Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 2.10 cm from the axis to equal 5.00×105 g (where g is the free-fall acceleration)

The radius of the orbit, measured from the center of Mars, should be approximately 1.04 x 10^7 meters to make the satellite take 8 times longer to complete one revolution of its orbit.

What is Orbit?

In physics, an orbit refers to the path that an object takes around another object under the influence of gravity. The object being orbited can be a planet, a star, a moon, or any other massive object. The object in orbit is constantly pulled towards the center of the object being orbited, but also has a forward velocity that keeps it moving in a curved path around the object

We can start by using the formula for the period of an orbit:

T = 2π √(r^3/GM)

where T is the period, r is the radius of the orbit, G is the gravitational constant, and M is the mass of the planet.

We can solve for r:

r = [(GMT^2)/(4π^2)]^(1/3)

We know that the satellite currently takes 9.2 hours to complete one revolution, so its current period is:

T1 = 9.2 hours = 33,120 seconds

We also know that we want the satellite to take 8 times longer to complete one revolution, so its new period will be:

T2 = 8 x T1 = 265,000 seconds

We can now plug in the given values into the equation to solve for the new radius:

r = [(G x mmars x T2^2)/(4π^2)]^(1/3)

r = [(6.67428 x 10^-11 N-m^2/kg^2) x (6.4191 x 10^23 kg) x (265,000 s)^2 / (4π^2)]^(1/3)

r ≈ 1.38 x 10^7 meters

However, we were asked for the radius measured from the center of Mars, so we need to subtract the radius of Mars to find the altitude above the surface:

altitude = r - rmars = 1.38 x 10^7 meters - 3.397 x 10^6 meters ≈ 1.04 x 10^7 meters

Therefore, the radius of the orbit, measured from the center of Mars, should be approximately 1.04 x 10^7 meters to make the satellite take 8 times longer to complete one revolution of its orbit.

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Answer:

D. Newton's third law of motion

Answer:

v' = -18 m/s

Explanation:

       \(p_{o} = p_{f} (1)\)

       \(m_{b} * v_{b} -M_{c}*V_{c} = m_{b} * 18 m/s + (-M_{c}* 20 m/s) (2)\)

        \(-(m_{b} * v'_{b}) + M_{c}*V'_{c} (3)\)

       \(-(m_{b} * v'_{b}) +(- M_{c}*V_{c}) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (4)\)

       \(m_{b} * 18 m/s + (-M_{c}* 20 m/s) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (5)\)

Answer:

7.447

Explanation:

Answer:then using equations of motion for constant acceleration, meaning the force providing the acceleration doesn't change throughout the motion. v^2 = u^2 +2as, v=final velocity, u = intial velocity=0, a=(f/m), s is distance over which the object is accelerated.

hope this helps! Brainlist?

Protons are located in the nucleus.

Protons and neutrons are found inside the nucleus. They group together in the centre of the atom. Protons are positively charged. Each atom has atleast one proton. Protons determine the identity of an atom.

Electrons are found in the orbits that surround the nucleus. They are negatively charged. In a neutral atom, the number of electrons is the same as the number of protons. They are much smaller than protons but have the same charge strength. As the charge of electrons is opposite in sign than protons, these two types of particles attract each other and this type of force is known as the Coloumb force.

Neutrons are the particles that have no charge and are about the same mass as protons. Not all the atoms have neutrons and the number of neutrons is not usually the same as the protons or electrons.

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2.1 Given that channel A's carrier frequency (100 kHz) and the IF frequency are different, the lowest local oscillator frequency that might be utilised to demodulate the signal on that channel is 50 kHz (50 kHz).

2.2 The difference between the IF frequency and the channel B carrier frequency (150 kHz) determines the lowest local oscillator frequency that could be used to demodulate the signal on channel B. This frequency is 100 kHz (50 kHz).

2.3 The difference between the carrier frequency of channel A and the local oscillator frequency is zero if the local oscillator is set to 100 kHz. Thus, the envelope of the modulated signal in channel A will be represented by a DC voltage (zero frequency) at the mixer's output. The channel B transmission won't be demodulated.

2.4 The difference between the carrier frequencies of channel A and channel B, assuming the local oscillator is set to 125 kHz, is 25 kHz, while the difference between channel B's carrier frequency and the local oscillator frequency is -25 kHz. Hence, the demodulated signal from channel A (1 kHz sinusoid) and the modulated signal will both be present in the mixer's output.

2.5 The difference between the carrier frequency of channel B and the local oscillator frequency is zero if the local oscillator is set to 150 kHz. Thus, the envelope of the modulated signal in channel B will be represented by a DC voltage (zero frequency) at the mixer's output. The channel A transmission won't be demodulated.

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Answer:

sorry i didn't understand

Answer:

you multiply and get a girl

Answer: Better to have a larger sample size to precisely calculate.

Explanation: Larger sample sizes enable the researchers to more precisely calculate the expected principles of their own data and avoid errors caused by testing a small number of potentially atypical samples.

A steam turbine receives steam with a velocity of 28 m/s, specific enthalpy 3000kJ/kg at a rate of 3500 kg per hour. The steam leaves the turbine with a specific enthalpy of 2200kJ/kg at 180 m/s then turbine output is 777.76kW.

To get the turbine output, we must first compute the change in specific enthalpy (h) and mass flow rate ().

Assume that the inlet steam velocity (v1) is 28 m/s.

Specific enthalpy at the inlet (h1) = 3000 kJ/kg

()=3500kg/h mass flow rate

2200 kJ/kg outlet specific enthalpy (h2)

v2 (outlet steam velocity) = 180 m/s

To begin, convert the mass flow rate from kg/h to kg/s as follows: =

\(3500 kg/h (1 h/3600 s) = 0.9722 kg/s\)

The change in specific enthalpy (h) can then be calculated:

3000kJ/kg-2200kJ/kg=800kJ/kgh=h1-h2

The following formula can be used to compute the turbine output (P):

\(P = ṁ * Δh\)

Substituting  P=0.9722kg/s*800kJ/kg=777.76kJ/sork W

As a result, ignoring losses, the turbine output is roughly 777.76kW

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Answer:

D - 1.52 m/s2

Explanation:

force: 125 N

Mass: 82 kg

you just divide the force by the mass which would be approximately 1.52

Answer:

The right solution is "4.8° east of north".

Explanation:

Given:

Distance,

= 500 km

Speed,

\(\vec{v}=120 \ m/s\)

Wind (towards west),

\(v_0=10 \ m/s\)

According to the question, we get

The angle will be:

⇒ \(\Theta=Cos^{-1}(\frac{v_0}{v_1} )\)

       \(=Cos^{-1}(\frac{10}{120} )\)

       \(=85.21\) (north of east)

hence,

The direction must be:

⇒ \(\Theta'=90-85.21\)

        \(=4.79^{\circ}\)

or,

        \(=4.8^{\circ}\) (east of north)

The value of spring constant (k) is 25 N/m.

Conservation of energy, potential energy of a stretched spring, gravitational potential energy, frequency of oscillation in a spring coupled to a mass, and variation of acceleration due to gravity with altitude are the principles necessary to answer the given problem.

To begin, use energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.

Formula apply

U=mgh

U=1/2kx^2

putting the value of K ,x ,mass and g then

k is 25N/m

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Answer:

  c.  in the absence of an unbalanced force, an object at rest will stay at rest and an object in motion will stay in motion.

Explanation:

First law: things keep doing what they are doing, unless force is applied.

Answer:

the answer is .D

Explanation:

force is greater than the boats weight

Answer: The buoyant force is less than the boats weight.

Answer:

yes

Explanation:

Answer:

Hmm looks tricky

Explanation:

The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).

Isaac's force:

Magnitude: 255 N

Angle: 13 degrees North of East

x-component: 255*cos(13) = 245.1 N (Eastward)

y-component: 255*sin(13) = 58.1 N (Northward)

Newton's force:

Magnitude: 156 N

Angle: 34 degrees South of East

x-component: 156*cos(34) = 129.4 N (Westward)

y-component: 156*sin(34) = 86.5 N (Southward)

Now we can add the x- and y-components of the forces to find the net force:

Net force:

x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)

y-component: 58.1 N - 86.5 N = -28.4 N (Southward)

The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).

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The highest energy, shortest wavelengths, and highest frequency are found in gamma rays.

An example of "electromagnetic" radiation is microwaved, which are waves of electrical and magnetic energy traveling across space together. There is a wide range of electromagnetic radiation, from very lengthy radio waves to very brief gamma rays.

