Four 18.0 ohm resistors are connected in parallel across a 25.0 V ideal battery. What is the current through the battery?

The answer is that the charge density in an electric point-electron is (1/2)e2/r. So, in this example we have σE = (1/2)e^2/(4.40 × 10^6 cm).

A charge of -323e is uniformly distributed over the volume of a 5.00 cm sphere. The charge density = 1.9 ×10 -19 C/m3.

The volume charge density of this sphere is 4.40C/m^3 with C being the charge of 1 coulomb and m_s being the sphere radius.

The volume charge density in this case is equal to the charge density of a sphere that occupies the same volume and has the same radius.

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Answer:  Radio waves, Microwaves infrared, optical ultraviolet, X-rays and gamma-rays

Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9

Answer:noo

Explanation:impossible

Answer

U Max velocity= Potential energy= kinetic energy

The potential energy is the product of mass * acceleration due to gravity * height

The kinetic energy is the product of 1/2 mass* square of velocity.

Max Velocity=mgh= 1/2mv^2

Mass is given as 62kg, height =1.2m and g= 9.8m/s^2

62kg* 9.8m/s^2*1.2= 1/2*62kg* v^2

729.12=31v^2

V^2= 729.12/31 =23.52

V^2=square root of 23.52

V= 4.85m/s

We expect the last colour of the sunset to be on the red end of the visible spectrum because of the dispersion of light.  Due to the particles present in the atmosphere, the light rays undergo scattering and the light of shorter wavelengths like blue gets dissipated but light rays of longer wavelengths travel long distances without getting dissipated.

Dispersion of light is the phenomenon in which the light from the sun is split into its constituent colours which are Violet, Indigo, Blue, Green, Yellow, Orange, and Red when it passes through a prism or due to the particles present in the earth's atmosphere.  

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Answer:

1.05m

Explanation:

To get this answer, you must first know how long it takes the ball to reach the ground. In order to figure that out, the process is simple:

First: Multiply the object's height by 2.

2.4x2=4.8

Next: Divide that answer by the speed of Gravity, 9.8 or 9.81m/s^2

(I prefer to use the method used by engineers, attend to precision, so I keep the same number of decimals in each number I am calculating.)

4.8/9.8=0.48979591836734693877551020408163m/s^2

Next: Square Root this answer.

=0.69985421222376517091350973563025

Last: Multiply your square rooted answer by your  forward velocity.

0.69985421222376517091350973563025x1.5=

1.0497813183356477563702646034454 or, since Khan Academy only wants three significant digits, round up to 1.05.

Answer:

1.05

Explanation:

what the other guy said trust

Answer:

Electromagnetic waves are waves that have no medium to travel whereas mechanical waves need a medium for its transmission. Electromagnetic waves travel in a vacuum whereas mechanical waves do not. The mechanical waves need a medium like water, air, or anything for it to travel.

Explanation:

Answer:

Answer:

KE = 110000 J

KE = 0.11 MJ

KE = 104.1794917935 \(BTU_{mean}\)

KE = 26252.857981585 \(cal_{mean}\)

The kinetic energy of a moving body can be calculated using its mass and velocity. The kinetic energy of the horse of 550 kg travelling at 20 m/s is 11000 J.

Kinetic energy of an object is generated by virtue of its motion. When the object starts moving its potential energy starts to convert into kinetic energy.

The kinetic energy of an object is related to its mass and velocity as follows:

Ke = 1/2 mv²

Hence, kinetic energy is directly proportional to the mass and velocity.

Given mass of the horse m = 550 kg

velocity = 20 m/s

then, Ke = 1/2 550 kg × (20 m/s)²

Ke = 11000 J.

Therefore, the kinetic energy of the horse is 11000 J.

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The maximum acceleration of the object is 10.94 x 10² m/s².

The equation of displacement is given as,

y(t) = 4.8 cos(15.1 t)

It is in the form, y(t) = A cos(ωt)

So, the amplitude of the SHM, A = 4.8 m

Angular frequency, ω = 15.1 s⁻¹

The maximum acceleration,

a(max) = -Aω²

the -ve sign indicates that the acceleration is acting towards the mean position.

a(max) = 4.8 x 15.1²

a(max) = 10.94 x 10² m/s²

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Sophie is responsible for the demographic aspect of a country market assessment, as she is assessing the market size and population growth of four European nations. This information helps Patterson Electronics understand the potential customer base in each country and make informed decisions about entering the global marketplace.

In addition, Sophie may need to assess other aspects of the market, such as the level of competition, regulatory environment, and cultural factors that could impact the success of Patterson Electronics' entry into the market. By conducting a thorough market analysis, Sophie can provide valuable insights and recommendations to help the company make informed decisions about whether or not to enter each of the four European nations.

