Find the volume of a sample of wood that has a mass of 95. 1 g and a density of 0. 857 g/mL (How do you do this!)

The  image that have been shown can be said to depict a weak base. Option A

A weak base is a material that, when exposed to water, partially ionizes or dissociates, producing hydroxide ions (OH-) and their conjugate acid. Weak bases only produce a minor concentration of hydroxide ions in an aqueous solution, in contrast to strong bases, which totally dissociate and produce a significant concentration of hydroxide ions.

Weak bases have a comparatively low affinity for protons because of their restricted capacity to receive protons (H+) from water.

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The reason why CaCl2 is used and not NaCl in the preparation of macrocapsules is due to the difference in solubility. Calcium chloride is a salt that is soluble in water, whereas sodium chloride is also soluble in water, but less so than calcium chloride.

A macrocapsule is a type of capsule that is large enough to be seen with the unaided eye. It is also known as a "large capsule." Macrocapsules are usually used in the medical industry to deliver drugs or other substances to specific parts of the body. The substance to be delivered is typically contained within the capsule, which is then implanted into the body.

In order to prepare macro-capsules, a process known as microencapsulation is used. During this process, the substance to be encapsulated is suspended in a solution, and then this solution is mixed with a polymer. The polymer hardens around the substance, creating a capsule that can be implanted into the body.

In the preparation of macro-capsules, CaCl2 is used instead of NaCl because of its solubility. Calcium chloride is highly soluble in water, which makes it ideal for use in the microencapsulation process. The solubility of CaCl2 allows for the formation of a hard, impermeable capsule that is able to protect the substance inside from the surrounding environment. On the other hand, NaCl is less soluble in water than CaCl2, which makes it unsuitable for the microencapsulation process.

Other factors which make CaCl2  suitable for macrocapsule preparation include:

Gel formation: CaCl2 can participate in gel formation reactions with certain polymers or gelling agents. It can crosslink polymers, resulting in the formation of a stable gel structure, which can be useful for encapsulating materials and providing mechanical stability to the macro-capsules.

Compatibility: The specific material being encapsulated or the application of the macrocapsules may require compatibility with CaCl2 rather than NaCl. For example, certain biological or chemical processes may be more compatible with CaCl2 as a component of the encapsulation system.

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Answer:

All atoms of chlorine (Cl) have 17 protons, but there are chlorine isotopes with 15 to 23 neutrons

Explanation:

Although all atoms of an element have the same number of protons, individual atoms may have different numbers of neutrons. These differing atoms are called isotopes.

hope it is useful mark it as brainlist answer

When current is allowed to flow, the species that gets oxidized depends on the specific conditions of the system. However, based on the given options, the likely species to be oxidized would be A) Cr₂O₇²⁻.

When current flows in a system, oxidation and reduction reactions occur simultaneously at different electrode surfaces. The species that gets oxidized is the one that loses electrons. In the given options, Cr₂O₇²⁻ and MnO⁴ are both polyatomic ions with high positive oxidation states, while Cr³⁺ and Mn²⁺ have lower positive oxidation states. H³⁺ refers to a hydrogen ion, which is not a likely candidate for oxidation in this context.

In the case of Cr₂O₇²⁻, it has a higher positive oxidation state compared to Cr³⁺. Therefore, it is more likely to undergo oxidation and lose electrons when current is allowed to flow. The half-reaction for the oxidation of Cr₂O₇²⁻ to Cr³⁺ can be represented as follows:

Cr₂O₇²⁻ (aq) → 2Cr³⁺ (aq) + 3e⁻

This reaction involves the reduction of another species, which gains the electrons released during the oxidation of Cr₂O₇²⁻. It's important to note that the actual species being oxidized or reduced can vary depending on the specific conditions of the system, such as pH and the presence of other reactants.

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An ICE table, also known as an "Initial, Change, and Equilibrium" table, is a tool used in chemistry to analyze equilibrium reactions and calculate the equilibrium concentrations of reactants and products.

It is used to organize data and determine the effects of different variables on a chemical equilibrium.

An ICE table typically has the following columns:

To use an ICE table, you first write the balanced chemical equation for the reaction. Next, you fill in the initial concentrations of the reactants and products, and then use the reaction stoichiometry to determine the changes in concentration as the reaction proceeds. Finally, you add the initial concentrations and changes to find the equilibrium concentrations.

ICE tables are commonly used in acid-base reactions, precipitation reactions and gas reactions. It's a powerful tool to understand Le Chatelier's principle and the effect of changes in concentration, temperature and pressure on the equilibrium state.

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Answer:

5ppm

Explanation:

there are 1 million (1,000,000) µg (micrograms or mcg) per g (gram) ("micro" means millionth). So, 4. 1 part per million (ppm) for a 1g sample is 1 µg or .

I know you said no links, but this is a converter that explained it much better than I know how to

http://www.endmemo.com/sconvert/ppmug_g.php#:~:text=%C2%BB%20Microgram%2Fgram%20Conversions%3A&text=ug%2Fg%E2%86%94ppm%201%20ug%2Fg%20%3D%201%20ppm

heres a screenshot of the site (since i understand links are awful)

Answer: O2+6H12O6=CO2+ENERGY(ATP)

I DON'T THINK SHE IS CORRECT

Explanation:

The question requires us to calculate the molecular mass of a gas, given its density (1.2 g/L) and conditions of pressure (745 torr) and temperature (20°C).

Density is defined as the mass of a compound over its volume. From this definition, we can calculate the molecular mass of the gas knowing the density, as given by the question, and the volume of 1 mol of the gas.

We can calculate the volume of a gas considering the equation of Ideal Gases:

where P is the pressure of the gas, V is its volume, n is the number of moles, R is the constant of gases and T is the temperature.

Note that the constant of gases R was given in units of L.atm/K.mol, while the pressure and temperature were given in Torr and °C, respectively. Thus we need to convert these values to the appropriate units.

Knowing that 1 Torr corresponds to 0.00131579 atm:

1 Torr --------------------- 0.00131579 atm

745 Torr ---------------- x

Solving for x, we have that 745 Torr corresponds to 0.980 atm.

To convert the temperature from Celsius degrees to Kelvin, we must add 273.15:

T = 20 + 273.15 K = 293.15 K

Therefore, the pressure and temperature we'll use in our calculation are 0.980 atm and 293.15 K. Also, since we are calculating the molecular mass, we'll consider 1 mol of gas.

Rearranging the equation of ideal gases to calculate the volume and applying the values to the equation, we'll have:

Therefore, the volume of 1 mol of the gas under the conditions given is 24.6L.

Next, we'll use this value to calculate the molecular mass using the density given by the question:

Therefore, the gas given by the question presents 29.5g per mol.

To prevent more than one sperm from entering the egg.

What is oocyte?

An oocyte , or ovocyte is a female gametocyte or germ cell involved in reproduction. In other words, it is an immature ovum, or egg cell. An oocyte is produced in a female fetus in the ovary during female gametogenesis. The female germ cells produce a primordial germ cell (PGC), which then undergoes mitosis, forming oogonia. During oogenesis, the oogonia become primary oocytes. An oocyte is a form of genetic material that can be collected for cryoconservation.

When the sperm and egg fuse it triggers a release of calcium ions, which cause the cortical granules inside the egg to fuse with the plasma membrane. As they fuse, these granules release their contents outside of the cell, toward the remains of the zona pellucida.

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Answer:

The amount of heat is 431.12 kJ/mol.

Explanation:

Given that,

Mass of Ba = 1.50 g

Mass of water = 100.0 g

Initial temperature = 22.00°C

Final temperature = 33.10°C

The reaction is,

\(Ba+2H_{2}O\Rightarrow Ba(OH)_{2}+H_{2}\)

We need  to calculate the heat

Using formula of heat

\(Q=ms\Delta T\)

Where, m = mass

s = specific heat

\(\Delta T\) temperature

Put the value into the formula

\(Q=(1.50+100)\times4.18\times(33.10-22.00)\)

\(Q=4709.397\ J\)

We need to calculate the amount of heat per mole

Using formula of energy per mole

\(per\ mole\ Q=\dfrac{4709.397}{moles\ of\ Ba}\)

Put the value into the formula

\(per\ mole\ Q=\dfrac{4709.397}{\dfrac{1.5}{137.32}}\)

\(per\ mole\ Q=431129.59\ J/mol\)

\(per\ mole\ Q=431.12\ kJ/mol\)

Hence, The amount of heat is 431.12 kJ/mol.

The correct order of increasing the average molecular speed at 25°C for the given gases is E) CO₂ < He < N₂ < O₂.

The average molecular speed of a gas depends on its molar mass and temperature. Lighter gases and higher temperatures generally result in higher average molecular speeds. Let's analyze the given gases:

Now, let's consider the order of increasing average molecular speed at 25°C:

He > O₂ > CO₂ > N₂

Comparing the options provided:

A) He < N₂ < O₂ < CO₂ (incorrect, N₂ should be after CO₂)

B) He < O₂ < N₂ < CO₂ (incorrect, N₂ should be after CO₂)

C) CO₂ < O₂ < N₂ < He (incorrect, He should be at the beginning)

D) CO₂ < N₂ < O₂ < He (incorrect, He should be at the beginning)

E) CO₂ < He < N₂ < O₂ (correct)

Therefore, the correct answer is E) CO₂ < He < N₂ < O₂.

The complete question should be:

Arrange the following gases in order of increasing the average molecular speed at 25°C. He, O, CO₂, N₂

A) He < N₂ <O₂ < CO₂

B) He < O₂ <N₃ < CO₂

C) CO₂ < O₂ < N₂ < He

D) CO₂ < N₂ <O₂ < He

E) CO₂ < He <N₂ < O₂

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Answer:

Nucleus

Explanation: it is the center of the atom, and contains protons and nuetrons

Answer:

For every force one object applies on another, there

is an equal force applied in the opposite direction.

Explanation:

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Answer:

3.75 moles

Explanation:

The chemical equation is 2CH₃OH + 3O₂ -> 2CO₂ + 4H₂O

2 moles of CH₃OH are burned by 3 moles of O₂

For 2.5 moles of CH₃OH are burned by x moles of O₂

Let's solve for x :

2*x=2.5*3 => 2*x=7.5 => x=3.75 moles of O₂ are needed to burn 2.5 moles of CH₃OH

Answer:

solute, im pretty sure

Explanation:

Nitrous oxide, also known as laughing gas, has an atmospheric lifetime of approximately 114 years.

This means that once it is released into the atmosphere, it can remain there for over a century before it is removed. Nitrous oxide is a potent greenhouse gas and contributes to global warming and climate change.

It is estimated that nitrous oxide is responsible for about 6% of the warming effect of long-lived greenhouse gases. In addition to its impact on climate, nitrous oxide also plays a role in the destruction of the ozone layer, which protects the Earth from harmful UV radiation.

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Answer:

pretty sure there is a calculator

Explanation:

there is a calculator for it ( that's what I do ) btw there is a calculator for every even science or chemistry

Answer:

An alkane is a hydrocarbon in which there are only single covalent bonds. The simplest alkane is methane, with the molecular formula CH4.

Explanation:

Alkanes.

Name Heptane

Molecular Formula C7H16

Condensed Structural Formula CH3CH2CH2CH2CH2CH2CH3

Boiling Point (°C) 98.5

Hydrocarbons which are alkanes with 4 or more than 4 carbon atoms have more than one possible structural formula which is a type of chemical formula.

Structural formula helps in identifying location of chemical bonds which are present between atoms in a molecule.It consists of symbols of elements for the atoms which are connected by short lines which actually represent the chemical bonds.

Structural formulae can be deduced from molecular formulae the fragment ions are studied in the mass spectrum.It is concerned with the valency which helps in determination of of how atoms a combine in a definite ratio.

Properties of molecules are much related with their structures. It helps in showing the arrangement of atoms in a three-dimensional space.

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Answer:

One Hectometer is 10,000 centimeters. So multiply your hectometer by 10,000, and that's your conversion. Your answer is 590.

The given representation of one unit of C₆H₁₂O₆ in water is incomplete as it does not include the water molecules that are essential for the dissolution process.

In the given representation, only the C₆H₁₂O₆ molecules are shown, while the water molecules are intentionally not depicted. However, when C₆H₁₂O₆  dissolves in water, it forms a solution where C₆H₁₂O₆ molecules are surrounded by water molecules, resulting in a hydrated state.

Therefore, the representation is incomplete and inaccurate since it neglects the presence of water molecules, which play a crucial role in the dissolution and formation of a hydrated C₆H₁₂O₆ complex in water.

The question should be:

A representation of one unit of C₆H₁₂O₆ in water is shown below. (The water 12 molecules are intentionally not shown.)

(a) What is wrong with this representation?

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Homogeneous and heterogeneous mixture in colloid, suspension and solution

A colloid is a heterogeneous mixture in which the dispersed particles are intermediate in size between those of a solution and a suspension and within the categories of homogeneous and heterogeneous mixtures there are more specific types of mixtures including solutions is alloys, suspensions, and colloids and a solution is a mixture where one of the substances dissolves in the other and the substance that dissolves is called the solute

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The mass of copper metal obtained from this process is 483 tons.

To calculate the mass of copper metal obtained from the given copper ore, we need to use the percentage composition and the mass of the ore processed.

1. Calculate the mass of Cu2S in the ore:

Since the ore contains 2.30% Cu2S by mass, we can calculate the mass of Cu2S in 21000 tons of ore:

mass of Cu2S = (2.30/100) × 21000 tons

2. Calculate the molar mass of Cu2S:

Copper (Cu) has a molar mass of approximately 63.55 g/mol, and sulfur (S) has a molar mass of approximately 32.07 g/mol. The molar mass of Cu2S can be calculated as:

molar mass of Cu2S = (2 × molar mass of Cu) + molar mass of S

3. Calculate the moles of Cu2S:

Using the mass of Cu2S and its molar mass, we can calculate the number of moles of Cu2S:

moles of Cu2S = mass of Cu2S / molar mass of Cu2S

4. Calculate the moles of copper (Cu):

Since each formula unit of Cu2S contains 2 moles of copper (Cu), the moles of copper can be calculated as:

moles of Cu = 2 × moles of Cu2S

5. Calculate the mass of copper (Cu):

The mass of copper can be calculated by multiplying the moles of copper by its molar mass:

mass of Cu = moles of Cu × molar mass of Cu

Finally, convert the mass of copper from grams to tons by dividing by 1000:

mass of Cu (in tons) = mass of Cu / 1000

Performing these calculations will provide the mass of copper metal obtained from the given ore in tons.

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Answer:

1.

meteorology A line drawn on a map or chart connecting places of equal or constant pressure.

2.

nuclear physics Either of two nuclides of different elements having the same mass number.

3.

thermodynamics A set of points or conditions at constant pressure.

Answer:

a line on a map connecting points having the same atmospheric pressure at a given time or on average over a given period.

Explanation:

The freezing point of a solution of 60.0 g of glucose, dissolved in 80.0 g of water is  -7.67 ⁰C

Freezing point is the temperature at which a liquid turns into a solid. In theory, the melting point of a solid should be the same as the freezing point of the liquid.

At freezing point, these two phases viz. liquid and solid exist in equilibrium i.e. at this point both solid state and liquid state exist simultaneously. The freezing point of a substance depends upon atmospheric pressure.

Given,

Mass of Glucose = 60g

Mass of water = 80g

Moles of glucose = 60/ 180 = 0.33 moles

Molality = number of moles of glucose / mass of water in kg

= 0.33 / 0.08

= 4.12 molal

Depression in freezing point = Kf × molality

= 1.86 × 4.12

= 7.67 K

Freezing point of pure water = O⁰C

Freezing point of glucose = 0 - 7.67

= -7.67 ⁰C

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Combine the stoichiometry by a element's subscript to find number of atom.  In 2AI\(_2\)(CO\(_3\))\(_3\), 4 aluminium atom, 3 carbon atom and 9 oxygen atom are there.

Aluminium carbonate is an aluminum carbonate. It is not well defined; according to one reference, simple carbonates of aluminum are unknown.

Yet, similar compounds such as the basic sodium aluminum carbonate solid dawsonite and the hydrated basic aluminum carbonate minerals scarbroite as well as hydroscarbroite are known. To find the number of atoms in an element, combine the stoichiometry by a element's subscript. In  2AI\(_2\)(CO\(_3\))\(_3\), 4 aluminium atom, 3 carbon atom and 9 oxygen atom are there.

Therefore, in  2AI\(_2\)(CO\(_3\))\(_3\), 4 aluminium atom, 3 carbon atom and 9 oxygen atom are there.

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The major product formed when the given compound reacts with RCO3H is an ester. This reaction, known as an esterification reaction, involves the conversion of a carboxylic acid to an ester. The specific ester formed will depend on the structure of the given compound and the nature of the R group in RCO3H.

The given compound, when reacted with RCO3H, undergoes an esterification reaction. In this reaction, the carboxylic acid group (-COOH) of the compound reacts with the RCO3H, which is a reagent known as an acid anhydride. The reaction proceeds through an intermediate where the oxygen of the carboxylic acid attacks the carbon of the acid anhydride, leading to the formation of an acyl-oxygen bond. Simultaneously, one of the oxygens in the anhydride group is cleaved off, forming a leaving group. The acyl-oxygen bond is then broken, and the resulting oxygen forms a bond with the carbon, leading to the formation of the ester. The specific ester formed will depend on the structure of the given compound and the nature of the R group in RCO3H. The R group can vary and may contain different substituents, such as alkyl or aryl groups. The structure of the given compound will determine which functional groups participate in the reaction and influence the regioselectivity and stereochemistry of the product. Thus, without knowing the exact structure of the compound and the R group in RCO3H, it is not possible to determine the specific major product formed in this reaction.

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