for a little over two weeks in february 2005, the gates by christo and jeanne-claude were installed in new york city's central park. how long had they worked on the project?

The value of z if x = 36 and y = 6 is 42

Suppose that y varies directly with x and inversely with z, hence the required expression will be:

y = kx/z

If  y = 4 when x = 8 and z = 14 then;

4 = k(8)/14

8k = 56

k = 7

To  find z when x = 36 and y = 6, we  will have:

6 = 7(36)/z
1 = 7(6)/z

z = 42

Hence the value of z if x = 36 and y = 6 is 42

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Answer:

Keep it simple. Answer:

y=kx/z

  k=7

 z=42

Step-by-step explanation:

the answer were to the question is 7.29

Answer:

The distance of the run is 10 miles

The distance of the bicycle race is 69 miles

Step-by-step explanation:

Let:

The run: r = 5t

The bicycle race: 79 - r = 23(5 - t)

Simplify the bicycle race:

Now we have two equations set up for r

We know that r = r, so 5t must equal 23t - 36

Now we know that the run took 2 hours.

Plug it back into the equation for the run to find the distance for the run

The run is 10 miles

To solve for the bicycle race, we simply subtract 10 from 79, because we know that the two distances combined are 79.

The bicycle race is 69 miles.

-Chetan K

Answer:

Step-by-step explanation:

Let r represent the distance run. Then 79-r is the distance biked. The total time is ...

  time = distance/speed

  5 = (r/5) +(79-r)/23 . . . . sum of time running and time biking

  575 = 23r +5(79 -r) . . . . multiply by 115

  180 = 18r . . . . . . . . . . . . . subtract 395

  10 = r . . . . . . . . . . . divide by 18

  79-r = 69 . . . . . . distance biking

The distance of the run is 10 miles; the bicycle race is 69 miles.

The appropriate regression model depends on the stationarity properties of both the dependent and independent variables, as well as the error term. The researcher can use a standard OLS regression model with first-order differencing of both Y and X.

In the first scenario, both Y and X are I(0), which means they are stationary time series. In this case, the researcher can perform a standard linear regression analysis, as the stationary series would lead to a stable long-run relationship. The answer from this model will be reliable and less likely to suffer from spurious regressions. In the second scenario, Y is I(2) and X is I(0). This implies that Y is integrated of order 2 and X is stationary. In this case, the researcher should first difference Y twice to make it stationary before performing a regression analysis. However, this approach might not be ideal as the integration orders differ, which can lead to biased results.

In the third scenario, Y and X are both I(1) and the error term is I(0). This indicates that both Y and X are non-stationary time series, but their combination might be stationary. The researcher should employ a co-integration analysis, such as the Engle-Granger method or Johansen test, to identify if there is a stable long-run relationship between Y and X. If co-integration is found, then an error correction model can be used for more accurate predictions.

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For equation 1;

For equation 2;

For equation 3;

Its C.

Negative x Negative is positive, so its not A or D.

Positive x Positive is Positive, so its not B either.

C is your option because Positive x Negative is Negative, and vice verca.

Answer:

C

Step-by-step explanation:

this is because a negative number multiplied with a negative number gives you a positive, a positive number multiplied with a positive number gives you a positive but a negative number multiplied with a positive gives you a negative so the answer is C.

for more information watch videos about the rules of positive and negative numbers.

Answer:

that is funny. That is where my dad was born and now he has horrible breathing issues

Step-by-step explanation:

Answer:

, Im in Arizona. Also what's this question about, that you disagree or agree?

A person leaves their home at noon walking toward a restaurant located 16 miles away If the person walks constantly at 2.5 miles per hour, the person arrive at the restaurant at 6:24 PM.

To determine the time it will take for the person to arrive at the restaurant, we can use the formula:

Time = Distance / Speed

Given:

Distance to the restaurant = 16 miles

Walking speed = 2.5 miles per hour

Substituting these values into the formula, we can calculate the time:

Time = 16 miles / 2.5 miles per hour

Time = 6.4 hours

Since we know the person leaves their home at noon, we can add the calculated time to noon to find the arrival time:

Arrival Time = Noon + 6.4 hours

To express the arrival time in a standard 12-hour clock format, we convert 6.4 hours into hours and minutes:

0.4 hours * 60 minutes/hour = 24 minutes

So, the person will arrive at the restaurant at approximately 6 hours and 24 minutes after noon.

Therefore, the person will arrive at the restaurant at approximately 6:24 PM.

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10+10+10+10+10+10+9=69

Answer:

its simple girl;;;;;

ans=69

(Ohh dear don't leave the question with this big pts!!! )

The maximum value of the function is 9, and the minimum value of the function is −9.

We have function is f(x,y)=x²−y² and constraint is x²+y²=9,

For getting the extreme values of the function subject to the given constraint using Lagrange multipliers

Firstly we will form the Lagrangian function L (x,y,λ) as follows:

L (x,y,λ)=f(x,y)+λ(g(x,y))

Where f(x,y) = x²−y²and g(x,y) =  x²+y² = 9

Thus, L (x,y,λ) =  x²−y² + λ(x²+y² = 9)

Now we have to find the partial derivatives of L (x,y,λ) with respect to x,y and λ and equate them to 0 for finding the critical points.

\(L_x= 2x+2 \lambda x = 0\) .......(1)

\(L_y= -2y+2 \lambda y = 0\) ........(2)

\(L_{\lambda}= x^2+y^2-9 = 0\) (3)

From the above equations (1) and (2),we get

2x+2λx = 0 ⇒ x(1+λ) = 0

Thus, x = 0 and λ = -1

Similarly, y = 0 and λ = 1

From equations (1) and (2), we have

2λx = -2x  ⇒ λ = -1

Therefore, x = 0 is not acceptable

From equations (1) and (2), we have

2λy = 2y ⇒ λ = 1

Therefore, y = 0 is not acceptable

Now using equation (3),we have

x²+y²-9 = 0

⇒ x²+0-9 = 0

⇒ x = ±3

Substituting x = 3 in equation (1), we get λ = -1

Hence, the first solution is (x,y) = (3,0)

Similarly, substituting x = -3 in equation (1), we get λ = -1

Hence, the second solution is (x,y) = (-3,0)

Now we will classify the obtained critical points as maxima or minima or saddle points

For finding the nature of critical points, we will form a Hessian matrix H of second partial derivatives of the Lagrangian function L at the critical point (x,y) as follows:

\($$ H = \left[\begin{array}{ccc} L_{xx}&L_{xy}\\L_{yx}&L_{yy}\\\end{array}\right] \\\)

On evaluating the Hessian matrix H at the critical point (x,y) = (3,0), we get the Hessian matrix as

\($$ H =\left[\begin{array}{ccc}4&0\\0&-2\\\end{array}\right]\)

Here, the determinant of the Hessian matrix,

\($$ D(H) = \left[\begin{array}{ccc} L_{xx}&L_{xy}\\L_{yx}&L_{yy}\\\end{array}\right] \\\)

= (4)(-2)-(0)(0)

= -8 < 0

Hence, Hessian matrix H is negative definite at the critical point (3,0)

Therefore, the function has a local maximum at (3,0)

On evaluating the Hessian matrix H at the critical point (x,y) = (-3,0), we get Hessian matrix as

\($$ H =\left[\begin{array}{ccc}4&0\\0&-2\\\end{array}\right]\)

Here, the determinant of the Hessian matrix,

\($$ D(H) = \left[\begin{array}{ccc} L_{xx}&L_{xy}\\L_{yx}&L_{yy}\\\end{array}\right] \\\)

= (4)(-2)-(0)(0)

= -8 < 0

Hence, Hessian matrix H is negative definite at the critical point (-3,0)Therefore, the function has a local maximum at (-3,0)Hence, the extreme values of the function are as follows:

The maximum value of the function f(x,y) = x² - y², subject to the given constraint x²+ y² = 9, is 9 at (3,0) and (-3,0)

Hence, the solution is -9.

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Answer:

27777/100000

Step-by-step explanation:

i hope its right

The parent function of a quadratic equation is f(x) = x². The function that is transformed to the right and down from the parent function with a minimum is given by f(x) = a(x - h)² + k.

The equation has the same shape as the parent quadratic function. However, it is shifted up, down, left, or right, depending on the values of  a, h, and k.

For a parabola to have a minimum value, the value of a must be positive. If a is negative, the parabola will have a maximum value.To find the vertex of the parabola in this form, we use the vertex form of a quadratic equation:f(x) = a(x - h)² + k, where(h, k) is the vertex of the parabola.The vertex is the point where the parabola changes direction. It is the minimum or maximum point of the parabola. In this case, the parabola is transformed to the right and down from the parent function, f(x) = x². Therefore, h > 0 and k < 0.

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Answer: B

Step-by-step explanation:

Answer: Table 3

Step-by-step explanation:

exponential relationship means the y value is increasing/decreasing exponentially

In table 1: the value of y is NOT increasing/decreasing exponentially as 2 is being added continuously (linear), so not table 1

In table 2: the value of y is NOT increasing/decreasing exponentially as 4 is being subtracted continuously (linear), so not table 2

In table 3: the value of y IS increasing exponentially as the y variable is multiplied by 2, so table 3

In table 4: the value of y is NOT increasing exponentially as the y variable is only being increased by 5 constantly (linear), so not 4

The money in the account at the end of the 4 years is $1034

What is compound interest?

Compound interest, also known as interest on principal and interest, is the practice of adding interest to the principal amount of a loan or deposit.

Now we are given that the initial amount deposited in the account is $1000

This account is giving 0.85% And we have to figure out how much amount will be there

We use compound interest formula to find the amount

\(A= P(1+r/n)^{nt}\\\\A= 1000(1+0.0085)^{4}\\A = 1000(1.034)\\A= 1034\)

Hence the amount will be after 4 years is $1034.

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If the atmospheric pressure of 5 is measured in millibars, it would correspond to a pressure of 0.5 kPa or a pressure of approximately 1.47 inHg. However, this value should be considered as a rough estimate and would still be subject to the variability of atmospheric conditions.

It is not possible to accurately determine the altitude at which atmospheric pressure reaches 5 without additional information about the context and conditions of the atmosphere being considered. The atmospheric pressure at a given altitude can vary widely depending on factors such as temperature, humidity, and atmospheric composition.

However, in general, atmospheric pressure decreases with increasing altitude. At sea level, the standard atmospheric pressure is about 101.3 kilopascals (kPa). At an altitude of approximately 5.6 kilometers, the atmospheric pressure drops to around 50 kPa. However, this value can vary greatly depending on the conditions of the atmosphere being considered.

It is worth noting that atmospheric pressure is typically measured in units of kilopascals (kPa), millibars (mb), or inches of mercury (inHg). The conversion between these units is as follows:

1 kPa = 10 mb = 0.2953 inHg

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Your question seems incomplete. I could not find the exact question details online so I answered in general.

Answer:

26-25=1

so none

I guess that is the answer

Answer:

we can study the relationship between the two given variables or quantities

The parabolas with respect to their positions are y = f(x + 3), y = f(x + 2), y = f(x - 1/2), y = f(x - 4) and f = (x - 7)

The parent function is given as:

f(x) = x^2

The parabolas are given as:

y = f(x - 4), y = f(x + 3), y = f(x - 7), y = f(x + 2) and f = (x - 1/2)

The transformation from the parent function to each of the parabola is a horizontal translation.

This means that the y coordinate of their vertices are the same.

Arrange the parabolas starting from the left translations

y = f(x + 3), y = f(x + 2), y = f(x - 1/2), y = f(x - 4) and f = (x - 7)

Hence, the parabolas with respect to their positions are y = f(x + 3), y = f(x + 2), y = f(x - 1/2), y = f(x - 4) and f = (x - 7)

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The numerical length of line CD is 15

From the question, we are to determine the numerical length of line CD

From the given information,

Point C is on line segment BD

Thus, we can write that

BC + CD = BD

Also, from the given information

BC = x+4

CD = 5x

BD = 5x +7

Therefore,

x+4 + 5x = 5x + 7

6x + 4 = 5x + 7

Collect like terms

6x - 5x = 7 - 4

x = 3

Now, substitute the value of x into the equation for line CD

CD = 5x

CD = 5×3

CD = 15

Hence, the numerical length of line CD is 15

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Answer:

102 in^3.

Step-by-step explanation:

Volume of the  ice cream container = 10*14*12 = 1680 in^3.

Volume of the  sherbet container = 11*18^9 = 1782 in^3.

So the answer is 1782 - 1680

= 102 in^3.

Answer:

Circumcenter

Circumcenter is the only center point on the edge of a triangle. this is true in the case of the right-angle triangle. It exactly lies on the midpoint of the hypotenuse. Circumcenter is the point of intersection of the perpendicular bisector of sides of triangles.

The circumcenter of a right triangle is the only center point that lies on the edge of a triangle.

A pair of numbers which describe the exact position of a point on a cartesian plane by using the horizontal and vertical lines is called the coordinates.

Given that;

To find the only center point that lies on the edge of a triangle.

Now, We know that;

The circumcenter of a right triangle is the only center point that lies on the edge of a triangle.

Thus, The correct statement is,

The circumcenter of a right triangle.

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The variables that the organizer can consider removing from the regression model are the Number of male visitors and Number of performance.

Based on the regression table provided, we can answer this question. The following is the regression table:Regression output table for night street fair variableNameCoefficientStandard Errort-StatP-ValueConstantb0.340.1402.430.023Number of male visitorsb10.6130.51320.750.462Number of female visitorsb10.9070.57918.830.000Number of retail standsb0.1160.0452.570.016Number of food (and beverage) standsb0.3160.0575.500.000Number of performanceb0.1460.1071.360.184The null hypothesis is rejected if p-value < 0.1; that is, there is a significant difference between the independent and dependent variables. The p-value of the Number of male visitors, the Number of female visitors, the Number of retail stands, the Number of food (and beverage) stands, and the Number of performances variables are 0.462, 0.000, 0.016, 0.000, and 0.184, respectively. As a result, the variables that are significant at the 10% level are the Number of female visitors, the Number of retail stands, and the Number of food (and beverage) stands. Therefore, the organizer should consider removing the Number of male visitors and Number of performance variables from the regression model. The variables that the organizer can consider removing from the regression model are the Number of male visitors and Number of performance.

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Answer: 480in^2

Step-by-step explanation:

The formula for the area of a triangle:  \(A = \frac{h*a}{2}\)

There are 4 sides on the roof so \(A = 4*\frac{12in * 20in}{2} = 480in^{2}\)

Answer:

No, Ssa triangle always not have two solutions

Step-by-step explanation:

the solution can be one, two or there will be no dolution. So this statement is false.

The length of the third side of the quadrilateral is 7.5 cm.

A quadrilateral is a polygon that has four sides and four angles. The sum of interior angles in a quadrilateral is 360°. Types of quadrilateral are square, rectangle, rhombus, kite and so on.

Let x represent the length of the third side, hence:

x = 5 + (5 * sin(20)) + (5 * sin(10)) = 7.5 cm

The length of the third side of the quadrilateral is 7.5 cm.

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Answer:

I just took the k12 quiz its 7.5 100%

Step-by-step explanation:

Answer:

1) 24

2) 25

Step-by-step explanation:

Given:

2a + 3b = 8

4x + 10y = 50

.

1)

\( \frac{6a + 9b}{2a + 3b} = \frac{3(2a + 3b)}{2a + 3b} = 3\)

Since the second expression is 3 times greater then the previous one, the product will also be 3 times greater:

6a + 9b = 3 × 8 = 24

.

2)

\( \frac{2x + 5y}{4x + 10y} = \frac{2x + 5y}{2(2x + 5y)} = \frac{1}{2} = 0.5\)

The second expression's value is two times smaller than the first one's, so the product will also be two times smaller:

2x + 5y = 0,5 × 50 = 25

Given the demand function P=$6.00-0.100(Qd)

a) at a price of $2.00, the quantity demanded is 40 units, thus, Total Revenue = $80

b) at a price of $1.00, the quantity demanded is 50 units, thus, Total Revenue  = $50

c) Since the price elasticity of demand is less than 1, demand is price inelastic between these two prices.

Given the demand function P=$4.80-0.060(Qd)

d)
The optimal price to maximize total revenue is $2.40 and the optimal quantity is 40 units. TR = $96

e) When the price is $3.00 and the quantity demanded is 30, TR = $90

f) When the price is $1.80 and the quantity demanded is 50, the total revenue = $90

g) If demand is price elastic and the market price is $3.00, total revenue can be increased by reducing the price.

