Gold, which has a density of 19.32 g/cm3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber.
(a) If a sample of gold with a mass of 1.915 g, is pressed into a leaf of 7.331 μm thickness, what is the area of the leaf?
(b) If, instead, the gold is drawn out into a cylindrical fiber of radius 2.100 μm, what is the length of the fiber?

Answers

Answer 1

Answer:

a) 0.014 m2

b) 7.1 Km

Explanation:

Density = mass/volume

volume - mass/density

volume = 1.915 g/19.32 g/cm3 = 0.099 * 10^-6 m3

Volume = Area * thickness

thickness =  7.331 * 10^-6 m

Area = Volume/thickness

Area= 0.099 * 10^-6 m3/7.331 * 10^-6 m

Area=  0.014 m2

b. Volume = πr^2h

h = volume/πr^2

h = 0.099 * 10^-6 m3/3.142 * ( 2.100 * 10^-6)^2

h =  0.099 * 10^-6 m3/3.142 *4.41 * 10^-12

h = 7.1 * 10^3 m

h = 7.1 Km

Answer 2

Answer:

The answer is below

Explanation:

Density is the ratio of mass to volume. It is given by the formula:

Density = mass / volume

a) Density of gold = 19.32 g/cm³

Mass of gold = 1.915 g

Therefore the volume (V) occupied by the gold is:

Density = mass / volume

19.32 = 1.915 / volume

volume = 1.915 / 19.32 = 0.0991 cm³

The volume of the leaf = Area * thickness

Volume of leaf = Area * (7.331 * 10⁻⁴ cm)

Volume of gold = volume of leaf

0.0991 cm³ = Area * (7.331 * 10⁻⁴ cm)

Area = 135.2 cm²

b) The volume of the cylinder = πr²h = π(2.1 * 10⁻⁴ cm)² * h

Volume of gold = volume of cylinder

0.0991 cm³ = π(2.1 * 10⁻⁴ cm)² * h

h = 0.0991 cm³ / [π(2.1 * 10⁻⁴ cm)²]

h = 340617 cm


Related Questions

a car travels 240km in 2hrs and a sprinter travels a 100m in 9.5s. which is traveling faster and by how much?

Answers

Given a car travels 240 km in 2 hrs.

Convert the km into meters and hrs into seconds.

\(\begin{gathered} 1km\text{ = 1000 m} \\ 240\text{ km = 240}\times1000\text{ m} \\ 240km\text{ = 2,40,000 m} \end{gathered}\)\(\begin{gathered} 1\text{ hr = 60 minute} \\ 2\text{ hr = 2}\times60\times60\text{ second} \\ 2\text{ hr = 7}200\text{ second} \end{gathered}\)

Calculate the speed of the car.

\(\begin{gathered} \text{speed = }\frac{Dis\tan ce}{\text{time}} \\ \text{speed = }\frac{2,40,000}{7200} \\ \text{speed = 33.33 }\frac{m}{s} \end{gathered}\)

Given a sprinter travels 100 m in 9.5 s.

\(\begin{gathered} \text{speed = }\frac{100\text{ m}}{9.5\text{ s}} \\ \text{speed = }10.53\frac{m}{s} \end{gathered}\)

Thus, the car travel fast than the sprinter by

\(33.33\text{ m/s - 10.53 m/s = }22.8\text{ m/s}\)

What is the motion of the object?
F = 90 N
F3 = 60 N
F = 20 N
F2 = 90 N
Constant speed to the left
Accelerating to the left
Accelerating to the right
Constant speed to the right

What is the motion of the object?F = 90 NF3 = 60 NF = 20 NF2 = 90 NConstant speed to the leftAccelerating

Answers

Answer:

Thus, the object is accelerating to the left

Explanation:

The Net Force

The net force is the result of adding all the forces as vectors acting on a body.

\(\vec F=\vec F_1+\vec F_2+...+\vec F_n\)

Each vector can be expressed in its rectangular components Fx and Fy, and the sum is the sum of the rectangular components separately.

Second Newton's law gives the relation between the net force and the acceleration of the body:

\(\vec F = m.\vec a\)

We can see the acceleration is a vector with the same direction as the net force.

The diagram shows two vertical forces and two horizontal forces.

The vertical forces are acting in opposite directions and with the same magnitude, thus they cancel out, leaving zero net force in the y-axis.

