of the function W = \(xye^z9\) are:

∂W/∂x = 9,

∂W/∂y = 5,

∂W/∂z = 45.

To find the first partial derivatives of the function W = xye^z9 and evaluate each at the point (5, 9, 0), we differentiate the function with respect to each variable separately.

Differentiating \(W = xye^z9\)with respect to x while treating y and z as constants, we get:

∂W/∂x =\(ye^z9\)

Differentiating W = xye^z9 with respect to y while treating x and z as constants, we get:

∂W/∂y =\(x * e^z9\)

Differentiating W = xye^z9 with respect to z while treating x and y as constants, we get:

∂W/∂z = \(9xye^z9\)

Now, we evaluate each partial derivative at the given point (5, 9, 0):

∂W/∂x (5, 9, 0) = \(9e^09 = 9\)

∂W/∂y (5, 9, 0) = \(5 * e^09 = 5\)

∂W/∂z (5, 9, 0) = \(9 * 5 * e^09 = 45\)

Therefore, at the point (5, 9, 0), the values of the partial derivatives are:

∂W/∂x = 9,

∂W/∂y = 5,

∂W/∂z = 45.

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Therefore , the solution of the given problem of coordinates comes out to be x =8 and y =4 as (8,4) is the midpoint of the given line.

Using one or more values or coordinates, a coordinate system is a geometry approach used to better able to monitor points or any other topological items on a spectrum, such as Euclidean space. The coordinates of a point or object on a double plane are a pair of integers. A point's placement on a 2D plane is specified by two integers called the x and y coordinates. a set of integers indicating precise locations. The figure typically includes two numbers.

Here,

given :

Points  = C(8,6) and D(8,2).

Thus ,

For midpoint:

=> x = (x1 + x2) /2

=>  x = (8 + 8 )/2

=> x =16/2

=> x = 8

For y :

=> y = (y1 + y2) /2

=> y = (6 +2) /2

=> y = 8/2

=> y =4

Therefore , the solution of the given problem of coordinates comes out to be x =8 and y =4 as (8,4) is the midpoint of the given line.

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Answer:

B

Step-by-step explanation:

This is proportional because the number of calories burned is directly proportional to the amount of time spent on the treadmill

There are 123 different possibilities. Therefore, we can derive from the multiplication principle that there are 13(123) ways.

Probability: The branch of mathematics known as probability deals with numerical expressions of the probability that an event will occur, or the probability that a statement will be true.

The probability of an event is a number between 0 and 1, with approximately 0 meaning improbability and 1 meaning certainty.

The probability of an event occurring increases with its probability. A simple example is tossing a fair (fair) coin.

Both outcomes (heads and tails) have equal probability, the coin is fair, heads are more likely than tails, there are no other possible outcomes, and either outcome has half the probability.

According to our question:

Let n be the maximum number of subsets of 5 elements that can be chosen from the first 14 natural numbers,

where at least 2 of the 5 digits are consecutive.

We created a block of two consecutive numbers ((1,2), (2,3), (13,14), etc.).

Now you can select this block in 13 different ways. You have to choose 3 numbers from the remaining 12 numbers.

So, from the multiplication principle, we know that we have 13 × (123).

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(a) The probability that a given non-infected person comes in contact with a zombie is P(contact with zombie | X+ = i) = 1 - (1 - p)^i.

(b) The pair (Xt, Yt) is a Markov chain and the transition probabilities are the transition from (i,j) to (i+1,j-1) and the transition from (i,j) to (i,j+1).

(c) The distribution of X2 is P(X2 = k) = ∑((N-1 choose i)p^i(1-p)^(N-1-i)pk-i(1-p)N-k+i) for i = 0 to N-1.

(a) If X+ = i, the number of zombies on day t, then the probability that a given non-infected person comes in contact with a zombie during day t is given by the expression:

P(contact with zombie | X+ = i) = 1 - (1 - p)^i

This is because the probability that a given non-infected person does not come in contact with any of the i zombies is (1-p)^i, and therefore the probability that he or she does come in contact with at least one zombie is 1 minus this probability.

(b) The pair (Xt, Yt) is a Markov chain, where the state space is S = {(i,j) | 0 ≤ i ≤ N, 0 ≤ j ≤ N-i}. The transition probabilities are given by:

P((i,j) → (i+1,j-1)) = pij(1-p)j

P((i,j) → (i,j+1)) = 1 - ∑(pij(1-p)j) for i=0 to N-1

The first equation represents the transition from (i,j) to (i+1,j-1), meaning one zombie is cured and one non-infected person becomes a zombie. The second equation represents the transition from (i,j) to (i,j+1), meaning no zombie is cured and a non-infected person does not become a zombie.

