Radiation with a wavelength of 263.9 nm can eject a 2.00 -eV electron from a calcium electrode. Calcium has a piece function of 2.seventy one eV.
The expelled photoelectrons are E = 2.0 eV, so
⇒ \(2.0 eV = E_{in} -2.71 eV\)
⇒ \(E_{in}=2.0 eV +2.71eV\)
⇒ \(E_{in} = 4.71 eV\)
in Joules, it is
⇒ \(E_{in} =4.71*1.6*10^{-19} J\)
⇒ \(E_{in} =7.536*10^{-19} J\)
Since \(E_{in}=h\nu=\frac{hc}{\lambda}\), the wavelength must be
\(\Rightarrow \lambda = \frac{hc}{E_{in} }\)
\(\Rightarrow \lambda=\frac{(6.64*10^{-34}Js)(3*10^{8}m/s) }{7.536*10^{-19} J}\)
\(\Rightarrow \lambda=263.9\times10^{-9} \; m\)
\(\Rightarrow \lambda=263.9 \;n m\)
inside the photoelectric impact, the electricity of the photoelectrons chosen from metallic with work function ∅ thanks to misguided radiation of the entirety
If radiation moves a calcium electrode with the work feature ∅ = 2.seventy one eV and the power of radiation equals
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300 high school students were asked how many hours of tv they watch per day. the mean was 2 hours, with a standard
deviation of 0. 5. using a 90% confidence level, calculate the maximum error of estimate.
o 7. 43%
0 4. 75%
o 0. 27%
0 5. 66%
Using the z-distribution, it is found that maximum the error of the estimate is of 0.0475 hours.
What is a z-distribution confidence interval?X ± Z(S ÷ √n)
briefly given that-x= is the sample mean.
z =is the critical value.
n= is the sample size.
ơ =is the standard deviation for the population.
margin of error is the given by:-
Margin of Error given as = Z * ơ / √n
We have 90% the confidence level, hence, z is the value of Z that has a p-value of , so the critical value of z = 1.645.
putting value in equation we get
Margin of Error= 1.645*.5/√300
so, Margin of Error is 0.0475 hours
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The magnetic field at the center of a 0.900-cm-diameter loop is 2.70mT . A. What is the current in the loop? B. A long straight wire carries the same current you found in part a. At what distance from the wire is the magnetic field 2.70mT ?
a. The current in the loop is 11.38 A.
b. The distance from the wire at which the magnetic field is 2.70 mT is 2.70 m.
The current in the loop, we can use the formula:
I = μ * N / A
First, we need to find the number of turns in the loop. The diameter of the loop is given, so we can find its circumference:
C = π * D
here C is the circumference and D is the diameter.
The circumference of the loop is:
C = π * 0.900 cm = 7.85 cm
The number of turns in the loop is then:
N = C / A
here A is the area of the loop.
The area of the loop is:
A = π * (0.900 cm) = 0.729 cm
Substituting these values into the formula for the current, we get:
I = μ * N / A
= μ * (7.85 cm / 0.729 cm)
= 11.38 A
Therefore, the current in the loop is 11.38 A.
To find the distance from the wire at which the magnetic field is 2.70 mT, we can use the formula:
B = μ * I * L
First, we need to find the length of the wire. The current in the wire is given, so we can find its cross-sectional area:
A = I / π
here A is the cross-sectional area and I is the current in the wire.
The cross-sectional area of a straight wire is proportional to its diameter, so we can use the diameter of the loop to find the cross-sectional area of the wire:
A = π * D / 2
here D is the diameter of the loop.
A = π * 0.900 cm / 2
= 0.682 cm
The cross-sectional area of the wire is therefore 0.682 cm.
The magnetic field is given, so we can find the distance from the wire at which it is 2.70 mT using the formula:
B = μ * I * L
= μ0 * 11.38 A * 2.70 m
= 31.37 mT
Therefore, the distance from the wire at which the magnetic field is 2.70 mT is 2.70 m.
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if you could dig a hole several kilometers deep the temperature would get colder or warmer?
Answer:
The temperature would get warmer.
Explanation:
It indicates heat from earth’s warm interior surface. The temperature increases for about 25℃ for every single kilometer of depth.
Answer:
Warmer is the answer think
why is the weight of a body more at the pole than at the equator of the earth ??
And according to newtons second law
Force=Mass×Acceleration
And
\(\\ \sf\longmapsto F\propto a\)
Hence force varies directly with acceleration hence weight will be more .\(\boxed{ \rm \green{ Answer:-}}\)
At equators,the radius of the earth is the greatest at the poles whereas at the equator,it is the least.
Due to this the value of g is greatest at poles and least at the equator of the earth.
Therefore,a body weight more at the poles and less at the equator of the earth.
How did private industries benefit from military expenditures?
The government paid private industries for goods and services.
The government sought goods and services from overseas, causing private industries to lose business.
The government purchased private industries to lower the costs of goods and services.
The government forced private industries to pay for research and development.
Option A is the correct answer
Answer:
option A: the government paid private industries for goods and services.
Explanation:
read this
work has only magnitude and no direction .f is taken as negative and denoted by a minus sign the work done by the force ×(-s) .now it is clear from the above discussion that the work done by a force can be either positive or negative .
now please explain me
at one place it was written that force has only direction and no magnitude so how can it be in the positive or negative form .? because a scalar quantity has only positive and zero value . also tell me what is the difference between work and work done?
please answer fast
When we talk about the work done by a force, we are considering only the magnitude of the force in the direction of the displacement.
Scalar and vector quantities.It is true that force is a vector quantity and has both magnitude and direction. However, when we talk about the work done by a force, we are considering only the magnitude of the force in the direction of the displacement. So, the sign of the work done by the force depends on the angle between the force vector and the displacement vector.
When the force and displacement vectors are in the same direction, the work done is positive. When they are in opposite directions, the work done is negative. And when they are perpendicular to each other, the work done is zero.
So, in the given context, when we say that the work done by the force can be positive or negative, we are referring to the sign of the work done, not the sign of the force. The negative sign is used to indicate that the force is acting in the opposite direction of the displacement, and hence the work done is negative.
As for the difference between work and force, force is a vector quantity that describes the push or pull on an object. It has both magnitude and direction. On the other hand, work is a scalar quantity that describes the energy transferred to or from an object by a force when it is displaced. It has only magnitude and no direction. The unit of work is joule (J) and it is given by the product of the force and the displacement, both of which are vector quantities.
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How is correlation related to cause and effect? Correlation shows how much cause and effect exists based on the magnitude. Correlation is not related to cause and effect Correlation shows cause and effect when it is really close to 1
Correlation is a measure of the linear relationship between two variables. It indicates the degree to which a change in one variable is associated with a change in the other variable.
Correlation does not necessarily imply causation, meaning that just because two variables are correlated does not mean that one variable caused the other to change.
There are a few reasons for this. First, correlation does not indicate the direction of the relationship. For example, two variables could be positively correlated (increase together) or negatively correlated (one increases while the other decreases), but correlation alone does not indicate which is the case.
Second, there may be third variables that are affecting both of the variables being correlated. For example, a study might find that ice cream sales are positively correlated with shark attacks.
However, this does not mean that eating ice cream causes people to be attacked by sharks, or that sharks attack more when people are eating ice cream. Instead, the third variable is likely temperature.
On hot days, people are more likely to buy ice cream and more likely to go swimming, which leads to more shark attacks.
In summary, correlation does not necessarily imply causation and other methods, such as experiments, are needed to establish causal relationships.
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1. A toroid filled with a magnetic substance carries a steady current of 1.76 A. The coil contains 1450 turns, has an average radius of 2.19 cm. The magnetic field through the toroid is 0.199333 T. Assume the flux density is constant. What is the magnetic field strength H within the core in the absence of the magnetic substance? Answer in units of A/m.
2. Determine the permeability of the core material. Answer in units of Wb/A m.
The magnetic field strength H within the core in the absence of the magnetic substance is 0.000001671 A/m.
The permeability of the core material is 227684.8 Wb/A m.
A toroid filled with a magnetic substance carries a steady current of 1.76 A.
The coil contains 1450 turns
average radius of coil is 2.19 cm.
The magnetic field through the toroid is 0.199333 T.
Assume the flux density is constant.
The magnetic field B through the toroid is
B = μHnI
Circumference of toroid
= 2πr
= 2 x π x 0.0219 m
= 0.1377 m
Mean length of toroid,
l = Circumference = 0.1377 m
Total number of turns,
N = 1450
n = 1450 / 0.1377
n = 10526.7 turns/m
1.
Using above values,
B = μHnI
H = B / (μnI)
H = 0.199333 / (μ x 10526.7 x 1.76)
H = 0.000001671 A/m
Hence, the magnetic field strength H within the core in the absence of the magnetic substance is 0.000001671 A/m.
2.
The permeability of the core material is,
μ = B / (HnI)
μ = 0.199333 / (0.000001671 x 10526.7 x 1.76)
μ = 227684.8 Wb/A m
Therefore, the permeability of the core material is 227684.8 Wb/A m.
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If the resistance in a constant voltage circuit is doubled what will the power dissipated by the circuit be
Answer:
Explanation:
Decrease to one half of its original value
A diverging lens of focal length 18.0m is used to view a shark that is 90.0m away from the lens. If the image formed is 1.0m long, calculate the: (i) image distance; (ii) length of the shark.
Answer:
i. + 22.5 m ii. 4.0 m
Explanation:
i. Image distance
Using the lens formula
1/u + 1/v = 1/f where f = focal length = + 18.0 m, u = object distance = distance of shark away from lens = + 90.0 m and v = image distance from lens = unknown
So, we find v
1/v = 1/f - 1/u
= 1/+18 - 1/+90
= (5 - 1)/90
= 4/90
v = 90/4
= + 22.5 m
So the image is real and formed 22.5 m away on the other side of the lens.
ii Length of Shark
Using the magnification formula, m = image height/object height = image distance/object distance. image height = 1.0 m where object height = length of shark.
m = image distance/object distance
= v/u
= +22.5/+90
= 0.25
0.25 = image height/object height
So,
object height = image height/0.25
= 1.0 m/0.25
= 4.0 m
So, the length of the shark is 4.0 m
You acoidentally drop an eraser out the window of Part A ah apartment 13 m above the ground. What is the average speed of the eraser from the instant it is roleased to the instant it reaches the ground? Express your answer with the appropriate units. X Incorrect; Try Again; 2 attemps remaining
The average speed of the eraser from the instant it is released to the instant it reaches the ground is approximately 8.9 m/s. To determine the average speed of the eraser, we need to calculate the time it takes for the eraser to fall from a height of 13 m to the ground. We can use the equation for free fall:
h = (1/2) * g * t^2,
where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time.
Solving for t:
t = sqrt((2 * h) / g).
Substituting the values:
t = sqrt((2 * 13 m) / 9.8 m/s^2) ≈ 1.46 s.
The average speed is calculated by dividing the total distance traveled (13 m) by the time:
Average speed = Total distance / Time = 13 m / 1.46 s ≈ 8.9 m/s.
Therefore, the average speed of the eraser from the instant it is released to the instant it reaches the ground is approximately 8.9 m/s.
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why plane mirror always give a virtual image (3 reasons})
A plane mirror always forms a virtual image because of the following reasons:
1. When light rays from an object fall on a plane mirror, they get reflected from the mirror. After reflection, they never meet at any point in real but they appear to meet at some point.
2. The image formed by a plane mirror cannot be obtained on a screen.
3. Plane mirrors never focus light into a single converging point.
An entertainer pulls a table cloth off a table leaving behind the plates and sliverware undisturbed is an example of
A.
the law of balanced forces
B.
Newton's second law
C.
Newton's third law
D.
Newton's first law
Answer:
d.) Newton's first law
Explanation:
This is also called the law of inertia, which means that an object in motion will not stop unless a force is acted upon it, and vice versa. Try this out with a piece of paper and a quarter. Pull the paper from under the quarter slightly quick, and the quarter will stay on the table. Hope i helped you.
the traits of friends
Answer:
someone you trust the most
Explanation:
What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 209 km above Earth's surface
The linear speed of an Earth satellite in a circular orbit at an altitude of 209 km above Earth's surface must be approximately 7.5 km/s.
We can use the equation for the velocity of an object in circular motion, which is v = sqrt(GM/r), where G is the gravitational constant, M is the mass of the Earth, and r is the distance between the center of the Earth and the satellite's orbit.
Plugging in the values for G, M, and r, we get\(v = \sqrt{(6.6743 * 10^{-11} m^3/kg s^{2} * 5.9722 * 10^{24} kg / (6,371,000 m + 209,000 m)}\)
Simplifying this equation gives us v = 7,462.9 m/s, which is approximately 7.5 km/s. Therefore, an Earth satellite at an altitude of 209 km above Earth's surface must have a linear speed of approximately 7.5 km/s to remain in a circular orbit.
The linear speed of an Earth satellite in a circular orbit at an altitude of 209 km above Earth's surface is approximately 7.5 km/s, which can be calculated using the equation for velocity in circular motion.
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5. Moving Blobs of Clay Collide. A 5kg blob of clay moving at 2m/s to the right collides inelastically with a blob of clay moving to the left at 2m/s. Afterward, the conjoined blob is moving at 0.5m/s to the right. What was the mass of the blob that was originally moving to the left?
Answer:
3.0 kg
Explanation:
This is a conservation of momentum problem. Total momentum before the collision must equal total momentum after the collision. Momentum = p = mv.
Let x = mass of blob
to the right is the positive direction
(5 kg)(2 m/s) - (x)(2 m/s) = (5 kg + x)(0.5 m/s)
note: I'm going to leave off the unit kg·m/s to save myself some typing!
10 - 2x = 0.5x + 2.5
-2.5x = -7.5
x = -7.5/-2.5 = 3.0 kg
A girl on a skateboard (total mass of 40kg) is moving at a speed of 10m/s at the bottom of a long ramp. The ramp is inclined at 20 degrees with respect to the horizontal. How far must she travel upward along the ramp before stopping?
An airplane needs to reach a forward velocity of 203 km/h to take off. On a 2000m runway, what is the minimum uniform acceleration necessary for the plane to take flight if it starts from rest?
Answer:
Minimum uniform acceleration in Km/hr² is 20,505.05 km/hr²
Explanation:
In other to determine the acceleration, we can use the formula below
acceleration = velocity/time
Time wasn't given in the question, hence we calculate for time using the parameters given and the formula below
Velocity= distance/time
time = distance/velocity
distance = 2000m ⇔ 2km
time = 2/203
time = 0.0099
Hence, we look for acceleration
which is
acceleration = 203/0.0099
= 20,505.05 km/hr² ⇔ 2.0 × 10⁴
what role does gravity have in the motion of planets around the sun?
Answer:
The gravity helps the planets stay together near the Sun, without it Earth would be floating away with the planet eventually becoming frozen up, thus the role gravity have in the motion of planets around the sun is by keeping them together.
Explanation:
Hope this helps!
calculate the pressure, in pounds per square inch, exerted on the floor by the heel if it has an area of 1.7 cm2 and the woman’s mass is 56 kg.
The answer is 467.311 pounds per square inch.
What is the relationship between pressure and area?
Force divided by area equals pressure. The equation demonstrates that whereas area and pressure are inversely related, respectively, to force. Pressure grows at a constant area as the size of the force exerted grows as well. The greater the pressure applied for a given amount of force, the smaller the area of contact.
\(P = \frac{F}{A} = \frac{mg}{A} = \frac{56 * 9.8}{1.7 *10^{-4} } = 32.282 * 10^{5} Pa\)
Hence, the answer is 467.311 pounds per square inch.
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Now, remove the positive charge by dragging it back to the basket, and drag one negative charge toward the middle of the screen. Determine how the voltage is different from that of the positive charge. How does the voltage differ from that of the positive charge?.
The correct option is;
The voltages become negative instead of positive and keep the same magnitudes
Explanation: Here we have that there is a change in direction from positive to negative with the direction pointing to opposite of the initial direction whereby the field strength does not change due to the reversal of the. Therefore the voltage becomes negative instead of negative while keeping the the magnitude.
That is there is a electric field reversal or a change electric field direction.
What conditions are needed for germination? Air, water, and warmth Cold air, water, and soil Water, warmth, and a good location Warmth, water, and wind
Answer: this answer is definitely c for k12
Explanation:
The volume per second of a fluid flowing through a horizontal pipe of length l is given by kpa/n where k is constant, p is the excess pressure (force per unit area) a is the radius of the pipe and U is the frictional quantity of dimension MLT-1 by dimensions find the number x
According to the given statement the number x is 2. The number x represents the dimensions of the term p * a in the given equation.
By comparing the dimensions of both sides of the equation, we find that x is equal to 2.
The equation given is:
Volume per second = k * (p * a) / n
Where:
- k is a constant
- p is the excess pressure (force per unit area)
- a is the radius of the pipe
- n is the frictional quantity of dimension MLT⁻¹
To find the number x, we need to determine the dimensions of each term in the equation.
1. Dimension of Volume per second:
- Volume has the dimension L³ (length cubed)
- Time has the dimension T (time)
- Therefore, Volume per second has the dimension L³ / T
2. Dimension of k:
- The equation states that k is a constant. Constants are dimensionless.
3. Dimension of p * a:
- Pressure has the dimension M / (L * T² ) (mass divided by length and time squared)
- Radius has the dimension L (length)
- Multiplying pressure by radius results in the dimension M / (L * T² ) * L = M / (L² * T² )
4. Dimension of n:
- Given in the question, n has the dimension MLT⁻¹
(mass times length times time to the power of -1)
Now, we can equate the dimensions:
L³ / T = k * (M / (L² * T² )) * MLT⁻¹
Simplifying the dimensions:
L³ / T = k * M / (L² * T² ) * MLT⁻¹
L³ / T = k * M / L² * M / T² * L^-1 * T⁻¹
L³ / T = k * M² / L² * T⁻¹
To equate the dimensions, both sides of the equation must have the same dimensions. Therefore:
L³ / T = k * M² / L² * T⁻¹
Comparing the dimensions on both sides, we can conclude:
L³ / T = k * M² / L²* T⁻¹
The dimensions on the left side are L^3 / T, and the dimensions on the right side are (k * M²) / (L² * T).
Therefore, the number x is 2.
The number x represents the dimensions of the term p * a in the given equation.
By comparing the dimensions of both sides of the equation, we find that x is equal to 2.
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a 21.6 gram arrow is shot through a 7.5 cm apple. if the arrow enters the apple at 35.5 m/s and emerges with a speed of 25.3 m/s in the same direction, what is the magnitude of the force with which the apple has resisted the arrow? (assume force is exerted only on the tip of the arrow)
The magnitude of the force with which the apple has resisted the arrow is 88.06 Newton.
Using, work-energy theorem,
According to which, the work done by the all the forces on the body is equal to the change in kinetic energy of the body.
So, we can write,
Work done = ∆KE
We know,
Work done = force × displacement
The force is the resistive force by the apple and the displayed is given to be 0.075 meters.
So, we can write,
F(0.075) = 1/2M(V²-U²)
Where,
M is the mass of apple,
V is final velocity,
U is initial velocity.
Putting all the values,
F(0.075) = 1/2(0.0213)((25.3)²-(35.5)²)
Solving further,
F = 88.06 Newton
The resistive force of the apple is 88.06 Newton.
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ANSWER THIS OR ILL GO TO YOUR HOME AND KIDDNAPP YOU FAMILY
How do you determine the net force acting on an object?
Answer:
The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.
Note:
Please mark as Brainliest, or i'll go to your house and kidnapp your family, lol
(it's a joke btw)
Answer:The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.
Explanation:Formula of Net Force
FN is the force acting on a body. When the body is at rest, the net force formula is given by, FNet = Fa + Fg.
I think that's correct
You weigh 710 N. What would you weigh if the Earth were three times as massive as it is and its radius were five times its present value? Answer in units of N
Answer:
85.2 N
Explanation:
You want to know your weight if the Earth were 3 times as massive and had 5 times the present radius. Your weight is 710 N.
WeightYour weight is proportional to the mass of the Earth and the square of the radius between your mass and the center of the Earth. The revised dimensions of the earth would multiply your weight by ...
W = k(M/r²) = 710 N
W' = k((3M)/(5r)²) = k(M/r²)(3/25) = (710 N)(3/25) = 82.5 N
Your weight would be 82.5 N.
A ______ is a single encased electrochemical unit, with one positive and one negative electrode, with a voltage differential across its two terminals
Answer:
Cathode: The positive electrode of a cell. Cell: A single encased electrochemical unit (one positive and one negative electrode) which exhibits a voltage differential across its two terminals.
Answer:
Cell
Explanation:
A cell is a single encased electrochemical unit (one positive and one negative electrode) which exhibits a voltage differential across its two terminals.
