The trigonometric ratios as a fraction in simplest form are
sin L = opposite side/hypotenuse = 30/34 = 15/17
cos L = adjacent side/hypotenuse = 16/34 = 8/17
tan L = opposite side/adjacent side = 30/16 = 15/8
sin M = opposite side/hypotenuse = 16/34 = 8/17
cos M = adjacent side/hypotenuse = 30/34 = 15/17
tan M = opposite side/adjacent side = 16/30 = 8/15
What is a right-angle triangle?
It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.
In the figure, find MK using hypotenuse theorem
hypotenuse² = sum of the squares of other two sides
=> 34² = 16² +MK²
=> MK² = 34² - 16²
=> MK² = 1156 - 256 = 900
=> MK =√900 = 30
sin L = opposite side/hypotenuse = 30/34 = 15/17
cos L = adjacent side/hypotenuse = 16/34 = 8/17
tan L = opposite side/adjacent side = 30/16 = 15/8
sin M = opposite side/hypotenuse = 16/34 = 8/17
cos M = adjacent side/hypotenuse = 30/34 = 15/17
tan M = opposite side/adjacent side = 16/30 = 8/15
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what is the solution to the system of equations graph below
\(\large\pink{\mid{\underline{\overline{\tt { →\: (-5,1)}\mid}}}}\)
Option ( A ) → (-5,1)Intersecting lines→ When two lines share exactly one common pointcuz here,the pôint where two lines meet is (-5,1) hence this is the solution of above graph.x = -5 , y = 1_______________☃️\(\sf{\:мѕнαcкεя\: ♪...}\)
A rain gutter is made from sheets of
aluminum that are 24 inches wide by
turning up the edges to form right
angles. Determine the depth of the
gutter that will maximize its cross-
sectional area and allow the greatest
amount of water to flow. What is the
maximum cross-sectional area?
Flat sheet 24 inches wide
1 Write a quadratic function for the Area in terms of x: A(x) =
2 The cross-sectional area is maximized when the depth of the gutter is
3 The maximum cross-sectional area is square inches.
1. The quadratic function for the Area in terms of x: A(x) = 24x.
2. The cross-sectional area is maximized when the depth of the gutter is 0.
3. The maximum cross-sectional area is square inches 0.
To determine the depth of the gutter that maximizes its cross-sectional area and allows the greatest amount of water to flow, we need to follow a step-by-step process.
1. Write a quadratic function for the area in terms of x:
The cross-sectional area of the gutter can be represented as a rectangle with a width of 24 inches and a depth of x. Therefore, the area, A(x), is given by A(x) = 24x.
2. The cross-sectional area is maximized when the depth of the gutter is:
To find the value of x that maximizes the area, we need to find the vertex of the quadratic function. The vertex of a quadratic function in form f(x) = ax² + bx + c is given by x = -b/(2a). In our case, a = 0 (since there is no x² term), b = 24, and c = 0. Thus, the depth of the gutter that maximizes the area is x = -24/(2 * 0) = 0.
3. The maximum cross-sectional area is square inches:
Substituting the value of x = 0 into the quadratic function A(x) = 24x, we get A(0) = 24 * 0 = 0. Therefore, the maximum cross-sectional area is 0 square inches.
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prove that (4/5)^-3 = 5^3/4^3, without using the exponent law (x/y)^a = x^a /y^a.
We need to prove that
\((\frac{4}{5})^{-3}=\frac{5^3}{4^3}^{}^{}\)this will be equivalent to prove that:
\(4^3\times(\frac{4}{5})^{-3}=5^3\)so let's start from the left side of the previous equality and try to obtain the right side:
\(undefined\)Help please!!! Missing assignments are due in a couple hours!!!
Answer: Option A is correct, which is 73
6.5 practice the measure of the exterior of a triangle is equal to the sum of the remote interior angles?
Answer:
Step-by-step explanation:
Yes, that is correct. The measure of the exterior angle of a triangle is equal to the sum of the two remote interior angles. In other words, if you extend one side of a triangle to form an exterior angle, then the measure of that exterior angle is equal to the sum of the measures of the two interior angles that are not adjacent to the exterior angle. This property is known as the Exterior Angle Theorem.
Mathematically, we can express this as:
Exterior angle = Sum of remote interior angles
Or, in symbols:
∠ABC = ∠A + ∠C
where ∠ABC is the exterior angle formed by extending side BC of triangle ABC, and ∠A and ∠C are the two remote interior angles.
Here are two more examples that illustrate the Exterior Angle Theorem:
Example 1:
Consider a triangle ABC with angles A, B, and C as shown below. If we extend side AC to form an exterior angle, then we can label the exterior angle as ∠DCE. The remote interior angles are ∠B and ∠A.
css
Copy code
C
/ \
/ \
/ \
/ \
/ \
/______\
A B
D
According to the Exterior Angle Theorem, we have:
∠DCE = ∠B + ∠A
Plz help I have a time limit
Answer:
Area 108cm2
Step-by-step explanation:
triangle =1/2 ×base× height
rectangle =length × width
then add the area of each shape
??
What is the asnwer plsssss
The arc length is 7/2 pi.
AB is a radius of the circle. The circumference of the circle is 119.56. Find the
length of AB, rounding to the nearest tenth.
B
A
Answer:
19.0285
Step-by-step explanation:
For this, we have to work backwards.
First, the equation for the circumference of a circle is:
\(2\pi r\)
We already know the circumference, so we can solve for r:
\(119.56=2\pi r\)
divide both sides by 2
\(59.78=\pi r\)
divide both sides by pi
\(19.0285...=r\)
So, depending on the answer choices, the answer is 19.0285 rounded to the according decimal place.
Hope this helps! :)
Given right triangle ABC with altitude CE. By the Right Triangle Altitude Theorem, which similarity statement is true?
△ABC ∼ △EBC
△ABC ∼ △AEC
△ABC ∼ △CBE
△ABC ∼ △BCE
(40 points)
Step-by-step explanation:
By the Right Triangle Altitude Theorem, the two triangles formed by the altitude of a right triangle are similar to the original triangle and to each other.
In this case, triangle ABC is the original right triangle and CE is the altitude. Therefore, the similarity statement that is true is:
△ABC ∼ △AEC
This is because triangles ABC and AEC are both right triangles that share the angle at C, and the altitude CE creates two pairs of congruent angles (the right angles and the angle at A and E) and a pair of proportional sides (CE and AE are corresponding altitudes).
So, we can write the similarity statement as:
△ABC ~ △AEC
Which of the following is a trinomial with a constant term O A. -x + y10 O B. x3 + 11x2 + x O C. x + 4y+ 7 O D.
Answer:
C. x + 4y+ 7Step-by-step explanation:
As,
In it there are three different terms x, 4y and 7 hence a trinomial, then there is a constant term 7.
Answer:
C. x + 4y+ 7
Step-by-step explanation:
Ape-x
round 8,437 to the nearest whole number
Answer:
the answer is 8,000.
Step-by-step explanation:
find the approximate area of the shaded region, given that the area of the sector is approximately 13.08 square units.
The area of the shaded region is 3915 units².
We have,
Area of the sector.
= 13.08 units²
Now,
To find the area of an isosceles triangle with side lengths 5, 5, and 4 units, we can use Heron's formula.
Area = √[s(s - a)(s - b)(s - c)]
where s is the semi-perimeter of the triangle, calculated as:
s = (a + b + c) / 2
In this case,
The side lengths are a = 5, b = 5, and c = 4. Let's calculate the area step by step:
Calculate the semi-perimeter:
s = (5 + 5 + 4) / 2 = 14 / 2 = 7 units
Use Heron's formula to find the area:
Area = √[7(7 - 5)(7 - 5)(7 - 4)]
= √[7(2)(2)(3)]
= √[84]
≈ 9.165 units (rounded to three decimal places)
Now,
Area of the shaded region.
= Area of the sector - Area of the isosceles triangle
= 13.08 - 9.165
= 3.915 units²
Thus,
The area of the shaded region is 3915 units².
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What is the area of this parallelogram?
A = 20 ft²
A=2123 ft²
A=3313 ft²
A=4123 ft²
Answer:
33.33 ft²
Step-by-step explanation:
→ Write down the formula for the area of a parallelogram
base × height
→ Substitute in numbers
\(8\frac{1}{3} *4\)
→ Simplify
33.33 ft²
Answer: A=33 1/3 ft²
Step-by-step explanation:
Which is worked out correctly ?
Answer:
choice 2) 1/5 x 3/15 = 3/75 = 1/25
Step-by-step explanation:
Select the correct answer.
Here's another plant stand. It has 2 rows, each holding 4 plants. Suppose this plant stand is turned upright.
Choose the number sentence that represents the plants on the upright plant stand.
8 × 1 = 8
4 × 2 = 8
2 × 2 = 4
4 × 4 = 16
The number sentence that gives the best representation of the plants on the upright stand is 8 × 1 = 8.
How to solve for the plant on the upright stand.Given that the plant is said to be upright, then the number of row would be seen as 1.
The rows of the plants are made up of 2 and the plants in them are said to be 4. Hence we would have 4 x 2 = 8
From here we would conclude that 8 × 1 = 8 is the plants on the upright stand.
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Find the slope of a line parallel
to 2y= 6x+8
The slope of a line parallel to 2y= 6x+8 is 3.
How to calculate or determine the slope of a line?In Mathematics and Geometry, the slope of any straight line can be determined by using the following mathematical equation;
Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)
Slope (m) = rise/run
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
In Mathematics and Geometry, parallel lines are two (2) lines that are always the same (equal) distance apart and never meet. Therefore, two (2) lines are parallel under the following conditions:
m₁ = m₂
By making y the subject of formula, we have:
2y = 6x + 8
y = 3x + 4
Therefore, the slope is 3.
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Can anyone help me find the correct angle for ZWP?
Answer:
56 degrees
Step-by-step explanation:
Here, I think you just accidentally put the value for the angle ZWX, which would be ZWP+PWX(56+56).
You actually already wrote it on the paper, so nothing wrong with your math here, just a thinking error :)
1. the number of enrolled female students to the total number
of students
Answer:
In fall 2019, female students made up 57 percent of total undergraduate enrollment (9.4 million students), and male students made up 43 percent (7.1 million students). Enrollment patterns for female and male students exhibited similar trends between 2009 and 2019.
Step-by-step explanation:
A plane flying with a constant speed of 360 km/h passes over a ground radar station at an altitude of 1 km and climbs at an angle of 30°. At what rate (in km/h) is the distance from the plane to the radar station increasing a minute later? (Round your answer to the nearest whole number.)
The rate (in km/h) at which the distance from the plane to the radar station is increasing a minute later is 0 km/h (rounded to the nearest whole number).
To solve this problem, we can use the concepts of trigonometry and related rates.
Let's denote the distance from the plane to the radar station as D(t), where t represents time. We want to find the rate at which D is changing with respect to time (dD/dt) one minute later.
Given:
The plane is flying with a constant speed of 360 km/h.
The plane passes over the radar station at an altitude of 1 km.
The plane is climbing at an angle of 30°.
We can visualize the situation as a right triangle, with the ground radar station at one vertex, the plane at another vertex, and the distance between them (D) as the hypotenuse. The altitude of the plane forms a vertical side, and the horizontal distance between the plane and the radar station forms the other side.
We can use the trigonometric relationship of sine to relate the altitude, angle, and hypotenuse:
sin(30°) = 1/D.
To find dD/dt, we can differentiate both sides of this equation with respect to time:
cos(30°) * d(30°)/dt = -1/D^2 * dD/dt.
Since the plane is flying with a constant speed, the rate of change of the angle (d(30°)/dt) is zero. Thus, the equation simplifies to:
cos(30°) * 0 = -1/D^2 * dD/dt.
We can substitute the known values:
cos(30°) = √3/2,
D = 1 km.
Therefore, we have:
√3/2 * 0 = -1/(1^2) * dD/dt.
Simplifying further:
0 = -1 * dD/dt.
This implies that the rate at which the distance from the plane to the radar station is changing is zero. In other words, the distance remains constant.
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A rectangular prism measures 3 ft by 6 ft by 5 ft. If the dimensions of the box were all quadrupled, how would the surface area of the box change?
1.The new surface area would be 16 times the original surface area.
2.The new surface area would be quadruple the original surface area.
3.The surface area would not change.
4.The new surface area would be 12 times the original surface area.
To determine how the surface area of a rectangular prism changes when all dimensions are quadrupled, we need to compare the original surface area to the new surface area.
The original surface area of the rectangular prism is given by:
SA_original = 2lw + 2lh + 2wh
where l, w, and h represent the length, width, and height of the prism, respectively.
In this case, the dimensions of the original box are:
Length (l) = 3 ft
Width (w) = 6 ft
Height (h) = 5 ft
Substituting these values into the formula, we have:
SA_original = 2(3)(6) + 2(3)(5) + 2(6)(5)
= 36 + 30 + 60
= 126 square feet
Now, if we quadruple all the dimensions of the box, the new dimensions would be:
Length (l_new) = 4(3) = 12 ft
Width (w_new) = 4(6) = 24 ft
Height (h_new) = 4(5) = 20 ft
The new surface area of the enlarged box is given by:
SA_new = 2(l_new)(w_new) + 2(l_new)(h_new) + 2(w_new)(h_new)
= 2(12)(24) + 2(12)(20) + 2(24)(20)
= 576 + 480 + 960
= 2016 square feet
Comparing the original surface area (SA_original = 126 sq ft) to the new surface area (SA_new = 2016 sq ft), we can see that SA_new is 16 times greater than SA_original.
Therefore, the correct answer is:
1. The new surface area would be 16 times the original surface area.
>Evaluate a² - 23.5 when a = 7.2.
The basic rate pay is K8.20. If the overtime is paid at time-and-a-quarter, what is the overtime rate of pay?
The overtime rate of pay is K10.25.
The overtime rate of pay can be calculated by multiplying the basic rate pay by the time-and-a-quarter factor. In this case, the basic rate pay is K8.20.
To determine the overtime rate of pay, we need to calculate one-quarter (1/4) of the basic rate pay, and then add that amount to the basic rate pay. One-quarter of K8.20 is calculated as (1/4) * K8.20 = K2.05.
By adding the calculated overtime amount to the basic rate pay, we get the overtime rate of pay: K8.20 + K2.05 = K10.25.
Therefore, the overtime rate of pay is K10.25.
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HELP Ross drives 402 miles in 6 hours. If Ross continues to drive at the same rate, how many miles can he drive in 12 hours? A. 804 B. 1,608 C. 335 D. 780
Answer:
804
Step-by-step explanation:
multiply 402 by 2
12÷2=6
6=402miles
402×2=804
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A tank full of water is leaking at a constant rate for 30 minutes. The equation
y=-9x+ 500
gives the amount of water in the tank, where yis the number of liters and x is
the number of minutes since the tank began to leak. Which statement is true?
Any one?
Answer: A. There were 500 liters in the tank when the leak started, and it is decreasing by 9 liters per minute.
Step-by-step explanation:
This equation is in the form; y =mx + c.
c in this equation is the value of y when x is at 0.
c in the above formula is 500 which means that the number of litres (y) at zero minutes(x) is 500 litres.
m is the rate of change as a result of a change in x.
m in this equation is -9 which means that the water is reducing by 9 litres every minute (x).
Each year caronline deposited a certain amount of money in an account which pays an annual interest rate of r so that at the end of each year, the balance in the account is multiplied by a growth factor of x=1+r. $600 is deposited at the start of the first year, and $200 at the start of the following year. Write an expression for a value of the account at the end of three years in terms of growth factors x. Find the value at the end of 3 years if the interest rate is 4%.
m.
x-intercept =
1/2
and y-intercept = 3
Write an equation for the line in point-slope form and in slope-intercept form
Answer:
slope intercept form: y= -6x+3
point slope form: y-0= -6(x -1/2)
Step-by-step explanation:
point slope form: y - y1 = m(x - x1)
substitute the values y-0=-6(x-1/2)
slope intercept form:
find the slope using two given points
m = (y2 - y1) / (x2 - x1)
= (3 - 0) / (0 - 1/2)
= 3 / (-1/2)
= -6
substitute into equation
y= -6x+3
Deena took six final exams and received these scores:
65, 72, 79, 86, 93, 100.
Answer:for the first exam she made a 65 for the second one she made a 72 for the third one she made a b for the forth one she made a 86 for the fifth one its b and replace it with a c for the last one she made a d
Step-by-step
How would you describe the translation from f(x)=x2 to f(x)=x2+5 ?
Answer:
5 units up
Step-by-step explanation:
Adding 5 to the y-value of an (x, y) coordinate moves it up 5 units.
f(x) = x^2 +5 is translated 5 units upward from f(x) = x^2.
If C is the incenter of ∆AMD, m∠A M C = 3 x + 6 and m∠ DMC= 8 x − 49.
find ∠ M A D , find m∠ADM and find m∠ADC
Answer:
3x+6=8x-49,
-6. -6
__________
3x=8x-55
-8x. -8x
________
-5x=-55
x=11,
3(11)+6=39
8(11)-49=39
Step-by-step explanation:
The machinery in a cereal plant fills 350 g boxes of cereal. The specifications for the machinery permit for a certain amount of fill tolerance. It is found that the weights of filled cereal boxes are normally distributed with a mean of 350 g and a standard deviation of 4 g. What is the probability that a box of cereal is under filled by 5 g or more?
There is approximately an 89.44% probability that a box of cereal is underfilled by 5 g or more.
To find the probability that a box of cereal is underfilled by 5 g or more, we need to calculate the probability of obtaining a weight measurement below 345 g.
First, we can standardize the problem by using the z-score formula:
z = (x - μ) / σ
Where:
x = the weight value we want to find the probability for (345 g in this case)
μ = the mean weight (350 g)
σ = the standard deviation (4 g)
Substituting the values into the formula:
z = (345 - 350) / 4 = -1.25
Next, we can find the probability associated with this z-score using a standard normal distribution table or a statistical calculator.
The probability of obtaining a z-score less than -1.25 is approximately 0.1056.
However, we are interested in the probability of underfilling by 5 g or more, which means we need to find the complement of this probability.
The probability of underfilling by 5 g or more is 1 - 0.1056 = 0.8944, or approximately 89.44%.
Therefore, there is approximately an 89.44% probability that a box of cereal is underfilled by 5 g or more.
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