(c) Suppose X0 = 1, Yo = N - 1. Then, the distribution of X2 is given by:

P(X2 = k) = ∑(P(X2 = k | X1 = i)P(X1 = i | X0 = 1, Y0 = N - 1)) for i = 0 to N-1

Using the Markov chain transition probabilities from part (b), we have:

P(X2 = k | X1 = i) = P((i,k-i) | (1,N-1)) = P((i,k-i) → (k,k-(k-i))) = pk-i(1-p)N-k+i

Therefore, we can write:

P(X2 = k) = ∑(pk-i(1-p)N-k+iP(X1 = i | X0 = 1, Y0 = N - 1)) for i = 0 to N-1

To find P(X1 = i | X0 = 1, Y0 = N - 1), we note that the conditional distribution of X1 given X0 = 1, Y0 = N - 1 is a binomial distribution with parameters N-1 and p. Thus:

P(X1 = i | X0 = 1, Y0 = N - 1) = (N-1 choose i)p^i(1-p)^(N-1-i)

Therefore, we can write:

P(X2 = k) = ∑((N-1 choose i)p^i(1-p)^(N-1-i)pk-i(1-p)N-k+i) for i = 0 to N-1

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Answer: Check out the diagram below

\(1.5 \le x \le 5.5\)

The lengths can be between   4   and   12   units

=======================================================

Explanation:

Let's find an expression that represents the area.

The length is 2x+1 and the width is 3. Multiply those two and we get

3(2x+1) = 6x+3

The area is 6x+3 square units.

In other words, A = 6x+3 represents the area.

------------------

We're then told that \(12 \le A \le 36\) saying that the area is between 12 and 36 square units (including both endpoints).

We'll replace the A with 6x+3 and solve for x like so:

\(12 \le A \le 36\\\\12 \le 6x+3 \le 36\\\\12-3 \le 6x+3-3 \le 36-3 \ \text{ .... see note1}\\\\9 \le 6x \le 33\\\\\frac{9}{6} \le \frac{6x}{6} \le \frac{33}{6} \ \text{ .... see note2}\\\\\frac{3}{2} \le x \le \frac{11}{2}\\\\1.5 \le x \le 5.5\\\\\)

note1: I subtracted 3 from all sides to undo the "plus 3"

note2: I divided all sides by 6 to undo the multiplication

------------------

We just found that \(1.5 \le x \le 5.5\\\\\) so it says that x is between 1.5 and 5.5 including both endpoints.

Plug in the smallest possible x value to find the smallest possible length

length = 2x+1

L = 2(1.5)+1

L = 3+1

L = 4

The smallest possible length is 4 units. Multiply this with the height 3 and we get L*W = 4*3 = 12 which is the smallest possible area.

------------------

Now use x = 5.5 to find the largest value of L possible

L = 2x+1

L = 2(5.5)+1

L = 11+1

L = 12

Then note how L*W = 12*3 = 36 is the max area possible, which matches with that your teacher wrote. So this confirms we have the correct value.

If you're not sure which values go where, check out the diagram below.

Answer:

Your answer is <, Hope it helps.

4) ∠9 and ∠16 - C - Alternative Exterior Angles

5) ∠3 and ∠5 - D - Consecutive Interior Angles

6) ∠7 and ∠15 - F  - No relationship

7) ∠1 and ∠ 10 -  F - No Relationship

8) ∠2 and ∠11 - F - No relationship

9) The transversal that connects ∠6 and ∠13 is S

A transversal is a line in geometry that connects two lines in the same plane at two separate places. Transversals help determine if two or more lines in the Euclidean plane are parallel.

When a transversal connects two parallel lines, the corresponding angles are equal.

If a transversal connects two lines with equal matching angles, the two lines are parallel to one other.

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The class that lost the most pencils overall based on the data displayed is D. Mr. Johnson's class; it has a wide spread in the data

The answer is Mr. Johnson's class. The median is the middle value in a set of data. In Mr. Johnson's class, the median is 11 pencils. This means that half of the students in his class lost 11 or fewer pencils, and half of the students lost 11 or more pencils.

