G
Mr. Chang's class has 28 students, 7 of whom are girls. Which equation shows how to determine the number of girls in
Mr. Chang's class?
o 28-4-49
0 28 x 7 - 16
017-28 - 11
o 1-28-

The two column proof of the given angles are as detailed below with all statements and reasons.

From the given diagram, we are shown that;

Statement 1; a II b

Reason 1; Given

Statement 2; ∠1 ≅ ∠2

Reason2 ; Given

Now, from the transversal line theorem, we know that If two parallel lines are cut by a transversal, then the alternate exterior angles are congruent. Similarly, If two parallel lines are cut by a transversal, then corresponding angles are congruent. Two lines cut by a transversal are parallel IF AND ONLY IF corresponding angles are congruent.

Thus;

Statement 3; ∠1 = ∠4

Reason 3; Transversal Line theorem

Statement 4; ∠2 = ∠3

Reason 4; Alternate angles

Statement 5; ∠3 ≅ ∠4

Reason 5; Substitution Property

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To determine whether the engineer's claim that the method is unbiased is false, we need to perform a hypothesis test.

The null hypothesis, denoted as H0, assumes that the method is unbiased, meaning that the mean error is zero. The alternative hypothesis, denoted as Ha, assumes that the method is biased, and the mean error is not zero.

Given a sample of 18 measurements with a mean error of 457.7 kNm and a standard deviation of 317.7 kNm, we can calculate the test statistic using a t-test. The test statistic is calculated by dividing the sample mean by the standard deviation divided by the square root of the sample size.

If the calculated test statistic falls within the rejection region defined by a chosen significance level, typically denoted as α, we can reject the null hypothesis and conclude that the engineer's claim of unbiasedness is false. The significance level determines the probability of making a Type I error, which is the probability of rejecting a true null hypothesis.

To make a definitive conclusion, we would compare the calculated test statistic to the critical value(s) from the t-distribution table or use statistical software to calculate the p-value associated with the test statistic. If the p-value is less than the significance level, we reject the null hypothesis and conclude that the claim of unbiasedness is false. Conversely, if the p-value is greater than the significance level, we fail to reject the null hypothesis and cannot conclude that the claim is false.

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(a) In matrix notation, the given functions can be expressed as:

1. W1 = ZMY

2. W2 = M2Y

(b) The expectation of the random vector W is:

E[W] = ZM1μ for W1, and

E[W] = M2μ for W2.

(c) The covariance matrix of W is:

Cov(W) = ZM1CM1T ZT + M2CM2T.

(a) In matrix notation, the given functions can be expressed as follows:

1. W1 = Z(y1 + y2 + y3 + y4)

2. W2 = (y1 + y2) - (y3 + y4)

To represent these equations in matrix form, we can define the following matrices and vectors:

Y = [y1, y2, y3, y4]T, where T denotes the transpose operation.

M1 = [0, 0, 0, 1]

M2 = [1, 1, -1, -1]

Then, we can rewrite the functions as:

1. W1 = ZMY

2. W2 = M2Y

(b) To find the expectation of the random vector W, we need to calculate E[W] using the linearity of expectations. Since Z is a constant, we have:

E[W1] = ZE[MY] = ZM1E[Y] = ZM1μ,

E[W2] = E[M2Y] = M2E[Y] = M2μ,

where μ is the mean vector of Y.

(c) To find the covariance matrix of W, we need to calculate Cov(W) using the property Cov(X) = E[(X - E[X])(X - E[X])T]. Thus, we have:

Cov(W1) = ZM1Cov(Y)M1T ZT,

Cov(W2) = M2Cov(Y)M2T.

To compute Cov(Y), we require the covariance matrix of Y, denoted as C. Therefore, we have:

Cov(W) = ZM1CM1T ZT + M2CM2T.

This represents the covariance matrix of the random vector W.

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Answer:

A.) 93

B.) 77

C.) 369

Step-by-step explanation:

Answer:

Its the same one that I answered lol

Step-by-step explanation:

Answer:

C:no the first expression is equal to 1/25 and the second expression is equal to 625

Step-by-step explanation:

if you do  in the calculator it will give you 0.04(wich is ecual to 1/25)

and the second one is 5^3 (which is 125) *5 = 625

Answer:

(x = 0,y = 0),(x = 1, y = 5),(x= 2, y =10)

Step-by-step explanation:

the rule is to multiply x by 5.

when x = 0, y =5(0) = 0

when x = 1, y =5(1) = 5

when x = 2, y =5(2) = 10

Hope this helps!

Please mark as brainliest!

0

5

10

A table can be completed by plugging x-values into an equation or by graphing.

Plug in x-values

First, plug 0 into the equation to find the first y-value.

Next, plug in 1 for x

Finally, plug in 2

Additionally, each of these y-values increases by 5. So, once we found the first y-value, 0, we can just add 5 to find the next y-values.

Graphing

Also, you can use a graph to find the missing values. The y-intercept is 0 and the slope is 5. Using this information you can graph the equation. Then, find the x-values on the graph and match these values to y-values.

Answer:

Step-by-step explanation:

In a right triangle, the sine of an angle is equal to the length of the side opposite the angle divided by the length of the hypotenuse (the longest side of a right triangle, also called the hypotenuse). Therefore, to find the length of the side opposite angle θ, we can use the following formula:

opposite = sin(θ) * hypotenuse

In this case, we know that θ = 25 degrees and the adjacent side has a length of 3. Since we are dealing with a right triangle, we can use the Pythagorean theorem to find the hypotenuse:

hypotenuse = sqrt(adjacent^2 + opposite^2) = sqrt(3^2 + opposite^2) = sqrt(9 + opposite^2)

So we can substitute that value into the first equation:

opposite = sin(25) * sqrt(9 + opposite^2)

Solving for opposite, we get:

opposite = sin(25) * sqrt(9 + opposite^2)

opposite = 0.4226 * sqrt(9 + opposite^2)

We can calculate the value of sin(25) which is 0.4226.

opposite = 0.4226 * sqrt(9 + opposite^2)

opposite = 0.4226 * sqrt(opposite^2 + 9)

Square both sides of the equation to get:

opposite^2 = (0.4226 * sqrt(opposite^2 + 9))^2

opposite^2 = 0.1799 * opposite^2 + 1.5874

Subtracting 0.1799 * opposite^2 from both sides of the equation gives:

0 = 1.5874

Solving for the opposite, we get:

opposite = sqrt(1.5874)

opposite = 1.259

So the side opposite to the angle of 25 degrees is 1.259 units long, rounding to at least 3 decimal places.

Answer:

.

Step-by-step explanation:

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\(y = \stackrel{\stackrel{m}{\downarrow }}{3} x + 3\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill\)

\(\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{3\implies\cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}\)

so we're really looking for the equation of a line whose slope is -1/3 and that is passes through (3 , 2)

\((\stackrel{x_1}{3}~,~\stackrel{y_1}{2})\hspace{10em} \stackrel{slope}{m} ~=~ - \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{- \cfrac{1}{3}}(x-\stackrel{x_1}{3}) \\\\\\ y-2=- \cfrac{1}{3}x+1\implies {\Large \begin{array}{llll} y=- \cfrac{1}{3}x+3 \end{array}}\)

Answer:

1a. four minus n, four subtracted by n

1b. t over 5, t divided by five

1c. nine plus q, the sum of nine plus q

1d. three times h, h times three

Answer:

1a. four minus n, n minus four

1b. t divided five, a number t is divided by five

1c. nine plus q, q plus nine

1d. three times h, three times a number h

Step-by-step explanation:

hope this helps have a safe and happy holiday

To write the following mathematical equation in the required format for programming\(\[a{x^2}+bx+c=2\]\)

let us begin by reviewing the standard format of the quadratic formula:\(\[ax^{2}+bx+c=0.\]\)

Therefore, to write the given quadratic equation into the required format for programming we should subtract 2 from both sides so that the quadratic equation is in the standard format.\(\[ a x^{2}+b x+c-2=0 \]\)

Therefore, the required format for programming is \(\[ a x^{2}+b x+c-2=0 \].\)

To write the mathematical equation \(\[ a x^{2}+b x+c=2 \]\) in the required format for programming, you would typically use a specific programming language syntax. Here's an example using Python:

```python

a = 1

b = 2

c = -3

x = # provide a value for x

result = a * x**2 + b * x + c - 2

```

In this example, the coefficients `a`, `b`, and `c` are assigned specific values. You would need to assign appropriate values based on your equation. Then, you can provide a value for the variable `x`. Finally, the equation is evaluated and the result is stored in the variable `result`.

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Answer:

No

Step-by-step explanation:

because c equals 17

hope this helps

Answer:

No

Step-by-step explanation:

We could solve for c and see what the value of c should be to satisfy this equation.

However, in this case we are given a value for c already i.e. c=25 and all we need to do is plug it into the equation and see if it is consistent i.e. if the value on the LHS equals the value of RHS for that specific value of c

Using the value of c = 25 and plugging it into the LHS of the equation we have \(\frac{1}{2} (25-13) =\frac{12}{2} = 6\)

Doing the same with the RHS gives us 19-25 = -6

6 ≠ -6 (6 not equal to -6)

So Lance's solution of c = 25 is incorrect

If you actually wanted to solve for the correct value of c, proceed as follows
Multiply by 2 on both sides of the equation
\(\frac{1}{2} (c-13) = 19 -2c\\\\\\text{This gives us } \\c-13 = 38-2c\\\)

Adding 2c to both sides and adding 13 to both sides  (or, in other words moving -2c to the LHS and -13 to the RHS) gives us

c- (-2c) = 38 - (-13)

3c = 51

c = 17

Check this is correct by plugging it into the original equation and seeing that the LHS = RHS = 2

The schedule is as follows:

T1 -> T2 -> T1 -> T3 -> T1 -> T2 -> T1.

To construct a schedule using the Earliest Deadline First (EDF) scheduling algorithm, we need to consider the execution time, period, and deadline of each task and assign them priorities based on their deadlines. The task with the earliest deadline will be scheduled first. Let's create a schedule for the given task set:

Task T1: Execution time (e) = 2 ns, Period (P) = 5 ns, Deadline (D) = 5 ns

Task T2: Execution time (e) = 4 ns, Period (P) = 7 ns, Deadline (D) = 7 ns

Task T3: Execution time (e) = 7 ns, Period (P) = 7 ns, Deadline (D) = 7 ns

We have a period of 22 ns, and we need to schedule these tasks within that period. Let's start with the task with the earliest deadline:

At time 0 ns: Execute T1 (2 ns)

At time 2 ns: Execute T2 (4 ns)

At time 6 ns: Execute T1 (2 ns)

At time 8 ns: Execute T3 (7 ns)

At time 15 ns: Execute T1 (2 ns)

At time 17 ns: Execute T2 (4 ns)

At time 21 ns: Execute T1 (2 ns)

This completes the execution of all tasks within the given period of 22 ns. The schedule is as follows:

T1 -> T2 -> T1 -> T3 -> T1 -> T2 -> T1

In this schedule, we have followed the EDF algorithm by selecting tasks based on their deadlines. The task with the earliest deadline is always scheduled first to meet the timing requirements of the system.

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Answer:

I have solved it u can have a look.

The angle that a side of 15 inches makes with the 6-inch side is approximately 78.46 degrees.

c²= a² + b² - 2ab cos(C)

In this case, we know that the lengths of the two congruent sides are both 15 inches, and the length of the remaining side is 6 inches. So we have:

15² = 6² + 15² - 2(6)(15)cos(x)

225 = 261 - 180cos(x)

180cos(x) = 36

cos(x) =\(\frac{36}{180}\)

cos(x) = 0.2

Now we can use the inverse cosine function (\(cos^{-1}\)) to find the value of "x" in degrees:

x = \(cos^{-1}\)(0.2)

x ≈ 78.46 degrees

An angle is a geometric figure formed by two rays with a common endpoint, called the vertex. The rays are known as the sides of the angle. The measure of an angle is usually expressed in degrees, and it represents the amount of rotation needed to rotate one of the sides of the angle onto the other. A full rotation around a point is 360 degrees, so an angle measuring 180 degrees is called a straight angle.

Angles can be classified according to their measure. An acute angle is an angle measuring less than 90 degrees. A right angle is an angle measuring exactly 90 degrees. An obtuse angle measures more than 90 degrees but less than 180 degrees. A reflex angle measures more than 180 degrees but less than 360 degrees.

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Hello,

I hope you and your family are doing well!

A polynomial of degree 4 with real coefficients that has the zeros 2, -1, and -3+i is given by:

\(f(x) = (x - 2)(x + 1)(x - (-3+i))(x - (-3-i))\)

\(= (x - 2)(x + 1)(x + 3 + i)(x + 3 - i)\)

\(= (x - 2)(x + 1)(x + 3 + i)(x + 3 - i)\)

\(= (x^2 - x - 6)(x^2 + x - 6)\)

\(= x^4 - 3x^2 + 36\)

This polynomial has degree 4 and real coefficients, and it has the zeros 2, -1, -3+i.

----

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Answer:

36.5feet

Step-by-step explanation:

tan47º=h/34

h=36.4605=36.5feet

The tree is at height 36.5 feet if the point on the ground is 34 feet from the tree.

The angle of elevation to a nearby tree from a point on the ground is measured to be 47º

The angle of elevation is when you are measuring the angle from the floor or the ground.

\(tan47^0=h/34\)

\(34 tan47^0=h\)

h=36.4605

h=36.5 feet

Therefore the tree is at height 36.5 feet if the point on the ground is 34 feet from the tree.

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The probability that a high school junior will take less than 135 minutes to complete the SAT exam is 0.5745.

To determine the probability, the standard normal distribution table or calculator is utilized.

The standard normal distribution table, also known as the z-score table, is used to find the probability of a certain z-score or a range of z-scores.

The SAT exam's time is normally distributed, with a mean of 150 minutes and a standard deviation of 25 minutes.The formula for z-score is as follows:

z=(x-μ)/σ

Where x is the time to complete the SAT exam, μ is the mean of the time to complete the SAT exam, and σ is the standard deviation of the time to complete the SAT exam.

To calculate the z-score, the time of 135 minutes is substituted for x, the mean μ of 150 minutes is substituted for μ, and the standard deviation σ of 25 minutes is substituted for σ.The computation is as follows:

z=(135-150)/25= -0.60

Using the standard normal distribution table, the probability of getting a z-score of -0.60 is 0.2743.

To obtain the probability that a high school junior will complete the SAT exam in less than 135 minutes, the area under the standard normal curve to the left of z = -0.60 must be computed. Because the normal curve is symmetrical, the region to the right of z = -0.60 is equal to 1 - 0.2743 = 0.7257.

Finally, to obtain the region to the left of z = -0.60, 0.7257 must be subtracted from 1:1 - 0.7257 = 0.2743

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Out of all the answer choices, d) 1.327 × 10-31 ng is the only one that matches the calculated value of the mass of a single bromine atom in nanograms. Therefore, d) is the correct answer.

To understand why, we need to convert the mass of a single bromine atom from grams to nanograms.

There are 10^9 nanograms in a single gram, so we can use this conversion factor to make the necessary calculation:
1.327 × 10-22 g x (10^9 ng/1 g) = 1.327 × 10-13 ng

However, none of the answer choices match this value. We need to use scientific notation to convert 1.327 × 10-13 ng into one of the given answer choices.
a) 1.327 × 10-16 mg = 1.327 × 10^-10 ng (since 1 mg = 10^6 ng)
b) 1.327 × 10-25 kg = 1.327 × 10^-4 ng (since 1 kg = 10^12 ng)
c) 1.327 × 10-28 μg = 1.327 × 10^-19 ng (since 1 μg = 10^3 ng)
d) 1.327 × 10-31 ng = 1.327 × 10-31 ng

Out of all the answer choices, d) 1.327 × 10-31 ng is the only one that matches the calculated value of the mass of a single bromine atom in nanograms. Therefore, d) is the correct answer.

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We can reduce the rate of refusals in telephone surveys by doing face to face surveys.

A phone study can keep going extremely lengthy, which brings about getting legitimate reactions and knowledge of the respondent's perspective which helps

social event a lot of information. Time limits are a disadvantage of telephone interview studies. Frequently, when you contact individuals at home, they are engaged with different exercises, like having supper or sitting in front of the TV. A few potential interviewees may be hesitant to partake in a meeting because of how much time they dread it will take. Examination can be assembled rapidly in light of the fact that telephone interviews are prompt and gifted questioners can finish a great deal of overviews in a day of work. A great many people have phones, so you have an adequate crowd for get-together a delegate test to finish the study.

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Answer:

no, janet could not have won 10 games because 3x is not equal to 24

Step-by-step explanation:

if janet won twice as many as nadia that means nadia times 2

so it would be 20 to add both nadia and janet it would be over 24 therefore the answer is d

hope this helps

Answer: No; Janet could not have won 10 games because 3x ≠ 24

Step-by-step explanation:

Janet and Nadia won 30 games together. 10x2(10)=30

! !

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Answer: The form of payment that Courtney can lose and not get back would be cash.

Step-by-step explanation:

The reason why cash couldn't be returned back because it doesn't have a piece of U.S money wouldn't have a specific certified owner that they can be returned to.

Other forms of payment like credit cards, debit cards, and checks have specific bank information with the card holder's name on it so if Courtney actually lost one of those, she would be most likely to receive it back without any complicated  verification process.

Therefore, Courtney would not be able to receive her cash back if she accidentally loses it. Hope this helps you with your Imagine Math homework or assignment!

-From Certified 5th Grade Honors Student

Answer:

x = 1

Step-by-step explanation:

Answer:

x=1

Step-by-step explanation:

Answer: 11

Step-by-step explanation:

The given function is,

Therefore, g(3) can be calculated by substituting 3 in the place of x. Therefore we have,

Thus the answer is 12.125.

Because b > 1, the correct response in this situation would be: "1.022 is the growth factor for the GDP since 1950, and the GDP increases by a factor of 1.022 every year."

In this instance, we're assuming that we can use the following function to simulate the US GDP, or gross domestic product, in dollars:

\(GDP = 11(1.0220)^{t}\)

We can also see that the exponential model formula given by: governs this formula.

\(GDP = 11(1.0220)^{t\)

Where a denotes the starting sum, b the model's growth/decay rate, and t is the number of years since 1950.

The value of b in this instance is provided by:

b = 1.022

And when we calculated r as the growth rate, we obtained:

1.022 = 1 + r

r = 1.022 - 1

r = 0.022

Because b > 1, the correct response in this situation would be: "1.022 is the growth factor for the GDP since 1950, and the GDP increases by a factor of 1.022 every year."

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Answer:

1846= 0% change

1847= 3.2/5 ×100 = 64% decrease in river

1848= 6.8/3.2 ×100 = 212.5% increase

( used 3.2 because that was the last record)

Given the transformations of the graph of f(x)=6x, the function rule g(x) is therefore g(x) = -1/2x.

A point, line, or geometric figure can be transformed in one of four ways, each of which affects the shape and/or location of the object. Pre-Image refers to the object's initial shape, and Image, after transformation, refers to the object's ultimate shape and location. Transformations can be divided into four categories: translation, rotation, reflection, and enlargement. You must be able to carry out each transformation and recognize which ones have already been done.

Given Data

f(x) = 6x

The resulting function will be f(x) = -6x if the function is not reflected over the x-axis.

The final function rule will be; if the resulting function is compressed by a factor of 1/12.

g(x) = 1/12(-6x)

g(x) = -1/2x

Given the transformations of the graph of f(x)=6x, the function rule g(x) is therefore g(x) = -1/2x.

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