Overall, Sophie's role in assessing the market size and population growth of the four European nations is critical to the success of Patterson Electronics' entry into the global marketplace. Her analysis will provide important information that will help the company make strategic decisions about where to focus their resources and how to best position themselves for success in each market.

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Answer:

lk

Explanation:

2

The trip will seem about `15.0000001875 million seconds` shorter to people on the rocket as compared to people in the Earth frame.

The given values are: Speed of rocket, `v = 6,000 m/s`

Distance to Mars, `d = 90 million km = 9 × 10^10 m`

Time taken to cover the distance, `t = 15 × 10^6 s`

Now, using Lorentz factor, we can find how much seconds shorter the trip will seem to people on the rocket.

Lorentz factor is given as: `γ = 1 / sqrt(1 - v^2/c^2)

`where, `c` is the speed of light `c = 3 × 10^8 m/s`

On substituting the given values, we get:

`γ = 1 / sqrt(1 - (6,000/3 × 10^8)^2)

`Simplifying, we get: `γ = 1.0000000125`

Approximately, `γ ≈ 1`.

Hence, the trip will seem shorter by about `15 × 10^6 × (1 - 1/γ)` seconds.

Using binomial approximation, `(1 - 1/γ)^-1 ≈ 1 + 1/γ`.

Hence, the time difference would be approximately:`15 × 10^6 × 1/γ ≈ 15 × 10^6 × (1 + 1/γ)`

On substituting the value of `γ`, we get:`

15 × 10^6 × (1 + 1/γ) ≈ 15 × 10^6 × 1.0000000125 ≈ 15.0000001875 × 10^6 s`

Hence, the trip will seem about `15.0000001875 × 10^6 s` or `15.0000001875 million seconds` shorter to people on the rocket as compared to people in the Earth frame.

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Answer:

The force that must be applied to the chain in order for the chain to have the given acceleration is approximately 694.2 N

Explanation:

The given restive force, \(F_f\) = 130 N

The mass of the wheel, m = 1.70 kg

The diameter of the wheel, D = 50.0 cm

∴ The radius of the wheel, R = 50.0 cm/2 = 25.0 cm = 0.25 m

The diameter of the sprocket over which the chain passes, d = 8.75 cm

The radius of the sprocket over which the chain passes, r = 8.75 cm/2 = 4.375 cm = 0.04375 m

The angular acceleration, α = 3.50 rad/s²

Torque, τ = I·α

Where;

I = The moment of inertia = m·R²·α

The net torque = The applied torque - The friction torque

Therefore, we get;

I × α = m × R² × α = F × r - \(F_f\) × R

1.70 kg × (0.25 m)² × 3.50 rad/s² = F × 0.04375 m - 120 N × 0.25 m

F = (1.70 kg × (0.25 m)² × 3.50 rad/s² +  120 N × 0.25 m)/(0.04375 m) = 694.214286 N

The force that must be applied to the chain in order for the chain to have the given acceleration, F ≈ 694.2 N

To determine the acceleration of the mass, we will need to use Newton's Second Law of Motion, which states that the force acting on an object is directly proportional to its acceleration. In this case, the force acting on the object is the tension of 35.0N that is being applied to the right.

We can use the following equation to determine the acceleration of the mass:
F = ma
Where F is the force applied to the object, m is the mass of the object, and a is the acceleration of the object. Rearranging this equation, we can solve for a:
a = F/m
Plugging in the values given in the question, we get:
a = 35.0N / 2.50kg
a = 14.0 m/s^2

Therefore, the acceleration of the mass is 14.0 m/s^2. This means that for every second that passes, the speed of the mass increases by 14.0 meters per second.

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The original capacitance of the vacuum-filled capacitor was 1.36 × 10^-8 F.

We can use the capacitance equation for a parallel-plate capacitor to find the original capacitance:

\(C = ε₀A/d\)

where C is the capacitance, ε₀ is the permittivity of free space\((8.85 × 10^-12 F/m),\) A is the area of each plate, and d is the distance between the plates.

Using the given values, we have:

\(C = (8.85 × 10^-12 F/m)(0.460 m^2)/(3.00 × 10^-3 m) = 1.36 × 10^-8 F\)

This is the capacitance of the vacuum-filled capacitor before the dielectric is inserted.

When the dielectric is inserted, it increases the capacitance of the capacitor according to the:

\(C' = kε₀A/d\)

where C' is the new capacitance, k is the dielectric constant of the material, and all other variables have the same meaning as before.

The potential difference between the plates decreases because the charge on each plate remains constant, so the equation for capacitance can be rearranged to:

V = Q/C

where V is the potential difference, Q is the charge on each plate, and C is the capacitance.

Using the values given, we can solve for the charge on each plate before the dielectric is inserted:

\(Q = CV = (1.36 × 10^-8 F)(4.00 × 10^3 V) = 5.44 × 10^-5 C\)

After the dielectric is inserted, the charge on each plate remains the same, so we can use the equation for the new capacitance to solve for k:

\(k = C'd/ε₀A = C/C' = V'/V\)

where V' is the new potential difference (2.50 kV).

Substituting in the known values, we get:

\(k = (2.50 × 10^3 V)/(4.00 × 10^3 V) = 0.625\)

The dielectric constant for the material is therefore 0.625.

Finally, we can use the equation for the new capacitance with the dielectric constant to find the capacitance with the dielectric inserted:

\(C' = kε₀A/d = (0.625)(8.85 × 10^-12 F/m)(0.460 m^2)/(3.00 × 10^-3 m) = 6.88 × 10^-9 F\)

So the original capacitance of the vacuum-filled capacitor was 1.36 × 10^-8 F.

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Answer: I never said anything to them but if i did it would be "I need a break from you, i love you but sometimes I have to find the path on my own." i would say this if i wasn't scared to hurt them.

Explanation:

A focal point placed too close to the edge of a composition will result in a visually unbalanced composition, potentially disrupting the overall harmony and equilibrium of the design.

The placement of a focal point is a crucial element in creating a well-balanced composition. When a focal point is positioned too close to the edge of a composition, it can disrupt the visual balance and harmony of the overall design.

A balanced composition typically involves distributing visual elements evenly and strategically within the frame. Placing the focal point too close to the edge can create an imbalance by causing an uneven distribution of visual weight. It may lead to a composition that feels lopsided or lacking in visual stability.

By placing the focal point closer to the centre or within the composition, you can achieve a better sense of balance and harmony. This allows for a more visually pleasing arrangement, where the focal point can be effectively emphasized and interact with other elements within the composition.

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The traffic conditions is the average speed of several vehicles equal to average speed of individual vehicles within the  group is low traffic density

Low traffic density refers to a condition in which there are fewer vehicles on the roadway, when there are fewer vehicles on the road, the chances of traffic congestion are reduced, and the speed of individual cars is improved. At a lesser speed, vehicles do not require to stop frequently, resulting in the reduction of traffic jams. The time it takes to cover a distance varies for each vehicle, and when the average speed of the group is calculated, the total time is divided by the number of vehicles in the group.

In low-density traffic conditions, all of the vehicles travel at similar speeds, and so the average speed of the group is equivalent to the average speed of an individual vehicle in the group. Therefore, during low-density traffic conditions, the average speed of several vehicles is the same as the average speed of individual vehicles within the group.In short, when traffic density is low, the average speed of a group of vehicles becomes equivalent to the average speed of an individual vehicle in the group.

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A 8.00-μF parallel-plate capacitor has charges of 60.0 μC on its plates, then the potential energy stored in this capacitor is 225 μJ. So, the correct option is (B).

To find the potential energy stored in the 8.00-μF parallel-plate capacitor with charges of 60.0 μC on its plates, you can use the formula for the energy stored in a capacitor:

Potential Energy (U) = (1/2) × Capacitance (C) × Voltage (V)²

First, we need to find the voltage (V) using the formula:

Voltage (V) = Charge (Q) / Capacitance (C)

Substitute the given values:

\(V = \frac{60.0\mu C}{8.00\mu F} =7.5V\)

Now, calculate the potential energy (U):

\(U =\frac{1}{2} \times 8.00\mu F \times (7.5 V)^2=225 \mu J\)

Therefore, the potential energy stored in this capacitor is 225 μJ, which corresponds to option B.

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The wood will sink lower in the water when the container is sealed and pressurized above atmospheric pressure.  

When the container is sealed and pressurized above atmospheric pressure, the pressure inside the container increases. According to Boyle's Law, the volume of a gas is inversely proportional to its pressure at a constant temperature. This means that as the pressure inside the container increases, the volume of the air trapped in the pores of the wood decreases.

This results in a decrease in the buoyant force acting on the wood, which causes the wood to sink lower in the water. Therefore, the correct answer is "it sinks lower in the water." This phenomenon is also observed in the diving and submarine industry, where pressure changes affect the buoyancy of submerged objects.

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Full Question: a piece of unpainted porous wood barely floats in an open container partly filled with water. the container is then sealed and pressurized above atmospheric pressure. what happens to the wood?

correct: your answer is correct. explain your answer.

Answer:

2.5m/s1

Explanation: