find x: -3 = 4x - 12x^2 + 7x^3

Answer:

7/54

Step-by-step explanation:

Answer:

Explanation:

The standard form of an hyperbola is:

Where (h, k) are the coordinates of the center.

We are given the asyptotes and the foci.

The foci are (7, 0) and (7, 10)

The y value of the center of the parabola is midway from the two foci. Then, the y-coordinate of the center is 5

The coordinated of the center are (7, 5)

Now, we can use that the form of the asymptotes are:

We have:

Then:

a = 4

b = 3

Now we can write:

Answer:

id say a or b but....... maybe not

Step-by-step explanation:

Answer:

C) 918,450 cm^3

Step-by-step explanation:

If the individual switches to a hybrid car, they will save approximately 8,021.24 gallons of gas in a year for their commute.

To determine how much gas the individual will save if they switch to a hybrid vehicle, we need to calculate the total amount of gas consumed by both the current car and the hybrid car.

First, let's calculate the total number of miles driven by the individual in a year:

Total number of miles driven = 6060 miles/week x 52 weeks = 315,120 miles

Next, let's calculate the total amount of gas consumed by the current car in a year:

Gas consumption of current car = Total number of miles driven / Miles per gallon of current car

= 315,120 miles / 22 miles per gallon

= 14,323.64 gallons

Now, let's calculate the total amount of gas that will be consumed by the hybrid car in a year:

Gas consumption of hybrid car = Total number of miles driven / Miles per gallon of hybrid car

= 315,120 miles / 50 miles per gallon

= 6,302.4 gallons

Therefore, the individual will save:

Gas saved = Gas consumption of current car - Gas consumption of hybrid car

= 14,323.64 gallons - 6,302.4 gallons

= 8,021.24 gallons

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The required answer is the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

Explanation:-

a. Economic order quantity (EOQ) is defined as the optimal quantity of inventory to be ordered each time to reduce the total annual inventory costs.

It is calculated as follows: EOQ = sqrt(2DS/H)

Where, D = Annual demand = 100 x 52 = 5200S = Order cost = $57 per order H = Annual holding cost = 0.30 x 10.75 = $3.23 per bag per year .Therefore, EOQ = sqrt(2 x 5200 x 57 / 3.23) = 234 bags. The average time between orders (TBO) can be calculated using the formula: TBO = EOQ / D = 234 / 100 = 2.34 weeks ≈ 2 weeks (rounded to nearest whole number).

Hence, the EOQ is 234 bags and the average time between orders is 2 weeks (approx).b. R is the reorder point, which is the inventory level at which an order should be placed to avoid a stockout.

It can be calculated using the formula:R = dL + zσL

Where,d = Demand per day = 100 / 5 = 20L = Lead time = 1 week (5 working days) = 5 day

z = z-value for 92% cycle-service level = 1.75 (from standard normal table)σL = Standard deviation of lead time demand = σ / sqrt(L) = 16 / sqrt(5) = 7.14 (approx)

Therefore,R = 20 x 5 + 1.75 x 7.14 = 119.2 ≈ 120 bags

Hence, the reorder point R should be 120 bags.c. An inventory withdraw of 10 bags was just made. Is it time to reorder?The current inventory level is 310 bags, which is greater than the reorder point of 120 bags. Since there are no open orders or backorders, it is not time to reorder.d. The store currently uses a lot size of 500 bags (i.e., Q = 500).What is the annual holding cost of this policy.

Annual ordering cost. Without calculating the EOQ, how can you conclude the lot size is too large?Annual ordering cost = (D / Q) x S = (5200 / 500) x 57 = $592.80 per year.

Annual holding cost = Q / 2 x H = 500 / 2 x 0.30 x 10.75 = $806.25 per year. Total annual inventory cost = Annual ordering cost + Annual holding cost= $592.80 + $806.25 = $1,399.05Without calculating the EOQ, we can conclude that the lot size is too large if the annual holding cost exceeds the annual ordering cost.

In this case, the annual holding cost of $806.25 is greater than the annual ordering cost of $592.80, indicating that the lot size of 500 bags is too large.e.

The annual cost saved by shifting from the 500-bag lot size to the EOQ can be calculated as follows:Total cost at Q = 500 bags = $1,399.05Total cost at Q = EOQ = Annual ordering cost + Annual holding cost= (D / EOQ) x S + EOQ / 2 x H= (5200 / 234) x 57 + 234 / 2 x 0.30 x 10.75= $245.45 + $93.68= $339.13

Annual cost saved = Total cost at Q = 500 bags - Total cost at Q = EOQ= $1,399.05 - $339.13= $1,059.92

Hence, the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

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Answer:

Here is the graph of the given equation:

Answer:

"To search whether carbonate mineral content in another material" is the right answer.

