Answers
Four electrons are placed at the corner of a square
So we will first find the electrostatic potential at the center of the square
So here it is given as
here
r = distance of corner of the square from it center
now the net potential is given as
now potential energy of alpha particle at this position
Now at the mid point of one of the side
Electrostatic potential is given as
here we know that
now potential is given as
now final potential energy is given as
Now work done in this process is given as
We have that Work is done by the Coulomb force when the alpha particle moves to the midpoint of one of the sides of the square
From the question we are told
Four electrons are located at the corners of a square 10.0 nm on a side, with an alpha particle at its midpoint.
How much work is done by the Coulomb force when the alpha particle moves to the midpoint of one of the sides of the square
Generally the equation for the Work done is mathematically given as
\(W=2kqQ\frac{2}{r1}-\frac{1}{r2}-\frac{1}{r3}\\\\\ W=2*8,99*10^9*-1.6*10^{-19}* -1.6*10^{-19} (\frac{2}{5*10^{-9}+5*10^{-9}}-\frac{1}{5*10^{-9}}-\frac{1}{10*10^{-9}+5*10^[-9]})\)
Therefore
Work is done by the Coulomb force when the alpha particle moves to the midpoint of one of the sides of the square
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Related Questions
A liquid having a mall depth but a large volume is forced by an applied pressure p
Answers
What is the ratio of thicknesses of glycerine (refractive index 1.473) to crystalline quartz (refractive index 1.544) such that they would contain the same number of wavelengths of 646nm light
Answers
Answer: The ratio of thicknesses of glycerine (refractive index 1.473) to crystalline quartz (refractive index 1.544) is 0.954.
Explanation:
Given: Refractive index of glycerine = 1.473
Refractive index of crystalline quartz = 1.544
Formula used is as follows.
\(2nt = m \lambda\)
For crystalline quartz: \(2n_{q}t_{q} = m \lambda_{q}\)
For glycerine: \(2n_{g}t_{g} = n \lambda_{g}\)
Here, m = n and \(\lambda_{q} = \lambda_{g}\)
So, the ratio of both these values can be written as follows.
\(\frac{2n_{q}t_{q}}{2n_{g}t_{g}} = \frac{m \lambda_{q}}{n \lambda_{g}} = 1\)
So, \(n_{q}t_{q} = n_{g}t_{g}\)
\(\frac{t_{q}}{t_{g}} = \frac{n_{g}}{n_{q}} = \frac{1.473}{1.544}\)
\(\frac{t_{q}}{t_{g}} = 0.954\)
Thus, we can conclude that the ratio of thicknesses of glycerine (refractive index 1.473) to crystalline quartz (refractive index 1.544) is 0.954.
prove the three laws of motion
Answers
Answer:
The first law, also called the law of inertia, was pioneered by Galileo. This was quite a conceptual leap because it was not possible in Galileo's time to observe a moving object without at least some frictional forces dragging against the motion. In fact, for over a thousand years before Galileo, educated individuals believed Aristotle's formulation that, wherever there is motion, there is an external force producing that motion.
The second law, $ f(t)=m\,a(t)$ , actually implies the first law, since when $ f(t)=0$ (no applied force), the acceleration $ a(t)$ is zero, implying a constant velocity $ v(t)$ . (The velocity is simply the integral with respect to time of $ a(t)={\dot v}(t)$ .)
Newton's third law implies conservation of momentum [138]. It can also be seen as following from the second law: When one object ``pushes'' a second object at some (massless) point of contact using an applied force, there must be an equal and opposite force from the second object that cancels the applied force. Otherwise, there would be a nonzero net force on a massless point which, by the second law, would accelerate the point of contact by an infinite amount.
Explanation:
What layer forms the largest portion of Earth
Answers
Answer:
the mantel
Explanation:
the asthenosphere is the part of the mantle that flows and moves the plates of the earth. the mantle is the layer located directly under the sima. it is the largest layer of the earth, 1800 miles thick.
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A car with a mass of 1200kg is traveling west at 25 m/s collides head on with highway barrier. The car comes to rest in 0.35 seconds . What is the magnitude of the force and the impulse applied to the car
Answers
The magnitude of the force and the impulse applied to the car are 85714 N and 30000 N-s respectively.
