For a confidence level of 98%, find the critical value for a normally distributed variable. The sample mean is normally distributed if the population standard deviation is known.
Add Work All else equal, an increase in sample size will cause an)
O increase
O decrease
in the size of a confidence interval

Answer:

B: A line that goes down

Step-by-step explanation:

if you sell a product for lesser price than what it cost then it will be a loss not profit.

Since the hats were bought for $20 and sold for $5 then the graph will be a line that goes down.

Not a curve, because all are bought at the same price, $20, and sold for the consistent price of $5.

Answer:

C

Step-by-step explanation:

We are given the function.

\(h(x)=e^{2x}\)

And we want to find its inverse.

Let's switch h(x) and x and change h(x) to h⁻¹(x). Hence solve:

\(\displaystyle \begin{aligned} x & = e^{2h^{-1}(x)} \\ \\ \ln x & = \ln e^{2h^{-1}(x)} \\ \\ \ln x & = 2h^{-1}(x) \\ \\ h^{-1}(x) & = \frac{1}{2} \ln x\end{aligned}\)

In conclusion, our answer is C.

Note:

\(\ln(x)=\log_ex\)

Answer:

809.6

Step-by-step explanation:

880*(1-8%)

In a standard 52-card deck of playing cards, each card is assigned one of four suits: spade, heart, club, or diamond. These suits are represented by symbols that are printed on the cards.

The deck consists of 13 cards for each suit. Within each suit, there are four face cards (king, queen, and jack) and nine numbered cards (from 2 to 10). Additionally, each suit has an Ace card, which can be counted as either a high or low card depending on the game being played. To summarize, a standard 52-card deck of playing cards consists of four suits (spade, heart, club, and diamond), each containing 13 cards. This provides a total of 52 cards in the deck. A standard 52-card deck of playing cards consists of four suits: spade, heart, club, and diamond. Each suit has 13 cards, including four face cards and nine numbered cards. In a standard 52-card deck of playing cards, the suits are spade, heart, club, and diamond. Each suit has its own symbol and color. Spades and clubs are black suits, represented by a ♠ and ♣ symbol, respectively. Hearts and diamonds are red suits, represented by a ♥ and ♦ symbol, respectively. Each suit contains 13 cards, making a total of 52 cards in the deck. Within each suit, there are four face cards: the king, queen, and jack. These cards often have additional designs or symbols, depending on the deck's style. In addition to the face cards, each suit has nine numbered cards, ranging from 2 to 10. Furthermore, each suit has an Ace card, which is considered the highest-ranking card in many card games. However, the Ace can also be used as a low card in some games, depending on the rules.

In a standard 52-card deck of playing cards, there are four suits: spade, heart, club, and diamond. Each suit contains 13 cards, including four face cards, nine numbered cards, and an Ace card. The deck is used for various card games, and the suits are represented by different symbols and colors.

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c) The statement "All soccer balls are round" is equivalent to "For all x, if S(x) then R(x)" and it can be written in predicate wff as

d) The statement "Some balls are not round" is equivalent to "There exist some x such that B(x) and not R(x)", which can be written in predicate wff as

e) The statement "Some balls are round but soccer balls are not" is equivalent to "There exist x such that B(x) and R(x) and there exist x such that S(x) and not R(x)", can be written in prediacte wff as

f) The statement "Every round ball is a soccer ball" is equivalent to "For all x, if R(x) then S(x)", can be written in prediacte wff as

Answer:75%

Step-by-step explanation:

15 out of 20 is 75%

The number of people of the country which is predicted will be illiterate in the year 2025 are 1,300,700.

Percentage decrease is the amount deducted or reduced from the initial value in the percentage part.

In the year 2017, an estimated 4,347,000 people in this country are illiterate. With new incentives and funding, The country is hoping to cut that number by 14% every year.

Total year from 2017 to 2025 are 8 years. Thus, use the following formula of compound interest to find percentage decrease:

\(A=P\times\left(1+\dfrac{r}{100}\right)^{t}\\\)

Here, A is the final population, The initial population is P, the rate is r and the time period is t. Put the values,

\(A=4347000\times\left(1-\dfrac{14}{100}\right)^{8}\\A\approx1300700\)

Thus, the number of people of the country which is predicted will be illiterate in the year 2025 are 1,300,700.

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Explanation:

1 hat = 45 dollars

6 hats = 6*45 = 270 dollars

1 phone = 40 dollars

4 phones = 4*40 = 160 dollars

total = $270 + $160 = $430

Felicia spent a total of $430. Since this amount of money leaves her account, this means we write a negative sign out front to end up with the final answer of -430

In other words, her account balance went down by $430 which is why we use a negative. If someone gave her $430, then the answer would be positive.

Step-by-step explanation:

First, we want to find profit given revenue and cost. Because profit = revenue - cost, we can write the profit function, P(x), as R(x) - C(x) and go from there.

P(x) = R(x) - C(x)

P(x) = (-x²+24x) - ( 10x + 30)

P(x) = -x²+24x - 10x-30

P(x) = -x²+14x-30

In a quadratic function such as this, the graph opens downward (meaning that it goes from up to down) if the leading coefficient is negative and vice versa. Here, since -1 is attached to x², we can say that the graph opens downward. The point where the direction of the slope changes (when it goes from up to down), or the peak of the quadratic, is called the vertex.

The x value of the vertex is given by -b/(2a) in a quadratic of form ax²+bx+c. As a=-1 and b=14 here, we can say that -b/(2a) =

-14/(2*-1) = -14/-2

= 7

Therefore, the x value of the vertex, or the number of containers sold that maximizes profit, is 7.

The height of the cylindrical shape cup is 8.8 centimeters.

Given that, Andrew measures its radius as 2.7 cm and its volume as 202 cubic centimeters.

Volume is the measure of the capacity that an object holds.

Formula to find the volume of the object is Volume = Area of a base × Height.

We know that, the formula to find the volume of a cylinder is πr²h.

Substitute, r=2.7 cm and volume = 202 cubic centimeters in the volume of a cylinder formula.

Here, 202 = 3.14×2.7²×h

h=202/22.8906

h=8.8 centimeters

Therefore, the height of the cylindrical shape cup is 8.8 centimeters.

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Answer:

hello,2 th made from the wrong place.

because She should have distributed the -2 inside the parentheses.

the process should be like this;

19-2(1-x)<13

17(1-x)<13

17-17x<13

-17x<13-17 (17 goes to the opposite side as -17)

-17x<-4 (we divide each side by 17)

x= -4/-17

I hope you understand. There are errors in the first 2 parts of the question.

The limit of (-8)^n / n^2 as n approaches infinity is -infinity.

To apply the ratio test to the series ∑(n=1 to infinity) (-8)^n / n^2, we need to compute the limit of the absolute value of the ratio of consecutive terms:

|(-8)^(n+1) / (n+1)^2|    |-8 / (n+1)^2|

lim -------------------- = lim ------------ = 0

n → infinity   |(-8)^n / n^2|   |(-8) / n^2|

Since the limit of this ratio is 0, which is less than 1, the series ∑(n=1 to infinity) (-8)^n / n^2 converges by the ratio test.

To identify the nth term, we can observe that the general term of the series is given by:

an = (-8)^n / n^2

To evaluate the limit, we need to use L'Hopital's rule:

lim n → infinity (-8)^n / n^2 = lim n → infinity (ln(-8))^n / (2n)

Now we can apply L'Hopital's rule again:

lim n → infinity (ln(-8))^n / (2n) = lim n → infinity [(ln(-8))^n * ln(-8)] / 2 = -infinity

Therefore, the limit of (-8)^n / n^2 as n approaches infinity is -infinity.

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a. f(4) = 11.

b. There is no element in the domain which  satisfies f(n) = 4.

c. n = 1 is the element in the domain such that f(n) = n.

d. The element 3 is in the codomain but not in the range.

a. T

f(4) = 2 f(4)

= 2 * (11 361)

= 11.

b. In order to find an element n in the domain such that f(n) = 4, we check the values of f(n) for each element in the domain:

f(1) = 2 * (11 361) = 11,

f(2) = 2 * 3 = 6,

f(3) = 2 * 4 = 8,

f(4) = 2 * 5 = 10,

f(5) = 2 * 3 = 6.

We say that there is no element in the domain that satisfies f(n) = 4.

c.

f(1) = 2 * (11 361) = 11,

f(2) = 2 * 3 = 6,

f(3) = 2 * 4 = 8,

f(4) = 2 * 5 = 10,

f(5) = 2 * 3 = 6.

f(1) = 11, so there is an element n = 1 in the domain such that f(n) = n.

d. We look at the possible values of the codomain, which is {1, 2, 3, 4, 5}. The range of f is {6, 8, 10, 11}.

In conclusion,  the element 3 is in the codomain but not in the range.

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========================================================

Work Shown

The two points are \((x_1,y_1,z_1) = (0,0,0)\) and \((x_2,y_2,z_2) = (3,6,8)\)

Use the 3D version of the distance formula to get the following:

\(d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}\\\\d = \sqrt{(0-3)^2+(0-6)^2+(0-8)^2}\\\\d = \sqrt{(-3)^2+(-6)^2+(-8)^2}\\\\d = \sqrt{9+36+64}\\\\d = \sqrt{109}\\\\d \approx 10.4403065\\\\d \approx 10.44\\\\\)

You'll need your calculator for the second to last step.

