Find the slope intercept form of an equation of the line perpendicular to the graph y = 2/3x - 5/3 and passing through the point (0, 6).

The perpendicular slope is:
State the y value of the y-intercept of the perpendicular line:
The equation of the perpendicular line is:

Answers

Answer 1

Answer:

Perpendicular slope: -3/2

Y-value of the y-intercept:  6

Linear equation of the perpendicular line: y = -3/2x + 6

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes, which means that multiplying the slopes of both lines will result in -1.

Given the linear equation, y = 2/3x - 5/3, and the point, (0, 6):

Let m1 = slope of line 1

     m2 = slope of the other line

Since the slope of y = 2/3x - 5/3 is 2/3, then the other line must have a slope of -3/2 because:

m1 × m2 = -1

\((\frac{2}{3}) (-\frac{3}{2}) = -1\)

Therefore, the slope of the other line (m2) = -3/2.

The y-intercept is the y-coordinate of the point where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0. The given point has coordinates (0, 6), which means that it is the y-intercept.  Its y-coordinate, (b) = 6.

Therefore, given the slope m = -3/2, and the y-value of the y-intercept, b = 6, then the equation of the perpendicular line is: y = -3/2x + 6.

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Related Questions

Find the equation of a line perpendicular to x=−4 that contains the point (−3,4). Write the equation in slope-intercept form.

Answers

Answer:

y=4

Step-by-step explanation:

We recognize x=−4 as a vertical line, so its perpendicular will be horizontal. The equation of the horizontal line containing the point (−3,4) is given by y=4.

The slope-intercept form of a line perpendicular to x=−4 that contains the point (−3,4) is y = 4.

What is the slope of a line that is perpendicular to the other line?

The slope-intercept form of a line is y = mx + c.

Here, m = slope and c = y-intercept of the line.

The equation of the given line is x = - 4

Therefore, the given line is a vertical line.

Now, the line that is perpendicular to the line x = - 4, is a horizontal line.

Now, the horizontal line that passes through the point (- 3, 4) is y = 4.

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Find the equation of a line perpendicular to x=4 that contains the point (3,4). Write the equation in

HELP . Gilligan sees a ship coming close to the shore he's standing on. He wants to

determine the distance (segment SD) from the ship to the shore. He walks 130 ft along the shore from point D to point C and marks that spot. Then he walks 23 ft further and marks point B. He turns 90° and walks until his location (point A), point C, and point S are collinear. Answer the following questions making sure to show all your work.

(a) Can Gilligan conclude that triangle ABC and triangle SDC are similar? Why or why not?

(b) Suppose AB = 50 ft. What is the distance from the ship to the shore? Show all your work and round your final answer to the nearest tenth of a foot.​

HELP . Gilligan sees a ship coming close to the shore he's standing on. He wants todetermine the distance

Answers

The distance (segment SD) from the ship to the shore and  Gilligan sees a ship coming close to the shore he's standing on.

The triangles ABC and SDC are similar.

Gilligan may deduce that triangles ABC and SDC are comparable.

Gilligan may deduce that the ship's distance from the cost is 509 feet.

The triangles ABC and SDC are similar.

Gilligan may deduce that triangles ABC and SDC are comparable.

Gilligan may deduce that the ship's distance from the cost is 509 feet.

We may deduce from the question that points S, C, and A are collinear, whereas lines AB and SD are vertical and parallel lines on either side of point C.

As a result, Gilligan may deduce that triangles ABC and SDC are comparable.

How to Determine SD Distance

To do this, we employ the corresponding ratio shown below.

90 should be substituted for AB.

Calculate as a fraction

Make SD the topic.

As a result, Gilligan may deduce that the ship's distance from the land is 509 feet.

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An outlier is a data value that differs greatly from other values in a data set.

Which is the outlier rule for the lower boundary?

Q1 + 1.5 ∙ IQR
Q3 + 1.5 ∙ IQR
Q1 − 1.5 ∙ IQR
Q3 − 1.5 ∙ IQR

Answers

Answer:

The person above me is correct.

Q1 − 1.5 ∙ IQR  (C) is your answer.

ED2021

For upper boundary its Q3 + 1.5 ∙ IQR (B). [This is the one right after]

The outlier rule for the lower boundary; Q1 − 1.5 ∙ IQR  (C) is your answer.

How to find the interquartile range?

IQR(inter quartile range)  is the difference between third and first quartile.

Quartiles are then selected as 3 points such that they create four groups in the data, each groups approximately possessing 25% of the data.

Lower quartile, also called first quartile has approx 25% in its left partition, and on its right lies approx 75% of the data.

Similarly, second quartile (also called median) is approximately in mid of the data.

Third quartile (also called upper quartile)  has approx 75% in its left partition, and on its right lies approx 25% of the data.

Given; An outlier is a data value that differs greatly from other values in a data set.

For upper boundary its Q3 + 1.5 ∙ IQR.

Therefore, the outlier rule for the lower boundary; Q1 − 1.5 ∙ IQR  (C) is your answer.

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If 20% of a number is 72 and 50% of the same number is 180, find 30% of that number.

Answers

Answer:

.20x = 72, so x = 360

.30(360) = 108

Researchers study the relationship between interpersonal violence and health in college age women. The selected an alpha of 0.05. The researchers wanted to see if there was a significant difference in the type of primary residence (home vs. student housing) for abused versus non abused college aged women. They report a p value of 0.35. You know this means:
Select There is an inadequate sample size. as your answer
There is an inadequate sample size.
Select A type II error has occurred. as your answer
A type II error has occurred.
Select There is a statistically significant difference in the type of primary residence for abused vs. non-abused college aged women. as your answer
There is a statistically significant difference in the type of primary residence for abused vs. non-abused college aged women.
Select There is not a statistically significant difference in the type of primary residence for abused vs. non-abused college aged women. as your answer
There is not a statistically significant difference in the type of primary residence for abused vs. non-abused college aged women.

Answers

Answer:

Explained below.

Step-by-step explanation:

A statistical hypothesis test is being performed to determine whether there was a significant difference in the type of primary residence (home vs. student housing) for abused versus non abused college aged women.

The hypothesis can be defined as:

H₀: There is no difference in the type of primary residence or abused versus non abused college aged women.

Hₐ: There is a significant difference in the type of primary residence or abused versus non abused college aged women.

The significance level of the test is:

α = 0.05

The computed p-value is:

p-value = 0.35

p-value = 0.35 > α = 0.05

The null hypothesis will not be rejected.

The p-value is inversely related to the sample size of the test.

That is, larger the sample size smaller is the p-value and smaller the sample size larger is the p-value.

A p-value of 0.35 is very large and unusual. This can happen because of the inadequate sample size selected.

As the p-value indicates an unusual result, it can be said that an error has been made while concluding that the null hypothesis is true, when in fact it is not.

This type of error is known as the type II error.

The correct decision should be:

There is a statistically significant difference in the type of primary residence for abused vs. non-abused college aged women.

Solve equation
17x-(2x-4)=79

Answers

Your conclusion would equal

x = 5

The answer would be 15 because 79-4=75 then 17x-2x=15x so the divide both sides by 15 and you get x=15

Erin records the following temperatures (in degrees
Fahrenheit) at noon during one week:
91, 95, 95, 95, 92, 95, 93
These temperatures do not contain an extreme value.
Which measure of center should Erin use to describe the temperatures?
O A. Mean absolute deviation (MAD)
B. Either the mean or the median. The values are about the same.
C. Interquartile range (IQR)
O D. Range

Erin records the following temperatures (in degreesFahrenheit) at noon during one week:91, 95, 95, 95,

Answers

Answer:

I think the correct answer should be B

Answer:

B

Step-by-step explanation:

B because there is no extreme values

How do you explain a math equation?

Answers

By doing doing the math question and explaining it at the same time

Find the size of the angle
3
x
.

Find the size of the angle 3x.

Answers

Answer:

Given - Two angles measures 2x and 3x

To find - size of 3x

Solution -

2x + 3x = 360° ( Make reflex angle )

5x = 360°

x = 360/5

x = 72°

3x = 3 * 72 = 216°

Is the relation shown in the table below a function? (type in yes or no)

Is the relation shown in the table below a function? (type in yes or no)

Answers

Answer:

Yes

Step-by-step explanation:

To know if a table is a function or not, we have to see if 1 input only has 1 output.

Looking at the table each input only has 1 output, so it is a function.

Which of the following statement(s) is (are) true?
I. The set of all second-degree polynomials with the standard operations is a vector space. II. The set of all first-degree polynomial functions 'mx' with the standard operations is a vector space. III. The set of second quadrant vectors with the standard operations is a vector space A) 1 B) II and III C) II and III D) 11

Answers

The true statement is; II. Option D

How to determine the correct statements

From the information given, we have that;

I. The set of all second-degree polynomials with the standard operations is a vector space

II. The set of all first-degree polynomial functions 'mx' with the standard operations is a vector space

III. The set of second quadrant vectors with the standard operations is a vector space

Note that;

All second- degree polynomials has no vector spaceAlso, all first - degree polynomials has a vector space

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Question 3
The first five triangular numbers are shown, where n represents the number of dots in the base of the figure, and d (n)
represents the total number of dots in the figure.
1 3 6
15
When n = 1, there is 1 dot. When n = 2, there are 3 dots. When n = 3, there are 6 dots. Notice that the total number of dots
d (n) increases by n each time.
Use induction to prove that d (n) = n(n+1)
10
Part A
Prove the statement is true for n = 1.

Answers

Question 3 is the answer 1

help plsssssssssssssssss

help plsssssssssssssssss

Answers

Answer:

Its is C! :)

Step-by-step explanation:

Hope you do Great! :)

brainliest would be nice:)

C is the answer for this question hope it helps

HELPPPPPPPPPPP PLEASEEEE.!!!!!!

HELPPPPPPPPPPP PLEASEEEE.!!!!!!

Answers

Answer:

it is the one with the open circle going to the left

Step-by-step explanation:

It is the one with the open circle going to the left

x2 - 3|x - 2| - 4x = - 6
Solve for x

Answers

Answer:

if that is x^2 -3|x-2|-4x=-6, then this should be the answer other wise it would be a biiiit diffrent

Step-by-step explanation:

x2 - 3|x - 2| - 4x = - 6Solve for x

Graph the system of inequality and shade the solution

2x+2y is greater than or equal to -6

x+y is less than or equal to -1

Answers

Answer: See attached.

Step-by-step explanation:

     First, we will graph the two inequalities. We will graph as we would with normal linear equations.

     However, 2x + 2y ≥ -6 uses a ≥ sign so we will shade above a solid line and x + y ≤ -1 uses a ≤ sign so we will shade below a solid line.

     The solution to this system of inequalities is where the shaded parts "overlap." You can see that in the attachment I have labeled it as such.

     These two lines are parallel, so there is no intersection between the two lines. However, there is an intersection between the shaded inequality lines, this gives us the solution.

Graph the system of inequality and shade the solution 2x+2y is greater than or equal to -6x+y is less

Y= - 1/2x + 5/2 what are the table solutions

Answers

Answer:

\(y = - \frac{1}{2} x + \frac{5}{2 } \\ y = \: x ( - \frac{1}{2}) + \frac{5}{2} \\ y = - \frac{6}{2} x \\ y = - 3x \\ \frac{y}{3} = x\)

The members of the city cultural center have decided to put on a play once a night for a week. Their auditorium holds 600 people. By selling​ tickets, the members would like to raise ​$3,900 every night to cover all expenses. Let x represent the number of adult tickets sold at ​$8.50. Let y represent the number of student tickets sold at ​$5.50 each. If all 600 seats are filled for a​ performance, how many of each type of ticket must have been sold for the members to raise exactly ​$3,900​? At one performance there were times as many student tickets sold as adult tickets. If there were 400 tickets sold at that​ performance, how much below the goal of ​$3,900 did ticket sales​ fall?

Answers

By using simultaneous linear equation, it can be calculated that 200 adult tickets and 400 student tickets were sold and the ticket sale falls $1320 below the goal of $3300.

What is simultaneous linear equation?

Equation shows the equality between two algebraic expressions by connecting the two algebraic expressions by an equal to sign.

A one degree equation is known as linear equation. Two or more linear equations, which can be solved together to obtain common solution are known as simultaneous linear equation.

The simultaneous linear equation needs to be solved

Let d represents the number of adult tickets and s represents the number of student tickets

Their auditorium holds 600 people

d + s = 600 ..... (1)

Price of adult ticket = $7.50

Price of student ticket = $4.50

Total price = $(7.50d + 4.50s)

Therefore,

7.50d + 4.50s = 3300

5d + 3s = 2200 ..... (2)

Multiplying (1) by 3

3d + 3s = 1800.... (3)

Subtracting (3) from (2)

2d = 400

d = 200

Putting the value of d in (1)

200 + s = 600

s = 600 - 200

s = 400

Now, Total tickets sold = d + 2d = 3d

d = 120

s = 240

Number of student ticket sold = 240

Number of adult ticket sold = 120

Total cost = 240  4.50 + 120  7.50

= $1980

Fall in ticket sale = $(3300 - 1980) = $1320

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A summary of the two stocks is shown.

Name of Stock Symbol Closing Price Day 1 Closing Price Day 2 Closing Price Day 3
Metropolis, Ltd MTP 17.95 18.25 18.28
Suburbia, Inc SBR 5.63 4.98 5.25

Suppose you purchase 65 shares of Metropolis stock and 50 shares of Suburbia stock on Day 1 at the closing price. Which day, during the following two days, would be the best to sell both stocks and by how much?
Day 2 is the best by $13.00.
Day 3 is the best by $13.00.
Day 2 is the best by $2.45.
Day 3 is the best by $2.45.

Answers

The day, from the following two days, which would be the best to sell both stocks with the closing price is day 3 by an amount of $2.45.

Given are the closing prices of two stocks in three days.

If you purchase 65 shares of Metropolis stock and 50 shares of Suburbia stock on Day 1 at the closing price,

Amount invested = (65 × 17.95) + (50 × 5.63) = $1448.25

If the stock is sold in day 2,

Amount received = (65 × 18.25) + (50 × 4.98) = $1435.25

Profit = $1435.25 - $1448.25 = -$13

If the stock is sold in day 3,

Amount received = (65 × 18.28) + (50 × 5.25) = $1450.7

Profit = $1450.7 - $1448.25 = $2.45

The profit is more for day 3 than day 2.

Hence it is best to sell on day 3 by $2.45.

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Are 9/21 and 6/14 equivalent fractions

Answers

Answer:

Yes

Step-by-step explanation:

9/21 SIMPLIFIED= 3/7

6/14 SIMPLIFIED= 3/7

no because you can’t evenly simplify them to the same number

Ramesh dan syarika ans. Ramesh takes a medical and health insurance policy with a deductible of RM1 500 per year and co-insurance of 20% of covered medical expenses. Ramesh went to the hospital for the first time for knee treatment and the medical cost was RM700, the medical cost for the second and third treatments was RM2 000 and RM1 700 respectively. The three treatments were in the same year. How much medical expenses should be borne by Ramesh and the insurance company? ​

Answers

Ramesh will bear a total medical expense of RM1,760, and the insurance company will cover RM2,900.

1. Ramesh's deductible is RM1,500 per year. This means that he is responsible for paying the first RM1,500 of medical expenses before the insurance coverage kicks in.

2. For the first treatment, the medical cost was RM700. Since this amount is less than the deductible, Ramesh will have to pay the entire RM700 out of pocket.

3. For the second treatment, the medical cost was RM2,000. Since Ramesh has already met his deductible with the first treatment, the insurance company will cover a portion of the expenses. Ramesh will be responsible for 20% of the remaining RM500 (RM2,000 - RM1,500), which amounts to RM100. The insurance company will cover the remaining 80% of RM500, which amounts to RM400.

4. For the third treatment, the medical cost was RM1,700. Again, since Ramesh has already met his deductible, the insurance company will cover a portion of the expenses. Ramesh will be responsible for 20% of the entire cost, which amounts to RM340 (20% of RM1,700). The insurance company will cover the remaining 80% of RM1,700, which amounts to RM1,360.

5. To calculate the total medical expenses borne by Ramesh, we add up the amounts he is responsible for in each treatment: RM700 + RM100 + RM340 = RM1,140.

6. The total medical expenses covered by the insurance company can be calculated by adding up the amounts they pay in each treatment: RM400 + RM1,360 = RM1,760.

7. Finally, to find the overall amount borne by Ramesh and the insurance company, we sum up the individual expenses: Ramesh's expenses + insurance company's expenses = RM1,140 + RM1,760 = RM2,900.

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There are two x intercepts for y = (x + 2)(x - 1)
The first is
and the 2nd is

Answers

Answer:

(-2,0) and (1,0)

Hope this helps!

What’s the length of kL?

Whats the length of kL?

Answers

Applying the intersecting secants theorem, the length of segment KL is approximately, 45.8.

What is the Intersecting Secants Theorem?

According to the intersecting secants theorem, if two lines from a point outside a circle intersect the circle, then the product of the length of one line segment and its portion outside the circle is equal to the product of the length of the other line segment and its portion outside the circle.

Using the theorem, we have:

MN * MO = ML * MK

Substitute:

21 * 48 = 22 * KL

1,008 = 22KL

1,008/22 = KL

KL = 45.8 (nearest tenth)

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Find the difference: -10 - 5 = *

Answers

Answer:

-15 is your answer

Step-by-step explanation:

-10-5=-1

Answer:

the answer is -15

Step-by-step explanation:

because you just add them put keep your negative

calculate the distance that P is :
a. north of Q b.east of Q​

calculate the distance that P is :a. north of Q b.east of Q

Answers

The distance of P at north of Q is 34.98 km.

The distance of P at east of Q is 19.39 km.

What is the distance of P?

The distance of P at the given directions is calculated by resolving the vector into vertical and horizontal components.

The distance of P at north of Q is calculated as follows;

Py = d sinθ

Py = 40 km x sin (61)

Py = 34.98 km

The distance of P at east of Q is calculated as follows;

Px = d cosθ

Px = 40 km x cos (61)

Px = 19.39 km

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What is the quotient of the following division problem?
58/8=

Answers

Answer:

7.25 or 7 ¼ or 56 R2

Step-by-step explanation:

Answer:

In Calculator, Quotient is 7.25

                   0      7  

   8 ⟌ 5 8  

     - 0    

       5 8  

     - 5 6  

         2  

But when we do long division the quotient is 7 and remainder is 2.

Hope it helps!

Don't forget to mark me brainiest if you got it correct.

What should you substitute for x in the second equation (bottom equation) in order to solve the system by the substitution method?

What should you substitute for x in the second equation (bottom equation) in order to solve the system

Answers

We substitute -1+1/6y for x in the second equation (bottom equation) in order to solve the system by the substitution method.

The given system of equations are 2x-1/3y = -2...(1)

3x+y=1...(2)

We solve this system of equations by using substitution method.

Let us solve for x in equation to substitute it in equation (2).

2x=-2+1/3y

Divide both sides of equation by 2.

x=-1+1/6y

Now plug in the value of x in equation 2.

Hence, we substitute -1+1/6y for x in the second equation (bottom equation) in order to solve the system by the substitution method.

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11 + ( − 11 ) = 0 whats the answer?

Answers

Answer:

0

Step-by-step explanation:

uhhh it already solved and also, its the answer because if theres like a "+-" you can just convert it to "-" so then it will be

11 - 11

11 - 11 = 0

Answer:

0

Step-by-step explanation:

as + and then - is - so 11- 11 = 0

below are the functions of y = |x| and y = |x| - 3. how are the functions related?

below are the functions of y = |x| and y = |x| - 3. how are the functions related?

Answers

Answer:

The first option

Step-by-step explanation:

They have the same shape and the second y-intercept is -3

suppose 2n c 1 numbers are selected from f1; 2; 3; : : : ; 4ng. using the pigeonhole principle, show that there must be two selected numbers whose difference is 2. clearly indicate what are the pigeons, holes, and rules for assigning a pigeon to a hole.

Answers

Yes, there must be two selected numbers whose difference is 2. Any assignment of n+1 pigeons to n holes. Then there exists at least one hole with at least 2 pigeons in it.

The Pigeon-Hole Principle :

A general rule, called the pigeon -hole principle, is that if there are more pigeons than holes, there should be at least one hole with at least two pigeons. If we put n + 1 objects into n boxes, we can say that at least one box contains 2 or more objects. Example: If there are Kn+ 1 (where k is a positive integer) pigeons distributed in n holes, then the holes contain at least k + 1 pigeons. Consider 2n pair of pigeon holes (1,3), (2,4), (5,7),(6,8), .. ..,(4n-3,4n-1),(4n-2,4n). The 2 numbers in each pair have the difference 2.

If we choose 2n+1 numbers(pigeons), then they cannot all belong to different pairs.

Thus by pigeon hole principle, there must be two selected numbers whose difference is 2.

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