A demand function is a mathematical equation that describes the relationship between the price of a good or service and the quantity of that good or service that consumers are willing and able to purchase at that price.

a. When the price is $2.00, the quantity demanded can be calculated by setting Qd equal to 2.00 in the demand equation:

Qd = (6.00 - 0.100Qd)

2.00 = (6.00 - 0.100Qd)

0.100Qd = 4.00

Qd = 40

Therefore, at a price of $2.00, the quantity demanded is 40 units. The total revenue can be calculated by multiplying the price by the quantity demanded:

Total Revenue = Price x Quantity Demanded = 2.00 x 40 = $80

b. When the price is $1.00, the quantity demanded can be calculated in the same way:

Qd = (6.00 - 0.100Qd)

1.00 = (6.00 - 0.100Qd)

0.100Qd = 5.00

Qd = 50

Therefore, at a price of $1.00, the quantity demanded is 50 units. The total revenue can be calculated as:

Total Revenue = Price x Quantity Demanded = 1.00 x 50 = $50

c. To determine the price elasticity of demand between these two prices, we need to compare the percentage change in quantity demanded to the percentage change in price.

At a price of $2.00, the quantity demanded is 40 units. At a price of $1.00, the quantity demanded is 50 units. The percentage change in quantity demanded can be calculated as:

% Change in Quantity Demanded = (New Quantity Demanded - Old Quantity Demanded) / Old Quantity Demanded x 100%

= (50 - 40) / 40 x 100% = 25%

The percentage change in price can be calculated as:

% Change in Price = (New Price - Old Price) / Old Price x 100%

= (1.00 - 2.00) / 2.00 x 100% = -50%

The price elasticity of demand between these two prices can be calculated as:

Price Elasticity of Demand = % Change in Quantity Demanded / % Change in Price

= 25% / -50%

= -0.5

Since the price elasticity of demand is less than 1, demand is price inelastic between these two prices. This means that a change in price will result in a proportionately smaller change in quantity demanded.

d). To find the optimal price and quantity to maximize total revenue, we need to take the derivative of the total revenue function with respect to quantity and set it equal to zero.

Total Revenue = Price x Quantity Demanded

TR = (4.80 - 0.060Qd)Qd

TR = 4.80Qd - 0.060Qd^2

Taking the derivative of TR with respect to Qd:

dTR/dQd = 4.80 - 0.120Qd

Setting dTR/dQd equal to zero:

4.80 - 0.120Qd = 0

Qd = 40

Substituting Qd = 40 into the demand equation to find the optimal price:

P = 4.80 - 0.060(40)

P = 2.40

Therefore, the optimal price to maximize total revenue is $2.40 and the optimal quantity is 40 units. The total revenue can be calculated as:

TR = P x Q = 2.40 x 40 = $96

e. When the price is $3.00 and the quantity demanded is 30, the total revenue can be calculated as:

TR = P x Q = 3.00 x 30 = $90

f. When the price is $1.80 and the quantity demanded is 50, the total revenue can be calculated as:

TR = P x Q = 1.80 x 50 = $90

g. If demand is price elastic and the market price is $3.00, total revenue can be increased by reducing the price. This is because the percentage increase in quantity demanded will be greater than the percentage decrease in price, resulting in a net increase in total revenue.


Therefore, the company could consider lowering the price from $3.00 to a price closer to the optimal price of $2.40 to increase total revenue.

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The median is the best measure of center, and it equals 19.

The median is a measure of central tendency that represents the middle value of a dataset when it is arranged in order. Specifically, it is the value that separates the dataset into two halves, with half of the data falling below the median and half of the data falling above the median.

The appropriate measure of center for the given data is the median, which is the middle value when the data is arranged in numerical order.

From the given box plot, we can see that the box extends from 17 to 21 on the number line, with a line in the box at 19. This means that 50% of the data falls between 17 and 21, with the middle value (median) being 19.

Therefore, the correct answer is:

The median is the best measure of center, and it equals 19.

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The concept of statistical significance is mathematically defined and widely accepted by those who use it to assess the usefulness of scientific claims.

However, there is no single definition for practical significance. It is subjective in nature, experiential, and each person decides what it is based on their own experiences.

Thus, it is clear that while Practical significance lacks a common definition, statistical significance has a mathematical definition and is widely accepted by those who use it to assess the usefulness of scientific claims. It is a subjective concept that each person decides for themselves based on their personal experiences.

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