The general solution is the sum of the complementary and particular solutions: y(t) = c1e9t + c2e-2t + (3t² - 2t)
To find the general solution of the differential equation y" – 7y' – 18y = –26t + 36t², we have to follow the given steps: First, let us write the auxiliary equation associated with the given differential equation as (m - 9) (m + 2) = 0. We get m = 9 and m = -2.
Hence, the general solution of the given differential equation is given by:y(t) = c1e9t + c2e-2t + (3t2 - 2t). Therefore, y(t) = c1e9t + c2e-2t + (3t² - 2t) is the general solution of the given differential equation.
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Micah is saving for a new skateboard. It costs $65, including tax. Micah has already saved $37. What in the equation?
Answer:
x + 37 ≥ 65
Step-by-step explanation:
Given:
Money Micah wants = $65
Money Micah had = $37
Find:
Money Micah need
Computation:
Money Micah need(x)
x + 37 ≥ 65
So,
Money Micah need = 65 - 37
Money Micah need = $28
The country of Phoenicia does not trade with any other country. Its 60P is $22 billion. Its government purchases $7 billion worth of goods and services each year, collects $7 billion in taxes, and provides $2 billion in transfer payments to households. Private saving in Phoenicia is $5 billion. a. What is Phoenicia's censumption? b. What is the country's investment? c. Does the country's government run a budget surplus or a budget deficit? 3) You rist thow all tive shops and colcuintions to receime ful polits 4) You may watte ty hand of tipe the arivewes
a) Consumption = $17 billion.
b) Investment = $6 billion.
c) Phoenicia's government runs a budget deficit.
a. To find Phoenicia's consumption, we can use the equation:
Consumption = 60
P - Private Saving.
Given that private saving is $5 billion, and 60P is $22 billion, we can calculate:
Consumption = $22 billion - $5 billion
= $17 billion.
b. To find the country's investment, we need to subtract government purchases, transfer payments, and taxes from the GDP.
Since the government purchases are $7 billion, transfer payments are $2 billion, and taxes are also $7 billion, we can calculate:
Investment = GDP - (Government purchases + Transfer payments + Taxes)
= $22 billion - ($7 billion + $2 billion + $7 billion)
= $6 billion.
c. To determine if the government runs a budget surplus or a budget deficit, we can compare government purchases, transfer payments, and taxes.
Given that government purchases are $7 billion, transfer payments are $2 billion, and taxes are also $7 billion, we can calculate:
Budget surplus/deficit = Taxes - (Government purchases + Transfer payments)
= $7 billion - ($7 billion + $2 billion)
= -$2 billion.
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BRAINLIST
Question 1
1 pts
Last Friday Zainab had $23. Over the weekend she received some money for
a good report card. She now has $41. How much money did she receive?
Which equation represents this problem?
O 41 x 23 - z
OZ + 23 =41
O 23 + 41 = 2
Oz/23 = 41
A number, n, rounded to one. is 2.7. place Complete the inequality to show the lower and bounds upper of Is n decimal □
The number n must be greater than or equal to 2.65 and less than 2.75 in order to round to 2.7 when rounded to one decimal place
If a number n rounded to one decimal place is 2.7, then we know that n lies between two numbers:
The lower bound is the number that is 0.05 less than 2.7, which is 2.65 (since the digit in the second decimal place is 5 or greater, we round up the last digit in the first decimal place).
The upper bound is the number that is 0.05 greater than 2.7, which is 2.75 (since the digit in the second decimal place is 5 or greater, we round up the last digit in the first decimal place).
Therefore, we can write the inequality as:
2.65 ≤ n < 2.75
This means that n must be greater than or equal to 2.65 and less than 2.75 in order to round to 2.7 when rounded to one decimal place.
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May you please help me. No links please.
i try to get the answer but it comes up all confusing so no one can answer.
Answer:
just guess it there a 50% you get it right \( ̄︶ ̄*\))
Step-by-step explanation:
find the interval of convergence for the given power series. [infinity] ∑ n = 1 ( x − 7 ) n n ( − 9 ) n
Answer : The interval of convergence is (-2/9+7, 20/9+7), which simplifies to (61/9, 209/9).
To find the interval of convergence of the given power series, we can use the ratio test. The ratio test states that if lim |(a_n+1)/(a_n)| = L, then the series converges absolutely if L < 1 and diverges if L > 1.
In this case, we have a_n = (x-7)^n / (n*(-9)^n), so a_n+1 = (x-7)^(n+1) / ((n+1)*(-9)^(n+1)). Taking the ratio of a_n+1 and a_n and simplifying, we get:
|(a_n+1)/(a_n)| = |(x-7)*(-9)/((n+1)*n)|
Taking the limit as n approaches infinity, we get:
lim |(a_n+1)/(a_n)| = |(x-7)*(-9)/n^2|
If |(x-7)*(-9)/n^2| < 1, then the series converges absolutely. Solving for x, we get:
|x-7| < 1/9 * sqrt(n^2)
|x-7| < n/9
So the interval of convergence is (-2/9+7, 20/9+7), which simplifies to (61/9, 209/9). Therefore, the power series converges absolutely for all x in this interval.
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Solve the equation cos x - xe =0 in the interval [0,1]. Use the results of the bisection method in the 10th iteration. O 0.617 O 0.517 O 0.527 O none of the choices
After the 10th iteration, the estimated value of the root obtained by the bisection method is approximately 0.517. Option B
To solve the equation cos(x) - x * e = 0 in the interval [0, 1] using the bisection method, we start by checking the function values at the endpoints of the interval.
For x = 0:
cos(0) - 0 * e = 1 - 0 = 1
For x = 1:
cos(1) - 1 * e ≈ 0.54 - 2.72 ≈ -2.18
Since the function values at the endpoints have opposite signs, we can apply the bisection method to find the root within the interval.
The bisection method involves repeatedly dividing the interval in half and checking the function value at the midpoint until a sufficiently accurate approximation is obtained. In this case, we will perform 10 iterations.
After the 10th iteration, the estimated value of the root obtained by the bisection method is approximately 0.517.
Therefore, the correct answer is OB) 0.517.
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Can someone please help me
Find EF
Answer:
Step-by-step explanation:
Remark
The relationship that solves this is
The outside segment * the whole length of the secant = the outside segment of the other secant * the whole length of the second secant.
Put in symbolic (and hence easier language)
GF * EG = HG * SG
Givens
GF = 4
EG = 2x + 4
GH = 5
SG = x + 5
Equation
4*(2x + 4) = 5*(x + 5) Remove the brackets
8x + 16 = 5x + 25 Subtract 5x from both sides
8x - 5x + 16 = 25 Combine
3x + 16 = 25 Subtract 16 from both sides
3x = 25 - 16
3x = 9 Divide by 3
3x/3 = 9/3
x = 3
EF = 2 * 3
EF = 6
Find the volume of the solid that lies within the sphere x2 y2 z2=1, above the xy plane, and outside the cone z=√(8x2/y2.
The volume of the solid that lies within the sphere x2 y2 z2=1, above the xy plane, and outside the cone z=√(8x2/y2 is 4π/5.
To solve the problem, we first need to find the limits of integration. The cone intersects the sphere at z=√(8x2/y2) and x2 + y2 + z2 = 1, so we can solve for y in terms of x and z:
x2 + y2 + z2 = 1
y2 = 1 - x2 - z2
y = ±√(1 - x2 - z2)
We only need the upper half of the sphere, so we take the positive square root:
y = √(1 - x2 - z2)
Since the cone is defined by z=√(8x2/y2), we can substitute this into the equation for y to get:
√(1 - x2 - z2) = √(8x2/(z2 - x2))
Squaring both sides gives:
1 - x2 - z2 = 8x2/(z2 - x2)
(z2 - x2) - x2 - z2 = 8x2
2x2 + 2z2 = z2 - x2
3x2 = z2
So the cone intersects the sphere along the curve 3x2 = z2. Since we are only interested in the portion of the sphere above the xy plane, we can integrate over the region x2 + y2 ≤ 1, 0 ≤ z ≤ √(3x2):
∫∫∫V dV = ∫∫R ∫0^√(3x^2) dz dA
where R is the region in the xy-plane given by x2 + y2 ≤ 1. We can switch to cylindrical coordinates by letting x = r cos θ, y = r sin θ, and dA = r dr dθ, so the integral becomes:
∫0^2π ∫0^1 ∫0^√(3r^2) r dz dr dθ
Evaluating the inner integral gives:
∫0^√(3r^2) r dz = 1/2 (3r^2)^(3/2) = 3r^3/2
Substituting back and evaluating the remaining integrals gives:
∫0^2π ∫0^1 3r^3/2 dr dθ = 2π ∫0^1 3r^3/2 dr = 2π [2/5 r^(5/2)]_0^1 = 4π/5
So, the volume of the solid is 4π/5.
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If you roll a regular die 5 times what is the probability of rolling a 6 at least twice?
Answer:
0.03215.
Step-by-step explanation:
Evaluate. 12/3+3/4÷(−1/3)−1/2
The fraction 12/3+3/4÷(−1/3)−1/2is evaluated to give -114/10
What is a fraction?A fraction can be defined as part of a whole element, variable or number
The several types of fractions in mathematics are;
Mixed fractionsProper fractionsImproper fractionsSimple fractionsComplex fractionsFrom the information, we have that;
12/3+3/4÷(−1/3)−1/2
The fraction given is a mixture of proper fractions and improper fractions
Expand the bracket, we get;
12/3 + 3/4 ÷ -1/3 -1/2
Find the lowest common denominator
48 + 9 /12 ÷ -2 - 3 /6
Add the numerators
57/12 ÷ -5/6
Take the inverse of the divisor and multiply
57/12 × 6/-5
-114/10
Hence, the value evaluated from the fraction is -114/10
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please can i have some help, just on this question, thank you so much!
Answer:
a) 1/2 of 12 = 1/4 of 24
b) 1/3 of 90 = 2/3 of 45
Step-by-step explanation:
1/2 of 16 is 6, so 6 would be 1/4 of what? 6 x 4 = 24. 6 is 1/4 of 24. The other one is the same. 1/3 of 90 is 30, and 30 is 2/3 of 45.
A treasure map says that a treasure is buried so that it partitions the distance between a rock and a tree in a 5:9 ratio. Marina traced the map onto a coordinate plane to find the exact location of the treasure. x = (StartFraction m Over m n EndFraction) (x 2 minus x 1) x 1 y = (StartFraction m Over m n EndFraction) (y 2 minus y 1) y 1 What are the coordinates of the treasure? If necessary, round the coordinates to the nearest tenth. (11.4, 14.2) (7.6, 8.8) (5.7, 7.5) (10.2, 12.6)
Answer:
(B) 7.6, 8.8
Step-by-step explanation:
u are welcome
Answer:
B.(7.6, 8.8)
Step-by-step explanation:
What happened to the owl who swallowed a watch
Answer:WAIT HE IS TELLING THE TIME
Step-by-step explanation:
Quantitative Problem 1t You deposit \( \$ 2,300 \) into an account that pays \( 6 \% \) per year. Your plan is to withdraw this amount at the end of 5 years to use for a down payment on a new car. How
You will be able to withdraw approximately $3,076.32 at the end of 5 years.
To calculate the amount you will be able to withdraw at the end of 5 years, we can use the future value formula for compound interest.
The formula for calculating the future value (FV) of a present value (PV) invested at an annual interest rate (r) for a certain number of years (t) is:
\(FV = PV * (1 + r)^t\)
Given:
PV = $2,300
r = 6% = 0.06 (decimal representation)
t = 5 years
Substituting these values into the formula, we get:
FV = $2,300 * \((1 + 0.06)^5\)
Calculating the expression inside the parentheses:
\((1 + 0.06)^5 = 1.338225\)
Multiplying the present value by this factor:
FV = $2,300 * 1.338225
FV ≈ $3,076.32
Therefore, you will be able to withdraw approximately $3,076.32 at the end of 5 years.
