find the radius circumference of this circle

Answer:

SORRY PEOPLE SHOULD NOT HELP BECAUSE WHAT IF A KID DOING a school test comes on this website and cheats and gets a answer.  - Teacher

Step-by-step explanation:

To determine whether the given lines are parallel, we need to compare their direction vectors. For the first line, the direction vector is <0,2,-3>, since the coefficients of t for x, y, and z are all 0, 2, and -3 respectively. For the second line, the direction vector is <3,-61,9>, since the coefficients of t for x, y, and z are all 3, -61, and 9 respectively.

Two lines are parallel if and only if their direction vectors are scalar multiples of each other. In other words, if one direction vector can be obtained by multiplying the other direction vector by a constant, then the lines are parallel.

To check if this is the case, we can compare the ratios of the corresponding components of the two direction vectors. For example, we can compare the ratio of the x-components, which is 0/3 = 0, and the ratio of the y-components, which is 2/-61 (which simplifies to -2/61). We can also compare the ratio of the z-components, which is -3/9 (which simplifies to -1/3).

If all three ratios are equal, then the two direction vectors are scalar multiples of each other, and the lines are parallel. However, if any of the ratios are different, then the two direction vectors are not scalar multiples of each other, and the lines are not parallel.

Comparing the ratios we obtained, we see that they are all different. Therefore, the two direction vectors are not scalar multiples of each other, and the lines are not parallel.
To determine whether the given lines are parallel, we need to compare their direction vectors.

For the first line, the direction vector is given by the coefficients of the parameter t: (2, -1, -3).
For the second line, the direction vector is given by the coefficients of the parameter t: (3, -6, 9).

Now, we need to check if these direction vectors are proportional (i.e., one is a scalar multiple of the other). Let's compare the ratios:

2/3 = -1/-6 = -3/9

2/3 = 1/6 = -1/3

As we can see, the ratios are not equal. Therefore, the given lines are not parallel.

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A distribution of scores on a driver's license test forms is normally shaped. This is an example of a symmetrical distribution is TRUE.

A symmetrical distribution is a distribution where there is an equal number of data points on both sides of the center point, in which the mean, mode, and median of a data set are all similar.

A normal distribution is a bell-shaped distribution that is symmetrical, with most of the data falling near the mean and progressively less toward the tails. When data are symmetrical, the mean and median values are similar, and the standard deviation can be used to compute the proportions of data within a range of values surrounding the mean.

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Answer:

A = (5, 3), so the x-value is 5

Step-by-step explanation:

Answer:

(5, 3), so the x-value is 5

Step-by-step explanation:

Person above me right thank you person above me

By answering the presented question, we may conclude that Therefore, equation Lucas ran 12 laps.

An equation in mathematics is a statement that states the equality of two expressions. An equation is made up of two sides that are separated by an algebraic equation (=). For example, the argument "2x + 3 = 9" asserts that the phrase "2x Plus 3" equals the number "9." The purpose of equation solving is to determine the value or values of the variable(s) that will allow the equation to be true. Equations can be simple or complicated, regular or nonlinear, and include one or more elements. The variable x is raised to the second power in the equation "x2 + 2x - 3 = 0." Lines are utilised in many different areas of mathematics, such as algebra, calculus, and geometry.

If the ratio of the number of laps Stew ran to the number of laps Lucas ran was two to three, we can set up a proportion:

2/3 = 8/x

2x = 3(8)

2x = 24

x = 12

Therefore, Lucas ran 12 laps.

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Answer:

-4

Step-by-step explanation:

The linear function equation is \(y=mx+b\). \(m\) is the slope, \(b\) is the y-intercept.

The weekly time card is an illustration of tables and charts

Eddie works 40 hours each week

From the employee time card (see attachment), the hours worked each day is represented with red ink.

So, the hours worked each day are:

To do this, we add up the hours worked each day.

So, we have:

\(Weekly = 8 + 8.25 +7.5 + 8.25 + 8\)

\(Weekly = 40\)

Hence, Eddie works 40 hours each week

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(24 ÷ 3) + x expresses the expression that represents the quotient of 24 and 3 plus x.

The expression refers to a mathematical phrase with two or more numbers or variables with mathematical operations such as addition, subtraction, division, multiplication, exponential, and so on. Examples of expression include 2a + 3p, and 9p.

To convert the given phrase into the expression, we have to start with the first operation which is a division that is represented by the word quotient. Thus we get 24 ÷ 3

Then we add the operation of addition which is represented by the word plus to the existing equation and we get (24 ÷ 3) + x

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Explanation:

The sign of the product of any odd number of negative integers is positive because when two minuses are multiplied with each other, it will result in a positive number.

For example:

Hoped this helped!

Answer:

5040 ways

Step-by-step explanation:

There will be 13 chairs altogether.

Since there are 7 girls who cannot sit together, the pattern will be alternate.

→ G, B, G, B, G, B, G, B, G, B, G, B, G

Total Ways

The required answer is the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

Explanation:-

a. Economic order quantity (EOQ) is defined as the optimal quantity of inventory to be ordered each time to reduce the total annual inventory costs.

It is calculated as follows: EOQ = sqrt(2DS/H)

Where, D = Annual demand = 100 x 52 = 5200S = Order cost = $57 per order H = Annual holding cost = 0.30 x 10.75 = $3.23 per bag per year .Therefore, EOQ = sqrt(2 x 5200 x 57 / 3.23) = 234 bags. The average time between orders (TBO) can be calculated using the formula: TBO = EOQ / D = 234 / 100 = 2.34 weeks ≈ 2 weeks (rounded to nearest whole number).

Hence, the EOQ is 234 bags and the average time between orders is 2 weeks (approx).b. R is the reorder point, which is the inventory level at which an order should be placed to avoid a stockout.

It can be calculated using the formula:R = dL + zσL

Where,d = Demand per day = 100 / 5 = 20L = Lead time = 1 week (5 working days) = 5 day

z = z-value for 92% cycle-service level = 1.75 (from standard normal table)σL = Standard deviation of lead time demand = σ / sqrt(L) = 16 / sqrt(5) = 7.14 (approx)

Therefore,R = 20 x 5 + 1.75 x 7.14 = 119.2 ≈ 120 bags

Hence, the reorder point R should be 120 bags.c. An inventory withdraw of 10 bags was just made. Is it time to reorder?The current inventory level is 310 bags, which is greater than the reorder point of 120 bags. Since there are no open orders or backorders, it is not time to reorder.d. The store currently uses a lot size of 500 bags (i.e., Q = 500).What is the annual holding cost of this policy.

Annual ordering cost. Without calculating the EOQ, how can you conclude the lot size is too large?Annual ordering cost = (D / Q) x S = (5200 / 500) x 57 = $592.80 per year.

Annual holding cost = Q / 2 x H = 500 / 2 x 0.30 x 10.75 = $806.25 per year. Total annual inventory cost = Annual ordering cost + Annual holding cost= $592.80 + $806.25 = $1,399.05Without calculating the EOQ, we can conclude that the lot size is too large if the annual holding cost exceeds the annual ordering cost.

In this case, the annual holding cost of $806.25 is greater than the annual ordering cost of $592.80, indicating that the lot size of 500 bags is too large.e.

The annual cost saved by shifting from the 500-bag lot size to the EOQ can be calculated as follows:Total cost at Q = 500 bags = $1,399.05Total cost at Q = EOQ = Annual ordering cost + Annual holding cost= (D / EOQ) x S + EOQ / 2 x H= (5200 / 234) x 57 + 234 / 2 x 0.30 x 10.75= $245.45 + $93.68= $339.13

Annual cost saved = Total cost at Q = 500 bags - Total cost at Q = EOQ= $1,399.05 - $339.13= $1,059.92

Hence, the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

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Answer:

2, -2, -6, -10

Step-by-step explanation:

In this graph, the x value represents the count of the terms, while the y represents the value of each term. This means that the value of the first one is 2, the value of the second one is -2, the third one -6, and the fourth one -10. Hope this helps!

Answer:

a = 7

Step-by-step explanation:

Let's solve your equation step-by-step.

3/5(a+5.25)=7.35

Step 1: Simplify both sides of the equation.

3/5(a+5.25)=7.35

(3/5)(a)+(35)(5.25)=7.35 (Distribute)

3/5a+3.15=7.35

Step 2: Subtract 3.15 from both sides.

3/5a+3.15−3.15=7.35−3.15

3/5a=21/5

Step 3: Multiply both sides by 5/3.

(5/3)*(3/5a)=(5/3)*(21/5)

a=7

The function n³ + n! belongs to the class O(n³).

The limit test for big O notation:

Now let's choose bn = n^n.

Then we have:lim n→∞ n² + n^(n-1) / n^n= lim n→∞ n^-1 + n^(n-1)/n^n

Using the theorem, we can show that this approaches 0 as n approaches infinity, which means that n³ + n! = O(n³).

: O(n³)

:We evaluated the function using the limit test for big O notation and found that it is bounded by n² + n^(n-1)/bn, which can be simplified to n³ + n! = O(n³).

Summary: The function n³ + n! belongs to the class O(n³).

