From where does the penny that is launched into the air get its energy

B. STATIC ELECTRICITY

IS THE CORRECT ANSWER.

JUST FOR MORE KNOWLEDGE ,,...

EVERY ATOM OF MATTER HAS ELECTRONS , AND THESE ELECTIONS HAVE NEGATIVE ELECTRIC CHARGE WHEN YOU RUB TWO OBJECTS TOGETHER, YOU CAN CAUSE THESE CHARGES TO MOVE FROM ONE OBJECT TO ANOTHER .THIS PULLING FORCE BETWEEN UNLIKE CHARGES IS CALLED STATIC ELECTRICITY .

The potential energy  and kinetic energy of the bowling ball are 2,205 J and 37.5 J respectively.

The bowling ball at the given position and speed possess gravitational potential energy and kinetic energy.

The potential energy  and kinetic energy of the bowling ball is calculated as follows;

P.E = mgh

where;

P.E =  (3 x 9.8 x 75 )

P.E = 2,205 J

The kinetic energy of the bowling ball is calculated as;

K.E = ¹/₂ mv²

where;

K.E = ¹/₂ ( 3 ) x (5²)

K.E = 37.5 J

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Answer:

1. troposphere

2. troposphere (still)

3. The most abundant gas in the atmosphere is nitrogen, with oxygen second. Argon, an inert gas, is the third most abundant gas in the atmosphere.

4.The stratosphere is where you'll find the very important ozone layer. The ozone layer helps protect us from ultraviolet radiation (UV) from the sun. In fact, the ozone layer absorbs most of the UV radiation the sun sends to us. Life as we know it wouldn't be possible without this layer of protection.

5. It contains the ozone, which protects Earth from the sun's radiation. Why aren't there many meteors in the troposphere? They burn up before they reach the troposphere.

Explanation:

1.The troposphere is the atmospheric layer closest to the planet and contains the largest percentage (around 80%) of the mass of the total atmosphere. Temperature and water vapor content in the troposphere decrease rapidly with altitude.

2.The layer closest to Earth's surface is the troposphere, reaching from about seven and 15 kilometers (five to 10 miles) from the surface. The troposphere is thickest at the equator, and much thinner at the North and South Poles.

3. Explained in the answer.

4. Explained in the answer.

5. Explained in the answer.

Answer:

1. Not a noun phrase

2. Noun phrase

3. Noun prase

4. Not a noun phrase

Explanation:

Answer:

The measurement of an object's motion with respect to any other object that is moving or stationary is called Relative Motion.

The various process used by farmers from sowing of seeds to the market-ready products are:

Here are the various processes used by farmers from sowing of seeds to the market-ready products:

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Answer:

Echoes. An echo is a sound that is repeated because the sound waves are reflected back. Sound waves can bounce off smooth, hard objects in the same way as a rubber ball bounces off the ground. Although the direction of the sound changes, the echo sounds the same as the original sound.

Explanation:

Rounding to two significant figures, the angular separation is 3.6 degrees.

Angular separation is a measure of the angular distance between two objects in the sky, such as stars, planets, or galaxies. It is expressed in degrees, arcminutes, and arcseconds. Angular separation is used to measure the distance between objects in the sky and to determine the size of celestial objects. It is also used to measure the distances between stars and galaxies, which helps astronomers to understand the size and scale of the universe.

The angular separation of the two spectral lines is equal to the difference between the two wavelengths, \($\lambda_2-\lambda_1$\), multiplied by the number of lines per cm in the spectrometer, \($L$\).
\($$\Delta\theta=\frac{(\lambda_2-\lambda_1) \cdot L}{d}$$\)
Where $d$ is the distance between the two lines in cm.
Using the given information, we can calculate the angular separation:\($$\Delta\theta=\frac{(589.592-588.995)\cdot 3900}{1 cm}=3.597 \ \text{degrees}$$\)
Rounding to two significant figures, the angular separation is 3.6 degrees.

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The alpha decay of polonium-214 can be represented by the following equation: ²¹⁴Po → ⁴He + ²¹⁰Pb

Radioactivity is the phenomenon in which certain types of atomic nuclei are unstable and undergo spontaneous decay, emitting particles and/or energy in the process. This decay can result in the transformation of one element into another and can be characterized by the emission of alpha particles, beta particles, gamma rays, and other types of particles or radiation.

Radioactivity is a natural process that occurs in radioactive materials, such as uranium and radium, as well as in some isotopes artificially produced by nuclear reactors and particle accelerators. For example;

²¹⁴Po → ⁴He + ²¹⁰Pb

In this equation, an alpha particle (⁴He) is emitted from a polonium-214 nucleus (²¹⁴Po), resulting in the formation of a lead-210 nucleus (²¹⁰Pb). The atomic number and mass number are conserved in this process, as the sum of the atomic numbers and mass numbers on both sides of the equation is equal.

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The bending moment from the controlling ASD load combination is 15,000 lb-in.

The bending moment from the controlling ASD load combination can be calculated using the equation M = Md + Ml, where M is the bending moment, Md is the dead load moment, and Ml is the live load moment.

In this case, the dead load moment Md is given as 5,000 lb-in and the live load moment Ml is given as 10,000 lb-in.

Therefore, the bending moment M can be calculated as follows:

M = Md + Ml
M = 5,000 lb-in + 10,000 lb-in
M = 15,000 lb-in

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Answer:

no its not correct ans is 30 use calculator

Explanation:

Answer:corrosion (i believe)

Explanation:

Answer

Mix baking soda and salt with hot water and cover everything with it. The proportions are not crucial, but about 1 tablespoon of salt and 1 tablespoon of baking soda to 3 dl water should do the trick. Lightly tarnished objects should clean up in a few minutes, and you just rinse them of and dry them.

Explanation:

Answer:(d) mass

Explanation: The kilogram is the standard mass unit that is used almost globally and is the SI unit of mass. The kilogram weighs 9.8 Newtons under normal conditions on the surface of the Earth, and Newton is the corresponding SI unit of force and weight.

kinetic energy that moves the robot and its brush.

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Answer:

Potential energy is stored energy and the energy of position.

Explanation:

There are several forms of potential energy. Kinetic energy is motion of waves, electrons, atoms, molecules, substances, and objects. Chemical Energy is energy stored in the bonds of atoms and molecules.

( Hope this helps )

Answer:

The answer is c.nutritionist

Explanation:

because they are a g

Of all the health and wellness careers,  the one has least opportunity for future job growth is nutritionist. The correct option is C.

Career is the most important phase of one's life. This helps a person financially independent by doing job or business.

Currently fitness is all over the people's mind. But the career as a nutritionist has less important or less interest.

Thus,  the one has least opportunity for future job growth is nutritionist.

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P = mv is the equation for linear momentum. Conservation of momentum refers to the fact that the overall amount of momentum remains constant.

Momentum underpins almost all motion-based actions. This principle of physics is crucial. Momentum is a word frequently used in sports. It will be challenging to stop a team that is moving forward, for example.

exclusive nouns Momentum is referred to as a momentum. force, speed, or impulse, as to a material entity or series of events: The car accelerated down and accelerated.

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Science does not  work when every one does the same thing, some creative thinking will be major breakthroughs for an invention. Therefore, option B is correct.

So how do researchers come up with those particular questions to look into ! It may come as a shock to learn how much imagination is required for the procedure.

Peter Medawar, a Nobel Prize-winning biologist, once described scientific inquiry as "the art of the soluble"  In order to succeed in science, one must first identify the questions that may be answered by scientific study and then determine the answers to those questions, according to Medawar.

Because of how intricate the natural world is, it is frequently impossible to directly address the really intriguing, significant scientific topics

The art of science includes repeatedly re-imagining these complex issues, mentally dividing them into more manageable components, and then guessing as to which of these more manageable components might hold the answer to solving the larger issue.

Therefore, all the discoveries and inventions are resulted from the creative ideas and thoughts of scientists. Therefore, creativity is the only way to make a controlled experiment.

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The real power in this circuit is 5.657 watts.

The real power (P) is given by:

P = Veff Ieff cosθ

where Veff is the effective voltage, Ieff is the effective current, and θ is the phase angle between the voltage and current.

To find Veff and Ieff, we need to first determine the root-mean-square (rms) values of the voltage and current:

Vrms = Vmax / √2 = 8 / √2 = 5.657 V

Irms = Imax / √2 = 2 / √2 = 1.414 A

where Vmax and Imax are the maximum values of the voltage and current, respectively.

To find the phase angle, we need to compare the phase angles of the voltage and current. The voltage is given as v(t) = 8 cos(ωt) and has no phase shift, so its phase angle is 0°. The current is given as i(t) = 2 cos(ωt π/6), which has a phase shift of π/6 or 30°. Therefore, the phase angle between the voltage and current is θ = 0° - 30° = -30°.

Finally, we can calculate the real power as:

P = Veff Ieff cosθ

= (5.657 V) (1.414 A) cos(-30°)

= 5.657 W

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Answer:

4.18 joules of heat energy to raise a gallon of water by 1 degree celcius

Explanation:

The distance between the negative plate and the point at which the electron and proton pass each other is 0.333 cm. (0.333 cm is the correct answer with three significant figures.

We are given: The two parallel plates are 0.500 cm apart. They are equally and oppositely charged. An electron is released from rest at the surface of the negative plate. A proton is released from rest at the surface of the positive plate. We need to find the distance between the negative plate and the point at which the electron and proton pass each other Part A We can use the equations of motion to determine the distance between the negative plate and the point at which the electron and proton pass each other. These equations relate the distance covered by a moving object, acceleration, time, and initial velocity.

The electron and proton are moving from rest with the acceleration due to electric field between the plates. The magnitude of the acceleration due to electric field between the plates is given byE = F/q = V/d where, F is the force on a charge q due to electric field E; V is the potential difference between the plates; and d is the distance between the plates. The potential difference between the plates is given byV = Edso, the magnitude of the acceleration due to electric field between the plates ise = V/dUsing Newton's second law of motion, we haveF = maThe force on an electron and a proton is given byFe = -eE  and Fp = eE, respectively, where -e is the charge on an electron and e is the charge on a proton.From the above expressions, we havea = Fe/me and a = Fp/mpwhere me and mp are the masses of an electron and a proton, respectively.

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A conductor is made in the form of a hollow cylinder with inner and outer radii a and b, respectively. It carries a current I, uniformly distributed over its cross section. We are given that

Consider a loop of radius r where r<a

A conductor is an object or kind of material that permits the movement of charge (electric current) in one or more directions. This term is used in both physics and electrical engineering. Metal-based materials are frequently used as electrical conductors. Negatively charged electrons, positively charged holes, and occasionally positive or negative ions flow to create electric current.

It is not essential for one charged particle to move from the component creating the current (the current source) to those consuming it for current to flow within a closed electrical circuit (the loads). Instead, the charged particle only needs to nuzzle its neighbor a limited number of times, and then the process repeats itself until a particle gets nuzzled into the consumer, generating electricity.

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The acceleration that a sled experiences when a child pushes on a 10 kg sled at an angle of 13 degrees below the horizontal with the sled being pushed across the frictionless horizontal surface in the positive direction, and experiences a normal force of 116 N is 1.92 m/s².

We can use the following steps to solve the problem: Step 1: Draw a Free Body Diagram. The sled has four forces acting on it: Normal force, N, acts perpendicularly to the surface of the sled. Weight, W, acts straight down, vertically. Force of the child, F, acts at an angle of 13 degrees below the horizontal. Force of friction, f, is absent in this problem.  Step 2: Resolve forces. The force of the child has both vertical and horizontal components, which can be written as:

\(Fcosθ =  F x cos(13°) = (58.94 N) cos(13°) = 55.34 N.\)

\(Fsinθ =  F x sin(13°) = (58.94 N) sin(13°) = 13.60 N.\)

Weight can be calculated as follows:

\(W = m*g = 10 kg * 9.8 m/s² = 98 N.\)

The normal force is equal in magnitude to the weight of the sled: N = W = 98 N. Step 3: Write the equation of motion. The net force acting on the sled is the horizontal component of the force of the child: F net = Fcosθ.

The acceleration of the sled is given by :

\(a = F net/m.\)

We can now substitute the values to calculate the acceleration:

\(a = F net/m = (55.34 N)/(10 kg) = 5.534 m/s².\)

Therefore, the acceleration that this sled will experience is 1.92 m/s² (to the right, since the sled is pushed in the positive direction).In this problem, a child pushes on a 10 kg sled at an angle of 13 degrees below the horizontal.

The sled is pushed across the frictionless horizontal surface in the positive direction, and experiences a normal force of 116 N. The acceleration that this sled will experience is 1.92 m/s² (to the right, since the sled is pushed in the positive direction).

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The angle travelled by the car when its total acceleration is 2.6 m/s² is 1.07 Radians.

Tangential acceleration of the car, a₁ = 1.1 m/s²

Total acceleration of the car, a₂ = 2.6 m/s²

The centripetal acceleration of the car, a = √(2.6² - 1.1²) = 2.356 m/s²

Radius, R = 110 m

Centripetal acceleration = v²/R = 2.356

v² = 2.356 × 110

v = 16.01 m/s

Time taken by the car the velocity from the rest to 16.01 m/s speed.

t = (v - u)/a₁

t = (16.01 - 0)/1.1  = 14.63 seconds

Distance travelled by the car during these 14.63 seconds,

S = ut + 0.5at²

S = 0 × 14.63 + 0.5×1.1×14.63²

S =  117.8 m

Angle travelled by the car = arc/radius

= 117.8/110

= 1.07 radians

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Answer:

t = S / V = 3.8E8 / 3E8 = 1.3 sec

It takes over 1 second for a radio signal to travel between the earth and the moon.

Answer:

1181.63 m

Explanation:

Assume : specific heat for copper = 386 J/kg.k

Determine the height a 300k  cu ball can lift itself after transforming all its thermal energy to work

Total thermal energy of ball =  386J/kg.k * 300 k

                                                = 115800 J

when we convert to potential energy ( work )  applying the law of conservation of energy

11580 J = mgh

11580 = 1 * 9.8 * h       ( note m = 1 because the cu is just 1 unit )

∴ h ( height attained ) = 11580 / 9.8   = 1181.63 m

The answers are Part A: The acceleration of the centre of the hoop is a = μ * g and Part B: The minimum coefficient of static friction required is μ >= \(sin(\theta).\)

Part A: To determine the acceleration of the centre of the hoop, we can consider the forces acting on it. The gravitational force can be decomposed into two components: one parallel to the ramp and the other perpendicular to it. The component parallel to the ramp is responsible for accelerating the hoop down the incline. It can be calculated as m * g * sin(theta), where m is the mass of the hoop and theta is the angle of the ramp with the horizontal.

Since the hoop is rolling without slipping, the frictional force opposes the motion and prevents slipping. The frictional force can be expressed as the product of the coefficient of friction (μ) and the normal force. The normal force acting on the hoop is equal to the weight of the hoop, which is m * g. Therefore, the frictional force is μ * m * g.

Considering the torque equation for rolling motion, the torque due to the net force on the hoop must be equal to the product of the moment of inertia (I) and the angular acceleration (α). For a hoop, the moment of inertia is given by \(I = m * r^2\).

By equating the torque and the net force, we have:

\(\mu * m * g * r = m * r^2 * \alpha\)

Since the hoop rolls without slipping, the linear acceleration (a) of the center of the hoop is related to the angular acceleration as a = r * α.

Substituting this into the equation above, we have:

μ * g = r * α

Therefore, the acceleration of the center of the hoop is given by a = μ * g.

Part B: The minimum coefficient of static friction (μ) required for the hoop to roll without slipping can be determined by considering the limiting condition when slipping is about to occur. In this case, the maximum static frictional force (\(f_s\)) is equal to the product of the coefficient of static friction and the normal force.

The normal force acting on the hoop is equal to the weight of the hoop, which is m * g. Therefore, the maximum static frictional force is μ * m * g.

To prevent slipping, the maximum static frictional force must be greater than or equal to the component of the gravitational force parallel to the ramp, which is m * g * sin(theta).

Setting up the inequality, we have:

μ * m * g >= m * g * \(sin(\theta)\)

Canceling out the mass and gravity terms, we obtain:

μ >= \(sin(\theta)\)

Therefore, the minimum coefficient of static friction needed for the hoop to roll without slipping is equal to the sine of the angle of the ramp with the horizontal, μ >= \(sin(\theta).\)

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