G the hydrogen generated in this lab was a product of the reaction between magnesium and hydrochloric acid. which of these reactants is the limiting reactant? magnesium saved (1pts) provide experimental evidence to support your choice.

Answer: Helium exhibit less density as compared to oxygen and nitrogen thus the balloons floats in the mass of air.

Explanation:

Oxygen has an atomic mass of 15.994 and nitrogen has an atomic mass of 14. 006. The helium which is a noble gas has an atomic mass of 4. 002. This is indicative of the fact that the helium is less denser than the air containing oxygen and nitrogen. Thus as a result of this the helium floats on the air being lighter then the other components of air and hence, the helium balloons float in the air.

No, the volume of water in a beaker is not an extensive property.

Extensive properties are those that depend on the amount or size of the substance being measured. In other words, they are properties that change with the quantity of the substance. Examples of extensive properties include mass, volume, and total energy.

In the given scenario, the volume of water in the beaker is 50 milliliters. This volume remains the same regardless of the quantity of water present. Whether it's 50 milliliters or 500 milliliters, the volume measurement does not change. Therefore, the volume of water in the beaker is an example of an intensive property.

Intensive properties are independent of the amount or size of the substance. They are characteristics that remain constant regardless of the quantity of the substance. Examples of intensive properties include temperature, density, and color.

It's important to note that the distinction between extensive and intensive properties depends on the specific property being considered. While volume is typically an extensive property for a bulk substance, in the case of a fixed volume of water in a beaker, it becomes an intensive property.

In summary, the volume of water in a beaker is not an extensive property but rather an intensive property because it does not change with the quantity of the substance.

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The dot structure that can be shown to be incorrect is the dot structure that has been shown by option A

The Lewis structure is based on the concept that atoms tend to gain, lose, or share electrons in order to achieve a stable electron configuration similar to that of a noble gas. In the Lewis structure, the valence electrons of the atoms are represented as dots around the symbol of the atom.

We can see that in the dot structure that is in option A the both atoms are coming from the hydrogen atoms and shoud not be differently marked.

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Free energy change for transporting Ca2+ ions is calculated as follows:∆G = RT ln ([Ca2+]outside/[Ca2+]inside)∆G = 8.315 J/mol.K x 310 K x ln (25 mM/145 mM) = -15,400 J/mol.

Here, ∆G is negative, which implies that Ca2+ ions transport spontaneously from the cell to blood. This is because the free energy of the system decreases when Ca2+ ions move from high concentration to low concentration. Therefore, transporting Ca2+ ions is energetically favorable.

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Answer:

A) photon

Explanation:

hope it helps and give brainliest if its correct

Answer:

Explanation:

Answer:

construction aka A

Explanation:

got 100

Answer:

Independent Variable (IV) with units : Independent Variable (IV) is defined as the variable that can be changed or manipulated in order to find the outcome. Examples of IV with units include temperature (degree Celcius), Pressure (pascal) and time (second, minutes or hours).

Dependent Variable (DV) with units:  Dependent Variable (DV) is defined as the variable that is measured in an experiment and gives outcomes by the influence of Independent Variable (IV). Examples of DV with units include Height (centimeter or meter) and Density ( kilograms per cubic meter)

High and low data points: Data points are defined as the set of measurements on a single member in an observation. High and low data points are two coordinates that represent the accuracy of the experiments.

Answer:

220

Explanation:

2.2 x 10^2

You just move the decimal two units to the right...

Hope this helps:)

Answer: B

Explanation:

Answer:

B. Both substances must be the same temperature.

Explanation:

Answer:

1000 years.

Explanation:

I'm not shure how to explain. it is a facr

Answer:

\( \huge{ \boxed{1.213 \: \text{moles}}}\)

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\( \bold{n = \frac{N}{L}} \\ \)

where

From the question

N = 7.30 × 10²³ NaCl molecules

\(n = \frac{7.30 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{7.30}{6.02} \\ = 1.2126\)

We have the final answer as

The probability that a person has the disease given that the test indicates the presence of the disease is approximately 0.9968

To calculate the probability that a person has the disease given that the test indicates the presence of the disease, we can use Bayes' theorem.

Let's denote:

A = Event of having the disease

B = Event of the test indicating the presence of the disease

We are given the following probabilities:

P(A) = 0.03 (3% of the population actually has the disease)

P(B|A) = 0.93 (the test indicates the presence of the disease 93% of the time when the disease is actually present)

P(B|not A) = 0.004 (the test indicates the presence of the disease 0.4% of the time when the disease is not present)

We need to find P(A|B), the probability that a person has the disease given that the test indicates the presence of the disease.

Applying Bayes' theorem:

\(P(A|B) = (P(B|A) * P(A)) / P(B)\)

To calculate P(B), we can use the law of total probability:

\(P(B) = P(B|A) * P(A) + P(B|not A) * P(not A)\)

\(P(not A) = 1 - P(A) = 1 - 0.03 = 0.97\)

Substituting the values into the equation:

\(P(B) = (0.93 * 0.03) + (0.004 * 0.97) ≈ 0.0279\)

Now, calculating P(A|B):

\(P(A|B) = (0.93 * 0.03) / 0.0279 ≈ 0.9968\)

Therefore, the probability that a person has the disease given that the test indicates the presence of the disease is approximately 0.9968 (rounded to four decimal places).

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Answer: The main difference between silicate minerals and nonsilicate minerals is that silicate minerals are composed of silicate groups whereas Nonsilicate minerals have no silicate groups.

Explanation:

The % acetic acid by mass in the vinegar sample is 5.14%.

The first step is to calculate the mass of the vinegar sample using its density:

Mass of vinegar = Volume of vinegar x Density of vinegar

Mass of vinegar = 5.00 ml x 1.00 g/ml = 5.00 g

Next, we can use the mass of acetic acid in the sample to calculate the percentage of acetic acid by mass:

% Acetic Acid = (Mass of acetic acid / Mass of vinegar) x 100%

% Acetic Acid = (0.2568 g / 5.00 g) x 100%

% Acetic Acid = 5.14%

To solve the problem, we first need to know the mass of the vinegar sample. We are given its volume and density, so we can use the density formula (density = mass / volume) to calculate the mass. Once we have the mass of the vinegar, we can use the mass of acetic acid in the sample (also given) to calculate the percentage of acetic acid by mass using the formula % Acetic Acid = (Mass of acetic acid / Mass of vinegar) x 100%.

This formula calculates the proportion of the mass of the sample that is due to acetic acid. Finally, we multiply the result by 100% to express the answer as a percentage. Therefore, the percentage of acetic acid by mass is 5.14%.

The complete question is

A 5.00 ml sample of vinegar contains 0.2568 g of acetic acid. if the density of vinegar is 1.00 g/ml, calculate the % acetic acid by mass.

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Answer:

Br2+KI→KBr+I2

Explanation:

Answer:

During the process of polymerization, monomers

combine by sharing electrons. This process forms a polymer, which is made of repeating subunits. The resulting material is used in a variety of ways.

Answer:

monomers and polymer.

Explanation:

Answer:

y  = 13x + 4

Explanation:

Given parameters:

number of computer games bought  = x

cost of each games  = $13

number of a magazine  = 1

cost of magazine  = $4

Unknown:

Total amount of money spent = ?

Solution:

The total amount spent;

  let total amount  = y

 y  = total cost of magazine + total cost of computer games

 total cost of magazine  =$4

 total cost of computer games  = 13x

y  = 13x + 4

The Nernst equation can be used to calculate the equilibrium constant of a reaction, given the half-reactions and the standard electrode potentials of the species involved in the reaction. We can use the Nernst equation to calculate the equilibrium constant (K) for the reaction below:Al3+ (aq) + 6F-(aq) → AlF63-(aq).

