Cycloalkanes (n=3, 4, 5):
Cyclopropane (C3H6)
Cyclobutane (C4H8)
Cyclopentane (C5H10)
Alkenes (n=3, 4, 5):
Propene (C3H6)
Butene (C4H8)
Pentene (C5H10)
What is a cycloalkane?Cycloalkanes are a type of organic compounds that contain a closed ring of carbon atoms. The carbon atoms in the ring are bonded to each other with single covalent bonds. Cycloalkanes are saturated hydrocarbons because they have the maximum number of hydrogen atoms that can be bonded to each carbon atom. The simplest cycloalkane is cyclopropane, which has three carbon atoms in the ring. Other examples include cyclobutane, cyclopentane, cyclohexane, and so on.
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1 points
A bottle contains a mixture of two gases: Oxygen and Hellum. The partial pressure of O2 is 1.0 atm and the partial pressure of He is 100.0 mmHg. What is the total pressure in the tank? (Volume and temperature are
constant)
101 alm
011 atm
O 101 mmHg
O 1.1 mmHg
101 mmHg is the total pressure in the tank.
Thus, Dalton's Law of Partial Pressures states that while the volume and temperature of a gaseous mixture are held constant, the total pressure of the mixture is equal to the sum of the partial pressures of its gaseous components.
Nitrogen, oxygen, argon, carbon dioxide, water vapor, and a trace amount of other gases are all present in atmospheric air and pressure.
The increased oxygen content in the chamber can displace the CO bound to hemoglobin faster than air oxygen, hence the hyperbaric chambers are also used to treat carbon monoxide (CO) poisoning. The treatment of scuba divers with the bends is another application for hyperbaric chambers.
Thus, 101 mmHg is the total pressure in the tank.
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PLEASE HELP!!!
How many calories are in 4,180 joules?
Answer:
To convert joules to calories, you can use the conversion factor:
1 calorie = 4.184 joules
To find out how many calories are in 4,180 joules, divide the given value by the conversion factor:
4,180 joules / 4.184 joules per calorie = 0.9 calories (approximately)
Therefore, there are approximately 0.9 calories in 4,180 joules.
How many Hg atoms are in 1.2mol Hg?
Plz tell me how you got it
Answer:
12
Explanation:
12
How many moles of Al2(SO4)3 would have been produced if 2.44 moles of KBr were produced according to the balanced chemical reaction below. 2AlBr + 3K2SO4 --> 6KBr + Al(SO4)3
According to the chemical equation, when 6 mol of KBr are produced 1 mol of Al(SO3) is produced aswel. This means we have to divide the number of mols of KBr produced (2.44) by 6, and then multiply the result for 1. This gives 0.4067 moles
What state of matter is hydrogen?
Answer:
its a gas
Explanation:
Hydrogen is the chemical element in the periodic table that has the symbol H and atomic number 1. At standard temperature and pressure it is a colorless, odorless, non-metallic, univalent, highly flammable diatomic gas. Hydrogen is the lightest and most abundant element in the universe.
In the given question, the state of matter of Hydrogen is gas in nature.
A state of matter is one of the four distinct forms in which matter can exist as solid, liquid, gas, and plasma.
Hydrogen is a chemical element that occurs naturally as a gas at standard temperature and pressure (STP). It is the lightest and most abundant element in the universe and is found in stars, gas giants, and other celestial bodies.
It is also used in various industrial processes, such as the production of ammonia and methanol, and as a fuel source in fuel cells.
Therefore, hydrogen is in the gaseous state at room temperature and normal atmospheric pressure.
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Number of atoms in 4.26 moles of (NH4)3PO4
Answer:
20 atoms
Explanation:
n=3
H =12
p=1
O=4
3+12+1+4=20
Unit 1 Exam
The mass of a glass of water is 45g and the volume is 45mL. What is the density of water?
O 1g/mL
O 5g/mL
2025 g/mL
Answer:
1g/mL is the correct answer
please help I need this finished asap. Please put answers down below.
Image 1
1) There is more proton repulsion in Uranium than in Barium
2) Barium experiences a stronger force holding the nucleons together
3) The repulsion of the neutrons in Uranium makes the nuclide unstable
4) The higher the atomic number, the more likely that the nucleus is radioactive.
5) U-238 has 146 neutrons
6) U - 235 has 143 neutrons
Image 2;
1) You can minimize background radiation by limiting your outdoor exposure.
2) Cosmic radiation is the most difficult to avoid.
What is background radiation?The natural radiation that is constantly present in the environment is known as background radiation.
It includes internal radiation found in all living things as well as cosmic radiation, which originates from the sun and stars and terrestrial radiation, which originates from the Earth.
We know that the repulsion of the protons in the Uranium nucleus is more than that of the barium nucleus because there are more neutrons in the Uranium nucleus. It is this repulsion that makes Uranium unstable.
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A sample of CO2 gas at 100 degrees Celsius has a volume of 250 mL at 760 mm Hg. How many moles of CO2 are present
There are 8.16 × 10-³ moles of CO2 gas at 100°C with a volume of 250 mL at 760 mm Hg.
HOW TO CALCULATE NUMBER OF MOLES:
The number of moles of a sample of gas can be calculated using the following formula:
PV = nRT
Where;
P = pressure of gas (atm)V = volume (L)n = number of moles (mol)R = gas law constant (0.0821 Latm/molK)T = temperature (K)According to this question;
P = 760mmHg = 1 atmT = 100°C = 100 + 273 = 373KV = 250mL = 0.250Ln = ?1 × 0.250 = n × 0.0821 × 373
0.250 = 30.62n
n = 0.250 ÷ 30.62
n = 8.16 × 10-³mol
Therefore, there are 8.16 × 10-³ moles of CO2 gas at 100°C with a volume of 250 mL at 760 mm Hg.
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A biologist explored a remote island and discovered a new living organism. After several observations were made of the
organism, the biologist claimed that it was a vascular plant. His notes are listed below.
"I have found a new organism during my explorations. The organism was found low to the ground and is green. Based on
experiments, the organism seems to require sunlight to survive. Small, oval seeds were
found on the organism; they grew
into identical organisms when put in the soil. The organism had sharp spikes around the main body, most likely for
protection. The organism was able to absorb water from the surrounding soil. It was also observed that the organism used
specialized veins to carry water throughout its body. Based on these observations and experiments, I have determined that
this organism is a vascular plant."
Which of the following observations LEAST supports his claim?
A)
The organism is low to the ground.
B)
The organism reproduces with seeds.
The organism requires sunlight.
D)
The organism was able to transport water through specialized veins.
The mass of a single barium atom is 2.28×10-22 grams. How many barium atoms would there be in 166 milligrams of barium?
166 milligrams is equal to 0.166 grams.
If 2.28x10^-22 grams is the mass of 1 atom, then 0.166 grams would constitute how many atoms?
The equation we would make is as follows:
2.28x10^-22/1 = 0.166/x
- If we cross multiply and solve for x, we get the answer which is 7.28x10^20 atoms.
6. How many moles are in 8.30 x 1023 molecules of CO₂?
a.
b.
C.
d.
1.37
2.8
55.5
100
A sample of gas occupies a volume of 350.0 mL at 840mm Hg and 33°C. Determine the volume of this sample at 600 mm By and 52°C
Answer:
V₂ = 520.42 mL
Explanation:
Given data:
Initial volume = 350.0 mL
Initial pressure = 840 mmHg
Initial temperature = 33°C (33 +273 = 306 K)
Final temperature = 52°C (52+273 = 325 K)
Final volume = ?
Final pressure = 600 mmHg
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 840 mmHg × 350.0 mL × 325 K / 306 K × 600 mmHg
V₂ = 95550000 mmHg.mL.K /183600 K.mmHg
V₂ = 520.42 mL
Under perfect conditions, which of these statements would you expect to be true about the magnitude of the potential (E"cell) for the CulMg voltaic cells in Part A when compared to the reduction potential for the Cu electrode? It may be helpful to refer to Appendix E of your lab manual The cell potential should be less than zero The cell potential should be greater than zero but less than the reduction potential for Cu The cell potential should be greater than the reduction potential for Cu The cell potential should be zero
The cell potential should be greater than the reduction potential for Cu.
It is given that,
The cell potential should be zero.
Because here we are considering the Cu-Cu cell so there would not be any potential difference and hence 0 E° cell value.
As we know that the reduction potential of copper is 0.34 V and the reduction potential of Mg is -2.37V
If we calculate the E°cell then,
E°cell= E(cathode)- E(anode)
Here copper is acting as the cathode and Mg as the anode
So, E°cell= 2.71V
So, the cell potential should be greater than the reduction potential for Cu.
Hence, option (c) is the correct choice.
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Which action would most likely create a light waye?
A. producing a fire fram fuel
B. dropping a pebble in a pond
O
C. pouring water into a pile of dirt
D. hitting a drum with a drumstick
Answer:
A. Producing a fire gram fuel
Explanation:
None of the other actions create light. Fire gives off light and heat.
If 4.53g Ar are added to 1.12 atm He in a 2.00 L cylinder at 27.0 Celsius degree
What is the total of gaseous mixture?
The total gaseous mixture is 4.48 g.
The total gaseous mixture can be calculated using the ideal gas law: PV = nRT.
First, we need to convert the temperature to Kelvin: 27.0°C + 273.15 = 300.15 K.
Next, we can use the ideal gas law to calculate the number of moles of each gas:
For He: n = (1.12 atm) (2.00 L) / (0.08206 L·atm/mol·K) (300.15 K) = 0.0906 mol
For Ar: n = (4.53 g) / (39.95 g/mol) = 0.113 mol
The total number of moles of gas in the mixture is then:
n(total) = n(He) + n(Ar) = 0.0906 mol + 0.113 mol = 0.204 mol
Finally, we can calculate the total mass of the mixture:
m(total) = n(total) × M(avg)
where M(avg) is the average molar mass of the mixture, which can be calculated as:
M(avg) = (M(He) + M(Ar)) / 2 = (4.003 g/mol + 39.95 g/mol) / 2 = 21.98 g/mol
Thus,
m(total) = 0.204 mol × 21.98 g/mol = 4.48 g
Therefore, The total weight of the gaseous mixture is 4.48 g.
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A sample of xenon occupies a volume of 715 mL at 8.01 atm and 67 °C. If the volume is changed to 963 mL and the temperature is changed to 52 °C, what will
be the new pressure?
Answer:
4.62 atm
Explanation:
To find the missing pressure, you need to use the Combined Gas Law equation:
P₁V₁ / T₁ = P₂V₂ / T₂
In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature.
P₁ = 8.01 atm P₁ = ? atm
V₁ = 715 mL V₁ = 963 mL
T₁ = 67 °C T₁ = 52 °C
P₁V₁ / T₁ = P₂V₂ / T₂
(8.01 atm)(715 mL) / 67 °C = P₂(963 mL) / 52 °C
85.47985 = P₂(963 mL) / 52 °C
4444.952 = P₂(936 mL)
4.62 atm = P₂
Identify the following reaction: 2Al + 3CuCh + 2AICh + 30u
Answer:
The chemical reaction identified is:
2Al + 3CuCl2 → 2AlCl3 + 3Cu
In this reaction, aluminum (Al) reacts with copper chloride (CuCl2) to form aluminum chloride (AlCl3) and copper (Cu). The coefficients in front of the chemical formulas indicate the stoichiometric ratio of the reactants and products, which means that two moles of Al react with three moles of CuCl2 to produce two moles of AlCl3 and three moles of Cu.
Determine if any of the following reactions could be written as net ionic equations. Write yes or no in the blanks.
_____a. CH4 (g) + 2 O2 (g) = CO2 (g) + 2 H2 O(g)
_____b. Cu(s) + 2 AgNO3 (aq) = 2 Ag(s) + Cu(NO3 )2 (aq)
_____c. MgCl2 (aq) + 2 KOH(aq) = Mg(OH)2 (s) + 2 KCl(aq)
_____d. CaCO3 (s) + 2 HCl(aq) = CaCl2 (aq) + CO2 (g) + H2 O(l)
Reaction b,c and d could be written as net ionic equations.
Further explanationThe electrolyte in the solution produces ions.
The equation of a chemical reaction can be expressed in the equation of the ions
For strong electrolytes (the ionization rate = 1) is written in the form of separate ions, while the weak electrolyte (degree of ionization <1) is still written as an un-ionized molecule
In the ion equation, there is a spectator ions that is the ion which does not react because it is present before and after the reaction
When these ions are removed, the ionic equation is called the net ionic equation
For gases and solids including water (H₂O(l)) can be written as an ionized molecule
So only the dissolved compound is ionized ((expressed in symbol aq)
To see the reaction can be expressed in terms of the net ionic equation, we must see that there are two or more ions that are the same from both sides of the reactant and the product in the form of aquoeus (because the form of compounds in the form of gases, solids and liquids will remain molecular and non-ionized)
CH4 (g) + 2 O2 (g) = CO2 (g) + 2 H2 O(g)
No⇒no compounds in the aqueous form
Cu(s) + 2 AgNO3 (aq) = 2 Ag(s) + Cu(NO3 )2 (aq)
Cu(s) + 2 Ag⁺+ 2NO3⁻ (aq) = 2 Ag(s) + Cu²⁺ +2NO3⁻ (aq)
Cu(s) + 2 Ag⁺(aq) = 2 Ag(s) + Cu²⁺(aq)
yes, because there are NO3 (spectators ion) on both sides
MgCl2 (aq) + 2 KOH(aq) = Mg(OH)2 (s) + 2 KCl(aq)
Mg²⁺(aq)+2Cl⁻ (aq) + 2K⁺(aq)+2OH⁻(aq) = Mg(OH)2 (s)+ 2K⁺(aq)+2Cl⁻(aq)
Mg²⁺(aq)+2OH⁻(aq) = Mg(OH)2 (s)
yes, because there are 2Cl⁻ (aq) and 2K⁺(aq (spectators ion) on both sides
CaCO3 (s) + 2 HCl(aq) = CaCl2 (aq) + CO2 (g) + H2 O(l)
CaCO3 (s) + 2 H⁺(aq)+2Cl⁻(aq) = Ca²⁺(aq)+2Cl⁻ (aq) + CO2 (g) + H2 O(l)
CaCO3 (s) + 2 H⁺(aq) = Ca²⁺(aq) + CO2 (g) + H2 O(l)
yes, because there are Cl⁻ (spectators ion) on both sides
Why does mass decrease when sugar dissolved in water
Answer:
Because the same amount of sugar is still there. The solid sugar crystals break apart in water as the sugar dissolves, but the individual sugar particles or molecules are still present and do not change as a result of dissolving in the water. The combined mass of the sugar and water shouldn't change.
Earth is a single interconnected system. True False
Answer:
True
Explanation:
Earth is a single interconnected system but it can be subdivided into smaller systems.
5.0 g of Ag2CO3(aq) is reacted with excess KBr(aq) to produce 4.3 g of AgBr(s). What is the percent yield of AgBr in the reaction
The percentage yield of AgBr is 63.14%
We'll begin by writing the balanced equation for the reaction. This is given below:
Ag₂CO₃ + 2KBr —> 2AgBr + K₂CO₃Molar mass of Ag₂CO₃ = (2×108 ) + 12 + (3×16) = 276 g/mol
Mass of Ag₂CO₃ from the balanced equation = 1 × 276 = 276 g
Molar mass of AgBr = 108 + 80 = 188 g/mol
Mass of AgBr from the balanced equation = 2 × 188 = 376 g
From the balanced equation above,
276 g of Ag₂CO₃ reacted to produce 376 g of AgBr
Next, we shall determine the theoretical yield of AgBrFrom the balanced equation above,
276 g of Ag₂CO₃ reacted to produce 376 g of AgBr
Therefore,
5 g of Ag₂CO₃ will react to produce = (5 × 376) / 276 = 6.81 g of AgBr
Thus, the theoretical yield of AgBr is 6.81 g
Finally, we shall determine the percentage yield of AgBr.Actual yield of AgBr = 4.3 g
Theoretical yield of AgBr = 6.81 g
Percentage yield =?\(percentage \: yield \: = \frac{actual}{theoretical} \times 100 \\ \\ percentage \: yield \: = \frac{4.3}{6.81} \times 100 \\ \\ percentage \: yield \: = 63.14\%\)
Thus, the percentage yield of AgBr is 63.14%
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Which of the following molecules would you expect to have the highest boiling point?
1
O Molecule 3
O Molecule 1
O Molecule 4
O Molecule 2
2
3
OH
O
4
The highest boiling point based on the data is option 4
What is the highest boiling point?Compared to alcohols of comparable molecular weight, carboxylic acids often have higher boiling temperatures. Between the hydrogen atoms of adjacent molecules and the oxygen in the carboxyl group of carboxylic acids, strong intermolecular hydrogen bonds can develop. Because it takes more energy to break the intermolecular interactions and change the substance from a liquid to a gas during boiling, these hydrogen bonds help materials have higher boiling temperatures.
Although carboxylic acids and alcohols are both capable of forming hydrogen bonds, carboxylic acids have higher boiling temperatures due to the extra carboxyl group that they contain.
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If you mastered this assignment, you will do exactly as it says to do.
What’s the Count?
NaC2HO4
Elements found in Formula:
Number of atoms in Element:
H2F5BLi
Elements found in Formula:
Number of atoms in Element:
2He2PSO4
Elements found in Formula:
Number of atoms in Element:
3He2O4PH
Elements found in Formula:
Number of atoms in Element:
The elements are the simplest chemical forms and they cannot be broken down through chemical reactions. There are many elements in the given formulas.
What are elements?
The elements are defined as those substances whose atoms all have the same number of protons. The elements are considered as the building blocks of matter. Each element has an atomic number and a symbol.
Each atom is regarded as an element. The elements create bonds to form molecules. The isotopes are the elements with the same atomic number but different mass numbers.
NaC₂HO₄ - 'N' , 'C', 'H','O'
H₂F₅BLi - 'H','F','B','Li'
He₂PSO₄ - 'He', 'P','S','O'
He₂O₄PH - 'He', 'O','P','H'
The energy of a pendulum is recorded at different positions in the table below. Use the data in the table to determine the amount of kinetic energy the pendulum had at Position 2. Record your answer below.
Please help me I just want to get this test over with
Answer:
so i got 34.5
Explanation:
Milk of magnesia, which is an aqueous suspension of magnesium hydroxide, is used as an antacid in the reaction below. How many molecules of HCl would have to be present to form 34.52 g of MgCl₂?
Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)
Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.
To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:
Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)
The molar mass of MgCl₂ is 95.21 g/mol.
First, we need to calculate the number of moles of MgCl₂ formed:
Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂
Moles of MgCl₂ = 34.52 g / 95.21 g/mol
Moles of MgCl₂ = 0.363 mol
According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:
Moles of HCl = 2 * Moles of MgCl₂
Moles of HCl = 2 * 0.363 mol
Moles of HCl = 0.726 mol
To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.
Number of molecules of HCl = Moles of HCl * Avogadro's number
Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol
Number of molecules of HCl = 4.37 x 10^23 molecules
Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.
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nitrous acid, hno2, is a weak acid. its weak acid dissociation reaction, written using the h3o convention, is:
Nitrous acid is a weak acid dissociation reaction, written using the H30 convention, is: HNO2 + H30 (where is used as the equilibrium symbol).
nitrous acid is an inorganic compound having the formula HNO3. It is a powerfully corrosive mineral acid. Although the material is colorless, older samples could have a yellow tint from nitrogen oxide decomposition. Most commercially available nitric acid has a 68% concentration in water. When the solution contains more than 86% HNO3, nitric acid flares. Depending on how much nitrogen dioxide is present, fuming nitric acid can also be categorized as red fuming nitric acid at concentrations above 86% or white fuming nitric acid at concentrations above 95%.
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o prepare vegetables for finishing by grilling, sautéing, pan frying, deep frying, or stewing, you should _______ them to cook them to partial doneness
Answer:
To prepare vegetables for finishing by grilling, sautéing, pan frying, deep frying, or stewing, you should parboil them to cook them to partial doneness.
What is the percent composition of a 16.75 g sample of a compound containing 14.02 g oxygen and 2.73 g hydrogen? Select the correct answer below: 83.7% oxygen, 16.3% hydrogen O 17% oxygen, 13% hydrogen O 68.2% oxygen, 31.8% hydrogen 89.5% oxygen, 10.5% hydrogen
Answer:
83.7% oxygen, 16.3% hydrogen
Explanation:
Mass of compound = 16.75 g
Mass of Oxygen = 14.02 g
Mass of Hydrogen = 2.73 g
Percentage composition = Mass of element / Mass of compound 100%
Percentage composition of Oxygen = 14.02 g / 16.75 g * 100%
Percentage composition of Oxygen = 0.837 * 100 = 83.7%
Percentage composition of Hydrogen = 2.73 g / 16.75 g * 100%
Percentage composition of Hydrogen = 0.163 * 100 = 16.3%
The correct option is;
83.7% oxygen, 16.3% hydrogen
Answer:
83.7% oxygen, 16.3% hydrogen
Explanation:
To determine the percent composition we can divide, our mass by total mass and afterwards, multiply by 100.
(Mass of O / Total mass) . 100 = % O
(Mass of H / Total mass) . 100 = % H
Remember that:
% O + % H = 100
Mass of O / Total mass + Mass of H / Total mass = 1
(14.02 g / 16.75g) . 100 = 83.7 %
(2.73 g /16.75g) . 100 = 16.3 %
what properties of a natural resource make it useful for humans as a materials or energy source?
The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.
What are natural resources?The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.
Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.
Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.
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