For each of the following studies, say whether you would use at test for dependent means or at test for independent means. a) A researcher randomly assigns a group of 25 workers to a new job skill training program and 24 other workers to receive the standard job skills program, and then measures how well they all do on a job skills test. Either Neither Dependent Independent

The average number of viewers over the two weeks written in scientific notation is 3.85 × 10^8. option C

Average number of viewers over the two weeks = (First week + Second week) / 2

= {(3.6 x 10⁴) + (4.1 x 10⁴)} / 2

= {3.6 + 4.1 × 10^(4×4) } / 2

= (7.7 × 10^16) / 2

= 3.85 × 10^8

Therefore, the average number of viewers over the two weeks written in scientific notation is 3.85 × 10^8.

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Answer:

n is 10 if that's what your asking

Answer:

n=10

Step-by-step explanation:

if you multiply 3.687 by ten, it carries the decimal place over making 36.87, so ten is the answer

The height the anchor begins to drop is 17.5 m

Since a Naval Carrier dropped anchor off the coast. The massive anchor drops at 3.5 m/s and will be 52.5 meters under the surface of the water after 20 seconds.

Let

The total height the anchor drops is thus H = h + h'

Now, the total height the anchor drops H = vt where

So, equating both equations, we have

vt = h + h'

Making h subject of the formula, we have that

h = vt - h'

Given that

Substituting the values of the variables into the equation, we have that

h = vt - h'

h = 3.5 m/s × 20 s - 52.5 m

h = 70 m - 52.5 m

h = 17.5 m

So, the anchor drops 17.5 m

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Answer:

He can buy five DVDs plus shipping and handling. And after that he would have $4.06 left so five is the most DVDs he can buy.

Answer:

B

Step-by-step explanation:

It just is

Answer:

Its b

Step-by-step explanation:

I just took the test. Hope this helps <3

The significance level of 0.01 indicates that we want to use a 1% level of significance to evaluate the evidence against the null hypothesis.

The null and alternative hypotheses for testing the claim that the majority of college students' cell phone bills are paid by their parents can be stated as follows:

Null hypothesis (H0): The majority of college students' cell phone bills are not paid by their parents.

Alternative hypothesis (Ha): The majority of college students' cell phone bills are paid by their parents.

In this scenario, the null hypothesis assumes that the proportion of college students whose parents pay their cell phone bills is less than 50% (not a majority), while the alternative hypothesis suggests that the proportion is greater than or equal to 50% (a majority). The significance level of 0.01 indicates that we want to use a 1% level of significance to evaluate the evidence against the null hypothesis.

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If each person eat one quarte (1/4) of the cake, this means that only 4 people can eat from one cake, as:

Each person eats 2 pieces of 1/8 of the cake, as 2*1/8=2/8=1/4.

Answer: 4 people can eat cake.

The component of statistical methodology that encompasses the collection, organization, and summarization of data is referred to as descriptive statistics.

Descriptive statistics is a fundamental aspect of statistical methodology that focuses on the initial stages of data analysis. It involves the collection of data through various methods such as surveys, experiments, or observational studies. This data is then organized and structured in a systematic manner to facilitate a comprehensive understanding of its characteristics.

The first step in descriptive statistics is data collection. This can involve various techniques such as sampling, where a subset of the population is selected to represent the entire group. The collected data can be quantitative (numerical) or qualitative (categorical), depending on the nature of the study.

Once the data is collected, it needs to be organized in a meaningful way. This can involve sorting, categorizing, and arranging the data into different groups or categories. For quantitative data, measures such as frequency distributions, histograms, and scatter plots can be used to organize and display the data. For qualitative data, methods such as tables, charts, or graphs may be employed to summarize the information.

Finally, descriptive statistics involves summarizing the collected and organized data to extract key insights and characteristics. This can include measures such as central tendency (mean, median, mode), variability (range, variance, standard deviation), and correlation. These measures provide a concise summary of the data, enabling researchers to gain a better understanding of its overall patterns, trends, and distribution.

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The ratio of C:D:F is 5:3:18.

The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.

here, we have,

given that,

The ratio of C:D is 5:3,

the ratio of F:D is 6:1.

i.e. F:D= 18:3

now,

C:D:F= 5:3:18.

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Answer:

-2a = 18

-2     -2 Divide by -2 in order to have A alone

a = -9

The area of the circle is approximately 866.36 cm (sqr). The circumference of a circle can be used to find its radius. The formula for the circumference of a circle is given:

C = 2πr

C is the circumference, π is the mathematical constant pi (22/7), and r is the radius. Given the circumference of the circle is 246 cm, we can find the radius by rearranging the formula:

r = C / (2π) = 246 / (2 * 22/7) = 246 / 44 * 7/2 = 246 / 44 * 7/2 = (246 * 7/2) / 44 = (246 * 7) / (2 * 44) = (246 * 7) / 88 = (1722) / 88 = 19.68 cm

Now that we have found the radius, we can use it to find the area of the circle. The formula for the area of a circle is given by:

A = πr^2

Where A is the area, π is the mathematical constant pi (22/7), and r is the radius. Plugging in the value of the radius we found earlier:

A = π * 19.68^2 = 22/7 * 19.68^2 = 22/7 * 386.1184 = 866.36 cm\(square\)

So the area of the circle is approximately 866.36 cm\(square\).

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Answer:

C

Step-by-step explanation:

P = S1t - S2t ← factor out t from each term on the right side

P = t(S1 - S2) ← isolate t by dividing both sides by S1-S2

\(\frac{P}{S1-S2}\) = t

It means that the artist charges $35 for every additional hour of the lesson, making it the hourly rate for their classes.

Part a: The expression to represent the total cost, c, of lessons as a function of the number of hours, h, of the lesson is:
c = 35h + 50
Part b: The rate of change in the expression is 35, which represents the hourly rate for the artist's classes. It means that for each hour of the lesson, the cost increases by $35. Therefore, if a student takes a 2-hour lesson, the cost would be $120 (35 x 2 + 50).
Part A: The expression to represent the total cost (c) of lessons as a function of the number of hours (h) of the lesson is: c = 50 + 35h.
Part B: The number 35 in the expression is the rate of change. It means that the artist charges $35 for every additional hour of the lesson, making it the hourly rate for their classes.

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Answer: 3

Step-by-step:

15/5=3

Each segment of a fifteen-foot beam divided into five equal parts is 3 feet long.

Since acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

To find out the length of each segment of a fifteen-foot beam divided into five equal parts, we have to divide the total length of the beam by the number of segments it is being divided into.

We can do this using the division operation as shown below:

15 ÷ 5 = 3

Therefore, we can conclude that each segment of a fifteen-foot beam divided into five equal parts is 3 feet long.

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Answer:

1.28 * 10^10

Step-by-step explanation:

Area Code:  8 * 2 * 10

7 digit number: 8 * 10 * 10 * 10 * 10 * 10 * 10

The total number of area codes is 160

8,000,000 * Area Codes

1.28*10^10

The optimal values of these parameters are:

a. β₁ = 0

b. β₂ = 0

The linear regression y = β1 + β2x + e, assuming that the sum of squared errors (SSE) takes the following form:

SSE = 382 + 681 + 382 + 18β1β2

Derive the partial derivatives of SSE with respect to β1 and β2 and solve the optimal values of these parameters.

Given that SSE = 382 + 681 + 382 + 18β1β2 ∂SSE/∂β1 = 0 ∂SSE/∂β2 = 0

Now, we need to find the partial derivative of SSE with respect to β1.

∂SSE/∂β1 = 0 + 0 + 0 + 18β2 ⇒ 18β2 = 0 ⇒ β2 = 0

Therefore, we obtain the optimal value of β2 as 0.

Now, we need to find the partial derivative of SSE with respect to β2. ∂SSE/∂β2 = 0 + 0 + 0 + 18β1 ⇒ 18β1 = 0 ⇒ β1 = 0

Therefore, we obtain the optimal value of β1 as 0. Hence, the partial derivative of SSE with respect to β1 is 18β2 and the partial derivative of SSE with respect to β2 is 18β1.

Thus, the optimal values of β1 and β2 are 0 and 0, respectively.

Therefore, the answers are: a. β₁ = 0 b. β₂ = 0

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The area of the shaded sector of the circle is 16π units².

Suppose the circle has radius of 'r' units, then, its area is given as:

\(A = \pi \times r^2\)

sq. units

Since radius of a circle is half of its diameter, so if diameter is of 'd' length, then r= d/2, thus, area can be rewritten as:

\(\pi \times (\dfrac{d}{2})^2\)

sq. units

We are given that;

θ = r radians

r = 4 units

Now,

To convert radians to degrees, we use the formula:

Degrees = Radians × 180°/π

So,

θ = r × 180°/π

Substituting these values in the formula for area of a sector, we get:

Area of a sector = (r × 180°/π / 360°) × π(4)²

Simplifying, we get:

Area of a sector = r² units²

=16π units².

Therefore, by the area of a circle the answer will be 16π units².

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Answer:

water in quarts is in the first jar after 10th pour = 12/11

Step-by-step explanation:

Let X represent first jar and Y represents second jar.

Lets give the initial value of 2 to the first jar which is filled with water. Lets say there are two liters of water in first jar.

Lets give the initial value of 0 to the second as it is empty.

So before any pour, the values are:

X: 2

Y: 0

After first pour the value of jar X becomes:

Previously it was 2.

Now half of water is taken i.e. half of 2

2 - 1 = 1

So X = 1

The value of jar Y becomes:

The half from jar X is added to second jar Y which was 0:

After first pour the value of jar Y becomes:

0 + 1 = 1

Y = 1

After second pour the value of jar X becomes:

Previously it was 1.

Now third of the water in second jar Y is added to jar X

1 + 1/3

=  (3 + 1)/3

= 4/3

X = 4/3

After second pour the value of jar Y becomes:

Previously it was 1.

Now third of the water in Y jar is taken and added to jar X so,

1 - 1/3

=  (3 - 1)/3

= 2/3

Y = 2/3

After third pour the value of jar X becomes:

Previously it was 4/3.

Now fourth of the water in the first jar X is taken and is added to jar Y

= 3/4 * (4/3)

= 1

X = 1

After third pour the value of jar Y becomes:

Previously it was 2/3

Now fourth of the water in the second jar X is added to jar Y

= 2/3 + 1/4*(4/3)

= 2/3 + 4/12

= 1

Y = 1

After fourth pour the value of jar X becomes:

Previously it was 1

Now fifth of the water in second jar Y is added to jar X

= 1 + 1/5*(1)

= 1 + 1/5

=  (5+1) / 5

= 6/5

X = 6/5

After fourth pour the value of jar Y becomes:

Previously it was 1.

Now fifth of the water in Y jar is taken and added to jar X so,

= 1 - 1/5

= (5 - 1)  / 5

= 4/5

Y = 4/5

After fifth pour the value of jar X becomes:

Previously it was 6/5

Now sixth of the water in the first jar X is taken and is added to jar Y

5/6 * (6/5)

= 1

X = 1

After fifth pour the value of jar Y becomes:

Previously it was 4/5

Now sixth of the water in the first jar X is taken and is added to jar Y

= 4/5 + 1/6 (6/5)

= 4/5 + 1/5

= (4+1) /5

= 5/5

= 1

Y = 1

After sixth pour the value of jar X becomes:

Previously it was 1

Now seventh of the water in second jar Y is added to jar X

= 1 + 1/7*(1)

= 1 + 1/7

=  (7+1) / 7

= 8/7

X = 8/7

After sixth pour the value of jar Y becomes:

Previously it was 1.

Now seventh of the water in Y jar is taken and added to jar X so,

= 1 - 1/7

=  (7-1) / 7

= 6/7

Y = 6/7

After seventh pour the value of jar X becomes:

Previously it was 8/7

Now eighth of the water in the first jar X is taken and is added to jar Y

7/8* (8/7)

= 1

X = 1

After seventh pour the value of jar Y becomes:

Previously it was 6/7

Now eighth of the water in the first jar X is taken and is added to jar Y

= 6/7 + 1/8 (8/7)

= 6/7 + 1/7

= 7/7

= 1

Y = 1

After eighth pour the value of jar X becomes:

Previously it was 1

Now ninth of the water in second jar Y is added to jar X

= 1 + 1/9*(1)

= 1 + 1/9

=  (9+1) / 9

= 10/9

X = 10/9

After eighth pour the value of jar Y becomes:

Previously it was 1.