Radiation with a wavelength shorter than visible light is known as ultraviolet light. If eye protection is not worn, UV exposure raises the risk of potentially blinding eye illnesses. UV radiation overexposure can cause major health problems, including cancer.

The waves are gamma rays (below 1 nm), x-rays (between 1 and 10 nm), infrared rays (between 700 and 105 nm), micro waves (between 105 and 108 nm), and radio waves (above 108 nm), in that order.

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The rumble feature on a video game controller is driven that turns electrical energy into mechanical energy. This device is best referred to as a motor.

An electric motor converts electrical energy into mechanical energy.

Thus, the option (D) is correct.

Yes, if a body is floating in a liquid, the rise in the liquid level is equal to the body height. This phenomenon is known as Archimedes' principle.

Archimedes' principle says when a body is immersed in a fluid (liquid or gas), it experiences an upward buoyant force equal to the weight of the fluid displaced by the body. Buoyant forces act in the opposite direction to gravity.

When a body floats in a liquid, it displaces a volume of liquid equal to its volume. As a result, the liquid level rises by an amount equal to the height of the submerged part of the body.

This principle holds for objects that float or are partially immersed in a liquid, such as a buoyant boat or a floating object. However, if the body sinks completely into the liquid, the liquid level rise will no longer be equal to its height. Instead, it depends on the density and volume of the submerged object.

Answer:

Explanation:

V = I R

V = 0.0418 * 30

V = 1.254

this battery seems dead  :P

Answer:

Explanation:

Let's just assume that the battery has no internal  resistance. If we get an absurd answer, we'll come back and look at that assumption.

E = I * R

I = 41.8/1000 amps = 0.0418

R = 30.0 ohms

E = 0.0418 * 30

E = 1.254 volts. This is an OK answer. The battery is a little old.

The magnification of a virtual image is 2. Magnification is defined as the ratio of image distance to object distance.

Magnification is the ratio of the image distance to the object distance.

The given data in the problem is;

Image distance (u) = 10 cm

Object distance (v) = 20 cm

The magnification of a virtual image is;

m=v/u

m=20/10

m=2

Hence the magnification of a virtual image is 2.

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Two references need to be modified. Pseudocode: tail.setNext(new_node) and tail = new_node.

To add a thing to a connected rundown, the main reference that should be changed is the reference of the ongoing tail hub to the new hub. Consequently, just a single reference should be changed.

Here is the pseudocode to carry out the append(item) technique:

1. Create a new node with the given item

2. Set the next reference of the current tail node to the new node

3. Set the new node as the new tail node

Accepting the connected rundown isn't unfilled and we approach the tail reference, the setNext(Node next) strategy permits us to adjust the following reference of the ongoing tail hub, and subsequently, attach the new hub to the furthest limit of the connected rundown.

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The complete question is:

In a Linked List, each node is an object, and objects are stored as references. Thus, each node has a reference that links it to the next node. We show references in diagrams with arrows, so the diagram below shows a Singly Linked List with head and tail references to the first and last nodes.

void prepend(item) // add item at the beginning

void append(item) // add item at the end

void add(item, position) // add item at specified position

Type get(position) // return item at specified position

Type remove(position) // remove & return item at position

int size() // return count of items

int indexOf(item) // return index of item if it exists

boolean contains(item) // return whether item exists in list

Consider implementing the append(item) method for a linked list. Assume: a) the list is not empty and you have access to the tail reference. b) you have access to the setNext(Node next) method.

What is the minimal number of references you need to modify in the initial linked list in order to append an item? Write pseudocode to describe how you would implement this

Answer:

Refer to the attachment

(1) the pressure of the skier is 416.67 N/m².

(2) the pressure exerted by the wheel is 76.67 N/m².

(3) the surface area of the knife is 0.03 m².

The pressure of the skier can be calculated using the formula:

pressure = force / area

Substituting the given values, we get:

pressure = 500 N / 1.2 m²

pressure = 416.67 N/m²

The pressure exerted by the wheel can be calculated using the same formula:

pressure = force / area

Substituting the given values, we get:

pressure = 23 N / 0.3 m²

pressure = 76.67 N/m²

The pressure exerted by the knife is given as 200 N/m² when a force of 6 N is applied. We can use the same formula to calculate the surface area of the knife:

pressure = force / area

Rearranging the formula, we get:

area = force / pressure

Substituting the given values, we get:

area = 6 N / 200 N/m²

area = 0.03 m²

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