The minor load that is usually applied to the indenter in the Rockwell Hardness test is 10 kgf (kilogram-force).
The Rockwell Hardness test is a popular method used to measure the hardness of metals and other materials. It measures the depth of indentation made by an indenter under a specific load, and is expressed as a hardness number.
The Rockwell test uses two loads: a minor load and a major load. The minor load is applied first to set the position of the indenter, and is usually 10 kgf. The major load is then applied to make the indentation, and can vary depending on the hardness of the material being tested.
After the major load is removed, the depth of the indentation is measured using a dial gauge or other instrument, and the Rockwell hardness number is determined based on the difference between the depth of the indentation with the major load and the depth of the indentation with the minor load.
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A 70.0kg person walks from the ground to the roof of a 25.3 m tall building. How much gravitional Potential Energy does she have at the top of the building.
A-17,394.4
B/18,865.8 J
C-17,355.8 J
D-12,873.2 J
Answer:
i would say C
Explanation:
if im right can i get the crown?
Can a resultant forces' direction be north or south, or is it only East and West?
By moving her arms outward, an ice skater speeds up a spin, while moving her arms inward slows down a spin. Question options: True False
false
ITS TURE.When there is no torque acting on a body, its angular momentum is constant. Net force changes momentum, while net torque changes angular momentum.
Answer: false
Explanation:
Curie temperature is the temperature above whichparamagnetic material becomes ferromagnetic material
ferromagnetic material becomes diamagnetic material
ferromagnetic material becomes paramagnetic material
paramagnetic material becomes diamagnetic material
The Curie temperature is the temperature above which ferromagnetic material becomes paramagnetic material. Option B
The Curie temperature is defined as the temperature above which ferromagnetic material becomes paramagnetic material. At this temperature, the magnetic dipoles of the material become unaligned and the ferromagnetic material loses its magnetic properties.
Curie temperature is also called the Curie point or Curie temperature point. The transition from ferromagnetic to paramagnetic behavior above the Curie temperature is due to the breaking of the atomic-level magnetic domains that are aligned below the Curie temperature.
This transition is due to the thermal energy becoming sufficient to overcome the exchange coupling between the magnetic dipoles and therefore, the materials will exhibit paramagnetic behavior.
The Curie temperature is a key parameter in the study of magnetism and magnetic materials and has a significant impact on the behavior of ferromagnetic materials. The Curie temperature varies with the type of material and it can be used to distinguish different types of magnetic materials. Option B
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An Indy car racer traveling at 15.0 meters per second slows as he makes a pit stop. If he decelerates at 2.5 meters per second squared, he was
away from the pit when he started braking.
meters
Answer:
x = 45 [m]
Explanation:
To solve this problem we must use the following kinematics equation:
\(v_{f}^{2} = v_{i}^{2}-(2*a*x)\)
where:
Vf = final velocity = 0
Vi = initial velocity = 15 [m/s]
a = desacceleration = 2.5 [m/s^2]
x = distance [m]
Note: the negative sign in the equation above, is because the car slows down.
0^2 = 15^2 - (2*2.5*x)
2*2.5*x = 15^2
x = 45 [m]
A material which lets energy flow through it easily is called a
Answer:
The ability of electrical energy to flow through materials is called conduction. Materials that allow electricity to easily flow are called conductors. Think of a conductor on a train. ... Materials that do not allow electricity to pass easily through them are called insulators.
I hope it's helpful!
a jogger is running down a a path at 10m/s when he hears a police siren (with a frequency of 1000hz) in front of him, leaving at a speed of 40m/s. what frequency does the jogger hear
The frequency the Jogger hears if he hears a police siren (with a frequency of 1000hz) in front of him, leaving at a speed of 40m/s is 921.05 Hz.
To determine the frequency the jogger hears, we can use the Doppler effect formula, which accounts for the relative motion of the source (police siren) and the observer (jogger). The formula is:
f_observed = f_source × (v_sound + v_observer) / (v_sound + v_source)
Here, f_observed is the frequency the jogger hears, f_source is the frequency of the police siren (1000 Hz), v_sound is the speed of sound (approximately 340 m/s), v_observer is the speed of the jogger (10 m/s), and v_source is the speed of the police siren (40 m/s).
Plugging the values into the formula:
f_observed = 1000 × (340 + 10) / (340 + 40)
f_observed = 1000 × (350) / (380)
f_observed ≈ 921.05 Hz
So, the jogger hears a frequency of approximately 921.05 Hz when the police siren is in front of him and moving away at 40 m/s.