The hypotheses for the test are H₀: σ₁² = σ₂² and H₁: σ₁² ≠ σ₂². This is a two-tailed test to assess if there is a difference in the standard deviations of sound levels between the areas designated as "casualty doors" and operating theaters. The claim being investigated is whether or not there is a difference in the standard deviations.

The hypotheses for the test are:

H₀: σ₁² = σ₂² (There is no difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)

H₁: σ₁² ≠ σ₂² (There is a difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)

This hypothesis test is a two-tailed test because the alternative hypothesis is not specifying a direction of difference.

To substantiate the claim that there is a difference in the standard deviations, we will conduct a two-sample F-test at a significance level of 0.10, comparing the variances of the two groups.

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No, g is not a continuous function. It is a correspondence, which is a set of ordered pairs.

A correspondence is a set of ordered pairs, which means that for each input there may be multiple outputs. In contrast, a continuous function must have a single output for each input. Therefore, g is not a continuous function because it can have multiple outputs for any given input.

A continuous function is a function that is defined for all values in its domain and range, and whose graph has no gaps or breaks in it. Continuous functions are often described as having no jumps, discontinuities, or holes in their graphs. Examples of continuous functions include polynomials, trigonometric functions, exponential functions, and logarithmic functions.

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SANA ALL SMART HAHAHAHHAAHHAHAAHA

Given two points: A(-3,4) and B(1, -2), the distance  between point A and point B is 7.2 units.

The distance between two points can be calculated using the Pythagorean Theorem.

We have two points: A(-3,4) and B(1, -2)

Hence,

xA = -3

yA = 4

xB = 1

yB = -2

The length of the sides of the right triangle are:

x-side = |xB - xA| = |1 - (-3)| = 4

y-side = |yB - yA| = |-2 - 4| = 6

Applying the Pythagorean Theorem:

AB = √(4² + 6²)

AB = √(16 + 36)

AB = √52 = 7.2

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The combination of scores that won the National Championship for Baylor are 18 free throws, 24 two point field goals and 6 three-point field goals.

An equation is a mathematical statement containing two expressions on either sides which are connected with an equal to sign.

Either sides of an equation is called as left hand side and right hand side.

Given Baylor University defeated Michigan State University by a score of 84 to 62.

Score of Baylor University = 84

Baylor won by scoring a combination of two-point field goals, three-point field goals, and one-point free throws.

Let the number of free throws = x

The number of two-point field goals was six more than the number of free throws.

Number of two point field goals = x + 6

Also, the number of two-point field goals was four times the number of three-point field goals.

Number of two point field goals =  4 (number of three-point field goals)

So, 4 (number of three-point field goals) = x + 6

Number of three-point field goals = (x + 6) / 4

Score for free throw = 1 point × x

Score for 2 point field goal = 2 points × (x + 6)

Score for 3 point field goal = 3 points × [(x + 6)/4]

[1 × x] + [2 (x+6)] + [3 ((x+6)/4] = 84

x + 2x + 12 + 3/4 x + 18/4 = 84

3.75x + 16.5 = 84

3.75x = 67.5

x = 18

Number of free throws = x = 18

Number of two point field goals = x + 6 = 18 + 6 = 24

Number of three-point field goals = (x + 6) / 4 = 24/4 = 6

Hence the combination are 18 free throws, 24 two point field goals and 6 three-point field goals.

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The taxi fare for a journey of n miles in dollars is 1 + 2n

Linear equations are equations that have constant average rates of change, slope or gradient

The given parameters about the taxi fares are given as

First two miles = $5

Additional mile = Increment of $2

Let the number of miles be n

So, we have:

2 miles = $5

Additional miles = (n - 2) * 2

Add the above expressions

5 + (n - 2)* 2

Represent the value with f(n)

So, we have:

f(n) = 5 + (n - 2)* 2

Expand the bracket

f(n) = 5 + 2n - 4

Collect the like terms

f(n) = 5 - 4+ 2n

Evaluate the like terns

f(n) = 1 + 2n

Hence, the taxi fare for a journey of n miles in dollars is 1 + 2n

So, the complete parameters are:

First two miles = $5

Additional mile = Increment of $2

n miles  1 + 2n

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The equation for the hyperbola is:

(x + 2)^2 / 9 - (y - 1)^2 / 16 = 1.

To find the equation for the hyperbola whose graph is shown, we need to determine its center, vertices, foci, and asymptotes.

From the graph, we can see that the center is at (-2, 1) and the vertices are at (-2, 4) and (-2, -2). The distance between the center and each vertex is a, where a = 3.

We can also see that the foci are located along the vertical axis, which passes through the center. The distance between the center and each focus is c, where c = 5. Using the formula c^2 = a^2 + b^2, we can solve for b:

b^2 = c^2 - a^2

b^2 = 25 - 9

b^2 = 16

b = ±4

Therefore, the foci are located at (-2, 5) and (-2, -3).

The equation for a hyperbola centered at (h, k) with vertices at (h, k ± a) and foci at (h, k ± c) is:

(x - h)^2 / a^2 - (y - k)^2 / b^2 = 1

Substituting in the values we found, we get:

(x + 2)^2 / 9 - (y - 1)^2 / 16 = 1

Therefore, the equation for the hyperbola is:

(x + 2)^2 / 9 - (y - 1)^2 / 16 = 1.

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The rate of discount for the CD radio cassette is 17.65%.

To calculate the rate of discount, we need to find the difference between the original price and the discounted price, and then divide that difference by the original price.

Original price: $16,999

Discounted price: $13,999

So, the Discount amount

= Original price - Discounted price

= $16,999 - $13,999

= $3,000

Rate of discount = (Discount amount / Original price) * 100%

= ($3,000 / $16,999) x 100%

≈ 17.65%

Therefore, the rate of discount for the CD radio cassette is 17.65%.

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Answer:

true.........

20÷5=4..

20÷4=5

Answer:

Step-by-step explanation:

Jared bought 7 cans of paint. Let the number of red paint cans that Jared bought be x. The number of black paint cans he bought would be 7 - x. A can of red paint costs $3.75 and a can of black paint costs $2.75.

He spent $22 in all. Therefore we can write:3.75x + 2.75(7 - x) = 22 Multiplying out the second term and collecting like terms gives:0.5x + 19.25 = 22Subtracting 19.25 from both sides:0.5x = 2.75Dividing by 0.5:x = 5.5Since Jared can't buy half a can of paint, we should round the answer to the nearest integer. Hence, he bought 5 cans of red paint and 2 cans of black paint. The total cost of the 5 cans of red paint would be 5 x $3.75 = $18.75.The total cost of the 2 cans of black paint would be 2 x $2.75 = $5.50.The total cost of all 7 cans of paint would be $18.75 + $5.50 = $24.25.We spent more than Jared's budget. The value of $24.25 exceeds Jared's budget of $22. Hence, there is a problem with this problem statement.

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Answer:

The act or state of going regularly to or being present at a place or event.

Explanation:

"my attendance at church was very patchy

Option D. Christa sliced the pyramid through the apex perpendicular to its base.

The value of x when f(x) = 0 in the graphed function is: C. -2, 1, or 3 only.

A function relates an input value (x-value) to a corresponding output value (y-value).

In the graphed function, f(x) = 0 means the value of y is 0, at this point, the values of x on the x-axis that corresponds to this y-value are -2, 1, or 3.

Therefore, if f(x) - 0, x would be: C. -2, 1, or 3 only.

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Step-by-step explanation:

3. B

because the figure to the left of the y-axis yields the one to the right when you reflect it across y = x.

4. C

Flip either of the figures vertically across x = -1 which is their intersection point and you'll get the other.

5. D

it can't be clockwise because the x value of the vertices would have been negative. so it is 270° counterclockwise resulting in ( -y , x )

6. A

Similar to #4 which except this time, you flip it horizontally like how you lay a book or pick it up.

(a) Using the data provided, where 9 out of 32 students are Business majors, we can construct a 95% confidence interval for the proportion of Cal Poly students who are Business majors.

To do this, we'll use the formula for the confidence interval:

CI = p ± z * sqrt(p(1 - p) / n)

Where p is the sample proportion, z is the z-score corresponding to the desired confidence level (95% confidence level corresponds to z = 1.96), and n is the sample size. In this case, p = 9/32 = 0.28125, z = 1.96, and n = 32. Plugging these values into the formula, we can calculate the confidence interval.

CI = 0.28125 ± 1.96 * sqrt(0.28125 * (1 - 0.28125) / 32)

Calculating the values, we get a 95% confidence interval of approximately 0.145 to 0.417.

(b) The above 95% confidence interval is a reasonable estimate of the actual proportion of all Cal Poly students who are Business majors. However, it is important to note that this estimate is based on a sample from a single section of STAT 251, which may not be representative of the entire student population.

To obtain a more accurate estimate, a larger and more diverse sample that includes students from different majors and sections would be required. Additionally, the confidence interval only provides a range of plausible values for the population proportion and does not guarantee the exact value.

(c) The above 95% confidence interval is specific to estimating the proportion of Business majors in the STAT 251 section based on the given data. It does not provide an estimate for the proportion of Business majors in the entire Cal Poly student population. The interval makes sense for the sample in STAT 251 because it is calculated based on the data from that section.

However, using this interval to estimate the proportion of Business majors in the overall Cal Poly population would be inappropriate since the sample is not representative of the entire student body. To estimate the proportion for the entire population, a broader and more diverse sample would be necessary.

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