Find the molecular formula for CH that has a molecular weight of 65g.

Answer:

A. 2.74g is the correct answer

Explanation:

\(average \: mass = \frac{(mass \: pre - 1982 \times abundance) + (mass \: post - 1982 \times abundance}{100 } \\ ave = \frac{ (3.1g \times 40.0) + (2.5g \times 60.0)}{100} \\ ave = \frac{124 + 150}{100} \\ ave = \frac{274}{10} = 2.74g\)

where, the sum of abundance always have to be 100%

Thus, 40.0 +60.0= 100.0

39.17 ml of the 15.0 M HF stock solution is required to prepare 250.0 ml of a 2.35 M HF solution.

To prepare 250.0 ml of a 2.35 M HF solution from a 15.0 M HF stock solution, we can use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.
In this case, we are looking for V1, the volume of the stock solution required.
M1 = 15.0 M
V1 = ?
M2 = 2.35 M
V2 = 250.0 ml
Plugging the values into the formula, we get:
15.0 M x V1 = 2.35 M x 250.0 ml
Solving for V1, we get:
V1 = (2.35 M x 250.0 ml) / 15.0 M
V1 = 39.17 ml
Therefore, 39.17 ml of the 15.0 M HF stock solution is required to prepare 250.0 ml of a 2.35 M HF solution.

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Answer:

a) club soda is a compound

b) Club soda is a manufactured form of carbonated water, commonly used as a drink mixer. Sodium bicarbonate, potassium sulfate, potassium bicarbonate, potassium citrate, or sodium citrate is artificially added to replicate constituents commonly found in natural mineral waters

Answer: A chemical reaction that releases heat into its environment

Explanation:

the exothermic process is a process or reaction that releases energy, (usually in the form of heat but also in light, electricity, or sound) into its environment

ex:

think of ice freezing, to change from a liquid to a solid it must release heat to lower it’s temperature to reach its freezing point

Exothermic changes give out energy to their surroundings, causing an increase in heat endothermic changes, take in energy, so the opposite takes place.

Answer:

15 grams of water will absorb 2,500 Joules  in going from 20.0 to 60.0 C.

Explanation:

The heat involved in raising a mass (m) of a substance with a specific heat (c) from one temperature to another (Delta T) is given by:

Heat = mc(Delta T)

2,500 Joules = m*(4.186J/gC)*(60C-20C)

2,500 Joules = m*(4.186J/gC)*(40C)

2,500 Joules = m*(4.186J/gC)*(40C)

m = (2,500J)/(4.186*40J/g)

m = 14.93 grams

Answer: B (15g)

Explanation:

Answer:

The third choice

Explanation:

The law of conservation of mass tells us that the mass of the reactants and products in a chemical reaction will be equal to one another. Equations follow the law of conservation of mass when they are balanced, which means that they have the same number and type of atoms on each side.

When individual atoms are counted, the third choice has the same number and type of atoms on each side: 1 gallium, three cesium and three fluorine.

Answer:

(0,1)

Explanation:

Endpoints (-3, 7) and (3,-5)

The midpoints will be the average of the x and y coordinates:

Midpoint for x = (-3+3)/2 = 0

Midpoint for y = (7-5)/2 = 1

(0,1)

The pressure of the argon be if we increase the volume to 500ml is fond to be  0.546atm

The exact pressure can be calculated using the Ideal gas law PV=nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant and T is the temperature in Kelvin.

P1 v1/T1 = P2v2/T2

=> P2 => 2x 100x 373 /273 x500

      => 0.546atm

The pressure of the argon would decrease if the volume is increased while the temperature is held constant. This is because the pressure of a gas is inversely proportional to its volume, as stated by Boyle's Law. As the volume increases, the pressure decreases. If the temperature is also increased, the pressure will decrease even further, as the gas particles will have more energy and will be moving faster, which will cause them to spread out and fill the larger volume. Therefore, if the volume of the argon is increased from 100ml to 500ml and the temperature is also increased from 0C to 100C, we would expect the pressure to decrease significantly.

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argon at a pressure of 2 atm, fills a 100 ml vial at a temperature of 0C. What would the pressure of the argon be if we increase the volume to 500 ml, and the temperature at 100C?

Recovery = (Weight of product recovered ÷ Theoretical yield) × 100% Recovery = (0.251 g ÷ 0.27594 g) × 100% Recovery = 91.08%Therefore, the % recovery of the reaction between 2,3-dimethyl-1,3-butadiene and maleic anhydride to form cyclic anhydride was 91.08%.

Diels-Alder Reaction   Diels-Alder reaction is a chemical process that joins a conjugated diene with a dienophile (a compound containing a double bond) to form a six-membered ring called a cyclohexene ring. It is a chemical reaction that can be used to make new carbon–carbon bonds. The reaction was discovered by two German scientists, Otto Diels and Kurt Alder, in 1928.In the Diels-Alder reaction between 2,3-dimethyl-1,3-butadiene and maleic anhydride to form cyclic anhydride, the % recovery was calculated using the following data:Weight of maleic anhydride used: 185 mg = 0.185 gVolume of diene used: 0.215 mLWeight of cyclic anhydride crystals recovered: 0.251 g% Recovery:We can calculate the percent recovery using the following formula:% Recovery = (Weight of product recovered ÷ Theoretical yield) × 100The theoretical yield of the product can be calculated from the balanced chemical equation as follows:2,3-dimethyl-1,3-butadiene + Maleic Anhydride → Cyclohexene-1,2-dicarboxylic AnhydrideThe molar mass of 2,3-dimethyl-1,3-butadiene is 68 g/mol. The molar mass of Maleic Anhydride is 98 g/mol. The molar mass of Cyclohexene-1,2-dicarboxylic Anhydride is 146 g/mol.Using these values, we can calculate the number of moles of each reactant: moles of diene used = (0.215 mL)(0.788 g/mL)/(68 g/mol) = 0.00248 mol moles of maleic anhydride used = 0.185 g/98 g/mol = 0.00189 mol The theoretical yield of cyclohexene-1,2-dicarboxylic anhydride = 0.00189 mol × 1 mol/1 mol = 0.00189 molThe theoretical yield of cyclohexene-1,2-dicarboxylic anhydride = 0.00189 mol × 146 g/mol = 0.27594 gNow, we can substitute these values into the percent recovery equation:% Recovery = (Weight of product recovered ÷ Theoretical yield) × 100% Recovery = (0.251 g ÷ 0.27594 g) × 100% Recovery = 91.08%Therefore, the % recovery of the reaction between 2,3-dimethyl-1,3-butadiene and maleic anhydride to form cyclic anhydride was 91.08%.

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Ovulation is the process in which mature egg is released from ovary.

The process in which a mature egg is released from ovary is known as Ovulation. It occurs as a LH (Luteinizing hormone) surge. Ovulation process occurs every month. In the ovulation process the ovum enters in the fallopian tube.

A menstrual cycle is divided into four phase:

Thus from the above conclusion we can say that Ovulation is the process in which mature egg is released from ovary.  

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The coefficient for OH⁻(aq) in the balanced equation is 8. The equation of a redox reaction in which oxidation and reduction take place is known as a redox equation.

To balance the equation in basic aqueous solution, the following steps can be followed:

Balance the atoms other than oxygen and hydrogen. In this case, Mn and S are already balanced.

Balance oxygen atoms by adding H₂O to the side that needs more oxygen. In this case, the left side needs more oxygen, redox reaction so we add H₂O to the left side:

MnO₄⁻(aq) + H₂S(g) → S(s) + MnO₂(s) + H₂O

Balance hydrogen atoms by adding H⁺ ions to the side that needs more hydrogen. In this case, the right side needs more hydrogen, so we add H⁺ ions to the right side:

MnO₄⁻(aq) + H₂S(g) → S(s) + MnO₂(s) + H₂O + 4H⁺

Balance the charge by adding electrons. In this case, the left side has a charge of -1, while the right side has a charge of +2. To balance the charges, we add 6 electrons to the left side:

MnO₄⁻(aq) + H₂S(g) + 6OH⁻(aq) → S(s) + MnO₂(s) + H₂O + 4H₂O + 6e⁻

Finally, balance the electrons by multiplying the half-reactions by appropriate coefficients. In this case, we multiply the reduction half-reaction by 6 and the oxidation half-reaction by 1:

6MnO₄⁻(aq) + 6H₂S(g) + 6OH⁻(aq) → 6S(s) + 6MnO₂(s) + 7H₂O

Therefore, the coefficient for OH⁻(aq) in the balanced equation is 6 × 2 = 12.

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The state of Matter in which the  Forces of Attraction is the Weakest is the gaseous state.

The forces of attraction that depends on the intermolecular attractions or the repulsions. The intermolecular repulsions are greater in the gaseous state than the intermolecular forces of attraction. The molecules have the more randomness in the gaseous state as compared to other states. The state of matter that has the least intermolecular forces of the attraction is the gaseous state because of the reason they are in random in the motion.

Thus, in the gaseous state of the matter, the Forces of Attraction the Weakest.

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The experimental set up in B is to observe the growth the green beans without the addition of fertilizer. Thus, we can compare the growth of the plant with and without fertilizer and thereby we can understand the effect the fertilizer on the plant growth.

Fertilizers are chemical substances used to nourish the plants by making the soil rich in nutrients and minerals. Plants needs minerals along with water such as potassium, calcium, phosphorous, nitrogen etc.

Sometimes the soil comes deficient of these minerals and we have to fertilize the soli by the addition of the chemicals containing these minerals. Hence, fertilizers provide a nutrient rich soil for plant growth.

The experimental set up with fertilizer added plant and the second one (B) without fertilizer helps to compare the growth in both conditions and we can clearly understand how fertilizers effect the growth of plants by comparing the plant growth in A and B.

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Answer:

415.401g

Explanation:

1 mol of CaCl = 75.5g

5.502mol of CaCl = xg

so 5.502 × 75.5 = 415.401g

2.56 x 10²² propane molecules must be burned with 6.82 grams of oxygen.

The following is the balanced equation for propane combustion:

\(C3H8 + O2 = 3CO2 + 4H2O\)

Hence, we require 5 oxygen molecules for every molecule of propane.

We must multiply the quantity of propane molecules by the ratio of oxygen molecules to propane molecules in order to determine how many oxygen molecules are needed to burn 2.56 x 1022 propane molecules.

\(O2\) to \(C3H8\) Ratio: 5:1

The necessary number of O2 molecules is (5/1) times 2.56, which equals 1.28 x 10²³.

So, using the molar mass of oxygen, we can convert the quantity of oxygen molecules to grams.

1 mole of \(O2\) = 32 g

1.28 x 10²³ molecules of O2 = (1.28 x 10²³/ 6.022 x 10²³) moles of O2

Mass of \(O2\) = (1.28 x 10²³/ 6.022 x 10²³) x 32 g.

Mass of \(O2\) = 6.82 grams.

Hence, 6.82 grams of \(O2\) are required to burn 2.56 x 10²² propane molecules.

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Answer:

There are three main sources of heat in the deep earth: (1) heat from when the planet formed and accreted, which has not yet been lost; (2) frictional heating, caused by denser core material sinking to the center of the planet; and (3) heat from the decay of radioactive elements.

Answer:

Internal sources of energy mean they are coming from within the earth

Explanation:

An atom X that has 12 protons and 12 electrons, loses 2 electrons to form an ions,  the charge of ion will be X⁺² the number of protons 12 and electrons in the ions is 10.

An atom X has 12 protons and 12 electrons that means X is a neutral atom and the atomic no. is 12 because total no. of protons is equal to atomic number. When it looses the 2 electrons then atom becomes positively charged ion . the charge on the ion is +2.

now, the no. of protons will be = 12

number of electrons will be = 12 - 2 = 10

Thus, An atom X that has 12 protons and 12 electrons, loses 2 electrons to form an ions,  the charge of ion will be X⁺² the number of protons 12 and electrons in the ions is 10.

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Answer:

When nitric acid reacts with ammonia, ammonium nitrate is formed.

Here we have to first determine the value of pOH from the given value of pH and have to obtain the concentration of hydroxide ion. The base will be LiOH.

The pH of a solution is defined as the negative logarithm of hydronium ion concentration in moles per litre. Mathematically it is given as:

pH = -log [H₃O⁺]

We have the relation, pH + pOH = 14

Then pOH = 14 - pH = 14 - 12 = 2

[OH⁻] = -log [pOH]

= -log (2)

= 10⁻² M

= 0.01 M

The molar mass of base is:

[OH⁻] = Mass of the base × 1000 / Molar mass × volume

0.01 = 0.02 × 1000 / 0.01 × 83

= 24 mol / gm

Thus LiOH has the molar mass of 24 mol / gm.

Thus the identified base is LiOH.

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The mole of HCl produced is 0.26 mole.

The mole of MgCl₂ that reacted is 0.13 mole.

The mass of MgCl₂ that reacted is 12.38 grams.

From the equation of the reaction:

MgCl₂(s) + H₂O(g) → MgO(s) + 2HCl(g)

The mole ratio of MgCl₂ and HCl is 1:2, while the mole ratio of H₂O and HCl is also 1:2.

5.85 L of HCl was produced. Based on the assumption that the gas was produced at STP.

1 mole of gas at STP = 22.4 L

Thus, 5.85 L of HCl would be equivalent to:

5.85 x 1/22.4 = 0.26 mole.

In other words, the mole of HCl produced is 0.26 mole.

The moles of MgCl₂ produced can be obtained from the mole ratio of MgCl₂ and HCl (2:1):

  0.26/2 = 0.13 mole

The mass of MgCl₂ produced can be obtained from the formula:

mass = mole x molar mass

Molar mass of MgCl₂ = 95.211 g/mol

mass of 0.13 mole MgCl₂ = 0.13 x 95.211

                                         = 12.38 grams

In other words, 12.38 grams of MgCl₂ reacted to produce 5.85 L of HCl according to the equation.

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ΔU of the reaction the combustion of compound x is -538 kJ/mol

Combustion is a reaction in which a substance reacts with oxygen gas and releasing energy in the form of light and heat

Here given data is

Mass of compound x = 0.485gram

Mass of water = 3000gram

Temprature rise =  0. 285°C

Heat capacity of the calorimeter = 3. 81 kJ/°C

Specific heat of water =  4. 184 J/g·°C

MW of x = 56. 0 g/mol

Then calculate q

ΔU = ΔH -PΔV

The bomb calorimeter has a constant volume ΔV = 0

ΔU = ΔH

q reaction = q(water + q(bomb)

q(bomb) = 3810J/°C×0.285 = 1085.85J

q(water) = 3000g × 4. 184 J/g·°C×0.285°C = 3577.32 J

q reaction = q(water) + q(bomb)

q reaction = 4663.17 J = 4.66kJ means this is an exothermic

Then calculate moles of compound

Moles = mass/molar mass

Moles = 0.485 g/56.0g/mol

Moles = 0.00866 moles

Then calculate ΔU

ΔU = 4663.17 J/0.00866 moles = 538472 j/mol = 538.5kJ/mol means the reaction is exothermic

ΔU = -538kJ/mol

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Answer: The kinetic energy of an object depends on both its mass and velocity, with its velocity playing a much greater role. Examples of Kinetic Energy: ... A baseball thrown by a pitcher, although having a small mass, can have a large amount of kinetic energy due to its fast velocity.

Explanation:

Hope this help

The balanced symbol equation for the Haber process, which is the industrial method for producing ammonia, is N2 + 3H2 → 2NH3

A. The Haber process is the industrial method for producing ammonia, and the balanced equation for the reaction is:

N2 + 3H2 → 2NH3

The atom economy for a product is the percentage of the total mass of reactants that becomes the desired product. For ammonia, the atom economy can be calculated as follows:

Molar mass of NH3 = 14.01 + 3(1.01) = 17.04 g/mol

Atom economy of NH3 = (2 mol NH3 x 17.04 g/mol) / [(1 mol N2 x 28.02 g/mol) + (3 mol H2 x 2.02 g/mol)] x 100% = 34.0%

B. To calculate the theoretical yield of ammonia, we need to use the given mass of nitrogen and the stoichiometry of the balanced equation. The molar mass of nitrogen is 28.02 g/mol, so 27.3 g of nitrogen is equal to:

27.3 g / 28.02 g/mol = 0.974 mol N2

According to the balanced equation, 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3. Therefore, the theoretical yield of ammonia is:

Theoretical yield of NH3 = (0.974 mol N2) x (2 mol NH3 / 1 mol N2) x (17.04 g/mol NH3) = 33.1 g NH3

C. The percentage yield of the reaction can be calculated by dividing the actual yield of ammonia by the theoretical yield, and then multiplying by 100%. The actual yield of ammonia is given as 29.9 g:

Percentage yield of NH3 = (29.9 g NH3 / 33.1 g NH3) x 100% = 90.4%

D. The percentage conversion of hydrogen can be calculated by dividing the mass of hydrogen used in the reaction by the mass of hydrogen that would have been used if all of it had been consumed in the reaction. The mass of hydrogen used is 10.4 g, and the mass of hydrogen that would have been used if all of it had been consumed in the reaction is:

1( mol H2 x 2.02 g/mol) x (0.974 mol N2 / 1 mol N2) = 1.98 g H2

Therefore, the percentage conversion of hydrogen is:

Percentage conversion of H2 = (10.4 g H2 / 1.98 g H2) x 100% = 525% (This result is not possible, as the percentage conversion cannot be greater than 100%. It is likely that there was an error in the calculation or in the data provided.)

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There are 0.164 moles of CO in 46 g. Thus 0.98 x 10²³ is the number of atoms in  4.60 grams of carbon monoxide, according to the Avogadro number.

The Avogadro number, often known as the Avogadro constant, is the number of units contained in one mole of any substance. 6.0221408571023 is the equivalent. Depending on the type of reaction taking place and the substance being used, the units could be electrons, ions, atoms, or molecules. Amedeo Avogadro discovered that two gases of the same volume have the same number of molecules when they are at the same temperature and pressure.

So the molar mass of CO is 28.01 g/mol.

There are 0.164 moles of CO in 46 g.

Hence in one mole, there is Avogadro number of molecules

i.e. 6.023×1023 6.023 × 10²³ molecules.

no of atoms = 0.164 x 6.023

= 0.98 x 10²³

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To change the hydraulic fluid on a Husqvarna zero-turn mower, you'll need to drain the old fluid, replace the filter, and add new hydraulic fluid.


1. Park the mower on a level surface and engage the parking brake.
2. Locate the hydraulic reservoir and filter. Consult your owner's manual if necessary.
3. Place a drain pan beneath the hydraulic reservoir to catch the old fluid.
4. Remove the drain plug or hose to allow the fluid to drain completely.
5. While the fluid is draining, replace the hydraulic filter by unscrewing the old one and installing a new one.
6. Once the fluid has finished draining, reinstall the drain plug or hose.
7. Fill the hydraulic reservoir with new hydraulic fluid, following the manufacturer's recommended specifications.
8. Start the mower and let it run for a few minutes to circulate the new fluid. Check for any leaks and ensure the hydraulic system is functioning properly.

Changing the hydraulic fluid on your Husqvarna zero-turn mower is a relatively simple process that involves draining the old fluid, replacing the filter, and adding new hydraulic fluid. Always consult your owner's manual for specific instructions and safety precautions.

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The plant’s production of carbohydrates stops producing high-energy sugars altogether.

When carbon dioxide is completely removed from a plant's environment it is expected that the plant will stop producing energy-rich sugars altogether.CO2 is required for plants to photosynthesize. So without CO2, plants have no way to make energy. In this scenario, it will probably wither.

Carbon dioxide is an important greenhouse gas and helps trap heat in the atmosphere. Without them, our planet would be uninhabitable and cold. Plant photosynthesis produces oxygen and carbohydrates in a strict ratio, so we run out of oxygen as soon as we eat. But lethal levels of carbon dioxide will be reached long before these things happen.

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