For a given experiment, the students know how much the angular momentum of the system has changed after a specific time interval. The students create a series of graphs for each experiment. The students must determine if the change in angular momentum of a given system is equal to the angular impulse applied to the system. How should the students use data from a particular graph to make the determination by using only the graph? A Calculate the slope of an angular velocity versus time graph and see if it equals the angular acceleration. Calculate the slope of an angular position versus time graph and see if it equals the average angular velocity. Calculate the slope of a graph of the change in angular momentum versus the product of the net torque and C the time interval and determine if the slope is equal to one. Calculate the slope of an angular momentum versus time graph and see if it equals the net torque

The Kelvin scale is known as the absolute scale. The lowest temperature in Kelvin is the temperature 0 (there is no negative temperature in Kelvin).

The conversion from Kelvin to Fahrenheit is given by the formula below:

Using K = 0 in this formula, we have:

So the lowest temperature in Fahrenheit is -459.67 °F.

The correct answer of terrestial weather:

The solar insolation in the visible and infrared regions of the solar electromagnetic spectrum is much more than the energy that space weather occurrences release into the troposphere and stratosphere. Despite claims to the contrary, there may be some connection between the Earth's climate and the 11-year sunspot cycle. There is no proof of this. For instance, it has frequently been suggested that the Maunder minimum, a 70-year period almost devoid of sunspots, is correlated to a cooler climate, but these correlations have vanished after further research. Changes in cosmic ray flux are hypothesized to affect how much cloud formation occurs.

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The period (in years) of an asteroid with a radius of four astronomical units.

The period of an asteroid refers to the time it takes for the asteroid to complete one full orbit around its primary object, typically a star. In this case, we are given that the radius of the orbit of a certain asteroid is four astronomical units. To determine the period of the asteroid, we can apply Kepler's third law of planetary motion.

Kepler's third law states that the square of the period of revolution (T) of an object orbiting a central body is proportional to the cube of the semi-major axis (a) of its elliptical orbit. Mathematically, this can be expressed as:

T² = k * a³

Where T is the period, a is the semi-major axis, and k is a constant of proportionality.

To calculate the period of the asteroid, we need to determine the value of k. This can be done by comparing the period and semi-major axis of a known celestial body. Let's consider the Earth as a reference. The Earth has an average distance from the Sun of one astronomical unit (AU) and a period of approximately one year.

Substituting these values into Kepler's third law, we can solve for k:

(1 year)² = k * (1 AU)³

1 year² = k * 1 AU³

k = 1 year² / 1 AU³

k = 1 year² / AU³

Now that we have determined the value of k, we can calculate the period of the asteroid. Given that the radius of the orbit is four astronomical units, we can use this information to find the semi-major axis (a) of the orbit. The semi-major axis is equal to half of the longest diameter of the elliptical orbit, which is the same as the radius in this case.

a = 4 AU

Substituting this value of a and the value of k into Kepler's third law, we can calculate the period of the asteroid.

T² = (1 year² / AU³) * (4 AU)³

T² = (1 year² / AU³) * 64 AU³

T² = 64 year²

T = √(64 year²)

T = 8 years

Therefore, the period of the asteroid with a radius of four astronomical units is 8 years.

It is important to note that this calculation assumes the asteroid's orbit is nearly circular and neglects the influence of other celestial bodies, which may introduce minor deviations in the period.

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Answer:

Speed = 300 m/s

Explanation:

Given the following data;

Frequency = 30 Hz

Wavelength = 10 m

To find the speed of the wave;

Mathematically, the speed of a wave is given by the formula:

\( Speed = wavelength * frequency \)

Substituting into the formula, we have;

\( Speed = 10 * 30 \)

Speed = 300 m/s

The compression takes 4.5 seconds to travel the entire 9-meter length of the classroom.

To determine the time it takes for the compression to travel the length of the classroom, we can use the formula:

time = distance / velocity

In this case, the distance is 9 meters, and the velocity of the compression is given as 2 m/s. Substituting these values into the formula, we get:

time = 9 meters / 2 m/s

Simplifying the equation gives:

time = 4.5 seconds

Therefore, it takes the compression 4.5 seconds to travel the entire 9-meter length of the classroom.

