First, describe a strategy to find out which items are heavier than others. See how many ants it takes to lift each object (using any length).

Wavelength of radiation must be used to eject electrons with a velocity of 2300 km/s is 63.9nm.

Einstein's equation for the photoelectric effect

hv = A + W

Where,

Energy of photon : E = hvx = hxc/λ

The work function for chromium is A

Planck's constant h= 6.626X 10⁻³⁴ Js

speed of light c = 2.998X10⁸ m/s

Velocity of 2300 km/s = 2300 X 10⁶ m/s

The kinetic energy of emitted electron

W = mv²/2 = (9.10939 X 10⁻³¹ kg X (2300X10⁶ m/s)²)/2 = 2.409X10⁻¹⁸

Hence,

    λ = ch/A+W

λ = (6.626X10⁻³⁴JsX2.998X10⁸m/s)/(7X10⁻¹⁹J + 2.409X10⁻¹⁸J)

  = 19.865X10²⁶Jm/3.109X10⁻¹⁸J = 6.39X10⁻⁸= 63.9 nm

Wavelength of radiation must be used to eject electrons with a velocity of 2300 km/s is 63.9nm

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I understand that the question you are looking for is "The work function for chromium metal is 7.0 x 10-19 J (4.37 eV). What wavelength of radiation must be used to eject electrons with a velocity of 2300 km/s?"

The person's complete trip was a 6km round trip because they traveled 3km north and then 3km south, returning to their original location.

A trip is a journey or excursion to some destination, usually for a specific purpose. It can be as short as a day trip or as long as a round-the-world adventure. A trip typically involves travel by foot, car, railroad, boat, or airplane and often involves multiple destinations. It may also involve activities such as camping, hiking, sightseeing, and other leisure activities. Travelers usually plan trips in advance to ensure they have enough time to see and do the things they want to. Trips can also be spontaneous, with travelers deciding on the fly where to go and what to do.

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Answer:

10 m

Explanation:

PE = mgh

m = 50kg

g= 9.8 m/s^2

h=?

so,

4900= 50×9.8× h

50h = 4900/9.8

50h = 500

h = 10 m

The light travels through water and gets reflected off on the glass surface into the water. There had been a 180° phase change between the incident and the reflected wave. This is called Total internal reflection (TIR).

In total internal reflection, in physics, a ray of light in a medium such as water or glass is completely reflected back into the medium from the surrounding surfaces. This phenomenon occurs when the angle of incidence is greater than a certain critical angle called the critical angle.

TIR only occurs when both of the following two conditions are met

Thus, the phases which include the TIR are the incident and the reflected phase and the incident light hits the surface while the reflected light reflects back.

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Answer:

The distance travelled in the next 5 seconds is 20 m.

Explanation:

The distance travelled is given by the formula,

\(s=ut+\frac{1}{2} at^{2}\)

Where,

u is the initial velocity in m/s

t is the time in s

a is the acceleration in \(m/s^{2}\)

As per the given data,

u= 9 m/s

t= 5 s

a= -2 \(m/s^{2}\) (The negative sign indicates the deceleration)

Substituting the values,

\(s=(9) * (5) +\frac{1}{2} (-2) (5)^{2}\)

=45-25

=20

So, a runner travels 20 m in the next 5 seconds.

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Answer:

For an object resting upon a non-accelerating surface, the normal force is equal to the ... Suppose that a person weighs 800 N and sits at rest upon a table. ... applying a downward force of 200 N. With the additional downward force of 200 N acting upon the person, the total upward force must be 1000 N.

Explanation:

The function \(h(x) = x^4 - 20x^3 - 144x^2\) is concave up on the intervals (-∞, -4) and (5, ∞), and concave down on the interval (-4, 5).

To determine the intervals where ℎ(x) is concave up or concave down, we need to find the second derivative of the function. Let's start by finding the first derivative, ℎ'(x), which represents the slope of the function at any given point.

Taking the derivative of \(h(x) = x^4 - 20x^3 -144x^2\) with respect to x, we get \(h'(x) = 4x^3 - 60x^2 - 288x\).

Next, we find the second derivative, ℎ''(x), by taking the derivative of ℎ'(x). Differentiating \(h(x) = 4x^3 - 60x^2 - 288x\), we obtain \(h''(x) = 12x^2 - 120x - 288.\)

To determine the concavity of ℎ(x), we need to find the intervals where ℎ''(x) > 0 (concave up) and ℎ''(x) < 0 (concave down). Setting ℎ''(x) = 0 and solving for x, we get the critical points x = -4 and x = 5.

Now, let's analyze the intervals:

For x < -4, ℎ''(x) > 0, indicating concave up.

For -4 < x < 5, ℎ''(x) < 0, indicating concave down.

For x > 5, ℎ''(x) > 0, indicating concave up.

Therefore, the function \(h(x) = x^4 -20x^3 -144x^2\) is concave up on the intervals (-∞, -4) and (5, ∞), and concave down on the interval (-4, 5).

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The work done by the drag force from the air is negative

When a skydiver descends towards the earth with a parachute open, there are two main forces acting on the skydiver: the gravitational force pulling the skydiver towards the earth and the drag force from the air resistance acting in the opposite direction to the motion. The drag force is proportional to the velocity of the skydiver and is directed opposite to the velocity vector. As the skydiver descends, the velocity decreases, and so does the magnitude of the drag force.

The work done by a force is defined as the product of the force and the displacement of the object in the direction of the force. In the case of the drag force acting on the skydiver, the direction of the force is opposite to the direction of the displacement.

In other words, as the skydiver descends, the drag force from the air resistance does negative work on the skydiver, which means that it reduces the kinetic energy of the skydiver. This is why a skydiver gradually slows down as they approach the ground, even with an open parachute.Therefore, the work done by the drag force is negative.

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Answer: The average velocity of the car is 37.27 km/h.

Explanation:

Answer:

Solution

100 km into m/s= 55.4 m/s

59 km into m/s = 13.8m/s

Average velocity= v+u/2

=69.2/2

= 34.6

I think it's average velocity is 35.6

I think it will help

The molten steel is the or melted

Answer:

vjad zdmenrmdnbeanssshsnaaamrnrnealatkujejdshdendddddjnyejeynarnDhdndndddnN\nnddzNHNdnnkddkddzmdddhmeeenNDN

Answer:....

Explanation:.....

Answer:

Explanation:

1

2

3

The third table shown in the diagram below can be modelled with the equation, y = x + 2, therefore, it represents a linear equation.

A linear function is a function whose graph represents a straight line when the points are plotted, and also can be modelled by the equation, y = mx + b.

b is the value of y when x = 0 (y-intercept)

m is the slope or unit rate.

Thus, the third table shown in the diagram below can be modelled with the equation, y = x + 2, therefore, it represents a linear equation (see attachment). The last table has a constant slope of -3, hence it represents a linear function.

Table of functions

From the given table, we need to determine which of the table is a linear table. To determine that, we must check which of the table has a constant rate of change

Looking at the last table;

Slope = -4-(-2)/2-1

Slope = -4+1/1

Slope = -3

Since the last table has a constant slope of -3, hence it represents a linear function.

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Li độ cực đại x=A=5 cm

Chu kỳ T= \(\frac{2\pi }{4\pi }\) = 0.5s

Tần số f= 1/T = 2Hz

Pha ban đầu = -π/3

x(0) = 2.5cm

x(2)= 2.5cm

Let v be the billiard ball's initial speed. The total momentum of the ball-marble system is conserved between the times before and after their collision, so that

(1 kg) v + (0.1 kg) (0 m/s) = (1 kg) (0.3 m/s) + (0.1 kg) (3 m/s)

Solve for v :

v + 0 = 0.3 m/s + 0.3 m/s

v = 0.6 m/s

It will take approximately 10.7895 million years for Los Angeles and San Francisco to become neighboring cities, assuming they continue moving towards each other at a rate of 5.7x10-5 km/yr.

The distance between the two cities is 615 km, and they are moving towards each other at a rate of 5.7x10-5 km/yr.

To determine the time it takes for them to become neighboring, we divide the initial distance by the relative velocity: 615 km / (5.7x10-5 km/yr) ≈ 10,789,474 years.

Converting this to millions (10^7), we find that it will take approximately 10.7895 million years for Los Angeles and San Francisco to become neighboring cities at their current relative velocity.

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The objects with a speed higher v = 7668 m/s than that number are likely to go into orbit. (Y & Z)

The orbital speed of an astronomical body or object (e.g. planet, moon, artificial satellite, spacecraft, or star) is the speed at which it orbits around either the barycenter or if one object is much more massive than the other bodies in the system, its speed relative to the centre of mass of the most massive body.

The term can be used to refer to either the mean orbital speed, i.e. the average speed over an entire orbit, or its instantaneous speed at a particular point in its orbit.

Maximum (instantaneous) orbital speed occurs at periapsis (perigee, perihelion, etc.), while minimum speed for objects in closed orbits occurs at apoapsis (apogee, aphelion, etc.).

In ideal two-body systems, objects in open orbits continue to slow down forever as their distance to the barycenter increases.

g = v^2 / r

so v = square root ( r x g )

v = 7668 m/s will be the minimum speed needed to go into orbit.

Based on that, objects with a speed higher than that number are likely to go into orbit. (Y & Z)

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The long time will decrease the velocity which will equally decrease the impulse applied to your knee.

The impulse experienced by an object is the change in momentum of the object.

J = ΔP = m(v - u)

where;

v = distance / time

when time of fall becomes 3 times long, the final velocity becomes 3 times smaller

Since the velocity will be reduced, the impulse applied to your knee will decrease as well.

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Tidal volume is the volume of air inspired or expired during normal respiration. The tidal volume is typically about 500 milliliters during resting breathing, and it can increase to more than 3,000 milliliters during exercise.

The inspiratory capacity is the maximum amount of air that can be inhaled following normal expiration.Tidal volume is the volume of air that moves in and out of the lungs with each breath. It is an essential component of the pulmonary system, and it is used to measure the lung's capacity. Tidal volume can be calculated by dividing the total volume of air moved in and out of the lungs by the total number of breaths taken.

The inspiratory capacity is the volume of air that can be inspired following a normal expiration. This is the maximum amount of air that can be inhaled, and it is used to measure the lung's overall function. The inspiratory capacity is typically measured by a spirometer, which measures the volume of air moved in and out of the lungs during breathing.The figure attached shows a graph of the volume of air breathed over time. The tidal volume is represented by the width of each breath, while the inspiratory capacity is the maximum height that each breath reaches.

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The net charge on the 20 μF capacitor attached across a 1000 V power supply is 20 milliCoulombs (mC).

The net charge on a capacitor can be calculated using the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage across the capacitor. In this case, the capacitance is given as 20 μF (microfarads), and the voltage is 1000 V.

First, we need to convert the capacitance from microfarads to farads. Since 1 μF is equal to \(10^{-6\) F, the capacitance becomes \(20 * 10^{-6\) F = \(2 * 10^{-5\) F.

Now, we can substitute the values into the formula: Q = (2 × \(10^{-5\) F) × (1000 V).

Calculating this expression gives us Q = 20 × \(10^{-3\) C. Since 1 C is equal to 1000 milliCoulombs (mC), the net charge on the capacitor is 20 mC.

Therefore, when the 20 μF capacitor is attached across a 1000 V power supply the net charge on it is about 20 milliCoulombs (mC).

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The SI unit of wavelength of a wave is meters (m).

We can solve this problem using the conservation of energy principle, which states that the total mechanical energy (potential energy + kinetic energy) of a system remains constant if no external work is done on the system.

At the top of the hill, the car has only potential energy, given by:

PE = mgh

where m is the mass of the car, g is the acceleration due to gravity, and h is the height of the hill.

PE = (1000 kg) x (9.81 m/s^2) x (200 m) = 1,962,000 J

At the base of the hill, the car has only kinetic energy, given by:

KE = (1/2)mv^2

where v is the velocity of the car.

Using the conservation of energy principle, we can equate the potential energy at the top of the hill to the kinetic energy at the base of the hill:

PE = KE

mgh = (1/2)mv^2

Canceling the mass on both sides, we get:

gh = (1/2)v^2

Solving for v, we get:

v = sqrt(2gh)

Substituting the given values, we get:

v = sqrt(2 x 9.81 m/s^2 x 200 m) = 44.3 m/s

Therefore, the velocity of the car at the base of the hill is approximately 44.3 m/s.

Answer:

True

Explanation:

This Question is a little tricky, so I am unsure if this s the most logical answer.

If you'd look at a compass, 60 degrees south is moreover south then east, and the two imaginary lines are unlikely to intercept.

Answer:

They are all units of pressure

The torque required to tighten the bolt is 16.9485 Nm when using the metric unit system.

First, we need to convert the units of the given torque from pound-foot (lbf-ft) to newton-meter (Nm):

1 lbf-ft = 1 pound * 1 foot = 1 lbf * 0.3048 m (since 1 m = 3.281 ft)

= 1 lbf * 0.3048 m/ft * 4.448 N/lbf (using the conversion factor 1 lbf = 4.448 N)

= 1.3558 Nm

Therefore, 12.5 lbf-ft is equivalent to:

12.5 lbf-ft * 1.3558 Nm/lbf-ft = 16.9485 Nm (rounded to four decimal places)

So the torque required to tighten the bolt is 16.9485 Nm when using the metric unit system.

What is torque?

Torque is a measure of the force that causes an object to rotate around an axis or pivot point. It is often described as a twisting or turning force and is commonly denoted by the symbol "τ" (tau).

The magnitude of torque depends on two factors: the magnitude of the force and the distance between the force and the axis of rotation. The greater the force or the distance, the greater the torque will be. Mathematically, torque can be expressed as:

τ = r x F

The unit of torque is the newton-meter (Nm) in the metric system, which is the force of one newton applied at a distance of one meter from the axis of rotation.

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Generally, the coefficient of static friction should be at least 0.7 for a car traveling at this speed, but this value could be higher depending on the specific conditions.

The coefficient of static friction, or μs, is the ratio of the maximum static force that can be applied without causing slipping to the normal force between two surfaces. The coefficient is affected by the surfaces in contact and the material they are made of.

The tires of a car also have an effect on the coefficient of static friction. Tires with a greater tread depth can provide better grip on the road and therefore have a higher coefficient of static friction than tires with a shallow tread. Tire pressure also plays a role, as low pressure can reduce the coefficient of static friction.

The weight of the vehicle is also an important factor. Heavier vehicles tend to have a higher coefficient of static friction, as the greater mass increases the normal force between the car and the surface.

In conclusion, the coefficient of static friction for a car traveling at 115 km/h around a turn depends on several factors, including the road surface, the vehicle's tires, and the vehicle's weight.

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Answer:

Well, it's because the air offers much greater resistance to the falling motion of the feather than it does to the brick. ... Galileo discovered that objects that are more dense, or have more mass, fall at a faster rate than less dense objects, due to this air resistance. A feather and brick dropped together.

Explanation:

To react completely with 0.500 L of volume of 0.500 M Na2CO3, you would need 0.250 L of 2.00 M HCl.

Write down the balanced chemical equation for the reaction between HCl and Na2CO3:

2 HCl + Na2CO3 → 2 NaCl + H2O + CO2

Determine the stoichiometry of the reaction:

From the balanced equation, we can see that 2 moles of HCl react with 1 mole of Na2CO3.

Calculate the number of moles of Na2CO3:

Given that the volume of Na2CO3 solution is 0.500 L and the concentration is 0.500 M, we can use the formula:

Moles = Concentration × Volume

Moles of Na2CO3 = 0.500 M × 0.500 L = 0.250 moles

Use the stoichiometry to determine the number of moles of HCl needed:

According to the stoichiometry of the balanced equation, 1 mole of Na2CO3 reacts with 2 moles of HCl.

Therefore, to react with 0.250 moles of Na2CO3, we would need 2 × 0.250 = 0.500 moles of HCl.

Convert moles of HCl to volume:

Given that the concentration of HCl is 2.00 M, we can use the formula:

Volume = Moles / Concentration

Volume of HCl = 0.500 moles / 2.00 M = 0.250 L

Convert the volume to liters:

The final answer is 0.250 liters of 2.00 M HCl are needed to react completely with 0.500 L of 0.500 M Na2CO3.

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The can be obtained by using the balanced chemical equation: Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2  Write the balanced chemical equation for the reaction.

Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2

Calculate the number of moles of Na2CO3. Using the formula n = c × V, where n is the number of moles, c is the concentration, and V is the volume, we get:

n = c × V

= 0.500 M × 0.500 L

= 0.250 mol

Calculate the number of moles of HCl required.The balanced chemical equation shows that 2 moles of HCl react with 1 mole of Na2CO3. Hence, the number of moles of HCl required can be calculated as follows

:n(HCl) = 2 × n(Na2CO3)

= 2 × 0.250 mol

= 0.500 mol

Calculate the volume of 2.00 M HCl required.The number of moles of HCl required is 0.500 mol. Using the formula V = n/c, where V is the volume, n is the number of moles, and c is the concentration, we get:

V = n/c

= 0.500 mol ÷ 2.00 M

= 0.250 L

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