1. For an input code of 721 on a 10-bit DAC with a VFSR of 5V, the output voltage would be approximately 3.527V.
2. The smallest voltage increment at the output, or voltage resolution, for a 10-bit DAC with a VFSR of 5V is approximately 0.00488V.
To calculate the output voltage for an input code of 721 on a 10-bit DAC with a full-scale voltage range (VFSR) of 5V, we need to determine the decimal equivalent of the binary code. The formula to calculate the output voltage is:
Output Voltage = (Input Code / (2^N - 1)) * VFSR
Where:
Input Code is the decimal representation of the binary code
N is the number of bits of the DAC
In this case, the input code is 721, and the number of bits is 10.
Output Voltage = (721 / (2^10 - 1)) * 5V
Output Voltage ≈ (721 / 1023) * 5V ≈ 3.527V
Therefore, for an input code of 721 on a 10-bit DAC with a VFSR of 5V, the output voltage would be approximately 3.527V.
The smallest voltage increment at the output, also known as the voltage resolution, can be calculated by dividing the VFSR by the total number of possible output levels. For a 10-bit DAC, the total number of possible output levels is given by 2^10.
Voltage Increment = VFSR / (2^N)
Voltage Increment = 5V / (2^10) ≈ 5V / 1024 ≈ 0.00488V
Therefore, the smallest voltage increment at the output, or voltage resolution, for a 10-bit DAC with a VFSR of 5V is approximately 0.00488V.
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A 1500 kg car has an applied forward force of 5000 N and experiences an air resistance of 1250 N. What is the car's acceleration?
Answer:
\(2.33\ m/s^2\)
Explanation:
Net Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
Fn = m.a
Where a is the acceleration of the object. The net force is the sum of the individual vector forces applied to the object.
The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.
The net force is Fn = 5000 N - 1500 N = 3500 N
To find the acceleration, we solve the equation for a:
\(\displaystyle a=\frac{Fn}{m}\)
\(\displaystyle a=\frac{3500}{1500}\)
\(\boxed{a = 2.33\ m/s^2}\)
The car's acceleration is \(a = 2.33\ m/s^2\)
Find the velocity of a runner who has a mass of 75 kg and 3,700 Joules of energy.
Answer:
125 joules
Explanation:
The velocity of the runner having a mass of 75 kg will be 9.93 m/s.
What is Kinetic energy of the body?
The energy of the body by virtue of its motion is called its kinetic energy.
Given is velocity of a runner who has a mass of 75 kg and 3,700 Joules of energy.
The kinetic energy of the body is given by the following formula -
KE = 1/2 mv².
Substituting the values -
3700 = 1/2 x 75 x v²
7400 = 75 x v²
v² = 7400/75
v² = 98.66
v = 9.93 m/s
Therefore, the velocity of the runner having a mass of 75 kg will be 9.93 m/s.
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A truck enters a highway driving 60 mph A car enters the highway at the same place 0 nutes later and dives 72 mph in t The car will pass the truck in (Round to the nearest minute) minutes same directi
A truck enters a highway driving 60 mph A car enters the highway at the same place 0 nutes later and dives 72 mph in t The car will pass the truck in (Round to the nearest minute) minutes same direction From So the car enters the highway,However, this contradicts the information given that the car enters the highway 0 minutes later than the truck.
To determine how long it will take the car to pass the truck, we can set up an equation based on their relative speeds and distances traveled.
Let's assume that the car passes the truck after time 't' minutes.
In 't' minutes, the truck will have traveled a distance of 60 × (t/60) = t miles.
The car enters the highway 0 minutes later and travels at a speed of 72 mph. Therefore, when the car passes the truck, it will have traveled a distance of 72 × (t/60) = 1.2t miles.
To find when the car passes the truck, we can set up the following equation:
t = 1.2t
Simplifying the equation, we get:
t - 1.2t = 0.2t
0.2t = 0
This equation does not yield a valid solution since it implies that the time required for the car to pass the truck is 0 minutes. However, this contradicts the information given that the car enters the highway 0 minutes later than the truck.