What is force?
The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
The magnitude of the force applied to the car = change in momentum/time interval
= (1200 kg × 25 m/s - 1200 kg×0)/0.35 second
= 85714 N.
The impulse applied to the car = change in momentum
= (1200 kg × 25 m/s - 1200 kg×0)
= 30000 N-s.
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Sharon and Kaylyn are playing air hockey. Sharon hits the hockey puck sending it at a velocity of 6 m/s and it hits Kaylyn's puck Both hockey pucks have a mass of 0.3 kg Sharon's puck stops after it hits Kaylyn's puck According to the law of conservation of momentum, what should the resulting velocity of Kaylyn's puck be if it. was at rest before colliding with Sharon's puck?
A. Equal to the velocity of Sharon's puck before they collided
B. Twice the velocity of Sharon's puck before they collided
C. Half the velocity of Sharon's puck before they collided
D. Equal to the velocity of Sharon's puck ball after they collided
Answers
Answer:
According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Since Sharon's puck stops after the collision, all of its momentum is transferred to Kaylyn's puck. Therefore, the resulting momentum of Kaylyn's puck is equal to the initial momentum of Sharon's puck:
m1v1 = m2v2
where m1 and v1 are the mass and velocity of Sharon's puck before the collision, and m2 and v2 are the mass and velocity of Kaylyn's puck after the collision.
Substituting the given values:
0.3 kg × 6 m/s = 0.3 kg × v2
Simplifying:
1.8 kg m/s = 0.3 kg × v2
Dividing both sides by 0.3 kg:
v2 = 6 m/s
Therefore, the resulting velocity of Kaylyn's puck should be equal to the velocity of Sharon's puck before they collided, which is 6 m/s.
Answer: A. Equal to the velocity of Sharon's puck before they collided.
Which of these statements is true concerning balanced forces acting on a car?
Balanced forces will cause no change in the car's motion.
Balanced forces will cause the car to accelerate in the direction of the greater force
Balanced forces will cause the object to change direction.
Balanced forces will cause the car to slow down and stop
Answers
Answer:
Balanced forces will cause no change in the car's motion.
Explanation:
Balanced forces are 2 forces that are equal in opposite directions. This means they 'cancel each other out' in a way. Since both are equal, they cause no effect on the motion of the car
how much work is done when a mass of 3kg (weighing 30N) is lifted vertically through 6m?
Answers
Answer:
180 J is the answer to how much work is done when a mass of 3kg is lifted vertically through 6 m
To calculate the amount of work done when a mass is lifted vertically through a certain distance, we can use the formula:
Work = Force * Distance
In this case, the mass is 3kg, which weighs 30N, and it is lifted vertically through a distance of 6m. Plugging these values into the formula, we get:
Work = 30N * 6m
= 180 Joules
Therefore, the amount of work done when the mass is lifted vertically through 6m is 180 Joules.
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What is indicated by the following displacement time graph ?
Answers
Answer:
The object in motion is deaccelerating in the negative direction.
Explanation:
Interpret the given position-time graph.
Observing the graph we can determine the slope is negative and is gradually flattening out. Thus, we can conclude the object in motion is deaccelerating in the negative direction.
Which statement best describes the circular flow model?
Answers
Calculate the net force on the particle q1.
Answers
Answer:
-12.1
Explanation:
i’m almost sure this is it, i’m checking my old answers
if not let me know and i’ll give you some more answers
A bicycle wheel, of radius 0.300 m and mass 2.07 kg (concentrated on the rim), is rotating at 4.00 rev/s. After 59.0 s the wheel comes to a stop because of friction. What is the magnitude of the average torque due to frictional forces?
Answers
ANSWER:
0.079 J
STEP-BY-STEP EXPLANATION:
The average torque exerted due to friction force is:
\(\tau=I\alpha\)Here, I is the moment of inertia and α is the angular acceleration.