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You deposit $2,300 into an account that pays 6% per year. Your plan is to withdraw this amount at the end of 5 years to use for a down payment on a new car. How much will you be able to withdraw at the end of 5 years? Do not round intermediate calculations. Round your answer to the nearest cent
Enter the values needed to find thelength CB. (Simplify your answer.)A(-3a, b)IFB(3a, b)ECB = V(4a)2 + ([?])2C(-a, -5b)Distance Formula: d = (x2 – xı)2 + (y2 - yı)2
We are asked to find the values needed for the length CB
The coordinates of points C and B are given as
C(-a, -5b)
Recall that the distance formula is given by
\(d=\sqrt{\left( {x_2 - x_1 } \right)^2 + \left( {y_2 - y_1 } \right)^2 }\)For the given case,
\(\begin{gathered} (x_1,y_1)=\mleft(-a,-5b\mright) \\ (x_2,y_2)=\mleft(3a,b\mright) \end{gathered}\)Let us substitute these coordinates into the above distance formula
\(\begin{gathered} CB=\sqrt[]{({x_2-x_1})^2+({y_2-y_1})^2} \\ CB=\sqrt[]{({3a_{}-(-a)})^2+({b_{}-(-5b)_{}})^2} \\ CB=\sqrt[]{({3a_{}+a})^2+({b_{}+5b})^2} \\ CB=\sqrt[]{({4a})^2+({6b})^2} \end{gathered}\)Therefore, the required values are
\(CB=\sqrt[]{({4a})^2+({6b})^2}\)Find 4 3/4 + 1 1/10
Answer:
Your Answer is: 237 /20
Answer:
5 17/20
Step-by-step explanation:
if this following sequence represents a simulation of 5 random numbers trials, r (for 0 <= r <= 1), what is the average drying time: r1 = 0.17 ; r2 = 0.22 ; r3 = 0.29, r4 = 0.31 , and r5 = 0.42.
The average drying time, based on the given sequence of 5 random numbers (r1 = 0.17, r2 = 0.22, r3 = 0.29, r4 = 0.31, and r5 = 0.42), is 0.282 seconds.
To calculate the average drying time, we sum up all the drying times and divide by the number of trials. In this case, the drying times are represented by the random numbers r1, r2, r3, r4, and r5.
Average drying time = (r1 + r2 + r3 + r4 + r5) / 5
Substituting the given values:
Average drying time = (0.17 + 0.22 + 0.29 + 0.31 + 0.42) / 5
= 1.41 / 5
= 0.282
Therefore, the average drying time, based on the given sequence of random numbers, is approximately 0.282 seconds. This average represents the expected value of the drying time based on the given trials. It provides a summary measure of central tendency for the drying times observed in the simulation.
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I need help with this please!!
Answer:
Step-by-step explanation:
B.
A study has a 2 Ã 2 Ã 3 within-groups factorial design. This example has a total of ___ cell(s). Researchers would need to investigate ___ main effect(s), ___ two-way interaction(s), and ___ three-way interaction(s) in this study.
A study has a 2 Ã 2 Ã 3 within-groups factorial design. This example has a total of _12_ cell(s). Researchers would need to investigate _three__ main effect(s), _Three two-way interactions __ two-way interaction(s), and _ One three-way interaction__ three-way interaction(s) in this study.
a 2 x 2 x 3 within-groups factorial design, you have:
A total of 2 x 2 x 3 = 12 cells
Three main effects to investigate (one for each factor)
Three two-way interactions to investigate (AxB, AxC, and BxC)
4. One three-way interaction to investigate (AxBxC)
So, in this study, there are 12 cells, researchers would need to investigate 3 main effects, 3 two-way interactions, and 1 three-way interaction.
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6. What is the perimeter of the trapezoid if x = 9 and y = -3? Round to the nearest whole number.
x2 + 3y
3(x + Ey)2
3
(x + y)?
X-5y
-2y
310
292
Ο Ο Ο Ο
940
289
Choose the correct simplification of 9x2(4x 2x2 − 1). 18x4 36x3 − 9x2 18x4 − 36x3 9x2 36x4 18x3 − 9x2 36x4 − 13x3 9x2
The correct simplification would be \(18x^4 - 36x^3 + 9x^2\) (option a).
To simplify the expression \(9x^2(4x - 2x^2\) - 1), we need to perform the multiplication and combine like terms.
1. Start by distributing the 9x^2 to each term inside the parentheses:
\(9x^2 * 4x = 36x^3 9x^2 * (-2x^2) = -18x^4 9x^2 * (-1) = -9x^2\)
2. Now we can combine the terms obtained from the distribution:
\(36x^3 - 18x^4 - 9x^2\)
3. Rearranging the terms in descending order of exponents:
\(-18x^4 + 36x^3 - 9x^2\)
4. However, we can simplify this expression further by factoring out a common factor of \(-9x^2\):
\(-9x^2(2x^2 - 4x + 1)\)
5. Thus, the final simplified expression is:
\(18x^4 - 36x^3 + 9x^2\)
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solve please im gonna fail
Answer:
The two little blue boxes are going
Step-by-step explanation:
Lets start with the 0s.