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What hydroxide concentration is required to a. initiate precipitation of al3 from a 2.50 x 10-2 m solution of al2(s04)3? b. lower the ai3 concentration in the foregoing solution to 2.00 x 10-7 m?
a. The hydroxide concentration required to initiate precipitation is 2.50 x 10⁻² M.
b. To lower the Al³⁺ concentration in the solution to 2.00 x 10⁻⁷ M, we can use the common ion effect by adding excess OH⁻ ions.
(A). To initiate the precipitation of Al³⁺ from a 2.50 x 10⁻² M solution of Al(SO₄)₃, the solubility product constant (Ksp) of aluminium hydroxide (Al(OH)₃) is determined. The balanced equation for the dissociation of Al₂(SO₄)₃ is:
Al₂(SO₄)₃(s) ⇌ 2Al³⁺(aq) + 3SO₄²⁻(aq)
The Ksp expression for aluminium hydroxide is Ksp = [Al³⁺][OH⁻]³.
At the point of precipitation, the concentration of Al³⁺ will be equal to the concentration of OH- ions.
Therefore, [Al³⁺] = [OH⁻].
Given [Al³⁺] = 2.50 x 10⁻² M,
So,the hydroxide concentration required to initiate precipitation is also 2.50 x 10⁻² M.
(B). To lower the Al³⁺ concentration in the solution to 2.00 x 10⁻⁷ M, we can use the common ion effect by adding excess OH⁻ ions.
As the desired concentration is much lower than the initial concentration, we can assume that the OH⁻ concentration will be equal to the change in Al³⁺ concentration.
By using the solubility product expression,
Ksp = [Al³⁺][OH⁻]³, and substituting the given values, we have (2.00 x 10⁻⁷+ Δ[Al³⁺])(Δ[Al³⁺])³ = (2.50 x 10⁻² - Δ[Al³⁺])(2.50 x 10⁻² - Δ[Al³⁺])³.
Solving this equation will yield the value of Δ[Al³⁺], which corresponds to the change in Al³⁺ concentration. Subtracting this value from the initial Al³⁺ concentration of 2.50 x 10⁻² M will give us the desired concentration of 2.00 x 10⁻⁷ M.
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YALL HELP ME QUICK IN 10 MINS
WITH WORKING OUT
Answer:
bro I'm sorry I'm only in 7th grade
Describe what happens to a moving object if NO forces are acting on it
Answer:
An object with no net forces acting on it which is initially at rest will remain at rest. If it is moving, it will continue to move in a straight line with constant velocity. Forces are "pushes" or "pulls" on the object, and forces, like velocity and acceleration are vector quantities.
Explanation:
A 1400 kg car traveling at 17.0 m/s to the south collides with a 4700 kg truck that is at rest. The car and truck stick together and move together after collision. What is the final velocity of the two-vehicle mass? If Kinetic Energy = 0.5 * m * v^2, calculate the KE before the crash and the KE of the combined vehicles after the crash.
Answer:
Final velocity = 7.677 m/s
KE before crash = 202300 J
KE after crash = 182,702.62 J
Explanation:
We are given;
m1 = 1400 kg
m2 = 4700 kg
u1 = 17 m/s
u2 = 0 m/s
Using formula for inelastic collision, we have;
m1•u1 + m2•u2 = (m1 + m2)v
Where v is final velocity after collision.
Plugging in the relevant values;
(1400 × 17) + (4700 × 0) = (1400 + 1700)v
23800 = 3100v
v = 23800/3100
v = 7.677 m/s
Kinetic energy before crash = ½ × 1400 × 17² = 202300 J
Kinetic energy after crash = ½(1400 + 1700) × 7.677² = 182,702.62 J
Which is a characteristic of all waves?
All waves carry energy.
All waves move through space.
All waves move through matter, from particle to particle.
All waves transfer energy parallel to the direction of wave mo
Answer:à
Explanation:waves carry energy in the direction in which they move
Characteristics of all waves:
All waves carry energy.
All waves move through space.
All waves move through matter, from particle to particle.
All waves transfer energy parallel to the direction of wave mo tion.
what is the total charge on the rod? hint: this exercise requires an integration. think about how to handle the absolute value sign.
