Find the slope of the line through the points (-5, 2) and (5,0).

The method that can be used to write the equation of a line in slope-intercept form given two points is A. Find the slope using the formula m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction, and then substitute one point and the slope into the equation y = m x + b to find the y-intercept.

It should be noted that the equation of line passing through two point =  y = mx + b.

Also, b can find out via putting values of x, y, and m in the equation of the line to get y-intercept.

In this case, the slope of the line will be y2 - y1/x2 - x1.

In conclusion, the correct option is A.

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Check the picture below.

The factorization of of −12x+6 is 6(-2x + 1).

Factorization simply means writing if a number as a product of several factors. It is also the breaking or the decomposition of an entity.

In this case, -12x + 6 will be illustrated thus. It should be noted that the common factor between the numbers is 6. This will be:

= -12x + 6

= 6(-2x + 1)

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a. Null hypothesis (H0) is that the mean blood pressure in rats exposed to a 5°C environment is equal to the mean blood pressure in rats exposed to a 26°C environment.

b. Three conditions required for the test:

Randomization

Independence

Approximately normal distributions

c. The 95% confidence interval on the difference in the two population means is approximately (-7.671, -5.329).

a. Null hypothesis (H0): The mean blood pressure in rats exposed to a 5°C environment is equal to the mean blood pressure in rats exposed to a 26°C environment.

Alternative hypothesis (Ha): The mean blood pressure in rats exposed to a 5°C environment is higher than the mean blood pressure in rats exposed to a 26°C environment.

b. Three conditions required for the test:

Randomization: The rats were assigned randomly to the two environments, ensuring that the samples are representative.

Independence: The blood pressures measured in each group are independent of each other.

Approximately normal distributions: Since the sample sizes are small (n < 30), we need to check if the blood pressure data within each group is approximately normally distributed. If not, we may need to rely on the Central Limit Theorem to justify the use of the t-test.

c Confidence interval = (x₁ - x₂) ± t * √[(s₁² / n₁) + (s₂² / n₂)]

(x₁ - x₂) = 128.7 - 135.2 = -6.5

t is the critical value from the t-distribution with α = 0.05 and df = 10. Using a t-table or statistical software, t ≈ 1.812.

s₁ ≈ 2.4

s₂ ≈ 2.2

n₁ = n2 = 6

Substituting the values:

Confidence interval = -6.5 ± 1.812 * √[(2.4² / 6) + (2.2² / 6)]

Confidence interval ≈ -6.5 ± 1.812 * √(1.44/6 + 1.21/6) ≈ -6.5 ± 1.812 * √0.417 ≈ -6.5 ± 1.812 * 0.646 ≈ -6.5 ± 1.171

Therefore, the 95% confidence interval on the difference in the two population means is approximately (-7.671, -5.329).

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Answer:

C) Trapezoid

Step-by-step explanation:

Given

\(A = (0,0)\)

\(B = (4,8)\)

\(C = (12,8)\)

\(D=(16,0)\)

Required

The possible shape

The above are 4 vertices.

Hence, the shape cannot be

(a) Triangle ---- it has 3 vertices

(b) Pentagon ---- it has 5 vertices

Calculate distance AB using distance formula

\(AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2\)

Where:

\(A = (0,0)\)

\(B = (4,8)\)

\(AB = \sqrt{(0 - 4)^2 + (0 - 8)^2\)

\(AB = \sqrt{( - 4)^2 + ( - 8)^2\)

\(AB = \sqrt{16+64\)

\(AB = \sqrt{80\)

\(AB = 8.94\)

Calculate distance BC using distance formula

\(BC = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2\)

Where:

\(B = (4,8)\)

\(C = (12,8)\)

\(BC = \sqrt{(4 - 12)^2 + (8 - 8)^2\)

\(BC = \sqrt{(-8)^2 + (0)^2\)

\(BC = \sqrt{64 +0\)

\(BC = \sqrt{64\)

\(BC = 8\)

Since

\(AB \ne BC\)

Then, the polygon is not a square

The last available option is (c) trapezoid

Answer: C. Trapezoid

Step-by-step explanation:

Graph the points and you get a trapezoid!!!

Hope this helps!!!

The time-series model that assumes that demand in the next period will be equal to the most recent period's demand is A) Naive approach.

This model is based on the simplest assumption of all, that the next period's demand will be equal to the current period's demand. It is called the naive approach because it assumes no underlying pattern in the data and provides a baseline prediction. The formula for the naive approach is as follows:

y(t) = y(t-1) where y(t) represents the demand in period t and y(t-1) represents the demand in the previous period.

Although this model is simple, it is often used as a benchmark for comparison with more complex models and can provide reasonable results for stable demand patterns.

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Answer:

Here you go!!!!! Its correct let me know if you need any more problems for me to try and solve!!!

Step-by-step explanation:

Answer:

7 toys

Step-by-step explanation:

3+4=7

Answer:

x=12degrees

Step-by-step explanation:

1st Angle=23degrees

2nd Angle=(4x+19)

3rd Angle=(In order to find this angle we need to take this angle as angle3)

angle3+90=180

angle3=180-90

angle3=90degrees

Now lets start with the sum

Sum of angles of a triangle=180degrees

23+(4x+19)+90=180

113+(4x+19)=180

(4x+19)=180-113

(4x+19)=67

4x=67-19

4x=48

x=48/4

x=12degrees

Hope this helps you

If a divides b and a divides c, then a divides (bm + cn).

To prove that if a divides b and a divides c, then a divides (bm + cn), we can use the properties of divisibility.

Given:

a|b, which means b is divisible by a.

a|c, which means c is divisible by a.

We want to show that a|(bm + cn), which means (bm + cn) is divisible by a.

By definition, if a divides b, then there exists an integer k₁ such that b = ka. Similarly, if a divides c, there exists an integer k₂ such that c = ka.

Now, let's substitute these expressions into (bm + cn):

(bm + cn) = (ka)m + (ka)n

= kam + kan

= a(km + kn)

We can see that (bm + cn) can be written as a times the integer (km + kn). Since (km + kn) is an integer, this implies that (bm + cn) is divisible by a.

Therefore, if a divides b and a divides c, then a divides (bm + cn).

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Equivalent expressions are expressions that have the same value.

The equivalent expression of \(g^{-3}h\) is: \(\frac{h}{g^3}\)

The expression is given as;

\(g^{-3}h\)

Apply law of indices to change the exponents

\(g^{-3}h = \frac{1}{g^3}h\)

Express as products

\(g^{-3}h = \frac{1}{g^3} \times h\)

Rewrite as

\(g^{-3}h = \frac{h}{g^3}\)

Hence, the equivalent expression is: \(\frac{h}{g^3}\)

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The piecewise function graphed below is given as follows:

A piecewise function is a function that has different definitions, depending on the input.

For x between -4 and -2, inclusive, the function is constant at 3, hence the definition is:

\(f(x) = 3, -4 \leq x \leq -2\)

For x greater than -2 until 3, the function is a line with slope 1 and y-intercept 2, hence the definiton is:

\(f(x) = x + 2, -2 < x \leq 3\)

For x greater than 3 until 5, the function is constant at -1, hence the definition is:

\(f(x) = -1, 3 < x \leq 5\)

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Without knowing the total cost of the wallpaper or the dimensions of the rectangular prism, it is not possible to determine the cost of the wallpaper per square foot.

To calculate the cost per square foot, we would need to know the total cost of the wallpaper and the total area covered by the wallpaper. Since we do not have this information, we cannot determine the cost per square foot.

In summary, the cost of the wallpaper per square foot cannot be determined without knowing the total cost of the wallpaper and the dimensions of the rectangular prism that Lamar built.

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Answer:

o really sis/bro hsgsmhsndjd

The slope of the line is -3/4.

What is a line?

A line is an object in geometry that is indefinitely long and has neither breadth nor depth nor curvature. Since lines can exist in two, three, or higher dimensional environments, they are one-dimensional things. The term "line" can also be used to describe a line segment in daily life that contains two locations that serve as its ends.

The points on the line are (-4, 5), (0,2), (4, -1).

The slope of a line that passes through the points (x₁, y₁) and (x₂, y₂) is (y₂ -  y₁)/(x₂ -  x₁).

The slope of the line is

(2 - 5)/(0 - (-4)) = -3/4

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Shape R and Shape S were put in the same group because they are the shapes with perpendicular line segments. Therefore the correct option is option D.

Shape S, a trapezium with one vertical side, and Shape R, a square, both have perpendicular line segments. All of the sides of a square are perpendicular, while one of the non-parallel sides of a trapezium with a vertical side is perpendicular to the base.

Reasons for ruling out other options

Option A, "Shapes without any right angles," is incorrect because Shape R (a square) has four right angles.

Option B, "Shapes with exactly one pair of parallel sides," is incorrect because Shape S (a trapezoid with one vertical side) has only one pair of parallel sides, while Shape R(a square) has two pairs of parallel sides.

Option C, "Shapes without parallel line segments," is also incorrect because all the other shapes P, Q, and T have parallel line segments.

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To indicate that a function is non-decreasing in a specific domain, we need to show that the function's values increase or remain the same as the input values increase within that domain. In other words, if we have two input values, say x₁ and x₂, where x₁ < x₂, then the corresponding function values, f(x₁) and f(x₂), should satisfy the condition f(x₁) ≤ f(x₂).

One common way to demonstrate that a function is non-decreasing is by using the derivative. If the derivative of a function is positive or non-negative within a given domain, it indicates that the function is non-decreasing in that domain. Mathematically, we can write this as f'(x) ≥ 0 for all x in the domain.

The derivative of a function represents its rate of change. When the derivative is positive, it means that the function is increasing. When the derivative is zero, it means the function has a constant value. Therefore, if the derivative is non-negative, it means the function is either increasing or remaining constant, indicating a non-decreasing behavior.

Another approach to proving that a function is non-decreasing is by comparing function values directly. We can select any two points within the domain, and by evaluating the function at those points, we can check if the inequality f(x₁) ≤ f(x₂) holds true. If it does, then we can conclude that the function is non-decreasing in that domain.

In summary, to indicate that a function is non-decreasing in a specific domain, we can use the derivative to show that it is positive or non-negative throughout the domain. Alternatively, we can directly compare function values at different points within the domain to demonstrate that the function's values increase or remain the same as the input values increase.

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Answer:

4,260

Step-by-step explanation:

4,000+200+60

Answer:

3 1/5 i think srry if im wrong

Step-by-step explanation:

Answer:

2·v - (u + w) = (5, 0, -10)

Step-by-step explanation:

The given values of the vectors are;

u = (2, -1, 3), v = (4, 0, -2), and w = (1, 1, 3)

The required vector is 2·v - (u + w)

2 × v = 2 × (4, 0, -2) = (8, 0, -4)

(u + w) = (2, -1, 3) + (1, 1, 3) = (3, 0, 6)

Therefore;

2·v - (u + w) = (8, 0, -4) - (3, 0, 6) = (5, 0, -10)

2·v - (u + w) = (5, 0, -10)

Answer: 29

It is very simple, just substitute.

x = 9, y = 10

Replace the x and y in the expression to that.

You get: 9 + 10 + 10. Just add and you will get 29.

Answer:

9+10+10=29

Step-by-step explanation:

We know that x=9, so where ever we see x we know it is 9. We also know that y=10, so where ever we see y we know it is 10. So then we just replace the variables with our numbers then just add them.  That is I got 9+10+10=29

Hope this helps!

The correct answer is:

b. Test statistic: t = -1.841

Critical value = ±2.045

Do not reject H0

To conduct the hypothesis test using the pooled t-test, we compare the calculated test statistic to the critical value at a significance level of α = 0.05.

Given the following statistics for two independent samples:

Sample 1: x1 = 11.1, s1 = 4.5, n1 = 14

Sample 2: x2 = 17.2, s2 = 4.9, n2 = 17

The pooled t-test assumes that the population variances are equal. We calculate the pooled standard deviation (sp) using the formula:

sp = sqrt(((n1-1)*s1^2 + (n2-1)*s2^2) / (n1 + n2 - 2))

Next, we calculate the test statistic (t) using the formula:

t = (x1 - x2) / (sp * sqrt(1/n1 + 1/n2))

For the given data, the calculated test statistic is t = -3.577.

To determine whether to reject or fail to reject the null hypothesis (H0), we compare the absolute value of the test statistic to the critical value from the t-distribution at a significance level of α = 0.05. In this case, the critical value is ±1.699.

Since the absolute value of the test statistic (-3.577) is greater than the critical value (1.699), we do not reject the null hypothesis (H0). Therefore, the correct answer is c. Test statistic: t = -3.577, Critical value = ±1.699, Do not reject H0.

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Answer:

\(\frac{V}{wh}=l\)

Step-by-step explanation:

Equation: \(V=lwh\)

1). \(\frac{V}{wh}=\frac{lwh}{wh}\)

2). \(\frac{V}{wh}=l\)

The value of each expression using the following functions:  a. f(g(0)) = 4, b. g(3) = -2, c. g(g(-1)) = -2, d. f(f(2)) = 2, e. g(f(0)) = -2.

To evaluate the given expressions using the functions f(x) = 2 - x and g(x) = -2:

a. f(g(0)):

First, substitute 0 into the function g(x): g(0) = -2

Then, substitute the result into the function f(x): f(-2) = 2 - (-2) = 4

b. g(3):

Simply substitute 3 into the function g(x): g(3) = -2

c. g(g(-1)):

First, substitute -1 into the function g(x): g(-1) = -2

Then, substitute the result into the function g(x) again: g(-2) = -2

d. f(f(2)):

First, substitute 2 into the function f(x): f(2) = 2 - 2 = 0

Then, substitute the result into the function f(x) again: f(0) = 2 - 0 = 2

e. g(f(0)):

First, substitute 0 into the function f(x): f(0) = 2 - 0 = 2

Then, substitute the result into the function g(x): g(2) = -2

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Answer:

A) 82.99(p-1) +90.99=C

and

B) 80.99(p-1) + 98.99 = C

plug and chug for p

Step-by-step explanation:

There will be 48 blocks in 6 rows, with 8 blocks in each row.

Multiplication is one of the four basic mathematical operations of arithmetic, along with addition, subtraction, and division. A product is the outcome of a multiplication operation. In mathematics, multiplying implies adding equal groups. The number of items in the group grows as we multiply. A multiplication issue includes the two elements and the product. Multiplication is a way of calculating the product of two or more integers in mathematics. It is one of the most fundamental mathematical operations that we utilize every day.

Here,

number of rows=6

number of blocks in row=8

total number of blocks,

=6*8

=48

There will be 48 blocks in 6 rows with each row having 8 blocks.

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Answer:

C

Step-by-step explanation:

Given y = f(x) then y = f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift to the left of a units

• If a < 0 then a shift to the right of a units

Thus (x - 5)² is a shift to the right of 5 units

Given y = f(x) then y = f(x) + c is a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

Thus

y = (x - 5)² + 6

is the graph of y = x² translated 6 units up and 5 units to the right → C

The Binomial Distribution applet will calculate the probability of the basketball player making 2 or less shots, and it turns out to be equal to 0.8425.

Using the Binomial Distribution Applet, we can find the probability that the basketball player makes 2 shots or less by inputting the given information into the applet. The number of trials is 3, the probability of success is 0.54, and the number of successes we are looking for is 2 or less.

Here are the steps to finding the probability using the Binomial Distribution Applet: Input the number of trials as 3, Input the probability of success as 0.54, Input the number of successes as 2, Click the "Calculate" button

The applet will then calculate the probability of the basketball player making 2 or less shots, which is 0.8425. Therefore, the answer to the question is 0.8425.

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The absolute minimum occurs at x = 4, where f(x) has the lowest value of 14.

To find the absolute minimum of the function f(x) = x^2 - 2 on the interval [1,4], we need to evaluate the function at its critical points and endpoints and determine the lowest value.

1. Evaluate the function at the critical point(s):

To find the critical point(s), we take the derivative of f(x) with respect to x and set it equal to zero:

f'(x) = 2x

Setting f'(x) = 0, we find x = 0.

2. Evaluate the function at the endpoints:

Evaluate f(x) at x = 1 and x = 4.

f(1) = 1^2 - 2 = -1

f(4) = 4^2 - 2 = 14

3. Determine the absolute minimum:

Now, we compare the values of f(x) at the critical points and endpoints:

f(0) = 0^2 - 2 = -2

f(1) = -1

f(4) = 14

The absolute minimum occurs at x = 4, where f(x) has the lowest value of 14.

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Answer:

\(\color{indigo}\rule{1pt}{1000000pt}\)