Two zeros is 0. so its
_ _ _ _ 0.
Now we add 2 and 0 which is 2.
_ _ _ 2 0
now we add 6 and 4, which is 10. We have to put the 1 above the 7 and 5 and we are going to put 0 down below
_ _ 0 2 0
now we are going to add 7 +5, but dont forget the 1! Its going to be 13. Put the 3 down below and put the 1 above the 2!
_ 3 0 2 0
Now its 2 + 1 which is 3
your answer is
33020
Which of the following constructions must you know how to do in order to construct an inscribed circle for a given triangle?
angle bisector
perpendicular bisector
duplicating a line segment
bisecting a segment
For the construction of an inscribed circle the required construction that must be known is the angle bisector. The correct option is (A).
What is an angle bisector?The angle bisector is a line that divides an angle into two equal parts. For a circle inscribed in a triangle the line joining the center to the vertex is the angular bisector of the interior angle.
The diagram for the given case can be drawn as follows,
For the circle inscribed in the circle, all the sides are tangents.
By the property of tangents to a circle ∠ODB and ∠OFB are right angles.
Now, in ΔODB and ΔOFB the relation is obtained as,
∠ODB = ∠OFB (right angles)
OB = OB (Common sides)
And, OD = OF (radius of the circle)
⇒ ΔODB ≅ ΔOFB (by RHS criteria)
This implies that ∠ODB ≅ ∠OFB.
Thus, the line joining the centre and the vertex of triangle bisects its angles.
Hence, for the given case the required construction to be known is the angle bisector of triangle.
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Partial Question 4 Determine the limit of the sequence (1) {2} [Select] n+3 (2) { (+³)"} [Select] (3) {n sin()} [Select] (4) {sin(nπ)} [Select] Answer 1: the limit DNE, the sequence diverges Answer
The limit of the sequence (1) {2}, (2) {(-1)^n}, and (3) {n sin(n)}, converges to DNE (does not exist) or the sequence diverges. The limit of the sequence (4) {sin(nπ)} is undefined, as it oscillates between -1 and 1.
In the case of sequence (1) {2}, the limit is a constant value, and the sequence converges to that value. However, in the case of sequence (2) {(-1)^n}, the sequence oscillates between -1 and 1, and there is no single value that it approaches as n tends to infinity. Therefore, the limit does not exist, and the sequence diverges.
Sequence (3) {n sin(n)} also does not have a limit as n tends to infinity. The term n sin(n) oscillates between positive and negative values without approaching a specific value. Hence, the limit of this sequence is DNE, and it diverges.
In the case of sequence (4) {sin(nπ)}, the term sin(nπ) oscillates between -1 and 1 as n varies. Since there is no convergence to a specific value, the limit of this sequence is undefined.
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*PLS HELP ME ASAP 100 POINTS* There are 49 servings in a box of cereal. Each serving size is 1/7 of a cup of cereal. If one person eats 1 cup and another person eats 4 cups, how many cups are left in the box of cereal?
Answer:
2 cups left
Step-by-step explanation:
problem 3: solve the initial value problem y 00 y = g(t) where g(t) = ? t if 0 ≤ t < 2 0 if 2 ≤ t and with y(0) = 0 and y 0 (0) = 0.
The general solution to the initial value problem is \(y(t) = y_h(t) + y_p(t).\)Substitute the initial conditions y(0) = 0 and y'(0) = 0 into the general solution to find the constants c1 and c2. The final solution to the initial value problem comes out as : \(y(t) = c1*e^t + c2*e^(-t) + u1(t)*e^t + u2(t)*e^(-t).\)
To solve the initial value problem \(y'' - y = g(t)\) with \(g(t) = -t if 0 ≤ t < 2\) and 0 if 2 ≤ t, and with y(0) = 0 and y'(0) = 0, we will use the method of variation of parameters.
