Find the missing dimension Use the scale 1:5


Model : 3ft
Actual: ???


help me pls ;-;

Answer:

ΔPQR and ΔSTU are not similar.

Step-by-step explanation:

The two triangles look distinguishable from each other.

Answer:

Step-by-step explanation:

23. 16 divided by 8 is 2, which means he spent 2 dollars on 1 wing. So 46 divided by 2 is 23.

For 46 dollars, Tyler can buy 23 chicken wings.

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given that, Tyler bought 8 chicken wings for $16.00.

To find the number of chicken wings, first find the cost of one chicken wing and to find number of chicken wings divide total cost by cost of one chicken wing.

So, the cost of each chicken wing is 16/8

= $2

So, the cost of each chicken wing is 2 dollars.

Tyler spent $46.00 on chicken wings.

Number of chicken wings = 46/2

= 23

So, the number of chicken wings are 23.

Therefore, Tyler can buy 23 chicken wings for $46.

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We have proven that if a>b and c<0, then a/c < b/c as shown below

From the question, we are to prove that if a>b and c<0, then a/c < b/c

To do this,

We will pick numbers to represent the letters a, b, and c that satisfy the given conditions

From the given information,

a > b

Let a = 6

and b = -2

Also, we have that

c<0

Let c = -1

Now, evaluate each of the expressions

Evaluating a/c

a/c = 6/-1

a/c = -6

Evaluating b/c

b/c = -2/-1

b/c = 2

-6 < 2

Thus,

a/c < b/c

Hence, we have proven that if a>b and c<0, then a/c < b/c

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None of the above. To form a standard triangle, all 3 sides must be of equal length.

Answer:

the first table

Step-by-step explanation:

Dividing 9x³ + 3x² + 10x + 3 by 3x + 2. will yield a quotient of 3x² - x + 4 and a remainder of -5 that is (3x² - x + 4) -5/(3x + 2).

Applying the long division method will require us to; divide, multiply, subtract, bring down the next number and repeat the process to end at zero or arrive at a remainder.

We shall divide the 9x³ + 3x² + 10x + 3 by 3x + 2. as follows;

9x³ divided by 3x equals 3x²

3x + 2. multiplied by 3x² equals 9x³ + 6x²

subtract 9x³ + 6x² from 9x³ + 3x² + 10x + 3 will result to -3x² + 10x + 3

-3x² divided by 3x equals -x

3x + 2 multiplied by -x equals -3x² - 2x

subtract -3x² - 2x from -3x² + 10x + 3 will result to 12x + 3

12x divided by 3x equals 4

3x + 2 multiplied by 4 equals 12x + 8

subtract 12x + 8 from 12x + 3 will result to a remainder of -5

Therefore by the long division method, 9x³ + 3x² + 10x + 3 divided by 3x + 2 gives a quotient 3x² - x + 4 and a remainder of -5 and can be written as (3x² - x + 4) -5/(3x + 2).

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Answer:

A

Step-by-step explanation:

If a logical vector z has at least one entry TRUE, the function all(!z) will always be false.

If a logical vector contains only TRUE items, the all() method returns FALSE; otherwise, it returns TRUE.

The any() function, on the other hand, gives a result of TRUE if a logical vector has at least one element that is TRUE and FALSE otherwise.

any(z) will always be TRUE if z contains at least one TRUE element since there is at least one TRUE element. On the other hand, depending on whether all of the components of z are TRUE, all(z) may or may not be TRUE.

any(!z) will always return FALSE since if z has at least one TRUE element, then!z must include at least one FALSE element.

Additionally, all(!z) will always return FALSE if any element is FALSE since if z has at least one TRUE element, then!z must include at least one FALSE element.

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Answer:

C.y=-3x-3

Step-by-step explanation:

Answer:

The rise over run is -1/2

Step-by-step explanation:

The equation for the price of house after x years is,

Simplify the equation to obtain the equation for value of house after x years.

So option B is correct.

The mode of this set of numbers is 1,the median of this set of numbers is 1.

Mean: To find the mean of this set of 5 numbers, we first add them together and divide by the number of measurements. 0 + 7 + 1 + 1 + 4 = 13. 13 divided by 5 (the number of measurements) is 2.6. Therefore, the mean of this set of numbers is 2.6.

Median: To find the median of this set of 5 numbers, we first need to arrange them in order from least to greatest. 0, 1, 1, 4, 7. The median is the middle number, so it is 1. Therefore, the median of this set of numbers is 1.

Mode: To find the mode of this set of 5 numbers, we need to look for the number that appears most often. In this set, the number 1 appears twice while the rest of the numbers appear only once. Therefore, the mode of this set of numbers is 1.

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The value of the function (b²)²(b²)² from the given quadratic equation is 390,625.

The solution of a quadratic function is determined from either formula method or completing the square method.

The equation for the formula method of solving a quadratic function is given as;

\(x = \frac{-b \ \ \pm \ \sqrt{b^2 - 4ac} }{2a}\)

where;

The given quadratic function;

3x² - 5x - 3 = 0

from the equation above we can infer the following;

a = 3

b = -5

c = -3

The obtain the value of the function [ (b²)²(b²)²], we will substitute the value of b from the above quadratic equation into the given function as shown below.

(b²)²(b²)² = (-5²)²(-5²)² = (-5)⁸ = 390,625

Thus, the value of the function (b²)²(b²)² is determined by applying the formula method of solving a quadratic function.

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Let's represent the unknown negative number as "x."

According to the given information, the square of the number is equal to five more than one-half of the number. Mathematically, we can write this as:

x^2 = (1/2)x + 5

To find the value of x, we need to solve this quadratic equation. Rearranging the equation, we have:

x^2 - (1/2)x - 5 = 0

To solve this quadratic equation, we can use factoring, completing the square, or the quadratic formula. Let's use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = -1/2, and c = -5. Substituting these values into the quadratic formula:

x = (-(1/2) ± √((-1/2)^2 - 4(1)(-5))) / (2(1))

Simplifying further:

x = (-1/2 ± √(1/4 + 20)) / 2

x = (-1/2 ± √(81/4)) / 2

x = (-1/2 ± 9/2) / 2

x = (-1 ± 9) / 4

Therefore, we have two possible solutions for x:

x = (-1 + 9) / 4 = 8/4 = 2

x = (-1 - 9) / 4 = -10/4 = -5/2

Since we are looking for a negative number, the solution is x = -5/2.

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The optimal value for x in the stochastic model is a range of values from x=6 to x=8. The stochastic model causes problems due to the uncertainty in the optimal solution and the assumptions.

With a=5, the optimal solution is x=8. However, with the addition of stochasticity and possible values for a of 3, 4, and 6, the optimal value for x becomes a range of values.

The expected value of a is 4.5, which means that there is a higher probability of a lower value for a, resulting in a lower optimal value for x. Therefore, the optimal value for x becomes x=6 when a=3 or a=4, x=7 when a=5, and x=8 when a=6.

The stochastic model causes problems because the optimal solution is no longer a fixed value but rather a range of values that are dependent on the probability distribution of a.

Additionally, this model assumes that the production time is the only constraint on production, which may not always be the case in real-world production scenarios. Therefore, the stochastic model may not accurately reflect the actual production process and could lead to suboptimal production decisions.

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Answer:

its the same thing as 3 x3 or 3+3 it always come´s back as 9 or 6 Becasue of its rotation

Step-by-step explanation:

Answer:

La distancia recorrida por el móvil es 240 metros.

Step-by-step explanation:

Puesto que el móvil experimenta movimiento rectilíneo uniformemente acelerado, la distancia recorrida es determinada por las siguientes ecuaciones cinemáticas:

\(\Delta x = v_{o}\cdot t + \frac{1}{2}\cdot a\cdot t^{2}\) (1)

\(v = v_{o} + a\cdot t\) (2)

Donde:

\(\Delta x\) - Distancia recorrida, medida en metros.

\(v_{o}\) - Velocidad inicial, medida en metros por segundo.

\(v\) - Velocidad final, medida en metros por segundo.

\(a\) - Aceleración, medida en metros por segundo al cuadrado.

\(t\) - Tiempo, medido en segundos.

En (2) despejamos el tiempo:

\(a = \frac{v-v_{o}}{t}\)

Si aplicamos esta ecuación en (1):

\(\Delta x = v_{o}\cdot t + \frac{1}{2}\cdot \left(\frac{v-v_{o}}{t} \right)\cdot t^{2}\)

\(\Delta x = v_{o}\cdot t + \frac{1}{2}\cdot (v-v_{o})\cdot t\)

\(\Delta x = \frac{1}{2}\cdot v_{o}\cdot t+\frac{1}{2}\cdot v\cdot t\)

\(\Delta x = \frac{1}{2}\cdot (v_{o}+v)\cdot t\) (3)

Si sabemos que \(v_{o} = 0\,\frac{m}{s}\), \(v = 60\,\frac{m}{s}\) and \(t = 8\,s\), entonces la distancia recorrida es:

\(\Delta x = \frac{1}{2}\cdot \left(0\,\frac{m}{s}+60\,\frac{m}{s}\right) \cdot (8\,s)\)

\(\Delta x = 240\,m\)

Answer:

x = 6

Step-by-step explanation:

x:(x + 3) = 2:3

\( \frac{ \\ x}{x + 3} = \frac{2}{3} \)

cross multiply

3x = 2(x + 3)

3x = 2x + 6

subtract (2x) from both sides

3x – 2x = 2x – 2x + 6

x = +6

x = 6

To find the critical points at which profit is maximized given the total revenue TR = 4700 - 302 and total cost TC = 320/10,500, we need to compute the marginal revenue and marginal cost, equate MR = MC to find the optimal quantity Q∗, verify if Q∗ is a relative maximum point, and compute the maximum profit level (π) by evaluating π∗ = 9(π(Q∗)).

Marginal Revenue (MR) is the derivative of the total revenue function with respect to quantity (Q). In this case, MR = dTR/dQ. By taking the derivative of TR = 4700 - 302 with respect to Q, we can find the expression for MR.

Marginal Cost (MC) is the derivative of the total cost function with respect to quantity (Q). In this case, MC = dTC/dQ. By taking the derivative of TC = 320/10,500 with respect to Q, we can find the expression for MC.

To find the optimal quantity Q∗, we equate MR and MC by setting MR = MC and solve for Q. This is because profit is maximized when MR equals MC.

Once we have found Q∗, we need to verify if it is a relative maximum point. This can be done by checking the second derivative of the profit function and determining if it is negative at Q∗. If the second derivative is negative, it confirms that Q∗ is a relative maximum point.

Finally, to compute the maximum profit level (π∗), we evaluate π(Q∗) by substituting Q∗ into the profit function. In this case, we can multiply the value of π(Q∗) by 9 to obtain the maximum profit level (π∗).

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Answer:

1) AD = 9 in

2) DE = 9.25 in

3) ∠EDC = 36°

4) ∠AEB = 108°

5) 11.5 in

Step-by-step explanation:

1) AD = BC = 9in

2) AC = BD (diagonals are equal)

⇒ BD = 14.25

⇒ BE + DE = 14.25

⇒ 5 + DE = 14.25

DE = 9.25

3) Since AB ║CD,

∠ABE = ∠EDC = 36°

4) ∠ABE = ∠BAE = 36°

Also ∠ABE + ∠BAE + ∠AEB = 180 (traingle ABE)

⇒ 36 + 36 + ∠AEB = 180

∠AEB = 108

5) midsegment = (AB + CD)/2

= (8 + 15)/2

11.5

Answer:

20 hours

Step-by-step explanation:

We can use a ratio to solve

90dollars      360 dollars

--------------- = -----------

5 hours         x hours

Using cross products

90x = 5* 360

Divide each side by 90

90x/90 = 5 * 360/90

x = 20

20 hours

Answer:

option 2 is correct given diagrm

The resulting box plot for the given data would show a box ranging from 5.2 to 5.7, with the median at 5.4.

A box plot, also known as a box-and-whisker plot, is a graphical representation of numerical data that displays the distribution of a dataset. It provides a visual summary of the minimum, first quartile, median, third quartile, and maximum values, as well as any outliers that may be present.

To construct a box plot from the given data (diameters of cans in an assembly line: 5.7, 5.6, 5.1, 5.4, 5.2, 5.6, 5.7, 5.3, 5.8, 5.2), follow these steps:

1. Sort the data in ascending order: 5.1, 5.2, 5.2, 5.3, 5.4, 5.6, 5.6, 5.7, 5.7, 5.8.

2. Find the median (middle value) of the dataset, which is 5.4.

3. Determine the first quartile (Q1), which is the median of the lower half of the data. In this case, it is the median of the numbers below 5.4: 5.2.

4. Find the third quartile (Q3), which is the median of the upper half of the data. In this case, it is the median of the numbers above 5.4: 5.7.

5. Calculate the interquartile range (IQR) by subtracting Q1 from Q3: 5.7 - 5.2 = 0.5.

6. Identify any outliers in the dataset. Outliers are values that fall below Q1 - 1.5 * IQR or above Q3 + 1.5 * IQR. In this case, there are no outliers.

7. Construct the box plot using a number line. Draw a box from Q1 to Q3, with a line inside representing the median. Add whiskers (lines) extending from the box to the minimum value (5.1) and the maximum value (5.8).

The resulting box plot for the given data would show a box ranging from 5.2 to 5.7, with the median at 5.4. The whiskers would extend from 5.1 to 5.8. This visual representation provides an overview of the distribution and key statistical measures of the diameters of cans in the assembly line.

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The conveyor speed for the assembly line is 2.67 meters per minute.

To calculate the conveyor speed for the assembly line, we need to consider the width of each component and the production requirements.

Given:

Width of each component = 0.4m

Production requirement = 3000 units per day

Number of shifts per day = 2

Shift duration = 8 hours

Personal time per shift = 30 minutes

Anticipated performance = 85%

First, let's calculate the effective production time per shift after accounting for personal time:

Shift duration = 8 hours = 8 * 60 minutes = 480 minutes

Personal time per shift = 30 minutes

Effective production time per shift = Shift duration - Personal time per shift

= 480 minutes - 30 minutes

= 450 minutes

Next, we need to determine the cycle time, which is the time required to produce one unit. To find the cycle time, we divide the effective production time per shift by the number of units required per day:

Cycle time = Effective production time per shift / Production requirement per day

= 450 minutes / 3000 units

= 0.15 minutes per unit

Finally, to calculate the conveyor speed, we need to consider the width of each component and the cycle time:

Conveyor speed = Width of each component / Cycle time

= 0.4m / 0.15 minutes per unit

= 2.67 m/minute

Therefore, the conveyor speed for the assembly line is 2.67 meters per minute.

It's important to note that this calculation assumes uniform production throughout the shift and does not account for any additional factors or constraints specific to your production process.

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The value of x from the given figure is 12 units.

Two triangles are similar if the angles are the same size or the corresponding sides are in the same ratio. Either of these conditions will prove two triangles are similar.

From the given figure,

Consider ΔADC and ΔABC,

∠C=∠C (Reflex property)

AC=AC (Reflex property)

∠BAC=∠CDA=90°

By AA similarity, ΔADC ~ ΔABC

So, AC/BC = DC/AC

x/36 = 4/x

x²=36×4

x²=144

x=12 units

Therefore, the value of x from the given figure is 12 units.

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Answer:

9 is the correct answer

Step-by-step explanation:

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