g why is the deflection not linear for larger deflections since by equation 25.12 it should be linear for all deflections?

SCI content that is secret may be processed over Siprnet. This assertion is untrue.

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There are different kinds of Ac motors. If the goal is to power three-phase AC motor, the three-phase motor can be run from a single-phase power source.

The act of running a three phase motor on single phase power is very possible. The thing one has to do is  to connect or wire the single phase power to the input side of the variable frequency drive that one has and then connect or wire the three phase power of one's motor to the output part of the drive.

Conclusively, A three phase system is known to be able to send a lot of power when viewed with the single phase system.  The three circuit conductors is known to have three alternating currents

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Answer:

final temperature = 26.5°

Explanation:

Initial volume of water is 1 x 1 x 1 = 1 \(m^{3}\)

Initial temperature of water = 20° C

Density of water = 1000 kg/\(m^{3}\)

volume of copper block = 0.46 x 0.46 x 0.46 = 0.097 \(m^{3}\)

Initial temperature of copper block = 100° C

Density of copper = 8960 kg/\(m^{3}\)

Final volume of water = 1 - 0.097 = 0.903 \(m^{3}\)

Assumptions:

mass of water remaining in the tank will be density x volume = 1000 x 0.903 = 903 kg

specific heat capacity of water c = 4186 J/K-kg

heat content of water left Hw = mcT = 903 x 4186 x 20 = 75.59 Mega-joules

mass of copper will be density x volume = 8960 x 0.097 = 869.12 kg

specific heat capacity of copper is 385 J/K-kg

heat content of copper Hc = mcT = 869.12 x 385 x 100 = 33.46 Mega-joules

total heat in the system = 75.59 + 33.46 = 109.05 Mega-joules

this heat will be distributed in the entire system

heat energy of water within the system = mcT

where T is the final temperature

= 903 x 4186 x T = 3779958T

for copper, heat will be

mcT = 869.12 x 385 = 334611.2T

these component heats will sum up to the final heat of the system, i.e

3779958T + 334611.2T = 109.05 x \(10^{6}\)

4114569.2T = 109.05 x \(10^{6}\)

final temperature T = (109.05 x \(10^{6}\))/4114569.2 = 26.5°

Answer: outrigger ??

Explanation:

Cranes and derricks installed on floating surfaces must have a stability test.

Stability testing is a method of determining the quality and behavior of a system or software in various environmental parameters such as temperature, voltage, and so on.

Cranes and derricks installed on floating surfaces such as barges or ships must be stable.

This is because the weight and position of the crane or derrick, as well as the load being lifted, can affect the stability of a floating surface.

Without proper stability calculations, the crane or derrick could capsize or become unstable, resulting in accidents or injuries. Understanding and managing your barge's stability is critical to its safety.

Thus, it should have a stability test to installed an floating surfaces.

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Answer:

Resistance = 3 Ω

Explanation:

As we know that, By Ohm's Law

V = IR

where

V is the voltage in volt

I is the current in amps

R is the resistance in ohm

Now,

Given that,

V = 15 volts

I = 5 amps

So,

R = V/I

  = 15/5

 = 3 Ω

⇒R = 3 Ω

Answer:

Used to recall the direction a standard screw

Answer:

  14,700 J

Explanation:

PE = Mgh = (75 kg)(9.8 m/s²)(20 m) = 14,700 J

Answer: true

Explanation:

Answer:

Resistance = 360,000 Ω = 360 kΩ

Tolerance = +/- 5%

Explanation:

You can follow a four-band resistor chart to determine resistance and tolerance based off each column.

1st Band = Orange = 3

2nd Band = Blue = 6

3rd Band = Yellow = 10,000 Ω (this is the multiplier)

Resistance = 36 * 10,000 Ω = 360,000 Ω = 360 kΩ

4th Band = Gold = +/- 5% Tolerance

Answer:

not understand language

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

Answer:

ee

Explanation:

This is an over the top question

The program requires a sequence control structure; First, we get input for the variables, and then use the formula to calculate the amount of calories burnt.

The program in python is as follows, where comments (in italics) are used to explain each line.

#This gets input for age, in years

age = int(input("Age (years): "))

#This gets input for weight, in pounds

weight = int(input("Weight (pounds): "))

#This gets input for heart rate, in beats per minutes

heart_rate = int(input("Heart Rate (beats per minutes): "))

#This gets input for time, in minutes

time = int(input("Time (Minutes) : "))

#This calculates the calories burnt for men

calories_man = ((age * 0.2017) - (weight * 0.09036) + (heart_rate * 0.6309) - 55.0969) * time / 4.184

#This calculates the calories burnt for women

calories_woman = ((age * 0.074) - (weight * 0.05741) + (heart_rate * 0.4472) - 20.4022 ) * time / 4.184

#This prints the calories burnt for men

print('Men: %0.2f calories' % calories_man)

#This prints the calories burnt for women

print('Women: %0.2f calories' % calories_woman)

Please note that the program does not check for valid inputs

See attachment for program output

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The first-order kinematic coefficient of the gear train is 0.028. Gear 8 rotates in the clockwise direction with a speed of 42.86 rev/min.

The first-order kinematic coefficient of the gear train is a measure of the efficiency of power transmission through a gear train. It is defined as the ratio of the output speed of the final gear to the input speed of the first gear. In this case, the first-order kinematic coefficient is 0.028, which means that the output speed of gear 8 is only 2.8% of the input speed of gear 4.

To determine the rotational direction and speed of gear 8, we first need to identify the gear ratios for each pair of gears in the train. Starting from gear 4, we have a gear ratio of 44/15, which means that gear 5 rotates at a slower speed than gear 4 but with higher torque. Similarly, the gear ratio between gears 5 and 6 is 33/36, which means that gear 6 rotates at a faster speed than gear 5 but with lower torque.

Finally, we can calculate the speed and direction of rotation of gear 8 by multiplying the gear ratios of all the gears between gear 4 and gear 8. We have:

44/15 * 33/36 * 487/36 = 42.86

This means that gear 8 rotates at a speed of 42.86 rev/min in the clockwise direction.

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A project team may choose to prepare a low-fidelity version of a website design using sticky notes for several reasons:

Sticky notes allow for quick and easy changes. Since they are easy to move around and modify, the team can iterate on the design quickly, making adjustments and improvements without investing significant time or resources. This promotes an iterative design process, enabling the team to refine and enhance the design rapidly.Collaboration and Communication: Sticky notes facilitate collaboration and communication among team members. They can be easily placed on a whiteboard or a wall, allowing everyone to visualize and discuss the design together. Team members can share their ideas, suggestions, and feedback by directly manipulating the sticky notes, fostering effective communication and collaboration within the team.Low Cost and Accessibility: Sticky notes are affordable and readily available, making them a cost-effective option for creating prototypes. Compared to digital design tools or high-fidelity prototypes, sticky notes are inexpensive and accessible to all team members, regardless of their technical expertise. This inclusivity encourages participation from different stakeholders and promotes a diverse range of perspectives during the design process.Focus on Conceptual Design: Low-fidelity designs with sticky notes primarily focus on the conceptual aspects of the website, such as layout, content organization, and user flow. By avoiding intricate details or visual aesthetics, the team can concentrate on the fundamental structure and functionality of the design. This allows for early validation and testing of design concepts before investing significant time and resources in higher-fidelity prototypes.Emphasis on User Experience: Sticky notes enable the team to simulate user interactions and test the usability of the design. By physically moving and rearranging the sticky notes, the team can simulate user flows and assess the user experience. This hands-on approach allows for early identification of potential usability issues, leading to design improvements and a better user experience.

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The Equivalent Service Life (ESL) of the injection molding system is determined to be 3 years, and the respective Annual Worth (AW) value of the system is calculated.

To determine the Equivalent Service Life (ESL) and Annual Worth (AW) value of the injection molding system, we need to calculate the Present Worth (PW) of costs and salvage value over the system's maximum useful life of 5 years. The first cost of $180,000 and the salvage value of 25% of the first cost ($45,000) are considered.

The annual operating cost of $95,000 in years 1 and 2, increasing by $4,500 per year thereafter, is converted to an equivalent uniform annual cost (EUAC) using the given MARR (12% per year). This EUAC is then added to the salvage value to obtain the PW.

By comparing the PW values at different service lives (1 to 5 years), the ESL is determined to be 3 years, which corresponds to the minimum PW value. The AW value is then calculated by dividing the PW by the ESL.

By considering the MARR, the cash flows over the system's life, and the salvage value, the ESL and AW value of the injection molding system can be determined, providing insights into the economic performance of the system over time.

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Answer:

a). \($0.0436 \ ft^3/s$\) , \($2.72 \ lb \ m/s$\)

b). \($61.32 \ s$\)

c). 32. ft/s

Explanation:

a). The volume flow rate of the water is given by :

\($\dot V = uA$\)

   \($=u \pi \left( \frac{d}{2}\right)^2$\)

   \($=\frac{u \pi d^2}{4}$\)

   \($=\frac{8\ ft/s \ \pi \left(\frac{1}{12}\right)^2}{4}$\)

    \($= 0.0436 \ ft^3/s$\)

The mass flow rate of the water is given by :

\($\dot m = \rho \dot V$\)

    \($= 62.4 \times 0.0436$\)

    \($=2.72 \ lb \ m/s$\)

b). The time taken to fill the container is

     \($\Delta t = \frac{V}{\dot V}$\)

          \($=\frac{20 \ gal}{0.0436 \ ft^3/s}\left( \frac{1 \ ft^3}{7.4804 \ gal}\right)$\)

          \($=61.32 \ s$\)

c). The average velocity at the nozzle is :

\($u=\frac{\dot V}{A}$\)

  \($=\frac{\dot V}{\frac{\pi d^2}{4}}$\)

  \($=\frac{0.0436}{\frac{\pi \left(\frac{0.5}{12}\right)^2}{4}}$\)

  = 32. ft/s

Answer:

Anything you want to do in Hootsuite can be found in the ___ Sidebar_____, with the main workspace in the ___center______

Sidebar; center

Explanation:

The main workspace of the Hootsuite is located in the center.  The sidebar is where the core access to the Hootsuite functionality, like Streams, Inbox, Planner, Analytics, Publisher, and the App Directory, is obtained.  Hootsuite is a media management platform for curating content, scheduling posts, managing team members, and measuring performances.

Answer: 50

Explanation:

Answer:

Hermetic compressors are ideal for small refrigeration systems, where continuous maintenance cannot be ensured.

9514 1404 393

Answer:

  1

Explanation:

Only one such circle can be drawn. The diameter of the 10" circle will be a radius of the semicircle. In order for the 10" circle to be wholly contained, the flat side of the semicircle must be tangent to the 10" circle. There is only one position in the figure where that can happen. (see attached).

Answer:

The voltage across the internal resistor is -16.67V. This negative sign indicates that the voltage drop is in the opposite direction to the current flow. It means that the internal resistance of the battery is causing a loss of voltage in the circuit, which reduces the overall output voltage of the battery.

When a battery is connected in a circuit, it has an internal EMF (electromotive force) and an internal resistance. In this scenario, the battery has an internal EMF of 10V and an internal resistance of 1 ohm. It is connected in series with a resistor of resistance R and an external resistor of 5 ohms.
The voltage across the internal resistor can be calculated using Kirchhoff's voltage law (KVL). According to KVL, the sum of all voltages in a closed loop is zero. Hence, we can write:
V_internal + V_external + V_R = 0
Here, V_internal is the voltage across the internal resistor, V_external is the voltage across the external resistor (which is equal to the voltage output of the battery), and V_R is the voltage drop across the resistor R.
Since the external resistor is 5 ohms and the internal resistor is 1 ohm, the current flowing through the circuit can be calculated using Ohm's law:
I = V_external / (R_internal + R_external)
I = 10 / (1 + 5)
I = 10 / 6
Now, the voltage drop across the external resistor can be calculated as:
V_external = I * R_external
V_external = (10 / 6) * 5
V_external = 8.33V
Therefore, the voltage across the internal resistor can be calculated as:
V_internal = - (V_external + V_R)
V_internal = - (8.33 + (I * R))
V_internal = - (8.33 + ((10 / 6) * R))
This equation gives us the voltage across the internal resistor in terms of the value of R. To get a specific value, we need to know the resistance of the external resistor. If the external resistor is 5 ohms, then the voltage across the internal resistor can be calculated as:
V_internal = - (8.33 + ((10 / 6) * 5))
V_internal = - (16.67)
In conclusion, the voltage across the internal resistor can be calculated using KVL and Ohm's law. It depends on the value of the external resistor and the internal resistance and EMF of the battery. In this case, the voltage across the internal resistor is negative, indicating a loss of voltage in the circuit due to the internal resistance of the battery.

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Answer:

C

Explanation:

True is the answer.....

To cool a given room it is necessary to provide 4 ft³/s of air through an 8-inches diameter pipe, for this Entrance length in this pipe = 17.7 ft

Q = 4ft³/s

Diameter = D = 8 inches

Entrance length in this pipe = \(l_{e}\) = ?

By using flow rate formula:

V = Q/A

V= Q/ π/4*D²

= 4ft³/s / π/4 (8/12 ft)²

V= 11.5 ft/s

Thus, with ν = 1.57 x 10⁻⁴ft²/s (value from table)

Re = VD/ν

Re = 11.5 ft/s (8/12 ft)/1.57x10⁻⁴ft²/s

Re = 48,800 > 4000 (based on the criteria)

so, the flow is turbulent

Hence,

\(l_{e} / D\) = \(4.4 R_{e}^{1/6}\)

\(l_{e}\) = 4.4 (48,800)\(^{1/6}\) (8/12)

\(l_{e}\) = 17.7 ft

Entrance Length of an 8-inch diameter pipe = 17.7 ft

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Answer:

Explanation:

1. Lumped Heat Capacity: A lumped heat capacity is a simplified model that assumes that the heat capacity of a system is concentrated in a single lump or point, rather than distributed throughout the system. This model is useful for simplifying calculations and modeling thermal behavior in situations where the temperature changes are small and the thermal properties of the system are constant.

2. Transient Heat Flow in a Semi-infinite Solid with Constant Surface Temperature: This concept refers to the mathematical model used to describe the behavior of heat flow in a semi-infinite solid when the surface temperature is kept constant over time. This model is commonly used to analyze the cooling of hot objects in contact with a cool surface, such as the cooling of a metal plate.

3. Transient Heat Flow in a Semi-infinite Solid with Constant Heat Flux: This concept refers to the mathematical model used to describe the behavior of heat flow in a semi-infinite solid when a constant heat flux is applied to the surface. This model is commonly used to analyze the heating of materials in contact with a hot surface, such as the heating of food in a microwave oven.

4. Energy Pulse at Surface: This concept refers to a sudden, brief application of energy to a material at its surface, such as a laser pulse or a sudden impact. The behavior of the material in response to the energy pulse can be analyzed using mathematical models and simulations.

5. Transient Heat Flow in a Semi-infinite Solid with Convection Heat Transfer: This concept refers to the mathematical model used to describe the behavior of heat flow in a semi-infinite solid when heat is transferred to or from the surface of the solid due to convection, such as when a fluid is flowing over the surface of the solid. This model is commonly used to analyze the behavior of heat exchangers and other devices that involve convective heat transfer.

6. Multidimensional Systems: Multidimensional systems refer to systems that involve multiple dimensions, such as three-dimensional systems. Some examples of multidimensional systems include:

(i) Three-dimensional heat transfer: This involves the behavior of heat flow in three-dimensional objects, such as the cooling of a complex-shaped object.

(ii) Three-dimensional fluid flow: This involves the behavior of fluids in three-dimensional objects, such as the flow of air through a complex-shaped duct.

(iii) Three-dimensional stress analysis: This involves the analysis of the stresses and strains in three-dimensional objects, such as the analysis of the structural behavior of a complex-shaped object under load.

One electron is lost and the ion shrinks when a cation is created from a representative element. The elements in the s-block and p-block of the periodic table are examples of representative elements.

The positive ions known as cations are created when one or more electrons are lost. The representative elements' cations that involve the complete loss of valence electrons are the ones that form the most frequently. Think about sodium, an alkali metal (Na). The third major energy level of it has one valence electron.

A negatively charged ion known as a cation results from an atom losing one or more electrons. acquiring one or more electrons

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