The horizontal forces are opposite and with different magnitudes. Since the force acting to the left (F3) has a greater magnitude than the force acting to the right (F4), there is a net force directed to the left with a magnitude of 60 N - 20 N = 40 N

Thus, the object is accelerating to the left

PLEASE How much voltage is required to run 1.6 A of current through a 2400 resistor? Use AV = IR.
A. 2.6 x 10-3 v
B. 6.7 x 10-3 v
C. 380 V
D. 150 V

Answers

Explanation:

\(from \: ohms \: law \\ voltage \: \: V =IR \\ = 1.6 \times 2400 \\ = 3840 \: Volts\)

Answer:

is it 380

Explanation:

If m1= 5 kg and m2 = 5 kg, wat would be a? (g = 10 m/s/s)

A.5m/s/s

B.10m/s/s

C.8m/s/s

D.6m/s/s

Answers

Answer:

a = 3.9m/s ²

Explanation:

The diagram is as shown

From the diagram, we can set up a simultaneous equation as shown;

T - F = m1a

W - T = m2a

Add both equation

-F + W = (m1 + m2)a

F is the frictional force

W is the weight

a is the acceleration

Let F = 10N since we are not given'

-10 + 5(9.8) = (5+5)a

-10 + 49 = 10a

39 = 10a

a = 39/10

a = 3.9m/s ²

Note that the frictional force was assumed

A burning candle is observed. Heat is felt above the flame, black smoke is seen rising from the wick, and wax melts. What caused each change?

Answers

Answer:

Chemical Changes in Burning Candle: When you light the candle, the wax present near the wick will melt. Wick absorbs the liquid wax. The liquid wax vaporizes due the heat produced by the flame. This wax vapor near to flame burns and gives new substances like Carbon Dioxide, Carbon soot, water vapours, heat and light.

Explanation:

hi

During burning of candle, wax molecules burn in oxygen and produces carbon-di-oxide, water vapor and carbon and heat. Hence, Heat is felt above the flame and Heat is felt above the flame because of chemical change. During this exothermal reaction, some wax melts for rising temperature. Hence, it is physical change.

What are chemical and physical change?

We can say that matter has experienced a physical transformation when it changes its visible properties. A sort of change known as physical change occurs when the physical characteristics of matter change. Physical changes include those in colour, odour, solubility, and the condition of matter, among others.

Changes to the chemical composition of matter are known as chemical changes. It is frequently referred to as a chemical reaction. Chemical characteristics of different substances vary.

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What is the opposite of 4/4

Answers

Answer: -1   or -4/4

Explanation:

4/4  simplifies to 1   and the opposite of 1 is -1.

A 1,700 kg car is accelerated at 2.8 m/s? What force was needed to produce this acceleration?

Answers

Answer:

\(4,760\:\mathrm{N}\)

Explanation:

From Newton's 2nd Law, we have \(\Sigma F=ma\). Substituting given values, we get:

\(F=1700\cdot 2.8,F=\boxed{4,760\:\mathrm{N}}\)

This is AP physics and how do u figure out a-f?

This is AP physics and how do u figure out a-f?

Answers

Take into account that if the system is in equilibrium, then, the sum of torques must be equal to zero. In this case, both weight of the block and applied force F generate a torque over the central fixed point with different signs:

\(\Sigma\tau=WL_1-FL_2=0_{}\)

W is the weight of the block, L1 the distance fromthe block to the pivot, F the applied force and L2 the distance between the point of the application of the force and the pivot.

The previous equation can be written as follow:

\(\begin{gathered} 100L_1=FL_2 \\ \frac{F}{100}=\frac{L_2}{L_1} \end{gathered}\)

The previous relation determines the equilibrium of the system.

Then, you can conclude:

(i) If F is increased, then, the board will rotate clockwise, because the torque produced by F will be greatest than the torque produced by the weight.

(ii) If is decreased, then, the board will rotate counter-clockwise, because the torque priduced by the weight will be greater.

(iii) If the applied force approaches to zero, then, the board will rotate counter-clockwise again, because there will be no torque at the right of the pivot.

(a) Now, if the weight is moved closer to the pivot (pin), the torque at the left appraches to zero, and then the board will rotate clockwise.

(b) If the applied force is moved to a position closer to the pivot, the torque at the right approaches to zero, and then, the board will rotate counter-clockwise.

(c) If the weight of the block decreases to 50N, it means that the torque at the left will decrease to ione half of its initial value. Under this new condition the equilibrium of the system breaks down and the board will rotate clockwise.