Step-by-step explanation:

So that the above is the right answer.

Answer:

The answer is B

Step-by-step explanation:

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We need approximately 164.57 inches of paper to wrap the gift, rounded to two decimal places.

We have,

To wrap a gift in the shape of a cylinder without wasting any paper, we need to calculate the surface area of the cylinder, which represents the amount of paper required to cover the entire cylinder.

The formula for the surface area of a cylinder is:

SA = 2πr^2 + 2πrh

where SA is the surface area, r is the radius of the base, h is the height of the cylinder, and π is pi, which we will approximate as 22/7.

We are given that the height of the cylinder is 18 inches and the diameter is 6 inches.

We can use the diameter to find the radius, which is half of the diameter:

r = d/2 = 6/2 = 3 inches

Now we can substitute the values of r and h into the formula for SA:

SA = 2πr^2 + 2πrh

SA = 2(22/7)(3)^2 + 2(22/7)(3)(18) (substituting r = 3 and h = 18)

SA = 2(22/7)(9) + 2(22/7)(54)

SA = 396/7 + 756/7

SA = 1152/7

Therefore,

We need approximately 164.57 inches of paper to wrap the gift, rounded to two decimal places.

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The "d" format specifier is used to denote a signed decimal integer in various programming languages and formatting systems.

When used in format strings or printf-style functions, the "d" specifier indicates that the corresponding argument should be formatted as a signed decimal integer. It allows for the representation of both positive and negative whole numbers, including zero.

For example, in C programming, the printf function can be used with the "%d" format specifier to display a signed decimal integer value. Similarly, in other languages such as Python, the "{:d}" format specifier can be used with the format() function or string interpolation to represent a signed decimal integer.

Using the "d" specifier ensures that the output is formatted as a base-10 representation of a signed integer, taking into account the sign of the number.

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Answer:

1025

Step-by-step explanation:

Answer:

1900 190×10 =1900 (half of 20 because every 2 hours) rate per hour is 95 half of 190.

The general solution of the following first-order differential equation for \(y(x) : \frac{dy}{dx}-\frac{y}{x}=x^{2}\)  is  \(x^{3}+cx\).

We have to find the general solution of the given first order differential equation.

Let y = u*v, where u and v are functions of x.

Hence,

dy/dx = u*dv/dx + v*du/dx

Putting this in the given equation, we get,

\(u\frac{dv}{dx}+v\frac{du}{dx}-\frac{uv}{x}=x^{2}\\\\ u\frac{dv}{dx}+v(\frac{du}{dx}-\frac{u}{x} )=x^{2}\\\)

Putting the v term as 0, we get

du/dx - u/x = 0

du/dx = u/x

du/u = dx/x

Integrating both sides, we get

\(\int {\frac{1}{u} } } \, du=\int {\frac{1}{x} } \, dx\\\\\)

ln(u) = ln(x) + p

Let p = ln(k)

Hence,

ln(u) = ln(x) + ln(k)

ln(u) = ln(kx)

u = kx

Putting u = kx in the differential equation with v term 0 , we get

\((kx)\frac{dv}{dx} =x^{2}\\\\(k)dv=\frac{x^{2}dx}{x} \\\\(k)dv=(x)dx\\\\ \int {k} \, dv=\int {x}dx\\\\kv = x^{2}+c\\\\v=\frac{x^{2}+c}{k}\)

Putting v in y = uv, we get

\(y=kx*(\frac{x^{2}+c}{k} )\\\\y=x(x^{2}+c)\\\\y=x^{3}+cx\)

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The simplified form of the expression 2x^2 - 3x - 2 remains as 2x^2 - 3x - 2.

To simplify the expression 8x - 2x - x^2, we can combine like terms by adding or subtracting coefficients.

8x - 2x - x^2

First, let's combine the x terms:

(8x - 2x) - x^2

This simplifies to:

6x - x^2

Therefore, the simplified form of the expression 8x - 2x - x^2 is 6x - x^2.

Now, let's simplify the expression 2x^2 - 3x - 2:

The expression is already in simplified form, and no further simplification is possible.

Therefore, the simplified form of the expression 2x^2 - 3x - 2 remains as 2x^2 - 3x - 2.

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Answer:

75 miles

Step-by-step explanation:

2x3=6

so you multiply 25x3 which will give you 75

Answer:

Elimination

Step-by-step explanation:

Elimination is a process which involves complete removal of one of the variables in a given equation, so as to first determine the value of the other variable.

For example in solving a simultaneous equation, applying the elimination method is easily understood, straight forward and simple to use. Once the logic behind the process is well understood and followed, errors can easily be avoided.

Therefore my favorite way of solving an equation would be by applying the elimination method because it is easy and direct to apply.

Answer:

1. 5 liters

2. 1,000 kilometers

3. 12 hours

4.Divide the numbers by two or multiple by 0.5

5. 200 kilometers

6. 1 liter of milk

7. 2.4 hours or 2 hours and 15 minutes

8. Multiple the number by 0.1

Hope this helps :)

Step-by-step explanation:

Answer:

30%

Step-by-step explanation:

Since its 10 marbles we can just add 1 zero to each number

5 marbles = 50%

3= 30%

2= 20%

Answer:

Step-by-step explanation:

P=3/5 ×1/6=1/10

Answer:

6 4/9

Step-by-step explanation:

Answer:

6 4/9

Step-by-step explanation:

i hope this help have a nice day

a) The revenue function, R(x)The revenue function is the amount of money that a company receives as payment from its customers.

In this problem, R(x) is the product of the price per pound and the number of pounds sold. The price per pound is $7. Thus, the revenue function is given by;R(x) = 7xwhere x is the number of pounds of the blend produced and sold.b) The profit function, P(x)The profit function is the difference between the revenue and cost functions.

Thus, the profit function is given by;P(x) = R(x) - C(x)where C(x) = 160 + 3xTherefore,P(x) = R(x) - C(x) = 7x - (160 + 3x) = 4x - 160c) The break-even quantity in poundsThe break-even quantity is the quantity where the revenue equals the cost. This means that;R(x) = C(x)Solving for x gives;7x = 160 + 3xSimplifying and solving for x gives;x = 40Therefore, the break-even quantity in pounds is 40.d) The revenue at the break-even quantityThe revenue at the break-even quantity is R(40) = 7(40) = $280e) The quantity that results in an average profit of $2.40The average profit is profit per pound. Therefore;Average profit per pound = Profit/QuantityThe profit function is P(x) = 4x - 160, therefore, the profit per pound is given by;Profit per pound = (4x - 160)/x = 4 - 160/xTo find the quantity that results in an average profit of $2.40, we solve the equation;4 - 160/x = 2.4Solving for x gives;x = 66.67 (rounded to two decimal places)Therefore, the quantity that results in an average profit of $2.40 is 66.67 pounds.

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(a) The solutions to the equation cos(θ) = -1/2, with 0° ≤ θ ≤ 360°, are θ = 120° and θ = 240°.

(b) The solutions to the equation tan(θ) = -1, with 0° ≤ θ ≤ 360°, is θ = 135°.

(c) The solutions to the equation √2sin(θ) + 1 = 0, with 0° ≤ θ ≤ 360°, is θ = 315°.

(a) To solve cos(θ) = -1/2, we can look for angles where the cosine function is equal to -1/2. These angles occur at 120° and 240° in the interval [0°, 360°].

(b) To solve tan(θ) = -1, we can look for angles where the tangent function is equal to -1. The angle 45° satisfies this condition, and since the tangent function has a period of 180°, we can add 180° to find another solution at 45° + 180° = 225°. Both angles lie in the interval [0°, 360°].

(c) To solve √2sin(θ) + 1 = 0, we can isolate the sine term. Subtracting 1 from both sides gives √2sin(θ) = -1. Dividing both sides by √2 gives sin(θ) = -1/√2. The angle that satisfies this condition is 315°, and it lies in the interval [0°, 360°].

To sketch a diagram for each part, you can plot the unit circle and mark the angles mentioned above. Label the corresponding trigonometric function values on the unit circle for clarity. This visual representation will provide a clearer understanding of the solutions within the given interval.

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Answer:

Line GH or Line HG

Step-by-step explanation:

Hope it help !!

Answer:

Step-by-step explanation:

a point to a point which makes a straight line is called a line segment

The  McCandless method has four steps divide the stage, assign lights, use color and fill the empty spaces.

Setting up the McCandless method for a thrust stage involves several steps.

To light a thrust stage using the McCandless method, divide the space into separately illuminated sections as the first step. The size of the stage will determine how you do it, but there should be enough areas for uniform lighting throughout.

Assign lights to each part of your stage once you've divided it into lighting segments. Three lights per section is the traditional norm, although you should use as many or as few as necessary to provide a consistent effect.

Use color: After placing your lights in each region, you may use gels to balance out their hues. To balance out the shadows on the performers' faces, the McCandless technique recommends a mix of warm and cold hues.

Fill in the blanks: At this stage, your lighting setup should be clear enough for you to understand how it affects your actors and see any potential issues. Use smaller lights, such as Fresnels, to tone down any unnaturally lit areas and blend the performers' looks.

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The process of McCandless method is explained below.

According to the theory of "Into the Wild", the process of McCandless method calls for a combination of warm and cool colors to balance out the shadows on the actors' faces.

And here we know that for a double McCandless system, then you can achieve this by making two of the lights warm and the other two cool.

Here you can also have all your lights be similar, neutral colors.

Apart from this, we have the following steps to do it:

We have to choose the right type of visualization.

And then we have to declutter your visualization.

And then we have to focus your audience's attention.

And the final steps is to think Like a Designer.

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Determining the number of electrons on a charged object requires information about the charge magnitude, the charge of an electron (1.602 x 10^-19 Coulombs), and any other relevant details about the system.

To calculate the charge on the pith balls for each rod/soft material combination and determine the number of electrons residing on each pith ball, we need additional information about the specific conditions and measurements.

The charge on an object can be calculated using Coulomb's law, which depends on factors such as the distance between the objects, the nature of the materials involved, and the applied voltage or potential difference.

Similarly, determining the number of electrons on a charged object requires information about the charge magnitude, the charge of an electron (1.602 x 10^-19 Coulombs), and any other relevant details about the system.

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Answer:

B

Step-by-step explanation:

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The number of inches of a segment is 1.06 inches if a segment is 2.7 centimeters long.

In geometry, a line segment is a portion of a straight line that is bounded by two distinct end points and includes all of the points on the line that fall inside those endpoints. A line segment's length is determined by the Euclidean distance between its endpoints.

In geometry, a line segment is a portion of a straight line that is bounded by two distinct end points and includes all of the points on the line that fall inside those endpoints. A line segment's length is determined by the Euclidean distance between its endpoints.

Given,

In 1 inch there are about 2.54centimeters

And the segment is 2.7 centimeters long

The number of inches=?

2.7/2.54=1.0629

When it is rounded to the nearest 100, we get

1.06 inches.

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The sum of 8th and 10th terms will be 18.

Given information is that the sum of 4th and 14th terms of an arithmetic sequence is 18.
Let the common difference be d and let the first term be a1.
The 4th term can be represented as a1 + 3d and the 14th term can be represented as a1 + 13d.
The sum of 4th and 14th terms is given by (a1 + 3d) + (a1 + 13d) = 2a1 + 16d = 18
It means 2a1 + 16d = 18.
Now, we have to find the sum of 8th and 10th terms, which means we need to find a1 + 7d + a1 + 9d = 2a1 + 16d, which is the same as the sum of 4th and 14th terms of an arithmetic sequence.

Therefore, the sum of 8th and 10th terms will be 18.

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Answer: The first option

Step-by-step explanation: Once you multiply all the denominators to make them the same, the numerators (in the original order they are given in) become 63, 16, and 44.

16<44<63, which is the first option.

The balance after 8 years with continuous compounding is $2,101.50.

A method of computing interest known as continuous compounding involves continuously adding interest to the principal sum. The resulting balance then accrues interest in the same way. In other words, the interest is "continuously" added to the account balance rather than compounding it on a regular basis (such as annually, semi-annually, quarterly, or monthly).

The formula for continuous compounding is B = P*e^(rt), where B is the balance, P is the principal, r is the annual interest rate as a decimal, t is the time period in years, and e is the mathematical constant approximately equal to 2.71828.

The formula for calculating the balance, B, after t years with continuous compounding at an annual interest rate of r, given an initial deposit or principal, P, is:

B = P*e^(rt)

where e is the mathematical constant approximately equal to 2.71828.

In this case, the initial deposit is P = $1250, the annual interest rate is r = 0.065, and the time period is t = 8 years.

Plugging in these values, we get:

B = 1250e^(0.0658) = 1250e^0.52 = 12501.6812 = $2,101.50

Therefore, the balance after 8 years with continuous compounding is $2,101.50.

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