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For a 3 m long ladder leaning against a frictionless wall, the minimum value of the coefficient of static friction is mathematically given as

mu=0.2886

Generally, the equation for the Force  is mathematically given as\(-\mu N_{1}+N_{2}=0\)

Therefore

\(\mu=\frac{1}{2}tan\theta\)

\(\mu=\frac{1}{2}tan30^{0}\)

mu=0.2886

In conclusion, the minimum value of the coefficient of static friction

mu=0.2886

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The air speed of the helicopter has the ground speed of 250 km/h is 233 km/h  

The ground speed of the helicopter = 250 km/h

The wind speed of the helicopter = 17 km/h

The air speed of the helicopter can be found using the formula,

            G = W + A
where G is the ground speed of the helicopter

           W is the wind speed of the helicopter

           A is the air speed of the helicopter

Let us rearrange the equation in order to get the airspeed,

          A = G - W

Let us substitute the known values in the above equation, we get

          A = 250 - 17

              = 233 km/h  

Therefore, the air speed of the air speed is 233 km/h

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Answer:the basic building block of chemistry

an atom

The best way to calculate the volume of a log with a serious defect is to calculate the volume of the defect and subtract it from the total volume of the log which is denoted as option C.

This is referred to as the amount of space occupied by any three-dimensional solid which could be a square, rectangle etc.

In a scenario where a defect is present in the log, then it is  best to consider it by first calculating the volume of the defect after which it is then subtracted from the total volume of the log in other to give an accurate result.

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The sound level of a single instrument is 50 - 10 log(I/I₀)

The frequency and intensity of all instruments are the same.

Sound level of 80 dB is measured.

Number of members in the orchestra is 100.

Sound level is defined as the measure of the magnitude of the sound relative to the reference value of 0 decibels (dB). The sound level is given by the formula:

L = 10 log(I/I₀)

Where, I is the intensity of sound, and

I₀ is the reference value of intensity which is 10⁻¹² W/m².

As given, the total sound level of the orchestra with 100 members is 80 dB. Let's denote the sound level of a single instrument as L₁.

Sound level of 100 instruments:

L = 10 log(I/I₀)L₁ + L₁ + L₁ + ...100 times

   = 8010 log(I/I₀)

   = 80L₁

   = 80 - 10 log(100 I/I₀)L₁

   = 80 - 10 (2 + log(I/I₀))L₁

   = 80 - 20 - 10 log(I/I₀)L₁

   = 50 - 10 log(I/I₀)

Therefore, the sound level of a single instrument is 50 - 10 log(I/I₀).

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By using Hubble's constant H₀, the estimated age of the universe would be 27,269,816,110  years.

As we know that the age of the universe is something near to the time the galaxies needed to reach their current distance:

T = D/V

where T is the time the galaxies needed, D is distance and V is speed.

By using Hubble's law we can use the equation

V = H₀*D

where H₀ is Hubble's constant

By combining these 2 equations, we get

T = D/(H₀*D) = 1/H₀ .............(A)

In conclusion, the age of the universe is something near the inverse of Hubble's constant.

From the question above, we know that:

H₀ = 11 km/s/Mly

By using equation A we get

T = 1/(11 km/s*Mly)

T = (1/11)  s*Mly/km

Convert 1 million light-years to km by (1 ly = 9.461*10^12 km)

T = (1/11) s*Mly/km

T = (1/11)*9.461*10^18 s

T = 8.6009*10^17 s

Convert to years by (1 year = 3.154*10^7 s)

T = 8.6009*10^17 s

T = (8.6009*10^17 s/3.154*10^7 s)* 1 yea

T = 27,269,816,110 years.

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Answer:

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Answer:

Ans : C

Explanation:

C. The force of gravity acting on the chair

Answer:

D. the force from the chair on the student

Explanation:

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself. 

Hope this helps :)

Answer:

\(\vec{A} + \vec{B} = \vec{A} - \vec{B}\) if and only if \(\vec{B}\) is a zero vector.

Explanation:

An equation is true if and only if adding the same value to both sides of the equation (the value needs to be compatible) gives an equation that is also true.

Start with the \(\vec{A} + \vec{B} = \vec{A} - \vec{B}\).

This equation is true if and only if \(\left(\vec{A} + \vec{B}\right) + \vec{B} = \left(\vec{A} - \vec{B}\right) + \vec{B}\) (\(\vec{B}\) is added to both sides of the original equation.)

Vector addition and subtraction are associative. Therefore, \(\left(\vec{A} + \vec{B}\right) + \vec{B} = \left(\vec{A} - \vec{B}\right) + \vec{B}\) if and only if \(\vec{A} + \left(\vec{B} + \vec{B}\right) = \vec{A} + \left(- \vec{B} + \vec{B}\right)\), which is equivalent to \(\vec{A} + 2\, \vec{B} = \vec{A}\).

\(\vec{A} + 2\, \vec{B} = \vec{A}\) if and only if \(\left(-\vec{A}\right) + \vec{A} + 2\, \vec{B} = \left(-\vec{A}\right) + \vec{A}\) (\(\left(-\vec{A}\right)\)is added to both sides of this equation,) which is equivalent to \(2\, \vec{B} = \vec{0}\).