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2. A 100Ω, 300Ω, and 200Ω resistor are all connected in parallel. What is the resistance?
When resistors are connected in parallel, the total resistance is calculated as:
1/R(total) = 1/R(1) + 1/R(2) + 1/R(3) + ...
So for this question, we can plug in the values:
1/R(total) = 1/100 + 1/300 + 1/200
1/R(total) = 0.01 + 0.003333 + 0.005
1/R(total) = 0.019333
R(total) = 1/0.019333
R(total) = 51.67Ω
The electrical resistance of an object is a measure of its opposition to the flow of electric current. Its reciprocal quantity is electrical conductance, measuring the ease with which an electric current passes. Electrical resistance shares some conceptual parallels with mechanical friction. The SI unit of electrical resistance is the ohm (Ω), while electrical conductance is measured in siemens (S) (formerly called the 'mho' and then represented by ℧).
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what are some activities you can do on a regular basis? Physical education
activities you can do on a regular basis for physical education?
If so
WalkingGardeningDancingBicyclingSwimmingYogamri systems are generally how many times stronger than a refrigerator magnet
MRI systems are generally thousands of times stronger than a refrigerator magnet. The strength of a magnet is measured in units called Tesla (T). A typical refrigerator magnet has a magnetic field strength of around 0.001 Tesla or 1 milliTesla (mT).
In contrast, MRI systems used in medical imaging operate at much higher field strengths, typically ranging from 1.5 Tesla to 3 Tesla or even higher.To put it into perspective, a 1.5 Tesla MRI scanner is approximately 1500 times stronger than a refrigerator magnet, while a 3 Tesla MRI scanner is approximately 3000 times stronger. These high magnetic field strengths are necessary for producing detailed and high-quality images of the body's tissues and organs during an MRI examination.It's worth noting that the strength of an MRI system can vary depending on the specific model and technology used. Advanced MRI systems with even higher field strengths, such as 7 Tesla or 9.4 Tesla, are also available for specialized research and clinical applications. These extremely high-field MRI systems are significantly stronger than a refrigerator magnet, often by tens of thousands of times.
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An atom of the element chromium has an atomic number of 24 and a mass number of 52. How many electrons are in an uncharged atom of chromium?
0
24
28
52
Answer:
it's 24
Explanation:
I took the test and got 100 %
Answer:
24
Explanation:
What is the velocity of a car that travels 200 meters In 8 seconds?
Answer:
25m/s
Explanation:
200m/ 8s =25m/s
what happens to the current in a circuit if a 1.5 volt battery is removed and is placed by a 9 volt battery?
Answer:
The current would increase.
Explanation:
The current would increase. 10. The relationship between resistance and current in a circuit is that the greater the resistance the less the current and the greater the current the less the resistance is.
if a 1.5-volt battery is removed and placed by a 9-volt battery in a circuit, From Ohm's law we can say that the current flow inside the circuit will increase because the voltage increases (resistance remains constant).
What is Ohm's law?Ohm's Law is a fundamental law of physics that describes the relationship between the three basic electrical quantities: voltage, current, and resistance in a circuit.
It states that the current through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. Mathematically, Ohm's Law is expressed as:
V = I x R
Where:
V = the voltage or potential difference between two points in the circuit, measured in volts (V).
I = the current flowing through the circuit, measured in amperes (A).
R = the resistance of the conductor, measured in ohms (Ω).
In other words, the voltage (V) across a circuit component is equal to the product of the current (I) flowing through the component and its resistance (R). This law is applicable to both DC (direct current) and AC (alternating current) circuits, as long as the resistance is constant.
Ohm's Law can be used to calculate any one of the three variables if the other two are known. For example, if the voltage and resistance in a circuit are known, the current flowing through the circuit can be calculated using the formula:
I = V / R
Here in the question,
The current in a circuit is determined by the resistance of the circuit and the voltage applied to it, according to Ohm's Law. If a 9-volt battery replaces a 1.5-volt battery, the voltage applied to the circuit will increase, which may cause an increase in the current flowing through the circuit if the resistance remains the same.
However, the increase in voltage may also cause an increase in the heat generated by the circuit, which could potentially damage the components or cause a safety hazard. Therefore, it is important to ensure that the components in the circuit can handle the higher voltage before replacing the battery.
It's also important to note that the current may also depend on the internal resistance of the batteries. A 9-volt battery typically has a lower internal resistance than a 1.5-volt battery, which means it can supply more current to the circuit. So, even if the resistance of the circuit remains the same, the current may still increase due to the higher voltage and lower internal resistance of the 9-volt battery.
Hence, The current flowing through the circuit increased when we removed a 1.5-volt battery and replaced it with a 9-volt battery.
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What is the current in a 160V circuit if the resistance is 10Ω?
Hello!!
For this, use the formula:
\(\boxed{I=V/R}\)
\(\textbf{Being:}\)
\(\sqrt{}\) \(I = Current = ?\)
\(\sqrt{}\) \(V = Voltage = 160 \ V\)
\(\sqrt{}\) \(R = Resistance = 10\ \varOmega\)
\(\textbf{If we replace and resolve it}\)
\(I = 160\ V / 10\ \varOmega\)
\(I = 16\ A\)
\(\text{The current of that circuit is \textbf{16 Amperes}}\)
An automobile with a mass of 1000 kg accelerates at a traffic light with a force of 4000 N. What is the automobile's acceleration?
Explanation:
Given
mass (m) = 1000 kg
Force (F) = 4000 N
Acceleration (a) = ?
We have the relation
F = m * a
or, 4000 = 1000 * a
or a = 4000 / 1000
a = 4 m/s²
The acceleration of the automobile is 4 m/s²
Hope it will help :)❤
Answer:
\(\boxed {\boxed {\sf 4 \ m/s^2}}\)
Explanation:
According to Newton's Second Law of Motion, force is equal to the product of mass and acceleration.
\(F=m*a\)
We know the mass is 1000 kilograms and the force is 4000 Newtons. Let's convert the units to simplify the question for later.
1 Newton is equal to 1 kilogram meter per square second. The force of 4000 N is equal to 4000 kg*m/s²\(m= 1000 \ kg \\F= 4000 \ kg*m/s^2\)
Substitute the values into the formula.
\(4000 \ kg*m/s^2=1000 \ kg *a\)
We want to find the acceleration, a. We must isolate the variable on one side of the equation.
1000 kg and a are being multiplied. The inverse operatio of multiplication is division. Divide both sides of the equation by 1000 kg.
\(\frac{4000 \ kg*m/s^2 }{1000 \ kg } =\frac{1000 \ kg*a}{1000 \ kg}\)
The kilograms will cancel.
\(\frac{4000 \ m/s^2 }{1000 }=a\)
\(4 \ m/s^2 =a\)
The autombile's acceleration is 4 meters per square second.
song What shoid the receed compary offer the band it it uses a dscoust rase of 5578 8 5%, or 95 ? (Frund to the nemest dolat)
The receed company should offer the band between $53 and $64, depending on the discount rate used.
The receed company should offer the band a discounted amount based on the given discount rates. To find the amount, we need to calculate the present value of the song's future cash flows. The formula for present value is:
PV = FV / \((1 + r)^n\)
Where PV is the present value, FV is the future value, r is the discount rate, and n is the number of periods.
Let's assume the future value of the song's cash flows is $100. We will calculate the present value using each discount rate given: 55%, 78%, 85%, and 95%.
1. For a discount rate of 55%:
PV = $100 /\((1 + 0.55)^1\) = $64
2. For a discount rate of 78%:
PV = $100 / \((1 + 0.78)^1\) = $56
3. For a discount rate of 85%:
PV = $100 / \((1 + 0.85)^1\) = $54
4. For a discount rate of 95%:
PV = $100 /\((1 + 0.95)^1\) = $53
Rounding these values to the nearest dollar, the receed company should offer the band $64, $56, $54, or $53, depending on the discount rate used.
In summary, the receed company should offer the band between $53 and $64, depending on the discount rate used.
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complete question: song What should the receed company offer the band if it uses a discount rate of 55% 78% 85%, or 95% ? (Found to the nearest dollar)
how fast would a 30-kg kid need to run in order to have the same kinetic energy as an 8.0-g bullet fired at 400 m/s, in m/s?
the 30-kg kid would need to run at approximately 16.2 m/s to have the same kinetic energy as the 8.0-g bullet fired at 400 m/s.
The mass of the 8.0-g bullet is equal to 8.0 × 10⁻³ kg, which is given.
The kinetic energy of the bullet is given by:
KE = (1/2)mv²
where K = kinetic energy, m = mass of the object, and v = velocity of the object.KE = (1/2)mv²KE = (1/2)(8.0 × 10⁻³ kg)(400 m/s)²KE = 640 J
Thus, the kinetic energy of the 8.0-g bullet is 640 J.
For the 30-kg kid to have the same kinetic energy, we need to use the same equation:
KE = (1/2)mv²
where K = kinetic energy, m = mass of the object, and v = velocity of the object.
To solve for v, we need to rearrange the equation:
KE = (1/2)mv² ⇒ v = √(2KE/m)
Substituting in the values for KE and m, we get:
v = √(2(640 J)/30 kg) ≈ 16.2 m/s
Therefore, the 30-kg kid would need to run at approximately 16.2 m/s to have the same kinetic energy as the 8.0-g bullet fired at 400 m/s.
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A projectile is fired straight up from the south pole of earth with an initial speed vi = 15km/s. find the speed of the projectil when it is very far from the earth, neglecting air resistance
The calculated value is 2.5×10⁷ m.
Velocity is a term that describes the speed and direction of a point's motion. For example, a circular path's direction is always perpendicular to a line from the point to the circle's center. A point always moves in a direction that is tangent to its path (a radius). A vector measurement of the rate and direction of motion is what is meant by the term "velocity." Simply said, velocity is the rate of movement in a single direction.
From energy conservation, since the velocity will be 0 at highest point,
1/2 m (10000) ²− GMm/R
=− GMm/d
=10⁸/2 −(9.8) (6400000)
=−(9.8) *(6400000) ²/d
d≈2.5×107 m
Answer is 2.5×10⁷ m.
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There is going to be demand for mechanical engineering skills in the future because
O it is the most useful field of engineering.
O housing problems are common in much of the developing world.
O the increasing global population creates many problems to solve.
O very few people have the skills and aptitude to be a mechanical engineer
The correct option is b. housing problems are common in much of the developing world.
What is mechanical engineering?
Technically speaking, mechanical engineering is the application of engineering ideas and procedures for solving problems from design to manufacture to market for any thing. Using the laws of motion, energy, and force, mechanical engineers assess their work to make sure that designs operate in a safe, effective, and reliable manner at a price that is competitive.
Mechanical engineers have a positive impact. That's because careers in mechanical engineering focus on developing technology that address demands of people. To aid humanity, mechanical engineers have likely had some influence on almost every product or service in modern existence.
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If the brakes on a 1,800 kg car cause it change velocity from 25
m/s to 0 m/s, what impulse did the brakes exert on the car?
Given the mass of the car and the change in velocity, the impulse exerted on the car by the brakes is 45000kgm/s.
What is impulse?Impulse is simply the product of force and time.
Using the formula of impulse.
Ft = m( v - u )
Given the data in the question;
Mass of car m = 1800kgInitial velocity v = 25m/s Final velocity u = 0m/sWe substitute our values into the expression above.
Ft = m( v - u )
Ft = 1800kg( 25m/s - 0m/s )
Ft = 1800kg × 25m/s
Ft = 45000kgm/s
Therefore, Given the mass of the car and the change in velocity, the impulse exerted on the car by the brakes is 45000kgm/s.
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Question 9 of 25
What is one difference between an atom and a molecule?
A. Only molecules can become ions.
B. Only atoms can become ions.
C. An atom can contain one or more chemical bonds.
D. A molecule can contain more than one element.
In a heat engine, 2.00 mol of a monoatomic gas are carried through the cycle ABCDA. The segment AB represents an isothermal expansion, the segment BC is an adiabatic expansion, the segment CD is an isobaric compression, and DA is a constant volume process. The pressure and temperature at A are 5.00 atm and 600 K. The volume at B is twice the volume at A. The pressure at D is 1.00 atm.
a) What is the pressure at B?
b) What is the temperature at C?
c) Find the total work done by the gas in one cycle.
(a)The pressure at B is 0.1248 atm.
(b)The temperature at C is 727.1 K.
(c)The total work done by the gas in one cycle is -1979J
General calculation:
We can use the First Law of Thermodynamics to analyze the heat engine cycle:
ΔU = Q - W
where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system. For a complete cycle, ΔU = 0, so:
Q = W
We can also use the ideal gas law to relate the pressure, volume, and temperature of the gas:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature.
(a)How to find the pressure at B segment?
To find the pressure at B, we can use the fact that the segment AB is an isothermal expansion. This means that the temperature remains constant, so:
PV = nRT
PB = (nRT)/(2V) = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/(2V) = (0.0821 L·atm/mol)(600 K)/V
Since the pressure at A is 5.00 atm, we can use the fact that the temperature is constant to find the volume at A:
PV = nRT
VA = (nRT)/P = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/5.00 atm = 197.76 L
Since the volume at B is twice the volume at A, we have:
VB = 2VA = 395.52 L
Substituting into the expression for PB, we get:
PB = (0.0821 L·atm/mol)(600 K)/395.52 L = 0.1248 atm
Therefore, the pressure at B is 0.1248 atm.
(b) How to find the temperature at segment C?To find the temperature at C, we can use the fact that the segment BC is an adiabatic expansion. This means that no heat is added or removed from the system, so:
\(PV^\gamma\)= constant
where γ is the ratio of specific heats (for a monoatomic gas, γ = 5/3). We can use the fact that the volume at C is equal to the volume at A to find the pressure at C:
\(PAV^\gamma = PCV^\gamma\)
PC = \(PA(V/A)^\gamma\) = 5.00 atm\((1/2)^(^5^/^3^)\) = 1.556 atm
Since the segment BC is adiabatic, the temperature changes but no heat is added or removed from the system. Using the ideal gas law, we can relate the pressure, volume, and temperature:
PV = nRT
TC = (PCVC)/(nR) = (1.556 atm)(197.76 L)/(2.00 mol)(0.0821 L·atm/mol·K) = 727.1 K
Therefore, the temperature at C is 727.1 K.
(c) How to find the total work done by the gas in one cycle?The total work done by the gas in one cycle is the sum of the work done in each segment of the cycle:
W = WAB + WBC + WCD + WDA
For segment AB, the work done is:
WAB = -QAB = -∫PdV = -nRT∫(1/V)dV = -nRT ln(VB/VA) = -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2) = -602 J
For segment BC, the work done is:
WBC = -QBC = -∫PdV = -nγRT∫(1/V)dV = -nγRT
We know that VB = 2VA and VC = 2VD, so we can express the ratio VB/VC in terms of VA/VD:
VB/VC = (2VA)/(2VD) = VA/VD
Substituting into the expression for WBC, we get:
WBC = -nγRT ln(VA/VD)
For segment CD, the work done is:
WCD = -QCD + PCDΔV = -nCpΔT + PCDΔV
where Cp is the specific heat at constant pressure, ΔT is the change in temperature, and ΔV is the change in volume. We know that the segment CD is isobaric, so ΔV = VB - VA = (2VA) - VA = VA. We can also use the ideal gas law to relate the pressure, volume, and temperature:
PV = nRTPC = (nRT)/VDSubstituting into the expression for WCD, we get:
WCD = -nCpΔT + (nRT/VD)VA = -nCp(TC - TD) + (nRT/VD)VA
For segment DA, the work done is:
WDA = -QDA + ΔU = -nCvΔT
where Cv is the specific heat at constant volume. We know that the segment DA is isovolumetric, so ΔV = 0. Using the First Law of Thermodynamics, we know that ΔU = 0 for a complete cycle, so:
QDA = -WDA = nCvΔT
Substituting into the expression for WDA, we get:
WDA = -nCvΔT
Adding up the work done in each segment, we get:
W = WAB + WBC + WCD + WDA
= -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(Cp)(TC - TD) + (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(Cv)(TC - TA)
We know that Cp and Cv for a monoatomic gas are related by Cp = Cv + R, so we can express Cp in terms of Cv:
Cp = Cv + R = (3/2)R + R = (5/2)R
Substituting and simplifying, we get:
W = (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(727.1 K)+ (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(600 K)
W = -966.2 J - 4957 J - 7476 J + 5154 J
= -1979 J
Therefore, the total work done by the gas in one cycle is -1979 J
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Why do the interiors of saturn and jupiter contain large amounts of liquid metallic hydrogen?
The interiors of Saturn and Jupiter contain a large amount of large metallic hydrogen because liquid hydrogen transforms into liquid metallic hydrogen as one descends, reaching a depth of 12,000 kilometers as the radius of Jupiter is 71,000 kilometers the hydrogen is below the cloud layers.
Helium and hydrogen make up the majority of the atmospheres of Jupiter and Saturn. The hydrogen changes from a high-pressure gas to liquid hydrogen a few hundred kilometers below the cloud levels. It would take some fairly intense pressures to create this on Earth, but it is possible. It's a component of rocket fuel.
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Un autobús viaja en una carretera a una velocidad de 70 km/h y acelera durante 30 segundos hasta llegar a su límite de velocidad, que son 95 km/h. ¿Cuál fue su aceleración?
Answer:
a = 30 km / h²
Explanation:
Dado que
Velocidad inicial, u = 70 km / h
Velocidad final, v = 95 km / h
Tiempo, t = 30 s = 0.1 h
Lo sabemos
v = u + a t
a = aceleración
Ahora poniendo los valores en la ecuación anterior
\(95 = 70 + a \ times 0.1 \)
\(a = \ dfrac {95-70} {0.1} = 30 \ km / h ^ 2 \)
Por lo tanto, la aceleración será
a = 30 km / h²
A capacitor of unknown charged capacitance c is charged to 100v and the connected across an intially uncharged 60micro f capacitor. If the final potenial diffrence across the 60micro-f capacitor is 40v ,determine c
If the final potential difference across the 69micro -f then capacitor is 40Mf
We cannot expect simple energy conservation to hold because energy is presumably dissipated as heat in the connection wires or as radio waves while the charge oscillates during the system "settling down" to its final state (40V across the parallel pair of capacitors C and 60 F).
We anticipate that charge will be conserved. Thus, if Q is the initial charge stored on C and q 1 and q2 are the charges on the parallel pair after "settling down," then -
Q= q1+ q2
C(100V) = C(40V) + 60mf(40V)
C= 40Mf
An electrical component that stores electrical energy in an electric field is known as a capacitor. It is made up of two conductive plates separated by a nonconductive material known as a dielectric.
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large-scale winds are generated on earth primarily because of
Large-scale winds are generated on Earth primarily because of atmospheric pressure differences.
What is the main cause of winds on Earth?The primary cause of large-scale winds on Earth is the uneven heating of the Earth's surface by solar radiation, which creates variations in atmospheric pressure.
The sun's energy heats the Earth's surface unevenly, with different regions receiving different amounts of heat. As a result, the air above these regions becomes warmer and expands, leading to a decrease in air pressure.
In contrast, areas with cooler temperatures have denser air, resulting in higher atmospheric pressure. The difference in pressure between these regions creates a pressure gradient, which drives the movement of air from high-pressure areas to low-pressure areas. This movement of air is what we perceive as wind.
The Earth's rotation also plays a significant role in shaping wind patterns. The Coriolis effect, caused by the planet's rotation, deflects moving air to the right in the Northern Hemisphere and to the left in the Southern Hemisphere.
This deflection further influences the direction and patterns of large-scale winds, creating phenomena like trade winds, prevailing westerlies, and polar easterlies.
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what does the principle of slope tell us about the slope of position vs. time (pt) and velocity vs. time (vt) graphs. in other words, what kind of information could we extract from the slopes of position vs. time (pt) and velocity vs. time (vt) graphs?
we can extract information about velocity from the slope of a position vs. time (pt), and acceleration from the velocity vs. time (vt) graph.
the slope of a position-time graph, \(v = \frac{S_{2}- S_{1} }{t_{2}- t_{1} }\)
The velocity of an object can be learned from the slope of a position vs. time graph. A low slope, for instance, indicates a low velocity; Negative slopes indicate negative speeds; A straight line with a constant slope indicates a constant velocity; an evolving incline (bent line) implies an evolving speed. As a result, the shape of the line on the graph—straight, curved, with a slight or steep slope, etc. describes the object's movement.
The slope of a velocity graph shows the acceleration of the object. Consequently, the slope's value is a representation of the object's acceleration at any given moment.
The slope of a velocity-time graph, \(v = \frac{V_{2}- V_{1} }{t_{2}- t_{1} }\)
This indicates that the object's velocity will change rapidly when the slope is steep. The object's velocity will not change as rapidly when the slope is shallow. This also indicates that the acceleration will be negative if the slope is negative and pointing downward, while the acceleration will be positive if the slope is positive and pointing upward.
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When balancing a chemical equation, can a coefficient within a chemical equation be adjusted to
balance the chemical equation?
23. As the frequency of a wave increases, the period of the wave
Answer: decreases
Explanation: As frequency increases the period of a wave decreases because they have an inverse relationship. The equation for wave period (T) is the inverse of the frequency (f). So, as frequency increases, the value for period will decrease accordingly.
If there are 3 apples and you take away two, how many do you have?
Answer:
1
Explanation:
Answer:
You have 1 apple.
Explanation:
3 - 2 = 1