3. On a hike you walk 5,000 m East, 3,000 m North, and 1,000 m West at a constant speed of 1 m/s. Calculate your velocity.(1 point)
A.0.44 m/s East + 0.33 m/s North

B.1.0 m/s

C.1.0 m/s East + 1.0 m/s North

D.0.55 m/s

4.You ride your bike at a constant speed of 5 ms for 300 s from your house to the mailbox. What was your acceleration for the trip?(1 point)

A.0 m/s2

B.5 m/s2

C.60 m/s2

D.300 s

Answers

(1) the average velocity of this motion is 0.55 m/s.

(2) the acceleration is of the trip is 0 m/s²

The given parameters;

displacement on hike = 5,000 m East, 3,000 m North and 1,000 m West.

(1) Average velocity is the ratio of the total displacement to total time of motion.

A simple sketch of the motion is given as;

                                 1000 m  

                               P --------- ↑

                                ↑            ↑ 3000 m

                                ↑            ↑

 Q|------------------------|------------|

         4000 m             1000 m

A line joining point P and Q is the resultant displacement = hypotenuse side of the right triangle.

\(R^2 = 4000^2 + 3000^2\\\\R^2 = 25,000\\\\R = \sqrt{25,000,000} \\\\R = 5,000 \ m\)

The total distance is calculated as;

= 5000m + 3,000m + 1,000 m

= 9,000 m

The time of this motion is calculated as;

\(speed = \frac{total \ distance }{time \ of \ motion} \\\\1 = \frac{9,000}{t} \\\\t = 9,000 \ s\)

The average velocity is calculated as;

\(v= \frac{displacement }{t} \\\\v = \frac{5,000 \ m}{9,000 \ s} = 0.55 \ m/s\)

Thus, the average velocity of this motion is 0.55 m/s.

(2) Acceleration is the change in velocity per change in time of motion,

\(a = \frac{v_2-v_1}{t} \\\\\)

at constant speed, v₁ = v₂, and v₂ - v₁ = 0

Thus, the acceleration is of the trip is 0 m/s²

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Find the direction of the sum
of these two vectors:
16.3 m
7.70 m
20.0°
magnitude (m)
A
27.8°

Find the direction of the sumof these two vectors:16.3 m7.70 m20.0magnitude (m)A27.8

Answers

The resultant of the two given vectors with magnitudes 16.3 m and 7.7 m at an angle of 137.8 degree is equal to 23.87 meters.

What is the parallelograms law of vector addition?

If two vectors are acting simultaneously at a point, then it can be represented both in magnitude and direction by the adjacent sides drawn from a point.

What is the trigonometric ratio?

Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle. The ratios of sides of a right-angled triangle with respect to any of its acute angles are known as the trigonometric ratios of that particular angle.

Given:

Vector 1 of magnitude 7.7 m at an angle of 27.8 degree to x-axis.

vector 2 of magnitude 16.3 m at an angle of 20 degree to minus y axis.

Using the law of parallelogram vector addition

i.e.

resultant vector = √((v₁) ² + (v₂) ² + 2 × v₁ × v₂ × cos (angle between two vectors))

substituting given value in parallelogram vector addition we get,

resultant vector = √ (570)

resultant vector = 23.87 meters

therefore, the resultant of the two given vectors with magnitudes 16.3 m and 7.7 m at an angle of 137.8 degree is equal to 23.87 meters.

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Answer:

11.79

Explanation:

A fish tank is 20 inches by 12 inches by 12 inches. What is its volume in m * m ^ 3

Answers

As the fish tank is 20 inches by 12 inches by 12 inches, its volume is 47194744.32 mm³.

What is volume?

The space that any three-dimensional solid occupies is known as its volume. These solids can take the form of a cube, cuboid, cone, cylinder, or sphere.

1 inch = 0.0254 meters.

20 inches = 20 × 0.0254 meters = 0.508 meters = 508 mm.

12 inches = 12 × 0.0254 meters = 0.3048 meters = 304.8 mm.

Hence, The volume of the fish tank  = length × width × height

=  508 mm ×  304.8 mm ×  304.8 mm.

= 47194744.32 mm³

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5. Draw the ray diagram to show the image formed by a concave lens with focal length 5cm whenthe object is placed 15 cm from the lens. What is the magnification?

Answers

Given:

The focal length of the concave lens is f = -5 cm

The object distance from the lens is u = -15 cm

Required:

Ray diagram

Magnification

Explanation:

The rules related to incident ray and reflected ray are:

1) Any incident ray moving parallel to the principal axis will pass through focus after reflection.

2) Any incident ray passing through the focus will move parallel to the principal axis after reflection.

3) Incident ray passing through the optical center will reflect undeviated.

The ray diagram is shown below

Here, yellow lines represent incident rays passing parallel to the principal axis and the reflected ray passing through the focus.

The maroon line shows the incident ray passing through the optical center and the undeviated reflected ray.

The green color is the object and image.

In order to find magnification, first, we need to calculate the image distance given as

\(\begin{gathered} \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\ \frac{1}{v}=\frac{1}{f}+\frac{1}{u} \\ =-\frac{1}{5}-\frac{1}{15} \\ v=-3.75\text{ cm} \end{gathered}\)

The magnification will be

\(\begin{gathered} m\text{ = }\frac{v}{u} \\ =\frac{-3.75}{-15} \\ =0.25\text{ } \end{gathered}\)

Final Answer: Thus, the magnification is 0.25 which means the size of the image is 0.25 times the object.

5. Draw the ray diagram to show the image formed by a concave lens with focal length 5cm whenthe object

A framed picture hangs from two cords attached to the ceiling. Which shows the correct free body diagram of the hanging picture?​

Answers

Answer: the answer is in the picture

Explanation:

A framed picture hangs from two cords attached to the ceiling. Which shows the correct free body diagram

Answer:

C

Explanation:

i did the test and got 100 :)

A 12.4 m rope attaches a board overhanging a building. A painter swinging on the board has a mass of 97kg. If the magnitude of the centripetal force is 113.0 N, what is the painters tangential speed?

Answers

When the painter swinging on the boar, his tangential speed is 3.8 m/s.

What is centripetal force?

A force that causes a body to follow a curved path is known as a centripetal force. It always moves in a direction that is the opposite of the body's velocity and in the direction of the immediate center of curvature of the path.

It is "a force by which bodies are dragged or driven, or in any manner tend, towards a point as to a center," according to Isaac Newton. Gravity is the centripetal force that drives astronomical orbits according to Newtonian mechanics.

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Why are some areas in Europe seeing a partial solar eclipse while others are observing a total solar eclipse?

plz answer ASAP

Answers

Answer:

Objects between the source and observer produce possible shadows known as the umbra and the penumbra.

The umbra is a totally shadowed area, no light travels directly from the source to the observer.

The penumbra is a partially shadowed are where some of the source light travels directly to the observer an some of the source light is blocked from the observer (the object blocking the light is not a point object).

The question apparently refers to the differences seen by the observers.

1. Determine the average of the three trials for each material.
Mystery A = ___30_______
Mystery B = ___2.8_______

In which material would light travel faster, Mystery A or Mystery B? Explain

2. As the index of refraction for the second medium is increased, what effect does this have on the angle of refraction? When it comes in at a lower angle, the ray bends more.

3. Write a conclusion for this lab.

Answers

The lab experiment found that light travels faster in Mystery A compared to Mystery B, with average speeds of 3.0 and 2.8, respectively. The increase in the index of refraction for the second medium led to a higher angle of refraction, resulting in light bending more. These findings have practical implications for optics and communications.

1. Light would travel faster in Mystery A since the average speed of light in Mystery A (3.0) is higher than Mystery B (2.8).

2. Increasing the index of refraction for the second medium leads to an increase in the angle of refraction. When light comes in at a lower angle, it bends more.

3. In conclusion, this lab experiment showed that the speed of light in a material is influenced by the material's index of refraction. Mystery A had a higher average speed of light compared to Mystery B, indicating that light travels faster in Mystery A. Additionally, the angle of refraction increased as the index of refraction for the second medium was increased. These findings have practical applications in the field of optics and communications.

Hence,The laboratory experiment discovered that, with average speeds of 3.0 and 2.8, respectively, light moves more quickly in Mystery A than Mystery B. Light bent more as a result of the second medium's increased index of refraction due to a higher angle of refraction. For optics and communications, these findings have real-world applications.

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) explain the concept of radiative forcing. (b) (4 points) some parts of the earth system are likely to respond rather slowly to rising greenhouse gases. describe at least two of these, mention roughly what time scales are involved, and explain what makes their response slow. (c) (3 points) explain why low clouds tend to have a net cooling effect on climate. (d) (3 points). depending on the efforts taken to mitigate greenhouse gas emissions, the trajectory of climate change can take very different paths in the future. which of the following is most likely to be true regardless of mitigation efforts in year 2

Answers

When the quantity of energy entering and leaving the Earth's atmosphere is not the same, radioactive forcing results.

What is a good illustration of radioactive forcing?

A radioactive forcing is an energy imbalance that the climate system is subjected to, either externally or as a result of human activity ( changes in solar energy output, volcanic anthropogenic emissions of greenhouse gases, aerosols, and their precursors; intentional land change.

The significance of radioactive forcing?

In other words, if you want to know how to tell if something is good or bad, you need to know how to tell if it's good or bad.

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An object floats with half its volume beneath the surface of the water. The volume of the object is 3.5 m. What is the weight of the object? The density of water is 1000 kg/m3​

Answers

Answer:

Since the object is floating, the buoyant force equals the weight of the water displaced:

W = d g v  where d is the density of water and v = V/2 where v is the volume of the water displaced   and v = V/2 where V is the volume of the object.

W = 1000 kg/m^3 * 9.8 m/s^2 * (3.5 /2 m^3)

W = 17150 kg m / s^2 = 17150 N

When an object floats with half its volume beneath the surface of the water. If the volume of the object is 3.5 m,then the weight of the object would be 17167.5 N if the density of water is 1000 kg/m3

What is density?

It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.

The density is the reciprocal of the specific volume of any substance.

The mathematical formula for density is given below

ρ =m /V

where ρ is the density of the substance

m is the mass of the substance

V is the volume of the substance

As given in the problem an object floats with half its volume beneath the surface of the water. The volume of the object is 3.5 m

The density of water is 1000 kg/m3​

According to the Archimedes principle, the buoyancy force acting on  the floating object is equal to the weight of the fluid displaced by it

W =  ρ g V

Given the object floats with half its volume beneath the surface of the water means the volume of the water displaced is half of the volume of the object

V=3.5/2 m³

W = 1000×9.81×3.5/2

   = 17167.5 N

Thus, the weight of the object is 17167.5 N

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A rock from a volcanic eruption is launched straight up into the air with no appreciable air
resistance. Which one of the following statements about this rock while it is in the air is
correct?
a. The acceleration is downward at all points in the motion.
b. Throughout the motion, the acceleration is downward, and the velocity is always in
the same direction as the acceleration.
c. On the way down, both its velocity and acceleration are downward, and at the
highest point both its velocity and acceleration are zero.
d. The acceleration is downward at all points in the motion except that is zero at the
highest point.

Answers

Answer:

A. The acceleration is downward at all points in the motion.

Explanation:

Did this before on Quiz 2.4 Free Fall

The statement which is true about the rock which is launched from a volcanic eruption is acceleration is downward at all points in the motion.

What is projectile motion?

Projectile motion is the motion of the body, when it is thrown in the air taking the action of gravity on it.

A rock from a volcanic eruption is launched straight up into the air with no appreciable air resistance. Let's check point wise what happens with this rock.

The rock is launched with upward velocity and reached to its highest point.At the highest point the rock stopped and started to free fall due to the acceleration of gravity.This acceleration also working on the rock while it was going up in the air, due to which the rock slows down.

Hence, with the above point it can be concluded that the acceleration on the rock is always working on the rock in downward direction, which slows it down, and bring back it on the earth.

Thus, the statement which is true about the rock which is launched from a volcanic eruption is acceleration is downward at all points in the motion.

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How/is climate change/human interaction affecting mutualism

Answers

Most mutualisms involve partnerships between ectothermic organisms. Therefore, they are particularly sensitive to changes in temperature, and most will be strongly affected by climate change. A mutualism will retain stability and function only under a particular set of environmental conditions.

come in my free candy van located at Skellerupvej 43, 8600 Silkeborg, Denmark

Answers

Answer:

Did you think you could pull that off-

:I

I live in Japan anyway so.. ウーフ-

Starting from rest, a wheel undergoes constant angular acceleration for a period of time T. At which of the following times does the average angular acceleration equal the instantaneous angular acceleration?

a. 0.50 T
b. 0.67 T
c. 0.71 T
d. all of the above

Answers

I think it would be a

A meteor which is moving at a speed of 100 m si
towards Mars is deteced at a height of 207.2 m
from its surface. The meteor reaches the surface of
Mars after 2 s.
What is the gravitational acceleration of Mars?

Answers

Answer:

Acceleration due to gravity of Mars

Explanation:

A 0.75 kg mass attached to a vertical spring stretches 0.30m. a) what is the spring constant?

Answers

Answer:25N/

Explanation:

A 0.75 kg mass attached to a vertical spring stretches 0.30m. a) what is the spring constant?

An injured monkey sits perched on a tree branch 4.5 m above the ground, while a wildlife veterinarian is kneeling down in the bushes 85.5 m away attempting to subdue the monkey with a tranquilizer gun. The vet knows that the moment the gun fires, the monkey will be frightened and fall down from the branch. At what angle up from the ground must the veterinarian aim the gun so that the tranquilizer dart will hit the falling monkey

Answers

Answer:

3.03°

Explanation:

Given that

Height of the tree branch, h = 4.5 m

Distance of the veterinarian away, d = 85.5 m

The vet is to aim at the monkey at a particular angle. If we consider the force of gravity that will be acting on the dart. Then the angle that will be needed will be calculated as this.

So the angle is

Tan θ = opposite / adjacent

Tan θ = 4.5 m/ 85.5 m

Tan θ = 0.053, then

θ = Tan^-1 (0.053)

θ = 3.03°

Therefore, the angle needed is 3.03°

Can anyone please help me

Can anyone please help me

Answers

To solve this problem, we can use Coulomb's law, which states that the electric force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.

We can then use the electric force to find the electric field at the location of q3 and the initial acceleration of q3.

a) To find the electric field at the location of q3, we can first find the electric force on q3 due to q1 and q2 and then use the definition of the electric field, which is the electric force per unit charge. The electric force on q³ due to q¹ and q² is:

F1 = k x q¹ x q³/ r1²

F2 = k x q² x q³ / r2²

where r¹ and r² are the distances from q¹ and q² to q³, respectively, and k is Coulomb's constant.

Since q³ is equidistant from q¹ and q², we have r¹ = r² = 0.20 m. Substituting the given values, we get:

F1 = (9.0 x 10⁹ N-m²/C²) x (4.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = 1.8 N

F2 = (9.0 x 10⁹ N-m⁻²/C²) x (-6.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = -5.4 N

The negative sign of F2 indicates that the force on q³ due to q² is in the opposite direction to the force due to q¹.

The net electric force on q3 is the vector sum of the forces due to q1 and q2:

Fnet = F1 + F2 = 1.8 N - 5.4 N = -3.6 N

The electric field at the location of q³ is then:

E = Fnet / q³ = (-3.6 N) / (2.0 x 10⁻⁶ C) = -1.8 x 10⁻⁶N/C

The negative sign of the electric field indicates that the field is directed towards q².

b) To find the initial acceleration of q³, we can use Newton's second law, which states that the net force on an object is equal to its mass times its acceleration:

Fnet = ma

where m is the mass of q³ and a is its initial acceleration.

Substituting the given values, we get:

-3.6 N = (2.0 x 10⁻⁶ kg) x a

Solving for a, we get:

a = -1.8 x 10³ m/s²

The negative sign of the acceleration indicates that it is directed towards q².

c) The direction of the initial acceleration of q³ is towards q².

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The ___ of a wave is the reciprocal of its frequency.

Answers

Answer:

time period of the wave

Answer:

The Frequency of a wave is the reciprocal of its Period

The Period of a wave is the reciprocal of its frequency

Explanation:

A P E X

Which of the four locations
would be the best and worst places to
build a house? Rank the four locations and
explain your reasoning.

Which of the four locations would be the best and worst places to build a house? Rank the four locations

Answers

Location B which is situated at some distance from the mountain is the best location to build a house because of possible volcanic events.

Building a house

When building a house a lot of things are taken into consideration to ensure that that the structure will survive for a long time.

In the case of the structures shows in the images in the questions, we can see that location B which gives some distance from the mountain is the best location to build a house because of possible volcanic events.

Learn more volcanic events: https://brainly.com/question/1622004

3) A square coil of sides 0.40 m carries a current of 3.0 A in a uniform magnetic field of 5.0 mT. the plane of the coil is parallel to the magnetic field as shown in figure below.

a) Calculate the force on each side of the coil.
b) What is the resultant effect of the force on the coil?
c) What happen to the coil?

3) A square coil of sides 0.40 m carries a current of 3.0 A in a uniform magnetic field of 5.0 mT. the

Answers

It’s B I took the assignment and passed

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Heeelp me faaast plllsss

Answers

Answer:

the first one

Explanation:

cartridge fuse

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