The half-reactions for the reaction are:Al3+ + 3e- → Al E° = -1.66 VF- → F- + e- E° = -2.87 V.

The Nernst equation is: E = E° - (RT/nF) ln(Q) where E is the electrode potential, E° is the standard electrode potential, R is the gas constant, T is the temperature in Kelvin, n is the number of electrons transferred, F is the Faraday constant, and Q is the reaction quotient.

For the reaction above: Q = [AlF63-] / ([Al3+] [F-]6) n = 6 (since 6 electrons are transferred) E°cell = E°(AlF63-) - E°(Al3+) - E°(F-)E°cell = -1.66 V - (-2.87 V) - 6(0.0257 V) * log ([AlF63-] / ([Al3+] [F-]6))E°cell = 1.21 V.

At equilibrium, Ecell = 0:0 = 1.21 V - (0.0257 V) * log (K)K = 2.12 x 1015.

Therefore, the equilibrium constant at 25°C for the reaction Al3+ (aq) + 6F-(aq) → AlF63-(aq) is K = 2.12 x 1015.

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A title, introduction, materials, methods, findings, discussion, and conclusion should be included in a lab report for this lesson's experiment. The experiment should be described briefly in the title, such as "Determining the Effect of Temperature on the Rate of Enzyme Activity."

The methods section should include a full account of how the experiment was carried out, including any calculations that were used. All collected data, such as tables or graphs,  methods of using the tacts should be included in the results section.

The discussion section should describe the findings and compare them to the Expected findings must be provided, as well as an explanation for any unexpected results. The conclusion should summarise the findings and respond to the initial hypothesis. Finally, any relevant references should be included in the report.  

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Answer:

Wavelength (λ) = 1.875 × 10⁻⁶ m

Explanation:

Given:

Energy (e) =  1.06 × 10⁻¹⁹ J

Find:

Wavelength (λ) = ?

Computation:

e = hc / λ

λ = hc / e

where c = 3 × 10⁸

Planck's constant (h) = 6.625 × 10⁻³⁴

So,

Wavelength (λ) = (6.625 × 10⁻³⁴)(3 × 10⁸) / (1.06 × 10⁻¹⁹)

1. Wavelength (λ) = 1.875 × 10⁻⁶ m

2. Given n = 4 to n = 3 both are integer not fraction so, electron is quantize

Carbon-14 (C-14) has 6 protons and 8 neutrons.

Carbon-14 is one of the isotopes of the element carbon. The atomic number of carbon is 6, which indicates the number of protons in its nucleus. Since C-14 is a specific isotope of carbon, it still has 6 protons.

Neutrons, on the other hand, contribute to the mass of the atom but do not affect its chemical properties. Carbon-14 has a mass number of 14, which means it has a total of 14 nucleons (protons + neutrons). To determine the number of neutrons, subtract the atomic number (protons) from the mass number. In this case, 14 - 6 = 8, so carbon-14 has 8 neutrons.

In summary, carbon-14 (C-14) has 6 protons and 8 neutrons. The atomic number determines the number of protons, while the mass number allows us to calculate the number of neutrons.

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The statement 'Science provides only a limited understanding of the supernatural issues such as art, philosophy, or religion" is TRUE because it is based on empirical evidence.

Science can be defined as a body of knowledge derived from applying the scientific method, which allows us to collect empirical evidence about the real world.

Supernatural issues such as art, philosophy, or religion cannot be scientifically explained because they are often based on a subjective point of view.

In conclusion, the statement 'Science provides only a limited understanding of the supernatural issues such as art, philosophy, or religion" is TRUE because it is based on empirical evidence.

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Large sand and gravel formations often comprise silicate minerals in the sand.

The loose substance known as gravel, commonly referred to as crushed stone, is mostly composed of rock pieces. Basalt, dolomite, and sandstone are the most frequent forms of bedrock found in gravel.

Gravel that is around this size is good for driveways or walkways. The stones must be smooth and easy to walk across with little effort. Pick gravel that is angular and won't move around much. The best gravel for walkways is 10mm or 14mm.

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The complete question is-

Sand found in commercial sand and gravel deposits is typically composed of _______.

Option a is correct. Maggots are collected from a crime scene they should be preserved in 70% ethanol.

Maggots must first be collected using sterile tweezers or forceps and placed in a sterile container before being preserved in 70% ethanol. Then, pour enough 70% ethanol into the container to thoroughly cover the maggots.

The container must be properly labeled with pertinent details including the date, place, and time of collection, and it must be completely sealed. Other preservation techniques, such as employing 30% isopropanol are less frequently employed and might not be as efficient as using ethanol.

It is crucial to remember that using sterile water as a preservative is not advised because it could hasten the decay of the maggots and weaken any potential DNA evidence.

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Complete question

When maggots are collected from a crime scene, how should they be preserved?

a. 70% ethanol

b. 50% ddt

c. 30% isoproponol

d. sterile water

After the calculating we have Test statistic: -3.874.

Critical values: -2.086 and 2.086.

To test if the population mean pH of rainwater is equal to 5.4, we can perform a one-sample t-test.

We have the data:

Population mean (μ) = 5.4

Sample mean (x) = 4.7

Sample standard deviation (s) = 0.8

Sample size (n) = 21

Significance level (α) = 0.05

To calculate the test statistic, we can use the formula:

t = (sample mean - population mean) / (sample standard deviation / sqrt(sample size))

Plugging in the values:

t = (4.7 - 5.4) / (0.8 / √(21))

Calculating:

t ≈ (-0.7) / (0.8 / 4.582)

t ≈ -3.874

The test statistic is approximately -3.874.

To find the critical values, we need to refer to the t-distribution table or use statistical software. At a significance level of α = 0.05 with (n-1) degrees of freedom (n = sample size), the critical values for a two-tailed test are approximately -2.086 and 2.086.

Therefore, the correct answer is:

Test statistic: -3.874.

Critical values: -2.086 and 2.086.

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The pH of the base before the titration begins is 7.

To calculate the pH, we need to consider the concentration of the conjugate acid. Since propylamine is initially present in excess, the concentration of the conjugate acid will be negligible. Thus, the pH of the base before the titration begins will be determined by the dissociation of water.

Water undergoes autoionization to form hydronium (H3O+) and hydroxide (OH-) ions.

At 25°C, the concentration of both ions is 1.0 x 10^-7 M.

To find the pH, we can calculate the concentration of hydronium ions and take the negative logarithm

(pH = -log[H3O+]).

Therefore, the pH of the base before the titration begins is 7.

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Answer:

Explanation:

The sum of the coefficients is 1 + 3+ 2+ 3 = 9

Answer:

There is no answer. This equation is unbalancable.

Explanation:

The numbers for Al always throw off the entire equation!

The amount, in grams, of radon that will be collected in the office sample of air, would be 148.8 grams.

The air sample contains 3.20 x 10⁻⁴ mg of radon per mL of gas. A total air volume of 4.65 x 10⁴ L passed through the office. The amount of radon in the air that passed through the office can be estimated as follow:

Amount of radon per mL of gas = 3.20 x 10⁻⁴ mg

Total volume of air in sample = 4.65 x 10⁴ L

The total air volume needs to be converted to mL:

4.65 x 10⁴ L x 1000 = 4.65 x \(10^7\) mL

1 mL = 3.20 x 10⁻⁴ mg

4.65 x \(10^7\) mL = 4.65 x \(10^7\) x 3.20 x 10⁻⁴

                       = 14.88 x \(10^4\) mg

In other words, the total amount of radon gas in the sample of air is 14.88 x \(10^4\) mg.

1 g = 0.001 mg

14.88 x \(10^4\) mg = 14.88 x \(10^4\)/1000

                        = 148.8 grams

In summary, the total amount of radon gas that will be collected in the office sample would be 148.8 grams.

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