In Mr. Simpson's class, the median is 14.5 pencils. This means that half of the students in his class lost 14.5 or fewer pencils, and half of the students lost 14.5 or more pencils.

Since the median for Mr. Johnson's class is lower than the median for Mr. Simpson's class, we can conclude that Mr. Johnson's class lost more pencils overall.

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If A coaxial cable with a = 0.25 mm, b = 2.50 mm, c = 3.30 mm, ϵr = 2.0, μr = 1, σc = 1.0 × 107 s/m, σ = 1.0 × 10−5 s/m, and f = 300 mhz then r,l,c, and g are approximately 0.001273 Ω/m, 0.622 μH/m, 67.17 pF/m, and 0.01339 S/m, respectively.

To find the values of r, l, c, and g for the given coaxial cable, we can use the following formulas:

r = ρ/2πaσc

l = μr/2π * ln(b/a)

c = 2πϵr/ln(b/a)

g = 2πaσ/ln(b/a)

where ρ is the resistivity of the cable's material.

To find ρ, we can use the formula: ρ = 1/σc

Substituting the given values, we get: ρ = 1/1.0 × 107 = 1.0 × 10^-7 Ωm

Substituting this value and the other given values into the formulas above, we get:

r = (1.0 × 10^-7)/(2π × 0.25 × 1.0 × 10^-5) ≈ 0.001273 Ω/m

l = 1/2π * ln(2.50/0.25) ≈ 0.622 μH/m

c = 2π × 2.0/ln(2.50/0.25) ≈ 67.17 pF/m

g = 2π × 0.25 × 1.0 × 10^-5/ln(2.50/0.25) ≈ 0.01339 S/m

Therefore, the values of r, l, c, and g for the given coaxial cable are approximately 0.001273 Ω/m, 0.622 μH/m, 67.17 pF/m, and 0.01339 S/m, respectively.

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Although part of your question is missing, you might be referring to this full question: If the 1st person saves 1/4 of total, 2nd person saves 2/3 of total, and 3rd person saves 1/10, which fraction left to pay for the birthday party?

The fraction left to pay for the birthday party is 17/30.

The calculation is as follows:

1 * 1/4 = 1/4 … (1)

1/4 * 2/3 = 2/12 … (2)

2/12 * 1/10 = 2/120 … (3)

Fraction left to pay:

= 1 - (1/4 + 2/12 + 2/120)

= 1 - (30/120 + 20/120 + 2/120)

= 1 - (52/120)

= 1 - 13/30

= 30/30 - 13/30

= 17/30

Thus, the fraction left to pay for the birthday party is 17/30.

A fraction is a part of a whole. In arithmetic, the number is expressed as a quotient, where the numerator is divided by the denominator. In a simple fraction, both are integers. A complex fraction has a fraction in the numerator or denominator. In a proper fraction, the numerator is less than the denominator.

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Answer:

greater than

Step-by-step explanation:

positive is higher than negative

Answer: 4/3 in

Step-by-step explanation:

1/5 : 3

x : 20

1/5 * 20/3 = 4/3, so it would be 4/3 inches on the blueprint.

We have to solve this equation by completing the square.

We have two terms from the quadratic equation: x² + 14x, so we can add the third term as:

We add the same term to both sides of the equation to preserve the equality.

We now can continue solving the equation as:

This equation does not have solutions for x for the set of real values, as we have a square root of a negative number.

We can express the solution as complex numbers as:

Answer: the solutions for the equation are x = -7 - 2(√5)i and x = -7 + 2(√5)i.

If the average of three numbers is 16 and one of the numbers is 18, then the sum of the other two numbers is option (d) 30

Let's use algebra to solve this problem. Let x and y be the other two numbers we are looking for. We know that the average of the three numbers is 16, so we can write:

(18 + x + y) / 3 = 16

Multiplying both sides by 3, we get,

[(18 + x + y) / 3] × 3 = 16 ×3

18 + x + y = 48

Subtracting 18 from both sides, we get,

18 + x + y - 18 = 48

x + y = 30

Therefore, the correct option is (d) 30

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The value of angle A is 58° and Angie B is 122°.

It's important to note that the value of the supplementary angles equals to 80°.

In this situation, ZA and B are m/A= (2x - 20)° mB= (3x + 5)° supplementary.

This will be:

2x - 20 + 3x + 5 = 180

5x = 180 + 15

5x = 195

Divide

x = 195 / 5

x = 39

Angle A = 2x - 20 = 2(39) - 20

= 58

Angle B = 3x + 5 = 3(39) + 5

= 122°

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The second vector that's perpendicular to the line we want (call it L) is missing; I'll denote it by ⟨a, b, c⟩.

The cross product of ⟨1, 1, 0⟩ and ⟨a, b, c⟩ is perpendicular to both of these vectors. The direction vector of L will be parallel to this cross product.

Compute the cross product.

⟨1, 1, 0⟩ × ⟨a, b, c⟩ = ⟨1•c - 0•b, 0•a - 1•c, 1•b - 1•a⟩ = ⟨c, -c, b - a⟩

Then the vector equation of L is

L(t) = ⟨c, -c, b - a⟩ t + ⟨-3, 3, -1⟩

As parametric equations, we write

x(t) = ct - 3

y(t) = -ct + 3

z(t) = (b - a) t - 1

Eliminating the parameter above, we get

x + y = (ct - 3) + (-ct + 3) = 0   ⇒   x = -y

and substituting

x = ct - 3   ⇒   t = (x + 3)/c

into z(t), we get

z = (b - a) (x + 3)/c - 1   ⇒   x = c (z + 1)/(b - a) - 3

As symmetric equations, then, we write

x = -y = c (z + 1)/(b - a) - 3

The error in the distance if the uppermost portion of a 3. 0m long stadia rod is inclined 14 cm toward the observer and the rod intercept is 1. 75m on a horizontal sight is 8.167cm.

The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. it is given as,

Tan(θ) = Perpendicular/Base

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The base is the adjacent smaller side of the angle θ.

Given the uppermost portion of a that is 3.0m long stadia rod is inclined 14 cm toward the observer, therefore, the angle of inclination, θ can be written as

tan(θ)=0.14/3

θ = 2.672°

Also, the rod intercept is 1.75m, therefore, t the error in distance in the distance is,

tanθ=x/1.75

x = 1.75 tan(θ)

x = 1.75 × tan(2.672°)

x = 0.08167 m = 8.167 cm

Hence, the error in the distance if the uppermost portion of a 3. 0m long stadia rod is inclined 14 cm toward the observer and the rod intercept is 1. 75m on a horizontal sight is 8.167cm.

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To find y' using implicit differentiation for the equation xy + 12 = 0, we differentiate both sides of the equation with respect to x. Y after implicit differentiation is 4/-3. After evaluation, Y'(4,-3) got 3/4.

Differentiating xy with respect to x involves applying the product rule. Let's differentiate each term separate The derivative of x with respect to x is 1.

The derivative of y with respect to x involves treating y as a function of x and differential accordingly. Since y' represents dy/dx, we can write it as dy/dx = y'.

Taking the derivative of y with respect to x, we get y'. Differentiating 12 with respect to x gives us 0 since it is a constant. Putting it all together, the differentiation of xy + 12 becomes y + xy' = 0. To solve for y', we can isolate it: y' = -y/x.

Now, to evaluate y' at the point (4, -3), we substitute x = 4 and y = -3 into the equation y' = -y/x: y' = -(-3)/4 = 3/4 Therefore, at the point (4, -3), the derivative y' is equal to 3/4.

The simplified answer for y' at (4, -3) is 3/4.

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The simplified answer for y' at (4, -3) is 3/4.

Here, we have,

To find y' using implicit differentiation for the equation xy + 12 = 0, we differentiate both sides of the equation with respect to x. Y after implicit differentiation is 4/-3. After evaluation, Y'(4,-3) got 3/4.

Differentiating xy with respect to x involves applying the product rule. Let's differentiate each term separate The derivative of x with respect to x is 1.

The derivative of y with respect to x involves treating y as a function of x and differential accordingly. Since y' represents dy/dx, we can write it as dy/dx = y'.

Taking the derivative of y with respect to x, we get y'. Differentiating 12 with respect to x gives us 0 since it is a constant. Putting it all together, the differentiation of xy + 12 becomes y + xy' = 0. To solve for y', we can isolate it: y' = -y/x.

Now, to evaluate y' at the point (4, -3), we substitute x = 4 and y = -3 into the equation y' = -y/x: y' = -(-3)/4 = 3/4 Therefore, at the point (4, -3), the derivative y' is equal to 3/4.

The simplified answer for y' at (4, -3) is 3/4.

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Answer: 66

Step-by-step explanation:

0 - 12 = -12

54--12 = 66

66 is the difference

Answer:

A

Step-by-step explanation: