Gamma rays (-rays) are high-energy photons. In a certain nuclear reaction, a -ray of energy 0.769 MeV (million electronvolts) is produced. Compute the frequency of such a photon.
Hz

To calculate the net torque required, you can use the formula:

Net torque = I * α

Where I am the moment of inertia of the solid ball and α is the angular acceleration.

For a solid ball, the moment of inertia (I) is given by:

I = (2/5) * m * r^2
where m is the mass and r is the radius of the ball.

Now, plug in the given values:

I = (2/5) * 20 kg * (0.20 m)^2
I = 0.32 kg m^2
Next, multiply the moment of inertia (I) by the angular acceleration (α):

Net torque = 0.32 kg m^2 * 20 rad/s^2
Net torque = 6.4 N m

What is torque?

Torque is a measure of a force's ability to rotate an object around an axis or pivot point. When the force is perpendicular to the object's axis of rotation, it is most effective. Torque is a measure of an object's "rotational motion. "Torque is expressed in newton-meters (N-m) or pound-feet (lb-ft) in the metric system (ft-lb). In simple terms, torque is the product of force and the distance from the point of rotation to the point where the force is being applied. Formula to calculate net torque is equal to the product of the force and the lever arm, which is the distance between the pivot point and the point at which the force is applied. The net torque can be calculated using the following formula: Net Torque = Lever arm x Applied force Where Net torque is the resultant torque acting on an object. The lever arm is the distance from the pivot point to the force being applied. The applied force is the force applied. It can be any type of force, such as gravitational force, frictional force, or electrical force.
So, the net torque required is 6.4 N m.

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Answer:

Heat energy does not cool. Objects cool. Energy is not an object. Now, what happens when an object cools is that it gives off some of its thermal energy by one or more mechanisms: radiation, conduction, or convection. In radiation the energy escaped the object as electromagnetic waves - you see the red hot poker slowly dim as it cools, in conduction the energy is transferred Mechanically by the atoms of the hot object being in physical contact with those of the cool object and in convection the hot material moves to a cooler region where it gives up its heat energy by either radiation or conduction.

Answer:

Deposition

Explanation:

Answer:

It is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle is not constant

Explanation:

The motion of a particle under constant acceleration, 'a', is be given by the following kinematic equations;

v² = u² + 2·a·s

v = u + a·t

Where;

v = The final velocity of the particle

u = The initial velocity of the particle

a = The acceleration of the particle

s = The distance through which the particle travels

t = The time of motion of the particle

By simplifying the above equation, we have;

v² - u² = 2·a·s

(v² - u²)/(2·a) = s

(v - u) × (v + u)/(2 × a) = s

((v - u)/a) × ((v + u)/2) = s

From v = u + a·t, we have;

t = (v - u)/a

∴ ((v - u)/a) × ((v + u)/2) = t × ((v + u)/2) = s

∴ ((v + u)/2) = s/t

The average velocity = (Total distance traveled by the particle) ÷ (The time of travel of the particle)

∴ The average velocity = s/t = ((v + u)/2) = Half the sum of the initial and final velocity

However, it is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle, 'a', is not constant, as the velocity time graph is no longer a straight line graph and the distance traveled by the particle, 's', which is the area under the velocity time graph, 'A', (given by the sum of area of the triangle and the rectangle given by the area under straight line graph for constant velocity) cannot be given directly by the product of the time and the average velocity.

The stall speed of an airplane under a load factor of 2 if the unaccelerated stall speed is 100 knots is 140.(option.c)

The stall speed of an airplane under a load factor of 2 can be calculated by multiplying the unaccelerated stall speed by the square root of the load factor. In this case, the load factor is 2, so we can calculate the stall speed as follows:

Stall speed under load factor of 2 = 100 knots x √2

= 100 knots x 1.414

= 141.4 knots

Therefore, the closest option from the given choices is option C, which is 140 knots. This means that the airplane's stall speed will increase to 140 knots when subjected to a load factor of 2, which is important information for pilots to be aware of to ensure safe flying practices.

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When two pipes of different diameters are joined in series, the volumetric flow rate remains constant. To find the speed and the volumetric flow rate of the liquid in the two pipes, we use the continuity equation, which is: A1V1=A2V2, where A1 and A2 are the cross-sectional areas of the two pipes, and V1 and V2 are the speeds of the liquids.

The volumetric flow rate can be found using the formula Q=AV, where Q is the volumetric flow rate and V is the speed of the liquid. Assume the speed of the liquid in the smaller pipe is V1, and the speed of the liquid in the larger pipe is V2. Let us take the density of the oil to be 800kg/m³.The cross-sectional area of the smaller pipe is: A1=π(0.1/2)²=0.007854m²

The cross-sectional area of the larger pipe is: A2=π(0.2/2)²=0.031416m²

Using the continuity equation:A1V1=A2V2V2=A1V1/A2V2=0.007854V1/0.031416=0.198V1

The volumetric flow rate is the same in both pipes:Q=AV=0.007854V1=0.031416V2

We can substitute V2 with the expression we derived earlier:

V2=0.198V1Q=0.007854V1=0.031416(0.198V1)Q=0.00493m³/s

The speed of the liquid in the smaller pipe is:

V1=Q/A1=0.00493/0.007854=0.627m/s

The speed of the liquid in the larger pipe is:

V2=Q/A2=0.00493/0.031416=0.157m/s

Therefore, the speed of the liquid in the smaller pipe is 0.627m/s, and the speed of the liquid in the larger pipe is 0.157m/s. The volumetric flow rate of the liquid is 0.00493m³/s. The total length of the two pipes is 14m + 13m = 27m,

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Answer:

Power = 130 watt

Explanation:

Power is described as the ability to do work, it is also defined as the amount of work in Joules done in a given time in seconds. Mathematically, it is represented as:

\(power = \frac{work (J)}{Time (s)}\)

In this example, power is calculated as follows:

Work = 39000 J

Time = 5 minutes

converting the time from minutes to seconds:

1 minute = 60 seconds

∴ 5 minutes = 60 × 5 = 300 seconds

\(\therefore power = \frac{39000}{300} \\power = 130 watt\)

N:B the unit for power can also be represented as Joules/seconds or J/s or JS⁻¹

The work done by the spring is -(mg)2/(2ks). Therefore, the correct option is A.

The work done by the spring, Ws, is determined by the force of the spring and the displacement of the block. The spring has a stiffness constant, ks, so the force exerted by the spring is ks multiplied by the displacement, s.

The block has a mass, m, and is in the presence of acceleration due to gravity, g. The work done by the spring is therefore

Ws = -(1/2) x ks x s² = -(1/2) x ks x (mg/ks)² = -(mg)²/(2ks).

Therefore, the answer is A: -(mg)2/(2ks)

The work done by the spring can be expressed in terms of the force of the spring and the displacement of the block. The force of the spring is proportional to the stiffness constant, ks, and the displacement of the block is dependent on the mass, m, and acceleration due to gravity, g.

The work done by the spring is equal to the negative of one-half of the stiffness constant multiplied by the displacement squared. Therefore, the answer is -(mg)2/(2ks).

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Mercury's higher eccentricity means it has a more elongated and non-circular orbit compared to Venus.

The eccentricity of a planet's orbit refers to how elliptical or circular its orbit is. A higher eccentricity indicates a more elongated and elliptical orbit, while a lower eccentricity signifies a more circular orbit.

In the case of Mercury, having the highest eccentricity among the planets in the solar system means that its orbit is significantly more elongated and less circular compared to the other planets.

Mercury's eccentricity is approximately 0.21, which means its orbit deviates more from a perfect circle compared to Venus. Venus, on the other hand, has a relatively low eccentricity of around 0.0067, indicating a nearly circular orbit. This makes Venus' orbit much closer to being circular compared to Mercury.

The high eccentricity of Mercury's orbit leads to significant variations in its distance from the Sun throughout its orbit. At its closest approach to the Sun (perihelion), Mercury is about 46 million kilometers away, while at its farthest point (aphelion), it is approximately 70 million kilometers away. In contrast, Venus has a more stable distance from the Sun throughout its orbit due to its lower eccentricity.

In summary, Mercury's higher eccentricity means it has a more elongated and non-circular orbit compared to Venus, resulting in greater variations in its distance from the Sun during its revolution.

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You should allow more space in front of your vehicle when following large trucks because: A. You need the extra room to see around the truck.

A traffic rule is an accepted and enforceable law or guideline established by a road safety agency, so as to give warnings and instructions to road users such as the following:

In accordance with national traffic rules and regulations, it is very important and essential for the drivers of small vehicles to allow more space in front of them when they are behind large trucks in order to give extra room to see around the truck.

In conclusion, it is very important for a driver to ensure that his or her blind spot is clear at all times.

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Gravitational potential energy of the wheelbarrow:

ΔPE = (m * g * h_final) - (m * g * h_initial)

    = [(250 N / 9.8 m/\(s^2\)) * 9.8 m/\(s^2\)* (h_final - h_initial)]

To find the change in gravitational potential energy of the wheelbarrow, we need to calculate the initial and final heights of the wheelbarrow and use the formula for gravitational potential energy.

The gravitational potential energy (PE) is given by the equation:

PE = m * g * h

Where m is the mass of the object, g is the acceleration due to gravity, and h is the height.

First, we need to calculate the initial height of the wheelbarrow. Since the wheelbarrow is on the ramp, we can consider the vertical component of the ramp as the initial height. The vertical height (h_initial) can be calculated using trigonometry:

h_initial = length of the ramp * sin(angle)

h_initial = 6.0 m * sin(20°)

Next, we need to calculate the final height of the wheelbarrow. Since the wheelbarrow is being pushed up the ramp, the final height (h_final) is the same as the initial height:

h_final = h_initial

Now we can calculate the change in gravitational potential energy:

ΔPE = PE_final - PE_initial

    = (m * g * h_final) - (m * g * h_initial)

    = m * g * (h_final - h_initial)

Given that the weight of the wheelbarrow is 250 N, we can convert it to mass using the equation:

Weight = mass * g

250 N = m * 9.8  m/\(s^2\)

Solving for m, we find:

m = 250 N / 9.8 m/\(s^2\)

Now we can substitute the values into the equation for the change in gravitational potential energy:

ΔPE = (m * g * h_final) - (m * g * h_initial)

    = [(250 N / 9.8 m/\(s^2\)) * 9.8 m/\(s^2\)* (h_final - h_initial)]

Simplifying the equation, we find the change in gravitational potential energy of the wheelbarrow.

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It would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

To calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet, we need to use the formula: time = distance / speed.

Given that the jet in NGC 5128 is traveling at 5000 km/s and is 40 kpc (kiloparsecs) long, we first need to convert the distance from kpc to km. 1 kpc = 3.086 × 10^16 meters, which means 1 kpc = 3.086 × 10^19 km.

Therefore, the length of the jet in kilometers is 40 x 3.086 × 10^19 km = 1.2344 × 10^21 km.

Now we can calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet as follows:

time = distance / speed
time = 1.2344 × 10^21 km / 5000 km/s
time = 2.4688 × 10^17 seconds

So, it would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

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Answer:

Kriss go Brrrrrrrrrrr

Explanation:

Answer:

The radius is  \(r = 0.0170 \ m\)  

Explanation:

From the question we are told that

      The speed at which the race car moves is \(v = 0.512 \ m/s\)

       The centripetal acceleration is  \(a _r = 15.4 \ m/s\)

Generally the centripetal acceleration is mathematically represented as

           \(a_r = \frac{v^2 }{r}\)

=>        \(15.4 = \frac{0.512^2 }{ r}\)

=>       \(r = 0.0170 \ m\)  

Young's modulus is defined as the ratio of the tensile or compressive stress to the longitudinal strain of a body.  Young's modulus of the wire is 1.5 x 10¹¹ N/m².

The symbol for Young's modulus is Y or E, and its unit is N/m² or Pascal (Pa). The formula to calculate Young's modulus is given by:E = (F/A) / (ΔL/L)whereF is the tensile or compressive force appliedA is the cross-sectional area of the wireΔL is the extension or compression of the wireL is the original length of the wireFrom the given question, we have:F = 20 NA = 8 x 10⁻⁷ m²ΔL = 10⁻⁴ mL = 3mSubstituting the given values in the formula of Young's modulus:E = (F/A) / (ΔL/L)E = (20 N / 8 x 10⁻⁷ m²) / (10⁻⁴ m / 3 m)E = (20 N / 8 x 10⁻⁷ m²) x (3 m / 10⁻⁴ m)E = 1.5 x 10¹¹ N/m²Therefore, the Young's modulus of the wire is 1.5 x 10¹¹ N/m².

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The spring constant (k) can be calculated using the formula:

k = F/x

where F is the applied force and x is the resulting displacement.

Plugging in the given values, we get:

k = 4 N / 0.05 m

k = 80 N/m

Therefore, the spring constant of the spring is 80 N/m.

When you compress or extend a spring – or any elastic material – you’ll instinctively know what’s going to happen when you release the force you’re applying: The spring or material will return to its original length. It’s as if there is a “restoring” force in the spring that ensures it returns to its natural, uncompressed and un-extended state after you release the stress you’re applying to the material. This intuitive understanding – that an elastic material returns to its equilibrium position after any applied force is removed – is quantified much more precisely by ​Hooke’s law​.

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Given:

The angle of incidence is,

The refractive index of the crown glass for red light is,

The refractive index of the crown glass for blue light is,

To find:

The angle separating rays of the two colours in a piece of crown glass

Explanation:

We know, Snell's law,

For, the red light,

For, the blue light,

The separation between the refracted rays is,

Hence, the required separation is 0.1 degrees.

The steel string is stretched by 0.06 mm.

We can use Hooke's Law to find the amount of stretch in the steel string:

F = kΔL

where F is the tension force, k is the spring constant (related to the Young's modulus), and ΔL is the amount of stretch.

Rearranging the equation, we get:

ΔL = F / k

The spring constant k can be expressed as:

k = A * E / L

where A is the cross-sectional area of the string, E is Young's modulus, and L is the original length of the string.

Substituting the given values, we get:

A = \(πr^2 = π(0.5 mm)^2 = 0.785 mm^2\)

k = (π/4) * (1.0 mm)^2 * (20 × \(10^10 N/m^2\)) / (1.8 m) = 5.50 × \(10^4 N/m\)

Now we can find the amount of stretch:

ΔL = (3.3 × \(10^3 N)\)/ (5.50 × \(10^4 N/m\)) = 0.06 mm

Therefore, the steel string is stretched by 0.06 mm.

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The liquid's specific heat capacity is 4.2 kJ kg⁻¹ K⁻¹.

In a calorimeter, mc = 25 J K⁻¹.

The calorimeter contains m(l) = 140 g = 140 × 10⁻³ kg of liquid.

The energy is provided at a rate of Q = 40 W for a time of 4 minutes.

The liquid's temperature increases by ΔT = 15.8° C = 15.8° K.

Q = mcΔT

The equation tells you how much heat is given (Q or E), how much of that heat changes the material's temperature T, and how much of that heat is applied to a mass-m material with a specific heat capacity (c).

Now, the heat supplied will be:

Q = mcΔT + m(liquid) c(liquid)ΔT

Q = mcΔT + m(l) c(l)ΔT

c(l) = ( Q - mcΔT ) / m(l)ΔT

Now, the heat supplied is Q = 40 W = 40 J/s = 40 × 4 × 60s = 9600 J

c(l) = { ( 9600 - 25 × 15.8 ) / [ (140 × 10⁻³) × 15.8 ] }

c(l) = ( 9600 - 395 ) / [ 2212 × 10⁻³ ]

c(l) = 9205 / 2212 × 10⁻³

c(l) = 4.1614 × 10³ = 4.2 kJ kg⁻¹ K⁻¹

The specific heat capacity of the liquid is 4.2 kJ kg⁻¹ K⁻¹.

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Assuming the truck is moving in a straight line, the force of friction between the toolbox and the bed of the truck would be equal to the force required to accelerate the toolbox, which is approximately 0.25 N.

Acceleration is the rate at which the velocity of an object changes over time. It can be calculated as the change in velocity divided by the time interval over which the change occurs.

The force of friction is the force that opposes motion between two surfaces that are in contact with each other. It arises due to the interlocking of the rough surfaces and can be calculated using the coefficient of friction and the normal force.

To answer this question, we need to use Newton's second law, which states that the net force on an object is equal to its mass times its acceleration. In this case, the toolbox is not slipping, which means the force of friction between the toolbox and the bed of the truck is equal to the force pushing the toolbox forward.
The force pushing the toolbox forward is the product of its mass and acceleration, which is:
F = ma
F = (1.00 kg)(0.25 m/s²)
F = 0.25 N
Therefore, the force of friction between the toolbox and the bed of the truck is also 0.25 N, since the toolbox is not slipping.

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Answer:

1.Tackle

2.helmet

3.touchdown

4.quarterback

5.interference

6.touchback

7.safety

8.cornerback

9.handoff

10.lateral

11. reciever

12.completion

13.interception

14.center

15.referee

16.huddle

17.overtime

18. facemask

19.pigskin

20.penalty

Explanation:

The correct words are "Tackle, Theme, Touchdown, Quarterback, Interference, Touchdown, Safety, Cornerback, Offhand, Aerial, Receiver, Completion, Receptionist, Center, Referee Huddle, Overtime, Safesmack, Kicking, and  Penalty."

A football word scramble is a game where a series of letters are provided in a scrambled order, and the goal is to rearrange those letters to form words related to football. Players need to unscramble the letters to identify the correct football-related terms, such as positions, equipment, or actions in the game. It is a fun and engaging activity that challenges players' knowledge and word-solving skills while connecting to the theme of football.

1. Tackle

2. Theme

3. Touchdown

4. Quarterback

5. Interference

6. Touchdown

7. Safety

8. Cornerback

9. Offhand

10. Aerial

11. Receiver

12. Completion

13. Receptionist

14. Center

15. Referee

16. Huddle

17. Overtime

18. Safesmack

19. Kicking

20. Penalty

Therefore, The correct answers are "Tackle, Theme, Touchdown, Quarterback, Interference, Touchdown, Safety, Cornerback, Offhand, Aerial, Receiver, Completion, Receptionist, Center, Referee, Huddle, Overtime, Safesmack, Kicking, and  Penalty."

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Asteroids appear as "dots" to Earth-based telescopes due to their small size and significant distance from Earth, resulting in limited angular resolution and light spread.

Asteroids appear like "dots" when observed through Earth-based telescopes due to their small size and distance from Earth.

1. Small size: Asteroids are relatively small celestial bodies compared to planets or stars. Most asteroids range in size from a few meters to hundreds of kilometers in diameter. Their compact size makes them appear as mere points of light when viewed from Earth.

2. Distance: Asteroids are typically located at significant distances from Earth. Even the nearest asteroids are millions of kilometers away. Due to their distance, the light reflecting off asteroids becomes significantly spread out by the time it reaches Earth, resulting in a small and concentrated point of light.

3. Angular resolution: Earth-based telescopes have a limited angular resolution, which determines the smallest details they can resolve. Since asteroids appear as relatively tiny objects in the sky, the limited angular resolution of telescopes causes them to appear as dots without revealing much surface detail.

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Answer:

0.71s

Explanation:

From Newton's law of motion ;

V =U +gt

V is the final velocity or speed

U is the initial velocity or speed

g is acceleration of free fall due to gravity given as 9.8m/S2

Note when a body moves horizontally down its said to do so with the aid of the force of gravity

Hence the final velocity is aided by gravity.

From the above formula;

t =V-U/ g

t= 12-5/ 9.8 = 0.71s

Answer: .71

Explanation:

Khan academy

If resultant force on the body is 0 the acceleration will also be 0.​

The term "acceleration" refers to the change in velocity with time. We must also recall that force is the product of mass and acceleration. If that is so, we can write; F = ma.

Now, we are told that the force on the body is zero so making the acceleration the subject of the formula; a = 0/mand a = 0.

Hence,  if resultant force on the body is 0 the acceleration will also be 0.​

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Answer:

There cannot be a force without motion and if there is no motion, then there is no force acting.

Explanation:

A force is a vector that causes an object with mass to accelerate.

Answer:

because force need motion

Explanation:

The force needed to stretch the steel wire by 1% is 25,140 N.

The given parameters include;

The area of the steel wire is calculated as follows;

\(A = \pi r^2\\\\ A= 3.142 \times (0.002)^2\\\\ A= 1.257 \times 10^{-5} \ m^2\)

The force needed to stretch the wire is calculated from Youngs modulus of elasticity given as;

\(E = \frac{stress}{strain} = \frac{F/A}{e/L} = \frac{FL}{Ae} \\\\F = \frac{EAe}{L}\)

\(F = \frac{200 \times 10^9\ \times\ 1.257\times 10^{-5}\ \times \ 0.01l_1}{l_1} \\\\F = 25,140\ N\)

Thus, the force needed to stretch the steel wire by 1% is 25,140 N.

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Answer:

yes

Explanation:

Arcology is the fusion of architecture with ecology, a comprehensive urban perspective. In nature, as organisms evolve, they increase in complexity and become a more compact system. A city should similarly evolve, functioning as a living system.

Arcology's major goal is to stop urban sprawl, which can be accomplished by building self-sufficient, remote settlements and structures that are (ideally, gigantic).

While it is theoretically conceivable to construct an arcology, at least structurally, it would take creative engineering to ensure the essential energy generation, food production, and waste reclamation systems are sustainable.

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Answer:

The concept of arcology that appealed to me the most is the fusion of architecture with ecology. If I were to incorporate an arcology concept into my community design, I would focus on creating a pedestrian environment where pedestrians move efficiently and freely.

Explanation:

Answer:

iyuksouijz

Explanation:

ok,kcipxuoa