Find y as a function of t if 5y^n+30y=0,
y(0) = 7 y’(0) = 5
y(t) =
Answers
The differential equation is \(5y^n+30y=0\). The initial conditions are y(0) = 7 and y’(0) = 5.
The differential equation is:\(5y^n+30y=0\). First, we solve for n which is the exponent of y.
We get:n = -1When n = -1, the differential equation becomes:5(1/y)+30y=0
Rearranging terms, we get:5(1/y) = -30y
Dividing both sides by 5y, we have:-1/y² = -6
This yields: y(t) = \(\sqrt{6}\)/t The initial conditions are:y(0) = 7 and y’(0) = 5
We can now apply the first initial condition to find the value of C_1.C_1 = 7/ \(\sqrt{6}\)
When we apply the second initial condition to solve for C_2, we get: C_2 = 5 \(\sqrt{6}\)
Now, we can write the final answer: y(t) = 7cos(t \(\sqrt{6}\)) + 5 \sqrt{6}sin(t \(\sqrt{6}\))
Thus, the function of y as a function of t is y(t) = 7cos(t \(\sqrt{6}\)) + 5 \sqrt{6}sin(t \(\sqrt{6}\)) which is generated by the differential equation \(5y^n+30y=0\) and initial conditions y(0) = 7 and y’(0) = 5.
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Related Questions
What is the value of m?
Answers
Answer and Step-by-step explanation:
We need to solve for m, and we do that by adding together the measure of angles SWT and TWV, and then equal them to 90.
36 + 6m + 6 = 90
Add 36 to 6.
42 + 6m = 90
Now, subtract 42 from both sides.
6m = 48
Now, divide each side by 6 to get m.
m = 8
So, we get the value of m to be 8.
#teamtrees #PAW (Plant And Water)
Look at the angle shown. Which measure is closest to the measure of the angle? A) 140° B) 90° C)40° D) 15°
Answers
Answer:
can you provide a picture?
Step-by-step explanation:
if it dorms an L it's C, is it's almost a straight horizontal line it's A
PLEASE HELP WILL GIVE BRAINLIEST SIMPLIFY THE FOLLOWING EXPRESSION I NEED BOTH
Answers
Answer:
First one- 1/5^2
Second- 2/3m^15
Step-by-step explanation:
Question 31 A professor scaled curved) the scores on an exam by multiplying the student's ow score by 12 the adding 15 points of the mean and standard deviation of the scores before true worstandsche the mean and standard deviation of the scaled scores are respectively 278 2 and 6 702 and 21 o cannot be determined without knowing the scores are normal debuted d. 78.2 and 5 61 and 6 Dusio 31 Question 31 A professor scaled (curved) the scores on an exam by multiplying the student's raw score by 1.2, then adding 15 points. If the mean and stand the mean and standard deviation of the scaled scores are respectively: a. 76.2 and 6 b. 76.2 and 21 c, cannot be determined without knowing if the scores are normally distributed d. 76.2 and 5 e. 61 and 6 1 points Save Answer ing the student's raw score by 1.2, then adding 15 points. If the mean and standard deviation of the scores before the curve were 51 and 5, respectively, then rectively: normally distributed
Answers
The mean and standard deviation of the scaled scores are 76.2 and 6 respectively. The correct option is A.
To find the mean and standard deviation of the scaled scores, we can use the following formulas:
Mean of Scaled Scores = (Mean of Raw Scores × Scaling Factor) + ConstantStandard Deviation of Scaled Scores = Standard Deviation of Raw Scores × Scaling FactorGiven that the mean and standard deviation of the raw scores are 51 and 5 respectively, the scaling factor is 1.2, and the constant is 15, we can calculate the mean and standard deviation of the scaled scores:
Mean of Scaled Scores = (51 × 1.2) + 15 = 61.2 + 15 = 76.2Standard Deviation of Scaled Scores = 5 × 1.2 = 6Thus, the mean and standard deviation of the scaled scores are 76.2 and 6 respectively. So the answer is option a. 76.2 and 6.
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Q.4 Find the area and perimeter of a square of side 85/4
Answers
• Side of the square = 85/4 m.
To find :• Area of the square
• perimeter of the square .
Solution :As we know that :
• Area of square = (side)²
=> Area of square = (85/4)²
=> Area of square = 7225/16
=> Area of square = 451.5 m².
Now ,
• Perimeter of square = 4 (side)
=> Perimeter of square = 4(85/4)
=> perimeter of square = 85 m.
HENCE, THE AREA IS 451.5M² AND PERIMETER IS 85M.
I hope it will help you.
Regards.
Represent the following sentence as an algebraic expression, where "a number" is the letter x. \text{the product of 5 and a number.} the product of 5 and a number.
Answers
The algebraic formula for "the product of 5 and a number" is represented as 5x.
An algebraic expression?
The mathematical operations (+, -, *, and /) are used to separate terms in an algebraic statement.
A term is made up of variables raised to integral powers and a combination of numbers.
How do you answer this?
Write the algebraic expression that corresponds to the phrase "the product of 5 and a number" as it appears in the question.
assuming that the quantity is x.
First, we attempt to create the terms.
The expression that results from adding the letters five to a number is five times five, or five times five is 5x.
Consequently, the algebraic expression for "the product of 5 and x " as 5x.
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help if you can asap pls!!!!!
Answers
The reason number 3 include the following: D. Definition of midpoint.
What is a midpoint?In Mathematics and Geometry, a midpoint is a point that lies exactly at the middle of two other end points that are located on a straight line segment.
In this context, we can prove that line segment AC is congruent to line segment BC by completing the two-column proof shown above with the following reasons from step 1 to step 3:
Statements Reasons
1. M is the midpoint of AB Given
2. AB ⊥CM Given
3. AM ≅ BM Definition of midpoint
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find the tangent of angle A (giving brainliest and thanks to all!)
Answers
Answer:
Option B, 8 / 6
Step-by-step explanation:
Tangent = Opposite / Adjacent
Tangent of ∠A = Opposite / Adjacent
Tan(A) = 8 / 6 which is the same as Option B
Hope this helps!
Solve 4.62 + (−12.3).
56.83
5.85
−7.68
−16.92
Answers
The sum of the given decimal numbers is -7.68
Sum of decimal numbersDecimal numbers are numbers that contains decimal points. Given the expression below;
4.62 + (−12.3).
Convert to fraction to have:
4.62 + (−12.3) = 462/100 - 123/10
Find the LCM
4.62 + (−12.3) = 462-1230/100
4.62 + (−12.3) = -768/100
4.62 + (−12.3) =-7.68
Hence the sum of the given decimal numbers is -7.68
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if an unknown compound has a moderately intense, wide peak in the 3200-3400 cm–1 region, what functional group is likely present?
Answers
A moderately intense, wide peak in the 3200-3400 cm⁻¹ region is indicative of the presence of hydroxyl (-OH) functional groups.
Identification of Hydroxyl Functional Groups Using Infrared Spectroscopy
One specific region of the infrared spectrum that can provide valuable information is the 3200-3400 cm⁻¹ region. If an unknown compound displays a moderately intense, wide peak in this region, it is highly likely that it contains a hydroxyl (-OH) functional group.
Infrared spectroscopy is a powerful tool in the identification of functional groups in unknown compounds.
The presence of hydroxyl groups can be further confirmed by looking for other characteristic peaks in the IR spectrum, such as a broad peak in the 1600-1700 cm⁻¹ region for the bending vibrations of the -OH bond. Overall, infrared spectroscopy can be an effective method for identifying hydroxyl functional groups in unknown compounds.
Infrared spectroscopy is a powerful tool in the identification of functional groups in unknown compounds. This is because the stretching vibration of the -OH bond falls in the range of 3200-3400 cm⁻¹ and the hydroxyl group is characterized by a broad, intense peak due to the high density of vibrational modes.
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. If Ya/n and Y2/n are the respective independent relative frequencies of success associated with the two binomial distributions b(n, P1) and b(n, P2), compute n such that the approximate probability that the random
interval (Y1/n - Y2/n) ‡ 0.05 covers pi - p2 is at least 0.80. HINT: Take p* = P° = 1/2 to provide an upper bound
for n.
Answers
we would need a sample size of at least 502 for the approximate probability of the random interval (Y1/n - Y2/n) ‡ 0.05 covering pi - p2 to be at least 0.80.
To compute n, we can use the formula:
n = ((zα/2)^2 * 2p*(1-p*)) / (ε^2)
Where zα/2 is the z-score associated with a confidence level of 1-α, p* is the probability of success for a binomial distribution, and ε is the margin of error.
Since we are given that the approximate probability of the random interval (Y1/n - Y2/n) ‡ 0.05 covering pi - p2 is at least 0.80, we can set α = 0.20 to find the corresponding z-score of 1.28.
Using p* = 1/2 as an upper bound for both P1 and P2, we can calculate the margin of error as:
ε = zα/2 * sqrt((p*(1-p*)) / n)
Plugging in the values, we get:
0.05 = 1.28 * sqrt((0.25) / n)
Solving for n, we get:
n = 501.76
Therefore, we would need a sample size of at least 502 for the approximate probability of the random interval (Y1/n - Y2/n) ‡ 0.05 covering pi - p2 to be at least 0.80.
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The number of adult tickets sold for a play is 8 more than 3 times the number of child tickets sold. In total, 96 tickets were sold to the play. Determine the number of adult tickets sold in the number of child tickets sold
Answers
Then 3x + 8 is the number of adult tickets
x + 3x + 8 = 96
4x = 88 - add the x’s and subtract 8 from both sides
x = 22 - divide both sides by 4
22 children’s tickets
3(22) +8 = 74 adult tickets
Check 22 + 74 = 96
hi, i know this is basic math and stuff but I still need some help
Answers
Answer:
the answer is :
20 for the first figure
12 for the second figure
30 for the last figure
Answers:
Perimeter = 22 cmPerimeter = 22 cmPerimeter = 30 cm==============================================
Explanation:
The perimeter is the total distance around the outer edge of the figure. It's the total amount of fence you need to enclose the region.
So we simply add up all the side lengths. Refer to the diagram to see any missing sides that aren't labeled (shown in blue).
For instance, the perimeter for problem 1 is 5+2+2.5+4+2.5+6 = 22 cm. Problems 2 and 3 are handled the same way.
It's not a typo that the perimeters of problems 1 and 2 are the same value. This is because both figures can be surrounded by a rectangle that is 6 cm across and 5 cm tall. The perimeter of the surrounding rectangle is exactly the same as the perimeter of the inner fenced region. We're effectively just moving fence around but not changing the perimeter.
geraldo has a gold chain that is 34 inches long.he cuts it into 2 1/8 - inch-long chains.how many gold chains does geraldo have now
Answers
The number of gold chains that Geraldo will have is 16 gold chains.
What is a fraction?A fraction is simply a piece of a whole. The number is represented mathematically as a quotient where the numerator and denominator are split. In a simple fraction, the numerator as well as the denominator are both integers.
Since Geraldo has a gold chain that is 34 inches long and he cuts it into 2 1/8 - inch-long chains.
The number of chains will be:
= 34 ÷ 2 1/8
= 34 / 2.125
= 16
He'll have 16 chains.
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The best unit of measure for the liquid in family-sized container of orange juice is the liter.
A. True
B. False
Answers
Answer:T
Step-by-step explanation:
Answer:
the answer is A.
I did this.
Step-by-step explanation:
50 points!!!
7. Write and solve an inequality for the value of x.
Answers
The value of x must be between -18 and -6. The solution has been obtained using Triangle inequality theorem.
What is Triangle inequality theorem?
The triangle inequality theorem explains how a triangle's three sides interact with one another. This theorem states that the sum of the lengths of any triangle's two sides is always greater than the length of the triangle's third side. In other words, the shortest distance between any two different points is always a straight line, according to this theorem.
We are given three sides of a triangle as 8, 6 and x+20
Using Triangle inequality theorem,
⇒8+6 > x+20
⇒14 > x+20
⇒-6 > x
Also,
⇒x+20+6 > 8
⇒x+26 > 8
⇒x > -18
Also,
⇒x+20+8 > 6
⇒x+28 > 6
⇒x > -22
From the above explanation it can be concluded that x is less than -6 but greater than -22 and -18.
This means that x must lie between -18 and -6.
Hence, the value of x must be between -18 and -6.
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(a) Find a nonzero vector orthogonal to the plane through the points P, Q, and R, and (b) find the area of triangle PQR.P(1, 0, 1), Q(-2, 1, 3), R(4, 2, 5)
Answers
The vector orthogonal to the plane through the points P, Q, and R is (8, -8, 12), and the area of triangle PQR is \($\sqrt{301}$\).
For part (a), we can find a nonzero vector orthogonal to the plane through the points P, Q, and R by constructing a normal vector to the plane using the cross product of two vectors in the plane. The two vectors in the plane are \($\vec{PQ} = (1- (-2), 0-1, 1-3) = (3, -1, -2)$\) and \($\vec{PR} = (1-4, 0-2, 1-5) = (-3, -2, -4)$\). Taking the cross product of the two vectors gives us the normal vector to the plane, \($\vec{n} = \vec{PQ} \times \vec{PR} = (8, -8, 12)$\). Therefore, the vector orthogonal to the plane is \($\vec{n} = (8, -8, 12)$.\)
For part (b), the area of triangle PQR can be found using the formula for Heron's Formula, which states that the area of a triangle with sides a, b,and c is given by
\($A = \sqrt{s(s-a)(s-b)(s-c)}$\)
where \($s = \frac{a+b+c}{2}$\) . In this case, the sides are \($a = \|\vec{PQ}\| = \sqrt{3^2 + (-1)^2 + (-2)^2} = \sqrt{14}$, $b = \|\vec{QR}\| = \sqrt{(-2-4)^2 + (1-2)^2 + (3-5)^2} = \sqrt{14}$\), and\($c = \|\vec{PR}\| = \sqrt{(-3)^2 + (-2)^2 + (-4)^2} = \sqrt{29}$\). Plugging these values into the formula, we get
\(= \sqrt{s(s-a)(s-b)(s-c)} = \sqrt{\frac{7(7-\sqrt{14})(7-\sqrt{14})(7-\sqrt{29})}{4}} = \sqrt{7(7-\sqrt{14})^2(7-\sqrt{29})} = \sqrt{7(7-\sqrt{14})^2(\sqrt{14}+\sqrt{29})} = \sqrt{7(7-\sqrt{14})^2\sqrt{43}} = \sqrt{301}$\)Therefore, the area of triangle PQR is \($\sqrt{301}$\)
The vector orthogonal to the plane through the points P, Q, and R is (8, -8, 12), and the area of triangle PQR is \($\sqrt{301}$\).
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Fill in the blank. When a data value is converted to a standardized scale representing the number of standard deviations the data value lies from the mean, we call the new value a _____ . When a data value is converted to a standardized scale representing the number of standard deviations the data value lies from the mean, we call the new value a ____.
Answers
When a data value is converted to a standardized scale representing the number of standard deviations the data value lies from the mean, we call the new value a Z-Score.
In statistics, each mathematical formula and each element has an internationally recognised name. This is to ensure that everyone in the world understands what every researcher has to say in every letter. A statistic that tells the number of standard deviations a data value is above or below the mean is called a z-score. And its formula is, Z = (X − μ)/σ
where, μ--> population mean,
σ --> population standard deviation and
x --> the raw-score.
Hence, when a data value is converted to a standardized scale, new value, Z-Score is representing the number of standard deviations the data value lies from the mean.
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Which values are solutions to the inequality below? Check all that apply.
√x <10
A. 100
B. 25
C. -100
D. 105
E. 36
F. 9
Answers
Answer:
The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²vvvThe diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²v
Step-by-step explanation:
its E and A
Answer:
The solutions to the inequality are B, E, and F: 25, 36, and 9.
Step-by-step explanation:
The solutions to the inequality √x < 10 are the values of x that make the inequality true when plugged in. To find these values, we can square both sides of the inequality:
√x < 10
x < 10^2 = 100
So, the values of x that make the inequality true are those that are less than 100. The options that satisfy this condition are:
A. 100 (not a solution)
B. 25 (solution)
C. -100 (not a solution)
D. 105 (not a solution)
E. 36 (solution)
F. 9 (solution)
the functions f and g are such that f(x)= x/(x+5) and g(x)=2x+1. Find fg(x)
Answers
Answer:
Evaluate g(f (x)) g ( f ( x)) by substituting in the value of f f into g g. Combine the opposite terms in (x− 2)+2 ( x - 2) + 2
Step-by-step explanation:
if that helps
the following data were collected from a simple random sample from an infinite population. 13 15 14 16 12 the mean of the population .
Answers
The mean of the population can be estimated using the sample mean, which is the average of the data collected from a simple random sample. In this case, the sample data consists of the numbers 13, 15, 14, 16, and 12.
To find the sample mean, we add up all the values in the sample and divide it by the total number of values. In this case, the sum of the sample values is 13 + 15 + 14 + 16 + 12 = 70. Since there are 5 values in the sample, the sample mean is calculated as 70 / 5 = 14.
The sample mean is an estimate of the population mean. It provides information about the central tendency of the population based on the collected sample. In this case, the sample mean of 14 is an estimate of the mean of the entire population from which the sample was taken.
It's important to note that the sample mean may not be exactly equal to the population mean, but it provides a good estimate when the sample is representative of the population and selected through a random sampling method.
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CAN ANYONE HELP ME IN DIS RQ!!!
Answers
Answer:
Hey!
Your answer is C!
Step-by-step explanation:
1. You must divide, 650/10. This is equal to 65.
2. Subtract 65 from 650. You will end up with 585.
To represent the amount that is left would be 9/10...
Now just put the 2 together to form...
\((\frac{9}{10} )\) b, $585
I HOPE THIS HELPED YOU! :PUse the discriminant to describe the roots of each equation. Then select the best description.
3x^2 - 2 + 7x =0
Answer options:
•double root
•imaginary root
•real and irrational root
•real and rational root
Answers
The quadratic equation 3 · x² + 7 · x - 2 = 0 has a positive discriminant. Thus, the expression has two distinct real roots (real and irrational roots).
How to determine the characteristics of the roots of a quadratic equation by discriminant
Herein we have a quadratic equation of the form a · x² + b · x + c = 0, whose discriminant is:
d = b² - 4 · a · c (1)
There are three possibilities:
d < 0 - conjugated complex roots.d = 0 - equal real roots (real and rational root).d > 0 - different real roots (real and irrational root).If we know that a = 3, b = 7 and c = - 2, then the discriminant is:
d = 7² - 4 · (3) · (- 2)
d = 49 + 24
d = 73
The quadratic equation 3 · x² + 7 · x - 2 = 0 has a positive discriminant. Thus, the expression has two distinct real roots (real and irrational roots).
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need help pleaseeeeeeeeeeeeeeeeeee
Answers
Quadrilateral ABCD is the result of a reflection of quadrilateral EFGH over the line
Which lime segment in the image corresponds to BC in the pre-image
EF
HE
GH
FG
Answers
Answer:
FG
Step-by-step explanation:
Answer:
fg
Step-by-step explanation:
(adapted from Ross, 2.31) Three countries (the Land of Fire, the Land of Wind, and the Land of Earth) each make a 3 person team. Each team consists of three ninjas, each of a different rank: one genin junior ninja, one journeyman ninja, and one elite ninja.
(a) If a ninja is chosen at random from each of the three different countries, what is the probability of selecting a complete team? (A complete team here is a group consisting of three ninjas, each ninja of a different rank).
(b) If a ninja is chosen at random from each of the three different countries, what is the probability that all 3 ninjas selected have the same rank?
Answers
Answer:
The answer is "\(\frac{2}{9} \ and \ \frac{1}{9}\)"
Step-by-step explanation:
In point a:
The requires 1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.
They can now pick 1 genin from a certain matter of national with the value:
\(\frac{1}{\binom{3}{1}}=\frac{1}{3} .\)
They can pick 1 Chunin form of the matter of national with the value:
\(\frac{1}{\binom{3}{1}}=\frac{1}{3} .\)
They have the option to pick 1 join from of the country team with such a probability: \(\frac{1}{\binom{3}{1}}=\frac{1}{3}\)
And we can make the country teams: \(3! = 6\) different forms. Its chances of choosing a team full in the process described also are:
\(6 \times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{2}{9}.\)
In point b:
In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).
Its likelihood that even a specific nation team ninja would be chosen is now: \(\frac{1}{\binom{3}{1}}=\frac{1}{3}\)
Its odds of choosing the same rank ninja in such a different country team are: \(\frac{1}{\binom{3}{1}}=\frac{1}{3}\)
The likelihood of choosing the same level Ninja from the residual matter of national is: \(\frac{1}{\binom{3}{1}}=\frac{1}{3}\) Therefore, all 3 selected ninjas are likely the same grade: \(3\times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{1}{9}\)
Answer: ITS 2 WEEKS AGO IT DOSE T MATTER IF IM RIGHT OR NOT HEHHEHEJSSHAGAGAHAHHAHAA
Step-by-step explanation:
How can I solve this:
Simplify
Answers
Answer:
see the attachment photo!
Answer:
the answer is 7! hope this helps
Step-by-step explanation:
You are shopping for single-use cameras to hand out at a party. The daylight cameras cost $2.75 and the flash cameras cost$4.25. You must buy exactly 20 cameras and you want to spend between $65 and$75, inclusive. Write and solve a compound inequality for this situation. Then list all the solutions that involve whole numbers of cameras.
Answers
The compound inequality for the given situation is $2.75x + $4.25y ≥ $65 and $2.75x + $4.25y ≤ $75, where x represents the number of daylight cameras and y represents the number of flash cameras.
To solve this compound inequality, we need to find the values of x and y that satisfy both conditions. The inequality $2.75x + $4.25y ≥ $65 represents the lower bound, ensuring that the total cost of the cameras is at least $65. The inequality $2.75x + $4.25y ≤ $75 represents the upper bound, making sure that the total cost does not exceed $75.
To list the solutions involving whole numbers of cameras, we need to consider integer values for x and y. We can start by finding the values of x and y that satisfy the lower bound inequality and then check if they also satisfy the upper bound inequality. By trying different combinations, we can determine the possible solutions that meet these criteria.
After solving the compound inequality, we find that the solutions involving whole numbers of cameras are as follows:
(x, y) = (10, 10), (11, 8), (12, 6), (13, 4), (14, 2), (15, 0), (16, 0), (17, 0), (18, 0), (19, 0), (20, 0).
These solutions represent the combinations of daylight and flash cameras that fulfill the requirements of buying exactly 20 cameras and spending between $65 and $75.
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Is (8,2) a solution to the system of equations
x-y=6
2x-10y=4
Answers
16 - 20 = -4!
The work that Ryan did to find the greatest common factor of 48 and 72 is shown below.
Prime factorization of 48: 2 x 2 x 2 x 2 x 3
Prime factorization of 72: 2 x 2 x 2 x 3 x 3
The greatest common factor is 2 ´ 2 ´ 2 ´ 3 x 3
What is Ryan’s error?
Answers
Answer:
there will only be one 3
Step-by-step explanation:
see cause the first 3 of both numbers are 2 but only the last one of both numbers are 3 .