To find the total charge on the rod, you need to integrate the charge density function over the length of the rod, considering the absolute value sign.
To find the total charge on the rod, follow these steps:
1. Identify the charge density function (λ(x)) along the rod's length.
2. Consider the absolute value of the charge density function, i.e., |λ(x)|, to ensure you account for positive and negative charges.
3. Set up the integration with respect to x over the entire length of the rod, from x=a to x=b: ∫[a,b] |λ(x)| dx.
4. Evaluate the integral using appropriate integration techniques or tools, such as substitution, integration by parts, or numerical methods.
5. The result of the integral is the total charge on the rod.
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When adp and pi are added to the external medium and the vesicles are exposed to light, what will happen?
adp and pi are added to the external medium and the vesicles are exposed to light, The DNP will collapse the H+ gradient that ATP synthase uses to generate ATP.
ATP synthase is the enzyme that makes ATP molecules. It is a multi-part complex that straddles the inner membrane of mitochondria, the energy factories in cells. The enzyme complex interacts with fatty molecules in the mitochondrial inner membrane, creating a curvature that is required to produce ATP more efficiently.
ATP can be hydrolyzed to ADP and Pi by the addition of water, releasing energy. ADP can be "recharged" to form ATP by the addition of energy, combining with Pi in a process that releases a molecule of water.
The DNP will collapse the H+ gradient that ATP synthase uses to generate ATP. Each of the three respiratory enzyme complexes includes metal atoms that are tightly bound to the proteins.
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Mention three bodies/organizations that need electricity 24 hours
There are three types of electricity – baseload, dispatchable, and variable
According to the law of conservation of energy, which statement must be true?
A. The total energy of a system can increase only if energy enters the system.
B. A system cannot take in additional matter.
C. The total energy in a system can only decrease over time.
D. Energy that is transferred cannot be transformed into a different type of energy.
Answer:
B. A system cannot take in additional matter.
Explanation: The total amount of energy in the universe remains constant, it can merely change from one form to another.
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When a wood block floats in water it displaces 0.006m3 find the weight of the block when it is in air
The weight of the wood block when it is in the air can be determined with the help of Archimedes' principle.
Archimedes' principle states that the weight of a body that is submerged in a fluid is equal to the weight of the fluid that is displaced by it.
Hence, we can say that when the wood block floats in water, it displaces 0.006 m3 of water. This means that the weight of the wood block is equal to the weight of water displaced by it.
Therefore, the weight of the wood block when it is in the air can be determined by finding the weight of 0.006 m3 of water.
The density of water is 1 g/cm3.
Since 1m³ = 1000000 cm³,
We can say that the mass of 1 m3 of water is 1000 kg, or 106 g.
Hence, the mass of 0.006 m3 of water is 0.006 x 106 g, or 6000 g.
Therefore, the weight of 0.006 m3 of water is 6000 x 9.8 N, or 58800 N.
Hence, the weight of the wood block when it is in the air is 58800 N.
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If you stack 3 nickels on a table, how far above the table is their center of gravity?
Answer:
2.93 mm
Explanation:
If you stack 3 nickels on a table, e the table is their center of gravity 2.93 mm
what is center of gravity?The Centre of gravity is a theoretical term, where the body’s total weight is thought to be concentrated and it predicts the behavior of a moving body when acted on by gravity.
It is also useful in designing static structures like buildings and bridges, the center of gravity is identical to the centre of mass.
For the Moon, the centre of mass is very close to its geometric centre and its centre of gravity is slightly towards the Earth due to the stronger gravitational force on the Moon’s near side.
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In the one pully system when you move the mass from the 20 cm mark to the 15 cm mark, it moves 5 cm. How far did you pull the string. Question 1 options: 5 cm 10 cm 15 cm 20 cm
Answer:
5 cm
Explanation:
in a laundromat, during the spin-dry cycle of a washer, the rotating tub goes from rest to its maximum angular speed of 2.2 rev/s in 6.8 s. you lift the lid of the washer and notice that the tub decelerates and comes to a stop in 14.5 s. assuming that the tub rotates with constant angular acceleration while it is starting and stopping, determine the total number of revolutions undergone by the tub during this entire time interval.