\(2\, \vec{B} = \vec{0}\) if and only \(\displaystyle \frac{1}{2} \cdot \left(2\, \vec{B}\right) = \frac{1}{2} \cdot \vec{0}\), which is equivalent to \(\vec{B} = \vec{0}\). That is: \(\vec{B}\) is the zero vector.

In other words:

\(\begin{aligned}& \vec{A} + \vec{B} = \vec{A} - \vec{B}\\ &\iff \left( \vec{A} + \vec{B}\right) + \vec{B} = \left(\vec{A} - \vec{B}\right) + \vec{B} \\ &\iff \vec{A} + \left(\vec{B} + \vec{B}\right) = \vec{A} + \left(- \vec{B} + \vec{B}\right) \\ & \iff \vec{A} + 2\, \vec{B} = \vec{A} \\ & \iff \left(-\vec{A}\right) + \vec{A} + 2\, \vec{B} = \left(-\vec{A}\right) + \vec{A} \\ &\iff 2\, \vec{B} = \vec{0} \\ &\iff \frac{1}{2} \cdot 2\,\vec{B} = \frac{1}{2} \cdot \vec{0} \\ &\iff \vec{B} = \vec{0}\end{aligned}\).

Hence, \(\vec{A} + \vec{B} = \vec{A} - \vec{B}\) if and only if \(\vec{B}\) is the zero vector.

The frequency of the wave would be approximately 3.125 Hz.

The frequency of a wave is the number of complete cycles or oscillations it completes in one second. the frequency (f) is the reciprocal of the period (T)  which is the time it takes for one complete cycle.

In this case  if the period is 0.32 seconds, the frequency would be:

f = 1 / T

f = 1 / 0.32

f ≈ 3.125 Hz

Therefore, the frequency of the wave would be approximately 3.125 Hz.

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Answer:

The impression of the image on the retina lasts for about 1/16th of a second after the removal of the object. If a burning stick of incense is revolved at a rate of more than sixteen revolutions per second, we see a circle of red light due to persistence of vision.

Explanation:

Answer:

a

Explanation:

i took the test

Five workers from the same factory developed angiosarcoma, a rare cancer of the veins and arteries. This is observation of the scientific method.

Since at least the 17th century, the scientific method—an empirical approach to learning—has guided the advancement of science. Since one's interpretation of the observation may be distorted by cognitive presumptions, it requires careful observation and the application of severe skepticism regarding what is observed.

It entails developing hypotheses through induction based on these observations, testing the validity of those hypotheses through experimental and measurement-based statistical testing of the inferences made from them, and then fine-tuning (or discarding) those hypotheses in light of the experimental results.

These are the guiding principles of the scientific process, as opposed to a predetermined set of steps that apply to all scientific endeavors.

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The equation that represents the relationship between the force, F, applied to the spring and its change in length, x, is F = kx, where k is the spring constant.

The relationship between the force applied to the spring and the extent to which it was compressed (stretched) is directly proportional. This means that as the force applied to the spring increases, the extent to which it is compressed (stretched) also increases.

The general equation describing the relationship between the applied force and the change in the length of the spring is F = kx, where F is the force applied, k is the spring constant, and x is the change in length.

For the second hoop, the same analysis can be conducted. The equation that represents the relationship between the force, F, applied to the spring and its change in length, x, is F = kx, where k is the spring constant. The relationship between the force applied to the spring and the extent to which it was compressed (stretched) is directly proportional. The general equation describing the relationship between the applied force and the change in the length of the spring is F = kx.

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The hypothesis that can be tested using this procedure is:

"Inserting a conducting slab between the plates of an isolated capacitor will increase the capacitance of the capacitor."

When the conducting slab is inserted between the plates of the isolated capacitor, it increases the effective area of the plates that are now partially covered by the conducting slab. This increases the capacitance of the capacitor, since capacitance is directly proportional to the area of the plates and inversely proportional to the distance between them.

Measuring the potential difference across the plates before and after inserting the conducting slab can allow us to calculate the change in capacitance. This can be used to test the above hypothesis and verify whether or not the capacitance of the capacitor increases when a conducting slab is inserted between the plates.