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Answer:

use average seep hours

top = 77/12 = 6.4 (most)

middle = 6 (middle)

bottom = 50/9 = 5.5 (least)

Step-by-step explanation:

The correct option is a b c d.

fd = 2,809

We need to round the given answers to the nearest hundredth.

a. 150, 150, fd = 2,809

Now, we need to find 150 such that it is the same percentage as 2,809 of 150.

150 * (2,809/100) = 4.2135 ≈ 4.21

So, 150, 150, fd = 2,809 ≈ 4.21, 4.21, fd ≈ 100

b. 150, 150, fd = 2,809

Now, we need to find 150 such that it is the same percentage as 2,809 of 150.

150 * (2,809/100) = 4.2135 ≈ 4.21

So, 150, 150, fd = 2,809 ≈ 4.21, 4.21, fd ≈ 100

c. 150, 150, fd = 53

Now, we need to find 150 such that it is the same percentage as 53 of 150.

150 * (53/100) = 79.5 ≈ 79.5

So, 150, 150, fd = 53 ≈ 79.5, 79.5, fd ≈ 100

d. 150, 150, fd = 53

Now, we need to find 150 such that it is the same percentage as 53 of 150.

150 * (53/100) = 79.5 ≈ 79.5

So, 150, 150, fd = 53 ≈ 79.5, 79.5, fd ≈ 100

Therefore, the correct option is a b c d.

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Answer:

15/13 OR 1.154

Step-by-step explanation:

2 1/2=5/2

2 1/6=13/6

5/2 / 13/6

=5/2 x 6/13

=30/26

=15/13

=1.15384615385

≈ 1.154

The term is called an identity element. In multiplication, the identity element is one because any number multiplied by one results in the same number. In addition, the identity element is zero because any number added to zero results in the same number.

The term in mathematics for the operation or number that leaves others unchanged when combined with them is called the identity element.

It is also known by the name of neutral element.

In multiplication, the identity element is one (1) because when you multiply a number by one the result remains the same as the original number. For any number a,

a1=1a=a.

While in addition, the identity element is zero (0) because when you add zero to a number, the result remains the same as the original number. For any number a,

a+0=0+a=a.

There is no identity element for subtraction, and division only has an identity element for certain sets.

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The values of μ and σ after converting the pulse rates of women to z-scores are: μ = 0 (since the mean of z-scores is always 0). σ = 1 (since the standard deviation of z-scores is always 1). Correct option is D.

To convert pulse rates of women to z-scores using the formula z = (x - μ) / σ, we can use the given values:

μ (mean) = 77.5 beats per minute

σ (standard deviation) = 11.6 beats per minute

To calculate the z-scores, we subtract the mean from each individual pulse rate and divide it by the standard deviation.

The units of the original pulse rates are "beats per minute." When we convert the pulse rates to z-scores, the resulting z-scores are numbers without units of measurement (choice D). Z-scores represent the number of standard deviations an observation is from the mean, and they do not have the same units as the original data.

Therefore, the values of μ and σ after converting the pulse rates of women to z-scores are:

μ = 0 (since the mean of z-scores is always 0)

σ = 1 (since the standard deviation of z-scores is always 1)

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Pulse rates of women are normally distributed with a mean of 77.5 beats per minute and a standard deviation of 11.6 beats per minute. Answer the following questions.

What are the values of the mean and standard deviation after converting all pulse rates of women to z scores using z=(x−μ)σ​?

μ=σ=

The original pulse rates are measure with units of​ "beats per​ minute". What are the units of the corresponding z​ scores? Choose the correct choice below.

A. The z scores are measured with units of​ "beats per​ minute."

B. The z scores are measured with units of​ "minutes per​ beat."

C. The z scores are measured with units of​ "beats."

D. The z scores are numbers without units of measurement.

Answer:

  11,180

Step-by-step explanation:

The usual assumption for organic growth is that it is exponential. Here, the number increased by a factor of 1000/200 = 5 in 8 hours. For t in hours, a model for population might be ...

  b = (initial value)·(growth factor)^(t/(period of growth))

  b = 200(5^(t/8))

Using t = 20, the predicted population is ...

  b = 200(5^(20/8)) = 200·5^2.5 ≈ 11,180

There might be about 11,180 bacteria in 20 hours.

Answer:

11,180

Step-by-step explanation:

a) Evaluating the polynomial 3x^2 + x + 1 at x = 2 using the conventional algorithm involves several assignment steps. The values assigned at each step are calculated and shown in detail.

b) To evaluate a polynomial of degree n at x = c using the conventional algorithm, there are a total of n multiplications and n additions required, excluding additions used to increment variables.

a) To evaluate the polynomial 3x^2 + x + 1 at x = 2, we follow the conventional algorithm step by step:

Assign c = 2.