The total number of revolutions undergone by the tub during the entire time interval is 23.1 revolutions.
To determine the total number of revolutions, we need to calculate the angular displacement of the tub during the starting phase, the stopping phase, and the constant speed phase.
During the starting phase, the tub goes from rest to its maximum angular speed of 2.2 rev/s. We can use the equation of motion for angular acceleration:
ω = ω₀ + αt
Given that ω₀ = 0 (initial angular speed) and ω = 2.2 rev/s (final angular speed), and t = 6.8 s (time), we can solve for α (angular acceleration). Using this angular acceleration, we can calculate the angular displacement (θ) during the starting phase.
During the stopping phase, the tub decelerates and comes to a stop. The angular displacement during this phase can be calculated using the same equation of motion for angular acceleration, with ω = 0 (final angular speed), ω₀ = 2.2 rev/s (initial angular speed), and t = 14.5 s (time).
Finally, during the constant speed phase, the angular displacement is given by ωt, where ω is the constant angular speed of 2.2 rev/s and t is the time interval between the end of the starting phase and the beginning of the stopping phase.
Adding up the angular displacements from each phase will give us the total angular displacement, which can be converted to the total number of revolutions by dividing it by 2π.
Calculating these values will result in a total of 23.1 revolutions undergone by the tub during the entire time interval.
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As a 70-kg person stands at the seashore gazing at the tides (which are caused by the Moon, how large is the gravitational force on that person due to the Moon? The mass of the Moon is 7.35 x 10^22 kg, the distance to the Moon is 3.82x10^8 m, and G- 6.67x10^-11 N* m^2/kg^2.
a) 0.24 N b) 0.024 N
c) 0.0024 N d) 0.00024 N
As a 70-kg person stands at the seashore gazing at the tides (which are caused by the Moon, The mass of the Moon is 7.35 x 10²² kg, the distance to the Moon is 3.82x10⁸ m, and G- 6.67x10⁻¹¹ N* m²/kg². The gravitational force on that person due to the Moon is (c) 0.0024 N.
The gravitational force on the person due to the Moon can be calculated using the formula:
F = G * (m1 * m2) / r²
where G is the gravitational constant, m1 is the mass of the person, m2 is the mass of the Moon, and r is the distance between the person and the Moon.
Plugging in the given values, we get:
F = 6.67x10⁻¹¹ * (70 kg) * (7.35x10²² kg) / (3.82x10⁸ m)²
F = 0.0024 N
Therefore, the gravitational force on the person due to the Moon is 0.0024 N. Answer (c) is correct.
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Respostas
2 M
3 M
5 M
7 M
8 M
Your supervisors at A&L Engineering have tasked you with evaluating the durability of three common materials used in the design of cell phone cases
A&L Engineering, as an engineer, you've been tasked with evaluating the durability of three common materials used in the design of cell phone cases.
These materials include:Carbon FiberPolycarbonateTPUExplanation:Carbon fiber is a lightweight, durable, and corrosion-resistant composite material. It is often used in the aerospace, automotive, and sporting goods industries.Polycarbonate is a thermoplastic polymer that is strong, shatter-resistant, and lightweight. It is often used in the production of CDs, DVDs, and eyeglass lenses.
TPU (thermoplastic polyurethane) is a flexible, soft material that is abrasion-resistant and provides excellent impact protection. It is often used in the production of phone cases, as well as sporting equipment and medical devices.To evaluate the durability of these materials, you can conduct a series of tests to measure their resistance to impacts, scratches, and bending.
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If it takes 20 N to move a box, how much power will be needed to move the box a distance of 5meters in 5 seconds?
Answer:
It will need 20 Watts power to move the box 5 meters in 5 seconds.
Step-by-step explanation:
The power is defined as the work per unit time or the rate of doing work:
W=dL/dt
Where de work L, can be calculated by multiplying the force by the displacement d:
L=F.d
To this example, F and D are known, therefore the work is:
L=20N . 5m=40 Nm
We know that the work is doing within a time of 5 seconds:
W= 40 Nm / 5s = 20 Nm/s = 20 Watts
which of the following stars has the largest habitable zone?
m
f
k
g
The classification of stars based on their spectral type follows the sequence O, B, A, F, G, K, and M, with O-type stars being the hottest and M-type stars being the coolest. The habitable zone, also known as the "Goldilocks zone," refers to the region around a star where conditions may be suitable for the existence of liquid water on the surface of a planet.
G-type stars, such as our Sun (classified as G2V), are considered to be within the optimal range for habitability. These stars have a stable and long-lasting main sequence phase, providing a relatively steady energy output over billions of years. Planets orbiting within the habitable zone of a G-type star have the potential to maintain a stable climate, with the right conditions for liquid water to exist. While other star types like F-type, K-type, and even some M-type stars can have habitable zones, G-type stars are generally considered to provide more favourable conditions for life.
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a pair of french bikers rode from paris to qatar for the world cup. a total of 7,000 kilometers in __ months.
From Paris to Qatar for the world cup, two French riders traveled by bicycle. In three months, 7,000 kilometers overall.
The Fédération Internationale de Football Association (FIFA), the world's governing organization of association football, and its senior men's national teams compete in the FIFA World Cup, commonly referred to as the World Cup. With the exception of 1942 and 1946, when it was postponed due to World War II, the tournament has been conducted every four years since its inception in 1930. The current winners are France, who captured their second championship during the 2018 competition in Russia.
The structure uses a qualification round to choose the teams that advance to the tournament phase, which occurs over the previous three years. 32 teams fight for the title at sites in the host country or nations during the tournament round.
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what is the difference between air resistance and friction?
Answer:Friction is a force that opposes the motion of objects; friction can cause objects to slow down. Air resistance is a type of friction. Air resistance causes moving objects to slow down. Different physical properties, such as the shape of an object, affect the air resistance on an object.
Explanation:
a rock was thrown up and reaches 10m how long was the rock in the air, what was the final velocity of the rock?
Answer:
sq root 2 sec.... same as initial speed
Q: How far will a car travel in 2 hours at 20 m/s
A 144 km
B: 158 km
C: 168 km
D:234
Also please show work
Explanation:
First convert hours to seconds by multiplying by 3600
2×60×60=7200seconds
D=?
t=7200s
s=20m/s
D=s×t
D=s×t
D=20×7200
D=144000m
when metres is converted to kilometres you divide by 1000
D= 144000/1000
D=144km
Option A!!!
A 23-N force is applied to a 7-kg object to move it with a constant velocity of 6.1 m/s across a level surface. The coefficient of friction between the object and the surface is approximately ____. Round your answer to the hundredths place.(Use the approximation g ≈ 10 m/s2.)
Given:
The applied force is F = 23 N
The mass of the object is m = 7 kg
The object moves with a constant velocity of v = 6.1 m/s
The acceleration due to gravity is g = 10 m/s^2
Required: The coefficient of friction between the object and the surface.
Explanation:
The object moves at a constant velocity, so the acceleration will be zero.
The equation of motion can be written as
\(\begin{gathered} F-f\text{ = ma} \\ F-f\text{ =m}\times0 \\ F-f=0 \\ F=f \end{gathered}\)So, the applied force will be equal to the frictional force.
The coefficient of friction can be calculated as
\(\begin{gathered} F\text{ = }\mu mg \\ \mu=\frac{F}{mg} \end{gathered}\)On substituting the values, the coefficient of friction will be
\(\begin{gathered} \mu=\frac{23}{7\times10} \\ =\text{ 0.33} \end{gathered}\)Thus, the coefficient of friction is 0.33
Final Answer: The coefficient of friction between the object and the surface is 0.33.
Consider a blimp that can be approximated as a 3-m diameter, 8-m long ellipsoid and is connected to the ground. On a windless day, the rope tension due to the net buoyancy effect is measured to be 120 N. Determine the rope tension when there are 50 km/h winds blowing along the blimp (parallel to the blimp axis).
Step 1 of 6
Diameter of the blimp,
Length of the blimp,
Rope tension,
The velocity of the wind,
Step 2 of 6
The drag force acting on the blimp can be calculated using the formula given below,
(1)
Where, is the drag coefficient is the density of air.
A is the frontal area of the blimp.
V is the velocity of the wind.
Step 3 of 6
The frontal area of the parachute,
Here,
Substitute the value in the above equation.
The drag coefficient for the balloon is,
Step 4 of 6
From the table properties of air,
The density of air at 1atm pressure and is,
The velocity of air,
Step 5 of 6
Now, substitute all the known values in equation (1)
Step 6 of 6
Now, rope tension is the sum of rope tension due to the buoyancy effect and the force due to the wind blowing.
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uotuN
CER: Momentum and Collisions - Preventing Concussions in Football Players and
Woodpeckers
Using the question below, develop a claim-evidence-reasoning to fully answer and explain
every part of the phenomenon we looked at in this part of the Unit.
Question: Why do football players get concussions, but woodpeckers don't?
Claim (your answer to the question; 1 sentence):
Evidence (values, descriptions, and observations that support your claim; 2-3
sentences):
Reasoning (explanation of the evidence to further support your claim; 3-4 sentences):
Even the most powerful woodpeckers could not penetrate a bird's brain with more than 60% of the force required to cause a concussion in a human.
How do concussions affect football players?One of the most frequent causes of concussions in football is helmet-to-helmet contact, but any collision that causes the head to rapidly snap back or to the side can cause the brain to collide with the skull. The brain striking the skull during this impact is what creates a concussion.
What physics governs the woodpecker?He uses his potential energy to maintain the swing by lowering a stick and hard-beating it with its beak.
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a 0.800 kg block is attached to a spring with spring constant 17.5 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 50.0 cm/s . what are
The block may move up to 19.7 cm from its resting position, and its oscillations last for a period of 2.76 seconds.
Displacement formula: What is it?The final position less the starting position is known as displacement.
The greatest displacement is:
The simple harmonic motion equation can be used to determine the block's maximum displacement:
x = A * cos (wt)
where w is the angular frequency, t is the time, and A is the amplitude. The block's starting velocity can be used to compute the amplitude:
A = v0 / w
The spring constant can be used to determine the angular frequency:
Sqrt(k / m) = w
Where k is the spring constant and m is the block's mass.
Replacement of values
A = 50.0 cm/s/sqrt(17.5 N/m/0.800 kg), and w = sqrt(17.5 N/m/0.800 kg).
w = 2.32 rad/s, with A = 19.7 cm
The maximum displacement is equal to the amplitude:
x = A = 19.7 cm
The oscillation's time scale:
The angular frequency can be used to calculate the oscillation's period:
T = 2 * pi / w
Replacement of values
T = 2.76 s = 2.32 rad/s / 2 * pi
Therefore, the oscillation's period is roughly 2.76 seconds.
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The angular quantities L, omega, and alpha are vectors. The vectors point along the axis of rotation with a direction determined by __________.
The vectors point along the axis of rotation with a direction determined by an arrow.
What is a vector?There are two types of physical quantity one is a scaler and another one is a vector.
The quantity that requires only megnitude to define is known as the scalar quantity. While the vector quantities need both megnitude and the direction to define.
The vector quantity is represented by an arrow. The vectors point along the axis of rotation with a direction determined by an arrow.
The angular quantities L, omega, and alpha are vector quantities.
Hence arrow is the correct answer for the blank.
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The direction of the vectors of angular momentum and L, angular velocity omega and the mass alpha is determined using the right hand rule.
What is right hand rule?Righthand rule in physics states that, when we curl our right hand fingers, the direction of the angular momentum and velocity will be in the direction of thumb and curl of fingers determine the axis of rotation.
Angular momentum is a vector quantity defined as the product of moment of inertia and angular velocity where, the angular velocity ω is the rotational analogue of linear velocity i.e.. product of the linear velocity and radius of rotational path.
Therefore, the angular quantities L, angular velocity ω along the axis of rotation can be determined using the right hand rule. Where direction of thump represents the direction of vector components.
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