Desde un rascacielos de 300 m de altura se lanza un objeto con una velocidad inicial de 50 m/s. Calcula el tiempo que transcurre hasta que llega al suelo y con qué velocidad llega en cada uno de los casos: a) Si se lanza verticalmente hacia arriba. b) Si se lanza verticalmente hacia abajo. c) Si se lanza horizontalmente (En este caso calcular también la distancia al edificio cuando llega al suelo) d) Si se lanza con un ángulo de 30o (Calcular también distancia al edificio)
Answer:
a) t = 14.2 s , v = -92 m / s , b) v = - 59.16 m / s , t = 0.916 s
c) t = 7.75 s , x = 387.5 m
d) t = 10.64 s , x = 463.9 m , v = 92.2 m / s
Explanation:
This is an exercise in kinematics, suppose we take the upward direction as positive
a) is thrown up vertically.
Let's use the equation
y = y₀ + v₀ t - ½ g t²
When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²
0 = y₀ + v₀t - ½ g t²
½ 10 t² - 50 t - 300 = 0
Let's solve the quadratic equation
t² - 10 t - 60 = 0
t = [10 ±√ (10² + 4 60)] / 2
t = [10 ± 18.4] / 2
t₁ = 14.2 s
t₂ = -4.2 s
since time must be a positive quantity, the correctors result t = 14.2 s
the speed at this point is
v = v₀ - g t
v = 50 - 10 14.2
v = -92 m / s
the sign indicates that the body is going down
b) in this case the initial velocity is vo = -50 m / s
let's calculate the velocity on the ground
v² = v₀² - 2g (y-y₀)
v² = 50 2 - 2 10 ((0- 300)
v² = 3500
v = + - 59.16 m / s
as the body is going down the correct sign is the negative
v = - 59.16 m / s
the time it takes to arrive is
v = v₀ - g t
t = (v₀ - v) / g
t = (-50 + 59.16) / 10
t = 0.916 s
c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0
y = y₀ + v₀ t - ½ g t²
0 = 300 + 0 - ½ 10 t²
t = √ (2 300/10)
t = 7.75 s
the horizontal displacement at this time is
x = v₀ₓ t
x = 50 7.75
x = 387.5 m
d) as it is thrown with an angle let's find each component of the velocities
v₀ₓ = v₀ cos 30
\(v_{oy}\) = v₀ sin 30
v₀ₓ = 50 cos 30 = 43.3 m / s
v_{oy} = 50 sin 30 = 25 m / s
we look for the time of descent
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + v_{oy} t - ½ g t²
0 = 300 + 25 t - ½ 10 t²
t² - 5t - 60 = 0
we solve the second degree equation
t = [5 ±√ (5² + 4 60)] / 2
t = [5 ± 16.28] / 2
t₁ = 10.64 s
t₂ = -5.64 s
since the time must be positive the result is t = 10.64 s
the range on the x axis is
x = v₀ₓ t
x = 43.6 10.64
x = 463.9 m
the ground speed is
v_{y} = \(v_{oy}\) - g t
v_{y} = 25 - 10 10.64
v_{y} = -81.4 m / s
speed is
v = √ (v₀ₓ² + v_{y}²)
v = √ (43.3² + 81.4²)
v = 92.2 m / s
A small rocket burns 0.0500 kg of fuel per second, ejecting it as a gas with a velocity relative to the rocket of magnitude 1600 m/s. (a) What is the thrust of the rocket
a gardener mounts a pot plant on the wall using a metal ring and a chain the ring exerts a horizontal force of 20n on the pot plant and the weight of the pot plant is 30n determine the magnitude of the chain by calculation and construction
The magnitude of the force exerted by the chain is 36.1 N.
Resultant forcesThe magnitude of the force exerted by the chain must balance the force exerted by the ring and weight of the pot.
The magnitude of the force exerted by the chain is calculated by applying Pythagoras theorem;
\(F_3^2 = F_1^2 + F_2^2\\\\F_3 = \sqrt{F_1^2 + F_2^2} \\\\F_3 = \sqrt{20^2 + 30^2} \\\\F_3 = 36.1 \ N\)
Thus, the magnitude of the force exerted by the chain is 36.1 N.
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