The general solution to the homogeneous equation \(y'' - y = 0\). The characteristic equation is \(r^2 - 1\) = 0, which has roots r = 1 and r = -1. So the general solution is \(y_h(t) = c1*e^t + c2*e^(-t).\)
The particular solution to the non-homogeneous equation using variation of parameters. We will assume that the particular solution is of the form \(y_p(t) = u1(t)*e^t + u2(t)*e^(-t).\)
The first and second derivatives of \(y_p(t):\)
\(y'_p(t) = u1'(t)*e^t + u1(t)*e^t + u2'(t)*e^(-t) - u2(t)*e^(-t) y''_p(t) = u1''(t)*e^t + 2*u1'(t)*e^t + u1(t)*e^t + u2''(t)*e^(-t) - 2*u2'(t)*e^(-t) + u2(t)*e^(-t)\)
Substitute \(y_p(t), y'_p(t), and y''_p(t)\) into the original equation, simplify:
\(u1''(t)*e^t + 2*u1'(t)*e^t + u1(t)*e^t + u2''(t)*e^(-t) - 2*u2'(t)*e^(-t) + u2(t)*e^(-t) - u1(t)*e^t - u2(t)*e^(-t) = g(t) u1''(t)*e^t + 2*u1'(t)*e^t + u2''(t)*e^(-t) - 2*u2'(t)*e^(-t) = g(t)\)
\(u1''(t)*e^t + u2''(t)*e^(-t) = 0\) and \(2*u1'(t)*e^t - 2*u2'(t)*e^(-t) = g(t)\).
This gives us two equations: \(u1''(t) = -u2''(t)*e^(-2t) and 2*u1'(t) - 2*u2'(t)*e^(-2t) = g(t)*e^(-t)\)
Getting values for u1'(t) and u2'(t):
\(u1'(t) = (g(t)*e^(-t) + 2*u2'(t)*e^(-2t))/2 u2'(t) = (-g(t)*e^(t) + 2*u1'(t)*e^(2t))/2\)Integrate both equations to find u1(t) and u2(t):
\(u1(t) = ∫(g(t)*e^(-t) + 2*u2'(t)*e^(-2t))/2 dt u2(t) = ∫(-g(t)*e^(t) + 2*u1'(t)*e^(2t))/2 dt\)
Substitute g(t) = -t if 0 ≤ t < 2 0 if 2 ≤ t into the equations for u1(t) and u2(t) and solve for \(u1(t)\)and \(u2(t)\). Substitute \(u1(t)\) and\(u2(t)\)into the equation for y_p(t) to find the particular solution. The final solution to the initial value problem is \(y(t) = c1*e^t + c2*e^(-t) + u1(t)*e^t + u2(t)*e^(-t).\)
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Question content area top
Part 1
Write an equivalent expression without parentheses. Then simplify the result.
m−(8−3m)
using exponents, On simplifying the equation, we get =4m+8.
The PEMDAS order of operations must be followed when you want to simplify a mathematical equation without using parenthesis (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction). There are no parenthesis in the expression, so you may start looking for exponents. If it does, first make that simpler.
What is the main objective of simplification?Work simplification is to develop better work processes that boost output while cutting waste and costs.
What does simplifying mean in algebra?Simplifying an expression is the same as solving a mathematical issue. When you simplify an equation, you essentially try to write it as simply as you can. There shouldn't be any more multiplication, dividing, adding, or deleting to be done when the process is finished.
Given equation,
m-(8-3m)
=m-8+3m
=4m+8
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The table represents a function.
What is f(-2)?
0 -3
х
-6
-2
f(x)
3
1
4
-2
O-1
O 1
O 3
9514 1404 393
Answer:
(c) 1
Step-by-step explanation:
To find f(-2), locate -2 in the x column. Then find the corresponding f(x) value.
-2 is in the second row, opposite f(x) = 1, so f(-2) = 1.
Answer: c
Step-by-step explanation:
C) find the two values of x that correspond to the x intercepts of the parabola and write them as a list,
separated by commas:
x= ___
The x-intercepts are the points (-2,0) and (4,0)
What is parabolaA parabola is a symmetrical, curved, U-shaped graph. Parabolas exist in everyday situations, such as the path of an object in the air, headlight shapes and the wire of suspension bridges. The equation of a parabolic graph is y = x² and all quadratic graphs have a line of symmetry which passes vertically through the minimum or maximum point
Find the x-intercepts of the parabola and write them as ordered pairs
The x-intercepts are the values of x when the value of y is equal to zero
so
For y=0
For x=4 and x=-2 the equation is equal to zero
therefore
The x-intercepts are the points (-2,0) and (4,0)
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