Find the work done in lifting the bucket
A 7 lb bucket attached to a rope is lifted from the ground into the air by pulling in 24 ft of rope at a constant speed. If the rope weighs 0.8, how much work is done lifting the bucket and rope?
Assuming the force required to lift the rope is equal to its weight, find the force function, F(x), that acts on the rope when the bucket is at a height of x ft.
F(x)=
Answers
The total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).
To find the work done in lifting the bucket and rope, we need to consider two parts:
Part 1: Work done lifting the bucket (without the rope) 24 ft:
The work done in lifting the bucket can be calculated by multiplying the weight of the bucket by the distance it is lifted.
Given:
Weight of the bucket = 7 lb
Distance lifted = 24 ft
Work done lifting the bucket = Weight of the bucket x Distance lifted
Work done lifting the bucket = 7 lb x 24 ft
Please note that the units need to be consistent for the calculation. In this case, we have pounds (lb) and feet (ft).
Part 2: Work done lifting the rope:
Assuming the force required to lift the rope is equal to its weight, we can calculate the work done lifting the rope by multiplying the weight of the rope by the distance it is lifted.
Given:
Weight of the rope = 0.8 lb
Distance lifted = 24 ft
Work done lifting the rope = Weight of the rope x Distance lifted
Work done lifting the rope = 0.8 lb x 24 ft
Now, we can calculate the total work done in lifting the bucket and rope by summing up the work done in both parts:
Total work done = Work done lifting the bucket + Work done lifting the rope
Please note that the units of work are in foot-pounds (ft-lb).
Now, we can calculate the values:
Work done lifting the bucket = 7 lb x 24 ft = 168 ft-lb
Work done lifting the rope = 0.8 lb x 24 ft = 19.2 ft-lb
Total work done = 168 ft-lb + 19.2 ft-lb = 187.2 ft-lb
Therefore, the total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).
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The complete question is:
Find the work done In lifting the bucket A 7 Ib bucket attached to a rope is lifted from the ground Into the air by puling in 24 ft of rope at a constant speed. If the rope weighs 0.8, how much work done lifting the bucket and rope? Part1 -1 Find the work done lifting the bucket (without the rope) 24 ft . ft-Ib Part-2. Assuming the force required to lift the rope is equal to its weight; find the force function, F(x), that acts on the rope when the bucket is at height of x Ft. Part- 3 Setup the Integral that will give the work required to lift the rope 24 ft. Part -4 The total amount of work done lifting the bucket and ft-Ib.
Related Questions
If the Kelvin temperature of a gas is tripled and the volume if doubled, the new pressure will be:A. 2/3 the original pressureB. 3/2 the original pressureC. 5 times the original pressureD. 1/6 the original pressure
Answers
If the Kelvin temperature of a gas is tripled and the volume if doubled, the new pressure will be (B) 3/2 the original pressure.
The new pressure of the gas can be determined using the ideal gas law, which states that the pressure of a gas is proportional to its temperature and inversely proportional to its volume. If the temperature of a gas is tripled, then its pressure will be multiplied by a factor of 3. If the volume is doubled, then the pressure will be divided by a factor of 2. So, the new pressure will be 3 divided by 2, or 3/2 times the original pressure, which is answer choice B.To know more about thermodynamics visit:
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Can someone answer this science question NO LINKS !!!!
Answers
Answer:
Point x.
Explanation:
The potential energy of an object is simply defined as the energy stored in an object by virtue of its location. Mathematically, it is expressed as:
PE = mgh
Where
PE => is the potential energy
m => is the mass of the object
g => is acceleration due to gravity
h => is the height
From the formula i.e PE = mgh, we can see that the potential energy (PE) is directly proportional to the height (h).
This simply indicates that as the height increases, the potential energy will increase and as the height decreases, the potential energy will also decrease.
Now, let us consider the question given above.
Point x indicates the greatest height attained by the ball. Therefore, the ball will have it's greatest potential energy at point x.
The graph shows the amplitude of a passing wave over time in seconds (s). What is the approximate frequency of the wave shown?
Answers
Answer:
Explanation:
you got that wrong it is a 0.4
= 1 / 6
= 0.16666 Hz, which is approximately 0.2Hz.
Therefore answer is 0.2Hz
FILL IN THE BLANK. Sometimes interactions are difficult to analyze during the process that causes changes in motion. In these cases it can be easier to describe the overall____in motion rather than detail it step by step.
Answers
Sometimes interactions between objects in motion are difficult to analyze during the process that causes changes in motion. In these cases, it can be easier to describe the overall change in motion rather than detail it step by step.
How describing overall change in motion is easier?In some cases, analyzing the interactions that cause changes in motion can be challenging. In such scenarios, it is more convenient to describe the overall change in motion rather than detailing each step. This approach is often referred to as the principle of conservation of momentum. This principle states that the total momentum of an isolated system remains constant in the absence of external forces.
It can be applied to a wide range of physical phenomena, including collisions between objects, rocket propulsion, and fluid dynamics. By using this principle, scientists and engineers can make accurate predictions about the behavior of physical systems without needing to analyze every individual interaction.
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Formation of the Solar System Lab Report
Instructions: In this virtual lab, you will investigate the law of universal gravitation by manipulating the size of the star and the positions of planets within Solar System X. Record your hypothesis and results in the lab report below. You will submit your completed report.
Name and Title:
Include your name, instructor's name, date, and name of lab.
Objectives(s):
In your own words, what is the purpose of this lab?
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity. These statements reflect your predicted outcomes for the experiment.
If the mass of the sun is 1x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.
If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.
If the mass of the sun is 3x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.
Procedure:
The materials and procedures are listed in your virtual lab. You do not need to repeat them here. However, you should note if you experienced any errors or other factors that might affect your outcome.
Using the summary questions at the end of your virtual lab activity, please clearly define the dependent and independent variables of the experiment.
Data:
Record your observation statements from Space Academy.
When the mass of the sun is larger, Earth moves around the sun at a ______ (faster, slower) pace.
When the mass of the sun is smaller, Earth moves around the sun at a ______ (faster, slower) pace.
When Earth is closer to the sun, its orbit becomes _____ (faster, slower).
When Earth is farther from the sun, its orbit becomes _____ (faster, slower).
For each trial, record the orbit number of each planet from the sun. Be sure to indicate the number of planets in the habitable zone after each trial. Create a different configuration of planets for each trial. An example has been supplied for you.
Orbit Number
Planet One Orbit Number
Planet Two Orbit Number
Planet Three Orbit Number
Planet Four Number of planets in the habitable zone Number of planets left in successful orbit
Example: sun's mass 1x
1
3
5
6
1
2
sun's mass 1x—Trial One
sun's mass 1x—Trial Two
sun's mass 2x—Trial One
sun's mass 2x—Trial Two
sun's mass 3x—Trial One
sun's mass 3x—Trial Two
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.
Using two to three sentences, summarize what you investigated and observed in this lab.
You completed three terra forming trials. Describe the how the sun's mass affects planets in a solar system. Use data you recorded to support your conclusions.
In this simulation, the masses of the planets were all the same. Do you think if the masses of the planets were different, it would affect the results? Why or why not?
How does this simulation demonstrate the law of universal gravitation?
It is the year 2085, and the world population has grown at an alarming rate. As a space explorer, you have been sent on a terraforming mission into space. Your mission to search for a habitable planet for humans to colonize in addition to planet Earth. You found a planet you believe would be habitable, and now need to report back your findings. Describe the new planet, and why it would be perfect for maintaining human life.
Answers
The law of universal gravitation says that each physical object attracts every other entity with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
What is the law of universal gravitation imply?The greater the mass of an object, the greater the gravitational force it exerts on other objects, and the closer two objects are to each other, the stronger the gravitational force between them.