Assign y = 0.

Assign y = y + (3 * c^2) = y + (3 * 2^2) = y + 12.

(Here, we calculate the value of the first term, 3x^2, by substituting c = 2 into the polynomial.)

Assign y = y + (1 * c) = y + (1 * 2) = y + 2.

(We calculate the value of the second term, x, by substituting c = 2.)

Assign y = y + 1.

(Finally, we calculate the value of the constant term, 1.)

The final value of y is the value of the polynomial at x = c, which in this case is 17.

b) To evaluate a polynomial of degree n at x = c using the conventional algorithm, there are n multiplications involved. Each term in the polynomial requires one multiplication with the corresponding coefficient and the value of c raised to the appropriate power.

Additionally, there are n additions required to accumulate the values of each term. Therefore, the total number of multiplications and additions is both equal to the degree of the polynomial, n.

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Answer:

-2

Step-by-step explanation:

Notice that 1/e^2 = e^(-2), by power rules.

Now ln(e^x)=x.

So ln(1/e^2) = ln(e^(-2))=-2

The average change in the volume of water per day is obtained as 0.625  litres.

The rate change of volume is the change of volume with respect to time.

For instantaneous change the derivative of the expression of volume can be taken.

The average change in the volume of water can be obtained as follows,

Average change = Volume of water ÷ Number of days

                            = 2.5 ÷ 4 = 0.625

Hence, the average change in water volume is given as  0.625 liters per day.

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Answer:

3>-3

Step-by-step explanation:

3 is larger than -3

The nurse will add 40 mL of diluent to the vials, resulting in a dosage strength of 48 mg/mL. The nurse will administer 20 mL of reconstituted gemcitabine.

To calculate these values, we can use the information provided in the package insert. If each vial contains 200 mg of gemcitabine powder, then 5 vials would contain a total of 1000 mg. To prepare a dose of 960 mg, the nurse would need to use 4.8 mL of the reconstituted solution.

To determine the amount of diluent needed, we can use the formula:

Amount of Diluent = Total Volume - Amount of Powder

The total volume is the sum of the volumes of the powder and the diluent. If the package insert recommends a diluent volume of 40 mL per vial, then the total volume for 5 vials would be:

Total Volume = 5 x (4 mL + 40 mL) = 220 mL

So the amount of diluent needed is:

Amount of Diluent = 220 mL - 5 x 4 mL = 200 mL

Therefore, the nurse will add 40 mL of diluent to the vials.

The resulting dosage strength is:

Dosage Strength = Total Amount of Powder / Total Volume

Total Amount of Powder = 1000 mg

Total Volume = 200 mL

Dosage Strength = 1000 mg / 200 mL = 5 mg/mL

To administer a dose of 960 mg, the nurse would need to use:

Amount of Reconstituted Solution = Dose / Dosage Strength

Amount of Reconstituted Solution = 960 mg / 5 mg/mL = 192 mL

Rounding to the nearest tenth, the nurse will administer 20 mL of reconstituted gemcitabine.

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If a typical giant hummingbird can flap its wings once in 0.08 of a second, we can calculate the number of times it will flap its wings in 7.2 seconds by dividing the total time by the time for one wing flap.

Number of wing flaps = Total time / Time for one wing flap. Number of wing flaps = 7.2 seconds / 0.08 seconds. Number of wing flaps = 90. Therefore, a typical giant hummingbird will flap its wings 90 times in 7.2 seconds. Since a ruby-throated hummingbird flaps its wings 4 times faster than a giant hummingbird, we can multiply the number of wing flaps for a giant hummingbird by 4 to find the number of wing flaps for a ruby-throated hummingbird in the same amount of time: Number of wing flaps (ruby-throated) = Number of wing flaps (giant) * 4. Number of wing flaps (ruby-throated) = 90 * 4 = 360.

Therefore, a ruby-throated hummingbird will flap its wings 360 times in the same amount of time.

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Answer:

\(\boxed {n = 1.8}\)

Step-by-step explanation:

Solve the following expression:

\(\frac{n}{-1.5} = - 1.2\)

-Multiply \(-1.5\) on both sides:

\((-1.5) \frac{n}{-1.5} = - 1.2 (-1.5)\)

\(n = 1.8\)

Therefore, the final answer is \(\boxed { n = 1.8}\).

Answer: n=1.8

Hope this helps!

Answer:

It's 8

Step-by-step explanation:

-1/7, since parallel lines have equal slopes.

Answer:

No

Step-by-step explanation: