Find the missing side or angle.
Round to the nearest tenth.
C=5
b=4
a=2
B=[ ? ]°

Answer:

(a) To find the mean of the data set, sum up all the values and divide by the total number of values.

44 + 44 + 54 + 54 + 65 + 39 + 54 + 44 = 398

Mean = 398 / 8 = 49.75

Rounded to one decimal place, the mean of this data set is 49.8.

(b) To find the median of the data set, i need to arrange the values in ascending order first:

39, 44, 44, 44, 54, 54, 54, 65

The median is the middle value in the sorted data set. In this case, we have 8 values, so the median is the average of the two middle values:

(44 + 54) / 2 = 98 / 2 = 49

Rounded to one decimal place, the median of this data set is 49.0.

(c) To determine the modes of the data set, identify the values that appear most frequently.

In this case, the mode refers to the value(s) that occur(s) with the highest frequency.

From the data set, i see that the value 44 appears three times, while the value 54 also appears three times. Therefore, there are two modes: 44 and 54.

Answer:

9 - 3 ÷ 1/3 + 1 = 1 ( Answer )

Step-by-step explanation:

hope u liked the answer :)

Answer:

3

Step-by-step explanation:

right ya rong you tell me ok

Answer: 101

Step-by-step explanation: 1+5x20 then 100+1= 101

Answer:

The value is  \(P( X > 0.50) = 0.089264\)

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  500

   The  population proportion is  p =  0.47  

Generally given that the sample size is sufficiently large , the mean of this sampling distribution is mathematically represented as

        \(\mu_x = p = 0.47\)

Generally the standard deviation of the sampling distribution is mathematically represented as

       \(\sigma = \sqrt{\frac{p(1- p )}{ n} }\)

=>     \(\sigma = \sqrt{\frac{ 0.47 (1-0.47 )}{ 500 } }\)

=>     \(\sigma = 0.0223\)

Gnerally the probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50 is mathematically represented as

          \(P( X > 0.50) = P( \frac{ X - \mu }{ \sigma } > \frac{ 0.50 - 0.47 }{ 0.0223 } )\)

\(\frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )\)

=>        \(P( X > 0.50) = P( Z> 1.3453 )\)

From the z table  the area under the normal curve to the left corresponding to  1.3453   is

          \(P( Z> 1.3453 ) = 0.089264\)

So  

          \(P( X > 0.50) = 0.089264\)

Using the normal distribution and the central limit theorem, it is found that there is a 0.0901 = 9.01% probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50.

In a normal distribution with mean \(\mu\) and standard deviation \(\sigma\), the z-score of a measure X is given by:

\(Z = \frac{X - \mu}{\sigma}\)

It measures how many standard deviations the measure is from the mean.  

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample proportions of size n of a proportion p has \(\mu = p, s = \sqrt{\frac{p(1-p)}{n}}\)

In this problem:

The mean and the standard deviation are:

\(\mu = p = 0.47\)

\(\sigma = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.47(0.53)}{500}} = 0.0223\)

The probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50 is 1 subtracted by the p-value of Z when X = 0.5, hence:

\(Z = \frac{X - \mu}{\sigma}\)

By the Central Limit Theorem

\(Z = \frac{X - \mu}{s}\)

\(Z = \frac{0.5 - 0.47}{0.0223}\)

\(Z = 1.34\)

\(Z = 1.34\) has a p-value of 0.9099.

1 - 0.9099 = 0.0901

0.0901 = 9.01% probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50.

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To solve this problem, we need to find the lengths of the two pieces when the wire is cut into two parts. Let's denote the length of each leg of the triangle as\(\(x\).\)

The perimeter of the triangle is the sum of the lengths of its three sides. Since the two legs are equal in length, the perimeter can be expressed as \(\(2x + x = 3x\).\)

The length of the wire is given as 71 cm, so we have the equation \(\(3x = 71\).\)

Solving for\(\(x\),\) we divide both sides of the equation by 3:

\(\(x = \frac{71}{3}\).\)

Now that we know the length of each leg of the triangle, we can proceed to the next part of the problem.

The circumference of a circle is given by the formula \(\(C = 2\pi r\)\), where\(\(C\)\)is the circumference and r is the radius. In this case, the wire of length xis bent into the shape of a circle, so we can set the circumference equal to x and solve for the radius r:

\(\(x = 2\pi r\).\)

Substituting the value of x we found earlier, we have:

\(\(\frac{71}{3} = 2\pi r\).\)

Solving for r, we divide both sides of the equation by \(\(2\pi\):\)

\(\(r = \frac{71}{6\pi}\).\)

Therefore, the two pieces of wire will have lengths\(\(\frac{71}{3}\)\)cm and the radius of the circle will be\(\(\frac{71}{6\pi}\)\) cm.

In summary, when the 71 cm wire is cut into two pieces, one piece will have a length o\(\(\frac{71}{3}\)\)cm, which can be bent into the shape of an equilateral triangle with legs of equal length, and the other piece can be bent into the shape of a circle with a radius of \(\(\frac{71}{6\pi}\)\) cm.

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The inequalities which satisfy the number line shown is x>2 and x>=2.

We are given that;

The number line showing inequality

Now,

x>2 satisfies the equation by the given number line

x>=2 satisfies the equation by the given number line

x<=-3 does not satisfies the equation by the given number line

x<=-3 does not satisfies the equation by the given number line

Therefore, by the number line the answer will be x>2 and x>=2 .

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Answer:

3. 8÷ x² is the correct answer.

The critical value, given the sample size of 5 and the confidence level of 99. 0 percent would be 16. 812.

The critical values for the chi-squared (χ^2) distribution depend on the degree of freedom and the level of significance.

The degree of freedom for a chi-squared distribution typically equals the sample size minus 1 so the degrees of freedom here is:

= 5 - 1

= 4

The level of significance would be:

= 1 - 99. 0 %

= 0. 01

The critical value of the sample would therefore be found on a chi -squared distribution table for df = 4 and α = 0.01 to be 16. 812.

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Answer:

D). (-4,-8)​

Step-by-step explanation:

An image at (8,-4) if rotated at an angle of 90° wipl have another location.

First of all, an image at (8,-4) is in the fourth quadrant, and if it's to rotate clockwise at 90° iths supposed to be in the third quadrant.

And in the third quadrant both x and y is negative.

So the new position is at (-4,-8)​

The formula for Pythagoras theorem is -

(hypotenuse)² = (base)² + (perpendicular)².

Given is to discuss the Pythagoras theorem.

Pythagoras theorem states that the square of the hypotenuse is equivalent to the square of the base and perpendicular.

We can write the formula for Pythagoras theorem as -

(hypotenuse)² = (base)² + (perpendicular)²

Therefore, the formula for Pythagoras theorem is -

(hypotenuse)² = (base)² + (perpendicular)².

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{Question in english -

What is the Pythagorean theorem? Formula}

Step-by-step explanation:

hello,

you just need to multiply all values inside the brackets with the value outside the bracket and then work it out as normal.

for instance,

a) 4( x + 3)

= 4x + 12

here you can see i multiplied both values by 4.

b) 4(x - 5)

= 4x - 20

c)2(x + 2)

= 2x + 4

d) 4(1 - c)

= 4 - 4c

hope this makes things clearer for you! thank you!

The correct step to prove that \(BC^2 = AB^2 + AC^2\) is:

By the cross product property, \(AC^2 = BC \cdot AD\).

To prove that \(BC^2 = AB^2 + AC^2\), we can use the triangle similarity and the Pythagorean theorem. Here's a step-by-step explanation:

Given triangle ABC with right angle at A and segment AD perpendicular to segment BC.

By triangle similarity, triangle ABD is similar to triangle ABC. This is because angle A is common, and angle BDA is a right angle (as AD is perpendicular to BC).

Using the proportionality of similar triangles, we can write the following ratio:

\($\frac{AB}{BC} = \frac{AD}{AB}$\)

Cross-multiplying, we get:

\($AB^2 = BC \cdot AD$\)

Similarly, using triangle similarity, triangle ACD is also similar to triangle ABC. This gives us:

\($\frac{AC}{BC} = \frac{AD}{AC}$\)

Cross-multiplying, we have:

\($AC^2 = BC \cdot AD$\)

Now, we can substitute the derived expressions into the original equation:

\($BC^2 = AB^2 + AC^2$\\$BC^2 = (BC \cdot AD) + (BC \cdot AD)$\\$BC^2 = 2 \cdot BC \cdot AD$\)

It was made possible by cross-product property.

Therefore, the correct step to prove that \(BC^2 = AB^2 + AC^2\) is:

By the cross product property, \(AC^2 = BC \cdot AD\).

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Answer: The correct answer is option C. 16,385/4.

Step-by-step explanation: First of all, we evaluate the expression x^6. Putting x= -4 gives (-4^6) which is equal to 4096. The next part (-x/4y) on substituting x = -4 and y =4 gives us the positive expression (1/4).

Adding both these parts, we get (4*4096+1)/4. This is finally evaluated as (16,384+1)/4, which is equal to the required answer of 16,385/4.

Answer:

\(d=-8\)

Step-by-step explanation:

If the first term of a sequence is \(258\) and the second term is \(250\), then each successive term in the sequence is \(8\) less than the previous term. Therefore, the common difference is \(-8\) ( \(d=-8\) ).

The formula representing the arithmetic sequence is:

\(a_n=-8n+266\)

Therefore:

Term 1: \(a_1=-8(1)+266=-8+266=258\)

Term 2: \(a_2=-8(2)+266=-16+266=250\)

Term 3: \(a_3=-8(3)+266=-24+266=242\)

…

Term 9: \(a_9=-8(9)+266=-72+266=194\)

Answer:

8 units, 3 units, √73 units

16 units, 30 units, √50 units

Step-by-step explanation:

Given the above side lengths of a triangle, to determine which triangles are right triangles, we would make use of the Pythagorean theorem which holds that the sum of the square of two smaller legs of a right triangle would give us the square of the length of the longest leg.

That is a² + b² = c²

Thus, let's check each options given.

Let c be the 3rd units given in each option, which is the longest leg.

Option 1:

c² = 8² + 15²

c² = 64 + 225 = 289

c = √289 = 17

∆ with lengths 8 units, 15 units, √75 units is not a right triangle because c ≠ √75, from calculation.

Option 2:

c² = 8² + 3²

c² = 64 + 9 = 73

c = √73 units

∆ with lengths 8 units, 3 units, √73 units is a right triangle because c = √73 from calculation

Option 3:

c² = 16² + 30²

c² = 256 + 900 = 1156

c = √1156 = 34

∆ with lengths 16 units, 30 units, √50 units is not a right triangle because c ≠ √50 units from calculation.

Option 4:

c² = 5² + 7²

c² = 25 + 49 = 74

c = √74 units

∆ with lengths 16 units, 30 units, √50 units is a right triangle because c =  √74 units from calculation.

Therefore, based on the sets of side lengths given, the following are right triangles:

8 units, 3 units, √73 units

16 units, 30 units, √50 units

Answer:

8 units, 3 units, √73 units

16 units, 30 units, √50 units

Step-by-step explanation:

Answer:

45 and 5 are the dimensions of the block of land.​

Step-by-step explanation:

2(x + y) = 100, x + y = 100/2, y = (50 - x)

xy = 225

x (50 — x) = 225

0 = x^2 — 50x + 225

0 = (x — 45) (x -5)

45 and 5 are the roots of the above polynomial, thus they are the sides or dimensions of the block of land.

Answer:

I don't have a life.....

Answer:

I am an Undertale trash. so this is my life.

Step-by-step explanation:

Answer:

Step-by-step explanation:

x-intercept is where the line cuts the x-axis. That is, when y=0.

Substitute y=0 and we get:

       \(0=\frac{1}{3} x-1\)

       \(1=\frac{1}{3} x\)

       \(x=3\)

So x-intercept is the point (3,0).

If the first term of a geometric sequence is 8 and the common ratio is 3. Then the fifth term of the geometric sequence will be 648.

There are three parameters that differentiate between which geometric sequence we're talking about.

The first parameter is the initial value of the sequence.

The second parameter is the quantity by which we multiply the previous term to get the next term.

The third parameter is the length of the sequence. It can be finite or infinite.

Suppose the initial term of a geometric sequence is 'a' and the term by which we multiply the previous term to get the next term is 'r' (also called the common ratio)

The first term of a geometric sequence is 8 and the common ratio is 3.

Then the fifth term of the sequence will be

\(\rm T_n = a_1 \ r^{n-1}\)

Then we have

T₅ = 8 x 3⁵⁻¹

T₅ = 8 x 3⁴

T₅ = 8 x 81

T₅ = 648

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Answer:

the difference is that the 2 extra LARGE containers weigh bigger than the

6 small ones

Step-by-step explanation:

The value of the given fraction in mixed numbers is 6, or 36/6.

A fraction is a portion of a whole or, more broadly, any number of equal pieces. In ordinary English, a fraction represents the number of pieces of a specific size, such as one-half, eight-fifths, or three-quarters. In mathematics, a fraction is used to represent a piece or part of a whole. It symbolizes the equal pieces of the whole. A fraction is made up of two parts: the numerator and the denominator. The top number is known as the numerator, while the bottom number is known as the denominator.

Here,

=81/6-45/6

=(81-45)/6

=36/6

=6

The value for given fraction in mixed number will be 6 that is 36/6.

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The system of equations -9x+8y = 9x and 7y+8=8x is linear.

A system of equations is considered linear if each equation in the system is linear, meaning that the highest power of any variable in each equation is 1.

In this case, the first equation -9x+8y = 9x is linear because the highest power of any variable is 1 (x is raised to the first power).

Similarly, the second equation 7y+8=8x is also linear because the highest power of any variable is 1 (x is raised to the first power and y is not raised to any power).

Therefore, the system of equations is linear.

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If Leila makes a dot plot of the heights of the girls in her class to the nearest ¹/₂ inch, the number of different heights that will include on the number line is 5.

A dot plot is a data visualization tool that consists of data points plotted as dots on a graph with an x- and y-axis.

The number of dots plotted on each number line shows the frequency of the data group.

Height    Frequency   Cumulative Frequency

56¹/₂             2                               2

57                 2                               4

57¹/₂             2                               6

58                2                               8

58¹/₂             1                               9

Thus, arranging the heights according to groups, the different heights on the number line can be classified into 5.

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Answer:

Step-by-step explanation:

A. 1.4366 = 1.437

B. 0.8792  = 0.879

C. 0.3455 = 0.346

\(0.1\:1\:1\:1\\0\:. 1\:2\:3\:4\:decimal \:place\)

Note ;

Mean: Winter = 17.7 & Summer = 25.6

Median: Winter = 18.5 & Summer = 26

Mode: Winter = 20 & Summer = 18

Range: Winter = 9 & Summer = 20

The range of values in the middle of the scores is known as the interquartile range, or IQR. The proper measure of variability is the interquartile range when a distribution is skewed and the median rather than the mean is employed to demonstrate a central tendency.

Mean: Winter = 17.7 & Summer = 25.6

Median: Winter = 18.5 & Summer = 26

Mode: Winter = 20 & Summer = 18

Range: Winter = 9 & Summer = 20

Mean: Winter = Sum of scores/ no. of scores

= 18+20+15+16+21+20+12+16+19+20/10

= 177/10

= 17.7

Mean: Summer = Sum of scores/ no. of scores

= 28+18+24+32+18+29+23+38+28+18/10

= 256/10

= 25.6

Median: Winter =

Ascending order = 12, 15, 16, 16, 18, 19, 20, 20, 20, 21

No. of observation = 10 (even)

Median = mean of middle 2 terms

Mean = 18+19/2

= 37/2

Median = 18.5

Median: Summer =

Ascending Order = 18, 18, 18, 23, 24, 28, 28, 29, 32, 38

No. of observation = 10 (even)

Median = mean of middle 2 terms

Mean = 24+28/2

= 53/2

Median = 26

Mode: Winter = Most frequent no.

= 20

Mode: Summer = Most frequent no.

= 18

Range: Winter = Highest obs. - Lowest obs.

= 21 - 12

= 9

Range: Summer = Highest obs. - Lowest obs.

= 38 - 18

= 20

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The complete question is:

Police records show the following numbers of daily crime reports for a sample of days during the winter months and a sample of days during the summer months. Required: 3.1 Compute the interquartile range for each period. 3.2 Compute the mean for each period. 3.3 Compute the variance for each period. 3.4 Compute the standard deviation for each period. (4)

Winter: 18 20 15 16 21 20 12 16 19 20

Summer: 28 18 24 32 18 29 23 38 28 18

Answer:

\(3a + b = 14\)

\(b = 4a\)

Step-by-step explanation:

Key:

a = 3 point throws

b = Free throws

Total points = 14

Required

Determine the system of equations

\(Total\ points = 14\) implies that:

\(3 * a + b = 14\)

\(3a + b = 14\)

4 times as many b as a implies that:

\(b = 4 * a\)

\(b = 4a\)

So, the system of equations are:

\(3a + b = 14\)

\(b = 4a\)

just here for the points :l

The random variable is the number of cars held up at the intersection.

A random variable is one whose value is aleatory, then you can not know anticipatedly the outcome for sure. In this case, the number of cars held up at the intersection may be different at any time inside the range given and you cannot know the number of cars that there will be in a future moment.

Answer:

Step-by-step explanation:

24,000 = 24 thousands

30,000 = 30 thousands

3,000 = 3 thousands

2,4000 = 2.4 thousands

"x" years

24 + 3x = 30 + 2.4x

3x - 2.4x = 30 - 24

0.6x = 6

x = 10 years