The mass of wheel is concentrated at the rim. Therefore, the moment of inertia of wheel is,
\(I=m\cdot r^2\)Here, m is the mass of wheel and r is the radius of wheel.
replacing:
\(\begin{gathered} I=2.07\cdot0.3^2 \\ I=0.1863\text{ kg}\cdot s^2 \end{gathered}\)The angular speed is decreased from 4 rev/s to 0 rev/s in 59 sec. Therefore, the angular acceleration is calculated as:
\(\begin{gathered} \alpha=\frac{0-4}{59} \\ \alpha=0.068\cdot\frac{rev}{\sec}\cdot\frac{2\pi\text{ rad/rev}}{1rev/sec^2} \\ \alpha=-0.426rad/sec^2 \end{gathered}\)The negative sign represents that the wheel is de-accelerating.
Replacing:
\(\begin{gathered} \tau=I\alpha \\ \tau=0.1863\cdot-0.426 \\ \tau=-0.079\text{J} \end{gathered}\)The negative sign represents the direction of torque i.e. clockwise direction. Thus, the magnitude of average torque is 0.079 J.
Find the components of vtot along the x and y axes in Figure 3.25, where = 23.0° and vtot = 7.56 m/s.
vtot, x =
m/s
vtot, y =
m/s
Answers
The component of the total velocity in the x - direction is 6.96 m/s.
The component of the total velocity in the y - direction is 2.95 m/s.
Component of the velocity in x direction
The component of the total velocity in the x - direction is calculated as follows;
v(x) = vtot cosθ
where;
vtot is total velocityv(x) is velocity in x directionv(x) = 7.56 x cos(23)
v(x) = 6.96 m/s
Component of the velocity in y - directionv(y) = vtot sinθ
v(y) = 7.56 x sin(23)
v(y) = 2.95 m/s
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a stone falls From rest From the Top of a Higher tower. Ignore Air resistance and take g=9.8m/s2. calculate:
a. speed of the stone after 2 seconds
b. how far the stone has travelled after 2 seconds
Answers
a)It takes 0 seconds for the stone to hit the ground.
b)The stone has traveled 19.6 meters after 2 seconds.
When an object is dropped from a height, the motion is described as free fall. It is a special form of motion in which an object is under the sole influence of gravity. The gravitational force acting on an object is always directed towards the center of the Earth, i.e., downwards. Therefore, when an object is dropped from a height, it falls freely towards the ground, and the acceleration of the object is equal to the acceleration due to gravity, which is approximately 9.8 m/s².
In the problem given, a stone is dropped from rest from the top of a higher tower. Therefore, the initial velocity of the stone, u = 0 m/s.
a. Time taken by the stone to reach the ground:
We can use the following equation of motion to calculate the time taken by the stone to reach the ground.
v = u + at
where,
v = final velocity of the object
u = initial velocity of the object
a = acceleration of the object
t = time taken by the object to reach from initial velocity to final velocity
Since the stone is dropped from rest, the initial velocity of the stone, u = 0 m/s.
At the ground level, the final velocity of the stone, v = ?
Again, the acceleration due to gravity, a = 9.8 m/s².
Therefore, we can write the equation as:
v = u + at
v = 0 + 9.8×t
v = 9.8t m/s
When the stone hits the ground, the final velocity of the stone, v = 0 m/s.
Therefore, we can rewrite the equation as:
0 = 9.8t
t = 0 seconds (when the stone is at the top of the tower)
We have found that it takes 0 seconds for the stone to hit the ground.
b. How far the stone has travelled after 2 seconds:
We can use the following equation of motion to calculate how far the stone has travelled after 2 seconds.
s = ut + (1/2)at²
where,
s = displacement of the object
u = initial velocity of the object
a = acceleration of the object
t = time taken by the object to reach from initial velocity to final velocity
Since the stone is dropped from rest, the initial velocity of the stone, u = 0 m/s.
The acceleration due to gravity, a = 9.8 m/s².
Therefore, we can write the equation as:
s = ut + (1/2)at²
s = 0×2 + (1/2)×9.8×(2)²
s = 19.6 m
Therefore, the stone has traveled 19.6 meters after 2 seconds.