In the case of the solar system, the sun is the largest object and therefore exerts the greatest gravitational force on all the planets and other objects within its orbit. The planets, in turn, also exert gravitational forces on each other, which can affect their orbits and positions within the solar system.
Therefore, if the size of the sun were to be manipulated, it would affect the gravitational forces on the planets and their orbits. Similarly, if the positions of the planets were to be manipulated, it would also affect the gravitational forces and their positions within the solar system.
As for a hypothesis, it could be that if the size of the sun were to increase, the gravitational forces on the planets would also increase, which could cause changes in their orbits and potentially lead to collisions or other catastrophic events.
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RC circuits
4. A 4.00 MΩ resistor and a 3.00 MΩ capacitor are connected in series with a
12.0V power supply.
a. What is the time constant of the circuit?
b. Express the current in the circuit and the charge on the capacitor as functions of the time
Answers
The time constant of the circuit can be determined from the formula τ = RC. The values given in the question are R = 4.00 MΩ and C = 3.00 µF. Thus, the time constant is given as:τ = RC = (4.00 × 10^6 Ω) × (3.00 × 10^-6 F) = 12 secondsb. The current in the circuit can be found by using Ohm’s law, which states that I = V/R, where V is the voltage across the circuit.
The voltage across the circuit is 12.0 V, so the current is given as:I = V/R = (12.0 V)/(4.00 MΩ) = 3.00 µAThe charge on the capacitor as a function of time can be found using the formula Q = Qmax (1 - e^(-t/τ)), where Qmax is the maximum charge that can be stored by the capacitor. The maximum charge can be found using the formula Qmax = CV, where V is the voltage across the capacitor.
The voltage across the capacitor is the same as the voltage across the circuit, which is 12.0 V. Thus, the maximum charge that can be stored by the capacitor is:Qmax = CV = (3.00 × 10^-6 F) × (12.0 V) = 36 µCThe charge on the capacitor as a function of time is given as:Q = Qmax (1 - e^(-t/τ)) = (36 µC) (1 - e^(-t/12)).
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A car moves with constant speed and then constant acceleration
Which graph is the speed-time graph for the car?
Answers
Answer:
You have no graph on the post.
A boy of 50 kg climbs a wall 2m high. Calculate the change in potential energy of the boy
Answers
Answer:
If this is the question : boy weighing 50kg climbs up a vertical height of 100m. Calculate the amount of work done by him. How much potential energy does he gain (g=9.8m/s2)
So the answer will be:
mass of boy = m = 50 kg
height = h = 100m
since boy does not move anything with his force, work done by him is zero work done on the boy = gain in potential energy
P.E=mgh P.E=50×9.8×100 P.E=49KJ so, potential energy gained by boy is 49 KJ
Explanation:
how much does a change in mass affect the kinetic energy of two balls of comparable diameter?
Answers
Answer:
Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.
In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.
Explain your observations when the aluminum-covered and uncovered cups were touched with a finger, using how charges flow to or from ground though your finger.
Answers
When the aluminum-covered and uncovered cups were touched with a finger, the main observation is that charges flow to or from the ground through your finger.
When you touch the aluminum-covered cup with your finger, charges from your body flow to the cup. This happens because your body is conducting electricity The charges flow from your body through your finger and into the cup. The cup acts as a conductor, allowing the charges to move freely.
On the other hand, when you touch the uncovered cup with your finger, charges flow from the cup into your body. Again, this happens because your body is conducting electricity. The charges flow from the cup through your finger and into your body. Since your body is also a conductor, the charges are able to move through it. when the aluminum-covered cup is touched with a finger, charges flow from your body to the cup. When the uncovered cup is touched, charges flow from the cup to your body. This flow of charges occurs because your body acts as a conductor, allowing electricity to pass through it.
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a spherical mirror produces a magnification of -1 on a screen placed at a distance of 40cm from the mirror i) write the type of mirror ii) What is the focal length of the mirror
Answers
Answer:
f =-20 cm
Explanation:
Given that,
The magnification of a spherical mirror, m = -1
The image distance, v = 40 cm (for negative magnification)
The magnification of a concave mirror is negative. The mirror showing -1 magnification is a concave mirror.
Let f be the focal length of the mirror. We know that,
\(m=\dfrac{-v}{u}\\\\-1=\dfrac{-v}{u}\\\\v=u\)
Object distance, u = -40 cm
Using mirror's formula i.e.
\(\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}\\\\f=\dfrac{1}{\dfrac{1}{-40}+\dfrac{1}{-40}}\\\\f=-20\ cm\)
So, the focal length of the mirror is 20 cm.
Describing Simple Machines
Match each simple machine with its description.
lever
is a ramp
inclined plane
+
similar to a seesaw, can lift an object
pulley
uses a rope; can change the direction
of a force
wheel and axle
reduces the amount of friction when
an object is being moved
wedge
t
can split apart an object
Answers
Answer:
A wedge can split an object apart
A lever is the seesaw
inclined plane is a ramp
a pulley can reduce the amount of friction
wheel and axle is the rope one
Explanation:
Following are the matches:
lever: similar to a seesaw, can lift an objectinclined plane: is a ramppulley: uses a rope; can change the direction of a forcewheel and axle: reduces the amount of friction when an object is being movedwedge: can split apart an objectWhat are simple machines?Simple machines are basic mechanical devices that can help make work easier by reducing the amount of force or effort needed to do a task. They are usually the most basic forms of machines, often made up of only one or two parts, and are used to change the direction or magnitude of a force.
There are six types of simple machines:
Lever: A rigid bar that pivots around a fixed point, called a fulcrum, to move a load. Examples include a seesaw, crowbar, and scissors.Inclined Plane: A sloping surface used to move a load from a lower level to a higher level. Examples include a ramp and stairs.Pulley: A wheel with a grooved rim used to change the direction or magnitude of a force by pulling a rope or cable. Examples include a crane and a flagpole.Wheel and Axle: A wheel with a rod or axle at its center used to move a load. Examples include a car wheel and a doorknob.Wedge: A triangular-shaped tool that can split or separate objects. Examples include a knife and an ax.Screw: An inclined plane wrapped around a cylinder or cone used to hold objects together or to lift or move them. Examples include a bolt and a jar lid.Simple machines are the building blocks for more complex machines, and they are used in many everyday devices and equipment to make work easier and more efficient.
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What is the current ????2 through resistor ????2? Find an expression for ????2 in terms of ????????, ????????, ????1, ????2, and ????3. Take the positive direction to be downward.
Answers
The current I2 through resistor R2 is given by the expression I2 = (Vb - Va) / (R1 + R2 + R3).
In this expression, Vb is the voltage across R2 in the positive direction from Va, and R1, R2, and R3 are the resistances of the respective resistors.
The flow of electricity in a conductor is known as the current, which is often measured in amperes. It is a measurement of the speed at which a certain location in a circuit experiences a flow of charge. Voltage placed across a conductor, the conductor's resistance, and the circuit's capacitance all have an impact on current. In electrical engineering and electronics, the current is particularly crucial since it is utilized to estimate the power lost in a circuit.
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Full Question: What is the current I 2 I2 through resistor R 2 ? R2? Find an expression for I 2 I2 in terms of V a , Va, V b , Vb, R 1 , R1, R 2 , R2, and R 3. R3. Take the positive direction to be downward
when a 0.106 kg mass is suspended at rest from a certain spring, the spring stretches 3.80 cm. find the instantaneous acceleration of the mass when it is raised 6.30 cm, compressing the spring 2.50 cm.
Answers
The instantaneous acceleration of the mass when it is raised 6.30 cm and compresses the spring 2.50 cm is 16.26 m/s^2.
To solve this problem, we can use the equation for the force exerted by a spring:
F = -kx
When the mass is suspended at rest from the spring, the force exerted by the spring balances the weight of the mass, so we can write:
kx = mg
Solving for the spring constant, we get:
k = mg / x
Substituting the given values, we have:
k = (0.106 kg)(9.81 m/s^2) / 0.0380 m = 27.36 N/m
When the mass is raised 6.30 cm, the displacement of the spring is x = -0.0250 m (since the spring is compressed by 2.50 cm). The force exerted by the spring is:
F = -kx = -(27.36 N/m)(-0.0250 m) = 0.684 N
By Newton's second law, the net force on the object is:
Fnet = ma
where a is the instantaneous acceleration of the object.
The net force is the sum of the force exerted by the spring and the weight of the object:
Fnet = F + mg = 0.6875 N + (0.106 kg)(9.81 m/s^2) = 1.7239 N
Solving for the acceleration, we get:
a = Fnet / m = 1.7239 N / 0.106 kg = 16.2632 m/s^2
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Two different sub-atomic particles are described below:
Particle X: No charge
Particle Y: Outside the nucleus
Which statement is true? (5 points)
X is a neutron and Y is an electron.
X is a neutron and Y is a proton.
X is a proton and Y is an electron.
X is an electron and Y is a proton.
Answers
Answer:
A
Explanation:
neutrons have neutral charge, while electrons are outside the nucleus with a negative charge
Answer:A
Explanation:took test
một chiếc thuyền đang chạy ngược dòng nước, chiếc thuyền là đứng yên so với ...
A. dòng nước
B. hai bờ
C. người lái thuyền
D. cả 3 đáp án trên đều dúng
Answers
Answer:
Một chiếc thuyền đang chạy ngược dòng nước, chiếc thuyền là đứng yên so với
During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with large catapults that are made with surgical hose mounted on a window frame. A balloon filled with dyed water is placed in a pouch attached to the hose, which is then stretched through the width of the room. Assume that the stretching of the hose obeys Hooke's law with a spring constant of 88.0 N/m. If the hose is stretched by 4.20 m and then released, how much work does the force from the hose do on the balloon in the pouch by the time the hose reaches its relaxed length
Answers
Answer:
The work done on the hose by the time the hose reaches its relaxed length is 776.16 Joules
Explanation:
The given spring constant of the of the spring, k = 88.0 N/m
The length by which the hose is stretched, x = 4.20 m
For the hose that obeys Hooke's law, and the principle of conservation of energy, the work done by the force from the hose is equal to the potential energy given to the hose
The elastic potential energy, P.E., of a compressed spring is given as follows;
P.E. = 1/2·k·x²
∴ The potential energy given to hose, P.E. = 1/2 × 88.0 N/m × (4.20 m)²
1/2 × 88.0 N/m × (4.20 m)² = 776.16 J
The work done on the hose = The potential energy given to hose, P.E. = 776.16 J
Why can't we currently power spacecraft beyond Jupiter on solar power?
Answers
Answer:
Ok, the answer is because there will not be enough sunlight for a spacecraft to power all the way.
To polish leather shoes, people use shoe polish. What does this tell you about the surface of leather?
Answers
Answer: Polish creates a thin layer of wax on the surface of the leather which protects the leather from getting wet and undergoing wear and tear. It also has a lubricating effect on the leather keeping it supple and preventing the leather from drying out and cracking
The weight shift forward and backwards in your vehicle is referred to as....
Pitch
Roll
Yaw.
Answers
a force that is at rest or moves in at a constant speed and in a constant direction is called a what force
Answers
The question is fishing for "balanced force".
But the description in the question is terrible.
The half life of carbon-14 is 5730 years. How old is a bone if it presently contains 0.3125 g of carbon-14, but it was estimated to have originally contained 80 g of carbon-14?
Answers
The age of the bone is 45840 years.
We'll begin by calculating the number of half-lives that has elapsed.
Amount remaining (N) = 0.3125 g
Initial amount (N₀) = 80 g
Number of half-lives (n) =?N × 2ⁿ = N₀
0.3125 × 2ⁿ = 80
Divide both side by 0.3125
2ⁿ = 80 / 0.3125
2ⁿ = 256
2ⁿ = 2⁸
n = 8Thus, 8 half-lives has elapsed
Finally, we shall determine the age of the bone.
Half-life (t½) = 5730 years
Number of half-lives (n) = 8
Time (t) =?t = n × t½
t = 8 × 5730
t = 45840 yearsTherefore, the age of the bone is 45840 years.
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A car drives at a steady speed around a perfectly circular track. Which of the following are false.(You will receive partial credit for each correct choice and lose partial credit for each incorrect choiceso choose carefully)The net force on the car is zeroBoth the acceleration and the net force point outwardBoth the acceleration and net force on the ground point inward.If there is no friction, the acceleration is outwardThe net force on the car is inversely proportional to the radius of the trackThe cars acceleration is zero.
Answers
The false statements about the force and acceleration of the car are statements 1, 2, 3, 4, and 6.
1. The net force on the car is zero: False.
The net force on the car is not zero since it is constantly accelerating due to the centripetal force. This force points inward towards the center of the circular track and is provided by the friction between the tires and the track.
2. Both the acceleration and the net force point outward: False.
The acceleration is inward and the net force is inward. This is due to the centripetal force which is pointing inward toward the center of the track.
3. Both the acceleration and the net force on the ground point inward: False.
The acceleration is pointing inward due to the centripetal force, while the net force is pointing outward due to the static friction between the ground and the tires.
4. If there is no friction, the acceleration is outward: False.
The acceleration is always inward due to the centripetal force, even if there is no friction.
5. The net force acting on the car is inversely proportional to the radius of the track: True.
As the radius of the track increases, the net force acting on the car decreases.
6. The car's acceleration is zero: False.
The car's acceleration is not zero, it is constantly accelerating due to the centripetal force.
In conclusion, all of the statements are false except for the fifth statement.
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A car travels from rest (0) to 60 m/s in 5 seconds. What is its acceleration?
Answers
Answer:
12 meters per seconds......
Explanation:
60/5=12
A car travels from rest to 60 m/s in 5 seconds, so its acceleration is 12 m/\({s}^2\) (60-0/5), and the acceleration is calculated by subtracting the final from the initial and by diving with the time.
What is the significance of the acceleration?Acceleration is the unit that describes the change in velocity, such as the quickness or slowness of the car, and when the acceleration is very high, there is a high chance of colliding and an accident occurring, but this is important for vehicles such as sports cars and racing cars. While low acceleration is used in magnetic resonance imaging in the medical field, it is also used in the industrial sector for robotics, etc.
Hence, a car travels from rest to 60 m/s in 5 seconds, so its acceleration is 12 m/\({s}^2\) (60-0/5), and the acceleration is calculated by subtracting the final from the initial and by diving with the time.
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Halley’s comet orbits the Sun in an elliptical path as shown.During its orbit, it moves faster when it is closer to the Sun than when it is further away.What can you conclude about the comet’s potential energy as it approaches the Sun? Explain.
Answers
Given what we know, we can confirm that as Halley's comet moves closer to the sun, we can expect its potential energy to be near its maximum.
How do we know this?We can conclude that its potential energy will increase as it comes closer to the sun, and will reach its maximum at the closest point to the sun. This is because the potential energy of an object is directly proportional to the force of gravity acting on that object. As Halley's comet approaches the sun, the sun's gravitational pull on the comet is stronger, and thus, its potential energy increases.
Therefore, given the relationship between gravity and potential energy, we can confirm that s Halley's comet moves closer to the sun, we can expect its potential energy to increase and be near its maximum.