Now ninth of the water in Y jar is taken and added to jar X so,

= 1 - 1/9

=  (9-1) / 9

= 8/9

Y = 8/9

After ninth pour the value of jar X becomes:

Previously it was 10/9

Now tenth of the water in the first jar X is taken and is added to jar Y

9/10* (10/9)

= 1

X = 1

After ninth pour the value of jar Y becomes:

Previously it was 8/9

Now tenth of the water in the first jar X is taken and is added to jar Y

= 8/9 + 1/10 (10/9)

= 8/9 + 1/9

= 9/9

= 1

Y = 1

After tenth pour the value of jar X becomes:

Previously it was 1

Now eleventh of the water in second jar Y is added to jar X

= 1 + 1/11*(1)

= 1 + 1/11

= (11 + 1) / 11

= 12/11

X = 12/11

After tenth pour the value of jar Y becomes:

Previously it was 1.

Now eleventh of the water in Y jar is taken and added to jar X so,

= 1 - 1/11

=  (11-1) / 11

= 10/11

Y = 10/11

Answer:

6/11

Step-by-step explanation:

1/2 + (1/2)(2/11) = 6/11

sus

Answer:

Down below hope it helps :)

Step-by-step explanation:

The evidence "SAY" was only written once. It wasn't by the same article, the writer introduces two separate articles.

Kinda confused by this question but I think that's the answer.

Answer:

y intercept is 1/3 and the slope is 6

Step-by-step explanation:

Answer: 42

Step-by-step explanation:

5/6x - 7 = 28

Add 7 to both sides.

5/6x=35

Divide by 5/6 on both sides.

x = 42

To check your work, take 42 and multiply it by 5/6, then subtract it by 7. You shoulc end up with 28.

42(5/6) = 35

35 - 7 = 28

Answer:

42

Step-by-step explanation:

Forming an algebraic equation and solving:

 Let the number she thought = 'x'

5/6 of the number : \(\sf \dfrac{5}{6}*x\)

\(\sf \text{take away 7 from $\sf \dfrac{5}{6}*x$} : \dfrac{5}{6}x - 7 \\\)

\(\sf \dfrac{5}{6}x-7 = 28\\\\\text{\sf Add 7 to both sides}\\\\ \dfrac{5}{6}x= 28 +7 \\\\ \dfrac{5}{6}x = 35\)

Multiply both sides by 6

 5x = 35 * 6

Divide both sides by 5,

     \(\sf x = \dfrac{35*6}{5}\\\\ x = 7 * 6\\\\\boxed{\text{\bf The number is 42}}\)

Answer:

I think you have to add those up then divid by 2 if im not mistake.

Step-by-step explanation:i learn this in middle school

The angle between the stick and the base of the box is 77. 9 degrees

To determine the angle between the stick and the base, we have to know the trigonometric identities.

These identities are;

From the information given, we have;

sin A = FB/AB

Given that;

GB = 14.5cm

AB = 18. 6cm

substitute for the length of the sides, we have;

sin A = 14.5/18. 6

Divide the values, we have;

sin A = 0. 7796

Find the inverse sine

A = 77. 9 degrees

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Answer:

angle SXV

Step-by-step explanation:

Answer:

hope it helps you..............

Answer:

Step-by-step explanation:

The given surface is z = x²√3y + x2(3)y. The triangle has vertices at (0,0), (1,0), and (1,2).Let's graph the surface and unitary triangle:

Graph of surface z = x²√3y + x2(3)yGraph of triangle with vertices (0,0), (1,0), and (1,2)From the graph, we can see that the surface intersects the triangle along the lines x = 0, y = 0, and y = 2 - x. Therefore, we can set up a double integral for the area of the part of the surface that lies above the triangle:∬R z = x²√3y + x2(3)y dA, where R is the region enclosed by the triangle.

Using the limits of integration, the integral becomes∫₀¹ ∫₀^(2-x) x²√3y + x2(3)y dy dxThe inner integral with respect to y is∫₀^(2-x) x²√3y + x2(3)y dy = [x²(√3/2)y² + x²y³]₀^(2-x)= x²(√3/2)(2-x)² + x²(2-x)³= x²(2 - x)²(√3/2 + 2x)The outer integral with respect to x is∫₀¹ x²(2 - x)²(√3/2 + 2x) dxWe can expand the (2 - x)² term, and then use polynomial integration to evaluate the integral:∫₀¹ x²(2 - x)²(√3/2 + 2x) dx= ∫₀¹ (√3/2)x²(2 - x)² dx + ∫₀¹ 4x²(2 - x)³ dx= (√3/2) ∫₀¹ x²(4 - 4x + x²) dx + 4 ∫₀¹ x²(8 - 12x + 6x² - x³) dx= (√3/2) [4/3 - 2 + 1/3] + 4 [8/3 - 6/2 + 3/3 - 1/4]= (8/3)√3 - (14/3) ≈ 0.7714Therefore, the area of the part of the surface z = x²√3y + x2(3)y that lies above the triangle with vertices (0,0), (1,0), and (1,2) is approximately 0.7714.

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Answer:

\(\frac{1}{3}\)

Step-by-step explanation:

1. Convert both mixed numbers into improper fractions:

\(\frac{15}{4} x = \frac{5}{4}\)

2. Multiply both sides by 4:

4 · \(\frac{15}{4} x=\frac{5}{4}\) · 4

15x = 5

3. Isolate x:

x = 1/3

hope this helps!

The graph of the inequality y^2 > 0 represents all real numbers except y = 0.

The graph of the inequality y < 30 represents all real numbers less than 30.

The inequality y^2 > 0 represents all values of y where y squared is greater than 0. Since the square of any nonzero number is always positive, the solution is all real numbers except y = 0, which can be graphed as a number line with an open circle at y = 0.

The inequality y < 30 represents all values of y that are less than 30. This can be graphed as a horizontal line on the y-axis with an open circle at y = 30, indicating that 30 is not included in the solution set.

For the real-world applications, let's solve them step-by-step:

Two numbers add up to 144. One number is half the square of the other number.

Let's assume the two numbers are x and y. We have the following system of equations:

x + y = 144 (Equation 1)

x = (1/2)y^2 (Equation 2)

From Equation 1, we can solve for x in terms of y: x = 144 - y.

Substituting this into Equation 2, we get 144 - y = (1/2)y^2.

Rearranging the equation, we have: (1/2)y^2 + y - 144 = 0.

Now we can solve this quadratic equation for y. Once we find the value(s) of y, we can substitute them back into Equation 1 to find the corresponding values of x.

The squares of two numbers add to 1,156. The second number is the square root of three times the square of the first number.

Let's assume the two numbers are x and y. We have the following system of equations:

x^2 + y^2 = 1156 (Equation 1)

y = √(3x^2) (Equation 2)

Substituting Equation 2 into Equation 1, we get: x^2 + (√(3x^2))^2 = 1156.

Simplifying, we have x^2 + 3x^2 = 1156.

Combining like terms, we get 4x^2 = 1156.

Now we can solve this quadratic equation for x. Once we find the value(s) of x, we can substitute them back into Equation 2 to find the corresponding values of y.

Remember to leave a 1 line space between paragraphs in your answer.

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(i) To express σ as a product of disjoint cycles: \((1\;3)(2\;2)(3\;1)(4\;6\;5)(7\;4)(8)\)

A disjoint cycle is defined to be disjoined as they do not move or disturb any element that they have in common. Let's assume that one permutation cycle has the element A and the same element is there in another permutation cycle. Now, if the first permutation cycle changes the position of element A but the other cycle makes the element stay where it is in its own cycle then its called a disjoint cycle of permutation.

The cycles of σ are (1 3), (2), (4 6 5), and (7 4 8).

In the second cycle, 2 appears twice because the identity map is an element of S₈, which includes all the permutations of 1 through 8, including fixed points. So, the notation for the second cycle is (2).

The three other cycles are written in the standard notation.

The number of disjoint cycles is 4.

(ii) To express σ as a product of transpositions: σ = \((1\;3)(4\;5)(4\;6)(7\;8)(2)\)

Transposition is defined as a permutation of elements where in a list of elements, two of them exchange or swap places but the rest of the list and its elements stay the same then that process is called transposition.

Therefore, the product of transpositions is \((1\;3)(4\;5)(4\;6)(7\;8)(2)\)

(iii) To determine whether σ is an odd or even permutation: The product of the lengths of all cycles of σ is 2 × 1 × 3 × 3 = 18.

Therefore, σ is an even permutation.

(iv) To compute σ¹⁵⁵: Since σ is even, σ¹⁵⁵ is also even. Thus, \(\sigma^{155} = 1\)

Therefore, the answer is 1.

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