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Answer:

\(distance \: is \: 19cm \\ displacement \: is \: 5cm \: easth \:of \:north \)

If the student replaced the water in the calorimetry device with an ice bath at 0°C, the experimental results would differ in several ways:

Temperature Change: Instead of measuring the change in temperature of the water, the student would measure the change in temperature of the ice bath. As heat is transferred from the surroundings to the ice bath, the ice will melt and the temperature of the ice bath will increase until it reaches 0°C. The temperature change observed in the experiment would be different from that of the water bath.
Heat Capacity: The heat capacity of the ice bath would be different from that of the water bath. Ice has a lower heat capacity than water, meaning it requires less heat energy to raise its temperature. This would affect the amount of heat absorbed or released during the reaction and lead to different experimental results.
Enthalpy Change: The enthalpy change calculated from the experiment would be specific to the reaction being studied. However, the enthalpy change determined using an ice bath would be based on the heat exchange with the ice bath, rather than the water bath. The enthalpy change values would differ due to the different heat capacities and temperature changes involved.
Overall, using an ice bath instead of a water bath would result in different temperature changes, heat capacities, and enthalpy change values in the experimental results.

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Answer:

2m

Explanation:

The closer the objects are, the more gravitational force there is

Answer:

c

Explanation:

Out of the given options, shovel, pushup, and seesaw are all examples of levers. Hence, the one that is not an example is :

Explanation:

Given that,

The x-component is 8 m/s east and y-component is 14.5 m/s North.

(a) As both x and y components are perpendicular to each other. Their resultant is given by :

\(R=\sqrt{x^2+y^2} \\\\R=\sqrt{(8)^2+(14.5)^2} \\\\R=16.56\ m/s\)

(b) Let \(\theta\) is the resultant vector. So,

\(\tan\theta=\dfrac{y}{x}\\\\\theta=\tan^{-1}(\dfrac{y}{x})\\\\\theta=\tan^{-1}(\dfrac{14.5}{8})\\\\\theta=61.11^{\circ}\)

Hence, the resultant is 16.56 m/s and the angle of the resultant vector is 61.11 degrees.

Answer:  7.723s

Explanation:

given data:

initial velocity = 7.56 m/s.

friction = 0.0695.

change in velocity = 2.32 m/s

Solution:

\(ax = \frac{-Fk}{m}\)

\(ax = \frac{-ukFN}{m}\)

\(ax = \frac{-ukmg}{m}\)

\(ax = -ukg\)

\(recall = v0x +axt\)\(.......eqn1\)

\(t = \frac{vx - v0x}{ax}\) \(........eqn2\)

\(substitute\)  \(ax\)  \(into\)  \(eqn 2\)

\(t = \frac{vx -v0x}{-ukg}\)

\(t = \frac{2.32m/s - 7.56m/s}{-(0.0695)(9.80m/s^{2})}\)

\(t= 7.723seconds\)

(a). The thermal efficiency is approximately 22.9%.

(b). The heat discarded in each cycle is approximately 1.6063 × \(10^6\) J.

(c). The mass of fuel burned in each cycle is approximately 0.035 kg.

(d). The engine's power output is approximately 222 kW or 297.6 hp.

To solve this problem, let's use the following formulas and conversions:

Given:

Heat input (Qin) = 1.61 × \(10^6\)J

Work done per cycle (W) = 3700 J

Heat of combustion of gasoline (H) = 4.60 × \(10^7\) J/kg

Cycles per second (f) = 60.0 cycles/s

(a) To calculate the thermal efficiency:

Thermal efficiency (η) = (Useful work output / Heat input) * 100%

η = (W / Qin) * 100%

η = (3700 J / 1.61 × 10^6 J) * 100%

η ≈ 0.229 * 100%

η ≈ 22.9%

(b) To calculate the heat discarded in each cycle:

Heat discarded = Heat input - Useful work output

Heat discarded = Qin - W

Heat discarded = 1.61 × \(10^6\) J - 3700 J

Heat discarded ≈ 1.6063 × \(10^6\) J

(c) To calculate the mass of fuel burned in each cycle:

Heat input = Heat of combustion * Mass of fuel burned

Mass of fuel burned = Heat input / Heat of combustion

Mass of fuel burned = 1.61 × \(10^6\) J / 4.60 × \(10^7\) J/kg

Mass of fuel burned ≈ 0.035 kg

(d) To calculate the power output in kilowatts and horsepower:

Power output (P) = Work done per cycle * Number of cycles per second

P = W * f

P = 3700 J * 60.0 cycles/s

P = 2.22 × \(10^5\) J/s

Power output in kilowatts:

P(kW) = P / 1000

P(kW) ≈ 2.22 × \(10^5\) J/s / 1000

P(kW) ≈ 222 kW

Power output in horsepower:

P(hp) = P / 745.7

P(hp) ≈ 2.22 × \(10^5\) J/s / 745.7

P(hp) ≈ 297.6 hp

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