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3. a frictionless pulley has the shape of a uniform solid disk of mass 2.5 kg and radius 20.0 cm. a 1.5-kg stone is attached to a massless wire that is wrapped around the rim of the pulley, as shown. the system is then released from rest. as always, show details of your calculation. a. how far (in m)must the stone fall so that the pulley has 4.5 j of kinetic energy? b. what percent of the total kinetic energy of the system does the pulley have at that point?
Answers
a. To calculate the distance the stone must fall, we need to use the formula KE = ½ mv², where m is the mass of the object and v is the velocity of the object. First, calculate the total kinetic energy of the system:
\(KEtotal = ½ mPulley x v² + ½ mStone x v² = ½ (2.5 kg)(4.5 J) + ½ (1.5 kg)(4.5 J) = 6.75 J\)
We then rearrange the equation to solve for v²: v² = 2 x KE / m = (2 x 6.75 J) / (1.5 kg) = 9 J/kg.Next, we need to calculate the velocity of the stone, vStone, which is equal to the square root of the above equation: vStone = √(9 J/kg) = 3 m/s
Finally, we need to use the equation s = vt, where s is the distance the stone falls, v is the velocity of the stone, and t is the time it takes for the stone to fall. We rearrange the equation to solve for t: t = s / v = 4.5 m / 3 m/s = 1.5 s Therefore, the stone must fall a distance of 4.5 m in order for the pulley to have 4.5 J of kinetic energy.
b. To calculate the percent of the total kinetic energy of the system that the pulley has, we need to use the equation: Percent of total KE = KEpulley/KEtotal x 100%. KEpulley = ½ mPulley x v² = ½ (2.5 kg)(4.5 J) = 4.5 J
Therefore, the percent of the total kinetic energy that the pulley has is 4.5 J/6.75 J x 100% = 66.67%.
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A 5.25 kg block starts at the top of a 16.1 m long incline that has an angle of 10∘ to the horizontal. the block then slides out on a horizontal frictionless surface and collides with a 7.11 kg block in an inelastic collision in which the blocks stick together. the blocks then slide to the right onto a frictional section of track as a result of the collision.
a)what was the velocity of the 5.25kg block at the bottom of the ramp? v = ___ m/s
b)how much kinetic energy was lost in the collision? δke = ___ m/s
c) how far do the blocks slide to the right on the frictional surface before stopping if the coefficient of kinetic friction is μk = 0.18. d = ___ m/s
Answers
A 5.25 kg block starts at the top of a 16.1 m long incline that has an angle of 10∘ to the horizontal.
a)what was the velocity of the 5.25kg block at the bottom of the ramp? v = _ 6.73 m/s.
b)how much kinetic energy was lost in the collision? δke = _ 68.22 J._ m/s
To solve this problem, let’s break it down into three parts:
a) To find the velocity of the 5.25 kg block at the bottom of the ramp, we can use the principle of conservation of mechanical energy. The initial potential energy of the block at the top of the ramp is equal to the final kinetic energy of the block at the bottom of the ramp. Therefore:
M1 * g * h = (m1 + m2) * v^2 / 2
Where m1 is the mass of the 5.25 kg block, g is the acceleration due to gravity, h is the height of the incline, m2 is the mass of the 7.11 kg block, and v is the velocity of the 5.25 kg block at the bottom of the ramp.
Plugging in the values, we have:
5.25 kg * 9.8 m/s^2 * 16.1 m * sin(10°) = (5.25 kg + 7.11 kg) * v^2 / 2
Solving for v, we get:
V ≈ 6.73 m/s
Therefore, the velocity of the 5.25 kg block at the bottom of the ramp is approximately 6.73 m/s.
b) To find the amount of kinetic energy lost in the collision, we can use the principle of conservation of linear momentum. Before the collision, the total momentum is given by the sum of the individual momenta of the blocks. After the collision, the blocks stick together and move as one mass. Therefore:
(m1 * v1 + m2 * v2)_initial = (m1 + m2) * v_final
Where m1 and v1 are the mass and velocity of the 5.25 kg block, m2 and v2 are the mass and velocity of the 7.11 kg block, and v_final is the common velocity of both blocks after the collision.
Since the 5.25 kg block starts from rest at the top of the ramp, v1 is 0. Plugging in the values and solving for v_final:
(5.25 kg * 0 + 7.11 kg * v2)_initial = (5.25 kg + 7.11 kg) * v_final
7.11 kg * v2 = 12.36 kg * v_final
After the collision, the two blocks stick together, so their final velocity is the same. Therefore:
V_final = v2
The amount of kinetic energy lost in the collision is:
ΔKE = (1/2) * (m1 * v1^2 + m2 * v2^2) – (1/2) * (m1 + m2) * v_final^2
Since v1 is 0 and v_final = v2:
ΔKE = (1/2) * (m2 * v2^2) – (1/2) * (m1 + m2) * v2^2 68.22 J.
Plugging in the values:
ΔKE ≈ 68.22 J
Therefore, the kinetic energy lost in the collision is approximately
c) To find how far the blocks slide to the right on the frictional surface before stopping, we can use the work-energy principle. The work done by the friction force is equal to the change in kinetic energy:
Work = ΔKE
The work done by friction is given by:
Work = force_friction * distance
The force of friction can be calculated using the equation:
Force_friction = μk * (m1 + m2) * g
Where μk is the coefficient of kinetic friction
Learn more about mechanical energy here:
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Describe what sandpaper does to wood to make it smoother, and explain why.
Answers
Answer it scapes away loose anf rough pieces of wood
Explanation:
Answer:
To achieve a nice smooth finish, it's essential to sand to help prepare the area for painting application, by sanding you are removing imperfections (also known as pimples), creating a nice smooth finish while at the same time adding adhesion by developing small, rough ridges for the paint to stick to.
Using the right sandpaper can make all the difference in a woodworking, painting, or finishing project; but choosing between the many different types of sandpaper that are available can be a challenge. Here are some tips on how to choose the best sandpaper for your next project.
Explanation:
Sry if this is wrong :(
Fill in the missing for each of the statements below:
Answers
Answer:
Explanation:
a. thermal
b. waste
c. chemical, electrical
d. efficiency
A test rocket is launched by accelerating it along a 200.0 m, 35 degree incline at 1.25 m/s/s starting
from rest. The instant the rocket leaves the incline, its engines turn off, it is subject only to gravity,
and air resistance can be ignored. Find
a) the maximum height above the ground the rocket reaches
Answers
Answer:
The maximum height above the ground the rocket reaches is 123.1 m.
Explanation:
Let's find the final velocity at a distance of 200 m:
\( v_{f}^{2} = v_{0}^{2} + 2ad \)
Where:
\(v_{f}\) is the final speed =?
v₀ is the initial speed =0
a is the acceleration = 1.25 m/s²
d is the distance = 200 m
\(v_{f} = \sqrt{2ad} = \sqrt{2*1.25 m/s{2}*200 m/s} = 22.4 m/s\)
Now, when the engines of the rocket turn off and it is subject only to gravity, the height reached is:
\( v_{fy}^{2} = v_{0y}^{2} - 2gh \)
Where:
\(v_{f}\) = 0
\(h = -\frac{v_{fy}^{2} - v_{0y}^{2}*sin(\theta)}{2g} = \frac{(22.4*sin(35))^{2}}{2*9.81 m/s^{2}} = 8.4 m\)
Finally, the maximum height above the ground is:
\( h_{max} = h + H \)
Where H is the vertical component of the 200.0 meters.
\(h_{max} = h + H = 8.4 m + 200.0 m*sin(35) = 123.1 m\)
Therefore, the maximum height above the ground the rocket reaches is 123.1 m.
I hope it helps you!