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A machine gun is pointed upward at an angel 30° with respect to the horizontal and fires a projectile with a velocity of 200m/s .find the height and range of the projectile
Answers
The height and range of the projectile are 500 meters.
Solution:
The initial vertical speed is 100m/s (200Sin30) so if g is 10m/s per second it will take 10 seconds to rise and 10 seconds to fall → 20 seconds fire time.
Horizontal velocity is 200Cos30 or 173 m/s
Range? 3460 meters.
Height? The average vertical speed is 50m/s (from 100 to zero) and it rises for 10 seconds. 500 meters.
This equation defines the maximum projectile height from the launch position and depends only on the vertical component of the initial velocity. The maximum horizontal distance a projectile travels is called range. The range is the difference between the lowest and highest values. Indicates that the maximum horizontal distance is four times the maximum height the projectile will reach.
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What is the relevant similarity in the following argument?
"If a single cell, under appropriate conditions, becomes a person in the space of a few years, there can surely be no difficulty in understanding how, under appropriate conditions, a cell may, in the course of untold millions of years, give origin to the human race"
a.
The human race is composed of many humans in the same way a human is composed of many cells
b.
understanding human biology is difficult and understanding the existence of the human race is difficult
c.
both involve biological processes of great complexity taking place under “appropriate conditions” and commencing with a single cell
d.
a person starts from a single cell and an animal life starts from a single cell
Answers
1. On this graph, what is the change in velocity between 5 seconds and 8 seconds?
Answers
2. Circle the best answer:
1000 Newtons
1000 Newtons
A. The forces shown above are PUSHING / PULLING forces.
B. The forces shown above are WORKING TOGETHER/OPPOSITE FORCES.
C. The forces are EQUAL/NOT EQUAL.
D. The forces DO / DO NOT balance each other.
E. The resultant force is 1000 N TO THE RIGHT / 1000 N TO THE LEFT/ZERO.
F. There IS/IS NO motion.
Answers
According to the information we can infer that the forces are PULLING forces, OPPOSITE FORCES, EQUAL, forces DO balance each other, the resultant force is ZERO, and there IS NO motion.
How to explain each element in the image?According to the information of the image, we can conclude that the forces shown above are PULLING forces because they involve pulling a rope on each side. Also, the forces shown above are OPPOSITE FORCES because they act in opposite directions, pulling the rope towards different sides.
On the other hand, the forces are EQUAL in magnitude because each side exerts a force of 1000 Newtons. Additionally, the forces DO balance each other because they have the same magnitude and act in opposite directions. The individuals on each side are exerting equal forces, resulting in a balanced system.
Finally, the resultant force is ZERO because the forces are equal in magnitude and act in opposite directions. The combined effect of the forces is no net force or resultant force and there IS NO motion because the forces are balanced, resulting in a net force of zero. In a balanced system, the objects will remain at rest or in a state of uniform motion.
Note: This question is incomplete. Here is the complete information:
Attached image
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What happens to the resistance of a wire as it gets wider
Answers
Answer:
it snaps
Explanation:
the more force you put on it, the wired out it gets than it snaps. I think
if the air was solid and we were liquid how would this work
Answers
Answer:
Chaos.
Explanation:
Four different insect mouthparts are shown which is best adapted for chewing leaves YXWZ
Answers
Answer:
i think its W, in the picture it looks like a cricket
Explanation:
i got it right on edg 2020
Answer:
w
Explanation:
edg 2921
A sound wave is traveling with a frequency of 880Hz. It has a wavelength of 0.75. What is the speed of the sound wave
Answers
The speed of the sound wave is 660 meters per second.
To calculate the speed of the sound wave, we need to use the formula:
Speed = Frequency x Wavelength
Here, the frequency of the sound wave is given as 880Hz, and the wavelength is given as 0.75. To get the answer, we just need to plug these values into the formula and solve for the speed:
Speed = 880 x 0.75
Speed = 660 meters per second
It's important to note that the speed of sound depends on the medium through which it is traveling. In air, the speed of sound is approximately 343 meters per second at standard temperature and pressure. However, this value can change depending on factors such as temperature, humidity, and altitude.
Understanding the speed of sound is important in various fields, such as music, engineering, and physics. For example, in music, the speed of sound determines the pitch of a note, while in engineering, it can be used to design and optimize acoustic systems. In physics, it's used to study the properties of waves and to explain phenomena such as Doppler effect and sonic booms.
Therefore, the speed of the sound wave is 660 meters per second.
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needing help with this please
Answers
Answer:
So A we cant sadly do because we cant draw. B is going to be kinetic. Thats because static friction means it stays in one place, for kinetic it means moving. So it will be 0.05 as the coefficient of the friction. Sadly, I cannot calculate C. You will have to use trigonemetry but I cannot fit that big an explanation.
Answer to A: the free body diagram would be the ski things inclined with gravity, friction, and air resistance. I except you know which directions
Answer to B: Kinetic friction is the answer.
Answer to C: Find on own, I cannot write super big explanations - use trigonometry.
Find the weight of a man whose mass is 40 kg on earth.
(also
write complete data plus proper formula).
Answers
I am sure it help you with that much ☺️
Explanation:
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How far *
O Speed
O Time
O Distance
Answers
Answer:
How far distance is answer
An object of mass 2kg moves in circles at radius 8m at uniform speed of 30m/s calculate. A_angular velocity B_ceritripetal force
Answers
The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.
The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.
Calculation:-
A. angular velocity ω = v/r
= 30 /8
= 3.75 m/s
B. Centripetal force = mv²/r
= 2×30²/8
= 225 N
There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.
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A bicycle wheel, of radius 0.300 m and mass 1.47 kg (concentrated on the rim), is rotating at 4.00 rev/s. After 56.4 s the wheel comes to a stop because of friction. What is the magnitude of the average torque due to frictional forces? Nm
Answers
Given,
The radius of the wheel, r=0.300 m
The mass of the wheel, m=1.47 kg
The initial angular frequency of the wheel, f=4.00 rev/s
The time it takes for the wheel to come to a stop, t=56.4 s
The final angular velocity of the wheel, ω=0 rad/s
The initial angular velocity of the wheel is
\(\begin{gathered} \omega_0=2\pi f \\ =2\pi\times4.00 \\ =25.13\text{ rad/s} \end{gathered}\)From the equation of motion,
\(\omega=\omega_0+\alpha t\)Where α is the angular acceleration of the wheel.
On substituting the known values,
\(\begin{gathered} 0=25.13+\alpha\times56.4 \\ \Rightarrow\alpha=\frac{-25.13}{56.4} \\ =-0.45\text{ rad/s}^2 \end{gathered}\)The moment of inertia of the wheel whose mass is concentrated on the rim is given by,
\(I=mr^2^{}\)The torque applied by the friction is given by,
\(\begin{gathered} \tau=I\alpha \\ =mr^2\alpha \end{gathered}\)On substituting the known values,
\(\begin{gathered} \tau=1.47\times0.300^2\times-0.45 \\ =-0.06\text{ Nm} \end{gathered}\)The negative sign of the torque indicates that the torque is applied to the wheel in the direction opposite to the direction of rotation of the wheel.
Thus the magnitude average torque due to frictional force is 0.06 Nm
The principle of cross-cutting relationships states that certain features, such as faults, are than the rock layers they cut through. These features are breaks in Earth’s surface where rock has moved sideways, upward, or downward. formations are made of molten rock that has cooled. Those on Earth’s surface are called . Those beneath Earth’s surface are called .
Answers
if a kettle has a power rating of 3000kw how much energy is transferred every second
Answers
\(\\ \sf\longmapsto E=Pt\)
\(\\ \sf\longmapsto E=3000kW(1)\)
\(\\ \sf\longmapsto E=3000KJ\)
A/An _____ is formed when the magnetic fields of electrons are aligned in the same direction.magnetic fieldmagnetic fluxdomainpolarization
Answers
In a region of a material in which the electrons are aligned in such a way their magnetic field produce a magnetic field wit higher intensity, we say that such a region is a domain.
Hence,
A domain is formed when the magnetic fields of electrons are aligned in the same direction.